The average maximum height will be 103.7m.
What is a Projectile?A projectile is defined as an object that has an initial velocity and follows a path that dependent on the gravitational acceleration.
The gravitational force initially will act on the opposite direction until it reach the maximum height, and right after that, the gravitational force will accelerate the speed of the projectile.
The formular used will be;
\(H = \frac{1}{2} gt^{2}\)
In this case, the initial velocity u = 0;
where g = 9.8m/s2
t = 4.6s
\(H = \frac{1}{2} (9.8)(4.6)^{2}\)
H = 4.9 x 21.16
H = 103.7m.
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Let to the right be the positive direction.
A 25.8 g marble sliding to the right at 21.0
cm/s overtakes and collides with a 12.4 g
marble moving in the same direction at 13.8
cm/s. After the collision, the 12.4 g marble
moves to the right at 23.9 cm/s.
Find the velocity of the 25.8 g marble after
the collision.
Answer in units of cm/s. Answer in units
of cm/s.
The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.
What is the velocity of the 25.8 g marble after the collision?
The velocity of the 25.8 g marble after the collision is calculated as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of 25.8 g marblem₂ is the mass of 12.4 g marbleu is their initial speedsv is their final speedsThe final velocity of the 25.8 g marble after the collision is calculated as;
( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )
712.92 = 296.36 + 25.8v
25.8v = 416.56
v = 416.56 / 25.8
v = 16.15 cm/s
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What are 4 ways individuals can influence the government?
a bike accelerates from 0 m/s to 5 m/s in 4.5s.Then continues at a Constant speed for another 2.5s How far does it move?
Answer:
Below
Explanation:
First we will find the distance from when the bike is accelerating
Use this formula to find this :
d1 = ( vf - vi / 2 ) t
d1 = ( 5m/s - 0 m/s / 2 ) 4.5 s
d1 = (2.5)(4.5)
d1 = 11.25 m
Now we can find the distance for another 2.5 seconds
Since the car accelerated to 5 m/s, the constant velocity will be 5 m/s
Use this formula to find this :
d2 = vt
d2 = (5m/s)(2.5s)
d2 = 12.5 m
Finally we can add them up to get the total distance :
dt = 12.5 m + 11.25 m
dt = 23.75 m
*Make sure to round this number to how your teacher taught you
Hope this helps!
40 POINTS!!!
A wave travels along a stretched horizontal rope. The vertical distance from crest to trough for this wave is 18 cm and the horizontal distance from crest to trough is 26cm.
Part A
What is the wavelength of this wave?
Express your answer using two significant figures
Part B
What is the amplitude of this wave?
Express your answer using two significant figures.
part a. the wavelength of this wave is 26 cm
part b. The amplitude (A) of a wave is 9 cm
What is wavelength?The wavelength (λ) of a wave is described as the distance between two consecutive points on the wave that are in phase.
In this scenario, the distance between two corresponding points on the wave will be equal to the horizontal distance from crest to trough, which is 26 cm.
Hence, the wavelength of the wave is: λ = 26 cm
The amplitude (A) of a wave is described as the maximum displacement of a particle from its rest position as the wave passes through it.
In this scenario, the vertical distance from crest to trough is 18 cm, which is equal to twice the amplitude.
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why fur coats would keep their owners warmer if they were worn inside out?
Answer:
The reason why this is, is because:
Explanation:
According to Jones, fur serves as an insulator for the body during cold weather and regulates the process of heat absorption during warm weather. It acts as a thermal regulator, preventing the body from taking on excessive heat. Dogs and cats shed their fur in hot weather to make their coats more appropriate for heat protection rather than warmth.
Answer:
Insulation
Explanation:
The reason for this is insulation, which describes the process of an object absorbing heat and harboring heat. It works as such: Fur protects you from the cold by forming what’s called a “boundary layer.” This happens as cold air hits the surface of your coat and the molecules cause friction.
A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her.
Which of the following was the girl's velocity when she began to stop?
Answer:10 m/s
Explanation:
A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. Velocity is vector quantity.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time. Here in the question velocity is changing by using work energy theorem we have,
work done = change in kinetic energy
5000 = (.5).m.v² , where v is velocity.
5000 = (.5).100.v²
v = 10 m/sec
A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.
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Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a current of 4.33 A. (a) Find the force per meter exerted on the 2.75-A wire. (b) Is the force per meter exerted on the 4.33-A wire greater than, less than, or the same as the force per meter exerted on the 2.75-A wire
Answer:
a)\(\frac{F_1}{L}=1.95*10^-^5N\)
b)\(\frac{F_2}{L}=1.95*10^-^5N\)
Explanation:
From the question we are told that:
Distance between wires \(d=32.2\)
Wire 1 current \(I_1=2.75\)
Wire 2 current \(I_2=4.33\)
a)
Generally the equation for Force on \(l_1\) due to \(I_2\) is mathematically given by
\(F_1=I_1B_2L\)
Where
B_2=Magnetic field current by \(I_2\)
\(B_2=\frac{\mu *i_2}{2\pi d}\)
Therefore
\(F_1=I_1B_2L\)
\(F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L\)
\(\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }\)
\(\frac{F_1}{L}=1.95*10^-^5N\)
b)
Generally the equation for Force on \(I_2\) due to \(I_1\) is mathematically given by
\(F_2=I_2B_1L\)
Where
B_1=Magnetic field current by \(I_2\)
\(B_1=\frac{\mu *I_1}{2\pi d}\)
Therefore
\(\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})\)
\(\frac{F_2}{L}=1.95*10^-^5N\)
FILL IN THE BLANK. 10. the mutcd advises examining emergency vehicle lighting policies with the intent of reducing lighting use as much as possible without endangering___at the scene.
the mutcd advises examining emergency vehicle lighting policies with the intent of reducing lighting use as much as possible without endangering_those __at the scene.
what is MUTCD ?
The United States Department of Transportation's Federal Highway Administration issued the Manual on Uniform Traffic Control Devices (MUTCD) for Streets and Highways to explain the standards for the construction, installation, and operation of traffic signs, surface markings, and signals.
All traffic control devices must meet the national standards outlined in the MUTCD. The MUTCD is a nationwide standard on which all public agencies and owners of privately held public highways rely. Because of the MUTCD, all road users benefit from greater safety and mobility.
The MUTCD recommends reviewing emergency vehicle lighting rules in order to reduce lights consumption as much as feasible without harming individuals on the site.
recent edition of the official FHWA document is a July 2022 PDF file that integrates the 2009 MUTCD with Revisions 1, 2, and 3.
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A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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5. Stas is pushing his car which has broken down. He does 3KJ of work against friction
and moves it a distance of 12m. How big is the friction force he has to push against?
6. Sam is a pole-vaulter who has a mass of 80kg. He vaults to a height of 4m.
a) How much work does he do?
b) How much kinetic energy will he have just before he lands?
c) When he lands, his trainers compress by 1cm. Calculate the average force acting
on his trainers as he lands.
If Stas is pushing his car which has broken down and does 3 KJ of work against friction and moves it a distance of 12m, the friction force is 250 N
W = F d
W = Work done
F = Force
d = Distance
W = 3 KJ = 3 * 10³ J
d = 12 m
F = W / d
F = 3 * 10³ / 12
F = 0.25 * 10³
F = 250 N
Therefore, the friction force he has to push against is 250 N
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A car driving at 20 m/s accelerates 2.5 m/s2 for a distance of 350 meters. What is the car's final velocity?
The time of the travel with 20m/s is 17.5 seconds. Thus, the final velocity of the car will be 63 m/s.
What is velocity?Velocity of an object is the measure of the distance travelled per unit time. The rate of change in velocity is called the acceleration.
Given that, initial velocity u = 20 m/s
distance = 350 meters.
time of travel = distance/ velocity
= 350 m/20 m/s = 17.5 s.
Acceleration = 2.5 m/s²
the final velocity v = u + at.
v = 20 + (2.5 × 17.5 ) = 63 m/s.
Therefore, the final velocity of the car is 63 m/s.
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Calculate the fringe separation for light of wavelength 680nm that falls on two slits 4 separated by 0.1 mm when the screen is placed 1.3 m away from the slits.
The fringe separation of the double-slit interference is 0.884 mm.
What is interference of lights?When two coherent light waves from separate sources collide, the energy distribution caused by the first wave is altered by the second. The term "interference of light" refers to this alteration in the distribution of light energy brought on by the superposition of two light waves.
Wavelength of light: λ = 680 nm = 680 × 10⁻⁹ m.
Separation between the two slits: d = 0.1 mm = 0.1 × 10⁻³ m.
Screen distance: D = 1.3 m.
Hence, the fringe separation: x = λD/d
= ( 680 × 10⁻⁹)×(1.3 )/(0.1 × 10⁻³ ) m
= 0.000884 m
= 0.884 mm.
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If someone gets pushed through a small opening and hits someone else, whose fault is it, the person who got pushed or the person who pushed?
What are the similarities and differences between these data sets in terms of their centers and their variability?
Data Set A: 12, 15, 18, 18, 22, 29
Data Set B: 13, 17, 17, 19, 20, 34
Select from the drop-down menus to correctly complete the statements.
Comparing the centers of the data sets, the median for Data Set A is Choose...
Choose.
Set A is Choose... the mean for Data Set B.
less than
equal to
greater than
the median for Data Set B. The mean for Data
4
g A person walks 70 m west, then turns and walks 30 m east. Find the average speed and velocity if the time for the total trip is 45 seconds.
Answer:
Average speed = 2.22m/s
Velocity = 0.89 m/s west
Explanation:
(i) Since speed is a scalar quantity, the direction of movement by the person is irrelevant. Therefore,
Average speed = total distance traveled / time taken
Where;
Total distance = 70m + 30m = 100m
Time taken = 45 seconds
Average speed = 100 / 45 = 2.22m/s
(ii) However, velocity is a vector quantity and so the direction of movement by the person is of utmost importance. Therefore,
Velocity = displacement / time taken
Where;
displacement = -70m + 30m [West direction is taken as negative and east is taken as positive]
displacement = -40m [The negative sign just means that the net displacement is in the direction of the West].
Thus, displacement can be written as 40m west.
Therefore,
Velocity = 40 / 45 = 0.89m/s west
The skin temperature of a person is 34o C and his body surface area is about 1.8 m2 . He is standing bare skin in a room where the air temperature is 24o C and the walls are 17o C. He is metabolizing food at a rate of 155 W, the emissivity of his skin is 0.97 and there is a 5mm thick dead layer (immobile) air next to his skin acting as an insulation. a./ at what rate his body is losing heat by conduction
Answer:
the rate at which his body is losing heat by conduction is 93.6 J/s
Explanation:
Given that;
surface area A = 1.8 m²
Skin temperature of the person Tp = 32°C = ( 34 + 273.15 ) = 307.15 K
Temperature of Air \(T_{air}\) = 24°C = ( 24 + 273.15 ) = 297.15 K
Temperature of wall \(T_{wall}\) = 17°C = ( 17 + 273.15 ) = 290.15 K
Length ( thick dead layer = 5 mm = 0.005 m
Skin emissivity = 0.97
Rate of metabolism = 155 W
rate his body is losing heat by conduction = ?
first we determine the difference in temperature between the skin and air
so
ΔT = 307.15 K - 297.15 K = 10 K
we know that; coefficient of thermal heat conductivity of air k = 0.026 W/mK
so
rate of heat loss by conduction Q/ΔT will be;
Q/ΔT = (KA/L)ΔT
so we substitute
= ( 0.026 × 1.8/ 0.005 )10
= 9.36 × 10
= 93.6 J/s
Therefore, the rate at which his body is losing heat by conduction is 93.6 J/s
The state of the atmosphere at a particular time and place is called the ————-.
Answer:
= weather
Explanation:
in fig. 13-21, a central particle of mass m is surrounded by a square ar- ray of other particles, separated by ei- ther distance d or distance d/2 along the perimeter of the square.what are the magnitude and direction of the net gravitational force on the central particle due to the other particles?
The magnitude of the net gravitational force on the central particle due to the other particles is zero.
The direction of the net gravitational force is also zero, since all of the forces on the central particle due to the other particles cancel out.
Given the mass of central particle = m
It is surrounded by array of square of other particles.
The particles are separated by a distance of d or d/2
We know the force of gravity is F = GMm/r^2 where G is the gravitational constant and r is the distance between the particles.
Each particle's gravitational force on one side of the square cancels out the gravitational pull of one of the other side's particles.
The magnitude of gravitational force acting on the particles is zero because the forces due to all other charges cancel due to the symmetry considerations.
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What is a small portable device that counts every step taken throughout the day?
A.stethoscope
B.pedometer
C.otoscope
D.thermometer
Answer: B
Explanation: i learned it last year
Pedometer is a small portable device that counts every step taken throughout the day. The correct option is (B).
A pedometer is a small portable device that counts the number of steps taken by an individual throughout the day. It is typically worn on the waist or carried in a pocket and uses a mechanism to detect body motion and count each step.
Pedometers are commonly used for tracking physical activity and encouraging individuals to achieve daily step goals as part of their fitness routines.
Therefore, Pedometer is a small portable device that counts every step taken throughout the day. Choose the option (B).
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Calculate the equivalent resistance for each of the following circuits.
Answer:
5. 60 Ω
6. 60 Ω
7. 10 Ω
8. 0.625 KΩ
Explanation:
5. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 20 Ω
Resistor 3 (R₃) = 30 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 20 + 30
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
6. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 35 Ω
Resistor 3 (R₃) = 15 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 35 + 15
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
7. Determination of the equivalent resistance.
Resistor 1 (R₁) = 6 Ω
Resistor 2 (R₂) = 4 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂
R = 6 + 4
R = 10 Ω
Thus, the equivalent resistance is 10 Ω
8. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 KΩ
Resistor 2 (R₂) = 2 KΩ
Resistor 3 (R₃) = 1 KΩ
Equivalent Resistance (R) =?
Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/10 + 1/2 + 1/1
Find the least common multiple (lcm) of 10, 2 and 1. The result is 10. Divide 10 by each of the denominator and multiply the result obtained by the numerator. This is illustrated below:
1/R = (1 + 5 + 10) / 10
1/R = 16/10
Invert
R = 10/16
R = 0.625 KΩ
Thus, the equivalent resistance is 0.625 KΩ.
What is internal energy?
The total energy within a system.
Internal energy is a measure of thermal energy. The total chemical energy of matter that makes up objects.
A sum of thermal energy and kinetic energy
The term "internal energy" describes the combined potential and kinetic energy of a system or substance. It is the potential energy held inside the bonds between those particles as well as the energy that results from the motion and interactions of the molecules and atoms within a substance.
What does a system's internal and overall energy consist of?The chaotic, random motion of molecules is known as a system's internal energy; a system's total (internal) energy is made up of both potential and kinetic energy.
How much heat does a system's internal energy produce?The sum of the random internal kinetic energies of the atoms and the total internal potential is known as a system's internal energy.energies due to the bonds between atoms. Internal energy is not a new concept or form of energy. On the other hand, heat is a new concept that is central to thermodynamics.
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An object is in free fall Group of answer choices Anytime it has an acceleration equal to 9.8 m/s/s Anytime it feels the force of gravity Only if the weight is the only force acting on the object Only when it's moving vertically down
Answer:
Anytime it feels the force of gravity.
Explanation:
Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and can occupy space. Therefore, it acts in such a way as to bring objects together i.e causing the objects to fall down towards the Earth.
This ultimately implies that, an object is in free fall anytime it feels the force of gravity i.e regardless of how fast the object moves or the direction it moves, the only force acting on the object is the force of gravity (g).
For example, when you throw any object up, it will naturally fall down due to the gravitational force between the Earth and the object.
Additionally, the gravity of earth makes it possible for all physical objects to possess weight.
On planet Earth, the acceleration due to gravity that all physical objects experience is 9.8 meters per seconds square.
a car moving at 5 m/s accelerates at a rate of 10 m/s2 for 25 seconds. How far does it move during this time?
Answer:
t is time in s For example, a car accelerates in 5 s from 25 m/s to 3 5m/s. Its velocity changes by 35 - 25 = 10 m/s. Therefore its acceleration is 10 ÷ 5 = 2 m/s2
Explanation:
Use conservation of energy to find the speed of impact on the ground.
According to the question, the speed of impact on the ground is v = √(2gh).
What is speed?Speed is a measure of how quickly an object or person moves, usually expressed in terms of distance traveled over a given period of time. It is a scalar quantity and is represented by the symbol v. Speed is a measure of the rate of motion or rate of change in position, but it is not directly related to the direction of motion. When an object moves in a certain direction, its speed is a measure of how quickly it is moving in that direction.
Let's assume the initial height of the object is h and its final speed is v.
Using the conservation of energy, we have:
Initial energy = Final energy
mgh = 1/2mv²
v = √(2gh)
Therefore, the speed of impact on the ground is v = √(2gh).
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A viewing screen is separated from a double slit by 5.20 m. The distance between the two slits is 0.0300 mm. Monochromatic light is directed toward the double slit and forms an interference pattern on the screen. The first dark fringe is 3.70 cm from the center line on the screen.
Required:
a. Determine the wavelength of light.
b. Calculate the distance between the adjacent bright fringes.
Answer:
The wavelength of this light is approximately \(427\; \rm nm\) (\(4.27\times 10^{-7}\; \rm m\).)The distance between the first and central maxima is approximately \(7.40\; \rm cm\) (about twice the distance between the first dark fringe and the central maximum.)Explanation:
WavelengthConvert all lengths to meters:
Separation of the two slits: \(0.0300\; \rm mm = 3.00\times 10^{-5}\; \rm m\).Distance between the first dark fringe and the center of the screen: \(3.70\; \rm cm = 3.70\times 10^{-2}\; \rm m\).Refer to the diagram attached (not to scale.) Assuming that the screen is parallel to the line joining the two slits. The following two angles are alternate interior angles and should be equal to each other:
The angle between the filter and the beam of light from the lower slit, andThe angle between the screen and that same beam of light.These two angles are marked with two grey sectors on the attached diagram. Let the value of these two angles be \(\theta\).
The path difference between the two beams is approximately equal to the length of the segment highlighted in green. In order to produce the first dark fringe from the center of the screen (the first minimum,) the length of that segment should be \(\lambda / 2\) (one-half the wavelength of the light.)
Therefore:
\(\displaystyle \cos \theta \approx \frac{\text{Path difference}}{\text{Slit separation}} = \frac{\lambda / 2}{3.00\times 10^{-5}\; \rm m}\).
On the other hand:
\(\begin{aligned} \cot \theta &\approx \frac{\text{Distance between central peak and first minimum}}{\text{Distance between the screen and the slits}} \\ &= \frac{3.70\times 10^{-2}\; \rm m}{5.20\; \rm m} \approx 0.00711538\end{aligned}\).
Because the cotangent of \(\theta\) is very close to zero,
\(\cos \theta \approx \cot \theta \approx 0.00711538\).
\(\displaystyle \frac{\lambda /2}{3.00\times 10^{-5}\; \rm m} \approx \cos\theta\approx 0.00711538\).
\(\begin{aligned}\lambda &\approx 2\times 0.00711538 \times \left(3.00\times 10^{-5}\; \rm m\right) \\ &\approx 4.26 \times 10^{-7}\; \rm m = 426\; \rm nm\end{aligned}\).
Distance between two adjacent maximaIf the path difference is increased by one wavelength, then the intersection of the two beams would move from one bright fringe to the next one.
The path difference required for the central maximum is \(0\).The path difference required for the first maximum is \(\lambda\).The path difference required for the second maximum is \(2\,\lambda\).On the other hand, if the distance between the maximum and the center of the screen is much smaller than the distance between the screen and the filter, then:
\(\begin{aligned}&\frac{\text{Distance between image and center of screen}}{\text{Distance between the screen and the slits}} \\ &\approx \cot \theta \\ &\approx \cos \theta \\ &\approx \frac{\text{Path difference}}{\text{Slit separation}}\end{aligned}\).
Under that assumption, the distance between the maximum and the center of the screen is approximately proportional to the path difference. The distance between the image (the first minimum) and the center of the screen is \(3.70\; \rm cm\) when the path difference is \(\lambda / 2\). The path difference required for the first maximum is twice as much as that. Therefore, the distance between the first maximum and the center of the screen would be twice the difference between the first minimum and the center of the screen: \(2 \times 3.70\; \rm cm = 7.40\; \rm cm\).
Find the density of seawater at a depth where
the pressure is 188 atm if the density at the
surface is 1050 kg/m3
. Seawater has a bulk
modulus of 2.3 × 109 N/m2
.
Answer in units of kg/m3.
The density of seawater at that depth is 1058.73 kg/m³
What is bulk modulus ?A substance's bulk modulus is a gauge of how resilient it is to compression. It is described as the ratio of the ensuing relative volume drop to the infinitesimal pressure rise.
Mathematically Bulk modulus can be defined as:
K = ρ dP/dρ
Hence, integrate and get:
ρ = ρ₀e^(p/K)
The density at the surface is 1050 kg/m³.
The bulk modulus = 2.3 × 10⁹ N/m²
Now put the values and get:
the density of seawater at that depth = 1050 × e^(188×101325 ÷ 2.3 × 10⁹)
= 1058.73 kg/m³
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The density of seawater at a depth of where the pressure is 188 atm with a surface density of 1050 Kg/m³ is 1058.5 kg/m³.
What is density ?The density of a substance is the measure of its mass per unit volume. It depends on the pressure, temperature and bond type of the substance.
The relation between the density at a depth in water to the surface density, pressure and bulk modulus is given by:
ρ = ρ0 (1+ ΔP/B)
Given ρ0 = 1050 kg/m³
pressure at depth = 188 atm
surface pressure = 1 atm
bulk modulus B = 2.3 × 10⁹ N/m²
Then,
ρ = 1050 kg/m³ (1 + (188- 1 atm) × 10⁵/2.3 × 10⁹ N/m²)
= 1058.5 kg/m³.
Therefore, the density of sea water at the given depth is 1058.5 kg/m³.
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Please help! quick and easy chart.
Answer:
sound and happiness are not matter
Explanation:
the 0.5-kg flyballs of a centrifugal governor revolve at a constant speed v in the horizontal circle of 152-mm radius shown. neglecting the mass of links ab, bc, ad, and de, and requiring that the links support only tensile forces, determine the range of the allowable values of v so that the magnitudes of the forces in the links do not exceed 75 n.
The horizontal circle with a radius of 153 mm shows the rotational speed of the 0.5 kilogram flyballs of a spinning governor. The requirement that the mass of linkages Ba, BC, AD, and DE be ignored and the
What is an object's speed?
This rate by which an object moves a distance can be understood of as its speed. A slow-moving object travels a relatively short distance in a given length of time, whereas a fast-moving object travels a big distance in a short amount of time.
What does speed look like mathematically?
Speed is mathematically represented as follows: Distance dimension formula: M0L1T0 Time has the following dimensions: M 0 L 0 R 1. By dividing the dimensional formulas for time and distance, we arrive to the following result:
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what is Ethyl butyrate used for
Answer:
Ethyl butyrate is used as an artificial flavoring resembling orange juice or pineapple in alcoholic beverages, as an ingredient of fragrance, and as a solvent and plasticizer for cellulose. It is also used in the production of polyvinyl butyral (PVB).
Explanation: