Answer:
if the frequency of the wave if tripled then period of wave gets tripled
When the wave frequency is tripled, the period of the wave becomes one-third of its original.
Relationship between frequency and period of a waveThe frequency (f) of a wave is inversely proportional to the period (T) of the wave.
Mathematically,
\($f \propto \frac{1}{T}$\)
Thus, when frequency increases, the period decrease and when frequency decreases, the period of the wave increases.
So when frequency of a wave increases by three time, the period of the wave decreases by three times.
Hence, when the frequency is tripled, the period of the wave becomes one-third of its original value.
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Find Density of a cylinder with diameter of 5.0 cm and height of 12.0cm and mass of 600.0g
Answer: 2.55 g/cm^3
Explanation:
density is defined as:
Density = mass/volume
Now, the mass of the cylinder is 600g
and the volume of a cylinder is:
V = pi*r^2*h
where r is the radius (half of the diameter), here r = (5/2)cm and h is the height, here 12 cm
So the volume is:
V = 3.14*(2.5cm)^2*12cm = 235.5cm^3
then the density is:
D = 600g/235.5cm^3 = 2.55 g/cm^3
A 215 N sign is supported by two ropes. One rope pulls up and to the right 1=29.5∘ above the horizontal with a tension 1 , and the other rope pulls up and to the left 2=44.5∘ above the horizontal with a tension 2 , as shown in the figure. Find the tensions 1 and 2 .
The sign is held in equilibrium. Using Newton's second law, we set up the equations of the net forces acting on the sign in the horizontal and vertical directions:
∑ F (horizontal) = T₁ cos(29.5°) - T₂ cos(44.5°) = 0
(right is positive, left is negative)
∑ F (vertical) = T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N = 0
(up is positive, down is negative)
Solve the system of equations. I use elimination here:
• Multiply the first equation by sin(29.5°) and the second by cos(29.5°):
sin(29.5°) (T₁ cos(29.5°) - T₂ cos(44.5°)) = 0
cos(29.5°) (T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N) = 0
T₁ cos(29.5°) sin(29.5°) - T₂ cos(44.5°) sin(29.5°) = 0
T₁ cos(29.5°) sin(29.5°) + T₂ cos(29.5°) sin(44.5°) = (215 N) cos(29.5°)
• Subtract the first equation from the second to eliminate T₁ :
T₂ cos(29.5°) sin(44.5°) - (- T₂ cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)
• Solve for T₂ :
T₂ (cos(29.5°) sin(44.5°) + cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)
T₂ sin(74.0°) = (215 N) cos(29.5°)
… … … (using the fact that sin(x + y) = sin(x) cos(y) + cos(y) sin(x))
T₂ = (215 N) cos(29.5°) / sin(74.0°)
T₂ ≈ 195 N
• Solve for T₁ :
T₁ cos(29.5°) - T₂ cos(44.5°) = 0
T₁ cos(29.5°) = T₂ cos(44.5°)
T₁ = T₂ cos(44.5°) / cos(29.5°)
T₁ ≈ 160. N
this is a FRQ test for AP Physics I NEED IT DONE IN 2 HOURS: A dart with mass md
is launched toward a block of mass mb
that is suspended from a string of length L, as shown at left above. The dart is moving horizontally with speed v immediately before it strikes the block and remains embedded. The dart-block system then swings up to a point at which its center of mass reaches a maximum height H above its starting position, as shown at right above. The block’s mass mb
is greater than the dart’s mass md
.
(a) Indicate which object, the dart or the block, if either, experiences an impulse of larger magnitude during the collision. If the impulse is the same magnitude for both objects, state this explicitly. Briefly explain your reasoning.
The dart experiences an impulse of larger magnitude during the collision. This is because the dart has less mass than the block, so the same amount of momentum change will result in a larger impulse.
What is momentum ?Momentum is a physical concept that describes the tendency of an object to remain in motion with the same speed and direction unless it is acted on by an outside force. It is a measure of an object's inertia and is often expressed as the product of its mass and velocity. Momentum is a vector quantity, meaning that it has both magnitude and direction. Momentum is conserved in closed systems, meaning that the momentum before an interaction is equal to the momentum after the interaction. This is known as the law of conservation of momentum and can be used to solve many problems involving collisions and other interactions between objects.
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motion.
The motion of an object thrown at an angle is
O A. vertical
O B. horizontal
O C. vector,
O D. projectile
A 12-V battery is connected to an air-filled capacitor that consists of two parallel plates,
each plate has an area of 7.60 cm2
. The separation between the plates of the capacitor is d =
0.30 cm. (Assume the electric field between the plates to be uniform).
a. Draw the situation.
b. Find the magnitude of the electric field between the plates.
Now, a proton (q = 1.6 x10-19 C) is released from rest at the positive plate of the capacitor.
c. Calculate the electric potential energy gained by the proton just before it touches the negative
plate.
A slab of Teflon of dielectric constant k =2.1 is then inserted between the plates of the
capacitor.
d. What is the new capacitance of the capacitor?
e. Calculate the change in the total energy stored in the capacitor before and after inserting the
dielectric slab.
Answer:
E = 4000 V / m
U = 1.92*10^-18 J
C' = 4.71 pF
1.2 times greater with di-electric
Explanation:
Given:-
- The potential difference between plates, V = 12 V
- The area of each plate, A = 7.6 cm^2
- The separation between plates, d = 0.3 cm
- The charge of the proton. q = 1.6*10^-19 C
- The initial velocity of proton, vi = 0 m/s
Solution:-
- The electric field ( E ) between the parallel plates of the air-filled capacitor is determined from the applied potential difference by the battery on the two ends of the plates.
- The separation ( d ) between the two plates allows the charge to be stored and the Electric field between two charged plates would be:
E = V / d
E = 12 / 0.003
E = 4,000 V/m ... Answer
- The amount of electrostatic potential energy stored between the two plates is ( U ) defined by:
U = q*E*d
U = (1.6 x10^-19)*(4000)*(0.003)
U = 1.92*10^-18 J ... Answer
- The electrostatic energy stored between plates is ( U ) when the proton moves from the positively charges plate to negative charged plate the energy is stored within the proton.
- A slab of di-electric material ( Teflon ) is placed between the two plates with thickness equal to the separation ( d ) and Area similar to the area of the plate ( A ).
- The capacitance of the charged plates would be ( C ):
C = k*ε*A / d
Where,
k: the di-electric constant of material = 2.1
ε: permittivity of free space = 8.85 × 10^-12
- The new capacitance ( C' ) is:
C' = 2.1*(8.85 × 10^-12) *( 7.6 / 100^2 ) / 0.003
C' = 4.71 pF
- The new total energy stored in the capacitor is defined as follows:
U' = 0.5*C'*V^2
U' = 0.5*(4.71*10^-12)*(12)^2
U' = 3.391 * 10^-10 J
- The increase in potential energy stored is by the amount of increase in capacitance due to di-electric material ( Teflon ). The di-electric constant "k" causes an increase in the potential energy stored before and after the insertion.
- Hence, the new potential energy ( U' ) is " k = 2.1 " times the potential energy stored in a capacitor without the di-electric.
why isn't direct current used in transformers
Answer:
No, it will not and this has a historical importance. The reason is that transformers work via induction of electrical forces by changes in magnetic fields, so the constat fields produced by dc currents won't work at all
Explanation:
Why is the Falcon 9 rocket so important in today's space exploration world?
It's the first rocket to have been built by robots, saving money for labor costs.
Carbon fiber is used on the outside, making it much more lightweight, requiring less fuel to launch it.
It was invented with the ability to recharge itself by using solar panels.
It's a reusable rocket and has saved money by being reused over 60 times already.
The Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.
option D.
Why is the Falcon 9 rocket so important in today's space exploration world?The Falcon 9 rocket, is developed by SpaceX, and it holds a significant importance in today's space exploration world due to several key features and achievements, and some of the importance include the following;
ReusabilityCost-effectivenessAdvancements in rocket technologyPayload capacity and versatilityInnovation and competitionFrom the given options, we can conclude that the Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.
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The speed-time graph above is for a motor cycle travelling along a road.
What is the motorcycle's maximum speed?
What is the acceleration during the first 10s?
. What is its deceleration during the last 5s?
• What distance is travelled during the first 10s?
. What is the total distance travelled?
. What is the time taken for the whole journey?
a. The motorcycle's maximum speed is 30m/s
b. The acceleration during the first 10s is 3m/s²
c. the deceleration during the last 5s is -5m/s²
d. The distance travelled during the first 10s is 300 meters
e. The total distance travelled is 750 meters
f. The time taken for the whole journey is 30 seconds
What is speed-time graph?A speed time graph is described as a graph that shows the motion of an object against time.
The speed-time graph is categorized into four segments and they include:
Speed-time graph with constant speed.Speed-time graph with constant acceleration.Speed-time graph with increasing acceleration.Speed-time graph when the object is decelerating.Learn more about Speed-time graph at: https://brainly.com/question/769606
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A force of 20 N is exerted on a box with a mass of 15 kg. if friction exerts a force of 4 N on the box, at what rate does the box accelerate?
Answer:
1.06 metres per second squared
Explanation:
since friction acts against foward force
20 N - 4 N = 16 N
use Newtons 2nd law F=ma Solve for a:
a= F÷m
= 16 ÷ 15
= 1.06 metres per second squared
In our simple system, what type of energy was used?
Type of energy was used is kinetic energy.
Obiects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the distance separating Objects 1 and 2 is tripled, then the new electrostatic force will be
__ units.
Objects 1 and 2 attract each other with an electrostatic force of 36.0 units. If the distance separating Objects 1 and 2 is tripled, then the new electrostatic force will be four units.
Coulomb's law can be expressed as:
F = k × (q1 × q2) / r²
In which:
F = electrostatic force
k = electrostatic constant (k = 9 × 10⁹ N·m²/C²)
q1 and q2 = the charges of the objects
r = distance between the objects
Let's consider that the initial electrostatic force in between objects 1 and 2 is 36.0 units.
F1 = 36.0 units
Next, if the distance is considered between the objects is tripled, the new distance (r') changes into three times the initial distance (r):
r' = 3 × r
To determine the new electrostatic force (F'), replacement r' into Coulomb's law:
F' = k × (q1 × q2) / (r')²
Place r' = 3r:
F' = k × (q1 × q2) / (3r)²
= k × (q1 × q2) / 9r²
The new force will be one-ninth (1/9) of the initial force since the electrostatic force (F') is directly proportional to (q1 q2) and inversely proportional to r2.
F' = (1/9) × F1
= (1/9) × 36.0
= 4.0 units
Thus, objects 1 and 2 attract each other with an electrostatic force of 36.0 units. If the distance separating Objects 1 and 2 is tripled, then the new electrostatic force will be 4 units.
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The timeline below shows some major discoveries in biology.
Which of the following theories did these discoveries lead to?
A.
the theory of evolution
B.
the cell theory
C.
the germ theory
D.
the atomic theory
Each piece has 15 of 4 meters of fabric.
Answer:
The cell theory
Explanation:
Answer:
The cell theory
Explanation:
A 5.0 "kilo" bag of sugar is on a counter. How much work is required to put the bag on a shelf at a distance of 0.33 m above the counter? answer in:____J
Given:
The mass of the sugar is m = 5 kg
The distance of the shelf from the counter is h = 0.33 m
Required: Work done to put the bag on a shelf above the counter.
Explanation:
The work done can be calculated by the formula
\(\begin{gathered} Work\text{ done = potential energy} \\ W=mgh \end{gathered}\)Here, g = 9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the work done will be
\(\begin{gathered} W\text{ =5}\times9.8\times0.33 \\ =16.17\text{ J} \end{gathered}\)Final Answer: The work done to put the bag on a shelf above the counter is 16.17 J.
PLS HELP!!
1. Radon-222 decays with a half-life of 3.82 days. If an initial sample of the element contains 1000 atoms, it takes ___ days for that sample to decay down to 125 atoms.
a. 2 days
b. 3 days
c. 4 days
d. 5 days
Answer: 3 days
Explanation:
The efficiency of a machine is 80%? What does it mean?
Answer:
It means how much input work you put into the machine, which then becomes output from the machine. So you're putting 80% of work into the machinie. To find the efficency of a machine, it's output divided by input work.
Explanation:
Answer:
efficiency is the ratio of the power ouput to the power input
Explanation:
It compares how much energy is used to do work versus how much is lost or wasted to the environment, the more efficient the machine, the less energy wasted.
EDGE
Follow-Up Questions Answer the following questions. 1. The accepted value for the index of refraction for water is 1.33. How does your value compare to the accepted value?
2. Why do you think there is a difference between your value for the index of refraction for water and the accepted value?
The index of refraction is the ratio of the speed of light in a vacuumto the speed of light in a medium
What is the index of refraction?The question is incomplete but I will like to highlight a few facts to help you understand the concept of the index of refraction.
The ratio of the speed of light in a vacuum (c) to the speed of light in a medium (c') is known as the index of refraction (n).
The propagation vector in the new medium has a different angle with respect to the normal as a result of this difference in speed when light travels from one medium to another at an angle.
A material's refractive index serves as a gauge for how light moves through it. Light travels more slowly at higher refractive indices, which results in a proportionally greater change in the direction of the light within the substance.
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1. A 20 Ohm resistor and a 5 Ohm lamp are connected in a single path, with a 50 amps.
What type of circuit is this:
What is the total resistance of the circuit?
What is the total voltage in this circuit?
What is the current?
The circuit given is a series resistance circuit.
1) The given circuit is a series resistance circuit.
2) Resistance, R₁ = 20 Ω
Resistance, R₂ = 5 Ω
The effective resistance of the circuit is given by,
Reff = R₁ + R₂
Reff = 20 + 5
Reff = 25 Ω
3) Total resistance of the circuit, R = 25 Ω
Current flowing through the circuit, I = 50 A
Therefore, the voltage across the circuit is,
V = IR
V = 50 x 25
V = 1250 V
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A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
3.13 m/s2
4.22 m/s2
5.31 m/s2
6.67 m/s2
none of the above
y(t) = -4 + Cos (2A10t - π/4)- Sin (2π20t)
i. Complete the energy and power
ii. Draw the spectrum of y(t)
The average power of the signal Y(t) is approximately 4.166 W.
The energy of the signal Y(t) over one period is approximately 0.833 J.
How to calculate the energyWe can calculate the average power:
P = (1/T) ∫0ⁿ |Y(t)|² dt
P = (1/0.1) ∫_0⁰¹ [(-4 + Cos(2π10t - π/4)) + Si²(2π20t)] dt
P = 2 ∫0⁰¹[16 + Cos²(2π10t - π/4) - 8Cos(2π10t - π/4)] dt
P = 2 [16t + (1/2)(t/2 + Sin(4π10t - π/2))/20 - 4Sin(2π10t - π/4)]0⁰₁
P ≈ 4.166 W
We can calculate the energy:
E = ∫-∞^∞ |Y(t)|² dt
E = T ∫0ⁿ |Y(t)|² dt
E = 0.1 ∫0^⁰¹ [(-4 + Cos(2π10t - π/4))² + Sin²(2π20t)] dt
E = 0.2 ∫0⁰¹ [16 + Cos²(2π10t - π/4) - 8Cos(2π10t - π/4)] dt
E = 0.2 [16t + (1/2)(t/2 + Sin(4π10t - π/2))/20 - 4Sin(2π10t - π/4)]0⁰¹
E ≈ 0.833 J
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Mark weighs 375 N and is carrying a full-sized cello as he climbs the stairs to a height of 4 m. It takes him 3 seconds to do this.
How does the amount of work he does change if he were to climb the same flight of stairs again in the same amount of time, but this time without the cello?
A) It depends on the weight of the cello.
B) It remains the same.
C) It increases
D) It decreases.
Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.
The correct answer is option D.
The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :
Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).
When Mark climbs the stairs with the cello, he is doing work against the force of gravity.
The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.
Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.
Therefore, mark's work decreases.
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determine the direction of the electric field at the given observation points (point p) inside insulators and conductors with charge distributions as shown.
In insulator electric field is zero and direction of electric field is away from the center.
In a insulator (dielectric) there are no (not very many) portable charge transporters thus the outer electric field mutilates the electron shells around the cores so the iota behaves like a dipole.
Every one of the electrons are as yet bound to cores yet the "middle" of the electron cloud is as of now not incidental with the place of the core.
The actuated dipoles are arranged and produce a prompted electric field contrary to the initiating electric field. The general permittivity of the medium is a proportion of how well the initiated field goes against the outer inciting field.
So the higher the permittivity the more modest is the electric field inside the protector.
Affected by an outer electric field the versatile charge transporters in a transmitter improve themselves (the portable charge transporters really move inside the grid) so the prompted electric field that they produce is equivalent in extent and inverse in heading to the outside initiating field with the outcome that there is no electric field inside the channel - relative permittivity is boundless.
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Please help and if you get this and answer the other one on my thing i’ll give u brainliest
How does increasing the energy of a wave affect its wavelength?
The increase in energy causes an increase in wavelength.
The shorter the wavelength, the lower the energy.
The higher the energy, the shorter the wavelength.
There is no relationship between energy and wavelength.
Answer:
The higher the energy, the shorter the wavelength.
Explanation:
Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.
Answer:
Current = 10 Amperes.
Explanation:
Given the following dat;
Quantity of charge, Q = 36 kilocoulombs (KC) = 36 * 1000 = 36000C
Time = 1 hour to seconds = 60*60 = 3600 seconds
To find the current;
Quantity of charge = current * time
Substituting in the equation
36000 = current * 3600
Current = 36000/3600
Current = 10 Amperes.
A plane wishes to fly due north to an airport which is 205 km away. The plane can fly at a speed in still air of 220 km/h. A wind of 43 km/h blows from east to west.
a. In which direction,relative to north, should the plane head to reach it’s destination?
b. How long does this take?
Answer:
nique ta mama
Explanation:
Why are hydraulic brakes used?
Answer:
Hydraulic brake systems are used as the main braking system on almost all passenger vehicles and light trucks. Hydraulic brakes use brake fluid to transmit force when the brakes are applied.
Explanation:
Which of the following methods of sound localization between the two ears can we rely on for tones of very low frequencies? -Interaural time differences -Interaural level differences -Interaural frequency differences -Interaural echo differences More than one of the above
According to Doerbecker and Ernst (1996) and Francart et al. (2011), interaural time difference (ITD) and interaural level difference (ILD) are the two primary auditory cues used by binaural hearing. The delay between each ear is known as ITD.
What technique best localizes sound between the two ears?
Rayleigh's view of horizontal sound localization has come to be known as the “duplex” theory: that sound localization at low frequencies relies on differences in phase at the two ears, or ITDs, and that high-frequency localization relies on interaural differences in sound level (ILDs).
What two variables affect sound localization?
The variation in the loudness of the sound in each ear and the time it took for the sound to reach each ear are two elements that affect how the sound is localized.
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25 points!
A 6 kg object accelerates from 5 m•s to 25 m•s in 30 seconds. What was the net force acting on the
object? Give your answer in Newtons to one significant figure and without a unit.
(Show Work)
Answer:
6N
Explanation:
Given parameters:
Mass of object = 6kg
Initial velocity = 5m/s
Final velocity = 25m/s
Time = 30s
Unknown:
Net force acting on the object = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
Acceleration is the rate of change of velocity with time
Acceleration = \(\frac{Final velocity - Initial velocity }{time}\)
Force = mass x \(\frac{Final velocity - Initial velocity }{time}\)
So;
Force = 6 x \(\frac{25 - 5}{30}\) = 6N
If the Hawaiian Islands were formed from a moving crustal plate over a hot spot, which direction was the plate
moving?
O East
O West
O Southwest
Northwest
M
An 80% furnace's discharge air temperature is 125 degrees F and is adding heat to a space at the rate of 80,000 BTU's an hour. What is the input rating of the furnace?
a. 60,000 Btu's
b. 120,000 Btu's
c. 75,000 Btu's
d. 100,000 Btu’s
D. The input rating of the furnace is determined as 100,000 BTU.
What is input rating?
Input power rating means the power, expressed in Watts or one of its multiples, for which the energy storage unit has been designed to operate at nominal conditions.
eff = (output rating / input rating) x 100%
80/100 = 80,000 BTU / input rating
0.8 = 80,000 BTU / input rating
input rating = 80,000 BTU/0.8
input rating = 100,000 BTU
Thus, the input rating of the furnace is determined as 100,000 BTU.
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HELP
Particles.q₁-75.8
μC, q2 +90.6.μC, and
93 = -84.2 μC are in a line. Particles q₁ and q2 are
separated by 0.876 m and particles q2 and q3 are
separated by 0.432 m. What is the net force on
particle q3?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-75.8 μC
91
0.876 m
+90.6 μC
+92
0.432 m
–84.2 μC
93
The net force on particle q3 is approximately -0.337 N.
To determine the net force on particle q3, we need to calculate the forces exerted on it by particles q₁ and q2.
The force between two point charges can be found using Coulomb's law, which states that the force (F) between two point charges is directly proportional to the product of their charges (q₁ and q₂) and inversely proportional to the square of the distance (r) between them.
Mathematically, Coulomb's law can be expressed as:
F = k * (q₁ * q₂) / r²
Where k is Coulomb's constant, which is equal to 9 × 10^9 N⋅m²/C².
Using this formula, we can calculate the forces between the particles:
Force between q₁ and q3:
F₁₃ = k * (q₁ * q₃) / r₁₃²
F₁₃ = 9 × 10^9 * (-75.8 × 10^-6) * (-84.2 × 10^-6) / (0.432)^2
F₁₃ ≈ 0.465 N (pointing to the left)
Force between q₂ and q3:
F₂₃ = k * (q₂ * q₃) / r₂₃²
F₂₃ = 9 × 10^9 * (90.6 × 10^-6) * (-84.2 × 10^-6) / (0.876 + 0.432)^2
F₂₃ ≈ 0.128 N (pointing to the left)
The net force on particle q3 is the vector sum of these two forces, which are pointing in opposite directions:
F_net = F₂₃ - F₁₃
F_net ≈ 0.128 N - 0.465 N
F_net ≈ -0.337 N (pointing to the left)
Therefore, the net force on particle q3 is approximately -0.337 N, which means it is being pulled to the left by the other two particles.
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