If the hydraulic lift in question 1 needs to lift a car with a weight of 6000 N, what is the surface area of the lifting platform to balance the pressures?Question 1 for reference:1.If a hydraulic lift uses a force of 400 N on a piston of area 0.065 m2, what is the pressure on the piston? (10 points) Approximately 6153.84 Pa

Answer:

the mass of the car is 890 kg

Explanation:

Given;

mass of the man, m = 92 kg

displacement of the car's spring, x = 4.5 cm = 0.045 m

acceleration due to gravity, g = 9.8 m/s²

The spring constant of the car,

f = kx

where;

f is the weight of the man on the car = mg

mg = kx

k = mg/x

k = (92 x 9.8) / 0.045

k = 20,035.56 N/m

The angular speed of car, ω, when the is inside is given as 4.52 rad/s

The total mass of the car and the man is calculated as;

\(\omega = \sqrt{\frac{k}{m} } \\\\\omega^2 = \frac{k}{m} \\\\m = \frac{k}{\omega^2} = \frac{20,035.56}{(4.52)^2} = 980.7 \ kg\)

The mass of the car alone = 980.7 kg - 92 kg

                                            = 888.7 kg

                                             ≅ 890 kg

Therefore, the mass of the car is 890 kg

We can use the formula:

velocity = distance / time

To find the velocity of the supersonic jet.

The distance traveled by the jet is 1,000 kilometers, and the time taken is 0.5 hours. So:

velocity = 1,000 km / 0.5 hours

velocity = 2,000 km/hour

Now, we need to find the velocity of the airplane that the jet passed during its flight. The airplane's velocity is given as 903 km/hour.

Since the jet and the airplane were traveling in opposite directions, we can add their velocities to find the relative velocity between them:

relative velocity = velocity of jet + velocity of airplane

relative velocity = 2,000 km/hour + 903 km/hour

relative velocity = 2,903 km/hour

So, the velocity of the supersonic jet is 2,000 km/hour.

Answer:

FRANZ REULEAUX

Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.

Answer:

un café y a seguir pensando porque no se la respuesta xd

The force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is 12.4 N.

Start by calculating the change in velocity (Δv) experienced by the object. This can be done by subtracting the initial velocity v₁ from the final velocity v.

Δv = v - v₁ = ((8î + 3) - 5k) - ((4î - 5) + 3k)

= 8î + 3 - 5k - 4î + 5 - 3k

= 4î - 8k + 8

Next, calculate the acceleration (a) using the formula:

a = Δv / t

where t is the time interval, given as 10 seconds.

a = (4î - 8k + 8) / 10

= (0.4î - 0.8k + 0.8) m/s²

The force (F) required to accelerate the object can be found using Newton's second law:

F = m * a

where m is the mass, given as 40 kg.

F = (40 kg) * (0.4î - 0.8k + 0.8) m/s²

= (16î - 32k + 32) N

Simplify the expression to obtain the final answer:

F = 16î - 32k + 32 N

≈ 12.4 N

Therefore, the force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is approximately 12.4 N.

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Answer:

i cant see it

Explanation:

sorry maybe try to show us a different way?

The magnitude of the force exerted by the fish is 3,052.5 N.

The given parameters;

According to Newton's third law, the force exerted by the reel is equal in magnitude to the force fish exerted on the reel.

The centripetal force of the reel = force exerted by the fish

\(F_c = m\omega^2 r\\\\F_c = 0.652 \times (306)^2 \times 0.05\\\\F_c = 3,052.5 \ N\)

Thus, the magnitude of the force exerted by the fish is 3,052.5 N.

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Answer: OB The pressure on the water decreased.

Explanation:Under normal conditions, water boils at 100°C. When these conditions are changed, water can boil at a lower temperature. One of the conditions that impacts water's boiling point is pressure. If the pressure on water is decreased below the normal level, water will boil at a lower temperature.

Answer:

a. 7.96 W/m² b. i. 0.205 V/m ii. 0.68 nT

Explanation:

(Part a) Calculate I, the intensity of the light incident on your book?

Intensity, I = Power, P/Area,A

I = P/A where P = 100 W and A = 4πr² where r = distance of source from book = 1 m.

So, I = P/A

= 100 W/4π(1 m)²

= 25/π W/m²

= 7.96 W/m²

(Part b) Find Eo and Bo, the amplitude of the electric and the magnetic fields of the EM waves emitted by the lamp.

i. Eo the amplitude of the electric field

Intensity, I = E²/cμ₀ where E = r.m.s value of electric field, c = speed of light = 3 × 10⁸ m/s and μ₀ = permeability of free space = 4π × 10⁻⁷ H/m

Thus, E =  √(I/cμ₀)

substituting the values of the variables into the equation, we have

E =  √(I/cμ₀)

E =  √(7.96 W/m²/[3 × 10⁸ m/s × 4π × 10⁻⁷ H/m])

E =  √(7.96 W/m²/120π H/s)

E =  √(0.0211 Ws/Hm²)

E = 0.145 V/m

Now E = E₀/√2 where E₀ = maximum value of electric field

So, E₀ = √2E

= √2 × 0.145 V/m

= 0.205 V/m

ii. Bo the amplitude of the magnetic field

Since c =  E₀/B₀ where c = speed of light = 3 × 10⁸ m/s

B₀ = E₀/c

= 0.205 V/m ÷ 3 × 10⁸ m/s

= 0.068 × 10⁻⁸ T

= 0.68 × 10⁻⁹ T

= 0.68 nT

Answer: you have to divide and multiple fam

Explanation:

The magnitude of the force acting at point O is determined as 240 N.

The magnitude of the force at point O is calculated by applying the principles of moment as shown below.

sum of the clockwise moment = sum of the anticlockwise moment

F₀(2 m + 2m + 2m) = 260 N (2m + 2 m ) +  200 N ( 2 m )

where;

6F₀ = 260 (4) + 200(2)

6F₀ = 1,440

F₀ = 1440 / 6

F₀ = 240 N

Thus, the magnitude of the force acting at point O is determined as 240 N.

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science is all about the world around us

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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The particle B will pass particle A in 1.10s.

Using kinematic formula,

d = Vini x t + 1/2 at²

where,

d is distance

Vini is velocity initial

a is acceleration

t is time

So, putting values

7.7 t + 1/2 x 1.8 t^² = 2.9 t + 1/2 x 5.7 t²

7.7 t + 2.7 t² = 2.9 t + 8.55 t²

t + t² / t + t² = 2.9 + 8.55 / 7.7 + 2.7

t = 1.10s

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Answer:

Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.

Answer:

35 N to the left

Explanation:

Do 65 minus 30, and you get 35 N to the left

Because force is a vector quantity, you have to mention both magnitude and direction in your answer.

Answer:

See below

Explanation:

F = C q1 q2 /r^2

    8.988 x 10^9   *   (1.60217 x 10^-19)^2 / ( 5.29 x 10^-11)^2 =

.00000008244 N

82.4   nano N

The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N

We'll begin by obtaining the mass of the rover vehicle. This is shown below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

Divide both sides by g

m = W /g

m = 37 / 3.72

m = 9.95 Kg

Now, we shall determin the weight of the rover vehicle on Earth. Details below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 9.95 × 10

Weight = 99.5 N

Thus, we can conclude that the weight on Erath is 99.5 N

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Answer:

D

Explanation:

Answer:It is a combination reaction; nitrogen and hydrogen combine to form ammonia

Explanation:

This is the reaction that is used to make ammonia from hydrogen and nitrogen. In this reaction, only one product is formed. Therefore, this reaction is known as a combination reaction.

Answer:

D - Water

Explanation:

Answer:

Lower

Lower

gsintheta (gsinθ)

Explanation:

The sum of forces resolved parallel to the inclined plane is given by;

F - mgsinθ = 0

ma - mgsinθ = 0

ma = mgsinθ

a = gsinθ

Acceleration is proportional to angle of inclination, thus the lower the angle of the slope, lower the acceleration along the ramp.

therefore, the speed at the bottom of a slope will be lower, (velocity is directly proportional to acceleration) and, consequently, the control will be better.

The acceleration along the ramp, is gsintheta (gsinθ)

Answer:

A burning candle. (chemical energy into energy of heat and light, i.e. thermal and wave)

Explanation:

different amounts of sunlight can be conducted throughout the world but some special are

Explanation:

take bisc(*- calcoihvx to ordz which makes to easy

Photosynthesis can be quantified exposing the plants to different amounts of sunlight.

It is defined as a process by which plants and other photosynthetic organisms convert the light energy in to chemical energy  through the process of cellular respiration.

Some of the energy which is converted  is stored in molecules of carbohydrates like sugar and starches  which are made up of from carbon dioxide and water . Photosynthetic organisms which can perform photosynthesis  are algae and cyanobacteria. Photosynthesis is largely responsible for producing and maintaining the content of oxygen in earth's atmosphere.

The process begins with proteins absorbing light energy  which are called reaction centers and contain a green pigment which is called chlorophyll . In plants ,these pigments are present inside organelles called chloroplasts while in bacteria they are present in plasma membrane.

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36.0 g water is to be heated through a

As per specific heat capacity ,42,638 J/Kg°C energy is required to raise the temperature by 9°C.

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

For the given question, it is calculated by substituting the values  in the given formula,

Q=30×4.2×282

=42,638 J/Kg°C

Thus, 42,638 J/Kg°C  of energy is required for raising the temperature by 9°C.

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Snell's law states:

n₁ * sin(θ₁) = n₂ * sin(θ₂),

where n₁ and n₂ are the refractive indices of the first and second medium, respectively, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.

In the Roman soldier model for refraction, the soldiers appear to be walking at an angle that is different from their actual direction of motion due to the bending of light at the interface between two media with different refractive indices.

Assuming that the soldiers entered the interface at an angle of 45 degrees, the angle at which they appear to be walking will depend on the refractive indices of the two media and the angle of incidence.

Since we are not given any information about the refractive indices of the media, we cannot determine the angle at which the soldiers appear to be walking. Therefore, the answer is D. Not enough info.

Answer:

The value is \(v_2 = 5.53 \ m /s\)

Explanation:

From the question we are told

  The pipe diameter at location 1 is  \(d = 8.8 \ cm = \frac{8.8 }{10} = 0.88 \ m\)

   The velocity at location 1 is  \(v_1 = 2.4 \ m /s\)

   The diameter at location 2 is  \(d_2 = 5.80 \ cm = 0.58 \ m\)

Generally the area at location 1 is  

       \(A_1 = \pi * \frac{d^2}{ 2}\)

=>     \(A_1 = \pi * \frac{0.88^2}{ 2}\)

=>     \(A_1 = 3.142 * \frac{0.88^2}{ 2}\)

=>     \(A_1 = 1.2166 \ m^2\)

Generally the area at location 1 is  

       \(A_2 = \pi * \frac{d_1^2}{ 2}\)

=>     \(A_2 = \pi * \frac{0.58^2}{ 2}\)

=>     \(A_2 = 0.528 \ m^2\)

Generally from continuity equation we have that

     \(A_1 * v_1 = A_2 * v_2\)

=>   \(1.2166 * 2.4 = 0.528 * v_2\)

=>   \(1.2166 * 2.4 = 0.528 * v_2\)

=>    \(v_2 = 5.53 \ m /s\)

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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