If the initial velocity of an object is upward in the positive direction, what must the sign of the acceleration due to gravity be in a calculation?
Answers
Therefore, the direction of motion is positive for upward motion if an object is travelling vertically up. Since gravity accelerates downhill, it is assumed that this acceleration is negative.
Depending on the sign convention you desire to adhere to, the sign of the acceleration caused by gravity (g) might be either positive or negative. G will be positive if you decide to make the downward direction positive and the upward direction negative (an often-used convention). The thing is either standing still or descending. The initial velocity of an object is zero meters per second if it is dropped from a height rather than being hurled.
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Related Questions
how much voltagr is required to make 4 amperes flow throgh a resistance of 20 ohms?
Answers
To make 4 amperes flow through a resistance of 20 ohms, 80 volts of voltage are required.
Ohm's law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. In other words, the greater the voltage, the greater the current that flows through a given resistance.
The voltage required to make 4 amperes flow through a resistance of 20 ohms can be calculated using Ohm's law:
Voltage (V) = Current (I) x Resistance (R)
Therefore, V = 4 A x 20 Ω = 80 V
So, to make 4 amps flow through a resistance of 20 ohms, 80 volts of electricity are required.
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A massless spring with force constant
580 N/m is fastened at its left end to a vertical
wall, as shown below.
The acceleration of gravity is 9.8 m/s
2
.
7 kg 5 kg
580 N/m
Initially, the 7 kg block and 5 kg block rest
on a horizontal surface with the 7 kg block in
contact with the spring (but not compressing
it) and with the 5 kg block in contact with the
7 kg block. The 7 kg block is then moved to
the left, compressing the spring a distance of
0.2 m, and held in place while the 5 kg block
remains at rest as shown below.
7 kg 5 kg
k 0.2 m
Determine the elastic energy U stored in
the compressed spring.
Answer in units of J.
Answers
The elastic potential energy stored in the compressed spring is determined as 11.6 J.
What is the elastic potential energy of the spring?
The elastic potential energy of the spring is the energy stored in the spring and the magnitude is calculated as follows;
U = ( ¹/₂kx² )
where;
k is the spring constantx is the extension of the springThe given parameters include the following;
the spring constant, k = 580 N/m
the extension of the spring, x = 0.2 m
Substitute the given parameters and solve for the elastic potential energy stored in the spring based on the compression produced by the two blocks.
U = ( ¹/₂kx² )
U = ( ¹/₂ ( 580 N/m ) ( 0.2 m )² )
U = 11.6 J
Thus, the elastic potential energy stored in the compressed spring is a function of the spring constant and extension of the spring.
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True or false.
a-
Magnetic force is a force acting from a
distance.
Answers
I need help with question 8 it is about distance and displacement
Answers
ANSWER:
Distance = 9 km
Displacement = 9 km east
STEP-BY-STEP EXPLANATION:
When we speak of distance we refer to the length between any two points in space, while displacement refers to the distance from an initial position to a final position regardless of the path.
In this case, being in the same direction, the displacement and distance are the same (in magnitude).
Therefore:
\(\begin{gathered} \text{ distance = 5 km + 4 km = 9 km} \\ \text{displacement = (5 km + 4 km) - 0 km = 9 km direction east } \end{gathered}\)An astronaut is floating in space with a velocity of zero. The astronaut has a total mass of 200 kg. They are holding a 5 kg ball, which they throw at a speed of 20 m/s.
question: Calculate the astronaut's velocity be after throwing the ball, in m/s. (Consider the direction the astronaut is facing to be the positive direction.)
Answers
With a total mass of 200 kg and a velocity of zero, an astronaut is floating in space while tossing a 5 kg ball at a velocity of 20 m/s. After hurling the ball, the astronaut's velocity is -0.04 m/s.
Describe momentum.Momentum is referred to as an object's rate of motion. It is the result of the mass and the velocity of the object. Linear momentum is another name for this concept. The kilogram-meter-per-second (abbreviated as kgm/s) is the SI unit for momentum.
The astronaut and the ball together weigh 205 kg (200 + 5 kilogramme).
The astronaut's initial velocity, v1, is zero because they are at rest.
200 kilogrammes is the astronaut's mass (m1).
The ball weighs 5 kg/m2.
The ball's velocity, v2, is 20 m/s.
The astronaut-ball system experiences no outside forces, hence its momentum is conserved. Before tossing the ball, the system has no net momentum. As a result, after the ball is thrown, the system's overall momentum is also zero.
Let v represent the astronaut's speed after throwing the ball.
The momentum of the astronaut and ball system after the ball is thrown is given by
(200 kg) v + (5 kg) v (-20 m/s) = 0
200 v = 5 * 20
v = 5*20/200 v = 0.5 m/s.
Therefore, the astronaut's velocity after throwing the ball, in m/s is -0.04 m/s (-0.5 m/s in the backward direction).
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Which of the following led a daring raid on British ports to help the Patriots with their war?
A.John Paul Jimenez
b. John Paul Jones
c.John Henry
d. John Smith
Answers
Obtain a pillow made of foam rubber. Press
down hard with your two hands on the surface
of the pillow. Then withdraw your hands
Describe what happened to its shape while you
pushed hard on the pillow and when you
withdrew your pushing. Repeat this activity on
a piece of rectangular block of wood and a
plasticine. Note the different effects.
Answers
Answer: Only foam rubber is compressible material
Explanation:
The pillow is made up of foam rubber which can be compressed easily due to the soft compressible rubber with hands on application of pressure on the surface. The shape of pillow regain its original shape when the pressure is withdrawn from the pillow. If the same activity is performed on the piece of rectangular block of wood and plasticine. Then the rectangular block of wood cannot be compressed with hand as it is a solid body. Plasticine is a putty like material. It is a clay like material and it can be compressed with hand but when the pressure is withdrawn the plasticine does not regain its shape back.
A bridge is constructed above a river such that an object dropped from it will reach the river after 4.5 seconds. A precocious youth takes a small stone and throws it downwards with some negative inital velocity so that it hits the river afer only 3 seconds. With what final velocity will the thrown stone hit the water?
Answers
Answer:
Vf = 11.04 m/s
Explanation:
First, we consider free fall motion with zero initial velocity. Using 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height of bridge = ?
Vi = Initial Speed = 0 m/s
t = time taken = 4.5 s
g = 9.8 m/s²
Therefore,
h = (0 m/s)(4.5 s) + (1/2)(9.8 m/s²)(4.5 s)²
Therefore,
h = 99.225 m
Now, we consider the forced motion when the youth throws the ball with some negative initial energy:
Vi = - Vi
t = 3 s
h = 99.225 m
Therefore,
99.225 m = - Vi(3 s) + (1/2)(9.8 m/s²)(3 s)²
Vi = (- 99.225 m + 44.145 m)/3 s
Vi = - 18.36 m/s
Now, we use this in 1st equation of motion for final velocity:
Vf = Vi + gt
Vf = -18.36 m/s + (9.8 m/s²)(3 s)
Therefore,
Vf = 11.04 m/s
Beginning: Identify the above circuits (A and B) as either a series or parallel circuit.
Answers
A diverging lens with a focal length of -30 cm is placed in front of a converging lens with a focal length of 60 cm. The lenses are 40 cm apart. A 6.0 cm tall object is 20 cm behind the diverging lens. 6. Where is the final image located (relative to the second lens) after the light passes through both lenses (in units of cm)? (A) 10 (B) 15 (D) 30 (E) 35
Answers
The final image is located 30 cm relative to the second lens.
First, we need to find the image location created by the diverging lens (first lens) using the lens formula: 1/f = 1/u + 1/v, where f is the focal length, u is the object distance, and v is the image distance.
For the diverging lens, f = -30 cm and u = -20 cm. Solving for v, we get an image distance of -60 cm relative to the first lens.
Next, we determine the object distance for the converging lens (second lens).
The lenses are 40 cm apart, and the first image is 60 cm behind the diverging lens, so the object distance for the second lens is 20 cm. The focal length of the converging lens is 60 cm.
Using the lens formula, we solve for the image distance (v) and find that it is 30 cm relative to the second lens.
Summary: By calculating the image distance for both lenses, we determine that the final image is located 30 cm relative to the second lens (converging lens). The correct answer is (D) 30.
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Suppose that you have left a 200-mL cup of coffee sitting until it has cooled to 30âC , which you find totally unacceptable. Your microwave oven draws 1100 W of electrical power when it is running. If it takes 45 s for this microwave oven to raise the temperature of the coffee to 60âC , what is the efficiency of heating with this oven?
e=(what you get/what you had to pay)
A) Which of the following is the quantity you would label as "what you got"?
B) Which of the following is the quantity you would label as "what you had to pay"?
C) Find the efficiency e of the oven. You will need to use the fact that 4.2 J of energy is required to raise the temperature of 1.0 mL of coffee by 1.0âC .
D) The oven draws 1100 W of power, and you have determined that it heats with an efficiency of 51%. Using this information, determine the time t it would take to bring 240 mL of water from 25âC to 100âC . Note that 4.2 J of energy is required to raise the temperature of 1.0 mL of water by 1.0âC (the same as for the coffee above).
Answers
A) The quantity labeled as "what you got" is the increase in thermal energy of the coffee, which is given by the equation:
ΔQ = mcΔT
where m is the mass of the coffee, c is the specific heat capacity of coffee (assumed to be the same as water), and ΔT is the temperature increase.
B) The quantity labeled as "what you had to pay" is the electrical energy consumed by the microwave oven, which is given by the equation:
E = Pt
where P is the power of the microwave oven and t is the heating time.
C) We can first calculate the thermal energy gained by the coffee:
ΔQ = mcΔT = (0.2 kg)(4.2 J/g°C)(60°C - 30°C) = 504 J
Next, we can calculate the electrical energy consumed by the microwave oven:
E = Pt = (1100 W)(45 s) = 49500 J
The efficiency of heating is then:
e = ΔQ/E = 504 J/49500 J = 0.0102 or 1.02%
D) We can use the same equations as above, but solve for the heating time instead of the efficiency:
ΔQ = mcΔT = (0.24 kg)(4.2 J/g°C)(100°C - 25°C) = 2268 J
E = Pt = (1100 W)t
e = ΔQ/E = 0.51 = 2268 J/(1100 W)t
Solving for t, we get:
t = ΔQ/(0.51E) = 2268 J/(0.51)(240 mL)(4.2 J/g°C)(75°C)(1 kg/L)(1100 W/s) = 925 seconds or 15.4 minutes.
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A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air? Part 1 of 2 The speed of the plane in still air is Part 2
Answers
The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.
Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.
The distance traveled with the wind in 3 hours is 408 miles.
Therefore, we can write the equation as:
3(x + y) = 408
Divide both sides by 3:
x + y = 136 .... (1)
The distance traveled against the wind in 4 hours is also 408 miles.
Therefore, the equation can be written as:
4(x - y) = 408
Divide both sides by 4:
x - y = 102 .... (2)
Now we can solve these two equations using the elimination method.
Add equations (1) and (2):
x + y + x - y = 136 + 1022x = 238x = 119 mph
Therefore, the speed of the plane in still air is 119 mph.
Now, substitute this value of x in equation (1):
119 + y = 136y = 17 mph
Therefore, the speed of the wind is 17 mph.
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The correct question is:
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?
A plane traveled for 3 hours at a velocity of 1200 km/hr North. What is the distance traveled?
Answers
Answer:
the answer is 3600 kilometers
Please help me as soon as possible.
Answers
Answer:
true
Explanation:
20 kg rodsis on the edge of a 80 m high de What is the rodes gracional potencial energy?
Answers
Answer:
Gpe = 15680 Joules
Explanation:
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
G.P.E = mgh
Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Given the following data;
Mass = 20 kg
Height = 80 m
We know that acceleration due to gravity is equal to 9.8 m/s²
To find the gravitational potential energy;
Gpe = mgh
Gpe = 20 * 80 * 9.8
Gpe = 15680 Joules
A lady is on a lab chair. The chair can freely spin on its axis (no friction). The lady was given an initial spin. While she is spinning freely, she extends her arms out O her moment of inertia increases and her angular speed decreases her moment of inertia increases and her angular speed increases. O her moment of inertia decreases and her angular speed increases O her moment of inertia increases and her angular speed remains the same. O her moment of inertia decreases and her angular speed decreases.
Answers
The correct answer is Option 3: her moment of inertia increases and her angular speed increases. When the lady extends her arms out, her moment of inertia increases because she is now further away from the axis of rotation and the mass of her arms is now contributing to her moment of inertia. Since her moment of inertia increases, her angular speed must also increase in order to conserve angular momentum.
a spherical weather balloon is filled with hydrogen until its radius is 3.00 m. its total mass including the instruments it carries is 15.0 kg. (a) find the buoyant force acting on the balloon, assuming the density of air is 1.29 kg/m3 . (b) what is the net force acting on the balloon and its instruments after the balloon is released from the ground? (c) why does the radius of the balloon tend to increase as it rises to higher altitude?
Answers
a) Buoyant force acting on the balloon is 1429.68 N ; b)Net force on the balloon is 1282.53 N.
What is Buoyant force?An upward force exerted by a fluid that opposes the weight of a partially or fully immersed object is called buoyant force.
Given, radius of balloon, r is 3 m ; Mass of balloon with instruments, m = 15 kg ; Acceleration due to gravity, g = 9.81 m/s² and Density of air, ρ is 1.29 kg/m3
a) Volume of balloon is ;
V= 4/3 π r³
= 4/3 π (3)³
= 113.09 m³
Buoyant force , F = ρ v g
= 1.29 * 113.09 * 9.8
So, F = 1429.68 N
Buoyant force acting on balloon is 1429.68 N
b) Net force acting on the balloon is ;
Fn = F -W
= 1429.68 - ( 15 * 9.81)
= 1429.68 - 147.15
So, Fn = 1282.53 N
Net force on the balloon is 1282.53 N.
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Scientists classify stars by color: white, red, blue. The color of a star helps to tells us how
______ The star is.
Answers
Answer: Hot
Explanation: Scientist use the color of starts to determine how hot the surface temperature is.
4. Increasing the mass of this freight train will
its kinetic energy
Answers
Increasing the mass of a freight train will increase the kinetic energy of the train, because these quantities are directly proportional.
It is correct to say that increasing the mass of the freight train will increase its kinetic energy. This is because kinetic energy is directly proportional to mass. The formula for kinetic energy is:
KE = 0.5 * m * v^2
Where KE is kinetic energy, m is mass, and v is velocity. As you can see from the formula, if the mass (m) increases, the kinetic energy (KE) will also increase. Therefore, the more massive the freight train is, the more kinetic energy it will have.
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a ball of 5 kg is moving towards the wall at 6 m/s. after a while, it hits the wall and rebounds back at 4 m/s in the opposite direction. what is the work done on it?
Answers
Answer:-50 J
Explanation:
Answer: -50 N
Explanation:
A.Calculate the wavelength of the photon absorbed by COCO in the following vibration-rotation transition: nn = 0, ll = 2 →n→n = 1, ll = 3.
Express your answer to four significant figures and include the appropriate units.
B.Calculate the wavelength of the photon absorbed by COCO in the following vibration-rotation transition: nn = 0, ll = 3 →n→n = 1, ll = 2.
Express your answer to four significant figures and include the appropriate units.
C.Calculate the wavelength of the photon absorbed by COCO in the following vibration-rotation transition: nn = 0, ll = 4→n→n = 1, ll = 3.
Answers
However, I can explain the general concepts and equations involved in calculating the wavelength of photons absorbed during vibration-rotation transitions.
In molecular spectroscopy, the wavelength of a photon absorbed during a transition can be determined using the equation: λ = c / ν
where λ is the wavelength, c is the speed of light in a vacuum (approximately 3.00 x 10^8 meters per second), and ν is the frequency of the absorbed radiation.
To calculate the frequency of the absorbed radiation, you would need to consider the energy levels associated with the initial (nn = 0, ll = 2) and final (nn = 1, ll = 3) states of the vibration-rotation transition for each case.
The frequency can be determined using the equation:
ν = (E_final - E_initial) / h
where ν is the frequency, E_final is the energy of the final state, E_initial is the energy of the initial state, and h is Planck's constant (approximately 6.63 x 10^-34 joule-seconds).
By substituting the frequency into the wavelength equation, you can calculate the corresponding wavelength of the absorbed photon.
Please note that the actual numerical calculations would require specific energy values and molecular parameters for COCO, which I don't have access to in real-time.
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A hair dryer with a resistance of 12.0 W and a lamp with a resistance of 125 W are connected in parallel to a 125-V source through a 1.50-W resistor in a series. Find the current through the lamp when the hair dryer is on.Question 2 options:1) 0.880 A2) 8.80 A3) 88.0 A4) 880 A
Answers
Given:
Resistance of hair dryer, R1= 12.0 Ohms
Resistance of lamp, R2 = 125 ohms
Voltage of source = 125 V
Resistance = 1.50 ohms
Let's find the curent through the lamp when the hair dryer is on.
Here, the lamp and dryer are connected in parralel. To calculate the equivalent resistance, apply the formula:
\(\begin{gathered} \frac{1}{R_p}=\frac{1}{R_1}+\frac{1}{R_2} \\ \\ R_p=\frac{R_1R_2}{R_1+R_2} \\ \\ R_p=\frac{12\ast125}{12+125} \\ \\ R_p=\frac{1500}{137} \\ \\ R_p=10.9\text{ }\Omega \end{gathered}\)Now, the Rp and the resistor are connected in series.
To find the equivalent resistance in series, we have:
\(\begin{gathered} R_{eq}=R_p+R \\ \\ R_{eq}=10.9+1.50=12.4\text{ }\Omega \end{gathered}\)We now have a single resistor flowing through the 125 voltage source.
To find the current, apply Ohm's law:
\(V=I\ast R\)Solve for the current (I), where:
V = 125 volts
R = 12.4 Ω
Thus, we have:
\(\begin{gathered} I=\frac{V}{R} \\ \\ I=\frac{125}{12.4}=10.1\text{ A} \end{gathered}\)Since the resistor and Rp are connected in series, we have:
\(\begin{gathered} V_p_{}=I_p\ast R_p \\ \\ V_p=10.1\ast10.9=110.1\text{ V} \end{gathered}\)Since the dryer and the lamp are in parallel, the voltage through them are the same.
V(dryer) = V(lamp) = 110.1 Volts
To find the current flowing through the lamp, we have:
\(\begin{gathered} I_{\text{lamp}}=\frac{V_{lamp}}{R_{\text{lamp}}} \\ \\ I_{\text{lamp}}=\frac{110.1}{125}=0.88\text{ A} \end{gathered}\)Therefore, the current through the lamp when the hair dryer is on is 0.880 ampere.
ANSWER:
1) 0.880 A
If the force of gravity acting on the box is 88 N, what is the normal force acting on the box?
Answers
Answer:
88N
Explanation:
If the force of gravity acting on the box is 88N, then the normal force on the box is also 88N;
The force of gravity is the vertical pull of gravity on a body.
The normal force is the force a surface impresses on an object to prevent it from passing through.The normal force is equal to the gravitational force pull on a body.
So the solution is 88N
Now consider the children's linear accelerations. Which of the following statements are correct? Check all that apply. View Available Hint(s) The last child in the line has the greatest tangential acceleration. The last child in the line has the greatest radial acceleration. All the children have the same tangential acceleration. All the children have the same radial acceleration. Submit
Answers
The last child in the line has the greatest tangential acceleration and the last child in the line has the greatest radial acceleration are correct statements.
What is accelaration?Acceleration is the rate of change of velocity over time. It is the rate at which an object's speed, direction, or both change. It can also be defined mathematically as the derivative of the velocity vector with respect to time. Acceleration is a vector quantity, meaning that it has both magnitude and direction. It is typically expressed in units of meters per second squared (m/s2).
All the children do not have the same tangential and radial accelerations as the accelerations depend on the position of the children in the line.
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John is rollerblading down a long, straight path. At time zero, there is a mailbox about 1 m in front of him. In the 5 s time period that follows, John's velocity is given by the velocity versus time graph in the figure. Taking the mailbox to mark the zero location, with positions beyond the mailbox as positive, plot his position versus time in the given position versus time graph. Assuming that all the numbers given are exact, what is John's position at a time of 4.35 s? Enter your answer to at least three significant digits. Assuming that all the numbers given are exact, what is John's position at a time of 4.35 s? Enter your answer to at least three significant digits.
Answers
The position of John at time of 4.35 s is -1.13 m
From the given chart;
at time, t = 0, the initial velocity, u = - 2 m/sat time, t = 5 s, the final velocity, v = 2 m/sThe average acceleration is calculated as follows;
\(acceleration = \frac{\Delta \ velocity}{\Delta \ time} \\\\acceleration = \frac{v- u}{t_2 - t_1} = \frac{2 - (-2)}{5 - 0} = \frac{4}{5} = 0.8 \ m/s^2\)The position of John at time, t = 4.35 s is calculated as follows;
\(x(t) = ut + \frac{1}{2} at^2\\\\x(4.35) = (-2 \times 4.35) \ + \ 0.5\times 0.8\times( 4.35)^2\\\\x(4.35) = -8.7 \ + \ \ 7.569\\\\x(4.35) = - 1.13 \ m\)
Thus, the position of John at time of 4.35 s is -1.13 m
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a boy looks at the reflection of his digital watch in a plane mirror and thinks the time is 10:11. what is the correct time?
Answers
Answer:
11:10 will be the time. reflection causes the object to be flipped when you see its image at the mirror
if the length of the centrifuge arm is 15.0 m m , at what speed is the rider moving when she experiences 10 g's?
Answers
The rider is moving at a speed of 12.2 meters per second when she experiences 10 g's.
The speed at which a rider experiences 10 g's (10 times the acceleration due to gravity) on a centrifuge can be calculated using the formula:
speed = (g * r)
Where g is the acceleration due to gravity (9.8 m/s^2) and r is the radius of the centrifuge arm (in this case, 15.0 m).
Plugging in the numbers, we get:
speed = (9.8 * 15.0) = (146) = 12.2 m/s
It's important to note that high g-forces can have serious health effects, and centrifuges are often used to simulate conditions experienced by pilots, astronauts, and other people who are subjected to high g-forces.
The g-forces experienced on a centrifuge can be used to determine the limits of human tolerance and to develop measures to protect people from the harmful effects of high g-forces.
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Calculate the equilibrium pressures of no if nitrogen gas has an initial pressure of 21.76 atm and oxygen gas is initially 9.32 atm
Answers
Equilibrium pressure of NO is 3.82 atm
What is the equilibrium pressure of NO?The equilibrium pressure of NO is calculated from the equation of the reaction given below as follows:
N₂ + O₂ ⇄ 2 NO
Initial pressure of N₂ = 21.76 atm
Equilibrium pressure of N₂ = 21. 76 - x atm
Initial pressure of O₂ = 9.32 atm
Equilibrium pressure of O₂ = 9.32 - x atm
Initial pressure of NO = 0 atm
Equilibrium pressure of NO = 2x atm
Equilibrium constant = 0.050
0.050 = 2x²/(9.32 - x)(21. 76 - x)
2x² = 0.05(202.8 - 31.08x + x²)
2x² = 10.14 - 1.554x + 0.05x²
1.95x² + 1.554x - 10.14
x = 1.91 atm
2x = 3.82 atm
Therefore, equilibrium pressure of NO is 3.82 atm.
In conclusion, the equilibrium pressure is calculated from the equilibrium constant.
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A horizontal force of 25 N is required to push a wagon across a sidewalk at a constant speed. (5 points)
What is the net (unbalanced) force acting on the wagon?
What is the value of the force of friction acting on the wagon?
If the force on the wagon increased to 30 N, use Newton's law to explain what the effect would be.
Answers
The net force acting on the wagon at a constant speed is 0.
The value of the force of friction acting on the wagon is 55 N.
What is the net force acting on the wagon?The net force acting on the wagon is calculated by applying Newton's second law of motion as shown below.
F - Ff = ma
where;
F is the applied forceFf is the force of frictionm is the mass of the wagona is the acceleration of the wagonAt a constant speed, the acceleration of the wagon = 0
F - Ff = 0
F - Ff = F(net)
Thus, the net force is zero, when the speed of the wagon is constant.
The force friction acting on the wagon if the force on the wagon increased to 30 N is calculated as;
F - Ff = 0
( 30 N + 25 N ) - Ff = 0
Ff = 55 N
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Scarcity impacts opportunity costs because most resources are limited. Which of the following resources is not considered scarce?
trash
clean air
oil
fresh water
Answers
The resource that is not considered scarce among the four given options is trash.
Trash is available in limited quantity. But a human being has no use for trash. So, trash is undesirable. Therefore, it not considered a resource. A resource mush have value or benefits.
Clean air is considered scarce because, there are some parts of world where you have to spend some money to keep the air clean. Oil is considered scarce because of increase in oil prices all over the world. Fresh water is considered scarce because only 3% of the world's water is fresh water and 2/3rd of it not accessible.
Therefore, the resource that is not considered scarce among the given options is trash.
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