If the parent function is y = 2*, which is the function of the graph?

The reason for the first and second steps in the equation are Addition Property of Equality and Division Property of Equality respectively

An equation is a mathematical statement that shows that two expressions are equal. It consists of two expressions separated by an equal sign (=) e.g. 2x + 3 = 7

Given: the equation 3x-2=4

Match the reason with the correct step in the equation as follows:

3x-2= 4

Add to 2 to both sides of the equation:

3x-2+2 = 4+2    (Addition Property of Equality)

3x = 6

Divide both sides by 3:

3x/3 = 6/3        (Division Property of Equality)

x = 2

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Answer:

24% increase

Step-by-step explanation:

percent change = (new value - old value)/(old value) × 100%

A positive percent change is a percent increase.

A negative percent change is a percent decrease.

In this problem:

new value = 31

old value = 25

percent change = (31 - 25)/(25) × 100%

percent change = 24%

Since the percent change is positive, the percent change is a

24% increase

The percentage change in the weight of a German Shepherd puppy from 4 months to 5 months is the an 24% increase in the puppy's weight in 1 month.

The percentage change in the weight of a German Shepherd puppy from 4 months to 5 months is the difference between the two values (31 - 25 = 6) divided by the starting weight (25). This gives us 6/25 = 0.24, or a 24% increase in the puppy's weight in 1 month.

To explain this further, let's look at an example. If a puppy weighed 25 pounds at 4 months, and it gained 6 pounds over the course of the following month, it would weigh 31 pounds at 5 months. To calculate the percentage increase, take the difference in weight (6 pounds) and divide it by the starting weight (25 pounds). This gives us 6/25 = 0.24, or a 24% increase in the puppy's weight.

To calculate the percentage decrease, use the same steps as above, but subtract the starting weight from the final weight instead. For example, if a puppy weighed 25 pounds at 4 months and lost 6 pounds over the course of the following month, it would weigh 19 pounds at 5 months. The percentage decrease would be calculated as (25 - 19)/25 = 0.24, or a 24% decrease in the puppy's weight.

In summary, the percentage change in the weight of a German Shepherd puppy from 4 months to 5 months is the difference between the two values (31 - 25 = 6) divided by the starting weight (25). This gives us 6/25 = 0.24, or a 24% increase in the puppy's weight in 1 month.

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The two sample means of 10 and 20 with variances of 20 and 25 will produce the largest value for an independent-measures t statistic.

An independent-measures t statistic is used to measure the differences between two independent groups. In this case, the two sample means are 10 and 20 with variances of 20 and 25. This will produce the largest value for an independent-measures t statistic because the larger the difference between the two sample means, the larger the t statistic will be. The larger the variance, the more spread out the data is which also results in a larger t statistic. Since the two sample means have a larger difference and the variances are also large, this will result in the largest value for an independent-measures t statistic.

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Answer:

27

Step-by-step explanation:

To find the area of the region interior to r = 9 + 7sin(θ) below the polar axis, we can integrate the function from the lower bound of θ to the upper bound of θ and take the absolute value of the integral.

To find the area of the region formed by two petals of r = 8sin(3θ), we can integrate the function over the appropriate range of θ and take the absolute value of the integral. To find dy/dx for the given parametric equations x = t^(1/3) and y = 3 - t, we differentiate y with respect to t and x with respect to t and then divide dy/dt by dx/dt.

To find the area of the region interior to r = 9 + 7sin(θ) below the polar axis, we need to evaluate the integral ∫[lower bound to upper bound] |1/2 * r^2 * dθ|. In this case, the lower bound and upper bound of θ will depend on the range of values where the function is below the polar axis. By integrating the expression, we can find the area of the region. To find the area of the region formed by two petals of r = 8sin(3θ), we need to evaluate the integral ∫[lower bound to upper bound] |1/2 * r^2 * dθ|.

The lower bound and upper bound of θ will depend on the range of values where the function forms the desired shape. By integrating the expression, we can calculate the area of the region. To find dy/dx for the parametric equations x = t^(1/3) and y = 3 - t, we differentiate both equations with respect to t. Taking the derivative of y with respect to t gives dy/dt = -1, and differentiating x with respect to t gives dx/dt = (1/3) * t^(-2/3). Finally, we can find dy/dx by dividing dy/dt by dx/dt, resulting in dy/dx = -3 * t^(2/3).

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Answer:

5 hours

Step-by-step explanation:

Let x represent the amount of hours that ralph can do.

Let y represent the money he earned.

Let m represent how much he earns per hour.

Let b represent the initial fee

y=mx+b

y=33x + 24

189=33x+24

Solve for x:

189=33x+24

165 = 33x

x=5

Answer:

All looks  good but Problem 5 K

363

Step-by-step explanation:

33 x 11 = 363

Answer: I only saw one mistake. On your mixed practice, K is wrong. It is 363, not 636.

hope this helps!

please give brainliest!

Answer:

x = -7

x = -2

x = 3

Step-by-step explanation:

The equation that represents the line shown is: D. y = 5/2x + 4.

The equation can be written as y = mx + b, which is in the slope-intercept form, where:

m = slope = rise/run

b is the y-intercept of the line.

From the image given:

slope (m) = rise/run = 5/2

Y-intercept (b) = 4

To write the equation of the line, substitute m = 5/2 and b = 4 into y = mx + b:

y = 5/2x + 4.

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(i) When sinФ=2/3 → It lies in Ist and IInd quadrants and the suitable graph is not provided here.

(ii) when cosФ=-1/2 → It lies in IInd and IIIrd quadrants and the suitable graph is A and D.

(iii) when cotФ=3/4 → It lies in Ist and IIIrd quadrants and the suitable graph is E.

(iv) when cosecФ=3/2 → It lies in the Ist quadrant and the suitable graph is not provided here.

What is Quadrant?

(i) When sinФ=2/3

Ф=sin^(-1)(2/3)

Ф=41.81°,138.18°

So it lies in Ist and IInd quadrant.

A suitable graph is not provided here.

(ii) when cosФ=-1/2

Ф=cos^(-1)(-1/2)

Ф=120°,240°

So it lies in IInd and IIIrd quadrant.

A suitable graph is A and D.

(iii) when cotФ=3/4

Ф=cot^(-1)(3/4)

Ф=53.13°,233,13°

So it lies in Ist and IIIrd quadrant.

A suitable graph is E.

(iv) when cosecФ=3/2 or sinФ=2/3

Ф=sin^(-1)(2/3)

Ф=0.729°

So it lies in Ist quadrant.

A suitable graph is not provided here.

(i) When sinФ=2/3 → It lies in Ist and IInd quadrants and the suitable graph is not provided here.

(ii) when cosФ=-1/2 → It lies in IInd and IIIrd quadrants and the suitable graph is A and D.

(iii) when cotФ=3/4 → It lies in Ist and IIIrd quadrants and the suitable graph is E.

(iv) when cosecФ=3/2 → It lies in the Ist quadrant and the suitable graph is not provided here.

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The principal for Account A is $150, and we do not have enough information to find the principal for Account B. Account A earned the most interest the first month because it has a higher monthly interest rate.

The principal for Account A can be found using the formula for simple interest:

I = Prt, where I is the interest, P is the principal, r is the interest rate, and t is the time in years.

Rearranging the formula to solve for P, we get P = I / (rt).

For Account A, the interest is $9.45, the interest rate is 3.6%, or 0.036, and the time is 21 months, or 1.75 years.

Plugging these values into the formula, we get:

P = $9.45 / (0.036 × 1.75) = $150

So the principal for Account A is $150.

For Account B, we do not have enough information to find the principal. We know the interest rate, but we do not know the interest or the time.

To determine which account earned the most interest the first month, we can compare the monthly interest rates.

The monthly interest rate for Account A is 3.6% / 12 = 0.3%, and the monthly interest rate for Account B is 2.4% / 12 = 0.2%.

Since the monthly interest rate for Account A is higher, it earned the most interest the first month.

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The phenomena of hiding distribution characteristics in a system from applications and users is known as distribution transparency. Access transparency, location transparency are some examples.

Distributed databases have the attribute of distribution transparency, which keeps consumers from knowing the internal workings of the distribution.

Thus, access transparency, location transparency are some examples of the (distribution) transparency.

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The Coase theorem is an economic theory that states that in the absence of transaction costs, the allocation of resources and the distribution of wealth will be efficient regardless of how property rights are assigned.

In this context, the theorem reminds us that efficiency is all about maximizing total welfare, rather than focusing solely on the allocation of resources or the distribution of wealth. When transaction costs are low or non-existent, parties can negotiate with each other to reach mutually beneficial agreements that maximize their combined welfare. This means that ownership of property or resources is less important than the ability of parties to freely negotiate with one another.

For example, imagine two neighboring farms: one produces apples and the other produces honey. If the apple farmer's use of pesticides harms the bee population and reduces the honey farmer's production, the honey farmer could demand compensation from the apple farmer. If transaction costs are low, the two farmers could negotiate a solution that is mutually beneficial, such as the apple farmer paying for the honey farmer to relocate their bees to a safer area. In this scenario, the assignment of property rights is not as important as the ability of the two parties to negotiate and reach an agreement that maximizes their total welfare.

Overall, the Coase theorem highlights the importance of considering the broader impacts of economic decisions and recognizing that efficiency depends on maximizing the overall benefits to all parties involved, rather than just focusing on individual outcomes.

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To determine the vertices of image U′V′W′ after a 180° counterclockwise rotation, we can apply the following transformation rules:

Using these rules, we can find the vertices of image U′V′W′ as follows:

Therefore, the vertices of image U′V′W′ after a 180° counterclockwise rotation are U′(0, -2), V′(1, -3), and W′(3, -3).

So, the answer is option (b) U′(0, −2), V′(1, −3), W′(3, −3).

\(\\ \rm\Rrightarrow \sum^{60}_{n=1}3n\)

It will form a arithmetic sequence as

\(\\ \rm\Rrightarrow 3(1)+3(2)+3(3)\dots 3(60)\)

So

Summation

\(\\ \rm\Rrightarrow \dfrac{n}{2}(a+\ell)\)

\(\\ \rm\Rrightarrow \dfrac{60}{2}(3+180)\)

\(\\ \rm\Rrightarrow 30(183)\)

\(\\ \rm\Rrightarrow 5490\)

Option D

Answer:

\(\mathsf {5,490}\)

Step-by-step explanation:

\(\textsf {Given :}\)

\(\lim_{1 \to \660} \sum3n\)

\(\textsf {Finding the necessary :}\)

\(\textsf {1. first term (a)}\)

\(\implies \mathsf {a = 3(1) = 3}\)

\(\textsf {2. final term}\) \(\mathsf {(a_n)}\)

\(\implies \mathsf {a_n = 3(60) = 180}\)

\(\textsf {3. common difference (d)}\)

\(\implies \mathsf {a_2 = 3(2) = 6}\)

\(\implies \mathsf {d = a_2 - a_1 = 6 - 3 = 3}\)

\(\textsf {Finding the sum of the series :}\)

\(\implies \mathsf {S_n =\frac{n}{2}(a + a_n) }\)

\(\implies \mathsf {S_6_0 = \frac{60}{2} (3 + 180)}\)

\(\implies \mathsf {S_6_0 = 30 \times 183}\)

\(\implies \mathsf {S_6_0 = 5,490}\)

By using  Fundamental Theorem of Calculus, we find the derivative of the function g(x) = In { sqrt( t + t^3)dt } limit from x to 0 is  ln(sqrt(x + x^3)).  The derivative of the function g(x) = { In (1+t^2) dt} where limit are from x to 1 is  ln(1 + x^2).

The Fundamental Theorem of Calculus, which states that if a function is defined as the definite integral of another function, then its derivative is equal to the integrand evaluated at the upper limit of integration.

So, applying this theorem, we have:

g'(x) = d/dx [∫x_0 ln(sqrt(t + t^3)) dt]

= ln(sqrt(x + x^3)) * d/dx (x) - ln(sqrt(0 + 0^3)) * d/dx (0)

= ln(sqrt(x + x^3))

Therefore, g'(x) = ln(sqrt(x + x^3)).

Using the Fundamental Theorem of Calculus, we have:

g'(x) = d/dx [∫1_x ln(1 + t^2) dt]

= ln(1 + x^2) * d/dx (x) - ln(1 + 1^2) * d/dx (1)

= ln(1 + x^2)

Therefore, g'(x) = ln(1 + x^2).

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____The given question is incomplete, the complete question is given below:

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. 7 g(x) = In { sqrt( t + t^3)dt } limit from x to 0.  8. g(x) = { In (1+t^2) dt} where limit are from x to 1.

Answer:

1.75 gallons of paint

Step-by-step explanation:

A student in the construction trades program has 4 1/2 gallons of paint

If the student uses 2.75 gallons in one room then the gallons of paint that are left can be calculated as follows

= 4 1/2 - 2.75

= 9/2 - 2.75

= 4.5 - 2.75

= 1.75

Hence 1.75 gallons of paint are left

Ratio analysis can be made more meaningful in all the following ways except by focusing more on long-term solvency than on short-term solvency.

Ratio analysis is a mathematical technique for analyzing a company's financial documents, such as the balance sheet and income statement, to gather knowledge about its liquidity, operational effectiveness, and profitability. Fundamental equity research is built on ratio analysis.

In order to get insights into profitability, liquidity, operational effectiveness, and solvency, ratio analysis examines line-item data from a company's financial statements.

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The full question:

ratio analysis can be made more meaningful in all the following ways except by?

Answer:

x = 110°, z = 32°

Step-by-step explanation:

x + 70 = 180 (Exterior angles)

x = 110

4z - 58 + 110 = 180 ( Linear pair)

4z = 128

z = 32

Pls mark as brainliest if possible and cheers!

Answer:yo mom

Step-by-step explanation:

Answer:

below

Step-by-step explanation:

17/40 * 100 % = 42.5 %

Answer:

42.5%

Step-by-step explanation:

to get 40 (denominator) to 100, you need to multiply 40 by 2.5times.

so, multiply 17 (numerator) too: 17 times 2.5 = 42.5

42.5 percent is your answer

The final value is:

f(-5) = (-5)^2 = 25.

f(-5) = (-5)^2 - 1 = 24.

f(-5) = (-5)^2 + 1 = 26.

We can solve this problem by using the fact that the derivative of a function gives us the slope of the tangent line at any point. We can then use this information to find the equation of the function that satisfies the given derivative and the additional information about the function's values at certain points.

A) To find f(-5) if f(0)=0, we need to integrate the derivative f'(x)=2x with respect to x, since integration is the inverse operation of differentiation.

∫f'(x)dx = ∫2xdx = x^2 + C

where C is the constant of integration.

Since f(0)=0, we can find C by substituting x=0:

f(0) = 0^2 + C = 0

C = 0

Thus, the equation of the function is:

f(x) = x^2

So, f(-5) = (-5)^2 = 25.

B) To find f(-5) if f(1)=0, we can use the same method:

∫f'(x)dx = ∫2xdx = x^2 + C

Since f(1)=0, we can find C by substituting x=1:

f(1) = 1^2 + C = 0

C = -1

Thus, the equation of the function is:

f(x) = x^2 - 1

So, f(-5) = (-5)^2 - 1 = 24.

C) To find f(-5) if f(-4)=17, we can again use the same method:

∫f'(x)dx = ∫2xdx = x^2 + C

Since f(-4)=17, we can find C by substituting x=-4:

f(-4) = (-4)^2 + C = 17

C = 1

Thus, the equation of the function is:

f(x) = x^2 + 1

So, f(-5) = (-5)^2 + 1 = 26.

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The opportunity cost of 1 lunch box is 3 sandwich containers. This means workers are giving up the opportunity to produce 3 sandwich containers

The opportunity cost represents the value of the next best alternative forgone when making a choice. In this case, the workers at Shadowland have the option to produce either lunch boxes or sandwich containers.

Given that they can produce 6 lunch boxes or 18 sandwich containers per hour, we can calculate the opportunity cost.

To find the opportunity cost of 1 lunch box, we compare the number of sandwich containers that could have been produced in the same amount of time.

Since they can produce 18 sandwich containers per hour, the opportunity cost of 1 lunch box is the number of sandwich containers that could have been produced instead, which is 18/6 = 3.

Therefore, the opportunity cost of 1 lunch box is 3 sandwich containers. This means that for every lunch box produced, the workers are giving up the opportunity to produce 3 sandwich containers, which represents the trade-off in their production choices.

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Answer:

c = 35°

Step-by-step explanation:

tanα = \(\frac{Opposite}{Adjacent}\)

cosβ = \(\frac{Adjacent}{Hypotenuse}\)

With respect to angle c:

Opposite = 2

Adjacent = 3x

∴tan c = \(\frac{2}{3x}\)

With respect to angle d:

Hypotenuse = 4x

Adjacent = 3

∴cos d = \(\frac{3}{4x}\)

Given that

tan c + cos d = 1.5

Substitute the derived expressions and solve for x:

\(\frac{2}{3x} + \frac{3}{4x} = 1.5\)

The denominators of the two fractions need to be made the same:

\((\frac{4}{4})(\frac{2}{3x}) + (\frac{3}{3})(\frac{3}{4x}) = 1.5\)

\(\frac{8}{12x} + \frac{9}{12x} = 1.5\)

\(\frac{8 + 9}{12x} = 1.5\)

\(\frac{17}{12x} = 1.5\)

Cross-multiplication is applied:

\((1)(17) = (12x)(1.5)\)

\(17 = 18x\)

∴\(x = \frac{17}{18}\)

Substitute this value of x in tanc equation to solve for c:

tan c = \(\frac{2}{3(\frac{17}{18})}\)

c = \(tan^{-1}[\frac{2}{3(\frac{17}{18})}]\)

∴c = 35.0° (Rounded to the nearest degree)

The probability that the last passenger end up in his/her assigned seats is 0.20.

In the given question, there are 6 people in line to board a plane with 6 seats.

The first person has lost his boarding pass, so he takes a random seat.

Everyone that follows takes their assigned seat if it's available, but otherwise takes a random unoccupied seat.

We have to find the probability the last passenger ends up in his/her assigned seat.

Given 6 people with 6 Seats.

The probability that the last passenger end up in his/her assigned seats = 1/5

The probability that the last passenger end up in his/her assigned seats = 0.20.

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Answer:

Step-by-step explanation: Vertex Equatiation Por mxa Plus B = X gtex Lp Cneter to 16u8 Killomtrss to ball

Answer:

C

Step-by-step explanation:

Small tier will serve 20 and medium tier will serve 40

Answer:

the lemon cookies they use more

Step-by-step explanation:

Answer:

The correct answer is - £ 40.5 for 3 large packs.

Step-by-step explanation:

Given:

Large pack = 40 tiles £18

Small pack = 28 tiles £14

Special offer = 25% reduction when you buy 3 or more large packs.

Solution:

Following combinations are possible for tom to get the tiles he needs:

1. 3 large packs

40*3 = 120 tiles with 25% discount

cost = 18*3 - 0.25*18*3 = 40.5

2. 4 small packs

28*4 = 112 tiles

cost = 14*4 = 56

3. 2 large packs and 1 small pack

40*2 + 28 = 108 tiles

cost = 18*2 + 14 = 50

4. 1 large pack and 3 small packs

40 + 28*3 = 124 tiles

cost = 18 + 14*3 = 60

Thus, the correct answer is - 1st case with three large packs.