The maximum power the shaft can transmit is 109.3s kW, where s is the thickness of the material being welded.
To determine the maximum power the shaft can transmit, we need to use the formula for shear stress:
τ = (4/3) * (F/A)
Where τ is the shear stress, F is the force being applied, and A is the area over which the force is being applied. For a fillet weld, the area is given by:
A = 0.707 * s * r
Where s is the thickness of the material being welded. We can solve for F by rearranging the formula for shear stress:
F = (3/4) * τ * A
Substituting in the values given, we get:
A = 0.707 * s * r = 0.707 * 13.2mm * s
F = (3/4) * 159MPa * 0.707 * 13.2mm * s
To find the maximum power, we need to calculate the torque that the shaft can transmit. This can be found using the equation:
T = F * r
Where T is the torque and r is the radius of the fillet weld. Substituting in the values we have calculated, we get:
T = [(3/4) * 159MPa * 0.707 * 13.2mm * s] * 13.2mm
Now we can calculate the maximum power using the formula:
P = 2πNT/60
Where P is the power, N is the rotational speed in rpm, and T is the torque. Assuming a standard rotational speed of 3600 rpm, we get:
P = 2π * 3600 * [(3/4) * 159MPa * 0.707 * 13.2mm * s] * 13.2mm / 60
Simplifying this expression, we get:
P = 12,252s * (τallow) * (r^2)
Substituting in the given values, we get:
P = 12,252s * 159MPa * (13.2mm)^2
P = 109.3s kW
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At first, right after the Big Bang, the universe was too hot for nuclei and electrons to combine into the kinds of neutral atoms that are familiar to us today. How soon after the beginning did it become cool enough for neutral atoms to form
After the Big Bang, it took the universe 3 minutes to become cool enough for neutral atoms to form.
Time taken for the universe to cool after the Big Bang
During the first moment, immediately after the Big Bang, the universe was too hot for nuclei and electrons to combine into the kinds of neutral atoms that are familiar to us today.
In the first three minutes after the Big Bang, these protons and neutrons began fusing together, forming deuterium also known as heavy hydrogen.
Thus, after the Big Bang, it took the universe 3 minutes to become cool enough for neutral atoms to form.
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A fire helicopter carries a 590 kg bucket
at the end of a 12.7 m long cable. When
the helicopter is returning from a fire at a
constant speed of 33.7 m/s, the cable makes
an angle of 25.7
◦ with respect to the vertical.
25.7
◦
Find the horizontal force exerted by air
resistance on the bucket. The acceleration
due to gravity is 9.8 m/s
2
.
Answer in units of N
The horizontal force exerted by air resistance on the bucket is 5,210 N.
What is the horizontal force exerted by air resistance on the bucket?
The horizontal force exerted by air resistance on the bucket is the parallel force on the cable carrying the bucket.
The magnitude of this force is calculated as follows;
Fx = mg cosθ
where;
m is the mass of the bucketg is the acceleration due to gravityθ is the angle of inclination of the cableFx = (590 x 9.8) x cos(25.7)
Fx = 5,210 N
Thus, the horizontal force on the bucket is determined from parallel force on the rope.
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Why will a struck tuning fork sound louder when it is held against a table?.
Answer:
1.)the surface of the table is set into vibration
2.)the initial vibration was larger
3.)The entire table vibrates
Explanation:hope this helps :3 have a good day xlXCherryColaXlx..(pls mark me brainliest)
Hi I need help my home work says can you change use the sun energy to produce the food in this sandwich the cheese came out from the milk I'm a cow that a crash that took energy from the sun for explain fill in the other chain
Answer: Food chain: cheese a product of the sun.
Explanation:
Food chain: The energy taken from the sun through photosynthesis enables plants to exist and grow.
The animal like cow takes chemical energy from plants by eating plants product.
The cow is able to produce the milk because of the energy that has been taken from the plant.
Since the cheese came out from the milk, we can therefore conclude that the food is initially a product of the sun.
Which characteristic is shared by all four fundamental forces?
large range
infinite range
repulsion
attraction
Answer:
D. attraction
Answer:
attraction
Explanation:
gravity attracts, electromagnetic force can attract, and both strong and weak nuclear forces hold together an atom, attracting at some points
edge2020
How much work is done by a 10 N frictional force which slows a moving block to a stop after a displace ment of 5.0m to the right?
a) 50J
b) -50J
c) 25J
d) -25J
Answer:
a)
Explanation:
work done = Fscosθ
=(10)(5)(cos0⁰)
=50J
Could you please help me with this question
Calculate the buoyant force on a 2.00-L helium balloon. (b) Given the mass of the rubber in the balloon is 1.50 g, what is the net vertical force on the balloon if it is let go
Answer:
Following are the solution to the given points:
Explanation:
In this question, some of the values are missing, that's why its solution can be defined as follows:
In point a:
Density of air \(\rho_{air} =1.29 \frac{kg}{m^3}\\\\\)
Density of helium \(\rho_{helium} =0.178 \frac{kg}{m^3} \\\\\)
The volume of the helium balloon \(V= 2L\)
\(\to V= 2 \times 10^{-3}\)
Formula:
\(F_B = e_a V g\\\\\)
\(= 1.29 \times 2 \times 10^{-3} \times 9.81\\\\ = 0.0253098 \ N\)
where g is the acceleration due to gravity
In point b:
\(m_g= 1.5 \ g\)
Formula:
\(F_{net}=F_B - (m_r + \rho_h \ v )g\)
\(= 0.0253098 - (1.5 \times 10^{-3} + 0.178 \times 2 \times 10^{-3} \times 9.81)\\\\= 7.10244 \times 10^{-3} \ N\)
what most likely caused the ice ages? the size of tree rings and the amount of pollen grains solar flares and gassy ejections from the sun the tilt of
The cause of the ice ages is a complex and multifactorial phenomenon that cannot be attributed to a single cause. However, scientists believe that several factors played a role in triggering the ice ages, including changes in the Earth's orbit, the tilt of the Earth's axis, and variations in the amount of solar radiation that the Earth receives.
These factors can affect the distribution of sunlight and heat across the planet, which in turn can impact the growth of glaciers and the amount of ice on Earth.
Other factors that may have contributed to the ice ages include volcanic activity, the size of tree rings, the amount of pollen grains, and even cosmic events like solar flares and gassy ejections from the sun.
Overall, the cause of the ice ages is a long answer that involves multiple factors working together in complex and dynamic ways.
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Convert the value from meters/second to kilometers/hour. One kilometer is equal to 1,000 meters, and 1 hour is equal to
3,600 seconds.
Type the correct answer in the box.
Answer:
we must multiply the speed value by 3.6
Explanation:
To reduce a magnitude from one unit to another, it must be multiplied by the equivalence in the order necessary so that the units do not change.
To reduce speed from m / s to km / h
we write the speed and the two conversion factors
v [m / s] [1 km / 1000m] [3600 s / 1h
v 3600/1000
v 3.6
therefore we must multiply the speed value by 3.6
Answer:
05 m/s =378 km/h
Explanation:
we have to convert the meters per second into kilometers per hour.
1m /sec = (1/1000)/ (1/3600) km/h = 3600/1000 km /h
divide 105 by 1000, and multiply it by 3600.
105 /1000 x 3600 = 378 km/h
you put a mirror at the bottom of a 2.3-m-deep pool. a laser beam enters the water at 29 ∘ relative to the normal, hits the mirror, reflects, and comes back out of the water.. How far from the water entry point will the beam come out of the water?
The beam will exit the water about 0.67 meters away from the entry point.
When the laser beam enters the water, it bends due to the change in refractive index between air and water. The angle of refraction can be calculated using Snell's law:
n1 sin θ1 = n2 sin θ2
where n1 and θ1 are the refractive index and angle of incidence in air, and n2 and θ2 are the refractive index and angle of refraction in water. Assuming a refractive index of 1.33 for water, we have:
1.00 sin 29° = 1.33 sin θ2
Solving for θ2, we get θ2 ≈ 21.2°.
When the beam hits the mirror, it reflects at the same angle of incidence. Therefore, the angle of incidence and refraction at the interface between the mirror and water are also 29° and 21.2°, respectively.
As the beam exits the water, it bends again due to the change in refractive index. This time, the angle of incidence is 21.2° and the angle of refraction in air can be calculated as:
1.33 sin 21.2° = 1.00 sin θ3
Solving for θ3, we get θ3 ≈ 16.3°.
Finally, we can use simple trigonometry to find the distance x between the water entry point and the point where the beam exits the water:
x = 2.3 m tan θ3 ≈ 0.67 m
Therefore, the beam will exit the water about 0.67 meters away from the entry point.
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You apply a constant force F =(−68.0N)i^+(36.0N)j^ to a 450 kg car as the car travels 44.0 m in a direction that is 240.0 ∘ counterclockwise from the +x-axis.How much work does the force you apply do on the car?Express your answer to three significant figures and include the appropriate units
That the force opposes the car's motion, and the magnitude of the work is 8.05 × 10³ J, rounded to three significant figures.
To calculate the work done by the force, we use the formula: Work = Force × Distance × cos(θ), where θ is the angle between the force vector and the displacement vector. In this case, the force vector F is given as\(\vec{F} = (-68.0 , \text{N}) \hat{\imath} + (36.0 , \text{N}) \hat{\jmath}\), and the car travels a distance of 44.0 m in a direction 240.0° counterclockwise from the +x-axis. The angle between the force vector and the displacement vector is equal to the angle between the +x-axis and the displacement vector.
Substituting the given values into the formula, we have: Work = (-68.0 N) × 44.0 m × cos(240.0°). Calculating the cosine of 240.0° gives us -0.5. Plugging this value into the formula, we find that the work is -8.05 × 10³ J. This negative value indicates that the force acts in the opposite direction of the displacement, opposing the car's motion. Therefore, the work done by the force on the car is 8.05 × 10³ J.
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If the slab with the yield lines shown carries a line load of 5 kN/m along the unsupported edge 2-3, and a uniform load throughout the slab of 10 kPa, determine the external work done. C 2 m A X B 4m
The external work done can be calculated by multiplying the loads by their corresponding distances and summing them up.
To calculate the external work done on the slab, we first consider the line load of 5 kN/m along the unsupported edge 2-3. The length of this edge is 4 m. Therefore, the external work done by the line load can be calculated as 5 kN/m * 4 m = 20 km. Next, we consider the uniform load of 10 kPa applied throughout the slab. The area of the slab is not provided in the given information, so we cannot determine the exact external work done by the uniform load without knowing the dimensions of the slab. However, we can still provide a general explanation. To calculate the external work done by the uniform load, we would need to determine the total area of the slab and multiply it by the load per unit area. Then, the product of the load per unit area and the distance from the centroid of the slab to the point of application of the load would give us the external work done by the uniform load. Without the exact dimensions of the slab, we cannot calculate the precise external work done. However, by considering the provided information, we can outline the steps and concepts involved in determining the external work done on the slab.
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3 students push on a 60kg Box, they each exert a 25 N force. What is the box’s acceleration if they all push in the same direction
Answer:
Acceleration = 1.25 m/s²
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Given the following data;
Force applied = 25 N
Mass = 60kg
The net force acting on the box = 25 + 25 + 25 = 75N
To find the acceleration;
Net force = mass * acceleration
Substituting into the equation, we have;
75 = 60 * acceleration
Acceleration = 75/60
Acceleration = 1.25 m/s²
Which of the following is not an example of an abiotic component of an ecosystem
A . water
B . minerals
C . sunlight
D . bacteria
E . air
\(\huge{ \mathfrak{ \underline{ Answer \: \: ✓ }}}\)
Which of the following is not an example of an abiotic component of an ecosystem :
A . water
B . minerals
C . sunlight
D . bacteria ✓
E . air
Bacteria is a single celled living organism.
\( \#TeeNForeveR\)
D. bacteria is not an example of an abiotic component of an ecosystem.
What is an ecosystem?An ecosystem is a community of living organisms (biotic) interacting with each other and with their non-living (abiotic) environment in a specific area. It encompasses all the living and non-living components of a particular environment and the complex interactions among them.
Here,
Abiotic components are the non-living factors that influence the distribution and abundance of living organisms in an ecosystem. Examples of abiotic components include water, minerals, sunlight, air, and temperature. Bacteria, on the other hand, are living organisms and are considered as biotic components of an ecosystem.
Thus, D. bacteria is not an example of an abiotic component of an ecosystem.
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1. A stone is dropped from the top of the tower and reaches the ground in 6 seconds. Find the height of the tower.
Answer:
176.4 m
Explanation:
To calculate the distance, the equation would be:
distance = acceleration X time² / 2
Assuming the stone is held at a complete stop before dropping, the acceleration would be equal to gravity which is 9.8m/s². So:
d = (9.8m/s²)( 6s)² / 2
= (9.8m/s²)(36s²) / 2
= 176.4 m
Which of these is an example of force?
A.Watching a slide of bread in the toaster
B. Pulling a casserole out of the oven
C. Listening to your school chorus
D.Taste testing soup cooking on the stovetop
Answer:
B is the answer a force is a push or pull
In an rlc circuit connected to an ac voltage source, which quantities determine the resonance frequency? choose all that apply
In an RLC circuit connected to an AC voltage source, the inductance and capacitance determine the resonance frequency. At resonance, the circuit behaves like a purely resistive circuit.
In an RLC circuit connected to an AC voltage source, the resonance frequency is determined by the inductance (L) and capacitance (C) of the circuit. These two quantities have an inverse relationship with the resonance frequency.
Inductance is the property of a circuit that opposes changes in current flow, while capacitance is the ability of a circuit to store electrical energy.
At resonance, the reactance of the inductor (XL) and the reactance of the capacitor (XC) cancel each other out, resulting in a purely resistive circuit. The equation for resonance frequency is given by:
f = 1 / (2π√(LC))
Here, f represents the resonance frequency, and π is a mathematical constant.
To summarize, in an RLC circuit connected to an AC voltage source, the inductance and capacitance determine the resonance frequency. At resonance, the circuit behaves like a purely resistive circuit.
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Forces between particles increase as the particles move faster and farther apart.true or false
Answer:
True
Explanation:
the best long jump is measured as 8.00m. the jumper took off at an angle of 39. what was the initial speed of the jumper
So the jumper's beginning speed was 12.47 m/s when the best long jump was measured at 8.00m.
What is speed?The pace at which an item travels or works is referred to as its speed, which is often defined in terms of distance per unit of time such as meters per second or miles per hour.
Here,
The initial speed of the jumper can be calculated using the following kinematic equation:
d = vit + 0.5a*t²
where d is the horizontal distance (8.00m), vi is the initial velocity, t is the time in the air, and a is the acceleration due to gravity (9.8 m/s^2). The time in the air can be found using the vertical displacement, which is given by:
h = visin(θ)t - 0.5at²
where h is the vertical height (0), θ is the launch angle (39°), and t is the time in the air. Solving for t in both equations and substituting into one of them, we can find the initial velocity:
vi = sqrt(2ad/cos²(θ)) = sqrt(29.88.00/cos²(39)) = 12.47 m/s.
So the initial speed of the jumper was 12.47 m/s when the best long jump is measured as 8.00m.
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5. Billy Bob pulls on a rope with a force of three hundred Newtons, Billy Joe is on the oth end. Billy Joe has a mass of 60 kg. What will be Billy Joe's acceleration?
Billy Joe's acceleration will be 5 m/s².
To determine Billy Joe's acceleration, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The formula for Newton's second law is:
F = m * a
Where:
F is the net force acting on the object,
m is the mass of the object, and
a is the acceleration.
In this case, the net force acting on Billy Joe is the force exerted by Billy Bob, which is 300 Newtons. The mass of Billy Joe is 60 kg.
Plugging these values into the formula, we can solve for the acceleration:
300 N = 60 kg * a
Divide both sides of the equation by 60 kg:
300 N / 60 kg = a
Simplifying the equation gives:
5 m/s² = a
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Please help me , I also have to show work on paper
Answer:
Choose B
Explanation:
Hope Can I help you
Determine the resistance, in milliOhms, of a metal rod 1.78 m long, 0.58cm diameter and composed of aluminum of resistivity 2.8 x 10-8 Ωm .
Given:
The length of the metal rod is,
\(l=1.78\text{ m}\)The diameter of the aluminum rod is,
\(\begin{gathered} d=0.58\text{ cm} \\ =0.58\times10^{-2}\text{ m} \end{gathered}\)The resistivity of aluminum is,
\(\rho=2.8\times10^{-8}\text{ ohm.m}\)To find:
The resistance
Explanation:
The resistance of the material is,
\(\begin{gathered} R=\frac{\rho l}{A} \\ Here,\text{ A=}\frac{\pi d^2}{4} \\ R=\frac{\rho l}{\frac{\pi d^2}{4}} \\ R=\frac{4\rho l}{\pi d^2} \end{gathered}\)Substituting the values we get,
\(\begin{gathered} R=\frac{4\times2.8\times10^{-8}\times1.78}{\pi\times(0.58\times10^{-2})^2} \\ =1.88\times10^{-3}\text{ ohm} \\ =1.88\text{ mOhm} \end{gathered}\)Hence, the resistance is 1.88 mOhm.
. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2
The length of the rubber band that the boy must use is 0.024 m or 24 mm.
What will be the length of the rubber required?To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:
U = 1/2 kx²where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.
Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.
We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):
v = √(2mk/M)where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:
k = (v² M) / (2 m)
We can now combine the two equations to solve for the length of the rubber band, L:
U = 1/2 k x²
U = 1/2 ((v² M) / (2 m)) (0.25 L)²
U = (v² M L²) / (32 m)
The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:
U = 1/2 M v²
(v² M L²) / (32 m) = 1/2 M v²
L = ((16 m v²) / (k M))
L = ((16 m v²) / ((v² M) / (2 m) M))
L = √(32 m^2 / M)
L = (0.032 M)
Substituting the given values, we get:
L = √(0.032 * 0.006)
L = 0.024 m
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hey guys can y’all help quickly?
how to induce a positive temporary charge on the right side of a metal ball
Answer:
Temporary? You have two options
If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).
If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).
Either way, the electron cloud will migrate towards the right side of the of your sphere.
Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.
I need help with these questions ASAP .. I have to get them done tonight because it is due tomorrow
Answer:
22. A: 4000m C: 3200
23: The feature at point D is a mid ocean ridge
24. cold and dark
25. E is far closer sitting just on the edge of the ridge
please help answer the question in the image!!!
Answer:
C (only)
Explanation:
Often, we consider the 0 position on a graph like this to be the starting point. However, the position on this graph is indicated as positive at time = 0. The motion shown can be described in each stage as follows.
A: moving away from the starting position toward the reference position (position = 0)
B: stationary at the reference position
C: moving away from the reference position toward the starting position
D: stationary at a point just short of the starting position
E: moving away from the starting position toward, then beyond, the reference position
An astronaut drops two pieces of paper from the door of a lunar landing module. one piece of paper is crumpled, and the other piece is folded into an airplane. why do the two pieces of paper land on the moon’s surface at the same time?
The two pieces of paper land on the moon's surface at the same time because they are both subject to the same gravitational force.
What controls motion on the moon?The force of gravity is determined by the mass of the object and the distance between it and the center of the celestial body. On the moon, the force of gravity is weaker than it is on Earth, but it is still strong enough to cause objects to fall toward the surface.
The shape of the paper, whether crumpled or folded into an airplane, has no effect on the force of gravity acting on it. In the absence of air resistance, all objects, regardless of their mass, shape, or size, will fall at the same rate in a vacuum.
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what is the magnitude and direction of the electric force on an electron ina uniform electric field of strenght 2360n/c that points due east
The magnitude of the electric force on the electron is 2360 N and it points due east.
What is electric force?Electric force is an attractive or repulsive force between two particles that have an electric charge. This force is generated when two charged particles interact due to their charges. The strength of the electric force depends on how much charge each particle has, as well as their distance from each other. Electric forces are responsible for phenomena such as static electricity and lightning, and they can also be used to power electric motors and other devices.
This is because an electric field exerts a force on a charged particle in the direction that is opposite to the direction of the field. Since the electric field points due east, then the force on the electron will point due west.
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which change to a circuit is most likely to increase it electrical power
A: increase it's current and increase it's voltage
B: decrease it's current and increase it's voltage
C: decrease it's current and decrease it's voltage
D: increase it's current and decrease it's voltage
Answer:
A................
Explanation:
Hope this helps you
A. increase it's current and increase it's voltage
Explanation: