If the rotation of a planet of radius 5.32 × 106 m and free-fall acceleration 7.45 m/s 2 increased to the point that the centripetal acceleration was equal to the gravitational acceleration at the equator, what would be the tangential speed of a person standing at the equator?

Answers

Answer 1

Answer:

v = 6295.55 m/s

Explanation:

Given that,

The radius of a planet, \(r=5.32\times 10^6\ m\)

The free fall acceleration of the planet, a = 7.45 m/s²

We need to find the tangential speed of a person standing at the equator.

Also, the centripetal acceleration was equal to the gravitational acceleration at the equator.

We know that,

Centri[etal acceleration,

\(a=\dfrac{v^2}{r}\\\\v=\sqrt{ar}\\\\v=\sqrt{5.32\times10^6\times 7.45}\\\\v=6295.55\ m/s\)

So, the tangential speed of the person is equal to 6295.55 m/s.


Related Questions

1. A 60 kg running back is moving east with a velocity of 9 m/s. What is their
momentum?

Answers

Answer:

\(\huge\boxed{\sf p = 540\ kg m/s}\)

Explanation:

Given data:

Mass = m = 60 kg

Velocity = v = 9 m/s

Required:

Momentum = p = ?

Formula:

p = mv

Solution:

p = (60)(9)

p = 540 kg m/s

\(\rule[225]{225}{2}\)

Hope this helped!

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Tool
Scientists are searching for planets that orbit stars outside Earth's solar system by collecting data from different technology tools. A student lists a few tools and their cases that would provide clients
with information about these planets in a table, as shown
Use
spectroscope
gathers information about the
planets in any weather conditions
space probe
collects data from the planets that
would otherwise not be available
identifies different elements present
reflector telescope
around the planets
radio telescope produces images of the planets
Which tool is paired correctly with its intended use?
space probe
Opectroscope
radio telescope
reflector telescope

Answers

Answer:

9758 how many significant figures

if the glider oscillates back and forth on the air-track, at what point in the motion is the acceleration zero? where is the velocity maximum? show with a drawing.

Answers

If the glider oscillates back and forth on the air-track, at what point in the motion is the acceleration zero when the glider reaches the extreme points of its motion, i.e., at the endpoints of the oscillation.

In the motion of a glider oscillating back and forth on an air-track, the acceleration is zero when the glider reaches the extreme points of its motion, i.e., at the endpoints of the oscillation. These points are called the turning points or the points of maximum displacement.

On the other hand, the velocity is maximum at the center of the motion, which is the midpoint between the two turning points. At this point, the glider changes its direction of motion and its velocity reaches its maximum value.

Here's a simplified diagram illustrating the motion of the glider:

  |       |

  |       |

  |       |

  |       |

  |       |

---+-------+---

Turning  Turning

Point    Point

At the turning points, the acceleration is zero (the glider momentarily stops before changing its direction), while at the midpoint between the turning points, the velocity is maximum (the glider is moving at its highest speed).

Note that this diagram represents a one-dimensional motion, where the glider moves back and forth along a straight line. In reality, the glider's motion may involve more complex trajectories, but the concept of acceleration being zero at the turning points and maximum velocity at the midpoint still holds true.

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how does the charge of one electron compare to that of another electron? how does it compare with the charge of a proton?

Answers

All electrons have the same charge. The electron charge is equal and opposite to the proton charge. A proton has 1800 times the mass of an electron.

It takes a lot of energy to extract protons from the nucleus. Electrons on the other hand are loosely bound outside the atom. Because of this electrons are easily removed. This is the main reason that charge is transferred by electrons rather than protons. Charges are different from being attracted to each other, just like charges repel. Therefore, two positive charges repel each other like two negative charges.

Positive and negative charges attract. Electrons are negatively charged. When a neutral object loses electrons it becomes more positively charged. When a neutral object gains electrons it becomes more negatively charged. Current is the flow of positive charge. All electrons have the same charge. The electron charge is equal and opposite to the proton charge. A proton has 1800 times the mass of an electron.

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12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.

Answers

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

a. The power necessary to maintain the speed of 15ms^-1 can be found using the equation for power, P = Force * velocity, where P is in watts, force is in newtons and velocity is in meters per second. Substituting the values given in the question, we get:

P = (400 + k * 15²) * 15
P = (400 + 11250) * 15
P = 11650 Watts

Therefore, the power necessary to maintain the speed of 15ms^-1 is approximately 11650 Watts.

b. The total resistive force at a speed of 30ms^-1 can be found by substituting 30 for v in the force equation:

F = 400 + k * 30^2

F = 12000 N

Therefore, the total resistive force at a speed of 30ms^-1 is approximately 12000 N.

c. The power required to maintain the speed of 30ms^-1 can be found using the same equation as in part a:

P = (400 + k * 30^2) * 30
P = (1500 + 600000) * 30
P = 625000000 Watts

Therefore, the power required to maintain the speed of 30ms^-1 is approximately 625000000 Watts. This is a very large amount of power and would require a significant amount of energy to maintain.

1) Which of the following is not a type of energy?
A: Thermal
B: Potential
C: Kinetic
D: Frictional

Answers

D. Frictional

The other three are energies while frictional energy is not

When resting, a person has a metabolic rate of about 4.70x10^5 joules per hour. The person is submerged neck deep into a tub containing no 812kg of water at 23.07 degrees Celsius. If the heat from the person goes only into the water, by how much will the water temperature temperature increase after 43 minutes of immersion?

Answers

Given

Rate of metabolic rate,

\(Q=4.70\times\frac{10^5J}{hr}\)

Mass of water,

\(m=812kg\)

The initial temperature,

\(T=23.07^oC\)

Explanation

The heat transferred in 43 minutes is given by

\(\begin{gathered} Q\times\frac{43}{60}=mc(T_f-T_i) \\ \Rightarrow4.70\times10^5\times\frac{43}{60}=812\times4180(T_f-28) \\ \Rightarrow T_f=28.099^oC \end{gathered}\)

Conclusion

The temperature increase to 28.099 degC

A circuit has a current of 1. 2 A. If the voltage decreases to one-third of its original amount while the resistance remains constant, what will be the resulting current? 0. 3 A 0. 4 A 1. 2 A 3. 6 A.

Answers

If the voltage decreases to one-third of its original amount while the resistance remains constant.  The resulting current will be 0.4 A.

What is current?

The current is the stream of electrons flowing from positive terminal of the battery to the negative terminal so as to generate electricity.

The circuit has a current of 1.2 A.

When the resistance  is constant, the voltage is proportional to current. According to the ohm's law,

V₂ / V₁ = I₂ / I₁

Substitute V for V₁ , V /3 for V₂ , 1.2 for I₁ , we get the resulting current,

I₂ = 0.4 A

Thus, the resulting current will be 0.4 A.

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A positive magnification means the image is inverted compared to the object. Is this true or false?

Answers

The given statement 'A positive magnification means the image is inverted compareed to the object' is false. Because when the image is virtual and erect then magnification is taken as positive.

Provide a conceptual definitions for each of the following variables used to describe waves: wavelength, period, velocity, amplitude, frequency, intensity, and phase.

Answers

The conceptual definitions for terms describing waves are:

1. Wavelength: The distance between two consecutive points in a wave that are in the same phase, usually measured from crest to crest or trough to trough.

2. Period: The time it takes for one complete cycle of a wave to pass a given point, usually measured in seconds.

3. Velocity: The speed at which a wave propagates through a medium, typically measured in meters per second (m/s).

4. Amplitude: The maximum displacement of a point in a wave from its equilibrium position, often representing the energy or intensity of the wave.

5. Frequency: The number of complete wave cycles that occur in one second, typically measured in hertz (Hz).

6. Intensity: The amount of energy carried by a wave per unit time and area, often related to the amplitude and frequency of the wave.

7. Phase: The position of a point in a wave relative to the wave's cycle, usually measured in degrees or radians and used to describe the timing relationship between different parts of a wave or between multiple waves.

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Two mechanical waves are traveling through the same medium, and Wave X has an amplitude of 2 cm and Wave Y has an amplitude of 3 cm.How do the two waves' speeds compare?A.   Wave X has a greater speed. B.   Wave Y has a greater speed. C.   Wave X and Wave Y share the same speed. D.   The speed of the waves is impossible to compare without more data.Part 2Which best explains the correct answer to Part 1?A.   The speed of a wave is always constant. B.   The speed of a wave is directly proportional to its amplitude.C.   The speed of a wave is determined by its wavelength and frequency.D.   The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.

Answers

ANSWER:

1. C. Wave X and Wave Y share the same speed.

2. D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.

STEP-BY-STEP EXPLANATION:

The amplitude of a wave does not affect the speed at which the wave travels. Both wave A and wave B travel at the same speed. The speed of a wave is only altered by alterations in the properties of the medium through which it travels.

Therefore, in the first art the correct answer is C. Wave X and Wave Y share the same speed.

If the medium is uniform (does not change), the speed of the wave will be constant.

Therefore, the correct answer is: D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.

A 20-kg block slides down a frictionless incline from point A to point B A force (magnitude P = 3.0 N) acts on the block between A and B, as shown Points A and B are 2.0 m apart If the kinetic energy of the block at A is 10 J,what is the kinetic energy of the block at B?

Answers

The kinetic energy of the block at B is 24J

we can solve this by using law of conservation of energy,

Ki = 10J                     Uf = 0 ( placed at origin point B)

Kf=?

Ui =mgh

To find height, h = 2 sin 30 = 1m

from this Ui = mgh = 20x1 = 20 J

law of conservation of energy,

Ki+ Ui + W = Kf + Uf  - (1)

work = - F X D = 3X2 = - 6 N

substituting in equation 1

10+20- 6 = Kf + 0

30-6 = Kf

Kf = 24 J

hence, KE at B is 24J

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A beaker containing 400g of water has 1200J of work done on it by stirring and 200cal of heat added to it from a hot plate.8.What is the temperature change of the water?A.1.2°C B.2.1°C C.1.4°C D.4.1°C

Answers

A.1.2°C

Explanation

The First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy.

To find internal energy, you have to add the heat added in the system and work done in the system because the work done is not lost but rather it is added in the system.

\(\begin{gathered} \Delta U=q+W \\ where\Delta U\text{ is the change in the internal energy} \\ q\text{ the heat added to the system} \\ W\text{ is the work done by the systeme} \end{gathered}\)

Step 1

a)let

\(q=200\text{ cal}\)

to add the energy it must have the same measure unit, so let's convert calories into Julies

remember that

\(\begin{gathered} 1\text{ cal}\Rightarrow4.184\text{ J} \\ so \\ 200\text{ cal}\Rightarrow200(4.814\text{ J})\Rightarrow836.8\text{ J} \end{gathered}\)

b) now, replace in the formula

\(\begin{gathered} \Delta U= q+W \\ \Delta U=836.8\text{ J+1200 J} \\ \Delta U=2036.8\text{ J} \end{gathered}\)

now, we have the change of internal energy

Step 2

now, let's find the change in temperature

Use the calorimetry formula.

\(\begin{gathered} Q=mc∆T \\ \end{gathered}\)

where m is the mass, Q = heat energy, c = specific heat capacity, and ∆T = change in temperature

a)

let

\(mass=\text{ 0.4 kg}\)

now,

\(\begin{gathered} Q=mC\Delta T \\ 2036.8\text{ j=0.4 kg*4184 }\frac{J}{Kg}|C*\Delta T \\ 2036.8=1673.6\Delta T \\ divide\text{ both sides by 1673.6} \\ \frac{2,036.8}{1673.6}=\frac{1,673.6\text{ }\Delta T}{1673.6} \\ 1.21=\Delta T \\ rounded \\ \Delta T=1.2\text{ \degree C} \end{gathered}\)

so, the answer is

A.1.2°C

FILL IN THE BLANK modern seatbelts have locking mechanisms that are triggered by _______ movement or ________ movement.

Answers

Modern seatbelts have locking mechanisms that are triggered by sudden or rapid movement or deceleration.

Seatbelt locking mechanisms are designed to secure the occupant in the event of a sudden stop, impact, or collision. They utilize various mechanisms to detect abrupt changes in movement or deceleration and lock the seatbelt to prevent excessive forward movement of the occupant.

One common type of locking mechanism is the emergency locking retractor (ELR), which is found in most modern seatbelts. The ELR allows the seatbelt to freely extend and retract during normal driving conditions but locks the belt during sudden movements or rapid deceleration. This is achieved through a pendulum or inertia sensor within the seatbelt retractor mechanism.

When the vehicle experiences a rapid forward movement or deceleration, the pendulum or inertia sensor detects the change and engages the locking mechanism. The locking mechanism prevents the seatbelt from extending further, holding the occupant in place and preventing excessive forward motion during a crash or sudden stop. This helps to distribute the forces of the impact more evenly across the body, reducing the risk of injury.

In addition to the sudden or rapid movement, some seatbelts may also have a feature called a pretensioner. Pretensioners are designed to activate during a collision and instantly retract the seatbelt, removing any slack and tightening it against the occupant's body. This further enhances the effectiveness of the seatbelt by reducing the occupant's forward movement and ensuring a snug fit.

Overall, the locking mechanisms in modern seatbelts are triggered by sudden or rapid movement or deceleration, enabling them to provide effective restraint and protection in the event of a crash or sudden stop.

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A very long wire has a linear charge density λ = 2 nC/m. What is the potential difference ∆V=V(r2) -V(r1) between points at radial distances r2 = 2 cm and r1 = 1 cm? (use εο =8. 85x10-12 C/ V-1 m-1 )

Answers

The potential difference ∆V = V(r₂) -V(r₁) between points at radial distances r₂ = 2 cm and r₁ = 1 cm is 78.9 V/m.

The potential difference ∆V = V(r₂) -V(r₁) between points at radial distances r₂ = 2 cm and r₁ = 1 cm can be calculated using the formula:

                                ∆V = (λ/2πεο) ln(r₂/r₁)

where λ is the linear charge density, εο is the permittivity of free space, r₁ and r₂ are the radial distances, and ln is the natural logarithm. Plugging in the given values, we get:

∆V = (2x10⁻⁹ C/m/2π(8.85x10⁻¹² C/V⁻¹m⁻¹)) ln(2 cm/1 cm)
∆V = (2x10⁻⁹  C/m/ 2π(8.85x10⁻¹² C/V⁻¹m⁻¹)) ln(2)
∆V = (1.14x10⁻² V⁻¹m⁻¹)) ln(2)
∆V = (1.14x10⁻² V⁻¹m⁻¹) (0.693)
∆V = 78.9 V⁻¹m⁻¹
∆V = 78.9 V/m

Therefore, the potential difference ∆V=V(r2) -V(r1) between points at radial distances r₂ = 2 cm and r₁ = 1 cm is 78.9 V/m.

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a 2 kg particle is moving to the left at 30 m/s. How much net work must be done on the particle to cause

Answers

60m/s ……….
Zzzzzzzzzzzzzzzzzzzz

Marjan, a skier of mass m, coasts a distance s on level snow to a stop from a speed of v, as depicted in the figure. Use the work-energy principle to find the coefficient of kinetic friction μk between the skis and the snow.
use the relationship wtotal=kfinal−kinitial=δkwtotal=kfinal−kinitial=δk to find the coefficient of kinetic friction between the skis and the snow.

Answers

To solve for the coefficient of kinetic friction μk, we need to use the work-energy principle which states that the total work done on an object is equal to the change in its kinetic energy. In this case, the skier starts with a kinetic energy of \(1/2mv^2\)and comes to a stop, so the final kinetic energy is zero.

The work done on the skier includes the work done by the friction force and the work done by any other forces acting on the skier. Since there are no other forces acting on the skier in this scenario, the total work done is equal to the work done by kinetic friction.

Thus, we have:
\(wtotal = kfinal - kinitial = δk\)

where wtotal is the total work done, k final is the final kinetic energy (which is zero), kinitial is the initial kinetic energy (which is 1/2mv^2), and δk is the work done by kinetic friction.

We can write the work done by kinetic friction as:

\(δk = Ffriction * s\\\)

where Ffriction is the force of kinetic friction and s is the distance the skier travels before coming to a stop.

We know that the force of kinetic friction is given by:

Ffriction\(= μk * m * g\)

where μk is the coefficient of kinetic friction, m is the mass of the skier, and g is the acceleration due to gravity.

Substituting this into our equation for\(δk, \\\)we get:

\(δk = μk * m * g * s\\\)

Setting δk equal to wtotal, we can solve for μk:

\(μk = wtotal / (m * g * s)\)

Substituting in the values we know, we get:

μk = (1/2mv^2) / (m * g * s)

Simplifying, we get:
\(μk = v^2 / (2 * g * s)\)

Therefore, the coefficient of kinetic friction μk between the skis and the snow is given by:
\(μk = v^2 / (2 * g * s)\)

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17.Shenna is observing two mineral samples in science class. He records his observations of the

samples in

the table below,

Minerals

Pyrite

Description

cubic crystals

Mica

breaks into thin sheets

Which property of the samples has Shenna recorded?

A. cleavage

B. hardness4

C. luster

D. streak

Answers

Shenna has recorded the property of cleavage. Cleavage refers to the tendency of a mineral to break along flat, smooth planes due to its internal structure.structure.So,The correct option would be (A) Cleavage.

Cleavage is a property that describes how a mineral breaks along planes of weakness, resulting in smooth, flat surfaces. It is one of the key characteristics used to identify and classify minerals.

In the given observations, Shenna noted that the mineral sample called "Mica" breaks into thin sheets. This characteristic indicates that Mica exhibits cleavage. When Mica is subjected to stress or force, it breaks along flat planes, resulting in thin, sheet-like fragments.

On the other hand, Shenna described the mineral sample called "Pyrite" as having cubic crystals. While this information is valuable for identifying Pyrite, it does not pertain directly to the property of cleavage.

Shenna has recorded the property of cleavage based on his observation that the mineral sample called "Mica" breaks into thin sheets.sheets.Hence the correct answer is Cleavage. Cleavage refers to the tendency of a mineral to break along flat, smooth planes due to its internal structure.

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The energy of motion is called ......

Answers

Answer:

kinetic energy

Explanation:

How much gravitational energy does a 65 kg skydiver have 650 m up in the sky?

Answers

Answer:

G.P.E  = 414050 Joules or 414.05 Kilojoules

Explanation:

Given the following data;

Mass = 65 kg

Height = 650 m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

\( G.P.E = mgh\)

Where;

G.P.E represents potential energy measured in Joules.m represents the mass of an object. g represents acceleration due to gravity measured in meters per seconds square. h represents the height measured in meters.

Substituting into the equation, we have;

\( G.P.E = 65 * 9.8 * 650 \)

\( G.P.E = 414050 \)

G.P.E  = 414050 Joules or 414.05 Kilojoules.

What was Kepler able to conclude from his analysis of the motions of Mars?

Answers

It is found that from his analysis of the motions of Mars, Johannes Kepler was able to conclude several important observations and formulate his famous laws of planetary motion from his analysis of the motions of Mars.

Planetary Orbits: Kepler determined that the planets move around the Sun in elliptical orbits rather than circular ones, with the Sun located at one of the foci of the ellipse.

Equal Areas Law: Kepler observed that a line connecting a planet to the Sun sweeps out equal areas in equal periods of time.

This means that a planet moves faster when it is closer to the Sun and slower when it is farther away.

Harmonic Law: Kepler formulated a mathematical relationship known as the Harmonic Law, which states that the square of the orbital period of a planet is directly proportional to the cube of its average distance from the Sun.

This law allows for the comparison of the orbital characteristics of different planets.

These conclusions were groundbreaking in understanding the nature of planetary motion and provided a significant contribution to the development of modern astronomy and our understanding of the solar system.

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A man is inside an airplane and walking toward the back of the plane at 7 m/s. The plane is flying West at 245 m/s. What is the speed and direction of the plane relative to the man?



7 m/s East

238 m/s, East

252 m/s West

238 m/s, West

Answers

Answer:

7 m/s East

Explanation:

The speed of the man relative to the plane is given as 7 m/s. Given that he's walking in the corridor of the plane, this is his speed relative to the plane. Since he's moving to the back of the plane, and the aircraft is headed to west, the man's direction relative to the plane is East.

_________ is the systematic self-observation and analysis of one’s conscious experience.
A.
Interrogation
B.
Introgression
C.
Internalization
D.
Introspection


Please select the best answer from the choices provided

A
B
C
D

Answers

Answer:

D:Introspection

Explanation:

Answer:

D

Explanation:

took the test got it right

Which form of heat transfer occurs through fluid motions?

Answers

"The type of heat transfer that occurs through fluid motions is known as convection."

Convection, which is the extensive movement of molecules within gases and liquids, is the mechanism through which heat is transported. Conduction is used to move heat from the object to the fluid initially, but fluid motion is responsible for the bulk of the heat transfer.

Forced convection is the term for the movement of fluid caused by an external source (such as a fan, blower, etc.), while natural or free convection refers to the movement of fluid that occurs naturally. This type of heat transfer occurs only when the fluid is in motion.

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10 points to whoever answers!!!
What is the formula for work? What is the formula for power?

Answers

Answer:

power= work done /time.

Answer:

W = Force  * distance

Power = W/ time

Explanation:

What is the use of a hydrometer​

Answers

Answer:

A hydrometer is an instrument used to determine specific gravity

Answer:

it is used determine specific gravity

Explanation:

and u can see them in use by measuring proof of moonshine

when properly supplied, both a selectable gallonage nozzle and a _____ will discharge a pre-determined gallonage a. automatic fog nozzle b. constant flow fog nozzle c. high-pressure fog nozzle d. selectable gallonage nozzle

Answers

When properly supplied, both a selectable gallonage nozzle and an a. automatic fog nozzle will discharge a pre-determined gallonage.

Correct answer is a. automatic fog nozzle

A selectable gallonage nozzle is a firefighting tool that allows firefighters to choose from several flow settings to suit various firefighting tasks. The operator can switch between a narrow, straight stream and different spray patterns, depending on the fire situation. This is accomplished by changing the baffle position inside the nozzle, which regulates the water flow rate.

Automatic fog nozzle: The Automatic fog nozzle is a special kind of nozzle that operates at a constant pressure and is used to spray water or other extinguishing agents. It creates a uniform, adjustable, and steady spray pattern that is ideal for extinguishing fires in enclosed spaces like buildings or rooms. It's called an automatic nozzle because it maintains a consistent flow rate as the pressure increases or decreases, without the need for an operator to adjust it.

Constant flow fog nozzle: A constant flow fog nozzle is a firefighting tool that combines the advantages of a constant flow nozzle with the benefits of a fog nozzle. A fixed orifice inside the nozzle limits the water flow rate, ensuring that it remains consistent regardless of the pressure. At the same time, the nozzle produces a cone-shaped mist that is ideal for extinguishing fires and cooling surfaces. It's particularly useful for combating high-temperature fires.

High-pressure fog nozzle: High-pressure fog nozzles are used in both firefighting and industrial applications where water consumption and visibility are important considerations. These nozzles operate at very high pressures, around 1,000 psi or higher, and use a special orifice design to atomize the water into tiny droplets. The mist produced is ideal for cooling and extinguishing fires without using a lot of water. It can also be used to suppress dust and reduce air pollution. However, this was not mentioned in the question.

When properly supplied, both a selectable gallonage nozzle and an automatic fog nozzle will discharge a pre-determined gallonage. Thus, the correct option is A. automatic fog nozzle.

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The ball and the shoulder area ABOVE the armpit of an attacker make contact and the ball goes into goal. What is the decision by the referee?

Answers

The referee should award a goal to the attacker since the part of the body in contact with the ball is not hand and it cannot be considered as handball.

Goal rules for soccer

There are several rules considered during a game of soccer before the referee will award goal.

Some of the rules include;The ball must cross the goal lineThe attacker must be on sideThe attacker must play the ball with any part of the body EXCEPT the hand.

The shoulder area ABOVE the armpit is not part of the hand, thus the referee should award a goal to the attacker since the part of the body in contact with the ball is not hand and it cannot be considered as handball.

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At what distance from a 1.00*10^-5 C charge will the electric potential be 10000 V? (Unit = m)​

Answers

Answer:

9.0 m

Explanation:

Applying

V = kq/r......................... Equation 1

Where V = Electric potential, q = charge, r = distance, k = Coulomb's constant.

make r the subject of the equation

r = kq/V................... Equation 2

From the question,

Given: q = 1.00×10⁻⁵ C, V = 10000 V

Constant: k = 9.0×10⁹ N⋅m²/C²

Substitute these values into equation 2

r = (9.0×10⁹×1.00×10⁻⁵)/10000

r = 9.0 m

Answer:

9.0

Explanation:

what is the light intensity (in terms of i0i0 ) at points aa , bb , and cc ? express your answers in terms of i0i0i 0 separated by commas

Answers

The light intensity at points A, B, and C can be expressed in terms of I0, which represents the initial intensity of the light.



At point A, the light intensity is equal to I0, as it is at the same distance from the source as the reference point.

At point B, the light intensity decreases with distance from the source. Let's say point B is twice as far away from the source compared to the reference point.

In this case, the light intensity at point B would be (1/2)² times I0, which simplifies to (1/4) times I0.

At point C, the light intensity also decreases with distance from the source. If point C is three times as far away from the source compared to the reference point, the light intensity at point C would be (1/3)² times I0, which simplifies to (1/9) times I0.

In conclusion, the light intensity at point A is I0, at point B is (1/4)I0, and at point C is (1/9)I0.

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