If the strong pull illustration below , a gradual pull of the lower string results in the op le strong breaking. Does this occur because of the balls weight or it’s mass?

Answer: 4.speed

Explanation:

In this case, we know that the cart remains at a constant 20km/h.

Now, one could say that "the velocity remains constant, because it always is 20km/h"

But remember that velocity is a vector, so this has a direction, and if the cart is going around a turn, then the direction of motion is changing, which tell us that there is acceleration.

But the module of the velocity, the speed, remains constant at 20km/h.

Then the correct option is 4, speed.

When heat is applied to a substance/material or steel in our case, a series of changes will occur, one of which is Expansion.

Hence the hole will expand from 1cm to a diameter that is greater.

Thermal expansion refers to the expansion or contraction of the dimensions of the solid, liquid or gas when their temperature is changed.

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Answer:

D = 4.47d

Explanation:

given that

1/R(eq) = 20/R

R(eq) = R/20

also, we know that the formula for resistance is given by the relation

R = pl/A, where A is πd²/4

If we substitute the value of A, we have

R = pl/(πd²/4)

R = 4pl/πd²

Now, we substitute this in the earlier derived equation

R(eq) = (4pl/πd²) / 20

R(eq) = pl/5πd²

To find the resistance of a single wire made of the same material, the resistance is

R(D) = 4pl / πD²

R(eq) = R(D), and thus

pl/5πd² = 4pl/πD²

1/5d² = 4/D²

D² = 20d²

D = √20d²

D = 4.47 d

The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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Answer:

i got u

Explanation:

The electromagnetic spectrum and microwaves have played a critical role in many scientific discoveries, including:

1. Cosmic Microwave Background Radiation: In 1964, Penzias and Wilson discovered Cosmic Microwave Background Radiation (CMB) using a microwave antenna. CMB is the remnant radiation from the Big Bang and provides evidence for the theory of the Big Bang.

2. Radio Astronomy: Radio astronomy is the study of celestial objects and phenomena that emit radio waves. Radio telescopes, which are designed to capture radio waves, have allowed scientists to observe and study many celestial objects, such as pulsars, quasars, and black holes.

3. Medical Imaging: Microwaves and other parts of the electromagnetic spectrum have also played a critical role in medical imaging. Magnetic Resonance Imaging (MRI) and X-rays use different parts of the electromagnetic spectrum to generate images of the human body, helping doctors to diagnose and treat medical conditions.

4. Telecommunications: The use of microwaves in telecommunications has revolutionized the way we communicate with each other. Microwaves are used to transmit information through mobile phones, radios, and televisions, and are an essential part of modern communication technology.

5. Microwave Ovens: Microwave ovens are a common household appliance that use microwaves to cook food. The microwaves penetrate the food and cause the water molecules in the food to vibrate, generating heat and cooking the food.

Overall, the electromagnetic spectrum and microwaves have played a significant role in many scientific discoveries, and their use continues to evolve and impact many areas of our lives.

Answer:

ok

Explanation:

Answer:

shooting

Explanation:

i hope you're joking

Answer:

it is D and B because they are both indicators

Answer:

The principle of simple machine states that "if there is no friction in a simple machine, work output and work input are found equal in that machine.

Explanation:

Answer:

Usually, the term refers to the six classical simple machines which were defined by Renaissance scientists:

Also, a simple machine uses a single applied force to do work against a single load force.

Answer:

1000s

Explanation:

Let t1 be time for 2km in 3m/s

t1= 2000/3

And t2 in the next 2km

t2= 2000/v.

So finding the average velocity

4000/t1+t2

=4000/2000(1/3+ 1/v)

V= 6m/s..

For 9km distance in 6m/s

The whole trip is 4m/s

So total time

4000/4=1000s

Answer:

It will take 0.46 seconds to reach home plate by ball.

Explanation:

Answer:

To test your hydraulic skills, your Boss has requested you calculate the difference in water surface elevation between two reservoirs that are connected.

Explanation:

The true facts about a fission chain reaction is that it involves the breakdown of a large nucleus into daughter nuclei when bombarded by a small particle such as a neutron. It is a self sustaining reaction.

Nuclear fission is said to have occurred when a neutron is used to bombard an unstable or fissile nucleus such that it breaks down into smaller daughter nuclei releasing tremendous energy in the process.

The reaction is self sustaining because more neutrons are produced as the fission reaction proceeds which ensures that the reaction continues.

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Answer: The number of freely moving neutrons increases over time

Explanation:

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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The distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

The distance that a person covers to come to a complete stop in 38 ms at a constant acceleration of 60 g can be calculated using the kinematic equation.

The formula is given by, d = (v^2 - u^2) / 2a, where d is the distance traveled, v is the final velocity, u is the initial velocity, and a is the acceleration given in g units.

To solve the problem, we need to first convert the acceleration given in g units to meters per second squared (m/s²). We know that 1 g is equivalent to 9.8 m/s².

Hence, 60 g is equivalent to 60 × 9.8 m/s² = 588 m/s².

Substituting the values in the above formula, we get,d = (0 - u^2) / 2a= u^2 / 2a, since the final velocity is 0 when the person comes to a complete stop= u^2 / 2 × 588= u^2 / 1176 m

The time taken, t = 38 ms = 0.038 s.

Now, we know that acceleration, a = (v - u) / t.

We can rearrange the above equation to find the final velocity, v. We get,v = u + at

Substituting the values, we get,588 = u + (588 × 0.038)u = 588 - (588 × 0.038)u = 567.816 m/s

Using the value of u, we can now find the distance traveled using the kinematic equation as, d = u^2 / 1176= (567.816)^2 / 1176≈ 273.42 m.

Therefore, the distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

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a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².

The relationship between the temperature,T and the peak wavelength, \(\lambda\) emitted by a black body is given by wien's displacement law:

\(\lambda\) = b / T

Where, b is a constant and it's value is 2.898 * 10-3 m-K

Given: T = 8400 K

So, \(\lambda\) =   (2.898 * 10-3 )/8400

\lambda = 3.45 * 10-7  

\lambda = 345 nm

Hence, the peak wavelength of the object at this temperature is 345 nanometre.

The amount of power emitted per unit area, P is given by Stefan Boltzmann law:

P =\(\sigma\)T⁴

Where,

Absolute temperature, T = 8400 K

Stefan Boltzmann constant, \(\sigma\) = 5.67 * 10-8 W/m²K⁴

So, P = 5.67 * 10-8 * (8400)⁴

P = 2.82 * 10⁸  W/m²

Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².

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Answer:

it is given that the water is to be compressed by 0.10%. Therefore, the pressure on the water should be

2.2 × 10^6 Nm ^ -2 .

Answer:

Longitudinal and transverse waves have many similarities and differences.

Explanation:

Similarities:

Mechanical waves can be transverse and longitudinal waves.

Transverse and longitudinal waves both have wavelengths and frequencies.

They both have amplitudes

Both waves can travel through a medium or not, but it depends on whether is an electromagnetic or a mechanical wave.

Differences:

Electromagnetic waves can only be transverse.

The particles of the medium in a longitudinal wave move parallel to the direction (motion) of a wave. It is in this back and forth motion.

The particles of the medium in a transverse wave move perpendicular to the direction (motion) of a wave. This means that there would be right angles showing that they are perpendicular.

Longitudinal waves have rarefactions and compressions.

These rarefactions and compressions are used to measure the wavelength of a wave. For instance, a wavelength in a longitudinal wave is measured from rarefaction to rarefaction

Transverse waves have troughs and crests.

Amplitude in a transverse wave is measured from the midline to the crest of trough.

Amplitude in a longitudinal wave is measured based on how closely packed the particles of the medium are

I hope this helps

Answer:

Longitudinal and transverse waves are mechanical waves, so both carry energy through particles of matter. Longitudinal waves transfer energy parallel to the direction of wave motion, and transverse waves transfer energy perpendicular to the direction of wave motion.

Explanation:

trust me youll get it right :D

Answer:

Explanation:

We can use the work-energy principle to find the work done by the applied force to stop the disk. The work-energy principle states that the work done by all forces acting on an object is equal to the change in its kinetic energy:

W = ΔK

where W is the work done, and ΔK is the change in kinetic energy.

Initially, the disk is rotating with an angular velocity of 950 rev/min. We need to convert this to radians per second, which gives:

ω_initial = (950 rev/min) × (2π rad/rev) × (1 min/60 s) = 99.23 rad/s

The initial kinetic energy of the disk is:

K_initial = (1/2) I ω_initial^2

where I is the moment of inertia of the disk about its axis of rotation. For a uniform disk, the moment of inertia is:

I = (1/2) m R^2

where m is the mass of the disk, and R is the radius. Substituting the given values, we get:

I = (1/2) (190 kg) (1.1 m)^2 = 115.5 kg m^2

Therefore, the initial kinetic energy of the disk is:

K_initial = (1/2) (115.5 kg m^2) (99.23 rad/s)^2 = 565201 J

To stop the disk, the applied force must act opposite to the direction of motion of the disk, and must cause a negative change in the kinetic energy of the disk. The force is applied at a radial distance of 0.5 m, which gives a torque of:

τ = F r

where F is the magnitude of the force. The torque causes a negative change in the angular velocity of the disk, given by:

Δω = τ / I

The work done by the applied force is:

W = ΔK = - (1/2) I Δω^2

Substituting the given values, we get:

W = - (1/2) (115.5 kg m^2) [(F r) / I]^2

The force F can be eliminated using the equation for torque:

F = τ / r = (Δω) I / r

Substituting this into the equation for work, we get:

W = - (1/2) (115.5 kg m^2) [(Δω) I / r I]^2

= - (1/2) (115.5 kg m^2) (Δω / r)^2

Substituting the values for Δω and r, we get:

W = - (1/2) (115.5 kg m^2) [(F r / I) / r]^2

= - (1/2) (115.5 kg m^2) [(2 Δω / R) / (2/5 m R^2)]^2

= - (1/2) (115.5 kg m^2) (25/4) (2 Δω / R)^2

= - 90609 J

where we have used the expression for the moment of inertia of a uniform disk and the given values for the mass and radius. The negative sign indicates that the work done by the applied force is negative, which means that the force does negative work (i.e., it takes energy away from the system). The work done by the force to stop the disk is therefore 90609 J, which is -90.6 kJ (to two decimal places).

Answer:

57 mm

Explanation:

57 mm is equivalent to 5.7 cm

Answer:

Examples of Radiant Energy All Around You

The term radiant energy refers to energy that travels by waves or particles, particularly electromagnetic radiation such as heat or x-rays. Radiant energy is created through electromagnetic waves and was discovered in 1885 by Sir William Crookes. Fields in which this terminology is most often used are telecommunications, heating, radiometry, lighting, and in terms of energy created from the sun. Radiant energy is measured in joules.

Everyday Examples of Radiant Energy

Virtually anything that has a temperature gives off radiant energy. Some examples of radiant energy include:

•The heat emitted from a campfire

•Emission of heat from a hot sidewalk

•X-rays give off radiant energy

•Microwaves utilize radiant energy

•Space heaters produce radiant energy

•Heat created by the body can be radiant energy

•Lighting fixtures

√Home heating units

•Fixtures that convert solar energy to heat

•Visible light

•Gamma rays

•Radio waves

•Electricity

•A surface heated by the sun converts the energy of the light into infrared energy which is a form of radiant energy

•Cell phones utilize radiant energy to function

•Magnetic motor generators that utilize •neodymium magnets create radiant energy

•Audio signals that come to home or cars via radio waves

•Ultraviolet light

√Infrared radiation

•The light emitted from a campfire

•The light generated from a light bulb

•A heated brake disc giving off heat

•The heat from a grill used for cooking

•Water can reflect or absorb radiant energy

•Soil can absorb radiant energy

•Light from the sun

•Heat emitted from a bunsen burner

•Heat from an overused computer

•Heat caused by friction

•Heat emitted from a dryer

•The heat generated by a light bulb

•Heat generated through reflection of visible light

•A window reflects radiant energy

•Heat created from a stove or oven

•Heat emitted from a washing machine

Answer:

192.6N

Explanation:

Let's consider the forces acting on the beam:

Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.

Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.

Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.

Let's break down the forces acting on the beam:

Vertical forces:

W (weight of the beam) - T (vertical component of tension) = 0

T = W

Horizontal forces:

F_link (horizontal component of the force exerted by the link) = ?

To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.

Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:

F_link = W * sin(θ)

Let's substitute the given values:

W = 39.4 kg * 9.8 m/s^2

θ = 33.1 degrees

F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)

Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.

Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.

Average Velocity = Displacement / Time

Displacement = 55 km (since he rode 55 km to the east)

Time = 51 minutes

Average Velocity = 55 km / 51 min

To express the average velocity in km/min, convert the time from minutes to minutes.

1 hour = 60 minutes

Average Velocity = 55 km / 51 min × (1 hour / 60 min)

Average Velocity = 55 km / 51 min × (1/60) hour

Simplifying the expression:

Average Velocity = 1.078 km/min

Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Explanation:

Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. ... In electrical terms, the joule equals one watt-second—i.e., the energy released in one second by a current of one ampere through a resistance of one ohm.

Answer:

A^2+B^2 is the scalar product of A and B

Answer:

Scalar product is equal to the magnitude a vector a times the projection of a onto vector B,

Answer:

4 degrees C

Explanation:

this is just a 'known'

The velocity of the boy skater if the mass is 50kg is 3 m/s.

The GUESCA method stands for Given, Unknown, Equation, Substitution, Calculation, and Answer. Let's use this method to solve the problem.

Given:

Mass of the girl (m₁) = 30 kg

Velocity of the girl (v₁) = -5 m/s (negative sign indicates backward direction)

Mass of the boy (m₂) = 50 kg

Velocity of the boy (v₂) = unknown (to be calculated)

Unknown:

Velocity of the boy (v₂)

Equation:

According to the law of conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction. Mathematically, it can be expressed as:

(m₁ * v₁) + (m₂ * v₂) = 0

Substitution:

Plugging in the given values, we have:

(30 kg * -5 m/s) + (50 kg * v₂) = 0

Calculation:

Simplifying the equation, we get:

-150 kg·m/s + 50 kg·v₂ = 0

Rearranging the equation to solve for v₂, we find:

50 kg·v₂ = 150 kg·m/s

v₂ = 150 kg·m/s / 50 kg

v₂ = 3 m/s

Answer:

The velocity of the boy skater is 3 m/s.

Using the GUESCA method, we identified the given and unknown quantities, wrote the relevant equation, substituted the values, performed calculations, and obtained the answer.

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Explanation: Magma is molten rock found below the earth's surface. ... On the other hand, if the rocks are under greater pressure, they will require higher temperatures to melt. Melting of rocks typically occurs in the lower lithosphere or upper asthenosphere. The earth gets hot pretty quickly as you dig down from the earth's surface.