Answers
Related Questions
Solve the equation 2b-20=8
Answers
Answer:
B=14
Explanation:
2(14)-20=8
28-20=8
you have two solid metal sphere that are identical except thatr one has a radius exactly twice the other(with the same density). what is the ratio of their moment of inertia?
Answers
The elasticity and Poisson's ratio for this metal is 0.232.
What is ratio?
The realation between two numbers which shows how much bigger one quantity is than another.
Sol-
As per the given question
P=190KN
d=16 mm
Lo=50mm
X=50.1349-50=0.1349mm
Y=15.99-16=-0.01mm
The formula-
E=ó/€
Ó=P/A
A=r/4 d^2 =π/4(16)^2=201.062 mm
ó={190(1000)}201.062=944.982 Mpa
E=944.982/0.002698=350.253 GPa
€y=-0.000625
v=0.232(answer)
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Marine science- question- what is climate change?
Answers
Answer:
Defined below
Explanation:
Climate change is simply the long term change in the average weather patterns that are associated with the local, regional and global climates of the earth. Climate change is usually driven by human activities like burning of fossils; natural processes like cyclic ocean patterns; external factors like volcanic eruptions.
A book remains at rest on a table. It is so because of:
A
no force acts on it
B
friction between the book and the surface of table
C
force exerted by book on the table, is same as the force exerted by the table on the book
D
all of the above
Easy
Answers
According to the information we can infer that the correct option is B. friction between the book and the surface of the table.
What happen to the book to remains at rest on a table?When a book remains at rest on a table, it is because of the presence of friction between the book and the surface of the table. Friction is a force that opposes the relative motion between two surfaces in contact. In this case, the frictional force acts in the opposite direction to the force that would cause the book to slide or move.
According to the information we can infer that the correct answer is option B, friction between the book and the surface of the table, as it is the frictional force that keeps the book in a state of rest on the table.
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4
9
Two objects X and Y move directly towards each other. The objects have the same mass.
Object X has a velocity of 5.0m/s to the right. Object Y has a velocity of 3.0 m/s to the left.
3.0 m/s
5.0 m/s
Y
Х
Object X and object Y collide and stick together.
What is their velocity after colliding?
A
1.0 m/s to the left
B
1.0 m/s to the right
с
4.0 m/s to the left
D
4.0m/s to the right
Answers
The velocity of the two objects velocity after colliding is B 1.0 m/s to the right.
To determine the velocity of the two objects after colliding, we need to consider the conservation of momentum. Since the masses of objects X and Y are the same, let's call their mass "m."
Before collision, the momentum of object X is m(5.0 m/s) and the momentum of object Y is m(-3.0 m/s), as it moves to the left. The total initial momentum is m(5.0 m/s) + m(-3.0 m/s) = m(2.0 m/s).
After collision, the objects stick together, so their combined mass is 2m. To find their final velocity, we'll divide the total initial momentum by their combined mass: (m(2.0 m/s))/(2m).
The mass "m" cancels out, and we're left with a final velocity of 1.0 m/s to the right. Therefore, the correct answer is B 1.0 m/s to the right.
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Naomi has increased the pressure on a solution of liquid and gas in a closed container. What will this do to the gas in her solution?
Answers
Answer:
Increase the amount of gas
Explanation:
By increasing the pressure of the solution, the amount of gas will have to increase. Solubility of gases increases as the pressure is made to increase. Before the pressure was increased, the gases moved freely about. But as it was increased, theses gases had more frequent collisions within this solution. Causing an increase. The liquid on its own will experience no changes.
Answer:
Increase the amount of gas
Explanation:
An action/reaction pair of forces ....
Select all that are True.
act on the same object.
point in the opposite direction.
act on two different objects.
point in the same direction.
Answers
Action-reaction pairs are forces that operate on separate objects in opposing directions and at identical magnitudes. Never do they affect the same thing. We learn that forces are interactions from Newton's third law.
An action-reaction pair is what?When two bodies contact, they exert an equal and opposite force on one another in accordance with Newton's third rule of motion. Action-reaction forces are made up of these forces.
What do action and reaction forces look like in practice?Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two separate objects together.
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What is the current through this circuit?
Answers
Answer: 1.25 A
Explanation:
I = R/V (Ohm's Law)
I = 150 Ω / 120 V = 1.25 A
A student is building a model of a lens that will spread light over the biggest space. Which best describes the type of model the student should make?
O A The student should make a convex lens model because it directs light away from the center of the lens.
OB. The student should make a concave lens model because it breaks light down into bands of color
c. The student should make a concave lens model because it directs light away from the center of the lens
D. The student should make a convex lens model because it breaks light down into bands of color.
Answers
Answer:
C. The student should make a concave lens model because it directs light away from the center of the lens
Explanation:
The student should make a concave lens model because it directs light away from the center of the lens.
What is Concave lens?A lens that has at least one inward-curving surface is said to be concave. Since it is a divergent lens, light rays that have been bent by it are dispersed. Short-sightedness is treated by concave lenses, which are thinner in the center than the borders (myopia).
The earliest known usage of a corrective lens is mentioned in Pliny the Elder's writings (23–79). Pliny claims that Emperor Nero used an emerald, perhaps concave formed to adjust for myopia, to watch gladiatorial matches.
After passing through the lens, light beams appear to originate from a spot known as the primary focus.
Therefore, The student should make a concave lens model because it directs light away from the center of the lens.
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A train is accelerating at a rate of 2.0 m/s/s. If it accelerates at this rate for 30
seconds, what is the change of velocity? *
Answers
Answer:
60m/s
Explanation:
Given parameters:
Acceleration = 2m/s²
Time = 30s
Unknown:
Change in velocity = ?
Solution:
Acceleration is the rate of change of velocity with time.
Mathematically;
Acceleration = \(\frac{Change in velocity }{Time }\)
Now,
Change in velocity = Acceleration x time
So,
input the parameters and solve;
Change in velocity = 2 x 30 = 60m/s
In which of the following situations is there acceleration? (There may be more than one correct answer)
a. A car is sitting at a stoplight. The light turns green and the car begins moving.
b. A car maintains a speed of 10 mi/hr as it turns a corner.
c. When a truck approaches a stop light, it begins to slow down.
d. A car travels at 65 mi/hr.
Answers
four particles enter a uniform magnetic field that points into the page, as shown below. they each enter the magnetic field with the same velocity, and each particle has the same mass. they do not, however, have the same charge. which of the particles has the least amount of charge on it?
Answers
The particle with the least amount of charge on it is particle D.
The particle with the least amount of charge on it is the one that has the least amount of curvature in its path, which is particle D.
This is because the force on a charged particle in a magnetic field is given by the equation F = qvB, where F is the force, q is the charge, v is the velocity, and B is the magnetic field.
The force is perpendicular to both the velocity and the magnetic field, and causes the particle to move in a circular path. The radius of this path is given by the equation r = mv/qB, where m is the mass of the particle.
As we can see from this equation, the radius of the path is inversely proportional to the charge of the particle.
This means that the particle with the least amount of charge will have the largest radius, and therefore the least amount of curvature in its path. In this case, that is particle D.
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During a demonstration of Newton’s laws of motion, a student used the setup shown in Figure 1. The student flicked the index card with a fingertip, and the coin fell straight down into a plastic cup as shown in Figure 2.
A: A falling body accelerates at a constant speed.
B: The motion of an object is constantly changing due to magnetic forces.
C: The force friction causes an object in motion to move faster.
D: An object remains at rest, or at a constant speed, an unbalanced force acts on it.
Answers
Answer:
D. An object remains at rest, or at a constant speed, an unbalanced force acts on it.The coin was at rest until the card was removed, so it tended to remain in the same location. Once the card was gone, the unbalanced force of gravity caused the coin to fall.
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pts
You walk 10 meters east, then 5 meters north. What is your displacement?
Answers
The angle East of North is = inv tan ( 5/10 )
The direction of the electric field is in the direction that a
_______ test charge would be pushed or pulled if placed in the space surrounding the source charge.
Answers
Answer:
The correct answer is Positive
Explanation:
Put the word POSITIVE
a sonar system can use sound waves wih a frequency of 120kHz or 200kHz. A. what is the wavelength of each of these waves when they are sent through sea water?
B. What are their wavelengths in freshwater?
C. The ship operating these sonar systems is in sea water with a depth of 3km.
How long will it take an echo to return to the ship after a ‘ping’
Answers
(A) The wavelength of each of these waves when they are sent through sea water is 0.0126 m and 0.0076 m respectively.
(B) The wavelength of each of these waves when they are sent through freshwater is 0.012 m and 0.0074 m respectively.
(C) The time taken for the echo to return to the ship is 3.97 seconds.
What is the wavelength of the sound wave in sea water?
The wavelength of the sound wave in sea water depends on the speed of sound in seawater and frequency of the wave.
The speed of sound in seawater, v = 1,510 m/s
λ = v/f
when the frequency, f = 120 kHz
λ = 1510 / 120,000
λ = 0.0126 m
when the frequency, f = 200 kHz
λ = 1510 / 200,000
λ = 0.0076 m
The speed of sound in freshwater, v = 1481 m/s
when the frequency, f = 120 kHz
λ = 1481 / 120,000
λ = 0.012 m
when the frequency, f = 200 kHz
λ = 1481 / 200,000
λ = 0.0074 m
The time taken for the echo to return is calculated as follows
v = 2d/t
t = 2d/v
t = (2 x 3,000 m) / (1510 m/s)
t = 3.97 s
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what happens to the light gathering power of a telescope if we double the diameter of its primary mirror?
Answers
Doubling the diameter of a telescope's primary mirror increases its light gathering power by fourfold, allowing the telescope to view and record faint details in deep space and reduce the effects of atmospheric distortion.
The larger primary mirror allows the telescope to gather more light from dim, distant stars and other faint objects in the sky. This makes the telescope more powerful, allowing it to view and record faint details in deep space. A larger primary mirror also increases the angular resolution of the telescope, which is the ability of the telescope to distinguish two objects that are close together.
Finally, a larger primary mirror helps to reduce the effects of atmospheric distortion. As light from distant stars travels through the atmosphere, it is affected by turbulence and refraction which can distort the image. A larger mirror will help reduce the amount of distortion caused by these atmospheric conditions.
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The half life of phosphorus-33 is 25 days. After 50
days, What is the original sample size if 10 g
remain?
Answers
The half-life of a first-order reaction is a constant that is related to the rate constant for the reaction: t1/2 = 0.693/k.
What is phosphorus-33?It is used in life-science laboratories in applications in which lower energy beta emissions are advantageous such as DNA sequencing. P can be used to label nucleotides. It is less energetic than 32P, giving a better resolution.
Phosphorus 33 is an artificial radioactive element. It is produced with a low yield by the neutron bombardment of phosphorus 31 (stable). The phosphorus 33 has a radioactive period of 25.3 days.
Phosphorus-33 atom is the radioactive isotope of phosphorus with relative atomic mass 32.971725, half-life of 25.34 days and nuclear spin (1)/2.
Phosphorus was discovered by the German merchant Hennig Brand in 1669.
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In a Young's double-slit experiment, a set of parallel slits with a separation of 0.102 mm is illuminated by light having a wavelength of 575 nm and the interference pattern observed on a screen 3.50 m from the slits.(a) What is the difference in path lengths from the two slits to the location of a second order bright fringe on the screen?(b) What is the difference in path lengths from the two slits to the location of the second dark fringe on the screen, away from the center of the pattern?
Answers
Answer:
Rounded to three significant figures:
(a) \(2 \times 575\; \rm nm = 1150\; \rm nm = 1.15\times 10^{-6}\; \rm m\).
(b) \(\displaystyle \left(1 + \frac{1}{2}\right) \times (575\;\rm nm) \approx 863\; \rm nm = 8.63\times 10^{-7}\; \rm m\).
Explanation:
Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.
Let \(k\) denote a natural number (\(k \in \left\lbrace0,\, 1,\, 2,\, \dots\right\rbrace\).) In a double-split experiment of a monochromatic light:
A maximum (a bright fringe) is produced when light from the two slits arrive while they were in-phase. That happens when the path difference is an integer multiple of wavelength. That is: \(\text{Path difference} = k\, \lambda\).Similarly, a minimum (a dark fringe) is produced when light from the two slits arrive out of phase by exactly one-half of the cycle. For example, The first wave would be at peak while the second would be at a crest when they arrive at the screen. That happens when the path difference is an integer multiple of wavelength plus one-half of the wavelength: \(\displaystyle \text{Path difference} = \left(k + \frac{1}{2}\right)\cdot \lambda\).MaximaThe path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where \(k = 0\) in \(\text{Path difference} = 0\).
The path difference increases while moving on the screen away from the center. The first order maximum is at \(k = 1\) where \(\text{Path difference} = \lambda\).
Similarly, the second order maximum is at \(k = 2\) where \(\text{Path difference} = 2\, \lambda\). For the light in this question, at the second order maximum: \(\text{Path difference} = 2\, \lambda = 2 \times 575\; \rm nm = 1.15\times 10^{-6}\; \rm m\).
Central maximum: \(k = 0\), such that \(\text{Path difference} = 0\).First maximum: \(k = 1\), such that \(\text{Path difference} = \lambda\).Second maximum: \(k = 2\), such that \(\text{Path difference} = 2\, \lambda\).MinimaThe dark fringe closest to the center of the screen is the first minimum. \(\displaystyle \text{Path difference} = \left(0 + \frac{1}{2}\right)\cdot \lambda = \frac{1}{2}\, \lambda\) at that point.
Add one wavelength to that path difference gives another dark fringe- the second minimum. \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda\) at that point.
First minimum: \(k =0\), such that \(\displaystyle \text{Path difference} = \frac{1}{2}\, \lambda\).Second minimum: \(k =1\), such that \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda\).For the light in this question, at the second order minimum: \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda = \left(1 + \frac{1}{2}\right)\times (575\; \rm nm) \approx 8.63\times 10^{-7}\; \rm m\).
ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
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Answers
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.
A car is Travis a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds what is the acceleration
Answers
Answer: 6 m/s^2
Explanation:
The acceleration of car is 6 m/s^2.
To calculate acceleration, we can use the following formula:
acceleration = (final velocity - initial velocity) / time
Substituting the given values, we get:
acceleration = (65 m/s - 35 m/s) / 5 s
acceleration = 30 m/s / 5 s
acceleration = 6 m/s^2
Therefore, the acceleration of the car is 6 m/s^2.
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What are the 7 steps of scientific method in order?
Answers
Answer:
1. Make an observation or ask a question.
2. Gather background information.
3. Create a hypothesis.
4. Create a prediction and perform a test.
5. Analyze the results and draw a conclusion.
6. Share the conclusion or decide what question to ask next.
7. Document the results of your experiment.
Hope this helps!
Seven scientific methods are observation, research, hypothesis, experimentation, data collection, result, conclusion and note.
What are the steps of scientific method ?Observation: Observe and identify a problem or question to be solved.
Research: Research and gather information and background knowledge on the problem.
Hypothesis: Develop a possible solution or explanation (hypothesis) for the problem.
Experimentation: Plan and conduct experiments to test the hypothesis.
Data Collection: Collect and analyze data from the experiments.
Results: Interpret and analyze the results to determine if the hypothesis was supported or rejected.
Conclusion: Draw a conclusion and make a statement about the problem based on the evidence collected during the experiments.
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A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is 700 kg, and the total resistance (air drag plus friction with the runway) on each may be assumed constant and equal to 2,500 N. The tension in the tow rope between the transport plane and the first glider is not to exceed 12,000 N.
What is the tension in the tow rope between the two gliders while they are accelerating for the takeoff?
Answers
The second law of Newton and kinematics allows to find the answers for the distance and tension are: The distance traveled is 133.3 m
kinematics studies the movement of bodies establishing relationships between the position, velocity and acceleration of bodies
v² = \(vo^{2}\) + 2ax
Where v is the velocity, v₀ the initial velocity, a the acceleration and x the distance traveled,
We look for the acceleration that the system has using Newton's second law,
Glider 1
x-axis
T₁ - T₂ - fr. = m a
y-axis
N₁ - W = 0
N₁ = W
Glider 2
x-axis
T₂ -fr = m a
y-axis
N₂ - W =0
N₂ = W
We write the system of equations
T₁ - T₂ -fr = m a
T₂ - fr = m a
We solve the system
T₁ - 2 fr = 2 m a
a = T1 - 2fr /2m
Indicates that the friction force for each glider is 1600 N
Calculate
a = 12000 - 3600 / 1400
a = 6 m / s²
Taking the acceleration we can use the kinematics relationship to find the distance traveled
v² = \(vo^{2}\) + 2ax
As part of rest the initial velocity is zero
v² = 0 + 2 ax
x = v² / 2 a
indicate that the speed of 40 { m/s} is required for takeoff
x = 1600 / 12
x = 133.33m
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What is the weight of a person who has a mass of 60 kg
Answers
Answer:
Depends on the grativy of the planet. On Earth is 600 Newtons
Explanation:
W = M . G
W = 60 . 10
W = 600
What are the two goals of the Artemis Mission?
Answers
Answer:
The Artemis program is a U.S. government-funded international human spaceflight program that has the goal of landing the first woman and the next man on the Moon, specifically at the lunar south pole region, by 2024.
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The spring mass system shown in Figure 2 is released from rest. The mass m slides vertically on the smooth rod. If the spring has a spring constant k and is unstretched at the position shown in the figure, determine the equations of motion for the mass.
Answers
Since I don't have access to the specific Figure 2 you mentioned, I won't be able to provide you with the exact equations of motion for the mass in the given system. However, I can provide you with a general framework for determining the equations of motion for a spring-mass system.
In a spring-mass system, the forces acting on the mass include the gravitational force (mg) and the spring force (kx), where m is the mass of the object, g is the acceleration due to gravity, k is the spring constant, and x is the displacement of the mass from its equilibrium position.
Using Newton's second law (F = ma), we can set up the equation of motion for the mass:
m * (d^2x/dt^2) = -kx - mgThis is a second-order linear differential equation, where (d^2x/dt^2) represents the acceleration of the mass with respect to time.
To solve this equation and obtain the equations of motion for the mass, you would need to apply appropriate initial conditions, such as the initial position and velocity of the mass.
If you can provide more specific information or a detailed description of the system in Figure 2, I can assist you further in determining the equations of motion.
About VelocityVelocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second. Velocity or speed: the quotient between the distance traveled and the time interval. Velocity or speed is a scalar quantity. Speed or velocity is the quotient of the displacement with the time interval. Speed or velocity is a vector quantity.
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4. The kinetic energy of a boat is calculated at 52,000 J. If the boat has a mass of 39,000
kg, with what velocity is it moving?
Answers
Answer:
The kinetic energy (KE) of an object is given by the formula:
KE = (1/2)mv^2
where m is the mass of the object and v is its velocity.
Given that the boat has a kinetic energy of 52,000 J and a mass of 39,000 kg, we can rearrange the formula to solve for v:
v = sqrt(2KE/m)
Substituting the values, we get:
v = sqrt[(2 x 52000 J) / 39000 kg]
v = sqrt(104000 J / 39000 kg)
v = sqrt(2.6667 J/kg)
v = 1.632 m/s
Therefore, the boat is moving with a velocity of approximately 1.632 m/s.
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You are a birdwatcher visiting the desert southwest. Which of the following birds are you most likely to find? a ferruginous pygmy owl, which often nests in saguaro cacti and eats insects a bay-breasted warbler, which feeds on larvae found in coniferous trees an orchard oriole, which builds its hanging nest in scrubby or open wooded areas an American dipper, which feeds on insects found in fast-flowing, rocky streams
Answers
As a birdwatcher visiting the desert southwest, the bird I am most likely to find is the ferruginous pygmy owl.
These owls are well-adapted to the arid desert environment and are often found nesting in saguaro cacti. Their small size and camouflage make them difficult to spot, but their distinctive call and active hunting behavior make them a sought-after sighting. The ferruginous pygmy owl primarily feeds on insects, which are abundant in the desert ecosystem, making it well-suited to this habitat.
While the bay-breasted warbler, orchard oriole, and American dipper are fascinating birds, they are not commonly found in the desert southwest. The bay-breasted warbler is typically found in coniferous forests and feeds on larvae found in trees. The orchard oriole prefers scrubby or open wooded areas, where it builds its hanging nest. The American dipper, on the other hand, is known for its unique adaptation to fast-flowing, rocky streams and feeds on insects found in these aquatic environments.
Therefore, if I were a birdwatcher in the desert southwest, my best bet for an exciting sighting would be the ferruginous pygmy owl, as it is well-suited to the arid conditions and can be found nesting in saguaro cacti.
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what index of refraction halves the wavelength that light has in a vacuum?
a) 1.33
b) 1.50
c) 1.41
d) 2.00
e) 5.00
Answers
The index of refraction that halves the wavelength that light has in a vacuum is 2.00. Therefore, the correct option is (d) 2.00.
When light passes from one medium to another, it changes its velocity, and thus its wavelength. The index of refraction is a measure of how much light is bent when passing through a medium and can be calculated using Snell's Law:n1sin θ1=n2sin θ2where n1 and n2 are the indices of refraction of the two media, and θ1 and θ2 are the angles that the light makes with the normal line in the first and second media, respectively.
For a given angle of incidence, we can see that the index of refraction is directly proportional to the sine of the angle of refraction, which means that as the angle of refraction increases, so does the index of refraction. Now, let's assume that light is passing from vacuum (with index of refraction n1=1) to a medium with an unknown index of refraction n2.
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what happens to the total energy in an isolated system
Answers
In an isolated system, the total energy remains constant. According to the law of conservation of energy, energy can neither be created nor destroyed; it can only be transferred or transformed from one form to another.
In an isolated system, which is a system that does not exchange energy or matter with its surroundings, the total energy within the system remains constant over time. While energy may be exchanged between different components or forms within the system, the sum of all energy remains unchanged.
For example, in a closed container with no external influences, the total energy of the system, including kinetic energy, potential energy, and any other forms of energy, remains constant. Energy can be converted between different forms within the system, but the total energy content remains conserved.
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