1. The four criteria for assessing a change in a system are environmental impact, economic impact, social impact, and technical feasibility.
Environmental impact: The use of electric toothbrushes may have a negative environmental impact due to the need for electricity to power them. However, if the electricity is generated from renewable sources, the impact may be minimal.
Economic impact: The cost of electric toothbrushes may be higher than manual toothbrushes, which may put a financial burden on some people. However, electric toothbrushes may also have a longer lifespan and require less frequent replacement, which may offset the initial cost.
Social impact: The use of electric toothbrushes may be seen as a status symbol, which may create social inequalities. Additionally, some people may prefer the feeling of a manual toothbrush, which may lead to resistance to the change.
Technical feasibility: The technology for electric toothbrushes already exists and is widely available, so this change is technically feasible.
2. Two methods of support used to keep a system operating safely and efficiently are maintenance and troubleshooting. Maintenance involves regularly checking and repairing components of the system to prevent breakdowns and ensure optimal performance. Troubleshooting involves identifying and resolving problems that arise during the operation of the system.
3.
a) The mechanical advantage of this pulley system is equal to the weight lifted divided by the force applied. In this case, the weight lifted is 500 N and the force applied is 100 N, so the mechanical advantage is 5.
b) The input that Marina did on the rope is equal to the force she applied multiplied by the distance she pulled the rope. In this case, the force is 100 N and the distance is 9.0 m, so the input is 900 J.
c) The useful output that the rope did on the weight is equal to the weight lifted multiplied by the distance it was lifted. In this case, the weight lifted is 500 N and the distance is 1.5 m, so the useful output is 750 J.
d) The efficiency of the pulley system is equal to the useful output divided by the input, multiplied by 100% to express the result as a percentage. In this case, the useful output is 750 J and the input is 900 J, so the efficiency is 83.3%.
An electric current can be generated in a wire in a circuit when at least part of the wire ____________.is coated in plastic.is made of aluminum.moves through and cuts magnetic field lines.is not moving.
Answer:
Explanation:
When a coil of wire is moved around a magnet, it induces electrons into the wire and creates electric current. Thus, the correct option is
moves through and cuts magnetic field lines
An object requires a force of magnitude x to accelerate at 5 m/s². What force is
required for it to accelerate at 10 m/s²?
The force required to accelerate the object at 10 m/s² is 4x/3.
What is the mass of the object?The mass of the object will be determined from the force and the acceleration produced by the applied force.
The relationship between the mass of an object, its acceleration and the applied force is given below:
Force = mass * accelerationThe force applied on the body which causes its acceleration includes the force applied to overcome the weight of the object.
Hence the total force applied will be:
Total force = net force + weight
Weight = m * g
Net force = m * a
Total force = ma + mg
g = 10 m/s²
The mass of the body is constant, g is constant, hence mg is constant.
Initial force x produces an acceleration 5 m/s².
x = 5m + mg
x = m(5 +10)
x = 15m
Second force y produces an acceleration of 10 m/s²
y = 10m + mg
y = m(10 + 10)
y = 20 m
Taking ration of the two forces:
y = 4x/3
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Youre diving down the highway late one night at 20 m/s when a deer steps onto the road 41 m in How much distance is between you and the deer when you came to a stop? frort of you. Your reaction time before stepping on the brakes is 0.50 s, and the maximum Express your answer with the appropriato units. deceleration of your car is 10 m/s
2
. Part B What is the maximum speed you could have and still not hit the deen? Express your answer with the appropriate units.
Given that the initial speed of the car is 20 m/s.
The car comes to a stop and the maximum deceleration of the car is 10 m/s².
Part A
To find the distance between the deer and the car when it comes to a stop, we need to find the distance traveled by the car after the brakes are applied.Using the formula:
v² = u² + 2
as where v = 0 (final velocity), u = 20 m/s (initial velocity), a = -10 m/s² (deceleration) and s = distance traveled by the car after the brakes are applied.
0² = 20² + 2(-10)s=> 0 = 400 - 20s=> s = 400/20= 20 m
The distance between the car and deer is 41 m. Therefore, the distance between the car and deer when the car comes to a stop is:
Distance between car and deer = 41 m - 20 m = 21 m.
Part B
We can use the same formula to find the maximum speed at which the car should travel to avoid hitting the deer.
The maximum distance that the car travels after the brakes are applied should be equal to the distance between the car and deer.
v² = u² + 2aswhere v = 0 (final velocity), u = maximum speed, a = -10 m/s² (deceleration) and s = 41 m (distance between car and deer).
0² = u² + 2(-10)(41)=> 0 = u² - 820=> u² = 820=> u = √820 = 28.64 m/s
Therefore, the maximum speed at which the car should travel to avoid hitting the deer is 28.64 m/s.
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1. Which of the following statements is false? A) During a reaction, electrons move from an electrophile to a nucleophile B) Homolytic bond cleavage yields neutral radicals in which each atom gains on
The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.
In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.
No atoms gain or lose electrons in this process.
In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.
This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.
A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.
These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.
It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.
Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.
Therefore, statement B, which suggests that each atom gains one electron, is false.
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Which diagram represents the postulate that states exactly one line exists between any two points?
B
Intro
#/108 core leam edgenuit
A
B
B
0000
A
B
Done
Answer:
A.BB is 000 with A.B is 0.00
The radius of a sphere decreases at a rate of 6 m/sec. Find the rate at which the surface area decreases when the radius is 20 m
.
Recall that the surface area of a sphere of radius r is given by S=4πr2
.
(a) 1200 m2/sec
(b) 960π m2/sec
(c) 1200πm2/sec
(d) 34π m2/sec
The radius of a sphere decreases at a rate of 6 m/sec. The rate at which the surface area decreases when the radius is 20 m is 960π m2/sec. The correct option is (b).
The surface area of a sphere is given by the formula: S = 4πr².
The rate of decrease of the radius is given to be 6 m/sec. This implies that dr/dt = -6, where the negative sign indicates that the radius is decreasing.
Now, we need to find the rate at which the surface area is decreasing when the radius is 20 m, i.e., we need to find dS/dt when r = 20 m.
We know that S = 4πr². Taking derivative of S with respect to t, we get:
dS/dt = 8πr (dr/dt)
Putting r = 20 m and dr/dt = -6, we get:
dS/dt = 8π × 20 × (-6) = -960π m²/sec
Since the radius is decreasing, the surface area is also decreasing. Thus, the rate of decrease of surface area is 960π m²/sec. However, since we are looking for the magnitude of the rate of decrease of surface area, we take its absolute value to obtain:
|dS/dt| = 960π m²/sec
Thus, the correct option is (b) 960π m2/sec.
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what happens to the mechanical energy of an apple as it falls from a tree?
Answer:
When the apple falls from the tree, it has some gravitational potential energy due to its height. Now, When it starts falling, the Gravitation Potential energy will starts converting into the Kinetic Energy. When the apple is about to strikes the ground, the Gravitational Potential energy have been converted into the Kinetic Energy.
Explanation:
The potential energy will be low when its kinetic energy is high and vice versa. But the mechanical energy remains conserved.
What is mechanical energy?Mechanical energy can be explained as the sum of kinetic energy and potential energy that can be used to do work. Mechanical energy can be described as the energy of a body due to its motion or position.
The total mechanical energy of a physical system is conserved as the energy can not be created or destroyed. The mechanical energy of a physical system can only be transformed from one form to another when the forces acting work are conservative in nature.
Each force is related to potential energy form and the energy changes between different kinds of potential energy and kinetic energy but the total energy remains constant.
The mechanical energy of the apple remains conserved. As the apple falls its potential energy is converted into kinetic energy.
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why doesn't the repulsive electric force of protons in the atomic nucleus cause the protons to fly apart?
The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons.
The repulsive electric force of protons in the atomic nucleus does not cause the protons to fly apart because of the strong nuclear force. The strong nuclear force is an attractive force between nucleons that overcomes the repulsion between protons due to the electromagnetic force. This force is responsible for holding the nucleus of an atom together.
We will explain the physics behind why the strong nuclear force overcomes the repulsive electric force. The protons in the nucleus are positively charged and would normally repel each other due to the electrostatic force. The reason why they do not is because they are held together by a stronger force, the strong nuclear force. This force acts between nucleons, which are particles found in the nucleus of an atom. The strong nuclear force is a short-range force that acts over distances of less than a femtometer. It is much stronger than the electrostatic force, which is why it is able to hold the nucleus together. The reason for this is that the strong nuclear force is mediated by particles called mesons, which are much heavier than electrons and photons. The strong force is able to overcome the repulsion between protons because it is much stronger than the electromagnetic force, which is what causes the repulsion in the first place.
The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons. This force is responsible for holding the nucleus of an atom together and is what allows for the existence of matter as we know it.
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What type of gaussian surface is best to determine the electric field from a large (ignore edge effects) sheet of charge?A. A box either above or below the sheet. B. A box that straddles the sheet of charge C. A sphere either above or below the sheet. D. A sphere that straddles the sheet of charge E. A cylinder either above or below the sheet.
The easiest way to extract the electric field from a big sheet of charge is to use a cylindrical gaussian surface. The correct option is E.
The easiest way to extract the electric field from a big sheet of charge is to use a cylindrical Gaussian surface. Calculating the flux through the surface is simple since the cylinder-shaped surface encloses the sheet of charge and the electric field lines are parallel to the axis of the cylinder.
The symmetry of the cylindrical surface also makes it simple to calculate the electric field. If the cylindrical Gaussian surface is selected to be sufficiently big in comparison to the size of the sheet, the edge effects can be disregarded. Charges and their arrangements, such as in capacitors and battery cells, produce electric fields.
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Explain, using a diagram, why electrons travel easily between atoms, while protons do not.
Answer:
Electrons are located in shells surrounding the nucleus of the atom,whereas protons are present inside the nucleus.
Explanation:
Electrons can move out of the shells on providing energy, but movement of proton will require a very high amount of energy (so as to break the nuclear force).
During an autumn storm, a 0.012-kg hailstone traveling at 20.0 m/s made a 0.20-cm-deep dent in the hood of Darnell’s new car. If the Force of the hail was 1200 N downwards, what was the time of impact of the damaging hail stone?
The time of impact of the hailstone on the hood of Darnell’s new car is -0.0002 s. The force that acts on the hailstone is F = ma, where F is the force, m is the mass of hailstone, and a is the acceleration of hailstone.
During an autumn storm, a 0.012-kg hailstone traveling at 20.0 m/s made a 0.20-cm-deep dent in the hood of Darnell’s new car.
We are given: F = 1200 N downwards, and m = 0.012 kg
Since the hailstone is stopped when it hits the hood of the car, we know that its final velocity is zero. To find the time of impact, we can use the formula: v = u + at
Here, u = 20.0 m/sv = 0, and
a = F/m = (1200 N downwards) / (0.012 kg)
= 100000 m/s² downwards
Substituting the values in the above equation, we get :0 = 20.0 m/s + (100000 m/s²)t
=> t = -0.0002 s
The time of impact of the hailstone on the hood of Darnell’s new car is -0.0002 s.
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A weight lifter raises a mass of 50kg through a height of 2m. He does this 25 times in one minute. Find his
average power.
Answer:
\(average power = 416.67 \: W
\)
Explanation:
\(are \: you \: sure \: this \: is \: a \: man \: or \: robot?......haha. \\ the \: average \: power \: is \: given \: by : \\ p_{(a.v)} = \frac{w}{t} \: but \: work \: or \: energy \: expanded \: is \: given \: by : \\ w = \: fs = mgs \: \: therfore, \: p_{(a.v)} = \frac{mgs}{t} \\ note \: the \: followng : \\ p_{(a.v)} = average \: power, \\ w = work \: done \: or \: energy \: expanded, \\ f = force \: due \: to \: gravity \: = weight = mg, \\ s = distance = height = 2m \times 25 \: lifts, \: m = mass = 50kg, \\ \: g \: = \: acceleration \: due \: to \: gavity = 10 {m(s)}^{ - 2} and \: t = time = 60s.
\\ so \: what \: now, ok \: lets \: find \: p_{(a.v)} . \\ p_{(a.v)} = \frac{mgs}{t}= \frac{50 \times 10 \times 50}{60} = 416.66666667 \: watts.\)
An object is subject to a 84 Nm torque about a point when a
21 N of force is applied to a second point along the object's
length. How far apart are the two points
Answer:
d = 4[m]
Explanation:
Torque in physics is defined as the product of force by distance. This way you can use the following equation to calculate the torque.
\(T=F*d\)
where:
T = torque [N*m]
F = force [N]
d = distance [m]
Now replacing in the equation above.
\(84=21*d\\\\d= 4[m]\)
What type of energy is thermal energy? A. Sound energy B. Chemical energy C. Kinetic energy D. Nuclear energy
Answer:
kinetic energy
Explanation:
You and your friend are playing motorized catapult catch, where you move towards each other while throwing a ball back and forth. If you are moving at 1.5 m/s, your friend is moving at 4.5 m/s and you can throw the ball at 25 m/s, how far will the ball have traveled if you start 200.0 m apart
In the game motorized catapult catch, two players throw a ball to one another while moving towards each other. The game is played such that if the ball is missed, it will travel some distance before it comes to a stop. The aim of the game is to see which player can throw the ball to the other before it comes to a stop. The problem above is stated as follows:
If you and your friend are playing motorized catapult catch, where you move towards each other while throwing a ball back and forth. If you are moving at 1.5 m/s, your friend is moving at 4.5 m/s and you can throw the ball at 25 m/s, how far will the ball have traveled if you start 200.0 m apart Solution Given the scenario, we can say that we have two players who are moving towards each other with speeds of 1.5 m/s and 4.5 m/s respectively.
Let's assume that the two players meet at a point, x. At this point, we can say that the ball is thrown at a speed of 25 m/s towards the other player. At this point, we can calculate the time it takes for the ball to reach the other player. Using the formula time = distance/speed, we can find the time it takes for the ball to reach the other player. The distance covered by the ball is given by: distance covered by ball
= 200 - x + 200 - x = 400 - 2xLet's call the time it takes for the ball to travel from one player to the other t. Thus:25t = 400 - 2xt = (400 - 2x)/25Now that we have found the time it takes for the ball to travel, we can now use the formula distance = speed × time to find the distance covered by the ball. Therefore, we can write: distance = 25t= 25(400 - 2x)/25= 400 - 2xHence, the distance covered by the ball is given by 400 - 2x. Answer: 400 - 2x.
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Two disks, A and B, are initially at rest at the left end of a track, as shown above. Disk B is more massive than disk A. The track has a horizontal section and then curves upward at the right end. The disks are each pushed to the right over a distance x0
by identical constant horizontal forces of magnitude F
. There is negligible friction between the track and the disks.
The figure presents two graphs, both in the first quadrant. For both graphs, the horizontal axis is labeled Position, the vertical axis is labeled Velocity, and the origin is labeled O. The graph on the left is labeled Graph 1. The graph is a curve that begins at the origin and extends upward and to the right, with a slope that is steeper near the origin and less steep at the upper right end of the curve. The second graph is labeled Graph 2. The graph is a straight line that begins at the origin and extends upward and to the right.
(a) Which of the graphs shown above correctly models the velocity of disk A as a function of position as it is being pushed by the force? Justify your answer.
(b) After sliding across the horizontal portion of the track, both disks slide partway up the curved section of the track. Identify which disk, if either, reaches a greater maximum height. If both disks reach the same maximum height, state this explicitly.
(c) In a clear, coherent paragraph-length response, justify your answer to part (b).
(d) Consider the case where friction is not negligible and the coefficient of kinetic friction between each disk and the track is the same. The disks are again pushed by the same force over the same distance, and each disk slides partway up the ramp. Identify which disk, if either, would reach a greater maximum height than the other in this case. If both disks reach the same maximum height in this case, state this explicitly. Briefly justify your answer.
The velocity vs displacement curve will be a parabolic graph and the height attained by object B will be lesser than object A.
What is Velocity?Velocity is the change in displacement of an object with the change in time. It is a vector quantity because it has both magnitude and direction. The SI unit of velocity is meter per second (m/s).
u = 0
x₀ = Distance travessed by both the discs
F= constant
f = 0
a) (F-f) = ma
a = F/ m
v² = u² + 20x
v² = 0 + (2F/m)x
v = \(\sqrt{(2f/m)x}\)
v v/s x curve will be similar to parabolic graph of v² = (2f/ m)x
b) Energy would be conserved for both.
Since, velocity gained by both is same as Vi = \(\sqrt{(F/m)Xo}\)
-mgh = 1/2mvf² - 1 mvi² = - 1 mvi²
mgh = 1/2mvi² = FXo/2m (Since, vf = 0)
So, h = (FXo/ 2mg)
Since, mb > ma
Hb < Ha
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A proton moves at 2.50 x 10^6 m/s horizontally at a right angle to a magnetic field. What is the strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally
The strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally is 0.0414 T.
Understanding Magnetic FieldTo balance the weight of the proton and keep it moving horizontally, we need to apply a magnetic field with a strength equal to the gravitational force acting on the proton.
The force experienced by a charged particle moving in a magnetic field is given by the formula:
F = q * v * B
where:
F is the magnetic force,
q is the charge of the particle,
v is the velocity of the particle, and
B is the magnetic field strength.
The weight of the proton is given by the formula:
Weight = mass * acceleration due to gravity
Since the proton is moving horizontally, the gravitational force is balanced by the magnetic force. Therefore:
F = Weight
q * v * B = mass * acceleration due to gravity
Given the following constants:
charge of a proton (q) = 1.6 x 10⁻¹⁹ C,
mass of a proton (mass) = 1.67 x 10⁻²⁷ kg
acceleration due to gravity (g) = 9.8 m/s².
Substituting the known values into the equation, we can solve for the magnetic field strength (B):
B = (mass * gravitational acceleration) / (q * v)
B = (1.67 x 10⁻²⁷ kg * 9.8 m/s²) / (1.6 x 10⁻¹⁹ C * 2.50 x 10⁶ m/s)
B = 0.0414 T
Therefore, the strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally is approximately 0.0414 Tesla (T).
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Write down any four points that should be considered during household wiring
Answer:
USE RUBBER CLOVES
USE A PLIER
USE CONDUCTIVE WIRES
SWITHC OFF THE MAIN SWITCH WHILE WIRRING
Explanation:
Which of the following most correctly describes end-diastolic volume?
A. the volume of the ventricle when it is least full
B. the volume of the ventricle at the end of atrial diastole
C. the increase in ventricular volume during atrial systole
D. the volume of the ventricle when it is most full
The correct option is D. the volume of the ventricle when it is most full.
The volume of the ventricle when it is most full is the most correct description of end-diastolic volume.
It can be defined as the amount of blood in the ventricle immediately before a cardiac contraction or systole occurs. End-diastolic volume is the volume of blood in the ventricles at the end of diastole, after filling with blood from the atria, before the ventricles contract to begin systole.
ventricles are hollow chambers or cavities found in the heart and brain. In the heart, there are two ventricles responsible for pumping blood, while in the brain, there are four interconnected ventricles that produce and circulate cerebrospinal fluid.
Therefore, the correct option is D. the volume of the ventricle when it is most full.
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How much work w, in joules, would you have to do to bring the third charge, q3, from very far away to the point p?
The work required to bring the third charge from very far away to the point P is approximately 36 millijoules (to two significant figures). The units are joules (J).
To calculate the work required to bring the third charge q3 from very far away to the point P, we need to know the electric potential at point P due to the other two charges q1 and q2. The electric potential at point P is given by:
V = kq1/r1 + kq2/r2
U = q3 V
where q3 is the charge of the third charge.
r1 = 0.1 m
r2 = 0.2 m
q1 = -2 μC = -2 × 10^-6 C
q2 = 3 μC = 3 × 10^-6 C
Substituting these values into the electric potential formula, we get:
V = kq1/r1 + kq2/r2
V = (9 × 10^9 N m^2/C^2) × [(-2 × 10^-6 C)/0.1 m + (3 × 10^-6 C)/0.2 m]
V ≈ 9000 V
final = q3 V
final = (4 μC) × (9000 V)
final = 36000 μJ
final = 36 mJ
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A bird flies 15 mph up at an angle of 45 degrees to the horizontal. What is the bird's velocity in component form
The bird's velocity can be represented in component form by breaking it down into its horizontal and vertical components. Given that the bird flies at 15 mph up at an angle of 45 degrees to the horizontal, we can determine its velocity components.
To find the bird's velocity components, we need to consider its magnitude and direction. The bird's velocity is given as 15 mph up at an angle of 45 degrees to the horizontal.
The horizontal component of the bird's velocity can be calculated by multiplying the magnitude of the velocity (15 mph) by the cosine of the angle (45 degrees). The cosine of 45 degrees is (√2)/2. Thus, the horizontal component of the velocity is (15 mph) * (√2)/2 = (15√2)/2 mph = (7.5√2) mph.
The vertical component of the bird's velocity is determined by multiplying the magnitude of the velocity (15 mph) by the sine of the angle (45 degrees). The sine of 45 degrees is also (√2)/2. Therefore, the vertical component of the velocity is (15 mph) * (√2)/2 = (15√2)/2 mph = (7.5√2) mph.
Hence, the bird's velocity in component form is (7.5√2) mph horizontally and (7.5√2) mph vertically. This means that the bird is moving with a velocity of (7.5√2) mph in the x-direction and (7.5√2) mph in the y-direction.
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calculate the potential energy of a 60 kg object that is 20 meters off the ground
Answer:
11772 joules
Explanation:
M = 60 kg
H = 20 m
G = 9.81 ms^-2
P.E = ?
P.E = MGH
P.E = 60 x 9.81 x 20
P.E = 11772 joules
What current flows through a 2.56-cm-diameter rod of pure silicon that is 18.0 cm long, when 1.00 ✕ 103 V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.)
_________________A fill in the blank
The current flowing through the 2.56-cm-diameter rod of pure silicon, which is 18.0 cm long, when 1.00 ✕ 103 V is applied to it, is approximately 2.17 A.
To determine the current flowing through the rod, we can use Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R). In this case, the rod is made of pure silicon, so we need to calculate its resistance.
The resistance of a cylindrical conductor can be calculated using the formula R = (ρ * L) / A, where ρ is the resistivity of the material, L is the length of the rod, and A is the cross-sectional area. The resistivity of pure silicon is approximately 640 Ω·cm.
First, let's calculate the cross-sectional area (A) of the rod. The diameter of the rod is 2.56 cm, so the radius (r) is half of that, which is 1.28 cm or 0.0128 m. Using the formula for the area of a circle (A = π * r²), we find that the cross-sectional area is approximately 0.00516 m^2.
Next, we can substitute the values into the formula for resistance: R = (640 Ω·cm * 0.18 m) / 0.00516 m². After performing the calculations, we find that the resistance of the rod is approximately 22,222 Ω.
Finally, we can use Ohm's Law to calculate the current: I = V / R. Substituting the given voltage of 1.00 ✕ 103 V and the resistance of 22,222 Ω, we find that the current flowing through the rod is approximately 2.17 A.
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Conduction occurs when thermal energy is transferred by the movement of
a. Waves
b. molecules
c. liquids
d. fluids
Answer: Molecules
Explanation:
Answer:
B. molecules
Explanation:
got 100% on the edge quiz
In order to find the resultant of two vectors we must use the pythagoran therom, a +b2-2. Where the crepresents the resultant vector
Answer:
Furthermore, the Pythagorean theorem works when the two added vectors are at right angles to one another - such as for adding a north vector and an east vector.
HELLO! Please Help me.
I can't do it! it's Science
Answer:
9V
Explanation:
V=IR
V=2.5*3.6
V=9
Answer:
9V
Explanation:
V =IR
V =2.5 * 3.6
V = 9V
Students conducted a lab investigation in which they applied 10,000 J of heat to 50 g samples of three different materials and measured the temperature change in each material. Which material has the highest specific heat?
Time (min)
Temperature (°C)
Material A
Material B
Material C
0
25°C
25°C
25°C
5
27°C
37°C
31°C
10
29°C
49°C
37°C
15
31°C
61°C
43°C
20
33°C
73°C
49°C
Claim
Evidence
Reasoning
if you find yourself being hit by infrared rays, you are experiencing
If you find yourself being hit by infrared rays, you are experiencing exposure to infrared radiation.
Infrared radiation refers to the electromagnetic waves with longer wavelengths than those of visible light. These rays are not visible to the human eye but can be detected by specialized devices or sensors. When you feel the sensation of being hit or exposed to infrared rays, it means that your body is absorbing this form of radiation.
Infrared radiation is commonly emitted by warm objects, such as the sun, fire, or heated surfaces. It is important to note that excessive or prolonged exposure to intense infrared radiation can have detrimental effects on human health, including thermal burns and tissue damage. Therefore, it is advisable to take appropriate precautions and limit exposure to high-intensity infrared sources.
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The speed of a wave is 65 m/sec. If the wavelength of the wave is 2 meters, what is the frequency of the wave
(f=65/2)
32.5 Hz
130 Hz
215 Hz
14.2 Hz
Identify similarities in the origins of the following solar system objects: planetary rings, satellites, asteroids, comets, the Oort Cloud, and the Kuiper Belt. How do these objects’ origins relate to the origin and formation of planets?
The solar system is formed 4.5 billion years ago and the solar system is made up of interstellar gas and dust. The solar system comprises planetary rings, satellites, comets, etc.,
The ring or disc forms around the planets are called the planetary ring. The planetary rings are made up of dust particles that orbit an astronomical object. An object that gets stable with the planet's gravity and makes the object move in orbit is called a satellite.
An asteroid revolves around the sun like a planet but the size of asteroids is lesser than the planets. Asteroids are made up of metals and rocky materials. The comets are made up of ice, dust, and rocky material. Both asteroids and comets are formed in the early stage of the solar system.
The Kuiper Belt is a ring-shaped or disc-shaped area and it is visible in Saturn's orbit and the sun. It is the region of leftovers of the solar system. The Oort cloud is a ring made up of dust particles. All planetary objects are made up of dust particles at the stage of formation of the solar system.
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