im giving out the game the last of us part 2 who wants it

Answer:

 4Al  + 3O₂  →  2Al₂O₃

Explanation:

The problem here is in balancing the equation below:

     Al  + O₂  →  Al₂O₃

In balancing a chemical equation, the number of atoms on both sides of the expression must be the same;

   put the alphabets a, b and c before each specie;

                  aAl  + bO₂  →  cAl₂O₃

Conserving Al;

                    a  = 2c

Conserving  O:

                     2b  = 3c

  Now, let c  = 1, a  = 2

                b  = \(\frac{3}{2}\)  

Multiply through by 2;

           c  = 2, a  = 4 and b  = 3

          4Al  + 3O₂  →  2Al₂O₃

The La Brea asphalt deposits have been trapping and preserving

organisms  for at least 38,000 years.

The La Brea Tar Pits, located in Los Angeles, California, are a group of tar pits that have been seeping asphalt for thousands of years. The asphalt has trapped and preserved the bones of animals that became stuck in it, as well as the remains of plants and other organic material.

The tar pits have been an important site for the study of Pleistocene era life, and the fossils that have been found there have provided a wealth of information about the animals that lived in the area during that time period. Some of the most commonly found species at the La Brea Tar Pits include saber-toothed cats, dire wolves, mammoths, and mastodons.

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Bethanechol mimics the neurotransmitter acetylcholine.

Bethanechol is a medication used to stimulate motility and increase secretions in patients with decreased vagal nerve function, such as after surgery. It is a synthetic cholinergic agonist that acts by mimicking the effects of acetylcholine, the neurotransmitter released by the vagal nerve.

Acetylcholine is an important neurotransmitter in the parasympathetic nervous system, which is responsible for regulating various bodily functions, including digestion and smooth muscle contraction. It acts on specific receptors called cholinergic receptors, activating them and triggering the desired physiological responses.

By mimicking acetylcholine, bethanechol can bind to and activate cholinergic receptors, particularly muscarinic receptors located in various tissues and organs. This activation leads to increased smooth muscle contractions, including those involved in gastrointestinal motility, and enhanced secretion of fluids and mucus in the digestive and respiratory systems.

Overall, bethanechol's ability to mimic acetylcholine allows it to compensate for decreased vagal nerve function and stimulate the parasympathetic responses needed for improved motility and secretion in post-surgical patients or individuals with impaired vagal nerve activity.

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To solve this problem, we'll use the Beer-Lambert Law and the information given.

(a) According to the Beer-Lambert Law, the absorbance (A) is directly proportional to the concentration (c) of the absorbing species:

A = εlc

where A is the absorbance, ε is the molar absorptivity constant, l is the path length (in cm), and c is the concentration (in M).

Given:

Slope of the Beer's Law plot (εl) = 3.5 × \(10^3\)

Absorbance (A) = 0.700

Since we have a 1 cm path length, the slope (εl) is equal to the molar absorptivity constant (ε).

Substituting the values into the equation, we can calculate the equilibrium concentrations:

ε = \(3.5*10^3 M^{(-1)} cm^{(-1)}\)

A = 0.700

Using the Beer-Lambert Law equation, we can rearrange it to solve for the concentration (c):

c = A / (εl)

For Fe3+:

c(Fe3+) = A / (εl) = 0.700 / (3.5 × \(10^3\)) = 2 ×\(10^{(-4)}\) M

For SCN-:

c(SCN-) = A / (εl) = 0.700 / (3.5 × \(10^3\)) = 2 × 1\(0^{(-4)}\) M

For FeSCN2+:

Since FeSCN2+ is the product of the reaction between Fe3+ and SCN-, the concentration of FeSCN2+ at equilibrium will be zero until the reaction reaches equilibrium.

Therefore, the equilibrium concentrations are:

[Fe3+] = 2 × \(10^{(-4)}\) M

[SCN-] = 2 × \(10^{(-4)}\) M

[FeSCN2+] = 0 M

(b) To calculate the equilibrium constant (Keq), we'll use the equation:

Keq = ([FeSCN2+]) / ([Fe3+][SCN-])

Substituting the given values:

Keq = (0) / (\((2 * 10^{(-4)})^2\)) = 0

Therefore, Keq is equal to 0.

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Answer:

this should help

Explanation:

Answer: (A)Distance of gaseous planets from the sun is more than that of solid planets.

Explanation: The gas and ice giant planets take longer to orbit the Sun because of their great distances. The farther away they are, the more time it takes to make one trip around the Sun. The densities of the gas giants are much less than the densities of the rocky, terrestrial worlds of the solar system. Gas giants are not all gas.

Answer:

(A) Distance of gaseous planets from the sun is more than that of solid planets.

Explanation:

The correct answer is (A) the distance of gaseous planets from the sun is more than that of solid planets.

The time taken by a planet to revolve around the sun is determined by its distance from the sun and the gravitational force acting between them. According to Kepler's laws of planetary motion, planets that are farther from the sun take longer to complete their orbits than those that are closer.

Gaseous planets such as Jupiter, Saturn, Uranus, and Neptune are much farther from the sun than the solid planets, including Mercury, Venus, Earth, and Mars. Thus, gaseous planets take longer to revolve around the sun than the solid planets.

The mass of a planet, the number of moons it has, and its temperature do not directly influence the time taken to complete an orbit around the sun. Therefore, options (B), (C), and (D) are incorrect.

Answer:

a bacterium with a rigid spiral structure,found in stagnant water and something causing disease

Answer:C

Explanation:

Glutamic acid has three pKa values because it has three ionizable groups: the carboxylic acid group, the amino group, and the side chain carboxylic acid group.

These groups can donate or accept protons at different pH levels, leading to the three pKa values. The ionizable groups in amino acids can donate or accept protons depending on the pH of the solution. At low pH, all of the groups are protonated, while at high pH, all are deprotonated. However, at intermediate pH values, the groups can donate or accept protons in different combinations, resulting in different levels of ionization. Glutamic acid has three ionizable groups: the carboxylic acid group (-COOH), the amino group (-NH3+), and the side chain carboxylic acid group (-CH2-COOH). Each of these groups can donate or accept a proton, resulting in three pKa values for glutamic acid. The pKa values for the carboxylic acid and amino groups are similar to those of other amino acids, while the pKa of the side chain carboxylic acid group is lower, making it more acidic.

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Answer:

The volume of the tank can be calculated using the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature.

In this case, we have P = 179 atm, n = 7.75 moles, R = 0.08206 Latm/(Kmol), and T = 295 K. Plugging these values into the ideal gas law equation and solving for V gives us:

V = (nRT)/P V = (7.75 moles * 0.08206 Latm/(Kmol) * 295 K) / (179 atm) V ≈ 1.01 L

So the volume of this tank at these conditions is approximately 1.01 liters.

Explanation:

Answer:

Volume = 1.05 L (3 s.f.)

Explanation:

To find the volume of the tank, we can use the ideal gas law.

\(\boxed{\sf PV=nRT}\)

where:

The given values are:

Substitute the given values into the formula and solve for V:

\(\implies \sf 179 \cdot V=7.75 \cdot 0.082057366080960\cdot 295\)

\(\implies \sf V=\dfrac{7.75 \cdot 0.082057366080960\cdot 295}{179}\)

\(\implies \sf V=\dfrac{187.6036532 \dots }{179}\)

\(\implies \sf V=1.04806510 \dots\;L\)

\(\implies \sf V=1.05\;L\;(3\;s.f.)\)

Therefore, the volume of the tank in these conditions is 1.05 liters (3 s.f.).

The equilibrium constant of a reaction requires certain environmental variables to remain constant. These variables are pressure, temperature, and concentration. The correct option is A.

An equilibrium constant is a mathematical tool that enables the quantification of the extent of a chemical reaction. The equilibrium constant is symbolized by Keq, and it is utilized to determine the concentration of reactants and products present at equilibrium.

                           This calculation is done using the law of mass action.Keq is defined as the ratio of product concentrations to reactant concentrations in a chemical reaction taking place at equilibrium. The concentrations used in the expression for Keq are equilibrium concentrations.

                                 As a result, Keq is a constant for a given reaction at a specific temperature. Keq is dependent on a variety of environmental variables such as temperature, pressure, and concentration. To keep the equilibrium constant stable, these variables must remain constant.

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The three states of matter are solid - example is stone, liquid - example is water and gas - example is air.

A matter is referred to as a substance which has a certain mass and takes up a certain volume in space.

For example pen, pencil, toothbrush, water, milk are matters as well as car, bus, bicycle is also a matter. So matter is considered as a living thing and a non-living thing.

There are three states of matter and they include;

They have different properties, which can be explained by looking at the arrangement of their particles. This is the theoretical temperature at which particles have the least amount of energy and the slowest movement.

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The reagent that could be added that would allow you to differentiate between the members of each pair of solid compounds below is the Sodium Thiosulfate (Na2S2O3) reagent.

Let's take a look at the process: Na2S2O3 can be used to distinguish between HgCl2 and Hg2Cl2. They react differently with Na2S2O3 due to the fact that they have different stabilities as mercuric and mercurous compounds. In the presence of HgCl2, Na2S2O3 quickly precipitates yellow-colored Hg2Cl2, which can be readily detected.

The balanced equation for this reaction is as follows:

HgCl2 (s) + Na2S2O3 (aq) → Hg2Cl2 (s) + NaCl (aq) + Na2S2O4 (aq)

Therefore, when Na2S2O3 reagent is added to HgCl2 and Hg2Cl2, Hg2Cl2 precipitates as a yellow-colored precipitate while HgCl2 does not form any precipitate.

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Answer: a computer

Explanation:

The matter in this series of images is going through a chemical change, because they are changing their form and making new substance.

Chemical change is defined as a change of materials into another, new materials with different properties and one or more than one materials are formed during the chemical reaction.

There are basically five types of chemical reaction.

Thus, the  matter in this series of images is going through a chemical change, because they are changing their form and making new substance.

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The correct answer is (a). There is a Lewis structure for Ca2+ but it has no electrons.

This is because calcium loses two electrons to form a cation with a 2+ charge. The Lewis structure for Ca2+ would show an empty valence shell with no electrons around the calcium ion.

Calcium (Ca) is a metallic element located in Group 2 of the periodic table, meaning it has two valence electrons. When calcium loses both valence electrons, it becomes a cation with a 2+ charge, represented as Ca2+.

In a Lewis structure, each valence electron is represented by a dot. Since Ca2+ has lost both valence electrons, it has no dots or electrons left to represent in the Lewis structure. Therefore, option a is correct: There is a Lewis structure for Ca2+, but it has no electrons.

Option b is incorrect because having 4 electron pairs would suggest that Ca2+ has 8 valence electrons, which is not the case.

Option c is incorrect because having 1 electron pair would suggest that Ca2+ has 2 valence electrons, but as mentioned earlier, it has lost both of its valence electrons to become a 2+ cation.

Option d is also incorrect because having 2 electron pairs would again suggest that Ca2+ has 4 valence electrons, which is not true.

Option e is incorrect because having 1 electron pair would suggest that Ca2+ has only 2 valence electrons, but we know that it has lost both of its valence electrons to form a 2+ cation.

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The calcium ion has 18 protons, 20 neutrons, and 20 electrons.
The relationship between the components a and b is Inverse proportion.


The calcium ion (Ca2+) has a 2+ charge, indicating that it has lost 2 electrons from its neutral state. To determine the number of protons, neutrons, and electrons in the calcium ion, we need to consider its atomic number and mass.

The atomic number of calcium is 20, which indicates that it has 20 protons. Since the calcium ion has a 2+ charge, it means it has lost 2 electrons. Therefore, the number of electrons in the calcium ion is 20 - 2 = 18.

The mass number of calcium is 40 amu, which represents the total number of protons and neutrons. Since the calcium ion has 20 protons, the number of neutrons can be calculated as 40 - 20 = 20.

So, the correct option is: d. 18 protons, 20 neutrons, and 20 electrons

In the expression a∼1/b, the relationship between the components a and b is an inverse proportion. This means that as the value of a increases, the value of b decreases, and vice versa. The symbol ∼ represents the proportional relationship between a and 1/b, indicating that they are inversely related. Therefore, the correct answer is: Inverse proportion

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In steps 11-14, each test tube is compared to the control test tube (#1). In these steps, the colors of each test tube are to be compared with the control test tube. One must determine whether the system has shifted towards reactants or products due to the changes.

Let us discuss how each change affects the equilibrium in terms of Le Chatelier's principle:11. A small amount of sodium bicarbonate (NaHCO3) was added to the system. The solution will turn cloudy, and a slight greenish-yellow color may appear in the test tube. Adding a base to an equilibrium system results in a shift towards the reactants. Since the solution is more acidic than basic, it will absorb the base and shift the equilibrium to the right. This change did not affect the equilibrium of the system.12.  A small amount of hydrochloric acid (HCl) was added to the system. A deep yellow color should appear in the test tube. Adding an acid to an equilibrium system results in a shift towards the products. Since the solution is more basic than acidic, it will absorb the acid and shift the equilibrium to the right. This change affects the equilibrium by increasing the amount of NO2 in the solution.13.  A small amount of copper (II) sulfate (CuSO4) was added to the system. The solution will turn greenish-blue. Adding a catalyst to an equilibrium system does not affect the equilibrium of the system. This change did not affect the equilibrium of the system.14.  A small amount of sodium nitrite (NaNO2) was added to the system. The solution will turn yellow-brown. Adding a product to an equilibrium system results in a shift towards the reactants. This change affects the equilibrium by decreasing the amount of NO2 in the solution. In conclusion, for the forward reaction, the system is exothermic.

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Given what we know, we can confirm that since Mr. Summers has to test a hypothesis, his next step should be to design an experiment.

Therefore, we can confirm that Mr. Summers must design an experiment given that this is the best way to gather data in order to be analyzed in the future and draw a valid conclusion.

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The question that will best help the student to classify the material is; "is the material malleable or ductile?"

Generally, materials can be classified as metals or non metals. There are properties that are particular to metals and there are properties that are particular to nonmetals and these properties can be used to identify each one of the materials.

The question that will best help the student to classify the material is; "is the material malleable or ductile?" These metallic properties.

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Missing parts;

A student is trying to classify an unidentified, solid gray material as a metal or a nonmetal. Which question will best help the student classify the material? A. Is the material malleable or ductile? B. Does the material feel hard to the touch? C. Will the material float in water? D. Does the material feel rough or smooth?

Answer:

There are several sources of errors when reading a thermometer. Some common sources include limitations in digital processing and physical issues with the device itself, errors with the sensor which is often the greatest source of error, and measurement error which can depend on the skill of the operator. An “Err” message can also appear on a thermometer’s display if the sensor is too warm before powering on, if the temperature reading is incomplete, or if there is an internal problem with the thermometer.

Answer:

Invertebrates are animals which do not have vertibral column. They do not debelop it also. For example: Arthropods , Crawfish and Sea Urchin.

Answer:

0.0305 moles of MgCO₃

Explanation:

In order to solve this problem, we first need to calculate the molecular weight of MgCO₃:

Finally we divide the mass by the molecular weight, to calculate the number of moles:

The actual protein concentration of the given milk sample is 1.176 mg/mL

The actual protein concentration of a milk sample can be determined using the Bradford protein assay test results.

This assay utilizes the Coomassie blue dye, which binds to proteins under acidic conditions, causing a shift in the absorption maximum from 465 nm to 595 nm.

The amount of dye bound to the protein is quantified by measuring the absorbance at 595 nm.

To calculate the protein concentration, a standard curve is generated using known protein concentrations.

Absorbance values of protein standards are plotted against their concentrations, and a linear regression line is drawn.

The equation of the line, Absorbance = m x [protein] + b, is used to calculate the protein concentration of an unknown sample.

Creating a new standard curve, a series of bovine serum albumin (BSA) standards with concentrations ranging from 0.1 mg/mL to 0.5 mg/mL are prepared.

The absorbance of each standard is measured at 595 nm.

Plotting the absorbance values against their concentrations and drawing a linear regression line, the equation of the line is determined.

Using the absorbance value obtained from the Bradford assay for the milk sample (0.825 mg/mL), we can substitute it into the equation of the line to calculate the protein concentration.

Assuming the equation is Absorbance = 0.69 x [protein] + 0.02, the protein concentration of the milk sample is determined as follows:

\(0.825 = 0.69 \times [protein] + 0.02\)

\([protein] = \frac{{0.825 - 0.02}}{{0.69}}\)

\([protein] = 1.176 \, \text{mg/mL}\)

Hence, the actual protein concentration of the given milk sample is 1.176 mg/mL.

This calculation demonstrates how the Bradford assay and standard curve can be utilized to determine the protein concentration in a sample.

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Energy levels are the fixed places from the nucleus to the electrons of the atoms. Three possible wavelength photons are possible from the transitional levels.

Spectral lines are the dark or light uniform spectrum caused by the surplus or insufficient photons in the atom. They absorb and emit light in a certain frequency range.

Photons are transmitted from one energy level to another level of lower energy, three transitions from levels 1 - 2, 1 - 3, and 2 - 3 are possible.

Therefore, 3 spectral lines are possible.

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O-linked oligosaccharides are commonly attached to the —oh group of amino acids.

Glycosylation is a post-translational modification of proteins in which glyco-linked oligosaccharides are added to proteins. This process is found in eukaryotes, primarily in the endoplasmic reticulum and Golgi apparatus, and involves the enzymatic attachment of sugar units to specific sites on a protein molecule.

These short chains of saccharide sugar residues, called glycosyl sidechains, are examples of glycoconjugates which are covalently attached to hydroxyl groups on the protein.

The most common types of glycosylation sites are the N-linked glycosylation sites, which have an attached sugar group, often an N-acetylglucosamine or N-acetylmannosamine connected to an asparagine sidechain, and the O-linked glycosylation sites, which have a sugar group, usually a galactose or mannose sugar, attached to a hydroxyl group on serine, threonine or hydroxylysine residues.

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