I'm very confused on Solubility and Temperature. Please Help!

Imagine you have two beakers. Both beakers are filled with the same amount of water. The water in both beakers is the same temperature as well. You add 50 g of Substance A to the first beaker, and 50 g of Substance B to the second beaker. After stirring both beakers, there is a small pile of Substance B at the bottom of the second beaker. None of Substance A is visible in the first beaker. Which of the following statements is true?

Select one:
a. Substance B is not soluble in water
b. Substance A is not soluble in water
c. Substance A is less soluble in water than Substance B.
d. Substance A is more soluble in water than Substance B.

Answers

Answer 1
When a solid is added to a liquid, there exists a possibility that it will get dissolved in the solid. However, this depends on a lot of factors, like the temperature of the substances, the volume of the liquid, and the amount and nature of the solid to be dissolved.


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40 POINTS!! AND IF YOU DONT GET IT RIGHT IMMA REPORT YOU AND PLEASE HELP ME

Once upon a time, a mother duckling sat on her eggs with great impatience. How long would it be before they hatched? Finally, one summer day, the mother duckling watched as the eggs cracked, and her cute, yellow ducklings waddled into the world. She was filled with joy until she noticed that one egg, which was larger than all of the others, remained. After many hours, the egg cracked. A large, gray duckling emerged. The mother duck was horrified at the duckling's appearance. The mother duck's only comfort was that the ugly duckling could swim and dive under the water.

As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him.

One day, the ugly duckling decided to run far away and find a place where the animals would look past his appearance and be kind and friendly. He came to a pond and sighted three beautiful swans. Their white feathers, long necks, and kind eyes made them look like royalty. The ugly duckling sighed in disappointment. He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged.

Read the fairy tale The Princess and the Pea.

Once upon a time, there was a handsome prince. The prince lived with his mother and father in a luxurious castle that overlooked a valley of wildflowers and a distant forest. As the prince grew up, he began to long for a princess. However, the prince wanted to be sure that the princess was a real princess. The queen and king searched far and wide for a real princess, but the prince always found something wrong with the princesses they found.

One evening, there was a terrible storm. The wind howled, thunder shook the stone walls, and lightning filled the dark night sky. Through the pelting of the rain, there came a knock at the door. When the king opened the door, he saw a bedraggled girl, soaked to the skin and covered in mud. He ushered her into the castle so that she could warm herself by the fire.

"Why is a young servant girl like you wandering about on such a ferocious night?" queried the king.

The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering.

The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion.

Bright and early the next morning, the king and queen arrived at the girl's bedchamber. The queen asked the girl how she had slept the night before.

"Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue."

The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit.

How do the authors use similar and different events in each fairy tale to illustrate the theme that people should not be judged based on their appearances? Use complete sentences and evidence from the text to support your answer.

Answers

Answer:

MAIN IDEA
What the authors meant is not to judge people by their looks.


_____________________________________________________________

THE UGLY DUCKLING

The ugly duckling doesn't fit with the other ducklings and grows up, to be a fabulous bird. In the beginning, he is teased because of his looks, in a quote, "As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him."

Near the end, however, it states, "He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged." Throughout the course of the story, the other birds' views change since now they realize how awful they felt for mistreating the ugly duckling.

_____________________________________________________________

THE PRINCESS AND THE PEA

The king and queen didn't believe that she was a princess, so they had her endure the trial of sleeping on twenty mattresses with a pea under the very bottom one. Near the beginning of the story, it states, "The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering. The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion." This is when the king and queen were in doubt that she was a princess.

However later on it stated, "Bright and early the next morning, the king and queen arrived at the girl's bed-chamber. The queen asked the girl how she had slept the night before. "Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue." The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit." As you can see the king and queen believed that she was a princess now because they stated, "Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses."

_____________________________________________________________

CONCLUSION
Both stories focus on how the main character is doubted or mistreated because of how they look, but throughout the stories, the main character proves them wrong.








Explanation:

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40 POINTS!! AND IF YOU DONT GET IT RIGHT IMMA REPORT YOU AND PLEASE HELP MEOnce upon a time, a mother

What is the mass of 3.25 miles of AsF5

Answers

Answer:

169.913616 g/mol

Explanation: This is weight of AsF5 molecular weight

In the reaction 4 Sb + 3 O2 --> Sb406, how many moles of antimony are
required to fully react with 8.00 moles of oxygen?
O 5.34 moles
O 10.7 moles
O 6.00 moles
O 12.0 moles
PLEASE HELP!!

Answers

Answer:

1.667 moles of antimony will be produced

Suppose two equal mass cars traveling with equal speeds in opposite directions collide head on and stick together. What fraction of the energy is dissipated?.

Answers

Suppose two equal mass cars traveling with equal speeds in opposite directions collide head on and stick together then fraction of the energy is dissipated is all kinetic is dissipated

A collision which is inelastic is one in which the internal energy changes and the collision is an example of a perfectly inelastic collision and the final velocity after the collision is zero

Here given data is

The mass of one car = the mass of the second car in the collision = m

The type of collision = inelastic collision

The speed of each of the cars in the collision = v and -v

And in an inelastic collision

m × v₁i + m₂ ×v₂i  = (m₁ + m₂)×vf

Therefore we get

m × v₁i - m × vi = 0 = 2 × m × vf

Which give

vf = 0

The collision is an example of a perfectly inelastic collision and the final velocity after the collision is zero

The change in the energy is

ΔK.E = K.E final - K.E initial

K.E initial = 0.5mv² + 0.5mv² = mv²

ΔK.E = 0.5×(2×m)×0-0.5mv²+0.5mv² = -mv²

ΔK.E = -mv²

And the negative sign stand for energy given out and which give

The energy dissipated = mv² that is initial kinetic energy

Therefore all kinetic energy is dissipated

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calculate the umber of moles in o.293kg of pb as well as number of atoms {pb =207, avogaoho's constant = 6.02x10 rise to power 23}

Answers

1. The number of mole in 0.293 Kg of Pb is 1.42 mole

2. The number of atom in 0.293 Kg of Pb is 8.55×10²³ atoms

1. How to determine the number of mole

The numbe of mole in the 0.293 Kg of Pb can be obtained as follow:

Mass of Pb = 0.293 Kg = 0.293 × 1000 = 293 gMolar mass of Pb = 207 g/mol Number of mole =?

Mole = mass / molar mass

Number of mole of = 293 / 207

Number of mole = 1.42 mole

Thus, the number of mole is 1.42 mole

2. How to determine the number of atoms

The number of atoms can be obtained as follow:

From Avogadro's hypothesis,

1 mole of Pb = 6.02×10²³ atoms

Therefore,

1.42 mole of Pb = (1.42 mole × 6.02×10²³ atoms) / 1 mole

1.42 mole of Pb = 8.55×10²³ atoms

Thus, the number of atoms is 8.55×10²³ atoms

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What is the mass (in grams) of 5.00 L of NH₃ at STP?

Answers

Answer:

3.79 grams

Explanation:

22.4= STP volume .          Molar mass of NH3=17.031

5.00 NH3 × (1 mol/22.4 L) =0.223

convert to grams->

0.223× 17.031= 3.79

According to ideal gas equation and standard temperature and pressure conditions the mass in grams of ammonia is 0.037 g.

What is ideal gas equation?

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.

The law can be derived from microscopic kinetic theory .All the other gas laws equations can be derived from ideal gas equation, In the given example at standard temperature and pressure conditions, P=1 atmosphere

V=5 L , molar mass of ammonia=17.031 g/mole,R=8.314 T=273 K

Substituting all these values in ideal gas equation,

mass=PV×molar mass/RT

mass=1×5×17.031/8.314×273=0.037 g

Thus the mass of ammonia gas in grams at STP is 0.037 g.

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11. Carbon tetrachloride is a solvent which is used as a refrigerant and also as a cleaning agent.
CH4 + 4Cl₂ ⇒ CCl4 + 4HCI
Use the balanced chemical equation above to calculate how many grams of carbon tetrachloride
(CCl4) can be produced from reacting 709.0 grams of chlorine (Cl₂).
Molar Mass Cl₂ = 70.906 g/mol
Molar Mass CCl4 = 153.823 g/mol
a. 3.845 g
b. 61.53 g
384.5 g
6153 g
c.3845 g
d.6153 g

Answers

Answer:

3846g of Carbon tetrachloride is in the chemical equation.

Explanation:

The Balanced equation is :

   CH4 + 4CL2 -> CCL4 + 4HCL

By observing the equation There are 4 moles of chlorine react to produce 1 mole of carbon tetrachloride.so, should use the mole ratio to tell the moles of carbon tetrachloride produced, and convert the moles of CCL to grams.Molar Mass of CL2 is 70.906 g/molMolar Mass of CCL4 is 153.823 g/molThe mass of CL2 is 709.0 grams

Converting grams to moles ;

  Moles of CL2 = Mass / Molar mass

  Molles of CL2 = 709.0g/70.906g/mol => 10 moles

  Moles  of CCL4 = Moles of CL2 / 4

  Moles of CCL4 = 10 moles/ 4 => 2.5 moles

Converting moles of CCL4 to grams:

 Mass of CCL4 = Moles of CCL4 x Molar mass of CCL4

 Mass of CCL4 = 2.5 moles x 153.823 g/mol => 384.5575 grams

Therefore 384.6 grams of carbon tetrachloride can be produced from reacting 709.0 grams of chlorine.

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(03.06 MC)

What is the strongest intermolecular force between an NaCl unit and an H2O molecule together in a solution? (4 points)

Group of answer choices

Covalent bonding

Dipole-dipole force

Hydrogen bonding

Ion-dipole force

Answers

Answer:

Hydrogen bonding

Explanation:

Its my answer

If i were to determine how many liters 26 grams of water is, what type of conversion would this be?

Answers

The type of conversion that would be required to determine how many liters 26 grams of water is would be a conversion from mass to volume. This is because grams are a unit of mass, while liters are a unit of volume. In order to make this conversion, it is necessary to know the density of water, which is approximately 1 gram per milliliter at room temperature and atmospheric pressure.

To convert 26 grams of water to liters, we need to divide the mass by the density. This gives us:

26 grams / 1 gram per milliliter = 26 milliliters
Since there are 1000 milliliters in a liter, we can further convert this to liters by dividing by 1000:
26 milliliters / 1000 = 0.026 liters

Therefore, 26 grams of water is equivalent to 0.026 liters of water.

In summary, to determine the volume of a given mass of water, we need to use the density of water as a conversion factor. This involves dividing the mass by the density to obtain the volume in milliliters, and then converting this to liters by dividing by 1000.

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The thermal energy needed to completely vaporize 36.04 g of water at 100°C is _________________kJ.

Answers

Explanation:

-26011130

Plss let me brainleist

52,475.39 J thermal energy is needed to completely vaporize 36.04 g of water at 100°C.

What is thermal energy?

Thermal energy is the energy contained within a system which is responsible for the temperature.

Given data:

36.04 grams of water.

Since the molecular weight of water is about 18 g/mol.

\(Moles = \frac{36.04 grams}{18 g/mol}\)

Moles = 2

Q = mcΔT

Q  = 36.04 x 4.184 J/g-K x 348 J/g-K x 348

Q = 52,475.39 J

Hence, 52,475.39 J thermal energy is needed to completely vaporize 36.04 g of water at 100°C.

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A solution is prepared by dissolving 250 g of CH4N2O into 6.0 L of solution. What is the molarity of this solution?

________M​

Answers

Answer:

Molarity = 0.65 M

Explanation:

Given data:

Mass of CH₄N₂O  = 250 g

Volume of solution = 6.0 L

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of solute:

Number of moles = mass/molar mass

Number of moles = 250 g/ 64.08 g/mol

Number of moles = 3.9 mol

by putting values,

Molarity = 3.9 mol / 6.0 L

Molarity = 0.65 M

If 30.0 ml of 0.20 M ethanol solution reacts with 1.80 g potassium permanganate, what will be the final pH of the solution

Answers

The final pH of the solution is 2. 72

How to determine the final pH

CH3CH2OH + KMnO4 ---> CH3COOH + MnO2

Mole of ethanol= Concentration * Volume = 0.20 * 30/100 = 6.0 *10-3mole

Molar mass of ethanol= 46g/mol

Mass of ethanol= mole * molar mass = 6 * 10-3 * 46 = 0.276g

Mass of KMnO4= 1.08g

Molar mass of KMnO4= 158g/mol

Molar mass of ethanoic acid formed = 60g/mol

Let's determine the limiting reagent

158g of KMnO4 reacts with 46g of ethanol

1.08g of KMnO4 should react with 46/158 * 1.08 = 0.314g of ethanol

With 0.276g of Ethanol is present, it is said to be the limiting reagent

46g of ethanol yields 60g/mol of ethanoic acid

Then, 0.276g of ethanol will yield = 60 * 0.276 /46 = 0.36g

Mole of ethanoic acid= 0.36/60= 6.0 * 10-3mole

To find the concentration of ethanoic acid= mole/volume

= 6.0 * 10-3/0.03 = 0.20M

Ionization of ethanoic acid will give;

CH3COOH ------> CH3COO- + H+

Ka= 1.8 * 10-5

Then, equilibrium concentrations will be

[CH3COOH] = 0.20-x

[CH3COO-] = x

[H+] = x

Then ,Ka= [CH3COO-][H+]/[CH3COOH]

Substitute values into the equilibrium equation

1.8 * 10-5 = x²/0.20-x

Ethanoic acid is a weak acid, so 0.20-x is approximately 0.20

x²= 0.20 * 1.8 * 10-5

x= 1.9 * 10-3

[H+] = 1.9 * 10-3M

To find the pH, use the formula;

pH= -log[H+]

Substitute the value of H+

pH= -log[1.9 x 10-3]

pH= 2.72

Therefore, the final pH of the solution is 2. 72

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Scientist are studying photosynthesisIn in a forest ecosystem that has plants animals and decomposers

Answers

Answer:

Ecosystem is food web of primary and secondary producers and consumers.

Explanation:

In an ecosystem, there exist primary producers, primary consumers, secondary consumers, and tertiary consumers such as detritivorous such as viruses and bacteria that act on the living bodies and recycle the nutrients back to plants through the soil. The primary producers such as all green plants and others make their own food being autotrophs they use sunlight and carry out photosynthesis process. On the depend on the herbivorous they eat grass etc. The secondary consumers are carnivores as heterotrophs that feed on herbivores.

5.00g of CaC12 in 95.0 g of water

Answers

Answer:

Explanation:

lo8

To understand galvanic cells, let's start with a familiar idea: oxidation-reduction (redox) reactions. This animation demonstrates a reaction of copper metal in a copper sulfate solution with an imaginary electron source
In this animation, are the Cuions in the solution being reduced or oxidized?

Answers

In this case, the copper ions are gaining two electrons to form copper metal. Therefore, the copper ions are undergoing reduction.

Why the  the copper metal loses two electrons?

In the animation, the copper metal (Cu) is initially in its solid state, while the copper sulfate solution contains copper ions (Cu²⁺) and sulfate ions (SO₄²⁻).

During the reaction, the copper metal loses two electrons (e⁻) and transforms into copper ions (Cu²⁺). This process is known as oxidation. Oxidation involves the loss of electrons from a species.

At the same time, an imaginary electron source (which is not shown in the animation) supplies two electrons to the copper ions present in the solution. This electron transfer to the copper ions causes them to gain electrons and reduces them to copper metal. This reduction process involves the gain of electrons by a species.

Overall, the reaction can be summarized as follows:

Oxidation half-reaction: Cu(s) → Cu²⁺(aq) + 2e⁻

Reduction half-reaction: Cu²⁺(aq) + 2e⁻ → Cu(s)

By combining the oxidation and reduction half-reactions, we get the balanced redox equation:

Cu(s) + Cu²⁺(aq) → 2Cu(s)

This balanced equation represents the net reaction, where copper metal reacts with copper ions to form an electrode made of solid copper. This process occurs in a galvanic cell, where the transfer of electrons drives an electric current.

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Which of the following is a non-polar molecule (have no permanent bond dipole moment)? Select the correct answer below: O CO2 be CO O CHO O CHO

Answers

CO₂ is a non-polar molecule. The correct answer is CO₂.

CO₂, which is carbon dioxide, is a non-polar molecule because it has a symmetrical shape and its bond dipoles cancel each other out. In CO₂, the carbon atom is bonded to two oxygen atoms. The molecule has a linear shape, with the carbon atom in the center and the oxygen atoms on either side.

The bond between the carbon atom and each oxygen atom is polar because oxygen is more electronegative than carbon, creating a partial negative charge on the oxygen atoms and a partial positive charge on the carbon atom. However, because the molecule is linear, the bond dipoles are equal in magnitude and opposite in direction, effectively canceling each other out.

This results in a non-polar molecule overall, with no permanent bond dipole moment. To summarize, CO₂ is a non-polar molecule because its bond dipoles cancel each other out due to its symmetrical linear shape. Hence, CO₂ is the correct answer.

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the volume of the water without the fish is 32 milliliters the volume of the water with the fish is 38 milliliters what is the volume of just the fish without the water 

Answers

Answer:

6 milliliters

Explanation:

38-32= 6

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What is the net ionic equation when agno3 and nh4cl are mixed?

Answers

The net ionic equation for the reaction between AgNO3 and NH4Cl is: Ag+(aq) + Cl-(aq) → AgCl(s)

When AgNO3 (silver nitrate) and NH4Cl (ammonium chloride) are mixed, a white precipitate of AgCl (silver chloride) is formed.

AgNO3 is a soluble salt that dissociates in water to form Ag+ and NO3- ions, while NH4Cl also dissociates in water to form NH4+ and Cl- ions. When these two solutions are mixed, the Ag+ ions react with the Cl- ions to form an insoluble precipitate of AgCl, which is a white solid. The ammonium ion (NH4+) and the nitrate ion (NO3-) are spectator ions and do not participate in the reaction.

The overall balanced chemical equation for the reaction is:

AgNO3(aq) + NH4Cl(aq) → AgCl(s) + NH4NO3(aq)

The net ionic equation shows only the species that are involved in the reaction and excludes spectator ions. Therefore, the net ionic equation for the reaction between AgNO3 and NH4Cl is:

Ag+(aq) + Cl-(aq) → AgCl(s)In the net ionic equation, the ammonium ion (NH4+) and the nitrate ion (NO3-) are not shown since they do not participate in the reaction.

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Farmers use conservation practices such as crop rotation to insure that their crops are sustainable. Crop rotation is the process of moving crops to a new location to get the nutrients from the soil needed for that specific crop to grow. What conclusion can be drawn if farmers do not use soil conservation practices such as crop rotation?

A.
If farmers do not use soil conservation practices, the topsoil, which contains weathered rocks, will not be fertile to promote plant growth because of loss of nutrients from the soil.

B.
If farmers do not use soil conservation practices, the topsoil, which contains weathered rocks, will be fertile to promote plant growth because of the loss of nutrients from the soil.

C.
If farmers do not use soil conservation practices, the topsoil, which contains humus, will not be fertile to promote plant growth because of the loss of nutrients from the soil.

D.
If farmers do not use soil conservation practices, the topsoil, which contains humus, will be fertile to promote plant growth because of the loss of nutrients from the soil.

Answers

Answer:

C.  If farmers do not use soil conservation practices, the topsoil, which contains humus, will not be fertile to promote plant growth because of the loss of nutrients from the soil.

Explanation:

The top soil is rich in humus and not weathered materials. It is not close to the bedrock. Rather, the topsoil is rich in organic matter and it is present as humus in the soil.

If crop rotation is not being practiced, the soil's nutrients would be highly depleted without replenishing them back. With crop rotation the top soil can be made more fertile when it is left uncultivated for a period of time. Instead of heavily relying on a single piece of land, crops can rotated on a timed basis so that soils will have enough time to restore their nutrients.

587. mL of 0.00531 M NaI (aq) is combined with 840. mL of 0.00536 M Pb(NO3)2 (aq). Determine if a precipitate will form given that the Ksp of Pbl2 is 1.40x10-8.
a. Precipitation will not occur because Qsp > Ksp
b. Precipitation will occur because Qsp > Ksp
c. Precipitation will occur because Qsp = Ksp
d. Precipitation will not occur because Qsp < Ksp
e. Precipitation will occur because Qsp < Ksp

Answers

The formation of a precipitate is possible when the product of the ionic concentrations exceeds the Ksp value. Qis is the reaction quotient, which is the ionic product (IP) in a solution.

To determine whether a precipitate will occur, the reaction quotient (Qis) must be compared to the solubility product constant (Kip). The correct option is (d) Precipitation will not occur because Qis < Kip. The calculations are provided solution below; Qis = [Pb2+] [I–]2Moles of NaI = 0.587 L × 0.00531 mol/L = 0.00313 mol Moles of Pb(NO3)2 = 0.840 L × 0.00536 mol/L = 0.00451 mol[Pb2+] = 0.00451 mol / (0.587 L + 0.840 L) = 0.00327 M[I–] = 0.00313 mol / (0.587 L + 0.840 L) = 0.00226 MQsp = (0.00327 M) × (0.00226 M)2 = 1.72 × 10–8 Kip = 1.4 × 10–8As Qsp is less than Ksp, a precipitate will not form. Therefore, the correct option is (d) Precipitation will not occur because Qis < Ksp.

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HELP ME PLEASEE!! I’m giving brainlest!!!

HELP ME PLEASEE!! Im giving brainlest!!!

Answers

(a) When electrons are in their lowest energy state, we say that they are in _________.

(b) Sometimes, when ________ energy such as ________ or electricity is applied to the atom, the electrons absorb energy and transition to an _________ state.

(c) The electrons can not sustain this higher energy state for so long, so eventually ________ occurs.

(d) As a result, the electrons release energy in the form of a ______ and return back to ____.

(e) The jump between the high energy state to a lower energy state is called a _________.

(a) Ground State

(b) higher energy , excited state

(c) unstability

(d) light , ground state

(e) excited state absorption

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what is octane number​

Answers

Answer:A measure of performance of fuel for internal combustion engines. Stated simply, a higher octane rating corresponds to more engine power and less knocking or other pre-ignition problems.

Explanation:

I'm also in chemistry.

Answer:

Explanation:

figure indicating the antiknock properties of a fuel, based on a comparison with a mixture of isooctane and heptane.

hcn and kcn have similar chemical formulas. however, 0.1 m hcn has a ph of 5.2, while 0.1 m kcn has a ph of 11.2. why do these two compounds behave so differently when they dissolve in water? hcn has a great solubility. hcn is an acid, and kcn is a salt. kcn is much stronger base than hcn. hcn is a nonelectrolyte.

Answers

HCN is highly soluble in water,

With rising temperatures and in extremely saline environments, its solubility declines. HCN is a colorless gas and liquid with an odor reminiscent to bitter almonds, however not everyone can smell it. HCN is created in solution when the cyanide ion interacts with water.

What is HCN?

Prussic acid, also known as hydrogen cyanide, is a chemical substance having the formula HCN and the structural formula HCN. It is a colorless, very deadly, and combustible liquid that boils at 25.6 °C (78.1 °F), only barely over room temperature. Industrial-scale HCN production makes it a highly prized precursor to a wide range of chemical compounds, from medications to polymers. Production of potassium cyanide and adiponitrile, which are used in mining and polymers, respectively, has large-scale uses. Due to its liquid nature, it is more hazardous than cyanide compounds that are solid.

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answer these questions fast ​

answer these questions fast

Answers

Answer:

1)0.5

3)1.7g

4)32g

5)1.12L

S-L Line
760
L-G Line
LIQUID
PRESSURE OF THE SUBSTANCE mm Hg
380
SOLID
58
GAS
-S-G Line
O'c
100°C
TEMPERATURE OF THE SUBSTANCE
S-L Line: Line showing conditions in which solid
and liquid phases are in equilibrium.
L-GLine: Line showing conditions in which liquid
and gas phases are in equilibrium
S-G Line: Line showing conditions in which solid
and gas phases are in equilibrium
What is the approximate vapor pressure when the gas condenses at 80'C?
200
05
760
430

Answers

2 solid 1 liquid 3 gas 430 is the answer

calculate the hydroxide ion concentration, [oh-], in 0.043 m hbr.

Answers

To calculate the hydroxide ion concentration, \([OH^{-}]\), in a solution of 0.043 M HBr, we need to consider the dissociation of HBr and the stoichiometry of the reaction. Being a strong acid, the final concentration of hydroxide ions in the solution would be negligible or approximately zero.

HBr is a strong acid that completely dissociates in water to form H⁺ and Br⁻ ions. Since it is a strong acid, we can assume that the concentration of H⁺ ions is equal to the concentration of HBr, which is 0.043 M in this case.

To find the hydroxide ion concentration, we can apply the concept of the ion product of water (\(k_{w}\)) and the fact that water is neutral (pH = 7). The product of the hydrogen ion concentration ([H⁺]) and the hydroxide ion concentration ([OH⁻]) is equal to Kw, which is 1.0 x \(10^{-14}\) at 25°C.

Since the solution contains HBr, which is an acid, the hydroxide ion concentration will be very low. In this case, we can assume that the concentration of OH⁻ is negligible compared to \(k_{w}\). Therefore, we can approximate the hydroxide ion concentration as 1.0 x \(10^{-14}\) M.

In summary, the hydroxide ion concentration, [OH⁻], in a 0.043 M HBr solution can be considered negligible or approximately zero.

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What is the volume occupied by 3.00 mol of hydrogen gas at STP? *

Answers

Answer: V=67.2 L

Explanation:

For this problem we will need to use the Ideal Gas Law.

Ideal Gas Law: PV=nRT

P=1.00 atm (STP)

V=?

n=3.00 mol

R=0.08206Latm/Kmol

T=273.15 K (STP)

To find V, we would manipulate the equation to V=nRT/P

\(V=\frac{(3.00 mol)(0.08206Latm/Kmol)(273.15K)}{1.00 atm}\)

\(V=67.244 L\)

With significan figures, our answer is V=67.2 L.

Water boils at 90∘Cwhen the pressure exerted on the liquid equals (1) 65 kPa (2) 90 kPa (3) 101.3 kPa (4) 120 kPa

Answers

The boiling point of water is dependent on the pressure exerted on the liquid. In this case, water boils at 90°C when the pressure exerted on the liquid equals 101.3 kPa, which is equivalent to atmospheric pressure. At different pressures, the boiling point of water will vary.

The boiling point of a substance is the temperature at which its vapor pressure equals the external pressure exerted on the liquid. When the external pressure is equal to the vapor pressure, the liquid starts to vaporize and boil.

In the given options, the pressure values are provided, and we need to determine which pressure corresponds to the boiling point of water at 90°C.

At standard atmospheric conditions, the pressure is approximately 101.3 kPa, which is equivalent to 1 atmosphere (atm) or 760 mmHg. This is also known as the normal boiling point of water, where water boils at 100°C.

Based on this information, we can conclude that option (3) 101.3 kPa is the correct choice. At this pressure, water boils at 90°C.
Therefore, the boiling point of water is affected by the pressure exerted on the liquid, and at 101.3 kPa, water boils at 90°C. At higher pressures, such as option (4) 120 kPa, water would boil at a higher temperature, and at lower pressures, such as options (1) 65 kPa or (2) 90 kPa, water would boil at a lower temperature.

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the aqueous aluminum sulfate formed is crystalized to make hydrated aluminum sulfate, Al2(SO4)3xH2O.

the relative formula mass of hydrated aluminum sulfate is 666.
calculate the value of x in the given formula.
(pls solve w explanation) ​

the aqueous aluminum sulfate formed is crystalized to make hydrated aluminum sulfate, Al2(SO4)3xH2O.the

Answers

In the crystalized form of aluminum sulfate, Al₂(SO₄)₃xH₂O, the value of x which represents the molecules of water is approximately 6.

How to find water per sulfate?

The formula mass of Al₂(SO₄)₃ can be calculated as follows:

Al = 2 x 26.98 = 53.96 g/mol

S = 3 x 32.06 = 96.18 g/mol

O = 12 x 16.00 = 192.00 g/mol

Total formula mass = 53.96 + 96.18 + 192.00 = 342.14 g/mol

The relative formula mass of hydrated aluminum sulfate is 666, so the mass of water in the formula can be calculated as:

mass of water = 666 - 342.14 = 323.86 g/mol

Since the formula for water is H₂O, the number of water molecules in the formula can be calculated as:

number of H₂O molecules = 323.86/18.02 = 17.92

Since there are 3 sulfate ions in the formula, the number of water molecules per sulfate ion can be calculated as:

number of H₂O per sulfate = 17.92/3 = 5.97

Therefore, the value of x in the formula  Al₂(SO₄)₃xH₂O is 6 (rounded up).

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Lab: Limiting Reactant and Percent Yield
Student Guide
Pre-Lab Information
Purpose Explore the yield of a chemical reaction by identifying the limiting reactant, comparing the
theoretical and actual yields, and explaining the sources of error.
Time Approximately 45 minutes
Question While observing a chemical reaction, how can you tell which reactant is limiting?
Reaction The reaction of copper(II) chloride and aluminum is shown in this balanced equation:
3CuCl2 + 2Al  2AlCl3 + 3Cu
Hypothesis If a substance is the limiting reactant, then it will be fully consumed by the time the
reaction completes because it is the reactant that reacts completely and the reaction
cannot proceed further.
Summary You will react copper(II) chloride with different quantities of aluminum in two trials. You
will also calculate percent yield for Trial 2.

Answers

Answer:

pre lab information would be the thing you to ressearch the lab to get the information

Limiting Reactant and Percent Yield Lab Report attached

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