Imagine a table that has a hole drilled through the center. Through this hole is a string that connects one mass that hangs under the table, to a mass that is on top of the table and spinning. mass M weighs 10kg, mass m weighs 5 kg, and the radius, R, of the circle mass M, traces out is 50cm.

1. Solve for Force centripetal
2. At what speed does the mass M need to rotate in order to keep mass m suspended

Answer:

Due to the effect of elevation on the experimental group the participants decided to try to help the research assistant who was having opening one of her files to finish the study. Schnall, Roper, and Fessler were able to conclude that happiness associated with a feeling of elevation can lead to more altruism or helping behaviors.

Explanation:

100 percent on edge

The effect of elevation on the experimental group was they show more urge of being altruistic and feeling happiness and satisfaction associated with elevation.

Altruism:

It is a practice in which a person help others without any selfishness, the person just want to help.

Witnessing someone's altruistic behavior, make other to feel good and a urge of being Altruistic, this is known as elevation.

After watching elevating Oprah video, the test group help the research assistant who was having trouble in opening file.

Therefore, the effect of elevation on the experimental group was they show more urge of being altruistic and feeling happiness and satisfaction associated with elevation.

To know more about Altruism:

https://brainly.com/question/25776081

Answer:

4 hoop, disk, sphere

Explanation:

Because

We are given data that

Hoop, disk, sphere have Same mass and radius

So let

And Initial angular velocity, = 0

The Force on each be F

And Time = t

Also let

Radius of each = r

So let's find the inertia shall we!!

I1 = m r² /2

= 0.5 mr² the his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere wiil be

I3 = (2/5) mr²

= 0.4 mr²

So

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

So we can see that

ωf is inversely proportional to moment of inertia.

And so we take the

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

hoop, disk, sphere

Option - 4

The ranking of the objects according to their angular acceleration is option 4 hoop, disk, sphere.

Since

Hoop, disk, sphere contain Same mass and radius

So here

Initial angular velocity, = 0

The Force on each be F

And Time = t

Radius of each = r

Now

I1 = m r² /2

= 0.5 mr² his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere should be

I3 = (2/5) mr²

= 0.4 mr²

Now

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

here,

ωf is inversely proportional to moment of inertia.

Now

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

Therefore, the fourth option is correct.

learn more about radius here: https://brainly.com/question/17257279

Answer: B

Explanation: the energy stored in the bowstring is a result of the elastic nature of the string (k) how far the bow has been stretched (x).

elastic potential energy is the energy stored in any elastic material when stretched.

Answer:

The answer is a fixed pulley

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

for such more questions on electric

https://brainly.com/question/1100341

#SPJ8

Hi there!

Recall Newton's Law of Universal Gravitation:

\(\large\boxed{F_g = G\frac{m_1m_2}{r^2}}\)

Where:

Fg = Force of gravity (N)

G = Gravitational Constant

m1, m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the given values stated in the problem:

\(F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}\)

Answer:

The mount saved is $ 0.105.

Explanation:

Concerned about the increase in the electricity bill, a person decides to save by reducing bathing time from 20 to 15 minutes. Your shower has the following specifications: 4200 W and 220V. Knowing that the kWh costs R$0.30, the savings made in 10 days were approximately​.

The electrical energy is given by

E = P x t

where, P is the electrical power and t is the time.

When he is using the shower for 20 minutes, the energy consumed is

E = 4200 x 20 x 60 = 5040,000 J = 1.4 kWh

When he is using the shower for 15 minutes, the energy consumed is

E' = 4200 x 15 x 60 = 3780000 J = 1.05 kWh

The difference in energy is

E'' = E - E' = 1.4 - 1.05 = 0.35 kWh

The money saved is

= 4 0.3 x 0.35 = $ 0.105

The  best description on  the weather conditions at location  A and B is  :It is warmer at position A than at position B.

Therefore Option (D) is correct

Weather condition is  described as  the regional weather during a defined time period from one up to several weeks describing typical weather phenomena, such as a series of thunderstorm in hot summer, foggy month in autumn or other weather conditions which are typical for a specific region and/or season.

From the given image, a warm front is being shown. Here, the region comprising letter A is the warm zone and the region above the front comprising the letter B indicates a cold zone. The position A forms a low-pressure zone, so it is comparatively warmer than the position B.

Learn  more about Weather condition at:

https://brainly.com/question/29332171

#SPJ1

#complete question:

Which of the following statements best describes the weather conditions at positions A and B shown below?

A. It is raining at position A and clear at position B.

B. It is cloudy at position A and clear at position B.

C. It is cooler at position A than at position B.

D. It is warmer at position A than at position B.

The magnitude of the displacement of the vector A is determined as 6.2 units.

The magnitude of the displacement of the vector is calculated as follows;

| A | = √[ (x₂ - x₁ )²  +  (y₂ - y₁ )² +  (z₂ - z₁ )²]

where;

The magnitude of vector A is calculated as;

| A | = √[ (2 - 0 )²  +  (3 - 0 )² +  (5 - 0 )²]

| A | = √ (4 + 9 + 25)

| A | = √ ( 38)

| A | = 6.2 units

Learn more about magnitude of vectors here: https://brainly.com/question/3184914

#SPJ1

The complete question is below;

If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2). find the magnitude of the displacement of vector A.

Answer:

(a) 8.57 x 10^8 Hz

(b) 23.3 cm

Explanation:

Wavelength = 35 cm = 0.35 m

speed =3 x10^8 m/s

Let the frequency is f.

(a) The relation is

speed  = frequency x wavelength

3 x 10^8 = 0.35 x f

f = 8.57 x 10^8 Hz

(b) refractive index of glass  is 1.5

The relation for the refractive index and the wavelength is

wavelength in glass= wavelength in air/ refractive index.

Wavelength in glass= 35/1.5 = 23.3 cm

Answer:

0.1351 m

Explanation:

*my number calculations may be wrong, but the process is correct*

W = Wg - Ws = mgh - \(\frac{1}{2}\)kx^2 = mg(d + x)sinθ - \(\frac{1}{2}\)kx^2

Δk = 0 - \(\frac{1}{2\\}\)mv\(_{i}\)^2

W = Δk

-\(\frac{1}{2}\)mv\(_{i}\)^2 = mg(d + x)sinθ - \(\frac{1}{2}\)kx^2

Now plug in your given values:

m=2.27, g=9.8, d=0.327, θ=20, k=455, v=0.750

Now rearrange the equation so it is in the form ax^2 + bx + c = 0 where x is the unknown distance you are looking for.

~if my math is correct it should be:~

0 = -227.5x^2 + 7.608580108x + 3.126443195

Now plug your numbers into the quadratic formula and the positive x value you get is the answer.

~if my math is correct it should be:~

x = 0.1351376847 m = 0.1351 m

Answer:

I think it's just 100+70+140

1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.

We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.

The heat lost by the metal is given by

Q1 = m1c1ΔT1

Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.

The heat gained by the ice is given by

Q2 = m2c2ΔT2

Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.

Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2

m1c1ΔT1 = m2c2ΔT2

Solving for c1, we get

c1 = m2c2ΔT2 / (m1ΔT1)

By putting these values we get

c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]

c1 = 0.902 kJ/kg·K

Hence, the specific heat of the metal is 0.902 kJ/kg·K.

To know more about equilibrium here

https://brainly.com/question/28844402

#SPJ1

Answer: It takes 3 seconds

Explanation:

Given:

The gravitational force between two objects is,

The mass of object 1 was doubled.

The distance between the objects was tripled.

To find:

The new force of attraction between the two objects

Explanation:

The force of attraction between two objects at a distance 'r' is,

According to the question,

The new force of attraction is,

Hence, the new force of attraction is 32/9 units.

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

Learn more about displacement and deceleration at: https://brainly.com/question/28786034

#SPJ1

We have that the time in seconds, minutes, and hours is

\(t=1.083*10^{-4}s\)

\(T_{min}=1.805*10^{-6}min\)

\(T_{hours}=3.0083*10^{-8}hours\)

From the Question we are told that

Velocity \(v=13.0m/s\)

Distance \(d=120 km\)

Generally the equation for the Time  is mathematically given as

\(t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s\)

Therefore

\(T_{min}=1.083*10^{-4}s/60\)

\(T_{min}=1.805*10^{-6}min\)

And

\(T_{hours}=T_{min}/60\)

\(T_{hours}=3.0083*10^{-8}hours\)

For more information on this visit

https://brainly.com/question/12319416?referrer=searchResults

Shift of half a wavelength from the previous part correspond to π radian.

Interference is a phenomenon in which two waves combine by adding  displacement together at every single point in the space and time, to form a resultant wave of greater, lower, or same amplitude.

The superposition principle explains that when two or more waves overlap in space, then the resultant disturbance is equal to the algebraic sum of  individual disturbances

Given, Wavelength= λ

We have to find the phase difference when  wavelength is half of the initial wavelength.

So, the path difference= Δx = λ/2

As, phase difference= 2π/λ * Δx

So, phase difference= 2π/λ * λ/2

Thus, phase difference= π radian

To know more about superposition of waves, refer

https://brainly.com/question/16602771

#SPJ4

A) There are 3.70 x 10¹⁶ Cs nuclei present initially and B) There are 2.27 x 10¹⁵ Cs nuclei present 2.6 min later.

A) To solve this problem, we can use the following equation,

\(N = N'2^{\frac{-t}{T_{1/2}}}\)), number of Cs nuclei present is N, initial number of Cs nuclei present is N', elapsed time is t, half-life of Cs-124 is T½. First, we need to convert the initial mass of Cs-124 to the number of nuclei present,

7.5 μg Cs-124(1g/10⁶μg)(6.022x10²³nuclei/1g)

= 4.52 x 10¹⁵ Cs-124 nuclei.

Using the equation above, we can find the number of Cs-124 nuclei present after 0 s,

\(N = 4.52 * 10^{15} * 2^{\frac{-0}{30.8}}}\)

= 4.52 x 10¹⁵ Cs-124 nuclei

Therefore, initially, there are 4.52 x 10¹⁵ Cs-124 nuclei present.

B) After 2.6 min (156 s), we can again use the same radioactivity equation to find the number of Cs-124 nuclei present,

\(N = 4.52 * 10^{15} * 2^{\frac{-156}{30.8}}}\)

N = 1.60 x 10¹⁴ Cs-124 nuclei

Therefore, 2.6 min later, there are 1.60 x 10¹⁴ Cs-124 nuclei present.

To know more about radioactivity, visit,

https://brainly.com/question/1236735

#SPJ1

Answer:

Explanation:

Something that attracts iron...duuhhh

Answer:

46-D

47-C

48-F

49-A

50-B

I am not very sure I am right about those answers though.

a.

The heat the engine extracts from its heat source in each cycle is 3.79 × 10⁴ J

The efficiency of the Carnot engine, ε = W/Q where W = work done per cycle = 2.5 × 10⁴ J and Q = heat extracted in each cycle.

Making Q subject of the formula, we have

Q = W/ε

Since ε = 66% = 0.66, we substitute the values of the variables into the equation for Q.

So, Q = W/ε

Q = 2.5 × 10⁴ J/0.66

Q = 3.79 × 10⁴ J

So, the heat the engine extracts from its heat source in each cycle is 3.79 × 10⁴ J

b.

The temperature of its heat source is 588.76 °C

Also, the efficiency of the Carnot engine, ε = 1 - T/T' where T = temperature of exhaust heat = 20° C = 273 + 20 = 293 K and T' = temperature of heat source.

Making T' subject of the formula, we have

T' = T/(1 - ε)

Since ε = 66 % = 0.66

Substituting the values of the variables into the equation, we have

T' = T/(1 - ε)

T' = 293 K/(1 - 0.66)

T = 293 K/0.34

T = 861.76 K

We convert this to Celsius.

T(K) = T(°C) + 273

T(°C) = T(K) - 273

T(°C) = 861.76 - 273

T(°C) = 588.76 °C

So, the temperature of its heat source is 588.76 °C

Learn more about Carnot engine here:

https://brainly.com/question/13170743

Answer:

Let vector C(x,y) be A-B.

Explanation:

Now the direction is given by: tan-1(y/x)

Use the correct angle on the basis in which quadrant the vector C lies.

Magnitude = sqrt(x^2 + y^2)

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

Learn more about sound waves at

https://brainly.com/question/1199084

#SPJ1

The break shot speed of the player is determined as 96.5 ft/s.

use the following kinematic equation to determine the time of motion of the player.

h = vt + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 2.75/32.17)

t = 0.171 s

vx = x/t

vx = 16.5 ft / 0.171 s

vx = 96.5 ft/s

Thus, the break shot speed of the player is determined as 96.5 ft/s.

Learn more about break shot speed here: https://brainly.com/question/8852339

#SPJ1

Answer:

a has a faster period

Explanation:

Period only depends on the length, irrelevant to the mass.

a has a shorter length, so has a small period, or faster.