Answer:
Step-by-step explanation:
A rectangle mural measures 234 inches inches by 245. Rhiannon creates a new mural that is 33 inches longer
The new mural dimensions are 267 inches by 273 inches.To find the new dimensions, we must add 33 inches to the original length of 234 inches, giving us a new length of 267 inches.
To calculate the new dimensions of Rhiannon's mural, we must first identify the original dimensions of the mural which are 234 inches by 245 inches. To find the new dimensions, we must add 33 inches to the original length of 234 inches, giving us a new length of 267 inches. We must also add 28 inches to the original width of 245 inches, giving us a new width of 273 inches. Therefore, the new dimensions of Rhiannon's mural are 267 inches by 273 inches.
The complete question is :
A rectangle mural measures 234 inches by 245. Rhiannon creates a new mural that is 33 inches longer. What are the dimensions of Rhiannon's new mural?
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For the function f(x)=−2∣x−3∣+2, describe the transformations (shifting, compress and/or reflecting) of the basic function. Graph the basic function f(x)=∣x∣. Then graph th function f(x)=−2∣x−3∣+2. Find the domain and the range of the given function. Transformations: Shifting Compressing or stretching Reflecting Graph of basic function f(x)=∣x∣ Graph of given function f(x)=−2∣x−3∣+2 Domain of f(x)=−2∣x−3∣+2 Range of f(x)=−2∣x−3∣+2
The function f(x) = -2|x - 3| + 2 involves a horizontal shift of 3 units to the right, a vertical reflection, and a downward stretch. Its domain is all real numbers, and its range is all real numbers less than or equal to 2.
The function f(x) = -2|x - 3| + 2 is a transformation of the basic absolute value function f(x) = |x|. Let's analyze the transformations and then graph both functions.Transformations:
1. Shifting: The function f(x) = -2|x - 3| + 2 involves a horizontal shift of the absolute value function f(x) = |x|. The term (x - 3) inside the absolute value causes a shift of 3 units to the right.
2. Reflecting: The negative sign in front of the absolute value function reflects the graph across the x-axis. It causes the function to be reflected vertically.
3. Compressing or stretching: There is no compression or stretching factor present in this particular function.
Graph of the basic function f(x) = |x|:
The graph of the basic function f(x) = |x| is a V-shaped graph that passes through the origin (0, 0). It has symmetry with respect to the y-axis.Graph of the given function f(x) = -2|x - 3| + 2:
To graph the given function, we start with the basic absolute value function f(x) = |x| and apply the transformations: a horizontal shift of 3 units to the right and a vertical reflection. The negative coefficient (-2) affects the amplitude, making the graph steeper.
Domain of f(x) = -2|x - 3| + 2:
The domain of the given function is all real numbers since there are no restrictions on the input values of x.
Range of f(x) = -2|x - 3| + 2:
The range of the given function is the set of all real numbers less than or equal to 2, as the vertical reflection and the coefficient (-2) cause the graph to be reflected and stretched downward.
Note: Without specific constraints on the values of x, the domain and range of the given function follow the typical domain and range of absolute value functions.
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Tara bought 2 bottles of jucie a day for 15 days. on the 16th day, Tara bought 7 bottles write an expression that matches the words
Answer:
15 x 2 + 7
Step-by-step explanation:
Tara bought 2 bottles for 15 day.
Total bottles bought = 15 x 2
Tara bought 7 bottles on the 16th day:
Total bottles bought = 15 x 2 + 7
Find the volume of the sphere. Round to the nearest tenth.
r = 2
find the value of x in the triangle shown below
Answer:
x=74º
Step-by-step explanation:
this is an isosceles triangle based on the two side lengths being the same
so 180=32+2x
148=2x
74=x
if the point p falls on the unit circle and has an x coordinate of 5/13 find the y coordinate of point p
To find the y-coordinate of point P on the unit circle, given that its x-coordinate is 5/13, we can utilize the Pythagorean identity for points on the unit circle.
The Pythagorean identity states that for any point (x, y) on the unit circle, the following equation holds true:
x^2 + y^2 = 1
Since we are given the x-coordinate as 5/13, we can substitute this value into the equation and solve for y:
(5/13)^2 + y^2 = 1
25/169 + y^2 = 1
To isolate y^2, we subtract 25/169 from both sides:
y^2 = 1 - 25/169
y^2 = 169/169 - 25/169
y^2 = 144/169
Taking the square root of both sides, we find:
y = ±sqrt(144/169)
Since we are dealing with points on the unit circle, the y-coordinate represents the sine value. Therefore, the y-coordinate of point P is:
y = ±12/13
So, the y-coordinate of point P can be either 12/13 or -12/13.
\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)
♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
plz help asap i will mark you brainlist plz help
I could use some help to find out Tony’s mistake(s)
To find the shaded area you subtract the area of the triangle from the area of the rectangle:
\(A_{shaded}=A_{rec\tan gle}-A_{triangle}\)\(\begin{gathered} A_{shaded}=w\cdot l-\frac{1}{2}b\cdot h \\ \\ A_{shaded}=(5cm)(11cm)-\frac{1}{2}(5cm)(3cm) \end{gathered}\)Then, Tony's mistake was that he added the areas instead of subtract it.
The shaded are is:
\(\begin{gathered} A_{shaded}=55cm^2-\frac{15}{2}cm^2 \\ \\ A_{shaded}=55cm^2-7.5cm^2 \\ \\ A_{shaded}=47.5cm^2 \end{gathered}\)Then, the shaded area is 47.5 square centimetersA triangle has sides with lengths of 11 mm 14 mm and 19 mm is it a right triangle?
Answer:
no
Step-by-step explanation:
because 2 of the sides would be the same length or almost the same number
Answer:
Not a right triangle
Step-by-step explanation:
I think the question is asking if this a right triangle?
In order to be a right triangle, the side lengths will need to follow Pythagorean theorem which says the two side legs of the triangle squared is equal to the hypothenuse squared or
\(a^{2}\) + \(b^{2}\) = \(c^{2}\); we can use the length given such as 11mm, 14mm and 19mm (assume is the hypothenuse)
\(11^{2}\) + \(14^{2}\) =? \(19^{2}\)
121 + 196 =? 361
317 ≠ 361; therefore it is not a right triangle
Define the relation O on Z as follows: ᵾm, n € z, m O n <----> ⱻk € z |(m – n) = 2k +1 Which one of the following statements about the relation O is true? a. The relation is reflexive, symmetric, and transitive. b. The relation is not reflexive, not symmetric, and transitive. c. The relation is not reflexive, symmetric, and not transitive. d. The relation is reflexive, not symmetric, and transitive.
The relation O is not reflexive, symmetric, and not transitive is one of the following statements that is true about the relation O. which is option (C).
Given, \(\forall m, n \in Z, m O n \longleftrightarrow \exists k \in Z \mid(m-n)=2 k+1\)
Let's verify for the following relations :
Reflexive relation:
\(\forall a\in Z, a O a \longrightarrow \exists k\in Z \mid (a-a)= 2k+1\)
\(0\neq 2k+1\) for all k \(\in\) Z
Since 2k+1 can never be zero for any k \(\in\) Z, hence we conclude that the relation O is not reflexive.
Symmetric relation:
Suppose a, b \(\in\) Zsuch that a O b i.e. (a-b)=2k+1, where k\(\in\) Z.
Now, we need to check whether b O a is true or not i.e. (b-a)=2j+1 for some j\(\in\) Z
We have,
\((a-b) = 2k+1 \longrightarrow (b-a) = -2k-1 = 2(-k) - 1\)
Let j=-k-1, then we have j\(\in\) Z and 2j+1 = -2k-1
Hence, (b-a) = 2j+1, and we conclude that the relation O is symmetric.
Transitive relation:
Suppose a, b, c\(\in\) Z such that a O b and b O c.
Now, we need to check whether a O c is true or not.
We have,
(a-b)=2k_1+1 and (b-c)=2k_2+1 for some k_1,k_2\(\in\) Z
(a-b)+(b-c) = 2k_1+1 + 2k_2+1
a-c = 2k_1+2k_2+2
Let j=k_1+k_2+1, then we have j\(\in\) Z and a-c=2j
Hence, (a-c) is even and we conclude that the relation O is not transitive.
Therefore, the relation O is not reflexive, symmetric, and not transitive. Hence, option (C) is the correct answer.
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the owner of a small deli is trying to decide whether to discontinue selling magazines. he suspects that only 8.4% of his customers buy a magazine and he thinks that he might be able to use the display space to sell something more profitable. before making a final decision, he decides that for one day he will keep track of the number of customers that buy a magazine. assuming his suspicion that 8.4% of his customers buy a magazine is correct, what is the probability that exactly 3 out of the first 11 customers buy a magazine?
The probability that exactly 3 out of the first 11 customers buy a magazine is 2.23%
The proportion of customers that buy a magazine = 8.4%
If 3 out of the first 11 customers buy a magazine, then this proportion is given as; 3/11 or 27.27%
Therefore, the probability that 3 out of the first 11 customers will buy a magazine is calculated as follows;
probability = 8.4% × 27.27%
probability = (8.4/100) × (27.27/100)
probability = 0.084 × 0.2727
probability = 0.0223
Converting it into percentage as follows;
probability = 0.0223 × 100
probability = 2.23%
Therefore, the probability that 3 out of the first 11 customers buy a magazine is calculated to be 2.23%.
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A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass-spring system is disturbed from its rest state by the force F(t) = 100cos(8t). The force F(t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
k = ? Newtons / meter
Formulate the initial value problem for y(t), where y(t) is the displacement of the object from its equilibrium rest state, measured positive in the downward direction. (Give your answer in terms of y,y′,y′′,t.)
Differential equation: ?
Initial conditions: y(0) = ? and y′(0) = ?
Solve the initial value problem for y(t).
y(t) = ?
Plot the solution and determine the maximum excursion from equilibrium made by the object on the time interval 0 ≤ t < [infinity]. If there is no such maximum, enter NONE.
maximum excursion = ? meters
Using Hooke's law the maximum value of |cos(8t)| is 1, so the maximum excursion is 1/6 meters.
To find the spring constant k, we use Hooke's law:
F = -ky
where F is the weight of the object, and y is the distance it is stretched from its rest position. At equilibrium, F = mg = 10 × 9.81 = 98.1 N. Thus,
98.1 = -k × 0.098
k = -1000 N/m
The equation of motion for the system is given by:
my'' + ky = F(t)
Substituting the given values, we get:
10y'' + (-1000)y = 100cos(8t)
y'' - 100y = 10cos(8t)
with initial conditions y(0) = 0 and y'(0) = 0.
The characteristic equation is r² - 100 = 0, with roots r = ±10i. The complementary solution is therefore y_c(t) = c1cos(10t) + c2sin(10t).
For the particular solution, we assume a form of yp(t) = Acos(8t) + Bsin(8t), and substitute it in the differential equation to get:
-64Acos(8t) - 64Bsin(8t) - 100(Acos(8t) + Bsin(8t)) = 10cos(8t)
Solving for A and B, we get A = -1/6 and B = 0. Thus, the particular solution is yp(t) = (-1/6) × cos(8t).
The general solution is therefore y(t) = c1cos(10t) + c2sin(10t) - (1/6)*cos(8t). Applying the initial conditions, we get c1 = 0 and c2 = 0, so the particular solution is simply y(t) = (-1/6) × cos(8t).
The maximum excursion from equilibrium can be found by taking the absolute value of y(t) and finding its maximum value. We have:
|y(t)| = (1/6) × |cos(8t)|
The maximum value of |cos(8t)| is 1, so the maximum excursion is 1/6 meters.
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mark looked at the statistics for his favorite baseball player, jose bautista. mark looked at seasons when bautista played 100 or more games and found that bautista's probability of hitting a home run in a game is 0.173. if mark uses the normal approximation of the binomial distribution, what will be the variance of the number of home runs bautista is projected to hit in 100 games? answer choices are rounded to the tenths place.
14.3 is probability of the variance of the number of home runs bautista is projected to hit in 100 games.
How does probability explain work?
Probability measures how probable something is to occur.We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out.Statistics is the study of events subject to probability.Given: n = 100
p = 0.173
Variance = np(1-p)
= 100*0.173*0.827
= 14.3071
Therefore, the variance to two decimal places is
= 14.3.
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The functions f(x) and g(x) are shown on the graph.f(x) = 2xWhat is g(x)?y5f(x)X-55g(x)
We know that
\(f(x)=2^x\)So, we can see that g(x) is f(x) reflected in the x-axis. But, it has another change which is a downward movement in 3 units.
So, we can deduce that
\(g(x)=-2^x-3\)Sketch of the situation:
When you reflect f(x) in the x-axis, you obtain something like -f(x).
We can see that -f(x) intersect the y-axis in -1. But, g(x) intersect the y-axis in -4.
So, we need to move the function 3 units down. Whe we make the movement the graph will intersect the y-axis in -4 because -1-3=-4.
Determine the domain of the following graph:
Answer:
[0,11)
Step-by-step explanation:
the function is defined over {0,11) because it includes x=0, but has an open dot at x=11.
PLS HELP MEMEMEMEME
Determine if triangle RST and triangle UVW are or are not similar, and, if they are, state how you know. (Note that figures are NOT necessarily drawn to scale.)
The two triangles ΔRST and ΔUVW are similar to each other by the SAS property.
What is the similarity?Two objects are said to be comparable if they have the same shape. Therefore, two figures are said to be comparable in mathematics if they share the same shapes, lines, or angles.
Given that there are two triangles ΔRST and ΔUVW. ΔRST has the angle ∠T = 59° and the sides RT = 15 units and ST = 13 units. The other triangle ΔWVU has the angle ∠W = 59° and the sides WV= 52 units and WU= 60 units.
Firstly the two angles are the same,
∠T= ∠W = 59°
The two sides are dilated by a scale factor of 4,
WV / ST = 52 / 13 = 4
WU / RT = 60 / 15 = 4
So these sides are similar.
Hence, from the SAS property, the two triangles are similar.
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1>) Alexa's 4th grade class has a spelling list organized by subject. The spelling list includes
170 words about history, 75 words about science, 60 words about math, and 55 words about
geography. Each week, Alexa's teacher tests her on 15 words from the list. Alexa's class has
already had 7 weeks of spelling tests. How many more words will Alexa be tested on before
the end of the year?
Answer:
Solution:
Total words are 170 + 75+60+55=360.
Each week, Sofia is test with 15 words from the list.
Total number of weeks it will take to finish the test is 24.
Average number of weeks in a year is 25 approximately.
Seven weeks are already over, that means 15×7=105 words are covered from the list. Conclusion:
Remaining words are 360—105=255.
These words can be covered in a group of 15 in a week, so 25515=17 are the number of weeks.
Therefore, the number of words that Sofia will be tested on before the end of the year is 255.
Step-by-step explanation:
Answer:
170+75+60+55=360
15x7=105
360-105= 255
Alexa has 255 more words until the end of the year.
Step-by-step explanation:
Hope this helps!!!
-Liyah
HURRY THIS IS DUE IN A COUPLE OF MINUTES!!!!
Answer: The model is 16.67 ft tall 16 feet, 8 inches
Step-by-step explanation: Divide the real height by the scale.
1250÷ 75 = 16.667
This is a quick Short cut for working out the ratio x/1250 : 1/75
Which of the following is an equivalent form of the compound inequality −22 > −5x − 7 ≥ −33?
A. −5x − 7 < −22 and −5x − 7 ≥ −33
B. −5x − 7 > −22 and −5x − 7 ≥ −33
C. −5x > −22 and −7 ≥ −33
D. −5x − 7 < −22 and −5x − 7 ≤ −33
Answer:your answer will be d -5x-7<-22 and -5x-7>-33
Step-by-step explanation:
I got it right pls brainliest
Answer:
im just answering so the other dude can get brainliest
Step-by-step explanation:
nationally, the proportion of red cars on the road is 0.12. a statistically-minded fan of the philadelphia phillies wonders if phillies fans are more likely to drive red cars. one day during a home game, he takes an srs of 210 and counts 35 red cars. what is the test statistic?
The test statistic for this scenario is 1.14. To calculate the test statistic, we can use the formula:
(test statistic) = (sample proportion - hypothesized proportion) / standard error
Here, the hypothesized proportion is the national proportion of red cars on the road, which is 0.12. The sample proportion is the proportion of red cars in the sample, which is 35/210 = 0.167.
To calculate the standard error, we use the formula:
\(standard error=\sqrt{\frac{(hypothesized proportion * (1 - hypothesized proportion)) }{ sample size} }\)
Plugging in the values, we get:
standard error = √[(0.12 * (1 - 0.12)) / 210] = 0.032
Now, we can calculate the test statistic:
test statistic = (0.167 - 0.12) / 0.032 = 1.14
The test statistic tells us how many standard errors the sample proportion is away from the hypothesized proportion. In this case, the test statistic is 1.14, which means that the sample proportion of Phillies fans driving red cars is 1.14 standard errors away from the national proportion of red cars on the road. We would need to compare this test statistic to a critical value from a t-distribution to determine if the difference is statistically significant at a given level of significance.
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please help me its my plato grade
Answer:
C)
Step-by-step explanation:
because the graph has been translated 5 units to the left and one unit down, and C matches the requirements
6. A radio tower 200 ft high casts a shadow 75 ft long. What is the angle of elevation to
the top of the tower?
Answer:
Angle of elevation of the sun: 69 degrees
Step-by-step explanation:
tan(x) = 200/75
x = tan^-1 (200/75)
x = 69 degrees
Find a number c such that the polynomial
p(x) = -x + 4x2 + cx3 - 8x4
has a zero at x =1/4
Answer:
c = 2
Step-by-step explanation:
Since the polynomial has a zero at x = \(\frac{1}{4}\) , then p(\(\frac{1}{4}\) ) = 0, then
p(\(\frac{1}{4}\) )
- \(\frac{1}{4}\) + 4(\(\frac{1}{4}\) )² + c(\(\frac{1}{4}\) )³ - 8\((\frac{1}{4}) ^{4}\) = 0
- \(\frac{1}{4}\) + 4(\(\frac{1}{16}\) ) + c(\(\frac{1}{64}\) ) - 8(\(\frac{1}{256}\) ) = 0
- \(\frac{1}{4}\) + \(\frac{1}{4}\) + \(\frac{c}{64}\) - \(\frac{1}{32}\) = 0 , simplifying gives
\(\frac{c}{64}\) - \(\frac{1}{32}\) = 0 ( add \(\frac{1}{32}\) to both sides )
\(\frac{c}{64}\) = \(\frac{1}{32}\) ( multiply both sides by 64 )
c = 2
Can someone please help me???
Classify each triangle by its sides.
3.
1)Scalene
2)isosceles
3)equilateral
4)acute
Answer:
1
Step-by-step explanation:
None of the sides are equal. Isosceles means that 2 sides are equal. Equilateral means that all sides are equal.
What is the surface area of this cone?
A) 161pi ft^2
B) 49pi ft^2
C) 112pi ft^2
D) 125pi ft^2
Answer:
I think it's C. cause I multipled 16 by 7
solve for y 1/3x+2y=8
1. Simplify \(\frac{1}{3} x\) to \(\frac{x}{3}\)
\(\frac{x}{3} +2y=8\)
2. Subtract \(\frac{x}{3}\) from both sides
\(2y=8-\frac{x}{3}\)
3. Divide both sides by 2
\(y=\frac{8-\frac{x}{3} }{2}\)
4. Simplify \(\frac{8-\frac{x}{3} }{2}\) to \(\frac{8}{2}\) - x/3/2
y=8/2-x/3/2
5. Simplify 8/2 to 4
y=4-x/3/2
6. Simplify x/3/2 to x/3x2
y=4-x/3x2
7. Simplify 3x2 to 6
-y=4-x/6
Write a simplified expression for the right half of the equation that can be used to find the nth term in the sequence6,7,8 9,10
help, I have a math question
Create a matrix where the column space is spanned by \( (1,2,3) \) and the null space is spanned by \( (1,3,4) \) and \( (5,2,7) \)
We can construct the matrix A with the desired column space and null space:
A = [(1,2,3), (0,0,0)]
To create a matrix where the column space is spanned by (1,2,3) and the null space is spanned by (1,3,4) and (5,2,7), we can start by creating the matrix A.
The column space of A is spanned by the columns of A. Since we want the column space to be spanned by (1,2,3), we can set the first column of A to be (1,2,3).
Next, we need to find the null space of A. The null space of A consists of all vectors x such that Ax = 0. In other words, we need to find vectors x that satisfy the equation Ax = 0.
To find these vectors, we can set up the following system of equations:
1x + 5y = 0
2x + 3y = 0
3x + 4y = 0
Solving this system of equations, we find that x = 0 and y = 0. Therefore, the null space of A is the zero vector (0,0).
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