In 1898, the world land speed record was set by Gaston Chasseloup-Laubat driving a car named Jeantaud. His speed was 39.24 mph (63.15 km/h), much lower than the limit on our interstate highways today. Repeat the calculations of Example 2.7 (assume the car accelerates for 6 miles to get up to speed, is then timed for a one-mile distance, and accelerates for another 6 miles to come to a stop) for the Jeantaud car. (Assume the car moves in the +x direction.)
Find the acceleration for the first 6 miles.

1a) Energy is absorbed, and the reaction is endothermic.

1b) The products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c) The peak of the potential energy diagram.

2a) The activation energy labeled as the difference between the reactants and the peak

2b) The activation energy can be determined by calculating the difference between the reactants.

2c) The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d) The reaction is exothermic. In terms of the graph's shape.

3a) A decrease in potential energy as the products form.

3b)This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier

Part 1:

1a. To determine if the reaction is endothermic or exothermic, we need to analyze the potential energy diagram. If the products have lower potential energy than the reactants, it indicates that energy is released, and the reaction is exothermic. Conversely, if the products have higher potential energy than the reactants, it suggests that energy is absorbed, and the reaction is endothermic.

1b. The enthalpy change (ΔH) for the reaction can be calculated by comparing the potential energy of the products and the reactants. If the products have lower potential energy, the enthalpy change is negative, indicating an exothermic reaction. If the products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c. The activation energy (Ea) can be determined by examining the energy difference between the reactants' potential energy and the peak of the potential energy diagram.

Part 2:

2a. Since the energy of the reactants is 30 kJ, the energy of the products is 5 kJ, and the maximum energy of the system is 40 kJ, we can sketch a potential energy diagram with the reactants at 30 kJ, the products at 5 kJ, the activation energy labeled as the difference between the reactants and the peak, and the enthalpy change as the difference between the reactants and products.

2b. The activation energy can be determined by calculating the difference between the reactants' energy and the peak of the potential energy diagram.

2c. The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d. Based on the energy values, if the energy of the products is lower than the energy of the reactants, the reaction is exothermic. In terms of the graph's shape, if the potential energy decreases from reactants to products, it indicates an exothermic reaction.

Part 3:

3a. The potential energy diagram for the striking and burning of a match can be sketched to show the initial potential energy of the reactants, a peak representing the activation energy, and a decrease in potential energy as the products form.

3b. The potential energy diagram would show an initial higher potential energy for the reactants, a peak representing the activation energy required for the reaction to occur, and a decrease in potential energy as the products form. This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier, leading to the release of a greater amount of energy during the burning process.

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Divide the net force by the mass:

a = (4.6 N) / (13 kg) ≈ 0.35 m/s²

also pointing backward, which looks like option B, but hard to say for sure since it's missing a decimal point.

Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.

The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.

The distance between the cars is 7 km = 7000 m.

The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.

1750 seconds is 29 minutes and 15 seconds.

To calculate the time in minutes;

Let:

v_p = the speed of car P (m/s)

v_q = the speed of car Q (m/s)

d = the distance between the cars (m)

t = the time it takes for the cars to pass each other (s)

Given that:

v_p = 30 m/s

v_q = 26 m/s

d = 7000 m

Use the equation for relative velocity to find the velocity of the cars relative to each other:

v_r = v_p - v_q

v_r = 30 m/s - 26 m/s = 4 m/s

Use the equation for distance to find the time it takes for the cars to pass each other:

d = v_r × t

7000 m = 4 m/s × t

t = 7000 m / 4 m/s = 1750 s

Convert 1750 seconds to minutes and seconds:

1750 s = 29 minutes and 15 seconds

Therefore, the cars pass each other at 9:29 and 15 seconds a.m.

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Since The table shows the traits of four tomato plant varieties. The plant that is best is Plant 2 and Plant 4.

A taxonomic rank beneath species is variety. In agriculture, a variety refers to a population of plants of a particular species that have been chosen and grown, frequently for millennia, to generate traits that are suitable for human use.

The tomato is an edible berry that is produced by the Solanum lycopersicum plant, also referred to as the tomato plant. Western South America, Mexico, and Central America are where the species first appeared. The Spanish term tomate, from which the English word tomato descended, was derived from the Mexican Nahuatl word tomatl.

Therefore, some typical tomato types include:

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A farmer wants to create a new breed of tomato that is sweet-tasting, has a very low quantity of seeds, and grows well in the hot and humid Georgia climate.

The table shows the traits of four tomato plant varieties. Which is best

Given:

The force applied on the box is: F = 1.25 N

The displacement of the box due to lifting is: d = 2.5 m

To find:

The amount of work done on a box.

Explanation:

The work done by the force acting on a particle/object is defined as the product of the force applied and the displacement of the particle/object. Whenever a force causes the box to move to a certain distance, the work is done on the box by the force.

Let F be the force acting on the box and d be the displacement of the box due to applied force. Then, the work done W is given as:

W = Fd

Substituting the values in the above equation, we get:

W = 1.25 N × 2.5 m

W = 3.125 N.m

As 1 Joule (J) is equal to 1 Newton meter (N.m), we get:

W = 3.125 J

Final answer:

The work done on the box is 3.125 J.

The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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At any point on a line charge distribution, the linear charge density is the amount of charge per unit length, expressed in coulombs per meter (Cm1). Electric charge can be positive or negative, hence charge density can also be positive or negative.

Linear charge density is a measure of the amount of electric charge per unit length along a line or wire. It is denoted by the symbol λ (lambda) and has units of coulombs per meter (C/m).

To calculate the linear charge density, you divide the total charge by the length of the line or wire. For example, if a wire has a total charge of 5 coulombs and a length of 2 meters, then the linear charge density would be:

λ = 5 C / 2 m = 2.5 C/m

P.S: Your information is incomplete and an overview was given.

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Answer:

false

Explanation:

False - For an object to maintain a constant velocity, 0 Newtons of net force (i.e., a balance of forces) is required. i. True - Unbalanced forces cause stationary objects to accelerate from rest. In the absence of an unbalanced force, a stationary object would remain at rest.

Answer:

     l = 0.548 m

Explanation:

For this exercise we compensate by finding the speed of the car

         p = m v

         v = p / m

         v = 0.58 / 0.2

         v = 2.9 m / s

this is how fast you get to the ramp, let's use conservation of energy

starting point. Lowest point

         Em₀ = K = ½ m v²

final point. Point where it stops on the ramp

         \(Em_{f}\) = U = m g h

  mechanical energy is conserved

          Em₀ = Em_{f}

          ½ m v² = m g h

           h = \(\frac{m v^2}{2 g}\)

let's calculate

          h = \(\frac{0.2 \ 2.9^2}{2 \ 9.8}\)

          h = 0.0858 m

to find the distance that e travels on the ramp let's use trigonometry, we look for the angle

          tan θ = y / x

          tan θ = 12/75 = 0.16

          θ = tan⁻¹ 0.16

          θ = 9º

therefore

           sin 9 = h / l

           l = h / sin 9

           l = 0.0858 / sin 9

           l = 0.548 m

Answer:

Resistance of the armature coil = 6.61 ohms

Back emf developed at normal speed = 98.62 V (Approx.)

Current drawn by the motor at one-third normal speed = 12.73 A

Explanation:

Given:

Potential difference V = 117 V

Current = 17.7 A

Motor drawn current = 2.78 A

Find:

Resistance of the armature coil

Back emf developed at normal speed

Current drawn by the motor at one-third normal speed

Computation:

A] Resistance of the armature coil R = V/ I

Resistance of the armature coil = 117 / 17.7

Resistance of the armature coil = 6.61 ohms

B] Back emf developed at normal speed  = V- IR

Back emf developed at normal speed = 117 V - (2.78 A)(6.61 ohms)

Back emf developed at normal speed = 117 V - 18.37

Back emf developed at normal speed = 98.62 V (Approx.)

C] Current drawn by the motor at one-third normal speed = 17.7 A - (98.62/3)/(6.61 ohms)

Current drawn by the motor at one-third normal speed = 17.7 - 4.97

Current drawn by the motor at one-third normal speed = 12.73 A

Answer:

When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.

A Type I error, also known as a false positive, occurs when a statistical hypothesis test rejects a null hypothesis that is actually true. For example, consider a medical test for a certain disease.

A Type II error, also known as a false negative, occurs when a statistical hypothesis test fails to reject a null hypothesis that is actually false. In the medical test example, a Type II error would occur if the test result suggests that the person is healthy when they actually have the disease.

Both Type I and Type II errors are harmful to research because they can lead to incorrect conclusions and decision-making.

A Type I error can result in unnecessary treatments or actions, while a Type II error can result in missed opportunities to identify and address a problem. These errors can negatively impact the validity of research and its real-world applications.

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Answer: 9.3m/s

Explanation:

Your question isn't complete but let me help out:

A 0.060 kg ball hits the ground with a speed of –32 m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a +55 N force on the ball. What is the magnitude of the velocity after it hits the ground?

We would use Newton's law of motion to solve this which goes thus:

F = ma

f = m(v-u)/t

Cross multiply

ft = m(v-u)

where,

f = 55

t = 45/1000 = 0.045

m = 0.0060

u = -32

v = Unknown

Therefore,

55 × 45/1000 = 0.060(v - -32)

55 × 0.045 = 0.060(v + 32)

2.475 = 0.06(v + 32)

2.475 = 0.06v + 1.92

0.06v = 2.475 - 1.92

0.06v = 0.555

v = 0.555/0.06

v = 9.25m/s

v = 9.3m/s Approximately

Answer:

A.9.3 m/s

Explanation:

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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Gauss's law and charges of the same sign repel allows us to find the results for the questions about the charged plates are:

Gauss's law says that the electric flux through a Gaussian surface is proportional to the charge inside it.

         Ф = ∫ E . dA = \(\frac{q_{int}}{\epsilon_o } \)

where Ф is the flux, E the electric field, A the area, \(q_{int}\) the charge inside the surface.

They indicate that we have two metallic plates with a charge of 80 μC = 80 10⁻⁶ C in each one, since the plate is metallic, the electrons are free to move in it and repel each other, therefore the ones that are farthest from each other are placed, this is concentrated on the surface of the metal plate, therefore the charge inside the surface is zero.

Let's use Gauss's law to find the electric field, we define a Gaussian surface with a cylinder base parallel to the plate, in this case the field created by the charge is parallel to the normal of the surface of the plates.

              2 E A = \(\frac{q_{int}}{\epsilon_o} \)

The two comes from the fact that the electric field is emitted towards both sides of the plate.

The charge density on each plate is:

              σ = q A

Let's substitute.

             E A = \(\frac{\sigma A}{2 \ \epsilon_o} \)

The electric field is a vector magnitude, so vector addition must be used, see attached for the direction of the electric field.

              \(R_{total} = E_1+E_2\)

              \(E_{total} = \frac{\sigma}{\epsilon_o} \)

Let's calculate.

The charge density.

          \(\sigma = \frac{q}{l^2} \)

          \(\sigma = \frac{ 80 \ 10^{-6} } { 2.0 \ 2.0}\)

          σ = 20 10⁻⁶ C

The total electric field.

          E = \(\frac{20 \ 10^{-6} }{8.85 \ 10^{-12} } \)

          E = 2.26 10⁶ N/C

In conclusion, using Gauss's law and that charges of the same sign repel each other, we can find the result for the questions about the charged plates:

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Answer:

pictures please

Explanation:

I need a picture so I can tell you

Answer:

Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789

The total energy at each point in the path of the skier is constant as the

skier travels down the slope.

Reasons:

1) Given that the total mechanical energy, M.E. is constant, we have;

M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant

M.E. = K.E. + P.E.

At the start, we have;

P.E. = 25,000 J

K.E. = 0 J

Therefore;

M.E. = 25,000 J + 0 J = 25,000 J

At point 1A, we have, K.E = 10,000 J

P.E. = M.E. - K.E.

Therefore;

P.E. = 25,000 - 10,000 = 15,000

The potential energy at point 1A, P.E. = 15,000 J

At point 1B, we have; PE = 6000 J

K.E. = M.E. - P.E.

Therefore;

K.E. = 25,000 J - 6,000 J = 19,000 J

At 1B, K.E. = 19,000 J

At point 1C, we have; K.E. = 25,000 J

Therefore;

P.E. = 25,000 J - 25,000 J = 0 J

At 1C P.E. = 0 J

2) The Law of Conservation of Energy states that the energy in a closed

system is constant.

The energy transformation follows the Law of Conservation of energy

given that the total mechanical energy is constant at all points along the

path.

3) The energy of a system is not conserved when a external force is

applied.

If the skier experiences friction, the force of friction does work to reduce

the speed of the skier, thereby reducing the kinetic energy at a point

downslope, where the potential energy has already been reduced,

resulting in an reduction in the mechanical energy of the system.

Therefore, if the skier experiences friction, the total energy of the system is

not conserved, as energy will be consumed in the work done by friction

which is converted to heat and sound energies.

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Answer:

An object increases its velocity from 20 m/s to 63 m/s in 10 s. What is the acceleration of the object?

Explanation:

The distance travelled by the car when it skids is 116.9 m.

The acceleration of the car is calculated by applying the following kinematic equation.

v² = u² - 2as

where;

when the car stops, the final velocity, v = 0

0 = u² - 2as

2as = u²

a = u²/2s

where;

u = 42 km/h = 11.67 m/s

a = (11.67²) / (2 x 13)

a = 5.24 m/s²

When the speed of the car changes from 42 km/h to 126 km/h, the distance travelled by the car at the same acceleration is calculated as follows;

s =  u²/2a

where;

u = 126 km/h = 35 m/s

s = (35²) / ( 2 x 5.24)

s = 116.9 m

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The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer: a

Explanation:

Answer:

C- A mixture can vary in composition, but a pure substance has a set composition

Explanation:

The main difference between a mixture and a pure substance is: A mixture can vary in composition, but a pure substance has a set composition ( option c )

A mixture is a substance which contains two or more constituents which can easily be separated by a physical means. It consists of two or more different substances, not chemically joined together.

A pure substance consists only of one element or one compound.

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Answer:

They are conductors/conductive. Materials that can transfer thermal energy well are conductive.

Explanation:

Answer:when material allow to heat to pass though them rapidly they are known as Conductors

What are conductors

In physics /electrical engineering They  allow the flow of charge (electrical current) in one or more directions. Materials made of metal are common electrical conductors.

What are examples of conductors

.Silver

.copper

.iron

.aluminum

.brass

Difference between conductors and insulators?

Insulators a material that is a poor conductor (as of electricity or heat)Whereas Conductors are fantastic at allowing the flow of the heat.

Hope this helps

                                                                           -Tobie

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Answer:

bro today my teacher will teach this answer only when I will be getting the answer I will copy and paste

Explanation:

wait for sometimes