In 1909 Fritz Haber reacted Nitrogen with hydrogen to produce 76.3 grams of ammonia. How many grams of hydrogen reacted?
N2(g) + 3H2(g) → 2NH3(g)

Question 5 options:

13.5 grams


4.8 grams


16.9 grams


21.2 grams

To convert grams (g) of a substance to moles (mol), you need to divide the mass by the molar mass of the substance.

The molar mass of Be(NO2)2 can be calculated by adding the molar masses of its constituent atoms, which are:

The molar mass of Be: 9.01 g/mol

The molar mass of N: 14.01 g/mol

The molar mass of O: 16.00 g/mol (there are two oxygen atoms in the nitrite ion, NO2-)

So the molar mass of Be(NO2)2 is:

9.01 g/mol (Be) + 2(14.01 g/mol (N) + 2(16.00 g/mol (O)) = 9.01 g/mol + 28.02 g/mol + 32.00 g/mol = 69.03 g/mol

Now we can use this molar mass to convert 11.9 g of Be(NO2)2 to moles:

moles = mass/molar mass

moles = 11.9 g / 69.03 g/mol

moles ≈ 0.1727 mol

Therefore, 11.9 g of Be(NO2)2 is equivalent to approximately 0.1727 moles.

Answer:

Anaxagoras was perhaps the first literate person to attempt to explain physical phenomena rationally, basing his ideas upon careful observations and simple experiments. This is fundamental to modern science and is the sine qua non of environmental study.

Explanation:

Molarity = mol/liter

Solution 240 mL = NaCl 9.0 g

Solution 1000 mL = NaCl 9.0/240 × 1000 = ..... g

mol NaCl = g/MW

MW NaCl = ?....

...........

Molarity = ......... Molar

Answer:

Lithium selenide Lithium selenide (Li2Se) 12136-60-6 Dilithium selenide lithium selenidolithium

Molecular Weight 92.9 g/mol

Dates Modify 2020-11-15 Create 2005-08-08

Answer:

Lithium is +1 and Selenium is -2, so Li2Se (Lithium Selenide).

Answer:

Lava, magma (molten rock) emerging as a liquid onto Earth's surface. The term lava is also used for the solidified rock formed by the cooling of a molten lava flow.

Explanation:

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

Equation 1 - nuclear fission

Equation 2 - nuclear fusion

Explanation:

Nuclear fission is a reaction in which a large nucleus is split into smaller nuclei when it is bombarded by neutrons. The process produces more neutrons to continue the chain reaction. This is clearly depicted in equation 1 as shown in the question.

Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.

In the first reaction, a neutron is released, and in the second a helium atom is released. The given two equations represent nuclear fission and fusion.

A nuclear reaction is a reaction that involves the nuclei of the atom and the absorption and release of energy. In the first reaction, a big nucleus is split by the neutron bombardment into smaller nuclei.

In the second reaction the process of nuclear fusion, two nuclei combine into a single larger nucleus that is shown as:

₁¹H+ ²₁H → ³₂He

Therefore, nuclear fission and fusion are represented by each of these equations.

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Answer:

11.5 g

Explanation:

28.0 g

−

16.5 g

=

11.5 g

The  ions has the noble - gas electron arrangement. The following ions has a noble gas electron arrangement is Ti⁴⁺ .

The atomic number of the titanium is 22. The symbol of the titanium is Ti.

The electronic configuration of Ti is as follows :

Electronic configuration : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d² 4s² or [Ar] 3d² 4s²

The Ti⁴⁺ means the titanium losses the four electrons and form the positively charged ion called as cation.

The electronic configuration of Ti⁴⁺ is as follows :

Electronic configuration : 1s² 2s² 2p⁶ 3s² 3p⁶ or [Ar]

Thus, the Ti⁴⁺  ions has a noble gas electron arrangement.

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In Atlanta, GA, certain seasons are associated with poorer air quality due to various factors such as weather conditions, human activities, and geographical location.

Typically, the seasons with the worst AQI in Atlanta, GA, are summer and early fall. This is primarily due to the combination of high temperatures, stagnant air masses, and increased pollution from various sources.

During the summer months, Atlanta experiences hot and humid weather, which can contribute to the formation of ground-level ozone. Ozone is a harmful pollutant that is created when pollutants from vehicles, power plants, and industrial activities react with sunlight and heat. High levels of ozone can cause respiratory issues and other health problems.

In addition to ozone, Atlanta also experiences increased levels of particulate matter (PM) during the summer and early fall. PM refers to tiny particles suspended in the air, which can come from sources such as vehicle exhaust, industrial emissions, and wildfires.

These particles can be inhaled into the lungs and can have detrimental effects on respiratory health.

It's important to note that air quality can vary from year to year and is influenced by various factors. Local regulations, weather patterns, and changes in pollutant emissions can all impact the AQI during different seasons.

Monitoring air quality reports and taking necessary precautions such as reducing outdoor activities during times of poor air quality can help individuals stay informed and protect their health.

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Answer:

The mass in grams of N₂O gas that can be dissolved is 0.18 g

Explanation:

The solubility of a gas is proportional to the partial pressure of that gas, over a determined solvent. That's what Henry's law states. We see the formula:

S = K . Pp

Where S is solubility and K is Henry's constant. This specific for each gas and each temperature, while Pp means partial pressure.

We replace data:

S = 0.025 M/atm .  0.69atm

S = 0.01725 M

This is the solubility of the gas, so now, we need to know what mass of gas is solubilized. We convert the moles, with the volume of water.

0.01725 mol/L . 0.235 L = 4.05×10⁻³ moles

Now, we determine the mass in grams:  4.05×10⁻³ mol . 28 g / 1mol =

0.1782 g

The conditions of a reactant at equilibrium are typically described using the terms concentration, pressure, and temperature. These factors play a crucial role in determining the state of a system at equilibrium.

Concentration: The concentration of the reactants and products in a chemical equilibrium system describes the amount of each substance present. It is usually expressed in terms of molarity (moles per liter). The equilibrium constant, denoted as K, is used to quantitatively express the relationship between the concentrations of reactants and products at equilibrium.

Pressure: Pressure is relevant when dealing with gaseous reactants and products. In the case of a gaseous equilibrium, the partial pressure of each gas is used to describe the conditions. The equilibrium constant can also be expressed in terms of partial pressures, known as Kp.

Temperature: Temperature plays a significant role in determining the position and stability of an equilibrium. It influences the value of the equilibrium constant and affects the rates of the forward and reverse reactions. The Le Chatelier's principle states that an increase in temperature favors an endothermic reaction, while a decrease in temperature favors an exothermic reaction.

Together, these three factors describe the conditions of a reactant at equilibrium. The equilibrium state occurs when the rates of the forward and reverse reactions become equal, resulting in a dynamic balance. By manipulating the concentrations, pressures, or temperatures, one can influence the position of equilibrium and shift it towards the desired direction.

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A doctor would choose to prescribe a liquid medicine to a patient when they have difficulties swallowing tablets and capsules. These types of medicines are preferred for small children.

Reaction rate may be defined as the speed through which a chemical reaction is accomplished. In a more simple sense, the reaction rate is directly proportional to the enhancement in the concentration of a product per unit time and to the reduction in the concentration of a reactant per unit time.

The reaction rate of liquid medicines is faster because they directly interact with the constituents of food in the gut. While the pills or capsules have an external layer that takes time to be completely swallowed.

Therefore, according to the patient's needs and capability doctors would choose to prescribe a liquid or pills.

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Explanation

Given

Mass of metal = 24.2 g

Initial volume = 15.50 mL

Final volume = 18.4 mL

Volume occupied by metal = 18.4 mL - 15.50 mL = 2.9 mL

Solution

density = mass/volume

density = 24.2g/2.9 mL

density = 8.34 g/mL

Answer

Density of metal = 8.34 g.mL

Answer:

0.87mole

Explanation:

The reaction equation is given as;

    4Fe + 3O₂  →  2Fe₂O₃

Number of moles of Fe₂O₃ in 138.5g

To solve this problem;

 Number of moles = \(\frac{mass}{molar mass}\)

Molar mass of Fe₂O₃ = 2(56) + 3(16) = 160g/mol

 Now;

          Number of moles  = \(\frac{138.5}{160}\)   = 0.87mole

Answer:

"0.1540 M" is the correct answer.

Explanation:

The given values are:

Mass of sample,

M = 6.04 g

Volume,

V = 100 mL

or,

  = 100×10⁻³ L

Molar weight of Chromium(III) sulfate

MW = 392.16 g/mol

Now,

The molarity will be:

= \(\frac{M}{MW\times V}\)

By putting the values, we get

= \(\frac{6.04}{392.16\times 100\times 10^{-3}}\)

= \(\frac{6.04}{39.216}\)

= \(0.1540 \ M\)

The increase in distance between moon and earth, the orbital speed of moon increases. As the gravitational force from earth at closer distances, the speed of orbiting decreases for moon.

Moon revolves around the earth through a fixed circular path called orbit. Moon also rotates on its own axis like earth do. The distance between moon an earth varies with revolution time.

Earth attracts every objects on or near its surface into its center of mass by gravitational force. The force exerted depends on the mass of object and distance from the ground.

As the distance from earth increases, the gravitational force experienced by moon from earth reduces and thereby, it is getting some freeness to orbits. Thus, orbital speed increase.

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a. Titration Curve:

On the x-axis, label it as "Volume of HCl added (mL)"

On the y-axis, label it as "pH"

b. Equivalence Point:

The equivalence point is the point in the titration where the moles of acid (HCl) added are stoichiometrically equivalent to the moles of base (unknown base) present initially. In the given data, the equivalence point can be estimated to be around 25.0 mL of HCl added. This is where the pH drops dramatically from 7.88 to 5.28, indicating the neutralization of the base.

c. Calculation of Kb Value:

To determine the Kb value, we need to find the pOH at half-neutralization, where half the volume of the equivalent point has been reached. In this case, the half-neutralization volume is 12.5 mL (half of 25 mL).

From the data, we can observe that at 12.5 mL of HCl added, the pH is 9.26.

pOH = 14 - pH = 14 - 9.26 = 4.74

pOH = -log[OH-]

[OH-] = 10^(-pOH)

[OH-] = 10^(-4.74)

To find [OH-] in moles per liter (M), we need to convert mL to L.

[OH-] = 10^(-4.74) mol/L

Now, since we know that at the equivalence point, the concentration of the acid (HCl) is 0.10 M, we can use the stoichiometry of the reaction to determine the concentration of the base (unknown base).

From the balanced equation:

HCl + OH- → H2O + Cl-

1 mole of HCl reacts with 1 mole of OH-

0.10 M (HCl) = [OH-] M (unknown base)

Therefore, Kb = [OH-][unknown base] / [base]

Kb = (10^(-4.74) mol/L)(0.10 M) / (0.10 M - 10^(-4.74) M)

Simplify and calculate Kb.

c. Selection of Indicator:

Based on the given pKa ranges of the indicators, the indicator phenolphthalein (pKa range: 8.3 - 10.0) would be appropriate for this titration. The reason is that the pH at the equivalence point is expected to be around 7, which is well within the range of phenolphthalein's color change. Bromophenol Blue and Methyl Red have lower pKa values and would not be suitable for indicating the equivalence point in this particular titration.

d. Calculation of Molarity and % Ionization of the Weak Base Solution:

To calculate the molarity of the weak base solution, we can use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

At the half-neutralization point, [A-] = [HA], and the pH is 9.26.

9.26 = pKa + log([A-]/[HA])

The pKa can be determined using the pOH at half-neutralization:

pKa = 14 - pOH = 14 - 4.74 = 9.26

9.26 = 9.26 + log([A-]/[HA])

log([A-]/[HA]) = 0

[A-]/[HA] = 10^0 = 1

Since [A-] = [HA], the concentration of the weak base (before titration) is equal to the concentration of its conjugate acid.

Therefore, the molarity of the weak base solution is 0.10 M.

To calculate the % ionization of the weak base, we can use the formula:

% Ionization = ([A-]/[HA]) × 100

% Ionization = (1/0.10) × 100

% Ionization = 1000%

Note: The % ionization may exceed 100% in cases where the concentration of the conjugate acid is very small compared to the concentration of the weak base.

The body of scientific knowledge is based on different Observations (Option C).

Observations in the scientific method are fundamental because it is the first step to raising scientific questions that may be explained through plausible hypotheses. Subsequently, hypotheses must be tested by experimental procedures.

In conclusion, the body of scientific knowledge is based on different Observations (Option C).

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Mass of the steel is \(1004.4 g\)

We can express this mathematically as ;

Given :

Density of this steel= 8.1g/cm3

\(Mass= 124 cm^{3}\)

If we make Mass subject of formula,

\(Mass= ( density *volume)\)

Then let us substitute the values into the expression

\(Mass= (124*8.1)\)

\(= 1004.4 g\)

Therefore, mass of the steel is \(1004.4 g\)

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Answer:

False.

Explanation:

I majored in Chemistry

Answer:

There are 2.85 x 10^22 atoms of carbon in a diamond with a mass of 0.568 g.

Hope this helps! :)

The statement that best explains why the chemical equation provided for combustion of methane supports law of conservation of mass is as follows: There is same number of each kind of atom before and after the chemical reaction and the total mass remains the same (option D).

The law of conservation of mass is a conservation law that states that the total mass of a closed system remains constant regardless of the chemical or physical changes that take place within it.

The law of conservation of mass further explains that in a chemical reaction, the amount of each atom on both sides of the equation is the same.

According to this question, methane gets combusted in air. To fulfill the law of conservation of mass, the same number of each kind of atom before and after the chemical reaction and the total mass remains the same.

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

0.0428 kg or 42.8 g

Explanation:

Applying,

Q = cmΔt.............. Equation 1

Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.

make m the subject of the equation above

m = Q/cΔt.................. Equation 2

From the question,

Given: Q = 428 J, Δt = 25 °C

Constant: c = 400 J/kg.°C

Substitute these values into equation 2

m = 428/(25×400)

m = 0.0428 kg

m = 42.8 g

Answer:

D

Explanation:

the metal are on the left and in the middle

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Therefore, the correct option is option D that is Blue only.

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Periodic table help a scientist to know what are the different types of elements are present in periodic table so that they can discover the new elements that are not being discovered yet.

The elements which is colored blue are elements that are metals. Metals are mostly on the left side of the periodic table. Metals loose lectrons easily. Metals are lustrous, malleable and ductile.

Therefore, the correct option is option D that is Blue only.

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