In 1949, an automobile manufacturing company introduced a sports car (the "Model A") which could accelerate from 0 to speed v in a time interval of Δt. In order to boost sales, a year later they introduced a more powerful engine (the "Model B") which could accelerate the car from 0 to speed 2.92v in the same time interval. Introducing the new engine did not change the mass of the car. Compare the power of the two cars, if we assume all the energy coming from the engine appears as kinetic energy of the car.

Answers

Answer 1

Answer: \(\frac{P_B}{P_A}\) = 8.5264

Explanation: Power is the rate of energy transferred per unit of time: P = \(\frac{E}{t}\)

The energy from the engine is converted into kinetic energy, which is calculated as: \(KE = \frac{1}{2}.m.v^{2}\)

To compare the power of the two cars, first find the Kinetic Energy each one has:

K.E. for Model A

\(KE_A = \frac{1}{2}.m.v^{2}\)

K.E. for model B

\(KE_B = \frac{1}{2}.m.(2.92v)^{2}\)

\(KE_B = \frac{1}{2}.m.8.5264v^{2}\)

Now, determine Power for each model:

Power for model A

\(P_{A}\) = \(\frac{m.v^{2} }{2.t}\)

Power for model B

\(P_B = \frac{m.8.5264.v^{2} }{2.t}\)

Comparing power of model B to power of model A:

\(\frac{P_B}{P_A} = \frac{m.8.5264.v^{2} }{2.t}.\frac{2.t}{m.v^{2} }\)

\(\frac{P_B}{P_A} =\) 8.5264

Comparing power for each model, power for model B is 8.5264 better than model A.


Related Questions

how to find work done under AB? can anyone teach me with detail ?​

how to find work done under AB? can anyone teach me with detail ?

Answers

Scientifically painting finished components might be given as, W = F * d. In this example, the pressure exerted at the block is regular, however, the path of force and the direction of displacement encouraged by using this pressure is one-of-a-kind. right here, force F reacts at an attitude θ to the displacement d.

The work accomplished through pressure is defined to be the product of the aspect of the force in the path of the displacement and the importance of this displacement. formulation. work may be calculated by multiplying force and Distance inside the route of force as follows. W = F × d.

The work W is equal to the pressure f instances the distance d, or W = fd. If the force is being exerted at a perspective θ to the displacement, the work accomplished is W = FD cos θ.

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The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various atmosphericprocesses, including lightning.
What is the excess charge on the surface of the earth? inC

Answers

Answer:

\(q = -461532.5 \ C\)

Explanation:

From the question we are told that

     The  electric filed is  \(E = 102 \ N/C\)  

Generally according to Gauss law

=>   \(E A = \frac{q}{\epsilon_o }\)

Given that  the electric field is pointing downward  , the equation become

    \(- E A = \frac{q}{\epsilon_o }\)

Here   \(q\) is the excess charge on the surface of the earth

          \(A\) is the surface  area of the of the earth which is mathematically represented as

     \(A = 4\pi r^2\)

Where r is the radius of the earth which has a value \(r = 6.3781*10^6 m\)

 substituting values

    \(A = 4 * 3.142 * (6.3781*10^6 \ m)^2\)

    \(A =5.1128 *10^{14} \ m^2\)

So

   \(q = -E * A * \epsilon _o\)

Here \(\epsilon_o\) s the permitivity of free space with value

          \(\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2\)

substituting values

     \(q = -102 * 5.1128 *10^{14} * 8.85 *10^{-12}\)

     \(q = -461532.5 \ C\)

URGENT!!! sorry this is my first time using brainly! but here is my question: Two ropes are attached to a wagon, one horizontal to the west with a tension force of 30 N, and the other east and at an angle of 30° northward and a tension force of 40 N. Find the components of the net force on the cart. Show all your work. Thank you in advance!

Answers

The components of the net force on the cart is determined as 67.66 N.

Component of net force on the cart

The component of net force on the cart is determined by resolving the forces into x and y -components.

T1 = 30 N

T2 = 40 N

T1x = -30cos(0) = 30 N

T1y = 30sin(0) = 0

T2x = 40 x cos(30) = 34.64 N

T2y = 40 x sin(3) = 20 N

∑X = 30 N + 34.64 N = 64.64 N

∑Y = 0 + 20 N = 20 N

Resultant force

R = √(64.64² + 20²)

R = 67.66 N

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How far does a roller coaster travel if it accelerates at 2.83 m/s2 from an initial
velocity of 3.19 m/s for 12.0 s?

Answers

Answer:

b

Explanation:

A 11.8-kg monkey is hanging by one arm from a branch and swinging on a vertical circle. As an approximation, assume a radial distance of 99.8 cm is between the branch and the point where the monkey's mass is located. As the monkey swings through the lowest point on the circle, it has a speed of 3.22 m/s. Find:

a. the magnitude of the centripetal force acting on the monkey
b. the magnitude of the tension in the monkey's arm.

Answers

Answer:

Explanation:

Fc = mv²/R = 11.8(3.22)²/0.998 = 123 N

T = m(g + v²/R) = 11.8( 9.81 + 3.22²/0.998) = 238 N

A circuit component that is a composed of a semiconductor layer sandwiched between two other semiconductor layers is a(n)?

Answers

Explanation:

It's a transistor. Hope that helps!

Answer:

D. Transistor

Explanation:

Edge 2021

What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.

Answers

Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.


To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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Calculate the net force for each of the following:
a.
20 N to the right and 30 N to the right:

Answers

Answer and Explanation:

A.

There would be a net force of 50 N going to the right.

Since both forces are going right, they add onto the force amount.

#teamtrees #PAW (Plant And Water)

The 7.4 N weight is in equilibrium under
the influence of the three forces acting on it.
The F force acts from above on the left at
an angle of a with the horizontal. The 5.9 N
force acts from above on the right at an angle
of 44° with the horizontal. The force 7.4 N
acts straight down.
Ĵ
44°
5.9 N
7.4 N
What is the magnitude of the force F?
Answer in units of N.
part 2 of 2
What is the angle a of the force F as shown
in the figure?

The 7.4 N weight is in equilibrium underthe influence of the three forces acting on it.The F force acts

Answers

a) Magnitude of force is 5.37N

b) Angle of force is - 37.88°

What is force?

In physics, we define a force is an influence that can change the motion of object. A force can cause an object with mass to change to accelerate.

Given force from above is 5.9N

∑Fₓ = F₁ₓ + F₂ₓ+F₃ₓ = 0

F₂ cos 44° + Fₓ = 0

Fₓ = - 5.9 cos44°

= - 4.24  N

Given force that acts downward as 7.4N

∑Fy= Fy1+ Fy2 +Fy3 =0

Fy+ 5.9 sin 44° - 7.4= 0

F =  3.30 N

F =√Fₓ² +Fy²

=  5.37 N

b)  angle of force= tan⁻¹ (3.30/-4.24)

= - 37.88°

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Baby Sadie gets a new rubber ducky for her first birthday! She sees that it floats in the bathtub during bath time. What do you know about the
density of the rubber ducky?

It must have a density higher than 1

It must have a density lower than 1

It must have density equal to nylon

It must have a density equal equal to acrylic

Answers

The rubber ducky was able to float because it’s density was less than the water. Water has a density of 1, meaning the rubber ducky must have a density lower than 1.

A long string is moved up and down with simple harmonic motion with a frequency of 46 Hz. The string is 579 m long and has a total mass of 46.3 kg. The string is under a tension of 3423 and is fixed at both ends. Determine the velocity of the wave on the string. What length of the string, fixed at both ends, would create a third harmonic standing wave

Answers

Answer:

a)  \(v=206.896m/s\)

b)  \(L=6.749m\)

Explanation:

From the question we are told that:

Frequency \(F=46Hz\)

Length \(l=579m\)

Total Mass \(T=4.3kg\)

Tension \(T=3423\)

a)

Generally the equation for velocity is mathematically given by

\(v=\sqrt{\frac{T}{\rho}}\)

Where

\(\pho=m*l\\\\\pho=46*579\\\\\pho=0.0799kg/m\)

Therefore

\(v=\sqrt{\frac{3423}{0.0799}}\)

\(v=206.896m/s\)

b)

Generally the equation for length of string is mathematically given by

\(L=\frac{3\lambda}{2}\)

Where

\(\lambda=\frac{v}{f}\)

\(\lambda=\frac{206.89}{46}\)

\(\lambda=4.498\)

Therefore

\(L=\frac{3*4.498}{2}\)

\(L=6.749m\)

Physics Question Work & Energy

Physics Question Work & Energy

Answers

Answer:

19,200j

Explanation:

formular W=f×d

a) W=240N×20m

= 4,800j

b) W=200N×20m

=4000j

C) Td= 4800×4000\20×50

td= 19,200,000/1000

td= 19,200j

sorry if am wrong ☹️

Activity

Many characters portrayed in the media suffer from psychological disorders. For example, piglet from Winnie the Pooh has generalized anxiety

disorder and Elsa from the movie Frozen has agoraphobla. Similarly, Identify at least four characters from movies or television shows and

describe the disorders the characters suffer from in the stories.

Answers

Answer:

Explanation:

Belle from beauty and the beast has what they call Stockholm syndrome.

Spongebob from Spongebob square pants has what is called Williams-Beuren syndrome

Ariel from the Little Mermaid has what they call Disposophobia.

Alice from Alice in the wonderland has what is called schizophrenia

Scar from the Lion King has what is known as anti social personality disorder.

Like the question suggested, many characters suffer different types of disorder, and I've just listed out a few

A projectile only has _____ acceleration and ______ velocity at the top of its path?
a. vertical, vertical
b. horizontal, horizontal
c. horizontal, vertical
d. vertical, horizontal

Answers

Answer:

d. vertical, horizontal

Explanation:

A projectile's acceleration is constantly downwards.

At the top of the path, the vertical velocity is 0, leaving only the horizontal component.

What type of force is jumping a trampoline?

Answers

Answer:

Tension

Explanation:

Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.

A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.

Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.A.)What

Answers

(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

What is the amplitude of the wave?

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

v is the speed of the wavef is the frequency of the wave

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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find the average speed of a car that travels 45km in 2hours 15minutes​

Answers

Answer:

20 km/h

Explanation:

45 km ÷ 2.25 hours (15 mins is 0.25 hours)

= 20

20 km/h

Which statement describes one feature of a mineral's definite chemical composition?
It always occurs in pure form.
It always contains certain elements.
It cannot form from living or once-living materials.
It cannot contain atoms from more than one element.
N

Answers

Answer:

It always contains certain elements

Explanation:

Minerals can be defined as natural inorganic substances which possess an orderly internal structural arrangement as well as a particular, well known chemical composition, crystal structures and physical properties. Minerals include; quartz, dolomite, basalt, etc. Minerals may occur in isolation or in rock formations.

Minerals contain specific, well known chemical elements in certain ratios that can only vary within narrow limits. This is what we mean by a mineral's definite chemical composition. The structure of these minerals are all well known as well as their atom to atom connectivity.

The statement describes one feature of a mineral's definite chemical composition - It always contains certain elements.

A mineral is a naturally occurring chemical compound, usually of a crystalline form.

A mineral has one specific chemical composition.chemical composition that varies within a specific limited range and the atoms that make up the mineral must occur in specific ratiosthe proportions of the different elements and groups of elements in the mineral.

Thus, The statement describes one feature of a mineral's definite chemical composition - It always contains certain elements.

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How much power does it take to lift 30.0 N 10.0 m high in 10.00 s?

Answers

Answer:

60w

Explanation:

The power required is 30 Watt.

Let us recall that power is defined as the rate of doing work. Hence, we can write as follows;

Power = Work done/ time taken

Now;

work done =  Force × distance

Force = 30.0 N

Distance = 10.0 m

work done = 30.0 N × 10.0 m = 300 J

The power expended = 300 J/10.00 s = 30 Watt

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A falling 0.60 kg object experiences a frictional force due to air resistance of 1.5 N. What is the object's acceleration?​

Answers

Answer:

7.5 m/s².

Explanation:

From the question given above, the following data were:

Mass (m) of object = 0.6 Kg

Force of friction (Fբ) = 1.5 N

Acceleration (a) =?

Next, we shall determine the force of gravity on the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Acceleration due to gravity (g) = 10 m/s²

Force of gravity (F₉) =?

F₉ = mg

F₉ = 0.6 × 10

F₉ = 6 N

Next, we shall determine the net force acting on the object. This can be obtained as follow:

Force of friction (Fբ) = 1.5 N

Force of gravity (F₉) = 6 N

Net force (Fₙ) =?

Fₙ = F₉ – Fբ

Fₙ = 6 – 1.5

Fₙ = 4.5 N

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Net force (Fₙ) = 4.5 N

Acceleration (a) of object =?

Fₙ = ma

4.5 = 0.6 × a

Divide both side by 0.6

a = 4.5 / 0.6

a = 7.5 m/s²

Therefore, the acceleration of the object is 7.5 m/s²

A spring stretches 6.0 cm when a 0.25 kg block is hung from it.

If a 0.80 kg block replaces the 0.25 kg block, how far does the spring stretch?

Answers

When a 0.80 Kg block is used in place of a 0.25 Kg block, the length of the string is increased by 19.6 cm.

How does spring stretch become calculated?

The formula used by the Hooke's Law Calculator is Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, or the length by which the spring is being stretched

We'll start by determining the spring's string constant. Specifics below:

Extension (e) = 6.0 cm

Mass (m) = 0.25 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.25 × 9.8 = 2.45 N

Spring constant (K) =?

F = Ke

2.45 = K × 6

Divide both sides by 6

K = 2.45 / 6

K = 0.40 N/cm

The extension will be calculated after the 0.25 kg block is replaced with the 0.80 kg block. As demonstrated below:

Mass (m) = 0.80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.80 × 9.8 = 7.84 N

Spring constant (K) = 0.40 N/cm

Extension (e) = ?

F = Ke

7.84 = 0.40 × e

Divide both sides by 0.40

e = 7.84 / 0.40

e = 19.6 cm

We may thus deduce from the preceding computation that the spring will lengthen by 19.6 cm.

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have a difinite shape and do not easily take the shape of their containers

Answers


Ok well that’s something to think about

A mass m at the end of a spring oscillates with a frequency of 0.71 Hz . When an additional 780 g mass is added to m, the frequency is 0.64 Hz .
a)What is the value of m ?

Answers

A mass m at the end of a spring oscillates with a frequency of 0.71 Hz . When an additional 780 g mass is added to m, the frequency is 0.64 Hz, thus the value of mass is 3.376 kg

What is frequency?

In terms of physics, frequency refers to the quantity of waves that pass through a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences over the course of a single unit of time.

Given that,

Frequency = 0.71 Hz

Mass = 780 g

After added to m, frequency becomes = 0.64 Hz.

Let the spring constant is k

k=m × w²

from the given info.

m × (0.71)² = (m+0.78) × (0.64)²

m ×[(0.71)²- (0.64)²] = 0.78 × (0.64)²

m = 0.78 × (0.64)² /[(0.71)²- (0.64)²]  

m = 0.319 / 0.0945

m = 3.376 kg

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Which landscape feature can be caused by chemical
weathering?
OU-shaped valley
O Basalt columns
O Limestone caves

Answers

Answer: Limestone Caves

Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.

What is the only thing that can change
an
object's velocity and give it acceleration?|
Pleaseee hElp

Answers

Answer:

Since velocity is a speed and a direction, there are only two ways for you to accelerate

Explanation:

change your speed or change your direction—or change both.

You can slow down or speed up or change direction

On the way to school, Jed traveled 100m north, 300m east, 100 north, 100m east, and 100m north. A.) Find the total distance travelled by Jed. B.) Determine the displacement by jed.​

Answers

Answer:

Total distance = 700 m

Displacement = 500 m

Explanation:

Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is:  300 + 400 = 700 m.

But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:

displacement = \(\sqrt{300^2+400^2} =\sqrt{250000} =500\,m\)

A typical atom has a diameter of about 1.32 x 10-10 m.
A) What is this in inches?
B) How many atoms are there along a 21.0cm line?

Answers

Answer:

A) The value of the diameter in inches is 5.19685 × 10⁻⁹ inches

B)  There are 1,590,909,091 atoms on a 21.0cm line

Explanation:

A) To determine what its diameter is in inches

We will convert 1.32 × 10⁻¹⁰ m to inches

First convert this to centimeters (cm)

1.32 × 10⁻¹⁰m = 1.32 × 10⁻¹⁰ × 10² cm

=  1.32 × 10⁻⁸cm

Now, since 1 inch = 2.54 cm

∴ 1 cm = \(\frac{1}{2.54}\) inches

If  1 cm = \(\frac{1}{2.54}\) inches

Then 1.32 × 10⁻⁸ cm will be

1.32 × 10⁻⁸ × \(\frac{1}{2.54}\) inches

= 5.19685 × 10⁻⁹ inches

This is the value of the diameter in inches

B) For the number of atoms on a 21.0cm line

The diameter of 1 atom is 1.32 × 10⁻¹⁰m

1.32 × 10⁻¹⁰m = 1.32 × 10⁻⁸cm

Hence, on a 21.0 cm line, we will have

(21.0 / 1.32 × 10⁻⁸) atoms

= 1590909091 atoms

Hence, there are 1,590,909,091 atoms on a 21.0cm line

urgent pls help

Which of the following best explains why the sand at the beach is hotter
than the water? *

urgent pls helpWhich of the following best explains why the sand at the beach is hotterthan the water?

Answers

In my opinion,Sand has more specific heat than water.

Answer:

the answer is d. because water has a higher specific heat capacity than sand

An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike

Answers

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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A health and fitness club surveys 40 randomly selected members and found that the average weight of those questioned is 157 lb. Is this average an example of a statistic or a parameter? A) Parameter B) Statistic I need help asap pls help me FILL IN THE BLANK. research indicates that automatic, negative associations with members of various stigmatized groups appear to be more easily activated among___than among___. The primary reason" the 1974 Constitutional Convention in Texas failed was because HELP PLEASEEEEEEE guys HEEEEELLLLLLLPPPP WITHHHHHH MATHHHHH *y = 4x - 19Is this a function? Required information Problem 15-3A (Algo) Debt investments in available-for-sale securities; unrealized and realized gales and losses LO P3 [The following information applies to the questions displayed below.] Stoll Company's long-term available-for-sale portfolio at the start of this year consists of the following. Available-for-Sale Securities Cost Company A bonds Company B notes Company C bonds $ 531,500 159,040 663,000 Fair Value $ 495,000 145,000 641,100 Stoll enters into the following transactions involving its available-for-sale debt securities this year. January 29 Sold one-half of the Company B notes for $78,200. July 6 Purchased Company x bonds for $120,700. November 13 Purchased Company notes for $268,000. December 9 Sold all of the Company A bonds for $515,200. Fair values at December 31 are B, $83,500; C, $605,700; X, $108,000; and Z, $280,000. Problem 15-3A (Algo) Part 1 and 2 Required: 1. Prepare Journal entries to record these transactions, including the December 31 adjusting entry to record the fair value adjustment for the long-term investments in available-for-sale securities. 2. Determine the amount Stoll reports on its December 31 balance sheet for its long-term investments in available-for-sale securities. 4 5 Record the year-end adjusting entry for the securities portfolio as of December 31. Note: Enter debits before credits. Date General Journal Debit Credit December 31 View general Journal Fair value adjustment - AFS Unrealized gain - Equity Record entry $ Clear entry > Fair Value Adjustment Computation - Available-for-Sale Securities Cost Fair Value Unrealized Amount December 31 AFS Securities Total $ December 31 Balance in the Fair Value Adjustment account 0 $ what must the charge (sign and magnitude) of a particle of mass 1.48 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 610 n/c ? use 9.80 m/s2 for the magnitude of the free-fall acceleration. Each subject was given a different protocol on each of the three nights, and the order of the protocols was varied among the subjects that so that one third had each protocol each night. What factors were the researchers attempting to control for with this approach? Which type of weathering involves transformation of rock into one or more new compounds? QUESTION 241 POINT Suppose that the piecewise function f is defined by f(x)= 3x +4. -2x + 5x-2, x>1 Determine which of the following statements are true. Select the correct answer below. Of(x) is y= -2x - 3 y= 7x + 6 solve by elimination how many miles per hour is someone running is they run run 1/4 of a mile in 1/20 of an hour What is the product of (22.1)(5.6)? What did nato promise? One-half of a number decreased by two-thirds is twoless than one-fifth of the number. Find the number. Refer to figure above. If the price is $15, Group of answer choices there would be surplus of 300 units. there would be a surplus of 200 units. there would be shortage of 300 units. there would be shortage of 400 units. You measure the weights of 28 5-year-old children, and find they have a mean weight of 70 pounds. Assume the population standard deviation is 8.6 pounds. Soon, we will construct (compute) a confidence interval for the true population parameter. Right now, we want to understand all the moving parts. Where applicable, round your answers to three decimal places. (a) Is this a confidence interval for a population proportion or a population mean? O proportion O mean : Take the sample variance of this data series: 15, 26, 0, 0, 0, 28, 20, 20, 31, 45, 32, 41, 54, 23, 45, 24, 90, 19, 16, 75, 29 And the population variance of this data series: 15, 26, 25, 23, 26, 28, 20, 20, 31, 45, 32, 41, 54, 23, 45, 24, 90, 19, 100, 75, 29 Calculate the difference between the two quantities (round to two decimal places- and use the absolute value).