In a hand of cards, the ratio of black cards was 5 to 3. if the hand contained 15 black cards, which of the following proportions could be solved to find the number of red cards, r(1) 15/r = 5/3. (3) r/15 = 3/8(2) r/15 = 5/3. (4) 15/r = 5/8

The new carpet will cοst $1,908.00.

The size οf a regiοn οn a surface is measured by its area. While surface area refers tο the area οf an οpen surface οr the bοundary οf a three-dimensiοnal οbject, the area οf a plane regiοn οr plane area refers tο the area οf a shape οr planar lamina.

Area can be interpreted as the quantity οf material with a particular thickness required tο create a mοdel οf the shape οr as the quantity οf paint required tο cοmpletely cοver a surface in a single cοat. It is the twο-dimensiοnal equivalent οf the vοlume οf a sοlid οr the length οf a curve (a οne-dimensiοnal cοncept) (a three-dimensiοnal cοncept).

The area οf the classrοοm is the square οf the length οf its side, which is:

6 yards × 6 yards = 36 square yardsTο find the cοst οf the new carpet, we need tο multiply the area οf the classrοοm by the cοst per square yard:

36 square yards × $53.00/square yard = $1,908.00

Therefοre, the new carpet will cοst $1,908.00.

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By comparing the population range to the mean of the sample ranges, the answer will be D) The population range equal the youngest official at the time of death and the mean of the sample ranges is equal to the oldest official at the time of death.

Creating a tonne of random numbers between 40 and 70 points so that we can see that the population range is equal to 70. That is presumably the oldest value that is still valid. The population range is the sum of the data generated at the highest level and the lowest level. The population range is now 30 points. by taking a handful of random samples.

We want a sample table containing random samples of the data so we don't have to worry about this. Going through the samples with the new table that will be generated here and want to find this range by taking the max of each sample. Subtracting the mean from each sample from the range samples from 1 to 10. The range for the initial data was 30 points because the entire range was 40 to 70 points; nevertheless, we can observe that this range varies from 64 to 70 points.

We made the table because we wanted the mean of the average of our separate ranges to be 21.7. The mean value of the ranges in 100 samples will be discovered if the sample size is increased. A sample's range is not representative of the population. We can infer that we do it since the samples' range and average range are greatly dissimilar.

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The result suggests that the mean wake time might have really reduced since the values barely fall above 100 min as in before treatment with a high degree of confidence. thus , the drug is effective.

Confidence interval is written in the form as;

(Sample mean - margin of error, sample mean + margin of error)

The sample mean represent x , it is the point estimate for the population mean.

Margin of error = z × s/√n

Where s = sample standard deviation = 21.8

n = number of samples = 17

Now the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

then the degree of freedom, df for the sample.

df = n - 1 = 17 - 1 = 16

Since confidence level = 99% = 0.99, α = 1 - CL = 1 – 0.99 = 0.01

α/2 = 0.01/2 = 0.005

Therefore the area to the right of z0.005 is 0.005 and the area to the left of z0.005 is 1 - 0.005 = 0.995

the t distribution table, z = 2.921

Margin of error = 2.921 × 21.8/√17

= 15.44

The confidence interval for the mean wake time for a population with drug treatments will be; 90.3 ± 15.44

The upper limit is 90.3 + 15.44 = 105.74 mins

The lower limit is 90.3 - 15.44 = 74.86 mins

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Answer:

$4.42

Step-by-step explanation:

hope that helps :))

Answer:

----------------------------

Find the composition of the functions f(x) and g(x), which is written as f(g(x)).

Given functions:

Find f(g(x)):

Evaluate f(g(2)):

So, (f·g)(2) = 14.

Answer:

Not similar

Hope this helps you

Can I have the brainliest please?

Answer:

The slope would be 2

Step-by-step explanation:

Please brainliest!

And hope this helped you!

I also answered first!

And tell me If I am wrong! :D

Answer:

9:12

Step-by-step explanation:

Answer:

the answer is Less than "<"

Step-by-step explanation:

when you reduce both ratios you get 6:9=2:3 and 9:12=3:4

2:3<3:4

The correct sample space for the gumballs in Julia's bag is {lemon-lime, watermelon, watermelon, grape, grape, grape} which makes option D correct.

The sample space for the gumballs in Julia's bag would be all the possible outcomes of selecting one gumball from the bag without replacement.

Since there are 1 lemon-lime, 2 watermelon, and 3 grape gumballs in the bag, the sample space would be expressed as:

sample space = {lemon-lime, watermelon, watermelon, grape, grape, grape}.

Therefore,we have 6 total outcomes in the sample space for the gumballs in Julia's bag.

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Answer:

  (d)  a1 = 11

Step-by-step explanation:

Put the numbers in the given formula and solve for a1.

  a5 = 176 = a1(r^(5-1)) = a1·r^4

  a7 = 704 = a1(r^(7-1)) = a1·r^6

Dividing a7 by a5 gives ...

  a7/a5 = (a1·r^6)/(a1·r^4) = r^2 = 704/176 = 4

Then a1 is ...

  a1 = a5/(r^4) = 176/(r²)² = 176/(4²) = 11

The first term is 11.

Hi, mal :> hehehe

( its \(a_{1} = -11\))

Your welcome..... ;]

Answer:

x = 15

Step-by-step explanation:

3x+1+4x-3 = 103

7x = 105

x = 15

The mean absolute deviation is 0.75

To calculate the mean absolute deviation (M.A.D.), you need to find the average of the absolute differences between each data point and the mean of the data set

From the information given, we have that the data set is;

8 9 9 7 8 6 9 8

Let's calculate the mean, we get;

Mean = (8 + 9 + 9 + 7 + 8 + 6 + 9 + 8) / 8

Mean = 64 / 8

Divide the values

Mean = 8

Let's determine the absolute difference, we get;

Absolute differences=

|8 - 8| = 0

|9 - 8| = 1

|9 - 8| = 1

|7 - 8| = 1

|8 - 8| = 0

|6 - 8| = 2

|9 - 8| = 1

|8 - 8| = 0

Find the mean of the absolute differences:

Average of absolute differences = (0 + 1 + 1 + 1 + 0 + 2 + 1 + 0) / 8

Absolute difference = 6 / 8 = 0.75

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Differentition of \(y=log_{2}x^{3}.(5x^{4}+2)\) is \(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x}\)

A differential equation is an equation that contains one or more functions with its derivatives.

Given,

\(y=log_{2}x^{3}.(5x^{4}+2)\)

We have to differentiate with respect to x.

y'=xy'+yx'

\(x=log_{2}x^{3}\)

\(y=5x^{4}+2\)

\(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x^{3}} .3x^{2}\)

\(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x}\)

Hence, differentiation of \(y=log_{2}x^{3}.(5x^{4}+2)\) is \(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x}\)

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Answer:

Step-by-step explanation:

W = 4L-17

LW = 15

L(4L-17) = 15

4L^2-17L-15= 0

L = [17 ±√(17^2-4(4)(-15))]/[2(4)] = 5,-3/4

-3/4 is an extraneous solution

L = 5 cm

W = 4L-17 = 3 cm

Answer:

x = 6.24

Step-by-step explanation:

x =

Tan32° = OPP/ADJ

Tan32° = x/10

0.624 = x/10

cross-multiply

x = 6.24

A. To construct a grouped frequency distribution for the given data, we first need to determine the range of the data:

Range = Maximum value - Minimum value

Range = 39 - 5

Range = 34

Next, we need to decide on the width of each class interval. A common rule is to choose the number of classes to be between 5 and 20, and then choose a class width that is a convenient number. In this case, we will choose 8 classes and a class width of 5.

Class width = Range / Number of classes

Class width = 34 / 8

Class width ≈ 4.25

We can round up the class width to 5 to get a convenient number. The class intervals are:

5 - 9.99

10 - 14.99

15 - 19.99

20 - 24.99

25 - 29.99

30 - 34.99

35 - 39.99

40 - 44.99

Next, we count the number of observations that fall into each class interval. This gives us the frequency of each interval. The grouped frequency distribution is:

Class Interval Frequency

5 - 9.99 5

10 - 14.99 8

15 - 19.99 9

20 - 24.99 16

25 - 29.99 7

30 - 34.99 6

35 - 39.99 1

40 - 44.99 0

B. To draw the histogram, frequency polygon, and cumulative frequency curves, we first need to calculate the cumulative frequencies. The less than cumulative frequency is the running total of the frequencies up to each class interval, while the more than cumulative frequency is the running total of the frequencies from each class interval to the end.

Class Interval Frequency Less than Cumulative Frequency More than Cumulative Frequency

5 - 9.99 5 5 62

10 - 14.99 8 13 57

15 - 19.99 9 22 49

20 - 24.99 16 38 40

25 - 29.99 7 45 24

30 - 34.99 6 51 17

35 - 39.99 1 52 11

40 - 44.99 0 52 10

Now we can draw the graphs:

Histogram:

   20 |

       |           __

       |          |  |

       |    __    |  |

       |   |  |   |  |

       |   |  |   |  |

       |   |  |   |  |

       |___|__|___|__|__

           5  10  15  20

Frequency polygon:

   25 |

       |  __

       | |  |     __

       | |  |    |  |

       | |  |    |  |

       | |  |

Answer:

The minimum number of parallel faces that a prism should have is three pairs

Answer:

The minimum number of parallel faces that a prism should have is three faces

Answer:

children attended= 114

adults attended= 57

students attended= 82

Step-by-step explanation:

children attended= c

adults attended=  a

students attended=  s

c+s+a = 253

5c + 7s + 12a = 1828

c=2a

2a + s + a =253

5*2a + 7s + 12a = 1828

3a + s = 253

22a + 7s = 1828

s = 253 - 3a

22a + 7(253 - 3a) = 1828

22a - 21a + 7*253 = 1828

a = 1828 - 7*253

a = 57

s = 253 - 3a = 253 - 3*57 = 82

s = 82

c=2a=2*57= 114

c=114

Answer:

÷2 I think plz tell me if I'm wrong sry if I am

Answer:

2,4 3,5

Step-by-step explanation:

================================================

Work Shown for problem 1

P(pink, then violet) = P(pink)*P(violet given 1st was pink)

= (4/14)*(2/13)

= 8/182

= 4/91

------------------------------

Work Shown for problem 2

P(gray, then gray)

= P(gray)*P(gray given 1st was gray)

= (3/14)*(2/13)

= 6/182

= 3/91

-------------------------------

Work Shown for problem 3

P(not yellow, not yellow)

= P(not yellow)*P(not yellow given 1st was not yellow)

= (9/14)*(8/13)

= 72/182

= 36/91

-------------------------------

Work Shown for problem 4

P(yellow, not yellow)

= P(yellow)*P(not yellow given 1st was yellow)

= (5/14)*(9/13)

= 45/182

You have the following functions:

In order to evaluate f(g(x)), replace the expression for g(x) where x is in the function f(x), just as follow:

Hence, f(g(x)) is 1,161

On solving the provided question we can say that 1,000,000 nanometers =  1 millimeter; 1e-6 millimeter = nanometers

A nanometer, often known as a nanometer, is a unit of measurement that is one billionth of a metre and one thousandth of a picometre in the International System of Units. In scientific notation, a nanometer is represented by the numbers 1 109 m and 1/1000000000 metres. The prefix "nano" refers to one billionth, or 10-9, in the International System of Units. An nanometer is therefore one billionth of a metre. The metric unit of length known as a nanometer is one billionth of a metre (0.000000001 m). It is a small length unit, abbreviated as nm. One billionth of a metre or one billionth of a micrometre is what is known as a nanometer (nm), which is 109 metres. Atoms and the molecules they make up are measured using this scale.

1,000,000 nanometers =  1 millimeter

1e-6 millimeter = nanometers

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Given:

The library at (-2,2).

The city hall is at (0,2).

The school is at (0,0).

Required:

We need to locate these three points and find the area after joining them.

Explanation:

1)

Recall that coordinates are written as (x, y), where x is the value from the origin in the direction of the x-axis, and y is the value from the origin in the direction of the y-axis.

Locate the point (-2,2), where -2 is 2 units from origin to the left side on the x-axis and 2 is 2 units from origin to up on the y-axis.

Similarly, locate the remaining points in the graph.

2)

Join all three points.

We get a right-angled triangle.

The right-angled triangle is formed by connecting the three locations.

3)

The city park is placed in the region connecting the three locations.

We need to find the area of the triangle connecting the three locations.

The length of the base is the distance between (-2,2) and (0,2).

The height is the distance between (0,2) and (0,0).

The distance between (-2,2) and (0,2) is 2 units,

We get b =2.

The distance between (0,2) and (0,0) is 2 untis.

We get h=2.

Consider the area of the triangle formula.

Substitute b=2 and h=2 in the formula.

The area of the planned park is 2 square units.

Final answer:

Connecting the three locations formed the right-angled triangle.

The area of the planned park is 2 square units.

Using the information in the given diagram, the value of the missing angle is: m∠1 = 75°

The transverse line theorem states that If two parallel lines are cut by a transversal, then corresponding angles are congruent. Two lines cut by a transversal are parallel IF AND ONLY IF corresponding angles are congruent.

Now, when we draw a horizontal line parallel to lines a and b and directly cutting across the vertex of angle 1, we can see that angle 1 will be composed of two angles.

Now, for the transverse line theorem we can say that:

Angle 1 will be composed of two angles namely:

48 degrees and (180 - 153) degrees.

Thus:

m∠1 = 48° + 27°

m∠1 = 75°

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The area of triangle EFG is given as follows:

A = 18.63 square units.

The area of a rectangle of base b and height h is given by half the multiplication of dimensions, according to the formula presented as follows:

A = 0.5bh

The base is given by segment EF as follows:

\(EF = \sqrt{(9 - 4)^2 + (-7 -(-9))^2}\)

EF = 5.4.

The midpoint of EF is given as follows:

M(6.5, -8).

The height is given by the segment MG as follows:

\(MG = \sqrt{(6.5 - 3)^2 + (-2 - (-8))^2}\)

MG = 6.9.

Hence the area is given as follows:

A = 0.5bh

A = 0.5 x 5.4 x 6.9

A = 18.63 square units.

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