in a hydraulic lift system, the output force is greater than the input force because

Answers

Answer 1

Answer:

In a hydraulic lift system, the output force is greater than the input force because the pressure acting on the output piston is greater than the pressure acting on the input piston.

Explanation:


Related Questions

Pyruvate is converted to lactate in order to replenish the cell's supply of a. ATP b. CO2 c. acetyl-CoAd. NAD+

Answers

Pyruvate is converted to lactate in order to replenish the cell's supply of NAD+, which is necessary for the continuation of glycolysis and the production of ATP. While this process may not be as efficient as cellular respiration in terms of ATP production, it allows cells to survive in low oxygen conditions and maintain energy production.

Pyruvate is a molecule that is produced during the process of glycolysis, which is a series of reactions that take place in the cytoplasm of cells. During glycolysis, glucose is broken down into pyruvate, which can then be further processed through cellular respiration to produce ATP, the energy currency of cells. However, in some cases, pyruvate is converted to lactate instead of being further processed. This conversion is catalyzed by the enzyme lactate dehydrogenase and requires the electron carrier molecule NAD+.
The conversion of pyruvate to lactate is an example of anaerobic respiration, which can occur in cells that do not have access to oxygen or in situations where oxygen is limited. This process helps to replenish the cell's supply of NAD+ so that glycolysis can continue. Without NAD+, the glycolytic pathway would be inhibited, and ATP production would be significantly reduced. By converting pyruvate to lactate, the cell can maintain a steady supply of NAD+ and continue to produce ATP through glycolysis, even in the absence of oxygen.

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what is an example of matter?4615 multiple choice light energy heat none of the answers are correct. oxygen gas

Answers

Matter is anything that has mass and occupies space.

An example of matter is oxygen gas. It is a gas that has a definite volume and can be measured in terms of its mass. Other examples of matter include solids like rocks and metals, liquids like water and oil, and gases like helium and nitrogen. An example of matter is oxygen gas. Matter refers to any substance that has mass and occupies space, and oxygen gas fits this description. In contrast, light and heat are forms of energy, not matter, so they are not suitable examples. In this multiple-choice question, the correct answer would be oxygen gas, as it is a tangible substance with mass and volume, distinguishing it from the other options presented.

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How many electrons does the Ca^2+ ion possess

Answers

Answer:

18 electrons

Explanation:

Answer:

18 electrons

Explanation:

Ca has 20 electrons. Ca^2+ has 18 electrons

carbon dioxide and particulates are emitted by volcanoes. particulates form stratospheric aerosols that reflect sunlight. which of the following best describes the impact of atmospheric carbon dioxide and stratospheric aerosols?

Answers

Carbon dioxide and particulates are emitted by volcanoes. Particulates form stratospheric aerosols that reflect sunlight The impact of atmospheric carbon dioxide and stratospheric aerosols can be briefly described below.

Carbon dioxide (CO₂): Carbon dioxide is a greenhouse gas that contributes to the greenhouse effect and global warming. It is released into the atmosphere through various human activities, such as the burning of fossil fuels and deforestation. The increasing concentration of CO₂ in the atmosphere is a significant driver of climate change.

Stratospheric aerosols: Stratospheric aerosols, formed by the release of particulates from volcanic eruptions or human activities, can have a cooling effect on the Earth's climate. These aerosols reflect sunlight back into space, reducing the amount of solar radiation that reaches the Earth's surface. As a result, they can temporarily offset some of the warming caused by greenhouse gases like CO2.

It's important to note that while stratospheric aerosols can have a cooling effect, they are relatively short-lived in the atmosphere compared to CO₂. Carbon dioxide, on the other hand, has a long residence time and accumulates over time, leading to long-term warming.

Therefore, the overall impact of increasing atmospheric CO₂ concentrations outweighs the cooling effect of stratospheric aerosols.

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A sample of helium had a volume of 3.20x102 mL at STP. What will be it’s new volume of the temperature is increased to 425.0k and it pressure is increased to 3.50 atm?

Answers

The new volume of the sample of helium gas as its temperature and pressure increases to the given values is 1.40×10²mL.

Combined gas law

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

Initial volume of helium gas V₁ = 3.20 × 10²mL = 0.32L

At standard remperature and pressure

Initial pressure P₁ = 1.0atmInitial temperature T₁ = 273.15K

Final pressure P₂ = 3.50atmFinal temperature T₂ = 425.0KFinal volume V₂ = ?

To calculate the new volume of the helium gas, we subtsitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

V₂ = P₁V₁T₂ / P₂T₁

V₂ = ( 1.0atm × 0.32L × 425.0K ) / ( 3.50atm × 273.15K )

V₂ = 136LatmK / 956.025atmK

V₂ = 0.14L

V₂ = 1.40×10²mL

Therefore, the new volume of the sample of helium gas as its temperature and pressure increases to the given values is 1.40×10²mL.

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What does the line with “alternating spikes and semicircles” mean?

Answers

Answer:

The line with spikes and semicircles is a stationary front, it brings days of steady rain.

Explanation:

L means Low pressure, it brings stormy weather with strong winds.

H means High pressure, it brings fair weather and light winds.

The line with spikes is a cold weather front, it brings thunderstorms and colder

temperatures.

The line with spikes and semicircles is a stationary front, it brings days of steady rain.

What does the line with alternating spikes and semicircles mean?

A student measures the molar solubility of silver carbonate in a water solution to be M. Based on her data, the solubility product constant for this compound is

Answers

A student measures the molar solubility of silver carbonate in a water solution to be 1.24 × 10⁻⁴ M. Based on her data, the solubility product constant for this compound is 7.63 × 10⁻¹² M³.

What is Stoichiometry ?

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

Silver carbonate dissociates as follows

Ag₂CO₃ (s) ⇄ 2Ag⁺ (aq) + CO₃⁻² (aq)

How to find the Solubility Product Constant ?

To find the solubility product constant use the expression

\(K_{sp} = [A^{+}]^{a} [B^{-}]^{b}\)

where

\(K_{sp}\) = Solubility product constant

A⁺ = cation in an aqueous solution

B⁻ = anion in an aqueous solution

a, b = concentration of a and b

Molar Solubility (S) = 1.24 × 10⁻⁴ M

Solubility, Ag⁺ = 2S

Solubility, CO₃⁻² = S

Put the value in above expression, we get

\(K_{sp} = [A^{+}]^{a} [B^{-}]^{b}\)

       = [Ag⁺]² [CO₃⁻²]¹

       = [2S]² [S]¹

       = 4S² × S

       = 4S³

       = 4 × ( 1.24 × 10⁻⁴ M)³

       = 7.63 × 10⁻¹² M³

       

Thus from the above conclusion we can say that A student measures the molar solubility of silver carbonate in a water solution to be 1.24 × 10⁻⁴ M. Based on her data, the solubility product constant for this compound is 7.63 × 10⁻¹² M³.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: A student measures the molar solubility of silver carbonate in a water solution to be 1.24 × 10⁻⁴ M. Based on her data, the solubility product constant for this compound is ..........

briefly describe the relationship between temperature and density of a gas

Answers

Answer:

Inversely proportional.

Explanation:

The density and temperature relationship for ideal gases is mathematically written as- Density and Temperature Relationship The density and temperature relation are proportionate. That is, the density is inversely proportional to temperature.

how is oxygen transported in the blood?multiple choice10-20% dissolved in plasma; 80-90% as oxyhemoglobin98-99% dissolved in plasma; 1-2% as oxyhemoglobin50% dissolved in plasma; 50% as oxyhemoglobin1-2% dissolved in plasma; 98-99% as oxyhemoglobin

Answers

The correct answer is A. 10-20% of oxygen is dissolved in plasma and 80-90% is transported as oxyhemoglobin in the blood.

Oxygen is transported in the blood primarily through a combination of dissolved oxygen in plasma and oxygen bound to hemoglobin within red blood cells. Approximately 10-20% of oxygen is found dissolved in plasma, while the remaining 80-90% is bound to hemoglobin in the form of oxyhemoglobin. The concentration of oxygen in plasma is determined by the partial pressure of oxygen in the environment, while the amount bound to hemoglobin is determined by the amount of hemoglobin present in the blood. Oxygen can also be transported in the form of bicarbonate and other small molecules.

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complete question: how is oxygen transported in the blood?multiple choice

A.10-20% dissolved in plasma; 80-90% as oxyhemoglobin

B.98-99% dissolved in plasma; 1-2% as oxyhemoglobin

C.50% dissolved in plasma; 50% as oxyhemoglobin

D. 1-2% dissolved in plasma; 98-99% as oxyhemoglobin

A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is a stainless-steel cylinder that measures
48.0cm
wide and
57.6cm
high. The maximum safe pressure inside the vessel has been measured to be
3.40MPa
.
For a certain reaction the vessel may contain up to
2.45kg
of carbon dioxide gas. Calculate the maximum safe operating temperature the engineer should recommend for this reaction. Write your answer in degrees Celsius. Round your answer to
3
significant digits.

Answers

The maximum safe operating temperature the engineer should recommend for this reaction is approximately 1063.77 degrees Celsius.

To calculate the maximum safe operating temperature, we need to consider the dimensions of the vessel, the maximum safe pressure, and the amount of gas inside.

First, let's convert the dimensions of the vessel from centimeters to meters:

Width = 48.0 cm = 0.48 m

Height = 57.6 cm = 0.576 m

Next, we need to calculate the volume of the vessel:

Volume = π * (radius)^2 * height

The radius of the vessel can be calculated as half of the width:

Radius = 0.48 m / 2 = 0.24 m

Volume = π * (0.24 m)^2 * 0.576 m

Volume ≈ 0.099 m^3

Now, we can use the ideal gas law to determine the maximum safe operating temperature. The ideal gas law is given by:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Rearranging the equation to solve for T:

T = (PV) / (nR)

To calculate the number of moles, we can use the molar mass of carbon dioxide (CO2):

Molar mass of CO2 = 12.01 g/mol (for carbon) + 2 * 16.00 g/mol (for oxygen)

Molar mass of CO2 ≈ 44.01 g/mol

Converting the mass of carbon dioxide from kilograms to grams:

Mass of CO2 = 2.45 kg * 1000 g/kg

Mass of CO2 = 2450 g

Now, we can calculate the number of moles:

Number of moles = Mass of CO2 / Molar mass of CO2

Number of moles = 2450 g / 44.01 g/mol

Number of moles ≈ 55.67 mol

The gas constant R is approximately 8.314 J/(mol·K).

Now, we can substitute the values into the equation:

T = (3.40 MPa * 0.099 m^3) / (55.67 mol * 8.314 J/(mol·K))

T ≈ 1063.77 K

Converting from Kelvin to Celsius:

T ≈ 1063.77 °C

The maximum safe operating temperature that the engineer should recommend for this reaction is approximately 1063.77 degrees Celsius.

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Use the reaction to answer the question.
Zn + 2HCI - ZnCl2 + H2
Which type of reaction is this?
(1 point)
o electronegative
O replacement
combustion
O ionic

Answers

Answer:

i think its replacement

Explanation:

By definition, the correct answer is the second option: the reaction is a replacement.

A simple substitution reaction or simple displacement reaction, called single-displacement reaction, is a reaction in which an element of a compound is substituted by another element involved in the reaction.

The starting materials are always pure elements and an aqueous compound. And a new pure aqueous compound and a different pure element are generated as products.

The general form of a simple substitution reaction is:

AB + C → A +BC

where C and A are pure elements; C replaces A within compound AB to form a new co, placed CB and elementary A.

A single-displacement reaction is characterized by a place of exchange of cations or anions with another to form a new product. A begins as an ion in the solution and appears elementally in the reaction products. In case of reagent C it starts in its elemental form and ends as an ion in an aqueous state forming compound BC.

In this case, it is a single replacement reaction where 1 atom of Zinc metal displaces 2 H⁺ ions from the hydrochloric acid to form hydrogen gas and zinc chloride, a salt.

Finally, the correct answer is the second option: the reaction is a replacement.

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1. What subatomic particle determines the charge of an atomA. protonsB. electronsC. neutronsD. all of the above

Answers

Answer:

Electric Charge in the Atom. Atoms contain negatively charged electrons and positively charged protons; the number of each determines the atom's net charge.

Explanation:

A bottle is filled with a small amount of a volatile liquid and sealed. Sometime later it is observed that no liquid is evident in the sealed bottle. Which of the following statements would explain this observation? a. More time is needed to establish equilibrium. b. Liquid and vapor are at equilibrium in the bottle. c. Too little liquid was added to achieve a liquid vapor equilibrium in the closed system d. The vapor state is favored when equilibrium is established e. The liquid has undergone sublimation

Answers

The statement that would best explain the observation of no liquid being evident in the sealed bottle is: b. Liquid and vapor are at equilibrium in the bottle.

When liquid and vapor are at equilibrium in a closed system, it means that the rate of condensation (liquid turning into vapor) is equal to the rate of vaporization (vapor turning into liquid). In this case, it appears that all the liquid has vaporized, and no liquid is evident. This suggests that the liquid and vapor have reached a state of equilibrium, where the amount of liquid remaining is negligible compared to the amount of vapor present.

The vapor state is favored when equilibrium is established because the pressure exerted by the vapor phase reaches a point where it equals the vapor pressure of the liquid at that temperature. At this equilibrium point, no further net condensation or vaporization occurs, resulting in the absence of visible liquid in the sealed bottle.


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I NEED HELP
Can an element be a molecule?

Answers

Answer:

Not quite, they are different catagories.

Explanation:

A molecule is two or more atoms connected to each other. An element is an atom with a name. Think of water, a single water molecule is called H2O because it has two hydrogen atoms and one oxygen atom. Hydrogen and oxygen are both elements. Another way to see it is like, there are many kinds of animals(atoms). A specific animal would be a cat or a bird or something(the elements).

TLDR: An element can be part of a molecule, but is not one on its own.

How many grams of AlCl3 are needed to completely react with 2.25 of NaOH?

Answers

Explanation:

hope the picture above help u understand I did it in step so it would be easier to understand:)

How many grams of AlCl3 are needed to completely react with 2.25 of NaOH?
How many grams of AlCl3 are needed to completely react with 2.25 of NaOH?

The molarity of 8 grams of an aqueous solution of sodium hydroxide in 2 liters of solution is what?​

Answers

Answer: 0.125

Explanation:

8g divided by 39.997. Then divide that answer by 2.

Answer:

0.1 M

Explanation:

Please help me with my Chemistry homework!! I have so much homework to do for other classes and I’m so stressed so even answering one question would be amazing!!!

1. A graduated cylinder had an initial volume of water of 22 mL. After an iron nail is dropped into the cylinder, the water rises to 38 mL. What is the volume of the nail?

2. Ms.Chavez dropped a gold ring into a graduated cylinder filled with water. The water level was originally at 20 mL. Now the water is at 25mL. Ms.Chavez knows that means the volume of the ring is 5 mL. What else would she have to do to find the density of her ring? Explain.

3. A simple of liquid propanol has a volume of 20.0 cm*^3 and a mass of 15.0 g. What is the density of propanol? Write only your answer below.

Answers

1. 16 mL

2. She need to find the mass, as density is mass divided by volume.

3. 0.75 g/cm^3

What is the approximate tangential speed of an object orbiting earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s? 7.7 × 10–4 m/s 5.1 × 104 m/s 7.7 × 104 m/s 5.1 × 105 m/s

Answers

This question involves the concepts of time period and tangential speed.

The tangential speed of the object is "5.1 x 10⁴ m/s".

What is the time period?

The following formula gives the time period of the object:

\(T=\frac{2\pi}{\omega}\\\\\)

\(\omega = \frac{2\pi}{T}\)

where,

\(\omega\) = angular speed = ?T = time period = 2.2 x 10⁴ s

Therefore,

\(\omega=\frac{2\pi}{2.2\ x\ 10^4\ s}\\\\\omega=2.86\ x\ 10^{-4}\ rad/s\)

Now, the tangential speed can be given by the following formula:

\(v=r\omega\)

where,

r = radius = 1.8 x 10⁸ mv = tangential speed = ?

Therefore,

\(v=(1.8\ x\ 10^8\ m)(2.86\ x\ 10^{-4}\ rad/s)\)

v = 5.1 x 10⁴ m/s

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Answer: 5.1 x 10⁴ m/s

Explanation:

edge 2023

IF YOU COME THEN YOU WILL GET BRAINLIEST HURRY!!!!
Describe how wind, water, ice and gravity move soil through erosion below.

Answers

Answer:

It's big brain time

Explanation:

Weathering is the process of breaking rocks into sediment while erosion is the process that wears away this sediment and other materials and moves them from one location to another.  Agents of erosion include gravity, glaciers, wind, and water.  Erosion only occurs when these agents have enough energy.  The moment agents of erosion lose their energy and momentum they deposit their load.  This process is known as deposition.  The load is what the agent is carrying.  As agents of weathering lose their energy, the heavier sediment is dropped.  As the energy is lost, gravel, then sand, then silt, and then clay are deposited, due to their respective masses.

Mass movement, sometimes referred to as mass wasting, is what we call the movement of surface material due to gravity, water, wind, and ice.  There are five main types of mass movements: falls, creep, flows, slides, and slump.

How many isomers are there in C7H16 ?

a. 6
b. 7
c. 8
d. 9​

Answers

the correct answer is 9 .

How many grams of nicotine (C10H14N2) are in a 0.125 mol sample of nicotine?

Answers

Taking into account the molar mass of the compound, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.

In first place, you have to know that molar mass is a physical property that is defined as the mass of a mole of a substance, which can be an element or a compound.

In a compound the molar mass is equal to the sum of the weight or atomic mass of its atoms multiplied by the quantity of each atom.

In the periodic table, it is possible to find the molar mass of the elements, also called atomic mass or atomic weight.

The molar mass of the elements, in this case, are:

C= 12 g/moleH=  1 g/moleN= 14 g/mole

So, the molar mass of the compound is:

C₁₀H₁₄N₂= 10× (12 g/mole) + 14× (1 g/mole) + 2× (14 g/mole)

C₁₀H₁₄N₂=  162 g/mole

Then you can apply the following rule of three: if 1 mole of nicotine contains 162 g of the compound, 0.125 moles contains how much mass?

\(mass=\frac{0.125 molesx162 grams}{1 mole}\)

Solving:

mass= 20.25 grams

In summary, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.

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Charles's law describes the relationship of the volume and temperature of
gas at a constant mass and pressure. According to this law, what would
happen to the volume of the gas if its temperature increased from 150 K to
300 K?

A. The volume would increase from 150 mL to 300 mL.
B. The volume would be reduced by half.
C. The volume would decrease by 150 mL.
D. The volume would double.

Answers

Answer:

Charles's law is: When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion. So the volume would increase

Help me out here please???

Help me out here please???

Answers

Answer:

A

Explanation:

Answer:

B

Explanation:

In a chemical reaction, the number of each element should be equal on both the reactant and product side.

Given the standard enthalpy changes for the following two reactions
Given the standard enthalpy changes for the following two reactions:



(1) 2C(s) + 2H2(g)C2H4(g)...... ΔH° = 52.3 kJ



(2) 2C(s) + 3H2(g)C2H6(g)......ΔH° = -84.7 kJ



what is the standard enthalpy change for the reaction:



(3) C2H4(g) + H2(g)C2H6(g)......ΔH° = ?

Answers

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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The equilibrium constant of a reaction requires certain environmental variables to remain constant. These variables are _____.

pressure, temperature, and concentration

temperature and concentration

pressure, temperature, and time

None of the above.

Answers

The equilibrium constant of a reaction requires certain environmental variables to remain constant. These variables are pressure, temperature, and concentration. The correct option is A.

An equilibrium constant is a mathematical tool that enables the quantification of the extent of a chemical reaction. The equilibrium constant is symbolized by Keq, and it is utilized to determine the concentration of reactants and products present at equilibrium.

                           This calculation is done using the law of mass action.Keq is defined as the ratio of product concentrations to reactant concentrations in a chemical reaction taking place at equilibrium. The concentrations used in the expression for Keq are equilibrium concentrations.

                                 As a result, Keq is a constant for a given reaction at a specific temperature. Keq is dependent on a variety of environmental variables such as temperature, pressure, and concentration. To keep the equilibrium constant stable, these variables must remain constant.

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26. Synthesize Why does examining population size,
density, and distribution together give you a bet-
ter understanding of a population than looking at
these characteristics separately?

Answers

Examining population size, density, and distribution together give you a better understanding of a population than looking at these characteristics separately because these variables play a role in how the ecosystem adjusts to the growing population.

What is population density, and how does it work?

The average population size per unit of area or volume is known as population density. A colony of 100 insects, for instance, has a density of 1 insect per square meter and occupies an area of 100 square meters.

Numerous creatures' location, development, and migration can all be described using population density. The share of residents by different regions of a country is known as the national population distribution. The quantity of people within a broadly defined geographic area is referred to as the population size.

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Rank these transition metal ions in order of decreasing number of unpaired electrons. If two ions have the same number of unpaired electrons



Fe^3 , Mn^4+ , V3+ , Ni^2+ , Cu^+

Answers

Answer: \(Fe^{3+} > Mn^{4+}\) > \(V^{3+}\) = \(Ni^{2+}\) > \(Cu^+\)

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

Fe: 26: \(1s^2s^22p^63s^23p^64s^23d^{6}\)

\(Fe^{3+}:23:1s^2s^22p^63s^23p^63d^{5}\) : 5 unpaired electrons

Mn: 25: \(1s^2s^22p^63s^23p^64s^23d^{5}\)

\(Mn^{4+}:23:1s^2s^22p^63s^23p^63d^{3}\) : 3 unpaired electrons

V: 23: \(1s^2s^22p^63s^23p^64s^23d^{3}\)

\(V^{3+}:23:1s^2s^22p^63s^23p^63d^{2}\) : 2 unpaired electrons

Ni : 28 : \(1s^2s^22p^63s^23p^64s^23d^{8}\)

\(Ni^{2+}:23:1s^2s^22p^63s^23p^63d^{8}\): 2 unpiared electrons

Cu : 29 : \(1s^2s^22p^63s^23p^64s^13d^{10}\)

\(Cu^{+}:23:1s^2s^22p^63s^23p^63d^{10}\): 0 unpaired electrons

Thus the order of decreasing number of unpaired electrons:

\(Fe^{3+} > Mn^{4+}\) > \(V^{3+}\) = \(Ni^{2+}\) > \(Cu^+\)

The more electronegative atom in a covalent bond will: * 1 point become an anion become a cation have a partial positive charge have a partial negative charge

Answers

Answer:

The correct option is have a partial negative charge

Explanation:

Since electronegativity can be described as the measure of the tendency of atom to attract electrons towards itself, the more electronegative atom in a covalent bond will have a partial negative charge. This is because, in covalent bond, there is sharing of electrons between participating atoms, the atom that has a higher electronegativity tends to attract the shared electrons towards itself making it slightly negative charge.

NOTE: The negative charge is partial and thus is not represented while drawing a covalent bonding diagram as this could be misinterpreted to mean an electrovalent bond if the charge is indicated.

When 25.0 g O2 (g) is burned according to the following reaction, 1,600.0 kJ energy is released. Find the value of ∆Hrxn.

4 NH3 (g) + 5 O2 (g) --> 4 NO (g) + 6 H2O (ℓ)

Answers

The enthalpy of the reaction is  10256 kJ/mol

What is the enthalpy of the reaction?

Enthalpy is a thermodynamic property that is used to describe the heat energy involved in a chemical reaction. The enthalpy change of a reaction, also known as ΔH, is defined as the difference between the enthalpy of the products and the enthalpy of the reactants.

Number of moles of oxygen = 25.0 g /32 g/mol

= 0.78 moles

If 0.78 moles of O2 produced 1,600.0 kJ

5 moles of O2 will produce 5 * 1,600.0/0.78

= 10256 kJ

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there are two benzylic bromides that give (e)-3,5-dimethyl-2-phenyl-2-hexene on e2 elimination. draw them.

Answers

The structures of the two benzylic bromides: 1. 1-Bromo-3,5-dimethyl-2-phenylhexane: This compound has the bromine atom at the 1st carbon, adjacent to the phenyl group. 2. 2-Bromo-3,5-dimethyl-2-phenylhexane: In this compound, the bromine atom is located at the 2nd carbon, next to the phenyl group and the methyl group at the 3rd carbon. Both of these benzylic bromides will undergo E2 elimination to give the desired product, (E)-3,5-dimethyl-2-phenyl-2-hexene.

Sure, the two benzylic bromides that give (e)-3,5-dimethyl-2-phenyl-2-hexene on E2 elimination are:

1. 1-bromo-3,5-dimethylbenzene
  CH3    Br
     \  /
      C-C
     /  \
  CH3   Ph
  The E2 elimination of the bromine and a proton on the carbon adjacent to the benzene ring leads to the formation of (e)-3,5-dimethyl-2-phenyl-2-hexene.

2. 4-bromo-1,3-dimethylbenzene
  CH3     Br
     \   /
      C-C
     /   \
  CH3   Ph
  Similar to the first example, the E2 elimination of the bromine and a proton on the carbon adjacent to the benzene ring leads to the formation of (e)-3,5-dimethyl-2-phenyl-2-hexene.

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The structures of the two benzylic bromides: 1. 1-Bromo-3,5-dimethyl-2-phenylhexane: This compound has the bromine atom at the 1st carbon, adjacent to the phenyl group. 2. 2-Bromo-3,5-dimethyl-2-phenylhexane: In this compound, the bromine atom is located at the 2nd carbon, next to the phenyl group and the methyl group at the 3rd carbon. Both of these benzylic bromides will undergo E2 elimination to give the desired product, (E)-3,5-dimethyl-2-phenyl-2-hexene.

Sure, the two benzylic bromides that give (e)-3,5-dimethyl-2-phenyl-2-hexene on E2 elimination are:

1. 1-bromo-3,5-dimethylbenzene
  CH3    Br
     \  /
      C-C
     /  \
  CH3   Ph
  The E2 elimination of the bromine and a proton on the carbon adjacent to the benzene ring leads to the formation of (e)-3,5-dimethyl-2-phenyl-2-hexene.

2. 4-bromo-1,3-dimethylbenzene
  CH3     Br
     \   /
      C-C
     /   \
  CH3   Ph
  Similar to the first example, the E2 elimination of the bromine and a proton on the carbon adjacent to the benzene ring leads to the formation of (e)-3,5-dimethyl-2-phenyl-2-hexene.

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