In a sack of marbles there are red marbles each weighing 11.50g and green marbles which each weighing 12.70g. There are 10,051 red marbles and 24,351 green marbles. Determine the mass of the average marble in the sack. (Explain why the answer is not equal to (11.50 + 12.70) / 2 = 12.10g .

The redox reactions is balanced as by adding coefficients as follows:2 H+ +ClO²⁻+I⁻⟶2 Cl⁻+H₂O+I₂.

Redox reactions comprise of two parts a reduced part and an oxidized part, which occur simultaneously . The part which is reduced gain electrons and hence there is a increase in oxidation state of the species.

While, the part which is oxidized looses electrons and hence there is a decrease in oxidation state of the species.During redox reactions, there is no net change in the number of electrons . Electrons which are given off in oxidation are used up in reduction.These too are balanced by adding coefficients.

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The density, in g/L, of an ideal gas when it is at 1.48 atm and 94.06 °C is 6.67g/L.

The density of an ideal gas can be calculated by dividing the mass of the substance by its volume in litres.

According to this question, the pressure and temperature of the ideal gas is given. The number of moles occupied by the gas can be calculated as follows;

PV = nRT

1.48 × 22.4 = n × 0.0821 × 367.06

33.152 = 30.14n

n = 1.1 moles

mass of gas = 1.1 mol × 145.63g/mol = 160.18g

Density = 160.18g ÷ 22.4L = 6.67g/L

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Ionic bonds are bonds that occur due to the handover of electrons to form positive ions and negative ions whose electron configuration is the same as that of the noble gasses.

Chemical bonds are the forces that hold atoms in elements and compounds together. Chemical bonds can occur with several types of bonds.

Based on the electron configuration that occurs in bond formation, chemical bonds are divided into 4 types:

1. Ionic or electrovalent bonds

This bond occurs because of the electrostatic attraction between positive ions and negative ions in a chemical compound

2. Covalent bonds

Covalent bonds occur when the sharing of electron pairs from each of the bonding atoms.

3. Coordinate covalent bond

Coordinate covalent bond is a bond that uses a shared pair of electrons, but the electrons only come from one of the atoms.

4. Metallic bond

This bond is formed due to the attractive force of the metal atomic nucleus with a sea of electrons.

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Answer:

different from ionic or covalent bonding

Explanation:

The concentration of Helium gas in the solution is 1.5 parts per million (ppm).

First, we need to convert the mass of helium gas to grams:

3.0 x 10⁻⁴g = 0.0003g

Next, we need to find the total mass of the solution:

Total mass of solution = mass of solvent + mass of solute

Since Helium gas is dissolved in the solvent, we can assume that its mass is negligible compared to the mass of the solvent. Therefore, we can use the mass of the solvent (200 g) as the total mass of the solution.

Now we can calculate the concentration of helium gas in ppm:

Concentration (in ppm) = (mass of solute / total mass of solution) x 10^6

Concentration = (0.0003 g / 200 g) x 10^6

Concentration = 1.5 ppm

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The compound has an empirical formula of \(K_2H_2P_2O_8\) and a molecular formula of \(K_2HPO_4\).

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The correct question would be as

The composition of a compound is 28.73% K. 1.48% H, 22.76% P, and 47.03% O. The molar mass of the compound is 136.1 g/mol. What is the Molecular Formula of the compound?

\(KH_2PO_4\\KH_3PO_4\\K_2H_4P_20_{12}\\K_2H_3PO_6\)

Answer:

75.9 KPa

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) 20000 L

Initial pressure (P1) = 748 kPa

Initial temperature (T1) = 525 K

New temperature (T2) = 293 K

New volume (V2) = 110000 L

New pressure (P2) =?

The new pressure pressure of the gas can be obtained by using the general gas formula as illustrated below:

P1V1 / T1 = P2V2 / T2

748 × 20000 / 525 = P2 × 110000 / 293

14960000 / 525 = P2 × 110000 / 293

Cross multiply

P2 × 110000 × 525 = 14960000 × 293

P2 × 57750000 = 4383280000

Divide both side by 57750000

P2 = 4383280000 / 57750000

P2 = 75.9 KPa

Thus, the new pressure of the gas is 75.9 KPa

Acceleration is the change in velocity from the time he starts pushing to when he stops.

Velocity narrates how position changes, acceleration relates to how velocity changes. We can use this formula to answer velocity for the acceleration of the table Aston pushes a table across the floor with a force of 6 N. Assume the table has a mass of 6 kg and he pushes the table for 2 seconds. they may source of motion; they may also slow, stop, or velocity changes the path of an object at a time, and the forces can push or pull in any direction.

So we can conclude that At end velocity, the speed is not changing. If the speed is not changing, there is no force on the stage on the falling object or the forces acting on it are in.

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Answer:

Compounds From Decaying Matter.

Explanation:

A long time ago, when these were compounds in the ground. They were under lots of pressure, and then they turned into coal/diamonds.

Answer:

Mass of Nacl = 4.92 gram (Approx)

Explanation:

Given:

Hydrochloric acid = 3.3 g

Sodium hydroxide = 5 g

Computation:

Hcl + NaoH ⇒ Nacl + H₂O

Number of mole of Hcl = 3.3 / 36.46 = 0.0905 moles

Number of mole of NaoH = 5 / 40 = 0.125 moles

We, know that number of moles in Hcl is less then number of mole in NaoH

So,

Number of mole of Hcl = Number of mole of Nacl

So,

Mass of Nacl = Number of mole of Nacl × Molar mass of Nacl

Mass of Nacl = 0.0905 × 54.4

Mass of Nacl = 4.92 gram (Approx)

Honestly, its based on your preference but the best recommended one would be loam. I use loam too, and it is really good for growing the plants.

:)

The law of multiple proportion account for subscripts in chemical formulas (option A).

The law of multiple proportion states that when two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.

For example, nitrogen dioxide and nitrogen tetroxide have nitrogen to oxygen ratios of 1:2 and 1:4.

This suggests that the law of multiple proportion addresses the subscripts in chemical formulas.

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Answer:

○ Subscripts in chemical formulas

Explanation:

The theoretical yield of the reaction is 1.13 g. The acid is the limiting reactant.

In a given chemical reaction, the theoretical yield can only be obtained from the balanced reaction equation. We have been given the balanced reaction equation in the question so we can work from there.

Number of moles of Cr =  0.50 g /52 g/mol = 9.6 * 10^-3 moles

Number of moles of acid =  0.75 g/98 g/mol = 7.7 * 10^-3 moles

Given that the reaction is 1:1, the limiting reactant would be the acid.

The theoretical yield is obtained from;

Number of moles of product * molar mass of product

We substitute to obtain;

7.7 * 10^-3 moles * 147 g/mole (since the reaction is 1:1)

= 1.13 g

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Answer:

A. Carbon dioxide, oxygen

Explanation:

Like plants, trees go through photosynthesis to produce their energy. They consume water and sunlight as well as carbon dioxide to produce oxygen and glucose.

If you traded (converted) 15 Skittles for M&Ms, you will have 20 M&Ms

We'll begin by converting 15 Skittles to cookies. This can be obtained as follow:

6 Skittles = 4 Cookies

Therefore,

15 Skittles = (15 Skittles × 4 cookies) / 6 skittles

15 Skittles = 10 cookies

We can convert 10 cookies to M&Ms as follow:

1 Cookies = 2 M&Ms

Therefore,

10 cookies = (10 cookies × 2 M&Ms) / 1 Cookies

10 cookies = 20 M&Ms

Thus, 15 Skittles is equivalent to 20 M&Ms

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Answer:

0.07 M

Explanation:

Given data:

Volume of NaOH = 50.0 mL

Molarity of NaOH = 0.2 M

Volume of H₃PO₄ =  50.0 mL

Concentration of H₃PO₄ = ?

Solution:

3NaOH + H₃PO₄    →   Na₃PO₄  +  3H₂O

Number of moles of NaOH react:

Molarity = number of moles / volume in L

0.2 M = number of moles = 0.05 L

Number of moles = 0.01 mol

Now we will compare the moles of NaOH  with  H₃PO₄ .

          NaOH        :       H₃PO₄

             3             :          1

           0.01          :       1/3×0.01 = 0.0033

Concentration of H₃PO₄:

Molarity = number of moles / volume in L

Molarity = 0.0033 mol / 0.05 L

Molarity = 0.07 M

Answer:

A.) 0.07M

Explanation:

I got it right in class!

Hope this Helps!! :))

The final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.

To determine the final concentration of I ions in the resulting solution, we need to consider the stoichiometry and volumes of the solutions being mixed.Given:

Volume of NH4l solution = 129.13 mL

Concentration of NH4l solution = 112.9 mM = 0.1129 M (converting from millimolar to molar)

Volume of Mgl2 solution = 105.31 mL

Concentration of Mgl2 solution = 0.87 M

First, we need to determine the moles of NH4l and Mgl2 in their respective solutions:

Moles of NH4l = Volume of NH4l solution * Concentration of NH4l solution

Moles of NH4l = 0.12913 L * 0.1129 M = 0.01459 moles NH4l

Moles of Mgl2 = Volume of Mgl2 solution * Concentration of Mgl2 solution

Moles of Mgl2 = 0.10531 L * 0.87 M = 0.09157 moles Mgl2

Next, we determine the limiting reagent, which is the reactant that is completely consumed and determines the maximum amount of product formed. In this case, the limiting reagent is NH4l because it has fewer moles than Mgl2.

The balanced chemical equation for the reaction between NH4l and Mgl2 is:

2 NH4l + Mgl2 → 2 NH4+ + MgI2

From the balanced equation, we can see that for every 2 moles of NH4l, we get 1 mole of MgI2.

Since the moles of NH4l is the limiting reagent, it will be completely consumed, and the moles of MgI2 formed will be half of the moles of NH4l.

Moles of MgI2 = 0.01459 moles NH4l * (1 mole MgI2 / 2 moles NH4l) = 0.007295 moles MgI2

Finally, we calculate the final concentration of I ions in the resulting solution:

Volume of resulting solution = Volume of NH4l solution + Volume of Mgl2 solution

Volume of resulting solution = 0.12913 L + 0.10531 L = 0.23444 L

Final concentration of I ions = Moles of MgI2 / Volume of resulting solution

Final concentration of I ions = 0.007295 moles / 0.23444 L = 0.0311 M

Therefore, the final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.

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Answer:

NaOH is the limiting reactant.

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write out the chemical reaction between NaOH and HCl:

\(NaOH+HCl\rightarrow NaCl+H_2O\)

Thus, since they react in a 1:1 mole ratio; we can now calculate the moles of each substance by using their volumes and molarities:

\(n_{NaOH}=0.0250L*0.81mol/L=0.02025molNaOH\\\\n_{HCl}=0.0650L*0.33mol/L=0.02145molHCl\)

Now, since NaOH is in a fewer proportion, we infer just 0.02025 moles of HCl are consumed so that 0.0012 moles of this acid remain unreacted; in such a way, we infer that the NaOH is the limiting reactant for this reaction.

Regards!

Answer:

Explanation:

Aniline is an organic compound with the formula C6H5NH2. Consisting of a phenyl group attached to an amino group, aniline is the simplest aromatic amine.

Answer:

Wadding is a disc of material used in guns to seal gas behind a projectile or to separate powder from shot. ... Wadding for muzzleloaders is typically a small piece of cloth, or paper wrapping from the cartridge.

Explanation:

To balance the equation it is necessary to have the same number of atoms of each element on both sides of the equation (reactant side and product side). Let's count the number of atoms of each element for the unbalanced equation:

__Cu(OH) + __H2CO3 --> __Cu2CO3 + _H2O

Reactant side:

Cu - 1

O - 4

H - 3

C - 1

Product side:

Cu - 2

O - 4

H - 2

C - 1

As it is an acid and base reaction, there is a trick to balance the reaction faster. We use the quantity of atoms of the cation of the salt on the products side as stoichiometric coefficient of the hydroxide and the quantity of the anion of the salt as stoichiometric coefficient of the acid.

In this case, the salt is:

Cu2CO3

So we have 2 cations and 1 anion.

So the coefficient of the hydroxide will be 2 and for the acid will be 1:

2 Cu(OH) + 1 H2CO3 --> __Cu2CO3 + _H2O

The coefficient of the salt will be 1 and for the water (H2O) is the coefficient of the acid multiplied by the coefficient of the acid (2x1 = 2):

2 Cu(OH) + 1 H2CO3 --> 1 Cu2CO3 + 2 H2O

To make sure that everything is right, let's count the number of atoms of each element for the balanced equation.

Reactant side:

Cu - 2

O - 5

H - 2

C - 1

Product side:

Cu - 2

O - 5

H - 2

C - 1

Now the equation is balanced.

Answer: 2 Cu(OH) + 1 H2CO3 --> 1 Cu2CO3 + 2 H2O

The coefficients are: 2, 1, 1, 2.

The instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

To find the instantaneous rate of reaction at 17 minutes, we can use the concept of differential calculus and estimate the slope of the tangent line at t=17 on the graph of rate versus time.

To do this, we can use the formula for the slope of a line

slope = (change in y) / (change in x)

In this case, the "y" values are the rates of reaction and the "x" values are the times. We want to find the slope at t=17, so we can choose two points that are very close to t=17, such as t=15 and t=20. Then, we can use these values to estimate the slope at t=17

slope = (rate at 20 min - rate at 15 min) / (20 min - 15 min)

slope = (0.135 - 0.223) / (20 - 15)

slope = -0.178

This slope represents the instantaneous rate of reaction at t=17. However, since it has a negative value, it means that the rate of reaction is decreasing at t=17.

Therefore, the instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

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Answer:

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The molarity of the final solution is 1.00 M.

The molarity of the final solution when a student dissolved 36.8 grams of KF into 1.2 L of water is 1.00 M.Molarity is a unit of concentration that measures the amount of a solute present in a solution. Molarity is defined as the number of moles of solute per liter of solution.

The formula for molarity is given as;Molarity (M) = moles of solute / liters of solution.The following steps should be followed to calculate the molarity of a solution:Convert the mass of the solute to moles using its molar mass.Divide the number of moles of solute by the volume of the solution in liters.

The volume of the solution in liters can be measured in any units (mL, L, etc.).

Example:A student dissolved 36.8 grams of KF into 1.2 L of water.

Mass of KF = 36.8 gMolar mass of KF = 58.1 g/mol

Number of moles of KF = mass / molar mass= 36.8 / 58.1= 0.632 M

Divide the number of moles of solute by the volume of the solution in liters= 0.632 M / 0.6 L= 1.00 M

Therefore, the molarity of the final solution is 1.00 M.

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Answer:

1.45 Atmospheres = 146.92125 Kilopascals, or about 146.9 Kilopascals

Explanation:

1 Atmosphere = 101.325 Kilopascals, so 101.325 Kilopascals x 1.45 Atmospheres = 146.92125 Kilopascals.

Using the conversion table, the pressure of the compressed gas at 1.45 atm when converted to kilopascal becomes 146.92 kPa.

Atm is the standard atmosphere which is a unit of pressure.

From conversion table

1 atm atmospheric pressure is equivalent to 101.325 kPa ( kilopascal ).

Now, the pressure of the compressed gas at 1.45 atm will be;

P = 1.45 × 101.325 kPa

P = 146.92 kPa

Therefore, the pressure of the compressed gas at 1.45 atm when converted to kilopascal using the conversion table becomes 146.92 kPa.

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Answer:

A) Using the ideal gas law, we can calculate the number of moles of gas present:

```

PV = nRT

```

where:

* P = pressure (atm) = 1 atm

* V = volume (L) = 5.6 L

* n = number of moles of gas

* R = ideal gas constant = 0.08206 L atm / mol K

* T = temperature (K) = 273.15 K

Solving for n, we get:

```

n = (P * V) / RT

```

```

n = (1 atm * 5.6 L) / (0.08206 L atm / mol K * 273.15 K)

```

```

n = 0.25 mol

```

Therefore, there are 0.25 moles of gas present.

B) The molar mass of the gas can be calculated by dividing the mass of the gas (8.0 g) by the number of moles of gas (0.25 mol):

```

Molar mass = Mass / n

```

```

Molar mass = 8.0 g / 0.25 mol

```

```

Molar mass = 32 g/mol

```

The molar mass of the gas is 32 g/mol.

C) The common atmospheric gas with a molar mass of 32 g/mol is oxygen (O2). Therefore, the gas that was collected is oxygen.

Explanation: