In a survey of 331 registered voters, 158 of them wished to see Mayor Waffleskate lose her next election Find a point estimate for the proportion of registered voters who wish to see Mayor Wamekate defeated.
a 158 b 0.5227 c 0.4773 d 0.02745

Answer:

a) 45/2,25=20 km per hour

b) 45 minutes

c) 45/3=15 km per hour

THIS IS THE COMPLETE QUESTION BELOW;

young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He started at 909090 kilograms and gained weight at a constant rate. After 888 months, he weighed 138138138 kilograms. Let W(t)W(t)W, left parenthesis, t, right parenthesis denote the sumo wrestler's weight WWW (measured in kilograms) as a function of time ttt (measured in months). Write the function's formula.

Answer:

W=6t+90

Step-by-step explanation:

We know that a linear equation in slope takes the form

y= mx+ c

where

m is the slope

c is the y-coordinate of the y-intercept

Let us denote W as the sumo weight in kg then

t as the time in months

Then forming a linear equation from this knowing t is a dependent variable then

W(t)= mt+90

But here we know that is our slope, W was given as 138kg and t is 8 months.

We we substitute this values in the equation we have

138= 8m+90

8m= 138-90

8m=48

m=6kg/month

Therefore, the function formula is W(t)= 6t+90

Given data:

The length of the wire is l= 50 foot.

The given base length is b= 35 feet.

The expression for the height of the antena is,

Substitute the given values in the above expression.

Thus, the height of the antena is 36 ft.

Answer:

3x^3 - 11x^2 + 93x - 105

Step-by-step explanation:

(x+5) (x-9) (x+1) (3) FOIL (First, Outside, Inside, Last)...

x^2 - 9x + 5x - 35 (3x+3) Multiply

3x^3 + 3x^2 - 27x^2 - 27x + 15x^2 + 15x - 105x - 105 Combine Like Terms...

3x^3 - 11x^2 + 93x - 105

To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure.

Assume that G is not a PRG, which means it fails to expand the seed sufficiently. Let's suppose that G is computationally indistinguishable from a truly random function on its domain, but it does not meet the requirements of a PRG.

Now, consider the private-key encryption scheme Π described in Construction 3.17 using G as the pseudorandom generator. If G is not a PRG, it means that its output is not sufficiently pseudorandom and can potentially be distinguished from a random string.

Given this scenario, an adversary A could exploit the distinguishability of G's output and devise an attack to break the security of the encryption scheme Π. The adversary could potentially gain information about the plaintext by analyzing the ciphertext and the output of G.

Therefore, if G is not a PRG, it implies that Construction 3.17 cannot provide EAV-security, as it would be vulnerable to attacks by distinguishing the output of G from random strings. This contradicts Theorem 3.18, which states that if G is a PRG, then Construction 3.17 achieves indistinguishable encryptions.

Hence, by proving the opposite, we conclude that if G is not a PRG, then Construction 3.17 cannot be EAV-secure.

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Option (A) Names of TV shows taped in New York are an example of qualitative data. Qualitative data is descriptive in nature and does not involve numerical values or measurements.

It deals with qualities or attributes that cannot be expressed numerically. In this case, the names of TV shows are characteristics that describe the nature of the data. Quantitative data, on the other hand, is numerical data that can be measured and expressed in numbers. A parameter is a measurable factor or variable that can be used to define a system, while statistics is a branch of mathematics that deals with data collection, analysis, and interpretation. In conclusion, since the names of TV shows are descriptive in nature and do not involve numerical values, they are an example of qualitative data.

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Answer:

The third option (9+\(3\sqrt{7}\)-\(3\sqrt{7}\)-\(\sqrt{49}\))

Step-by-step explanation:

With FOIL, this can be expanded. (a+b)(a-b) is equal to a²+ab-ab-b² or a²-b².

In this case, all the answers have 4 terms, so we want the first option. This makes the equation 3²+(3×\(\sqrt{7}\))-(3×\(\sqrt{7}\))-(\(\sqrt{7}\))².

Solving these gives 9+\(3\sqrt{7}\)-\(3\sqrt{7}\)-7. This is the same as  9+\(3\sqrt{7}\)-\(3\sqrt{7}\)-\(\sqrt{49}\).

**This content involves multiplying with surds and expanding perfect squares, which you may wish to revise. I'm always happy to help!

The equivalent expression is (c) \(9 - 3\sqrt 7 + 3\sqrt 7 - \sqrt {49}\)

The difference of squares equation is given as:

\((a + b)(a - b) = a^2 -b^2\)

And the radical expression is given as:

\( (3+ \sqrt 7)(3- \sqrt7)\)

By comparing the above expression to \((a + b)(a - b) = a^2 -b^2\), we have:

\(a =3\)

\(b = \sqrt 7\)

Substitute these values in \((a + b)(a - b) = a^2 -b^2\)

\( (3+ \sqrt 7)(3- \sqrt7) = 3^2 - (\sqrt 7)^2\)

This gives

\( (3+ \sqrt 7)(3- \sqrt7) = 9 - \sqrt {49}\)

By complete expansion, we have:

\( (3+ \sqrt 7)(3- \sqrt7) = 9 - 3\sqrt 7 + 3\sqrt 7 - \sqrt {49}\)

Hence, the equivalent expression is (c)

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Answer:

b=180°-69° (adj angles on a str line)

=111°

Answer:

0.01

Step-by-step explanation:

because the tax is 10%, you multiply by 0.01 to find the total.

Answer:

A) 200 N 1.4 m 40 kg.

Step-by-step explanation:

I hope this is correct, if it is im glad to be of help.

Answer:

2(l+b ) is the answer

Step-by-step explanation:

ok mark me as markliest

Based on the information provided, it appears that Sammi did not make any mistakes in creating the tally chart. The information appears to be correctly recorded and organized.

To create a dot plot, Sammi would simply plot a dot above the appropriate number on the number line for each entry in the "hours" column and mark it the number of times specified in the corresponding entry in the "tally" column.

The answer was determined based on the information provided in the question, which was a 2-column table with 4 rows. The first column was labeled "hours" and had entries of 3, 4, 5, 6. The second column was labeled "tally" and had entries of 4, 6, 3, 5.

Given this information, it can be concluded that Sammi correctly recorded the hours and their respective tallies. Therefore, there is no mistake in the creation of the tally chart.

It is important to note that the question only asks about the creation of the tally chart and not the creation of the dot plot, so the answer is based solely on the information provided in the question and not any assumed knowledge or steps in creating a dot plot.

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To find the selling price that will yield the maximum profit, we need to find the vertex of the quadratic function given by the profit equation y = -5x² + 286x - 2275.The x-coordinate of the vertex can be found using the formula:

x = -b/2a

where a = -5 and b = 286.

x = -b/2a

x = -286/(2(-5))

x = 28.6

So, the selling price that will yield the maximum profit is $28.60 (rounded to the nearest cent).

Therefore, the widgets should be sold for $28.60 to maximize the company's profit.

Hope I helped ya...

Answer:

29 cents

Step-by-step explanation:

The amount of profit, y, made by the company selling widgets, is related to the selling price of each widget, x, by the given equation:

\(y=-5x^2+286x-2275\)

The maximum profit is the y-value of the vertex of the given quadratic equation. Therefore, to find the price of the widgets that maximises profit, we need to find the x-value of the vertex.

The formula to find the x-value of the vertex of a quadratic equation in the form y = ax² + bx + c is:

\(\boxed{x_{\sf vertex}=\dfrac{-b}{2a}}\)

For the given equation, a = -5 and b = 286.

Substitute these into the formula:

\(\implies x_{\sf vertex}=\dfrac{-286}{2(-5)}\)

\(\implies x_{\sf vertex}=\dfrac{-286}{-10}\)

\(\implies x_{\sf vertex}=\dfrac{286}{10}\)

\(\implies x_{\sf vertex}=28.6\)

Assuming the value of x is in cents, the widget should be sold for 29 cents (to the nearest cent) to maximise profit.

Note: The question does not stipulate if the value of x is in cents or dollars. If the value of x is in dollars, the price of the widget should be $28.60 to the nearest cent.

Answer:

Step-by-step explanation:

I'm pretty

a. Let's check whether the given pairs are in the relation S or not.

Is 2 S 2?

To check if (2, 2) is in S, we need to evaluate the expression:

(1/2) - (1/2) = 1/2 - 1/2 = 0

Since 0 is an integer, (2, 2) is in S.

Is -1 S -1?

To check if (-1, -1) is in S, we need to evaluate the expression:

(1/-1) - (1/-1) = -1 - (-1) = 0

Since 0 is an integer, (-1, -1) is in S.

Is (3, 3) ∈ S?

To check if (3, 3) is in S, we need to evaluate the expression:

(1/3) - (1/3) = 1/3 - 1/3 = 0

Since 0 is an integer, (3, 3) is in S.

Is (3, -3) ∈ S?

To check if (3, -3) is in S, we need to evaluate the expression:

(1/3) - (1/-3) = 1/3 + 1/3 = 2/3

2/3 is not an integer, so (3, -3) is not in S.

b. Set of ordered pairs S:

S = {(x, y) | (1/x) - (1/y) is an integer}

S = {(2, 2), (-1, -1), (3, 3)}

c. Domain and Co-domain of S:

Domain of S: The set of all first components (x-values) of the ordered pairs in S.

Domain of S = {-3, -2, -1, 1, 2, 3}

Co-domain of S: The set of all second components (y-values) of the ordered pairs in S.

Co-domain of S = {-3, -2, -1, 1, 2, 3}

d. Arrow diagram for S:

Domain (C): {-3, -2, -1, 1, 2, 3}

Co-domain (D): {-3, -2, -1, 1, 2, 3}

(2, 2) -----> (0)  // 0 represents an integer

(-1, -1) -----> (0)

(3, 3) -----> (0)

(3, -3) -----> (2/3)  // 2/3 is not an integer

Note: The arrow diagram helps visualize the mapping of elements from the domain to the co-domain based on the relation S. Arrows point from the element in the domain to the result of the expression (integer or not integer) in the co-domain.

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A consumer loan of $40,000 with a 15.8% interest rate will require monthly payments over a period of 2 years. The total amount to be paid, including both principal and interest, will be approximately $45,380.

To calculate the monthly payments, we need to determine the total amount to be paid over the loan period, including the principal amount and the interest. The formula used for calculating equal monthly installments is:

M = P * (r * (1 + r)^n) / ((1 + r)^n - 1)

Where:

M = Monthly payment

P = Principal amount

r = Monthly interest rate

n = Number of monthly payments

In this case, the principal amount (P) is $40,000, the interest rate (r) is 15.8% per year, and the loan duration (n) is 2 years (24 months).

First, we convert the annual interest rate to a monthly rate by dividing it by 12: 15.8% / 12 = 0.0132.

Next, we substitute the values into the formula:

M = 40,000 * (0.0132 * (1 + 0.0132)^24) / ((1 + 0.0132)^24 - 1)

Calculating this formula gives us the monthly payment (M) of approximately $1,907.42.

To find the total amount to be paid, we multiply the monthly payment by the number of payments: $1,907.42 * 24 = $45,778.08. However, this includes both the principal and the interest. Subtracting the principal amount ($40,000) gives us the total interest paid: $45,778.08 - $40,000 = $5,778.08.

Therefore, the total amount to be paid, including both principal and interest, will be approximately $45,778.08.

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For this function, A is -2/3, B is 0 and C is 2/3.

To find the critical numbers of the function f(x) = 9x + 4\(x^{-1}\) , we need to find the values of x where the derivative of the function is equal to zero or undefined.

The derivative of f(x) is:

f'(x) = 9 - 4\(x^{-2}\) = 9 - 4/\(x^{2}\)

To find where the derivative is equal to zero, we set f'(x) = 0 and solve for x:

9 - 4/\(x^{2}\)  = 0

4/\(x^{2}\)  = 9

\(x^{2}\) = 4/9

x = ±2/3

Therefore, the critical numbers of f(x) are x = 2/3 and x = -2/3.

To find the intervals where the function is not defined, we need to look for values of x that make the denominator of the expression 4\(x^{-1}\)  equal to zero. In this case, the function is not defined at x = 0.

Now we need to determine the sign of the derivative in each of the intervals (−∞,A], [A,B), (B,C], and [C,∞).

For x < -2/3, f'(x) is negative because 4/\(x^{2}\)  is positive and 9 is greater than 4/\(x^{2}\) . Therefore, the function is decreasing on the interval (−∞,−2/3).

For −2/3 < x < 0, f'(x) is still negative because 4/\(x^{2}\)  is positive and 9 is still greater than 4/\(x^{2}\) . Therefore, the function is decreasing on the interval (−2/3,0).

For 0 < x < 2/3, f'(x) is positive because 4/\(x^{2}\)  is positive and 9 is less than 4/\(x^{2}\) . Therefore, the function is increasing on the interval (0,2/3).

For x > 2/3, f'(x) is still positive because 4/\(x^{2}\)  is positive and 9 is still less than 4/\(x^{2}\) . Therefore, the function is increasing on the interval (2/3,∞).

Finally, the function is not defined at x = 0, so the interval [A,B) is (−∞,0) and the interval (B,C] is (0,∞).

Therefore, we have:

A = -2/3

B = 0

C = 2/3

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Answer:

D: 2 1/2

Step-by-step explanation:

Answer:

the correct answer is.

A. 2/5

\(\frac{12+12.3935}{2}\)The value of   x in \(x^2/(.200-x)=12\)

=0.1967 or x=0.197

x= \(\frac{-12+\sqrt{12^2-4.1(-2.4)} }{2.1}\)

x=\(\frac{12+12.3935}{2}\)

x=0.1967

or x=0.197

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

Numbers and arithmetic operators make into a mathematical numerical expression. There are no symbols for undefined variables, equality, or inequality.

Unknown variables, integers, and arithmetic operators are the components of an algebraic expression. There are no symbols for equality or inequality in it.

The quantity of terms in an algebraic expression determines how it is categorized. The several kinds of algebraic expressions include:

From the question :

Given:

\(\frac{x^2}{0.200-x}\)=12

\(x^2=12\)×\(0.2\)-\(12x\)

\(x^2+12x-2.4=0\) --------(0)

This is the quadratic equation.

x=\(\frac{-12+\sqrt{12^2-4.1(-2.4)} }{2.1}\)

x=\(\frac{12+12.3935}{2}\)

x=0.1967

or x=0.197

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question:

Answer:

98

Step-by-step explanation:

The formula for this situation = Cube volume - cone volume

Cube volume = 5.1 * 5.1 * 5.1 = 132.7 ( rounded )
Cone volume = pi × r^2 × h/3 = pi × 2.55^2 × 5.1/3 = 3.14 × 6.5025 × 1.7 = 34.7 ( rounded )

Total volume = 132.6 - 34.7 = 98

Notes for myself: Cube = 5.1 * 5.1 * 5.1
Problem Description:
the volume of the cube with the empty cone-shaped indentation is ___ cubic meters.

Use 3.14 for pi and round your answer to the nearest hundredth.
Hope this helped

Certify Completion Icon Tries remaining: 3 A high school has 52 players on the football team. The summary of the players' weights is given in the box plot. The median weight of the players on the football team is 160 pounds.

The box plot shows that the median weight of the players is the middle value of the distribution. In this case, the median weight is halfway between the 26th and 27th players, which is 160 pounds.

The box plot also shows that the minimum weight of the players is 150 pounds and the maximum weight is 212 pounds. The interquartile range, which is the range of the middle 50% of the data, is 20 pounds.

In conclusion, the median weight of the players on the football team is 160 pounds. This means that half of the players on the team weigh more than 160 pounds and half of the players weigh less than 160 pounds.

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Answer:

567

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

2x2=4-2 =2

Answer:

the Number of Adult tickets sold is 1,020 and Number of Children tickets sold is 530

Step-by-step explanation:

The computation of the number of adults and number of children tickets sold is given below:

Let us assume the number of adult be x

And, for children be y

So, the equations are

x + y = 1,550..........(1)

45x + 15y = $53,850.......(2)

Now multiply by 15 in equation 1

15x + 15y = $23,250

45x + 15y = $53,850

Now subtract last equation from the other equation

-30x = -$30,600

x = 1,020

And, y = 1,550 - 1,020

= 530

Hence, the Number of Adult tickets sold is 1,020 and Number of Children tickets sold is 530

Answer:

this is a nonlinear function

Step-by-step explanation:

a linear function is when the y value increases the same amount every time the x value increases by 1(or any constant interval). in this problem when x increases 1, they y value increases by 2 for the first 3 sets of numbers, but in the 4th set of numbers the x value increases by 1 and the y value increases by 2. This does not follow the same pattern and therefore makes this nonlinear. A quicker way to figure this out when you have a graph like this is to draw a line through all the points in order of increasing x values or vice versa if the line you drew is straight all the way through then it is linear and if it isn't then it is nonlinear. I hope this helped.

Step-by-step explanation:

(3j - 5k^3) ( 3j + 5k^3)  =  9j^2 - 25k^6

Answer:

$\frac{10}{3}$ in by $\frac{14}{3}$ in by $\frac{10}{3}$ in.

Step-by-step explanation:

Let's denote the length of the box as $l$, the width as $w$, and the height as $h$. We are given that the original piece of cardboard has dimensions 10 in by 12 in, so we know that:

$$l + 2h = 10 \quad \text{and} \quad w + 2h = 12.$$

To find the dimensions of the box with the largest volume, we need to maximize the volume function, which is given by:

$$V(l,w,h) = lwh.$$

Using the equations above, we can express the volume in terms of just two variables, say $l$ and $h$:

$$V(l,h) = lwh = l(10-2h)h = 10h^2 - 2h^3.$$

Now we can use calculus techniques to find the maximum of this function. To do this, we need to find the critical points, which are the values of $h$ where the derivative of $V$ with respect to $h$ is zero or undefined.

Taking the derivative of $V$ with respect to $h$, we get:

$$V'(h) = 20h - 6h^2.$$

Setting this to zero to find the critical points, we get:

$$20h - 6h^2 = 0 \quad \Rightarrow \quad h(10 - 3h) = 0.$$

This equation has two solutions: $h = 0$ and $h = \frac{10}{3}$. We can check that $h=0$ corresponds to a minimum, and $h = \frac{10}{3}$ corresponds to a maximum by computing the second derivative of $V$ with respect to $h$:

$$V''(h) = 20 - 12h.$$

At $h=0$, we have $V''(0) = 20$, which is positive, so $h=0$ is a minimum. At $h=\frac{10}{3}$, we have $V''\left(\frac{10}{3}\right) = -8\frac{1}{3}$, which is negative, so $h=\frac{10}{3}$ is a maximum.

Therefore, the maximum volume is achieved when $h=\frac{10}{3}$. Using the equations we derived earlier, we can find the corresponding values of $l$ and $w$:

$$l = 10 - 2h = \frac{10}{3}, \quad w = 12 - 2h = \frac{14}{3}.$$

So the dimensions of the box with largest volume are $\frac{10}{3}$ in by $\frac{14}{3}$ in by $\frac{10}{3}$ in.

The formula for the volume of cylinder with base area B and height H is V = B × H.

A cylinder is a 3-dimensional shape having two parallel circular bases joined by a curved surface.

The volume of a cylinder is expressed as;

V = π × r² × h

Area of a circle which is the base of a cylinder = πr²

Given that;

Plug the given values into the above formula.

V = π × r² × h

V = πr² × h

V = Base area × Height

V = B × H

Therefore, formula for the volume is V = B × H.

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The answer is ,  the Taylor series (centered at c=0) for the function f(x) = e^(4x) is given by:

\($$\large f(x) = \sum_{n=0}^{\infty} \frac{4^n}{n!}x^n$$\)

The Taylor series expansion is a way to represent a function as an infinite sum of terms that depend on the function's derivatives.

The Taylor series of a function f(x) centered at c is given by the formula:

\(\large f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(c)}{n!}(x-c)^n\)

Using the definition of Taylor series to find the Taylor series (centered at c=0) for the function f(x) = e^(4x), we have:

\(\large e^{4x} = \sum_{n=0}^{\infty} \frac{e^{4(0)}}{n!}(x-0)^n\)

\(\large e^{4x} = \sum_{n=0}^{\infty} \frac{4^n}{n!}x^n\)

Therefore, the Taylor series (centered at c=0) for the function f(x) = e^(4x) is given by:

\($$\large f(x) = \sum_{n=0}^{\infty} \frac{4^n}{n!}x^n$$\)

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The Taylor series for f(x) = e^(4x) centered at c = 0 is:

f(x) = 1 + 4x + 8x^2 + 32x^3/3 + ...

To find the Taylor series for the function f(x) = e^(4x) centered at c = 0, we can use the definition of the Taylor series. The general formula for the Taylor series expansion of a function f(x) centered at c is given by:

f(x) = f(c) + f'(c)(x - c) + f''(c)(x - c)^2/2! + f'''(c)(x - c)^3/3! + ...

First, let's find the derivatives of f(x) = e^(4x):

f'(x) = d/dx(e^(4x)) = 4e^(4x)

f''(x) = d^2/dx^2(e^(4x)) = 16e^(4x)

f'''(x) = d^3/dx^3(e^(4x)) = 64e^(4x)

Now, let's evaluate these derivatives at x = c = 0:

f(0) = e^(4*0) = e^0 = 1

f'(0) = 4e^(4*0) = 4e^0 = 4

f''(0) = 16e^(4*0) = 16e^0 = 16

f'''(0) = 64e^(4*0) = 64e^0 = 64

Now we can write the Taylor series expansion:

f(x) = f(0) + f'(0)(x - 0) + f''(0)(x - 0)^2/2! + f'''(0)(x - 0)^3/3! + ...

Substituting the values we found:

f(x) = 1 + 4x + 16x^2/2! + 64x^3/3! + ...

Simplifying the terms:

f(x) = 1 + 4x + 8x^2 + 32x^3/3 + ...

Therefore, the Taylor series for f(x) = e^(4x) centered at c = 0 is:

f(x) = 1 + 4x + 8x^2 + 32x^3/3 + ...

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Step-by-step explanation:

First find the total weight of the male students

5/3 = x / 870     cross multiply

4350 = 3x

x = total boys' weight = 1450 kg

    if the mean is GREATER THAN 80 then    

               1450 / n > 80     where n is the number of boys

                   1450/80 > n

                              n< 18.125         max number would be 18 boys

Answer:

Step-by-step explanation:

Answer: I believe A is 52 degrees.

Solution:  Find angle c (D + C adds up to 180 degrees cuz its a line)

So do 180-116=64 degrees

Assuming this is an isosceles triangle because the sides on d and c look equal, we know that those 2 angles add up to 128 degrees(64 + 64).

Therefore, since the shape is a triangle(adds up to 180 degrees) you just do 180 minus 128 to get angle A which is 52 degrees.

Answer:

50 years

Step-by-step explanation:

Given data

Principal= $500

Rate= 6%

Amount = $2000

The simple interest expression is given as

A=P(1+rt)

Substitute

2000= 500(1+0.06*t)

open bracket

2000=500+ 30t

2000-500=30t

1500=30t

t= 1500/30

t= 50 years

Hence the time is 50 years

Answer:

50 years

Step-by-step explanation:

Formula for simple interest:

I = Prt

where

I = interest earned

P = principal amount deposited

r = annual interest rate

t = number of years

When the account reaches $2000, $500 is from the principal and

$2000 - $500 = $1500 is from the interest.

We use the simple interest formula to find the number of years needed to earn $1500 in interest from $500 principal at 6% interest rate.

1500 = 500 * 0.06 * t

t = 50

Answer: 50 years