In an opamp inverting amplifier circuit, R = 10 ko. and Ri= 2.2 k. Find the output voltage when the input voltage is (a) +0.25 V (b)-1.8V

Answer:

fan

Explanation:

To develop the logic circuit for the given Boolean equation Y=AB(C+DEF)+CE(A+B+F), we need to analyze the equation and design a circuit using AND and OR gates.

To develop the logic circuit, we break down the Boolean equation into its constituent terms. Each term can be represented using a combination of AND and OR gates.

For example, the term AB(C+DEF) can be implemented by connecting the outputs of AND gates to an OR gate.

Similarly, CE(A+B+F) can be implemented using another set of AND and OR gates. By combining these sub-circuits, we can create the overall logic circuit for the given equation.

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The step response of the closed loop system can be categorized as under damped, critically damped, over damped, or unstable based on the behavior of the output.So the correct option is c. over damped

The step response of the closed loop system shown in the figure can be determined by analyzing the behavior of the output. If the output oscillates and gradually approaches the steady state value, the system is under damped. If the output approaches the steady state value without oscillations, the system is critically damped. If the output approaches the steady state value very slowly without any oscillations, the system is over damped. If the output does not reach a steady state value, the system is unstable.

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Answer:

33.1144 °C

Explanation:

From the information given;

The first step is to find the mean temperature \(T_m\) by using the formula:

\(T_m = \dfrac{T_i- T_\infty}{2}\)

where:

\(T_i\) = initial temperature = 40 °C

\(T_{\infty}\) = ambient temperature = 10 °C

\(T_m = \dfrac{(40+10)^0C}{2}\)

\(T_m = \dfrac{50^0C}{2}\)

\(T_m\)  = 25 °C

\(T_m\)  = (25 + 273) K

\(T_m\)  = 298 K ≅ 300 K

The following properties expressed below were obtained from the thermal physical properties table.

For soda-lime glass at the temperature of 300 K:

Density \(\rho_s = 2500 \ kg/m^3\)

Thermal conductivity \(k_s\) = 1.4 W/m.K

Specific heat \((c_p)_s\) = 750  J/kg.K

For bakelite at the temperature of 300 K:

Density \(\rho_B = 1300 \ kg/m^3\)

Thermal conductivity \(k_B\) = 1.4 W/m.K

Specific heat \((c_p)_B\) = 1465  J/kg.K

From these data; The next process is to find out the thermal diffusivity of each component.

To start with soda-lime glass by using the expression:

\(\alpha_s = \dfrac{k_s}{\rho_s ( c_p)_s}\)

\(\alpha_s = \dfrac{1.4 \ W/m.K}{2500 \ kg/m^3 \times 750 \\J/kg.K}\)

\(\alpha_s = 747 \times 10^{-9} \ m^2/s\)

For Bakelite: The thermal diffusivity is computed as:

\(\alpha_B = \dfrac{k_B}{\rho_B ( c_p)_B}\)

\(\alpha_B = \dfrac{1.4 \ W/m.K}{1300 \ kg/m^3\times 1465 \ J/kg.K}\)

\(\alpha_B = 735 \times 10^{-9} \ m^2/s\)

From the above two results, we will realize that \(\alpha _ s \simeq \alpha _B\)

Thus, as obvious as it is; we presume that the uniform thermal diffusivity

\(\alpha = 740 \times 10^{-9} \ m^2/s\)

However, the diameter of the sphere can be estimated by the summation of the diameter of the glass sphere \((D_1)\) with twice the thickness of the sphere (L)

i.e. \(D = D_1 + 2L\)

D = 25 mm + 2 (10 mm)

D = 45 mm

\(D = 45 \ mm ( \dfrac{10^{-3} \ m}{1 \ mm} )\)

D = 45 × 10⁻³ m

The expression for Biot Number can be estimated by using the formula:

\(Bi = \dfrac{hL}{k}= \dfrac{h(D/6)}{k}\)

Given that:

h = 30 W/m².k

D = 45 × 10⁻³ m

k = 1.4 W/m.K

Similarly, to estimate the Fourier No \(F_o\) by using the expression:

\(F_o = \dfrac{\alpha t}{(D/2)^2}\)

\(F_o = \dfrac{740 \times 10^{-9} \ m^2 /s \times 200 \ s}{( \dfrac{45 \times 10^{-3} m}{2})^2}\)

\(F_o = 0.292\)

It is obvious that \(F_o\) is > 0.2, thus, the validity of one term approximation is certain.

Again; the Biot Number is calculated by using the formula:

\(Bi = \dfrac{h(D/2)}{k}\)

\(Bi = \dfrac{30 \ W/m^2.K (\dfrac{45 \times 10^{-3 }\ m}{2}) }{1.4 \ W/m.k}\)

Bi = 0.482

Bi \(\simeq\) 0.5

We obtain the Eigen coefficient \(\xi_1\) as well as the coefficient for a sphere \(C_1\) using the Bi Number:

From one-term approximation of transient 1 heat conduction in the sphere;

\(\dfrac{T - 10^{0 } \C }{40^{0} \ C - 10^0 \ C} = 1.1441 \ exp \ ( -1.1656^2 \times 0.291)\)

\(\dfrac{T - 10^{0 } \C }{30^{0} \ C} = 0.77048\)

\(T - 10^{0 } \C = 30^{0} \ C \times 0.77048\)

\(T - 10^{0 } \C = 23.1144^0 \ C\)

T = (23.1144 + 10) °C

T = 33.1144 °C

The function begin() refers to the first element in the vector, and the function end() refers to one position after the last element in the vector. Therefore, the correct answer is (2) True, (2) True.

Statement 2 is true because the function end() in the vector class refers to one position after the last element in the vector. It returns an iterator pointing to the imaginary element following the last element in the vector. This is often used as an indicator to determine the end of a range when iterating through the vector. Statement 1 is false because the function begin() in the vector class refers to the first element in the vector, not one position before it. The function begin() returns an iterator pointing to the first element of the vector. It provides access to the beginning of the vector for iteration or other operations.

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Answer:

Poor workshop layout and design.

Cluttered walkways leading to slips, trips and falls.

Electrical power leads.

Welding and grinding equipment.

Power tools – checking guards and cords.

Hoists used to work on farm vehicles.

Poor lighting – leading to accidents.

Battery charging.

Explanation:

Answer:

22400 volts

Explanation:

According to Ohms law, the resistance can be calculated as;

R=V/I where R is total resistance, V is voltage across the whole circuit and I is the current across the whole circuit.

From the question;

I= 400 A

R= 56 Ω

Applying the formula;

R=V/I

56 =V/400

V= 400*56 =22400 volts

Answer:

I didn't understand your question or is it a fun fact

Answer:

b remains the same

Explanation:

voltage and amps have no connection

the electricity used to rin your clothes dryer is normally 220V 18-24A

the voltage in your car's battery is usually 12V 20-30A

see they are approximately the same amperage but very different voltage

Answer:

a) The spring constant is 50 lb/ft

b) The man is 26.3 ft close to the ground.

Explanation:

Height of tower is 130 ft

Specification calls for a cable of length 85 ft

the maximum this length stretches is 100 ft when subjected to a load of 750 lb

The extension of the cable is calculated from the formula from Hooke's law

F = kx

where F is the load or force on the cable

k is the spring constant of the cable

x is the extension on the cable

a) The extension on the cable is

x = 100 ft - 85 ft = 15 ft

substituting into the formula above, we'll have

750 = k*15

k = 750/15 = 50 lb/ft

b) for a 185 lb man, jumping down will give an extension gotten as

F = kx

185 = 50*x

x = 185/50 = 3.7 ft

The total length of the cable will be extended to 100 ft + 3.7 ft = 103.7 ft

closeness to the ground = 130 ft - 103.7 ft = 26.3 ft

Overloading is responsible for a relatively small portion of mobile crane accidents.

While overloading can certainly pose risks and lead to accidents, it is not the primary cause of most incidents involving mobile cranes. Mobile crane accidents are typically attributed to factors such as inadequate training, improper use or setup of the crane, mechanical failures, unstable ground conditions, insufficient planning, or human error. These factors can contribute to incidents such as tipping, structural failure, or loss of control. Therefore, while overloading should be avoided to ensure safe crane operations, it is crucial to address multiple other factors and adhere to proper safety protocols to prevent accidents and ensure the overall safety of crane operations.

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Large aircraft, turbojet-powered multiengine civil aircraft, and fractional ownership program aircraft are all subject to the operating regulations outlined in part 91, subpart F. Operations needed to comply with requirements under: are not subject to the rules of this component : Part 121, 125, 129, 135, and 137,

An air-breathing jet engine, the turbojet is frequently found in airplanes. It is made up of a gas turbine and a nozzle for propulsion. The gas turbine has a compressor, a combustion chamber, a turbine, and an air inlet with inlet guiding vanes (that drives the compressor). Fuel combustion in the combustion chamber heats the compressed air from the compressor before allowing it to expand via the turbine. The propelling nozzle expands the turbine exhaust, which is subsequently accelerated to a high speed to provide push. In the late 1930s, two engineers, Hans von Ohain in Germany and Frank Whittle in the United Kingdom, independently developed the idea into workable engines. Turbojets are only helpful in aviation because of their poor efficiency at low vehicle speeds. In rare instances, turbojet engines have been utilized to power vehicles other than airplanes, usually in an effort to break land speed records. When a vehicle is "turbine-powered," it most often means it has a turboshaft engine, a modified gas turbine engine that uses a second turbine to power a revolving output shaft. These are typical in hovercrafts and helos. On Concorde and the longer-range versions of the TU-144, which had to spend a lot of time travelling supersonically, turbojets were used.

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These four characteristics, as outlined by Hollnagel (2010), are critical in developing resilient systems that can cope with unexpected situations and adverse external events. Software engineers must educate system developers about these characteristics to develop more resilient systems.

Resilience engineering is about developing adaptable systems that can handle unexpected situations and are able to cope with the effects of adverse external events that might cause system failure. As a software engineer, you need to inform system developers about the following four characteristics that reflect the resilience of an organization, as described by Hollnagel (2010):Maintainability: This characteristic reflects the degree to which a system can be maintained or repaired after it has been damaged. In other words, it assesses the system's ability to remain in good working order or quickly recover from damage. An example of maintainability would be the ability to quickly repair an engine that has been damaged during an accident.Flexibility: This characteristic reflects the degree to which a system can be modified or adapted to cope with changing circumstances. Flexibility is essential for resilience because it enables a system to respond to new challenges and adapt to different circumstances. An example of flexibility would be the ability to change the specifications of a car to adapt to different driving conditions.Redundancy: This characteristic reflects the degree to which a system can continue to function even if some of its components fail. Redundancy is important because it ensures that the system can continue to operate even if one or more components are not working properly. An example of redundancy would be having a backup generator in case the primary generator fails.Responsiveness: This characteristic reflects the degree to which a system can respond to changing circumstances or threats. Responsiveness is important because it enables a system to quickly and effectively respond to unexpected events. An example of responsiveness would be the ability of an air traffic control system to quickly respond to changing weather conditions to ensure the safety of airplanes in the area.

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The Poisson's ratio for a cast iron with a modulus of elasticity (E) of 110 Gpa and a modulus of rigidity (G) of 44 Gpa is 0.42.

Poisson's ratio is the ratio of transverse strain to corresponding axial strain on a material stressed along one axis. The Poisson's ratio for a cast iron with a modulus of elasticity (E) of 110 Gpa and a modulus of rigidity (G) of 44 Gpa can be calculated as follows:

Poisson's ratio (ν) = (E/2G)-1

ν = (110/2(44))-1

ν = 0.42

Therefore, the answer from the above calculation is 0.42.

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Answer:

The shear stress will be 80 MPa

Explanation:

Here we have;

τ = (T·r)/J

For rectangular tube, we have;

Average shear stress given as follows;

Where;

\(\tau_{ave} = \frac{T}{2tA_{m}}\)

\(A_m\) = 100 mm × 200 mm = 20000 mm² = 0.02 m²

t = Thickness of the shaft in question = 2 mm = 0.002 m

T = Applied torque

Therefore, 50 MPa = T/(2×0.002×0.02)

T = 50 MPa × 0.00008 m³ = 4000 N·m

Where the dimension is 50 mm × 250 mm, which is 0.05 m × 0.25 m

Therefore, \(A_m\) = 0.05 m × 0.25 m = 0.0125 m².

Therefore, from the following average shear stress formula, we have;

\(\tau_{ave} = \frac{T}{2tA_{m}}\)

Plugging in then values, gives;

\(\tau_{ave} = \frac{4000}{2\times 0.002 \times 0.0125} = 80,000,000 Pa\)

The shear stress will be 80,000,000 Pa or 80 MPa.

9514 1404 393

Answer:

  1

Explanation:

Only one such circle can be drawn. The diameter of the 10" circle will be a radius of the semicircle. In order for the 10" circle to be wholly contained, the flat side of the semicircle must be tangent to the 10" circle. There is only one position in the figure where that can happen. (see attached).

Answer:

Answer:

=> base transport factor = 0.98.

=> emitter injection efficiency = 0.99.

=> common-base current gain = 0.97.

=> common-emitter current gain = 32.34.

=> ICBO = 1 × 10^-6 A.

=> base transit time = 0.325.

=> lifetime = 1.875.

Explanation:

(Kindly check the attachment for the diagram showing the dominant current components, with proper arrows, for directions in the normal active mode).

The following parameters or data are given for a p-n-p BJT with NE 7 NB 7 NC and they are: IEp = 10 mA, IEn = 100 mA, ICp = 9.8 mA, and ICn = 1 mA.

(1). The base transport factor = ICp/IEp=9.8/10 =  0.98.

(2). emitter injection efficiency =IEp/ IEp + ICn = 10/10 + 0.1 =  0.99.

(3).common-base current gain = 0.98 × 0.99 = 0.9702.

(4).common-emitter current gain =0.97 / 1- 0.97  = 32.34.

(5). Icbo = Ico = 1 × 10^-6 A.

(6). base transit time = 1248 × 10^-2 × (1.38× 10^-23/1.603 × 10^-19). = 0.325.

(7).lifetime;

= > 2 = √0.325 + √ lifetime.

= Lifetime = 2.875.

No, the physical address 346E0 cannot be the starting address for a segment. This is because the starting address of a segment must be aligned with the segment's size or boundary, which is determined by the processor's architecture.

Segment boundaries are defined by 16-byte or 4-byte boundaries, depending on the segment's use. Therefore, the starting address of a segment must be a multiple of 16 or 4, respectively, depending on the segment type.

In the given address 346E0, the last digit is 0, which indicates that it is a multiple of 16. However, we do not have enough information about the processor architecture and segment size to determine whether this is an appropriate starting address for a segment.

In general, when defining a segment, it is important to ensure that the starting address is properly aligned with the segment's boundary to avoid any issues with memory access and processing.

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The magnitude of normal stress is greatest at point D. Point A in the triangular cross-section of a homogeneous beam subjected to a pure bending moment.

The cross-section of a homogeneous beam of triangular cross-section, the point of the cross-section where the magnitude of normal stress is the greatest is Point C.

Normal stress is a type of stress that occurs in a member when a force is applied perpendicular to the member's cross-section. It is calculated using the formula: σ = F/A

Where,σ = normal stress, F = the applied force, and A = the cross-sectional area of the member.

Now, let us consider the cross-section of the beam in question:

The centroid of the cross-section is at point C. This means that the cross-section is symmetric with respect to the y-axis. When a pure bending moment is applied to the beam, it causes the top of the beam to compress and the bottom of the beam to stretch. This creates a normal stress that is maximum at the top and minimum at the bottom.

Since the cross-section is symmetric, this maximum normal stress will occur at a point equidistant from the top and bottom of the beam. This point is point C. Therefore, the point of the cross-section where the magnitude of normal stress is the greatest is Point C.

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Given values: Diameter of segment AC, d₁ = 0.5 in Diameter of segment CB, d₂ = 1 inLength of segment CB, L = 10 inUniform distributed torque along segment CB, t = 60 lb.in^(-1) Shear modulus of elasticity, G = 11 × 10³ ksi The formula for maximum shear stress τ is given as,τ = (t × r) / J …(1)

Here,r is the radius of the shaftJ is the polar moment of inertiaThe polar moment of inertia J is given as,J = (π / 2) × (d²₁ + d²₂) …(2 )

Now, substituting the given values in Equation (2), we haveJ = (π / 2) × (0.5² + 1²)J = 0.9817 in⁴

Therefore, substituting the values of t, r, and J in Equation (1), we have,τ = (60 × 0.5) / 0.9817τ = 30.55 psiThus, the absolute maximum shear stress in the shaft is 30.6 psi (approx) and the unit is psi. Therefore, option (c) is correct.

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An incremental encoder with 500 windows in its track is used for speed measurement.

Speed = 1 rev/s

With 500 windows, we have 500 pulses/s

A. Pulse counting method

Counting period = 1/10Hz=0.1 s

Pulse count (in 0.1 s) = 500 × 0.1 = 50

Percentage resolution = 1/50×100% = 2%

B.Pulse timing method

At 500 pulses/s, pulse period = 1/500s

Percentage resolution = 0.005%

ii. Speed = 100 rev/s

With 500 windows, we have 50,000 pulses/s

a. Pulse counting method

Pulse count (in 0.1 s) = 50,000 × 0.1 = 5000

Speed (Rev/s)  1, 100.0

Pulse-Counting Method (%) 2, 0.02

Pulse-Timing Method (%) 0.005, 0.5

Improves with speed, and hence it is more suitable for measuring high speeds. Furthermore, in the pulse-timing method, the resolution degrades with speed, and hence it is more suitable for measuring low speeds.

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Answer:

The answer is V = √2FD ÷ CD × PA

Explanation:

FD = CD × PV²A ÷ 2

V² = 2FD ÷ CD × PA

V = √2FD ÷ CD × PA

Thus, The value of V is V = √2FD ÷ CD × PA

-TheUnknownScientist 72

The flowrate Q is estimated to be 10.83 m³/s, and the uncertainty is 0.64 m³/s (i.e., 5.89%).

To estimate the uncertainty in the flowrate for the measured values: Q = 128μL ΔPπD / 4.

Where ΔP = 12kN/m² ± 0.3kN/m²; D = 0.3m ± 0.01 m,

L = 150m ± 0.1m and μ = 0.001 kg/m-s (the dynamic viscosity of water).

The formula for the uncertainty of flowrate using the given parameters can be calculated as follows:

ΔQ/Q = ΔΔP/ΔP + ΔD/D + ΔL/L Since ΔP = 12kN/m² ± 0.3kN/m²,

The percentage uncertainty in ΔP is given as follows: (0.3kN/m²/12kN/m²) × 100% = 2.5%

Similarly, the percentage uncertainty for D and L can be computed as follows:

ΔD/D = (0.01m/0.3m) × 100% = 3.33%ΔL/L = (0.1m/150m) × 100% = 0.067%

The flowrate Q can be calculated as follows: Q = 128μL ΔPπD / 4Q = 128 x 0.001 x 150 x (12/4) x 3.1416 x (0.3) ⁴ = 10.83 m³/s

The uncertainty in Q can be calculated as follows:

ΔQ/Q = ΔΔP/ΔP + ΔD/D + ΔL/LΔQ/Q = 2.5% + 3.33% + 0.067%ΔQ/Q = 5.89%

Therefore, the flowrate uncertainty is ΔQ = (5.89/100) x 10.83 = 0.64 m³/s.

The volumetric flowrate formula in a horizontal pipe for laminar flow is Q = 128 μL ΔPπD / 4.

The flowrate uncertainty can be calculated using the formula, ΔQ/Q = ΔΔP/ΔP + ΔD/D + ΔL/L.

The values of ΔP, D, and L are ΔP = 12k N/m ² ± 0.3k N/m ², D = 0.3m ± 0.01 m, and L = 150m ± 0.1m,

Therefore, the flowrate Q is estimated to be 10.83 m³/s, and the uncertainty is 0.64 m³/s (i.e., 5.89%).

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Answer:

A sole proprietorship, also known as the sole trader, individual entrepreneurship or proprietorship, is a type of enterprise that is owned and run by one person and in which there is no legal distinction between the owner and the business entity.

Explanation:

Answer:

A business owned by one people is a-Sole proprietorship

Explanation:

This is correct i did it for my electives class which was career reaserch and decision making.

brainliest?

Answer:

Explanation:

Wow

An engine is composed of several major components; the block, the crank, the rods, the pistons, the head (or heads), the valves, the cams, the intake and exhaust systems and the ignition system. These parts work together in an exacting manner to harness the chemical energy in gasoline.

The engine block consists of a cylinder block and a crankcase. An engine block can be produced as a one-piece or two-piece unit. The cylinder block is the engine component that consists of the cylinder bore, cooling fins on air-cooled engines, and valve train components, depending on the engine design.

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Answer:

multimeter

Explanation:

there's several devices that are used to measure power. the most common one is a multimeter. there's also the voltmeter and ammeter or the oscilloscope.