In music, two notes are said to be an octave apart whenone note is exactly twice the frequency of the other. Suppose youhave a guitar string playing frequency fo.a) To increase the frequency by 4 octave(s), to 16fo, by what factor would you have toincrease the tension?Tv/To= ?b) To increase the frequency by 4 octave(s), to 16 fo, by what factor would you have todecrease the length?

Answer:

allows no light to pass

Explanation:

Using the work done relation, the value of force is 25 Newton.

When a force is applied along a displacement, "work" in physics refers to the energy that is transported to or away from an object. The following situations include work: relocating a table. a door being pulled and pushed. Walking. raising a stone.

The work W that a force F traveling across a distance x exerts on an object is calculated using the formula W=Fs. If the object is moving in the opposite direction from how we expect it to, we add a minus sign.

Work done is equal to displacement times force.

50J = force × 2

f=50/2

Force = 25 Newton.

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The ratio of voltage and current from the scope display compares to the resistance so that R = U/i.

The resistance of an electrical system is configured as the difficulty that the current faces to travel through the entire system.

With the value of the resistance it is possible to determine the value of the voltage that the electrical object will be subjected, so that:

                                                \(U = R \times i\)

Thus, the value of current and voltage can be related to the value of resistance in such a way that:

                                                    \(R = \frac{U}{i}\)

So, the ratio of voltage and current from the scope display compares to the resistance of the resistor so that R = U/i.

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The velocity of the vehicle relative to the police car is -4.6 m/s. The velocity of the police car relative to the vehicle is 4.6 m/s.

Part A: For finding the velocity of the vehicle relative to the police car, subtract the velocity of the police car from the velocity of the vehicle:

Relative velocity = Velocity of the vehicle - Velocity of the police car

Relative velocity = 34.3 m/s - 38.9 m/s

Relative velocity = -4.6 m/s

Therefore, the velocity of the vehicle relative to the police car is -4.6 m/s. The negative sign indicates that the vehicle is moving in the opposite direction of the police car.

Part B: For determining the velocity of the police car relative to the vehicle, subtract the velocity of the vehicle from the velocity of the police car:

Relative velocity = Velocity of the police car - Velocity of the vehicle

Relative velocity = 38.9 m/s - 34.3 m/s

Relative velocity = 4.6 m/s

Hence, the velocity of the police car relative to the vehicle is 4.6 m/s, indicating that the police car is moving in the same direction as the vehicle.

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Answer:

The water filled balloon does not burst because the rubber obviously does not reach a temperature sufficient for it to melt or burn. The rubber is stretched thin so that heat is quickly transferred into the balloon. With air inside the balloon, this heat is not readily dissipated away from the spot touching the flame.

The rate of constant at 366 K is \(0.58s^{-1}\).

Explain about rate of constant?

The rate constant is a measure of how fast a reaction will proceed. It describes the speed at which reactants are converted into products in a given reaction. The rate constant is proportional to the rate of reaction and is usually expressed as the amount of product formed per unit time. It is a constant that is specific to each reaction, and it is determined by the reaction mechanism, the temperature and pressure at which the reaction takes place, and the concentrations of the reactants.

Here,  is the rate of constant  is the activation energy,  is the gas constant (8.314 J/mol-K).

\(log \frac{k_{2} }{k_{1} } = \frac{Ea}{2.303R} * [\frac{1}{T_{1} } - \frac{1}{T_{2} }]\)

The activation energy of the reaction is 108 kJ/mol.

The rate constant for the reaction is 4.60 x 10-6 s-1 at 275 K.

As the initial temperature is 275 K and the final temperature is 366 K.

Thus, \(log \frac{k_{2} }{4.60*10^{-6} } } = \frac{108000}{2.303* 8.314} * [\frac{1}{275 } - \frac{1}{366 }]\)

\(K_{2} = 0.58s^{-1}\)

Therefore, 0.58s^{-1} is the rate constant at 366 k.

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The stopper travels approximately 4.5 meters horizontally before hitting the ground.

We can use conservation of energy to solve this problem. At the highest point of the stopper's motion, all of its energy is in the form of potential energy, and at the lowest point (when it hits the ground), all of its energy is in the form of kinetic energy.

The potential energy of the stopper at the highest point is:

Ep = mgh

where m is the mass of the stopper, g is the acceleration due to gravity, and h is the height above the ground. Plugging in the values given in the problem, we get:

Ep = (0.150 kg) * (9.81 m/s²) * (2.3 m) ≈ 3.2 J

At the lowest point, all of the potential energy has been converted to kinetic energy:

Ek = (1/2) * mv²

where v is the speed of the stopper just before it hits the ground. Since the stopper is released from rest, we can use conservation of energy to equate the potential energy at the highest point to the kinetic energy just before hitting the ground:

Ep = Ek

mgh = (1/2) * mv²

Solving for v, we get:

v = √(2gh)

where h is the height from which the stopper was released. Plugging in the values given in the problem, we get:

v = √(2 * 9.81 m/s² * 2.3 m) ≈ 6.6 m/s

Now we can use the time it takes for the stopper to fall to the ground to calculate the horizontal distance it travels. The time is given by:

t = √(2h/g)

Plugging in the values given in the problem, we get:

t = √(2 * 2.3 m / 9.81 m/s²) ≈ 0.68 s

During this time, the stopper travels a horizontal distance given by:

d = vt

Plugging in the values we just calculated, we get:

d = (6.6 m/s) * (0.68 s) ≈ 4.5 m

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The acceleration vector of the club head in circular motion is pointed inward, toward the center of the circular path.

When an object undergoes circular motion, it experiences a centripetal acceleration directed toward the center of the circle. This centripetal acceleration is required to continuously change the direction of the object's velocity, keeping it tangent to the circular path.

In addition to the centripetal acceleration, if the speed of the club head is increasing, there is also an acceleration component in the direction of the velocity vector. This component is called tangential acceleration and is responsible for the change in magnitude of the velocity.

Therefore, the total acceleration vector of the club head is a combination of the centripetal acceleration and the tangential acceleration. Since the club head is undergoing circular motion and its speed is increasing, the acceleration vector is pointed inward, toward the center of the circular path. This inward acceleration allows the club head to maintain its circular motion and increase its speed simultaneously.

In summary, the acceleration vector of the club head in circular motion is pointed inward, toward the center of the circular path, due to the presence of the centripetal acceleration and the tangential acceleration.

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The latitude and longitude coordinates for Location C are given as 50S, 68W. Therefore, the correct answer is 4) Cannot discern from the information provided.

Latitude and longitudinal lines are shown on a globe of Earth as parallel and vertical lines. To determine which distance is farther, we need to compare the distance between Location B and the Equator with the distance between Location C and the Equator.

However, the latitude and longitude coordinates for Location B and the specific direction or coordinates of the Equator are not provided. Without this information, it is not possible to determine which distance is farther between Location B and the Equator or Location C and the Equator.

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When the wave receptor and wave source move relative to one another, the frequency of the wave remains constant. This phenomenon is known as the Doppler effect.

The Doppler effect is the change in the observed frequency of a wave when the wave source or receiver is moving relative to one another.

When the wave source and the wave receptor move relative to one another, the frequency of the wave remains the same because the frequency of a wave is determined by the source of the wave, not the observer's relative motion.

Relatively, the wavelength and the wave speed of the wave changes.

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Answer:

300 is the answer

Explanation:

Hope that this answer will help you

The electric potential difference between the two large, charged parallel metal plates is 300 V.

The electric potential difference (V) between two points is defined as the work done per unit charge in moving a positive test charge from one point to another.

Mathematically,

V = W/Q

where W is the work done in moving the charge Q between two points.

Here in the Question,

In the case of two large, charged parallel metal plates, The electric field intensity (E) is given as 6000 N/C and the distance between the plates (d) is 0.05 m. The electric field intensity between the plates is uniform, which means that the force on a test charge is constant at any point between the plates.

The work done (W) in moving a positive test charge from one plate to the other against the electric field is given by

W = F × d

where F is the force acting on the test charge and d is the distance moved.

Using the formula for electric field intensity

E = F/Q

we can express force:

F = QE

Substituting this in the formula for work done, we get

W = Q × E × d.

Now,  the electric potential difference (V) between the plates is given by

V = W/Q = E × d = 6000 N/C × 0.05 m = 300 V.

V = 300 V

Therefore, the electric potential difference between the two large, charged parallel metal plates is 300 V. This means that if a positive test charge is moved from one plate to the other, the work done in moving it against the electric field is 300 J per coulomb of charge.

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Our Sun will not become a nova because this phenomenon primarily occurs in stars with a binary companion. The correct option is D.

Novas typically involve a white dwarf star and a companion star in a close binary system. The white dwarf accumulates matter from the companion star, and when the accumulated matter reaches a certain mass, a thermonuclear explosion occurs, leading to a sudden increase in brightness, which we observe as a nova.

Stars that are much less massive or much more massive than the Sun, as well as those without planetary systems, are not the primary factors contributing to a nova event. The key factor is the presence of a binary companion, which allows for the transfer of matter necessary for the explosion to take place.

Since our Sun is a single star without a binary companion, it will not become a nova. Instead, it will eventually exhaust its nuclear fuel and expand into a red giant. Following this phase, it will shed its outer layers and form a planetary nebula, leaving behind a white dwarf at its core, which will eventually cool down over billions of years. So, the correct option is D.

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Answer:

42

Explanation:

range of ball = u×t

= 28×1.5

=42

Answer:

mass energy

Explanation:

because of the kinetic energy

Answer:

Cuba, Jamaica, Dominican Republic, Haiti, Turks & Caicos, and The Bahamas

Explanation:

Answer:

Cuba, Jamaica, Dominican Republic, Haiti, Turks & Ciacos & Bahamas's.

Explanation:

It is (Harder/easier) to push an empty wheelbarrow than one filled with dirt. Because the dirt-filled wheelbarrow has more (Force/Speed/Mass) than the empty one, it requires more (Force/Inertia/Acceleration) to push at the same speed. A wheelbarrow containing grass clippings will require (More/Less/The Same) force to push at the same speed than a dirt-filled one because the grass clippings have less mass than dirt. Either wheelbarrow will require more force to push it uphill than downhill due to the effect of (Friction/Inertia)

The electric field at the origin O is zero since the electric field vectors from the two charges cancel each other out.

Electric fields are areas of force created by stationary electric charges. An electric field is represented by lines of force, which are perpendicular to each other and form concentric circles around the charge. The electric field strength is the force per unit charge, measured in newtons per coulomb (N/C). Electric fields can exist around single charges as well as larger collections of charges. Electric fields are also created between two objects that have different electrical charges, and the strength of the electric field is determined by the amount of charge on each object. Electric fields can be used to create electrical potential energy, and when a charged particle moves through an electric field it will experience a force. Electric fields can also be used to move charged particles and define the path of an electric current.

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Answer:

no they can't talk to each other bcoz of the lack of atmosphere.

Explanation:

l hope it helps you

The correct option is a, all the digits are significant in this measurement, so there are 8.

Here we want to see how many significant digits we have in the measurement:

50.003010

To determine the significant digits in a measurement, follow these rules:

So all the digits in the measurement are significant, the correct option is a.

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The formula currently used for calculating the correlation coefficient was developed by e. Pearson.

Sir Karl Pearson, a British mathematician and statistician, introduced the formula for the Pearson correlation coefficient in the early 20th century. The Pearson correlation coefficient, also known as the Pearson's r, is a measure of the strength and direction of the linear relationship between two variables. The coefficient ranges from -1 to 1, where -1 indicates a perfect negative correlation, 1 indicates a perfect positive correlation, and 0 implies no correlation.

Pearson's correlation coefficient formula has been widely adopted in various fields, such as psychology, finance, and biology, to determine the extent of the relationship between two sets of data. This valuable statistical tool has paved the way for further development and understanding of correlations and their significance in research and data analysis. So therefore the correct answer is e. Pearson is the developer formula currently used for calculating the correlation coefficient.

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Vega and Sirius are both well-known stars that are often mentioned in astronomical and popular culture.

Vega is a bright, blue-white star located 25 light-years from Earth. It is one of the brightest stars in the night sky and is often used as a reference star in various astronomical studies.

Sirius, also known as the Dog Star, is the brightest star in the night sky and is located approximately 8.6 light-years from Earth. It is a binary star system, consisting of a main-sequence star (Sirius A) and a white dwarf star (Sirius B).

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The perpendicular component of a displacement factor with a magnitude of 20 m is 20 m as well. When an object moves from its initial position to a final position, the displacement is the straight-line distance between the two positions and the direction of the displacement is from the initial position to the final position.

A perpendicular component is created when the displacement vector is resolved into two components. When a displacement vector is divided into two perpendicular components, the magnitude of each component is found using the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

This theorem is represented mathematically as: a² + b² = c².Where c is the length of the hypotenuse, and a and b are the lengths of the other two sides of the triangle. In this case, the hypotenuse represents the displacement vector, and the two other sides represent the components of the displacement vector that are perpendicular to each other. Therefore, the perpendicular component of a displacement factor with a magnitude of 20 m is 20 m as well.

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The required radius of the copper cable is approximately 4.18 x 10^(-7) meters.

To determine the required radius of the copper cable, we can use the formula for power loss in a wire:

Power Loss (P) = (I^2) * R

Where I is the current flowing through the wire and R is the resistance of the wire.

Given that the power loss per unit length is 2.00 W/m, we can rewrite the equation as:

Power Loss per Unit Length (P/L) = (I^2) * (R/L)

We know that P/L is 2.00 W/m and I is 310 A.

Since the wire is made of copper, we can use the resistivity of copper to find the resistance per unit length (R/L). The resistivity of copper is approximately 1.7 x 10^(-8) Ω·m.

Plugging in the values, we have:

2.00 W/m = (310 A^2) * (R/L)

Solving for R/L, we get:

R/L = (2.00 W/m) / (310 A^2)

Now, to find the required radius, we can rearrange the equation for resistance per unit length:

R/L = ρ / (π * r^2)

Where ρ is the resistivity of copper and r is the radius of the wire.

Plugging in the values for ρ and R/L, we can solve for r:

(2.00 W/m) / (310 A^2) = (1.7 x 10^(-8) Ω·m) / (π * r^2)

Simplifying further, we get:

r^2 = [(1.7 x 10^(-8) Ω·m) / (π)] / [(2.00 W/m) / (310 A^2)]

r^2 ≈ 1.753 x 10^(-13) m^2

Taking the square root of both sides, we find:

r ≈ 4.18 x 10^(-7) m

Therefore, the required radius of the copper cable is approximately 4.18 x 10^(-7) meters.

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Explanation:

First we have to descompose velocity, and get Velocity of X and Y side:

Vx = V * cos 30°

Vx = 3 m/s * 0,866...

Vx = 2,598 m/s

Vy = V * sen 30°

Vy = 3 m/s * 0,5

Vy = 1,5 m/s

Lets calculate time of fly:

Firat, lets calulate up time:

uT = (Fv - Iv) / g

uT = (0 m/s - 1,5 m/s) / -9,8 m/s^2

uT = -1,5 m/s / -9,8 m/s^2

uT = 0,15 s

Like up time is equal to down time, time of fly will be:

T =uT + dT

T = 0,15 s + 0,15 s

T = 0,3 s

Now for calculate how far will reach, lets aplicate the formula:

d = Vx * T

d = 2,598 m/s * 0,3 s

d = 0,779 meters

Will reach 0,779 meters

Gud luck

Answer:

....

Explanation:

The equation dT/dt = -k(T - To) represents the rate of change of temperature with respect to time, where T is the temperature of the metal ball at a given time, To is the ambient temperature, k is the cooling constant, and dT/dt denotes the derivative of temperature with respect to time.

We can solve this first-order differential equation to find the time it takes for the metal ball to reach a temperature of 40°C.
Given:
Initial temperature (T0) = 100°C
Final temperature (T) = 40°C
Ambient temperature (To) = 30°C
The equation can be rewritten as:
dT / (T - To) = -k dtIntegrating both sides:
∫ dT / (T - To) = -k ∫ dt
Applying the natural logarithm:
ln|T - To| = -kt + C
To determine the constant C, we use the initial condition:
ln|T0 - To| = -k(0) + C
ln|T0 - To| = C
Substituting the values:
ln|100 - 30| = ln|70| = C
The equation becomes:
ln|T - To| = -kt + ln|70|
Now, we can solve for the time it takes for the metal ball to reach a temperature of 40°C.
ln|T - To| = -kt + ln|70|
ln|40 - 30| = -k(t) + ln|70|
ln|10| = -kt + ln|70|
ln(10) - ln(70) = -kt
Simplifying,
ln(10/70) = -kt
Rearranging the equation to solve for time (t):
t = -ln(10/70) / k
To find the value of the cooling constant k, we can use the given information that the metal ball cools from 100°C to 70°C in 15 minutes.
ln(70 - 30) = -k(15)
ln(40) = -15k
Solving for k:
k = -ln(40) / 15
Now we can substitute the value of k into the equation for time (t):
t = -ln(10/70) / (-ln(40) / 15)
t ≈ 10.97 minutes
Therefore, it will take approximately 10.97 minutes for the metal ball to reach a temperature of 40°C.

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Answer:

option 3

Explanation:

work is said to be the ability to move an object from it initial position. therefore, holding a tray is not a work

Answer:

C

Explanation:

a) The resistance will be:

R = V / I = 12 V / 0.80 A = 15 Ω

b) E = P * t = 9.6 W * 60 s = 576 Joules

2) The 75 W lightbulb used at 120 V will have a relative brightness of 18.75 W 120 V bulbs.

a) To calculate the resistance, we can use Ohm's Law, which states that resistance (R) is equal to the voltage (V) divided by the current (I). Therefore, the resistance can be calculated as follows:

R = V / I = 12 V / 0.80 A = 15 Ω

b) The power (P) consumed by the battery can be calculated using the formula: P = V * I, where V is the voltage and I is the current. The energy (E) consumed in a given time period can be calculated by multiplying power (P) by time (t). In this case, since we want to find the energy consumed in a minute, the time is 60 seconds.

P = V * I = 12 V * 0.80 A = 9.6 W

E = P * t = 9.6 W * 60 s = 576 Joules

The power of the lightbulb remains constant regardless of the voltage applied, so the power rating of the lightbulb is still 75 W. However, the brightness of a lightbulb is typically measured in terms of its luminous flux, which is not directly proportional to power. Luminous flux is measured in lumens (lm).

To determine how bright the 75 W lightbulb will be at 120 V relative to 75 W 120 V bulbs, we need to compare the luminous flux. Assuming the lightbulb's resistance remains constant, we can use the formula for power (P) in terms of resistance (R) and voltage (V): P = V^2 / R.

For the 75 W lightbulb at 240 V:

P1 = 75 W

V1 = 240 V

For the lightbulb at 120 V:

P2 = ?

V2 = 120 V

Using the formula, we can solve for P2:

P1 / P2 = (V1 / V2)^2

75 W / P2 = (240 V / 120 V)^2

75 W / P2 = 2^2

75 W / P2 = 4

P2 = 75 W / 4 = 18.75 W

Therefore, the 75 W lightbulb used at 120 V will have a relative brightness of 18.75 W 120 V bulbs.

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In a vacuum chamber, both the golf ball and the ping pong ball experience the same acceleration due to gravity, which is about 9.81 m/s² on Earth.

As there is no air resistance in a vacuum chamber, the only force acting on the balls is gravity. When the balls have fallen halfway down the chamber, they will have the same:
a) Speed: Since they experience the same acceleration, they reach the same speed while falling.
b) Potential energy: Both balls will have lost half of their initial potential energy as they fall halfway down the chamber. Their potential energy depends on their mass, height, and gravity (PE = mgh), and although their masses are different, their heights are the same at the halfway point.
However, they will not have the same:
c) Kinetic energy: Since kinetic energy depends on mass and velocity (KE = 1/2mv²), the golf ball will have more kinetic energy due to its larger mass.
d) Momentum: Momentum depends on mass and velocity (p = mv), so the golf ball will have more momentum due to its larger mass. In summary, the golf ball and ping pong ball will have the same speed and potential energy when they fall halfway down the vacuum chamber, but they will not have the same kinetic energy or momentum.

The force that prevails in a space when no matter is present, or when there is a perfect vacuum, is known as absolute pressure. The starting point for measurements of absolute pressure is this absolute zero. The best example of an absolute referenced pressure is the measurement of barometric pressure. The absolute pressure inside the chamber can be estimated by subtracting the ambient pressure from the vacuum gauge reading. The chamber's absolute pressure is determined by subtracting the vacuum gauge measurement from atmospheric pressure.

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Answer:

The energy transferred to the gas is 9 mJ

Explanation:

Given;

initial volume of the gas, v₁ = 5 x 10⁻⁵ m³

final volume of the gas, v₂ = 4.7 x 10⁻⁵ m³

initial pressure of the gas, P₁ = 5.4 x 10⁴ Pa

final pressure of the gas, P₂ = 5.7 x 10⁴ Pa

The work done in compressing the gas is given by;

W = ΔPV = (P₂ - P₁)(V₂ - V₁)

W = (5.7 x 10⁴ Pa - 5.4 x 10⁴ Pa)(4.7 x 10⁻⁵ m³ - 5 x 10⁻⁵ m³)

W = (3000)( -3 x 10⁻⁶)

W = - 9  x 10⁻³ J

W = -9 mJ

Thus, the work done in compressing this gas is equal to the energy transferred to the gas = 9 mJ