In the 19th century, J. B. A. Dumas devised a method for finding the molar mass of a volatile liquid from the volume, temperature, pressure, and mass of its vapor (next column). He placed a sample of such a liquid in a flask that was closed with a stopper fitted with a narrow tube, immersed the flask in a hot water bath to vaporize the liquid, and then cooled the flask. Find the molar mass of a volatile liquid from the following:
Mass of empty flask = 65.347 g
Mass of flask filled with water at 25° C = 327.4 g
Density of water at 25°C = 0.997 g/mL
Mass of flask plus condensed unknown liquid = 65.739 g
Barometric pressure = 101.2 kPa
Temperature of water bath 5 99.8°C

Answer:

4. c) Lose only 3 electrons

5. d) Nitrogen.

Your answers are correct

Answer:

Atoms and molecules are always moving or vibrating.

Answer:

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Astronomers studying the planet of Rhombus have detected sedimentary rock on its surface. One astronomer wonders if material in this sedimentary rock used to be in igneous rock deep in Rhombus's interior. Can igneous rock become sedimentary rock? Explain your answer

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igneous rocks can form ____, _____ and _____ rock

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Okay so let's answer now the question. So we have here the igneous rock. So the igneous rock, it was formed when lava or magma, okay when magma or lava solidified. So the solidification of the lava or magma resulted to the igneous rock. Now Igneous rock can be sedimentary rock. So this is our first answer. So igneous rocks and sedimentary rocks when the igneous rocks became um ah through weathering and through erosion became sediments. If the igneous rock became sediments and the sediments undergo the process of lit defecation then it will become sedimentary rock. The next rock is we have metamorphic rocks. So Igneous rock can be metamorphic rock if there is an igneous rock that will be subjected in intense he and pressure. So this heat and pressure will transform these the igneous rocks into metamorphic rock and the last time or the next. The next thing is the igneous rock can become big news rock again. Okay so if the igneous rocks will be molten again and then after the molten rocks or the lava or magma solidifies, then it becomes igneous rock. So basically this is our answer. So igneous rock can be a symptom entire Iraq if it becomes sediments through um weathering and erosion and through lift ification process it becomes sedimentary rocks. Next through intensity and pressure. Igneous rock will become metamorphic rock. Next the igneous rock can be another igneous rock. If the big news if the previous igneous rock will be subjected to heat and it will be melted and then after that it solidifies again then it becomes another igneous rock. So here we go. These are the answers. Thank you for listening.

The  X element in the compound = titanium

The chlorine has the molecular weight = 35.5 g/mol

In the compound of Xcl4 , there are four atoms of chlorine molecules who occupy 0.75 of total weight.

The weight of all 4 chlorine atoms = 4×35 = 140 g/mol

Now the total weight of the all chlorine atoms in the compound = 140/0.75

Now the total weight of  the compound = 186.66≈ 187

The weight of X element = 187 - 140 = 47 g /mol

if we match any element from the periodic table , so can find that the titanium has the molecular weight roughly equal to 47.

So The compound is TiCl4 whose molecular weight is 140 g/mol.

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Answer:

d = distance traveled by her on her bicycle on a long flat road = 24 kilometer

t = time taken by her to travel distance "d" on her bicycle on a long flat road = 1.2 hours

v = average speed of vivian = ?

we know that average speed is given as

v = d/t

inserting the values in the above formula

v = 24 kilometer / 1.2 hour

v = 20 kilometer/hour

hence the correct choice is

C) 20 km/h

1. The equation is not balanced. The balanced equation is \(4NH_3 + 5O_2 --- > 4NO +6 H_2O\)

2. The equation is balanced.

3. The equation is not balanced. The balanced version is \(2H_2O --- > 2H_2 + O_2\)

A balanced chemical equation usually has the same number of atoms of different elements in the reactants and the products, even though the forms of the atoms might have changed.

Consider the first equation: \(NH_3 + O_2 --- > NO + H_2O\)

The number of hydrogen atoms is not balanced. Thus, the equation that shows balanced atoms of different elements would be: \(4NH_3 + 5O_2 --- > 4NO +6 H_2O\)

Consider the second equation: \(N_2 + 3H_2 -- > 2NH_3\)

There are 2 atoms of nitrogen in the reactants and there are also 2 in the product. The number of hydrogen atoms is 6 in the reactants and 6 in the products. Thus, it is a balanced equation.

Consider the third equation: \(2H_2O --- > H_2 + O_2\)

There are 4 hydrogen atoms in the reactant and only 2 in the products. The balanced equation would be: \(2H_2O --- > 2H_2 + O_2\)

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Answer:

Because it is the hottest zone

Answer:

the non luminous flames are very hot. little light is produced by non luminous flames.

Answer:

Pros: No vehicle emissions other than water vapor. Fuel economy equivalent to about twice that of gasoline vehicles. Hydrogen is abundant, and can be made from renewable energy. Cons: This space-age technology is expensive.

Answer:

The pros of hydrogen fuel cells are that they are very efficient, producing very little waste. They are also very stable, which makes them safe to use.

The cons of hydrogen fuel cells are that they can be expensive to produce and maintain, and they require a lot of energy to power them, meaning that they often aren't as efficient as they could be.

Despite these pros and cons, hydrogen fuel cells are still a very promising technology. With more research, attention, and development, they could be a powerful force in the fight against carbon emissions and global warming.

The Earth's surface is not covered with the same materials ; however, some areas share similar materials.Several drilling sites have been dug in various regions of the planet to analyze the Earth's surface.

Each drilling site is unique, with differing characteristics and results. Despite these differences, all of the drilling sites analyzed offer scientists a more in-depth knowledge of the Earth's surface.In essence, the scientific drilling sites each had different lithologies, stratigraphies, and geologies. Each site had different types of rocks, depths, and ages, which led to varying drilling conditions, depths, and equipment used. Different types of equipment were also used to reach the depths required, which was a significant difference in each drilling site.The scientific drilling sites also had different purposes. Scientists had specific goals they wanted to achieve at each location. For example, the scientific drilling site in the Iceland region was focused on analyzing a unique layer of igneous rocks. The primary objective was to investigate the formation of the rock layer.The same materials were not found at each scientific drilling site.

Still, they had some similarities. They all provided geologists with vital information about the Earth's surface. The data provided from each drilling site was used to piece together the Earth's geologic history and how it has changed over time.

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9514 1404 393

Answer:

  Meteor: A streak of light made when an object burns up as it enters Earth's atmosphere

Explanation:

A meteorite is an object that has come from space and hit Earth.

A comet is a space object that develops a tail as it nears the sun. It is believed to be a mixture of dust and ice. In general, a comet will appear stationary in the night sky, since it moves rather slowly relative the starry background.

A meteor is a space object that makes a streak of light across the sky as it burns up in the atmosphere. (It may or may not become a meteorite, depending on the degree to which it burns up.)

__

UFOs have also been known to make streaks of light when moving across the sky.

Answer:

A streak of light made when an object burns up as it enters Earth's atmosphere

Explanation:

100 % 2021  

Answer:

the products are more stable than the reactants

Explanation:

Considering a low-mass atom, such as helium or lithium, the possible atomic terms for the electron configuration np1nd1 would be 2P1 and 2D1.

The term that is likely to lie lowest in energy would be 2P1, as it has a lower angular momentum quantum number (l=1) compared to 2D1 (l=2), resulting in a lower energy state.

For n = 2 and l = 1, the possible values of S and L are 1/2 and 1, respectively. Thus, the term notation for np1 is ^2P.

For n = 2 and l = 2, the possible values of S and L are 1/2 and 2, respectively. Thus, the term notation for nd1 is ^2D.

Combining the terms ^2P and ^2D, we get the possible atomic terms as ^2P^2D.

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Answer:If we dissolve NaF in water, we get the following equilibrium:

text{F}^-(aq)+text{H}_2text{O}(l) rightleftarrows text{HF}(aq)+text{OH}^-(aq)

The pH of the resulting solution can be determined if the  K_b of the fluoride ion is known.

20.0 g of sodium fluoride is dissolve in enough water to make 500.0 mL of solution. Calculate the pH of the solution. The  K_b of the fluoride ion is 1.4 × 10 −11 .

Step 1: List the known values and plan the problem.

Known

mass NaF = 20.0 g

molar mass NaF = 41.99 g/mol

volume solution = 0.500 L

K_b of F – = 1.4 × 10 −11

Unknown

pH of solution = ?

The molarity of the F − solution can be calculated from the mass, molar mass, and solution volume. Since NaF completely dissociates, the molarity of the NaF is equal to the molarity of the F − ion. An ICE Table (below) can be used to calculate the concentration of OH − produced and then the pH of the solution.

Explanation:

Answer:

not sure if this is 100% correct but this is what i got first question: molarity=mol/L 5g*1mol/58.44g=5/58.44 =0.085558mol 4.8m=0.085558/L L=0.0178

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second question: pH = - log [H3O+] pH= -log [4.6*10^-9] = 8.33724216

Explanation:

Answer:

See the answer below

Explanation:

When a solution of iodine is mixed with a solution of tetrachloromethane, the mixture turns purple due to the formation of \(I_2(CCl_4)\).

Iodine solution dissolves in carbon tetrachloride solution (another name for tetrachloromethane) due to the fact that both solutions are similarly non polar in nature. The equation of the reaction is as shown below:

            \(I_2 + CCl_4 --> I_2(CCl_4)\)

The answer is (a) 3.52 g, which is the closest value to the calculated maximum mass of Li3N.

To determine the maximum mass of Li3N that can be produced, we need to use stoichiometry and determine which of the reactants is the limiting reagent.

First, we need to determine the number of moles of each reactant:

moles of Li = 3.50 g / 6.94 g/mol = 0.503 mol

moles of N2 = 3.50 g / 28.02 g/mol = 0.125 mol

According to the balanced equation, 6 moles of Li react with 1 mole of N2 to produce 2 moles of Li3N. Therefore, the limiting reagent is N2 since only 0.125 moles are available, which is not enough to completely react with all the Li.

Using the mole ratio from the balanced equation, we can calculate the maximum mass of Li3N that can be produced:

0.125 mol N2 × (2 mol Li3N / 1 mol N2) × (50.94 g Li3N / 1 mol Li3N) = 3.23 g Li3N

Therefore, the answer is (a) 3.52 g, which is the closest value to the calculated maximum mass of Li3N.

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To calculate the subscripts in the actual molecular formula, we first have to find out the empirical formula of the given compound. Empirical formula mass is the sum of the atomic masses of all the atoms in a formula unit of the empirical formula of a compound.

To calculate the empirical formula mass, we add up the atomic masses of all the atoms present in a molecule of a compound. Using the molecular formula mass and empirical formula mass, we can calculate the actual molecular formula of the compound. The subscripts in the actual molecular formula are calculated by dividing the molecular formula mass of the compound by the empirical formula mass of the compound. Let's consider an example to understand how to calculate the subscripts in the actual molecular formula.

Example:

The empirical formula of a compound is CH2O, and the molecular formula mass of the compound is 180 amu. The empirical formula mass can be calculated using the formula:

Empirical formula mass = sum of atomic masses of atoms in the empirical formula

= (1 × atomic mass of C) + (2 × atomic mass of H) + (1 × atomic mass of O)

= (1 × 12.01 amu) + (2 × 1.01 amu) + (1 × 16.00 amu)

= 30.03 amu

Molecular formula mass = 180 amu

Now, we can calculate the ratio of the molecular formula mass to the empirical formula mass as:

180 amu ÷ 30.03 amu

= 6

The actual molecular formula will have six times the number of atoms as the empirical formula: C6H12O6. Therefore, the subscripts in the actual molecular formula of the compound are C6H12O6.

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The subscripts of a molecular formula, where its mass is known, can only be determined when the elements in the compound are specified. The subscripts in this case are the ratios of these elements. Without these, one can only give hypothetical answers, like a carbon dioxide compound repeated five times which gives subscripts of 5 (C5O10).

To deteremine the subscripts in the actual molecular formula, one first needs to know the formula of the compound itself. Without knowing the elements in the compound, we cannot ascertain the subscripts from the molecular formula mass. For example, if the compound is carbon dioxide (CO2), and knowing that the molecular mass of carbon (C) is approximately 12 amu and oxygen (O) is 16 amu, we know that two oxygens (16 * 2) with one carbon (12) has a total mass of 44 amu. Repeating this compound 5 times (as 240 is 5 times 44) would imply, in this hypothetical case, subscripts of 5, making the compound C5O10 . However, to get actual subscripts we need specifics about the compound's elements.

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The \(Br^{-}\) describes the reducing agent in the reaction below.

\(Cl_{2} (aq) + 2Br^{-} (aq)\) → \(2Cl^{-}(aq) + Br_{2}( aq)\)

Reducing agent is the species in which oxidation is takes place. Reducing agent is the species in which loss of electrons is takes place. In the above reaction bromine ion in left hand side of the reaction loss electron to become bromine atom. So, bromine ion is reducing agent.

Oxidizing agent is the species in which reduction is takes place. Oxidizing agent is the species in which gain of electrons is takes place. In the above reaction chlorine atom in right hand side of the reaction gain electron to become chlorine ion. So, chlorine atom is reducing agent.

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Answer:

These munitions typically use radio signals from the global positioning system (GPS), laser guidance, and inertial navigation systems (INS)—using gyroscopes—to improve a weapon's accuracy to reportedly less than 3 meters (approximately 10 feet).

The atomic weight of the metal is 36 g/mol.

To solve this problem, we need to use the concept of equivalent weight. The equivalent weight of a divalent metal is equal to its atomic weight divided by its valency, which in this case is 2.

First, let's calculate the number of equivalents of H2SO4 present in the solution.

4.9 g of H2SO4 per liter of solution means that there are 4.9/98 = 0.05 moles of H2SO4 per liter.

So in 250 cc (or 0.25 liters) of solution, there are 0.05 x 0.25 = 0.0125 moles of H2SO4.

Since H2SO4 is a diprotic acid, each mole of H2SO4 can donate 2 equivalents of H+. Therefore, the total number of equivalents of H+ present in the solution is 2 x 0.0125 = 0.025.

Now let's calculate the number of equivalents of alkali (which we know is N/10 or 0.1 N) required to neutralize 50 cc of the solution.

20 cc of N/10 alkali is equal to 0.002 equivalents of alkali (since N/10 alkali has a normality of 0.1, which means it can donate 0.1 equivalents of OH- per liter of solution).

Since the acid and alkali react in a 1:1 ratio, this means that there are also 0.002 equivalents of H+ in 50 cc of the solution.

Therefore, the initial number of equivalents of H+ in the solution must have been 0.025 + 0.002 = 0.027.

Now we can use this information to calculate the number of equivalents of metal present in the solution.

Since the metal is divalent, it will donate 2 equivalents of metal ions for every 1 equivalent of H+ that it reacts with.

Therefore, the number of equivalents of metal present in the solution is 0.027/2 = 0.0135.

Finally, we can calculate the atomic weight of the metal using the formula:

Atomic weight = Equivalent weight x Valency

In this case, the equivalent weight is equal to the atomic weight divided by 2 (since the metal is divalent).

So:

Atomic weight = Equivalent weight x 2

Atomic weight = (0.018 g / 0.0135 equivalents) x 2

Atomic weight = 36 g/mol

Therefore, the atomic weight of the metal is 36 g/mol.

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neutron activation analysis for a sample of a rock revealed the presence of 140 56ba , which has a half-life of 12.5 days . assuming the isotope was freshly separated from its decay products, 13.4 ng is the mass of 140 56ba in a sample emitting 1.00 mci of radiation

radiation = 1.00 mCi, radiation = 1.00 x 10-3 Ci, radiation = 1.00 x 10-3 Ci * (3.7 x 1010 dps / 1 Ci), radiation = 3.7 x 107 dps, half life = 12.5 days, half life = 12.5 days * (24 hr / day) * (3600 s / hr), half life = 1.08 x 106 secondsdecay constant = 6.418 x 10-7 s-1number of disintegrations = 5.765 x 1013number of moles = 9.57 x 10-11 mol mass Ba-140 = (number of moles) * (molar mass Ba-140), mass Ba-140 = (9.57 x 10-11 mol) * (139.911 g/mol), mass Ba-140 = 1.34 x 10-8 g, mass Ba-140 = 13.4 ng   (where ng = nanogram). Isotopes are atoms and have the same amount of protons but different neutron numbers. They have nearly identical chemical properties but vary in mass and thus in physical properties. An isotope is one of two or more types of atoms of a chemical element that have the same number of protons and position in the periodic table as well as remarkably similar chemical actions but differ in atomic mass and physical properties. The term "daughter products" refers to decay products. They are radionuclides formed thru the nuclear reactions of parent radionuclides.

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Answer:

The correct answer is 15.54 kJ per degree C.

Explanation:

The enthalpy change for one mole of a substance, which combines or burns with the oxygen under the standard conditions, that is, at 25 degree C and 1 bar pressure is known as the standard molar enthalpy of combustion. The amount of heat transferred can be calculated by using the formula, q = mcΔT -------------(i)

Here q is the amount of heat transferred, c is the specific heat, ΔT is the change in temperature, and m is the mass of the substance. As in case of bomb calorimeter, mass if considered constant, thus, for calorimeter the equation mentioned will become, q = cΔT ---- (ii)

The standard molar enthalpy of combustion for carbon is -393.5 kJ/mol, that is, -393.5 kJ per mole of heat is generated by burning one mole of carbon. The molecular mass of carbon is 12 gram per mole.  

Thus, the number of moles of carbon equivalent to 0.562 grams of carbon can be determined as,  

Number of moles of carbon = mass / molecular mas

= 0.562 grams / 12 gram per mole

= 0.047 mol

The heat generated by burning 0.562 grams or 0.047 mole will be,  

q = ΔH° × number of moles

= (-393.51 kJ/mol) × 0.047 mol

= -18.49 kJ, the negative sign shows that the heat is produced.  

To find heat capacity of calorimeter, put the value of q as -18.49 kJ, for ΔT as (27.93 °C - 26.74 °C) in the equation (ii)

18.49 kJ = c × (27.93 - 26.74)

c = 18.49 kJ/1.19 °C

c = 15.54 kJ/°C

The approximate bond angle for a molecule with a t-shape molecular geometry is d. 109.5°. This is because the three bonded atoms in this geometry are arranged in a trigonal bipyramidal arrangement, with bond angles of 120° between them.

However, the presence of the two lone pairs of electrons pushes the bonded atoms closer together, reducing the bond angle to 109.5°. This is known as the distorted tetrahedral angle.

The t-shape molecular geometry is a type of molecular shape where there are three bonded atoms and two lone pairs of electrons. This geometry is typically found in molecules such as ClF3. In this geometry, the bond angles between the atoms are not all the same. The two lone pairs of electrons occupy two of the equatorial positions, while the three bonded atoms occupy one equatorial and two axial positions.
It is important to note that the bond angles in a molecule with t-shape molecular geometry may not be exactly 109.5° due to various factors such as lone pair-bonded atom repulsion and bond-bond repulsion. Nonetheless, this value serves as a good approximation for the bond angle in this molecular geometry.

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To ensure safety while carrying out her experiment, Maria should follow proper laboratory protocols and take necessary precautions like handle equipment and glassware carefully,wear appropriate personal protective equipment (PPE),read safety data sheets (SDS) to understand the proper handling,never work alone in the laboratory,etc.

Here are some recommendations:

1.Wear appropriate personal protective equipment (PPE), including safety goggles, lab coat, and gloves, to protect her eyes, body, and hands from potential hazards.

2.Familiarize herself with the properties and potential risks associated with the chemicals she will be working with. Read safety data sheets (SDS) to understand the proper handling, storage, and disposal procedures.

3.Work in a well-ventilated area or use a fume hood to minimize exposure to any fumes or gases that may be generated during the experiment.

4.Handle equipment and glassware carefully to prevent accidents or breakages. Ensure that all equipment is in good condition and appropriate for the experiment.

5.Follow proper techniques for measuring, mixing, and transferring chemicals to prevent spills or splashes. Use appropriate containers and labels to clearly identify and store chemicals.

6.Be aware of emergency procedures, including the location of safety equipment such as fire extinguishers, eyewash stations, and emergency showers.

7.Never work alone in the laboratory. Inform a supervisor or lab mate about the experiment and maintain communication throughout the process.

By following these safety measures, Maria can minimize risks and ensure a safe working environment during her experiment.

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The ratio of carbon bond with fluorine to form a stable compound is 1:4.

All organofluorine compounds have the polar covalent bond between fluorine and carbon known as the carbon-fluorine bond. Due to its partly ionic nature, it is one of the chemical world's strongest single bonds and is also relatively short.

It is a covalent bond between a carbon atom and a fluorine atom in a molecule. It is one of the strongest single bonds found in organic chemistry due to the high electronegativity of fluorine, which attracts electrons away from the carbon atom and makes the bond very polar.

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Answer:

Sulfur and Nitrogen

Explanation:

Molecular compounds are formed mostly when nonmetals combine. Usually electrons are shared between atoms in the covalent bond.

Sulphur and nitrogen are nonmetals whose difference in electronegativity is not much. Hence they form a molecular compound.

Answer: A

Explanation: A

From the calculation, Suzanne is lying and she is guilty of killing her husband.

Stoichiometry provides a means of calculating the relationship between mass and mole or mole and volume in a reaction.

Now the preparation of ethylbenzene goes according to the reaction;

C6H6 + C2H6 ---->C6H5C2H5 + H2

Number of moles of benzene =  15 g/78 g/mol = 0.192 moles

Number of moles of ethyl benzene= 25 g/106 g/mol = 0.236 moles

Since the reaction is 1:1, 0.192 moles of ethyl benzene is produced.

Mass of 0.192 moles  of ethylbenzene =  0.192 moles * 106 g/mol = 20.4 g

Suzanne is lying.

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The AH value for the combustion of ethane, as represented by the given balanced chemical equation, is -1560.6 kJ/mol. The energy is absorbed during this reaction.

In the balanced chemical equation provided, 2 moles of ethane (C₂H6) react with 7 moles of oxygen gas (O2) to produce 4 moles of carbon dioxide (CO₂) and 6 moles of water vapor (H₂O). The AH value represents the change in enthalpy, or heat, during the reaction per mole of reactant.

To determine the AH value, we can look at the coefficients of the reactants and products in the balanced equation. In this case, 2 moles of ethane react to produce 4 moles of carbon dioxide and 6 moles of water vapor. The AH value is calculated per mole of reactant, so we can divide the AH value by the number of moles of ethane (2) to get the AH value per mole of ethane.

The given value of -84.7 kJ is the AH value per mole of ethane, so we need to multiply it by the number of moles of ethane in the balanced equation (2) to get the total AH value for the reaction. Therefore, the AH value is -84.7 kJ/mol × 2 mol = -169.4 kJ.

However, it's important to note that the given AH value (-84.7 kJ) appears to be incorrect in the question. The actual value for the combustion of ethane is around -1560.6 kJ/mol. This value represents the energy released or absorbed during the reaction. In this case, the negative sign indicates that energy is absorbed, meaning the reaction is endothermic.

In summary, the AH value for the combustion of ethane is -1560.6 kJ/mol, and the energy is absorbed during the reaction.

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