in the diagram below O is circumscribed about quadrilateral. what is value of x?​

Answer:

y= -3x -3

Step-by-step explanation:

The unit of measurement used to describe how far a set of values are from the mean is the standard deviation. Therefore, the correct answer is (b) standard deviation.

The variance is another measure of spread, but it is not in the form of the original units of measurement. The median is a measure of central tendency and not a measure of spread. The mode is the most frequently occurring value in a set and is also not a measure of spread.
The unit of measurement used to describe how far a set of values are from the mean is the Standard Deviation (b). It is calculated by taking the square root of the variance and provides a measure of the average distance between each value in the set and the mean. The Median (c), on the other hand, is the middle value in a set when the values are arranged in numerical order.

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We have evaluated the limit of the given function f(x) which is lim f(x) = -20 and lim f(x) = -6.

To evaluate lim f(x) and lim f(x), we need to simplify the given function f(x) first. Let's simplify the given function f(x) using the formula a²-b²=(a+b)(a-b).

f(x) = -4 - 2x² + 2x - 2x - 2x²= -4 - 4x² + 2x

Now, we can evaluate the limit of the given function lim f(x) and lim f(x)

.lim f(x)=lim [-4-4x²+2x]= -4 - 4*8 + 2*8= -20

Here, we have used the following substitution x→8 since it was already given in the function f(x).So, lim f(x) = -20Therefore, the limit of the given function is

-20lim f(x) = lim [-4-4x²+2x]= -4 - 4*1 + 2*1= -6

Here, we have used the following substitution x→1 since it was already given in the function f(x).So, lim f(x) = -6Therefore, the limit of the given function is -6.

Thus, we have evaluated the limit of the given function f(x) which is lim f(x) = -20 and lim f(x) = -6.

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The length of the row will be equal to 900''.

The measure of the size of any object or the distance between the two endpoints will be termed the length.

Given that:-

Number of the chairs = 50

Size of the chair = 18''

Now the size of the row will be:-

Size of the row =  50  x  18  =  900''

Therefore the length of the row will be equal to 900''.

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The answer is 104°.

.. .. ..

Answer:

Step-by-step explanation:

A line is always equal to 180. So if angle POR is 76, you would do 180-76 which equals 104.

Answer:

square root of 148

Step-by-step explanation:

distance formula: d=√(x2−x1)^2+(y2−y1)^2

d√=(-5--3)^2+(11--1)^2

d=√(-2)^2+(12)^2

d=√4+144

d=√148

Answer:

5^12

Step-by-step explanation:

Answer:

$23.12

Step-by-step explanation:

you'll need 3 sides so take 8×2.89

answer is $23.12

Answer:

B

Step-by-step explanation:

Answer:

96 dollars

Step-by-step explanation:

60 percent of 11500 is 6900

11500-6900=4600

4600÷48=95.8

round it up to 96

96 is your answer

Using line tangent, the approximation for f(2.1) is 3.95

Given,

The point (a, f(a)) is on the line tangent to the graph of y = f(x) at x = a, which has a slope of f'(a).

The equation be like;

y - f(a) / (x - a) = f'(a)

y = f'(a) (x - a) + f(a)

Using the provided data and a = 2, we can determine that the tangent line to the graph of y = f(x) at x = 2 has equation

y = f'(2) (x - 2) + f(2)

y = -1/2 (x - 2) + 4

To compute a "approximation of f(2.1) using the line tangent to the graph of f at x = 2," one must substitute x = 2.1 for f in the equation for the tangent line (2.1). You get 2.1 when you plug this in.

y = -1/2 (x - 2) + 4

y = -1/2 (2.1 - 2) + 4

y = -1/2 x 0.1 + 4

y = 3.95

That is,

The approximation for f(2.1) using line tangent is 3.95

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Question:

James has 14,500g of sand in his sandbox. He brings home another 7,400g of sand from the beach to add to his sandbox. How many kilograms of sand does James have in his sandbox now?

Answer:

The quantity of sandbox James has is 21.9kg

Step-by-step explanation:

Given

Initial quantity of sandbox = 14,500 g

Additional quantity = 7,400 g

Required

Total quantity of sandbox in kg

Tp get the total quantity of sandbox, we simply add in the initial and additional quantity of sandbox together;

This is represented mathematically as follows;

Total = Initial Quantity + Additional Quantity

Total = 14,500 g + 7,400 g

Total = 21,900 g

But the question says the answer should be in kg

1000 g is equivalent to 1 kg

21,900 g will be equivalent to \(\frac{21,900}{1,000} kg\)

\(21,900g = \frac{21,900}{1,000} kg\)

\(21,900g = 21.9 kg\)

Hence, the quantity of sandbox James has is 21.9kg

Answer:

38.1

Step-by-step explanation:

The z score associated with the highest 10% is closest to: option (c) 1.28

-To find the z score associated with the highest 10%, first determine the percentage that corresponds to the lower 90%, since the z score table typically represents the area to the left of the z score.

- Look up the 0.90 (90%) in a standard normal distribution  (z score) table, which will give you the corresponding z score.

-The z score closest to 0.90 in the table is 1.28, which corresponds to the highest 10% of values.

Therefore, the z score associated with the highest 10% is closest to 1.28.

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Answer:

6 and 4

Step-by-step explanation:

Answer:

Part A: 4 and x are factors of 4x

Part B: 6 and 4

Part C:  4

Step-by-step explanation:

This can be derived using Chebyshev's inequality, as Chebyshev's inequality and the law of large numbers are different in nature.

Let M_n be the maximum of n independent U(0, 1) random variables.

To derive the exact expression for P(|M_n − 1| > ε), we need to follow the below steps:

First, we determine P(M_n ≤ 1-ε). The probability that all of the n variables are less than 1-ε is (1-ε)^n

So, P(M_n ≤ 1-ε) = (1-ε)^n

Similarly, we determine P(M_n ≥ 1+ε), which is equal to the probability that all the n variables are greater than 1+\epsilon

Hence, P(M_n ≥ 1+ε) = (1-ε)^n

Now we can write P(|M_n-1|>ε)=1-P(M_n≤1-ε)-P(M_n≥1+ε)

P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n.

Thus we have derived the exact expression for P(|M_n − 1| > ε) as P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n

Now, to show that $lim_{n\to\∞}$ P(|M_n - 1| > ε) = 0 , we can use Chebyshev's inequality which states that P(|X-\mu|>ε)≤{Var(X)/ε^2}

Chebyshev's inequality and the law of large numbers are different in nature as Chebyshev's inequality gives the upper bound for the probability of deviation of a random variable from its expected value. On the other hand, the law of large numbers provides information about how the sample mean approaches the population mean as the sample size increases.

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Answer:

the mean in all of the numbers added together devided by how many numbers there are so it would be 8.4, and the median is the middle so it would be 9.

Step-by-step explanation:

your welcome

Answer:

-14z^2-5zw+5z-2w^2+6w

Step-by-step explanation:

2z(4w+3z-5)-(2w+5z)(1w+4z-3)

8zw+6z^2-10z-\left(2w+5z)(w+4z-3)

8zw+6z^2-10z-20z^2-13zw+15z-2w^2+6w

-14z^2-5zw+5z-2w^2+6w

F(x - 7)=2x - 10

Step-by-step explanation:

F(x)=2x+4 translation 7 units left is given as:

\(F(x - 7)=2(x - 7)+4 \\ \\ F(x - 7)=2x - 14+4 \\ \\ \purple{ \boxed{F(x - 7)=2x - 10 }} \\ \\ \)

The correct relative frequency and the conclusion based on the table is B. The relative frequency for traveling out of state for longer than a week is 48%. This could be high because people want to spend more time if they have traveled farther.

Given a table.

Relative frequency of a data set is defined as the ratio of the number of outcomes that occured by the total number of trials.

Total number of surveys = 100

Relative frequency for traveling in state for longer than a week is,

10/100 = 10%

Relative frequency for traveling out of state for longer than a week is,

48/100 = 48%

This must be true since people will be more likely to spend more time if they travelled farther.

Hence the correct option is B.

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The task is to determine if there is evidence to conclude that the mean weight of six-year-old girls in the United States was lower in 2006 than in 2002. Data from the NHANES surveys conducted

To test the hypothesis, we can set up the null and alternative hypotheses as follows:

Null Hypothesis (H0): The mean weight of six-year-old girls in 2006 is not lower than the mean weight in 2002.

Alternative Hypothesis (H1): The mean weight of six-year-old girls in 2006 is lower than the mean weight in 2002.

Next, we can compute the p-value using the T1-84 calculator or statistical software. The p-value is the probability of obtaining a sample mean as extreme or more extreme than the observed sample mean, assuming the null hypothesis is true.

Using the provided data, the sample mean in 2002 is 49.3 pounds, the sample mean in 2006 is 48.8 pounds, and the population standard deviation is 15.2 pounds. We can calculate the p-value by performing a one-sample t-test, comparing the sample mean of 48.8 pounds to the hypothesized population mean of 49.3 pounds.

After calculating the p-value, we compare it to the significance level of 0.10. If the p-value is less than 0.10, we can reject the null hypothesis and conclude that the mean weight of six-year-old girls in 2006 is lower than in 2002. If the p-value is greater than or equal to 0.10, we fail to reject the null hypothesis and do not have sufficient evidence to conclude that the mean weight is lower.

Note: Since the specific p-value calculation requires detailed statistical calculations, I am unable to generate the exact value without access to a calculator or statistical software.

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Answer:

it's your answer

I hope it's help you

The length and breadth of the plot are 33 cm and 16 cm, respectively

Represent the length with x and the breadth with y.

So, we have:

x = 1 + 2y

The area of a rectangular plot is:

Area = xy

The area is given as 528.

So, we have:

\(xy = 528\)

Substitute 1 + 2y for x

\((1 +2y)y = 528\)

Open the brackets

\(y + 2y^2 = 528\)

Rewrite as:

\(2y^2 + y - 528 = 0\)

Using a graphing calculator, we have:

y =-16.5 and y = 16

The dimension cannot be negative.

So, we have:

y = 16

Recall that:

x = 1 + 2y

This gives

\(x = 1 + 2*16\)

\(x = 33\)

Hence, the length and breadth of the plot are 33 cm and 16 cm, respectively

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Answer:

To find the speed of the boat in still water, we can use the formula:

Speed in still water = (Downstream speed + Upstream speed) / 2

We know that the speed of the current is 1.5 km/h and the boat can travel twice the distance downstream as it can travel upstream. Therefore, if the boat travels x km downstream in one hour, it travels x/2 km upstream in one hour.

We can use this information to set up the following equation:

x + (x/2) = (x + x/2) = (3/2)x = Downstream speed

And the upstream speed is x/2

Now we can substitute this value into the formula for speed in still water:

Speed in still water = ( (3/2)x + (x/2) )/2 = (3x + x)/4 = x = (3+1) km/h = 4 km/h

So, the speed of the boat in stillwater is 4 km/h.

We don't know the exact distance that the boat travels downstream in one hour, so we can't calculate the speed in still water with the given information. To find the speed in still water we need to know the distance traveled downstream or upstream.

Answer:

The most important characteristic of a correlation coefficient is the absolute value.

The absolute value of a correlation coefficient represents the strength of the relationship between two variables, regardless of the direction of the relationship. A correlation coefficient can range from -1 to +1, where a value of -1 indicates a perfect negative correlation (i.e., as one variable increases, the other decreases), a value of +1 indicates a perfect positive correlation (i.e., as one variable increases, the other also increases), and a value of 0 indicates no correlation (i.e., there is no relationship between the variables).

The most important characteristic of a correlation coefficient is the absolute value.

The absolute value of the correlation coefficient represents the strength of the relationship between two variables, regardless of its direction. It indicates the degree to which the variables are associated with each other.

By focusing on the absolute value, we can assess the magnitude of the correlation without being influenced by whether it is positive or negative. For example, a correlation coefficient of -0.8 or +0.8 both indicate a strong relationship, while a correlation coefficient of 0 suggests no relationship.

The number of variables included is not a characteristic of the correlation coefficient itself, but rather a consideration in the analysis. One-tailed and two-tailed refer to the type of hypothesis being tested and are relevant in statistical testing. However, the absolute value of the correlation coefficient is crucial in determining the strength of the relationship between variables, making it the most important characteristic to assess in correlation analysis.

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Answer:

he is correct because 20% is the same thing as 1/5 amd 1/5 is the same thing as dividing by 5

Step-by-step explanation: