Answer:
A
Step-by-step explanation:
Because B corresponds with 80 and a line segment is 180 degrees b + a =180 and a would be 100.
Mr. Garcia has 11 boys and 13 girls in his math class. He selects two students at random to demonstrate how they solved the day’s challenge assignment. What is the probability that both students chosen in a row are girls
Answer:
29%
Step-by-step explanation:
Amount of girls in his class: 13/24
13/24 x 13/24 = 169/576 or 0.2934...
Basically, 29%
in the following equation , what happens to the value of y when the value of x is divided by 6 y=3/x
The value of y is multiplied by 6 when x is divided by 6
How to determine what happens to yFrom the question, we have the following parameters that can be used in our computation:
y = 3/x
Also, from the question we understand that
x is divied by 6
This means that the new equation is
y = 3/(x/6)
Evaluate
y = 6 * 3/x
This means that the new value of y is multiplied by 6
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a 12 cm cube is built from small cubes, each 2 cm on an edge. write a ratio that compares the edge lengths of the large and small cubes.
The ratio of the edge lengths of the large and small cubes is 6:1
The ratio that compares the edge lengths of the large and small cubes is the ratio of the length of the edge of the large cube to the length of the edge of the small cube.
The edge length of the large cube is 12 cm and the edge length of the small cube is 2 cm. To find the ratio, we divide the length of the large cube by the length of the small cube.
So the ratio of the edge length of the large cube to the small cube is:
12cm/2cm = 6
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Select the answer that correctly orders the set of numbers from greatest to least.
0.25, start fraction 2 over 5 end fraction , 32%, start fraction 7 over 14 end fraction
A. start fraction 7 over 14 end fraction, start fraction 2 over 5 end fraction, 32%, 0.25
B. start fraction 7 over 14 end fraction, 0.25, 32%, start fraction 2 over 5 end fraction
C. start fraction 7 over 14 end fraction, 32%, start fraction 2 over 5 end fraction ,0.25
D. start fraction 2 over 5 end fraction, start fraction 7 over 14 end fraction, 32%, 0.25
Answer:
I think the answer would be C, I hope it helps! :) please mark me the brainiest
Find the values of the constant c which makes the function continuous on the [cx¹ +7cxª³+2, x < -1 interval (-[infinity]0,00): f(x) = Ac-2² -cr. T>1
For any value of c, the equation holds true, meaning the function is continuous at x = -1 for all values of c. Any value of c will make the function continuous on the interval (−∞, 0) and (0, ∞).
To find the values of the constant c that make the function continuous on the interval (−∞, 0) and (0, ∞), we need to ensure that the left-hand limit and the right-hand limit of the function are equal at the point of discontinuity, which is x = -1.
First, let's find the left-hand limit of the function as x approaches -1. We substitute x = -1 into the function:
lim(x → -1-) f(x) = lim(x → -1-) (Ac^2 - cr)
Next, let's find the right-hand limit of the function as x approaches -1:
lim(x → -1+) f(x) = lim(x → -1+) (Ac^2 - cr)
To make the function continuous at x = -1, the left-hand limit and the right-hand limit must be equal:
lim(x → -1-) f(x) = lim(x → -1+) f(x)
Now, let's evaluate the left-hand and right-hand limits:
lim(x → -1-) (Ac^2 - cr) = lim(x → -1+) (Ac^2 - cr)
Simplifying the expressions:
(Ac^2 - c(-1)) = (Ac^2 - c(-1))
Ac^2 + c = Ac^2 + c
The c terms cancel out, leaving:
Ac^2 = Ac^2
We can see that for any value of c, the equation holds true, meaning the function is continuous at x = -1 for all values of c.
Therefore, any value of c will make the function continuous on the interval (−∞, 0) and (0, ∞).
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) Suppose that a random variable X represents the output of a civil engineering process and that X is uniformly distributed. The PDF of X is equal to 1 for any positive x smaller than or equal to 2, and it is 0 otherwise. If you take a random sample of 12 observations, what is the approximate probability distribution of X − 10? (You need to find the m
The approximate probability distribution of X - 10 is a constant distribution with a PDF of 1/2 for -10 ≤ y ≤ -8.
To find the probability distribution of X - 10, where X is a uniformly distributed random variable with a PDF equal to 1 for any positive x smaller than or equal to 2, we need to determine the PDF of X - 10.
Let Y = X - 10 be the random variable representing the difference between X and 10. We need to find the PDF of Y.
The transformation from X to Y can be obtained as follows:
Y = X - 10
X = Y + 10
To find the PDF of Y, we need to find the cumulative distribution function (CDF) of Y and differentiate it to obtain the PDF.
The CDF of Y can be obtained as follows:
\(F_Y(y)\) = P(Y ≤ y) = P(X - 10 ≤ y) = P(X ≤ y + 10)
Since X is uniformly distributed with a PDF of 1 for any positive x smaller than or equal to 2, the CDF of X is given by:
\(F_X(x)\) = P(X ≤ x) = x/2 for 0 ≤ x ≤ 2
Now, substituting y + 10 for x, we get:
\(F_Y(y)\) = P(X ≤ y + 10) = (y + 10)/2 for 0 ≤ y + 10 ≤ 2
Simplifying the inequality, we have:
0 ≤ y + 10 ≤ 2
-10 ≤ y ≤ -8
Since the interval for y is between -10 and -8, the CDF of Y is:
\(F_Y(y)\) = (y + 10)/2 for -10 ≤ y ≤ -8
To obtain the PDF of Y, we differentiate the CDF with respect to y:
\(f_Y(y)\) = d/dy [F_Y(y)] = 1/2 for -10 ≤ y ≤ -8
Therefore, the approximate probability distribution of X - 10 is a constant distribution with a PDF of 1/2 for -10 ≤ y ≤ -8.
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A rectangular television is 45 inches by 30 inches. What is the length of its diagonal?
Answer:
54.1 inches (round to 1 dp)
Step-by-step explanation:
the formula to calculate the diagonal or a rectangle is
\(\sqrt{(w^{2} +l^{2})}\)
30^2+45^2 is 2925
and \(\sqrt{2925}\)
and the answer to that is 54.1 inches (to 1 dp)
If two mathematically similar shapes have a scale factor of volume of 64, what is the scale factor of length?
Answer:
4
Step-by-step explanation:
Given scale factor of lengths k , then
scale factor of volumes = k³
Here scale factor of volume = 64 , then
scale factor of length = \(\sqrt[3]{64}\) = 4
The scale factor of length of the shape is calculated as: 4.
How to find the find the scale factor?When two shapes are mathematically similar, it means that their corresponding sides are proportional, and the scale factor of length is the same as the scale factor of volume raised to the power of 1/3 (since volume is a three-dimensional concept).
Given that the scale factor of volume is 64, we can find the scale factor of length as follows:
Scale factor of length = Scale factor of volume^(1/3)
Scale factor of length = 64^(1/3)
Scale factor of length = ∛64 = 4
The scale factor of length is 4.
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The diagram at the right shows some
dimensions of Cominskey Park in
Chicago, Illinois. BD is a segment from
home plate to dead center field, and AE is
a segment from the left field foul-ball pole
to the right field foul-ball pole. If the
center fielder is standing at C, how far is
he from home plate?
The distance that he is from the home plate will be 245.37 feet.
How to calculate the distanceFrom the diagram, look at the DACB. LACB is right angle and both the remaining We know that- two angles are equal (45°). So we know that in a in front of their are A two sides are equal then angles also equal and vice-versa.
AC = CB
So AC is also x.
Now by Pythagoras theorem
(AC)² + (BC)² - (AB)²
x² + x² = 347²
2x² = 347²
x = 347 / ✓2
= 245.37 ft.
l
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a watermelon is thrown down from the 7th floor of urey hall at ucsd. if the initial height of the watermelon is 21.0 meters, and it is thrown straight downward with an initial downward velocity of 3.00 m/s. how far will the watermelon have fallen from its starting height after 1.50 seconds?
Answer:
The watermelon has fallen 15.53625m
Step-by-step explanation:
x=vi*t+.5*a*t^2
x=3*1.5+.5*9.81*1.5^2
x=15.53625m
What is the least common multiple of 50, 41, and 30?
Hello!
[ 50; 41; 30 ] = ?
50 | 2 × 5
5 | 5 => 50 = 2 × 5²
1 |
41 | 41 => 41 = 41
1 |
30 | 2 × 5
3 | 3 => 30 = 2 × 3 × 5
1 |
[ 50; 41; 30 ] = 2 × 3 × 5² × 41 = 2 × 3 × 25 × 41 = 6 × 25 × 41 = 150 × 41 = 6150
Good luck! :)
The measures of the exterior angles of an octagon are x°, 2x°, 4xº, 5x°, 6x°, 8xº,
9x", and 10x°. Find the measure of the smallest exterior angle.
Answer:
8°
Step-by-step explanation:
The sum of the measures of the exterior angles of a any polygon = 360.
So, x + 2x + 4x + 5x + 6x + 8x + 9x + 10x = 360
45x = 360
x = 8°
The measure of the smallest exterior angle would be equal to 8°
What is Octagon ?In geometry, a Octagon is a eight - sided polygon. For a [n] sided polygon -
Sum of interior angles = (n - 2) × 180°Each interior angle of a regular polygon = [(n − 2) × 180°/n]Sum of exterior angles = 360°According to the question, we have - A Octagon and the measures of the exterior angles of an octagon are x°, 2x°, 4x°, 5x°, 6x°, 8x°, 9x° and 10x°.
The sum of the exterior angles of the octagon will be 360°.
Therefore, we can write -
x + 2x + 4x + 5x + 6x + 8x + 9x + 10x = 360°
45x = 360°
x = 360/45
x = 8
The smallest exterior angle would be equal to [x]° = 8°
Therefore, the measure of the smallest exterior angle would be equal to 8°
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Solve (x - 2 < 5) ∩ (x + 7 > 6).
1. Ø
2. {x | x < -1 x < 7}
3. {x | -1 < x < 7}
Answer:
c2
Step-by-step explanation:
A certain small country has $10 billion in paper currency in circulation, and each day $50 million comes into the country's banks. The government decides to introduce new currency by having the banks replace old bills with new ones whenever old currency comes into the banks. Since both old bills and new bills will come into the banks while the new currency is gradually introduced, we will need to solve a differential equation to track the amount of new currency in circulation at a given time. Let x (t) denote the amount of new currency, in billions of $, in circulation after t days. We've shown that new currency is introduced at the rate 10 - x (t) / 10 0.05, which simplifies to 0.005 (10 - x (t)). This justifies that x (t) satisfies the differential equation dx / dt = 0.005 (10 - x). (a) Solve the differential equation to find x (t). (b) At what time t will new bills make up 90% of the currency in circulation?
(a) The solution to the differential equation isx(t) = 10(1 - e^(-0.005t))
To solve the differential equation dx/dt = 0.005(10 - x), we can use separation of variables:
dx / (10 - x) = 0.005 dt
Integrating both sides:
-ln|10 - x| = 0.005t + C
where C is the constant of integration. Solving for x:
|10 - x| = e^(-0.005t - C)
Since x cannot be negative, we can drop the absolute value sign and solve for C using the initial condition that x(0) = 0:
C = -ln(10)
Therefore, the solution to the differential equation is:
x(t) = 10 - e^(-0.005t - ln(10))
Simplifying:
x(t) = 10(1 - e^(-0.005t))
(b) New bills will make up 90% of the currency in circulation after approximately 461 days.
We want to find the value of t such that x(t) = 0.9(10) = 9. Plugging this into our solution from part (a):
9 = 10(1 - e^(-0.005t))
Dividing both sides by 10 and taking the natural logarithm:
ln(0.1) = -0.005t
Solving for t:
t = 200 ln(10) = 460.51
Therefore, new bills will make up 90% of the currency in circulation after approximately 461 days.
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Solve the following quadratic equation for all values of x in simplest form. 2 ( x+ 8 ) ^2 + 9 =29
Answer:
x = -8 + sqrt(10) and x = -8 - sqrt(10)
Step-by-step explanation:
The quadratic equation to be solved is:
2(x + 8)² + 9 = 29
First, we need to simplify the left-hand side of the equation by expanding the squared term:
2(x + 8)(x + 8) + 9 = 29
Simplifying further, we get:
2(x² + 16x + 64) + 9 = 29
Distributing the 2, we get:
2x² + 32x + 128 + 9 = 29
Combining like terms, we get:
2x² + 32x + 137 = 29
Subtracting 29 from both sides, we get:
2x² + 32x + 108 = 0
Dividing both sides by 2, we get:
x² + 16x + 54 = 0
We can solve this quadratic equation by factoring or by using the quadratic formula :
The equation presented is a quadratic equation in standard form, ax² + bx + c = 0, where a = 1, b = 16, and c = 54. To solve this equation, we can use the quadratic formula, x = (-b ± sqrt(b² - 4ac)) / 2a. Plugging in the values, we get x = (-16 ± sqrt(16² - 4(1)(54))) / 2(1) = (-16 ± sqrt(16)) / 2 or (-16 ± 2sqrt(10)) / 2. Simplifying, we get x = -8 ± sqrt(10). Therefore, the two solutions to this equation are x = -8 + sqrt(10) and x = -8 - sqrt(10).
P(-3,-7) and Q(3,-5)
The midpoint of the two points of P (-3,-7) and Q (3,-5) is (0, -6).
How to find the midpoint ?When you have the vertices of two points, you can find the midpoint by the formula :
= ( ( x 1 + x 2 ) / 2 , ( y 1 + y 2 ) / 2 )
Solving for the midpoint therefore gives:
= ( ( - 3 + 3 ) / 2 , ( - 7 + ( - 5 ) ) / 2 )
= ( 0 / 2 , ( - 12 ) / 2 )
= (0, -6)
In conclusion, the midpoint is (0, -6).
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how do you write 750 gallons to 14 minutes as a unit rate
Tanner is cutting a 23-inch board into 2.25-inch sections. How many whole sections will he end up with?
11
12
10
13
Can someone explain why the statement is true. Will Mark brainliest.
Answer:
The triangle is isosceles.
Step-by-step explanation:
This means that one angle's sine is the same as the other's cosine.
if 10 KM = 5/6 hour, 1 hour=
Answer:
Step-by-step explanation:
10/5x6=12
Five students are placed in a group to complete a project in anatomy class. Because Freddy's father is a doctor, he feels he has a stronger grasp on the content and should therefore guide the project. When other group members speak, Freddy butts in frequently, making sure his perspective takes priority. Freddy's group members probably find his ________ to be distracting and frustrating, as they can tell Freddy thinks he knows more than they do. (chapter 6)
Freddy's group members probably find his interruptions to be distracting and frustrating, as they can tell Freddy thinks he knows more than they do. (chapter 6)
What is anatomy?The scientific study of the shape and composition of living organisms is referred to as anatomy, which focuses on their anatomical structure and organization.
The skill of observing and analyzing the various components of a structured entity to unearth their placement, makeup, and workings is also known as science.
They find his behavior annoying because he is distracting them and not letting them focus.
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What is the value of b?
Answer:
C. 42
Step-by-step explanation:
The sum of the series: -2+(-8) + (-32)++ (-2048) equals
I really neeed help!!! Please I’m begging you!!!!!!
Answer:
-2090
Step-by-step explanation:
1) Remove parentheses.
-2 -8 -32 -2048
2) Simplify - 2 - 8 to -10.
-10 - 32 - 2048
3) Simplify -10-32 to -42.
-42 - 2048
4) Simplify.
-2090
Pavi has a credit line of $8,000 on his credit card. Review the summary of his credit card statement. How much credit does Pavi currently have available on this card?
Summary Previous Balance Payments/Credits New Purchases Finance Charge New Balance
$2,500. 00 $1,500. 00 $3,000. 00 $7. 50 $4,007. 50
A.
$3,992. 50
B.
$5,000. 00
C.
$5,500. 00
D.
$6,500. 50
The correct option is option (a) $3,992.50. Pavi currently has a $3,992.50 credit on her current card.
The calculation of the provided data, according to the question, is as follows:
$8000 is the credit limit on the card.
Paid in Full = $2,500
$1,500 has been credited to the account.
The value of recent purchases made by Pavi is $3,000
Applied finance charges equal $7.50
The card's current balance is equal to $4,007.50.
Using the formula below, we can now determine the amount of credit that is now available on the card:
The credit line on the card = Available Credit - New Balance
By entering values into the formula provided, we obtain
Credit available on the current card: $8,000 - $4,007.50= $3,992.50.
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A triangle has vertices at (-9,2), (-9,-6), (-3,-6). What is the perimiter of the triangle in units?
Answer:
The perimeter is 24 units
Step-by-step explanation:
Given
\(A = (-9,2)\) --- \((x_1,y_1)\)
\(B = (-9,-6)\) --- \((x_2,y_2)\)
\(C = (-3,-6)\) --- \((x_3,y_3)\)
Required
Determine the perimeter
To do this, we calculate the distance AB, BC and AC.
Distance is calculated as:
\(d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2\)
So, we have:
\(AB = \sqrt{(-9 - -9)^2 + (2 - -6)^2\)
\(AB = \sqrt{64\)
\(AB = 8\)
\(BC = \sqrt{(-9 - -3)^2 + (-6 - -6)^2\)
\(BC = \sqrt{36\)
\(BC = 6\)
\(AC = \sqrt{(-9 --3)^2 + (2 --6)^2\)
\(AC = \sqrt{100\)
\(AC = 10\)
So, the perimeter (P) is:
\(P = AB + BC + AC\)
\(P =8 + 6 + 10\)
\(P =24\)
find the matrix of the relation r={(1,2),(2,3),(3,4),(4,5)} on the set x={1, 2, 3, 4, 5}; ordering of x:1,2,3,4,5
The matrix of the relation r={(1,2),(2,3),(3,4),(4,5)} on the set x={1, 2, 3, 4, 5}; ordering of x:1,2,3,4,5 is as follows.
\($$\begin{pmatrix} 0 & 1 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 & 0 \end{pmatrix}$$\)
A relation is a set of ordered pairs.
The matrix of a relation is constructed by using its ordered pairs with their respective values as its entries, and its rows and columns by its domain and range, respectively.
So, the relation r is given as{(1,2),(2,3),(3,4),(4,5)}
The elements in the rows of the matrix correspond to the elements of x, while the elements in the columns of the matrix correspond to the elements of x as well, in that order.
So, the matrix of r on x can be written as:
\($$\begin{pmatrix} 0 & 1 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 & 0 \end{pmatrix}$$\)
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Please help, it’s not college math!!
Answer: The first answer choice
AKA: y = -1.74x + 46.6
Step-by-step explanation:
When looking at the average student debt, how might you divide up the period
from 1993-2015 into three distinct periods based on the rate of growth?
When dividing the period from 1993-2015 into three distinct periods based on the rate of growth of average student debt, one possible approach could be:
1. 1993-2003: Slow and steady growth
During this period, the rate of growth of average student debt was relatively stable and moderate. The increase in student debt was gradual, and the overall burden on students was not as pronounced as in later periods. For example, the average student debt may have increased by a few thousand dollars over these ten years.
2. 2003-2008: Accelerated growth
In this period, the rate of growth of average student debt started to accelerate. The increase in student debt became more significant, potentially due to factors such as rising tuition costs, increased borrowing, and changes in financial aid policies. For example, the average student debt may have doubled or tripled during this five-year period.
3. 2008-2015: Rapid and substantial growth
The period from 2008 to 2015 witnessed a sharp and substantial increase in the rate of growth of average student debt. This period corresponds with the aftermath of the 2008 financial crisis and its impact on the cost of education. The economic recession led to reduced financial support for higher education, resulting in higher borrowing rates for students. For example, the average student debt may have increased by tens of thousands of dollars or even more during this seven-year period.
It's important to note that the division of periods may vary based on the specific data and factors considered. The examples provided are meant to illustrate potential trends rather than represent precise figures. Additionally, it's crucial to consult reliable sources and data on average student debt to obtain accurate information for a comprehensive analysis of the topic.
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(4/9)^-1=
A. -4/9
B. 9/4
C. -9/4
Answer: 9/4
Step-by-step explanation: Think of \((\frac{4}{9})^{-1}\)as \(\frac{4^{-1} }{9^{-1}}\).
Now, we can change 4⁻¹ to 4¹ by moving it to the denominator and
we can change 9⁻¹ to 9¹ by moving it to the numerator.
So we have 9¹/4¹ which simplifies to 9/4.
PRIN Question 31 Let f(x) be a continuous function that has exactly one critical point in the interval [4, 12). Find the x-values at which the global maximum and the global minimum occur in this interval given that f'(4) = 0 and f"(4) = -1. Global maximum at x = Number Global minimum at x = Number Click if you would like to Show Work for this question: Open Show Work
The global maximum occurs at x = 4 and the global minimum occurs at x = 12.
Method to find critical point:
The x-values at which the global maximum and global minimum occur with exactly one critical point can be calculated by the following criteria:
1. Identify the critical point.
2. Check the endpoints of the interval.
3. Determine the global maximum and global minimum based on the information given.
1. Identify the critical point
Since f'(4) = 0, we know that there is a critical point at x = 4. Moreover, since f''(4) = -1, which is negative, we can conclude that this critical point is a local maximum.
2. Check the endpoints of the interval
The interval is [4, 12), so the only endpoint we need to check is x = 12. We don't have information about f'(12), so we can't determine if there's a critical point at this endpoint.
3. Determine the global maximum and global minimum
Since there is only one critical point in the interval and it is a local maximum, the global maximum must occur at x = 4. Since the function is continuous, the global minimum must occur at the other endpoint of the interval, which is x = 12.
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