4 ft
3 ft
A 60 sq ft
B 69 sq ft
6 What is the area of the figure?
D
3 ft
81 sq ft
90 sq ft
2 m
3m 3m
4 m
8 m
2 m
7m
Based on the information in the graph, we can infer that the area of the figure is 57 square feet (option C).
How to calculate the area of the figure?To calculate the area of the figure we must calculate the area of two segments of the figure and then add them. First we can calculate the area of the area on the left that is 3 * 4.
3*4=12ft²Then we must find the area of the area on the right which is 7.5 ft * 6ft.
7.5ft * 6ft = 45ft²Finally we must add both areas to find the total area:
12ft² + 45ft² = 57ft²Note: This question is incomplete. Here is the complete information:
Image attached.
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Tyler collects 1242 cans of pet food. He gives 150 cans to the vet. Then he packs 9 cans in each box to give to the animal shelter. How many cans of pet food are not in a box?
Answer:
121
Step-by-step explanation:
1242-150=1092/9 = 121 (remainder 3)
Answer: 121
Step-by-step explanation: 1241 - 150 / 9
please please help me
Answer:
I'm pretty sure its 3500
Answer:
3,500 meters above the ground.
Step-by-step explanation:
The working is in the picture I attached to this response.
⭐ if this response helped you, please mark it the "brainliest"!⭐
1. If f(x) = (3x-2)/(2x+3), then f'(x) =
Answer:
\(f'(x)= \frac{13}{(2x+3)^2}\\\)
Step-by-step explanation:
\(f(x)= \frac{3x-2}{2x+3} \\\)
\(f'(x)=\frac{dy}{dx} = \frac{d}{dx}(\frac{3x-2}{2x+3})\\ f'(x)= \frac{(2x+3)\frac{d}{dx}(3x-2)-(3x-2)\frac{d}{dx}(2x+3) }{(2x+3)^{2} } \\f'(x)= \frac{(2x+3)(3)-(3x-2)(2)}{(2x+3)^{2} } \\\)
\(f'(x)= \frac{6x+9-6x+4}{(2x+3)^{2} }\\ f'(x)= \frac{13}{(2x+3)^2}\\\)
how many zeros does the function y=x^2-8x-20 have
5/32×7= multiplicación de fracciones, paso paso por favor rápido para hoy doy 5
Answer:
35/32
Step-by-step explanation:
Primero, es necesario hacer el 7 en una fracción
\(\frac{5}{32} * \frac{7}{1}\)
Entonces puede multiplicarse a través
\(\frac{5(7)}{32(1)} \\\\\frac{35}{32}\)
35/32 es la respuesta
¡También, lo siento si mi español es malo! Todavía estoy aprendiendo jaja
what do many prefixes and suffixes have in common?
South the inequality. The temperature of the freezer is never greater than -2°C. Yesterday the temperature was -10°C but it increased at a steady rate of 1. 5°C per hour. How long in hours and minutes did the temperature increase inside the freezer?
It took approximately 5.3 hours for the temperature inside the freezer to increase from -10°C to -2°C.
If the temperature inside the freezer increased by 1.5°C per hour, and it started at -10°C, then to reach -2°C the temperature inside the freezer would have had to increase by 8°C.
To find out how long it took for this to happen, we can use the formula:
Temperature increase/rate of increase = time
8°C / 1.5°C per hour = 5.3 hours (approx).
The temperature was exactly -10°C at the start and exactly -2°C at the end. It means that the temperature increased by 1.5°C per hour on average.
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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I will mark you brainliest
I need the answer to all 3 questions not just one question
Answer:
if you need help than yse 50 points
Which is true about ALL quadrilaterals? *
All angles are congruent.
All sides are congruent.
All angles add up to 360 degrees.
Diagonals are always congruent.
Answer:
all angles add up to 360 degrees
Step-by-step explanation:
Let the domain be the set of all employees of a certain company and Joshua is an employee of that company. Define the following predicates: - P(x) : x was sick yesterday. - W(x) : x went to work yesterday. - Q(x) : x was on vacation yesterday. Translate each of the following English statements into a logical expression. 1. Everyone who was well went to work yesterday. 2. Someone who was sick yesterday did not go to work yesterday. 3. Someone who missed work was neither sick nor on vacation. 4. Joshua was on vacation yesterday and he did not go to work. 5. Everyone was well and went to work yesterday.
To translate the given English statements into logical expressions using the provided predicates, here are the translations:
1. Everyone who was well went to work yesterday.
- ∀x [(W(x) ∧ ¬P(x)) → W(x)]
2. Someone who was sick yesterday did not go to work yesterday.
- ∃x (P(x) ∧ ¬W(x))
3. Someone who missed work was neither sick nor on vacation.
- ∃x (¬(P(x) ∨ Q(x)) ∧ ¬W(x))
4. Joshua was on vacation yesterday and he did not go to work.
- Q(Joshua) ∧ ¬W(Joshua)
5. Everyone was well and went to work yesterday.
- ∀x (W(x) → W(x) ∧ ¬P(x))
Please note that these translations assume that the domain consists of all employees of the company, including Joshua. Also, the logical expressions are based on the provided predicates and their interpretations.
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Translate each expression
No answering with a link !!!
Directions :
Translate each expression 1-6
Answer:
Solving the first 6Assumed the number is x#14x - 1#2(2/3)x + 7#3m - n#4x² - 9#52x/5#6(1/4)x + 27Help me with this, it’s due in a bit!
Answer:
64 square centimeters
Step-by-step explanation:
The surface are of a pyramid is found by finding the sum of the area of the four sides and the base.
Finding the triangular face:
Area of triangle = \(\frac{1}{2} b h\) = \(\frac{1}{2}*4*6 = 12\)
12 * 4 (4 sides) = 48 square cm
Finding the Base = \(w * l = 4 * 4 = 16\)
Finally, we add it together. 48 + 16 = 64
I need help ASAP this is really hard
Answer:
x = -13
Step-by-step explanation:
Isolate the variable (x)
9 - 2x = 35
Subtract 9 from both sides
This action cancels out the 9 on the side of the variable
- 2x = 35 - 9
- 2x = 26
Divide by -2 on both sides
x = 26 ÷ -2
x = -13
Emily invests £150,000 in a savings account offering a compound interest rate of 2.4% per annum for 4 years. Work out the amount of interest Emily earns over 4 years. Emily invests £ 150,000 in a savings account offering a compound interest rate of 2.4 % per annum for 4 years . Work out the amount of interest Emily earns over 4 years .
14926.74417
Step-by-step explanation:
Based on the given conditions, formulate:
150000 ((2.4% +1)4-1)
Evaluate the equation/expression: 14926 14926.74417 get the result:14926.74417 Answer: 14926.74417
if it is helpfulthe mark me brainliest pls
the statistical range, with a given probability, that takes random error into account is called the
The statistical range that takes random error into account, with a given probability, is known as the confidence interval. It provides a measure of uncertainty associated with a particular estimate or sample statistic. In the first paragraph, we'll provide a summary of the answer.
A confidence interval consists of two values, an upper and a lower bound, within which the true population parameter is likely to fall. The range is determined by the desired level of confidence, often expressed as a percentage (e.g., 95% confidence interval). The confidence interval considers both the variability within the sample data and the desired level of certainty. It acknowledges that due to random sampling error, the estimate obtained from a sample may differ from the true population parameter. In the second paragraph, we'll delve into an explanation of the answer.
To understand confidence intervals, we need to consider the concept of sampling variability. When we collect a sample from a population, it's rare for the sample to perfectly represent the entire population. There will be inherent variation due to random chance. This variability is known as sampling error. Confidence intervals take into account this sampling error and provide a range of values within which the true population parameter is likely to exist.
The level of confidence chosen for the interval represents the desired probability that the range will contain the true parameter. Commonly used confidence levels are 90%, 95%, and 99%. For example, a 95% confidence interval implies that if we were to repeat the sampling process many times, 95% of the resulting intervals would contain the true population parameter. The wider the interval, the higher the level of confidence, and vice versa.
In conclusion, a confidence interval is a statistical range that incorporates random error and provides an estimate of the likely range within which the true population parameter exists. It considers the desired level of confidence and takes into account the inherent variability due to random sampling error. Confidence intervals are an essential tool in statistical inference, allowing researchers and analysts to quantify the uncertainty associated with their estimates and draw meaningful conclusions from sample data.
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A circle with center (6, 7) includes the point (1,4). A second
circle also include the point (1,4), and contains the same area
but has a different center.
Find the ordered pair that corresponds to the center of the
second circle.
The ordered pair that corresponds to the center of the second circle is (6,4).
Given that, a circle with center (6, 7) includes the point (1,4).
The center of the second circle must have the same distance from (1,4) as the center of the first circle. This distance is the radius of the circles.
The radius can be calculated with the Pythagorean theorem, which states that the distance between two points (x₁,y₁) and (x₂,y₂) is equal to the square root of (x₂-x₁)² + (y₂-y₁)².
Therefore the radius of the two circles is the square root of (6-1)^2 + (7-4)^2 = 5.
The center of the second circle must then be (1,4) + (5,0) = (6,4).
Therefore, the ordered pair that corresponds to the center of the second circle is (6,4).
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A box shaped as a rectangular prism can hold 176 wooden cube blocks with edge lengths of 1/2 ft (decimal)
what is the volume of the box?
_ ft
please hurry-
Answer:22
Step-by-step explanation: 1/2 = .5
.5x.5x.5
0.125 x 176= 22
does someone know these answers??? PLEASE HELPPP ASAPPP
Answer:
it's false
Step-by-step explanation:
Hope this helps you.
One of the following vector fields is conservative. Identify it and find its potential function p(x, y, z). F₁ = (1, -z, y) F₂=(2, 1, x) F3 = (y, x, x - y)
Among the given vector fields, F₁ = (1, -z, y) is the conservative vector field. Its potential function p(x, y, z) can be determined as p(x, y, z) = x + 0.5z² + 0.5y².
A vector field is said to be conservative if it can be expressed as the gradient of a scalar function, known as the potential function.
To identify the conservative vector field among the given options, we need to check if its curl is zero.
Let's calculate the curl of each vector field:
F₁ = (1, -z, y):
The curl of F₁ is given by
(∂F₁/∂y - ∂F₁/∂z, ∂F₁/∂z - ∂F₁/∂x, ∂F₁/∂x - ∂F₁/∂y) = (0, 0, 0).
Since the curl is zero, F₁ is a conservative vector field.
F₂ = (2, 1, x):
The curl of F₂ is given by
(∂F₂/∂y - ∂F₂/∂z, ∂F₂/∂z - ∂F₂/∂x, ∂F₂/∂x - ∂F₂/∂y) = (0, -1, 0).
The curl is not zero, so F₂ is not a conservative vector field.
F₃ = (y, x, x - y):
The curl of F₃ is given by
(∂F₃/∂y - ∂F₃/∂z, ∂F₃/∂z - ∂F₃/∂x, ∂F₃/∂x - ∂F₃/∂y) = (0, 0, 0).
The curl is zero, so F₃ is a conservative vector field.
Therefore, F₁ = (1, -z, y) is the conservative vector field. To find its potential function, we integrate each component with respect to its respective variable:
p(x, y, z) = ∫1 dx = x + C₁(y, z),
p(x, y, z) = ∫-z dy = -yz + C₂(x, z),
p(x, y, z) = ∫y dz = yz + C₃(x, y).
By comparing these equations, we can determine the potential function as p(x, y, z) = x + 0.5z² + 0.5y², where C₁, C₂, and C₃ are constants.
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what is the approximate probability of randomly choosing one vegetable and one grain-based side dish?
Thus, the probability of randomly choosing one vegetable and one grain-based side dish in this scenario is 2%.
The probability of randomly choosing one vegetable and one grain-based side dish depends on the number of options available for each category.
For example, if there are 10 vegetable options and 5 grain-based side dish options, the probability of choosing one vegetable and one grain-based side dish would be calculated as follows:
Probability of choosing one vegetable = 1/10
Probability of choosing one grain-based side dish = 1/5
To find the probability of both events happening together, we multiply the probabilities:
Probability of choosing one vegetable and one grain-based side dish = 1/10 x 1/5 = 1/50
Therefore, the approximate probability of randomly choosing one vegetable and one grain-based side dish in this scenario is 1/50 or 0.02 (2%).
However, the actual probability may vary depending on the specific number of options available for each category. It's important to note that this calculation assumes that each option is equally likely to be chosen, which may not always be the case in real life.
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a radioactive material decays according to the formula , where a is the final amount, is the initial amount and t is the time in years. find k, if 700 grams of this material decays to 550 grams in 8 years.
the decay constant for this material is approximately 0.0445.when t = 8 years, the amount of the material remaining is 550 grams.
The formula for radioactive decay is given by:
a = \(e^(-kt)\\\) * A
where a is the final amount,A is the initial amount, t is the time in years, and k is the decay constant.
We can use the given information to solve for k as follows:
When t = 0, a = A. So, we have:
A = \(e^(0 * k)\) * A
Simplifying this gives:
1 = e^0
Therefore, we can see that k = 0 at the start of the decay process.
Now, when t = 8 years, the amount of the material remaining is 550 grams. Therefore, we have:
550 = \(e^(-8k)\) * 700
Dividing both sides by 700 and taking the natural logarithm of both sides, we get:
ln(550/700) = -8k
Simplifying this gives:
k = ln(700/550)/8
Using a calculator, we can evaluate this expression to get:
k ≈ 0.0445
Therefore, the decay constant for this material is approximately 0.0445.
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Builtrite has calculated the average cash flow to be $14,000 with a standard deviation of $5000. What is the probability of a cash flow being between than $16,000 and $19,000 ? (Assume a normal distribution.) 16.25% 18.13% 23.90% 2120%
The correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.
To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.
We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.
The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.
First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.
z1 = 2,000 / 5,000 = 0.4.
Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.
z2 = 5,000 / 5,000 = 1.
Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.
Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.
Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.
Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.
So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.
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The probability of a cash flow between $16,000 and $19,000 is approximately 18.59%.
To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.
We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.
The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.
First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.
z1 = 2,000 / 5,000 = 0.4.
Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.
z2 = 5,000 / 5,000 = 1.
Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.
Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.
Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.
Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.
So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.
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I dont get the question
Factor the expression 4x + 32. Explain each step you
take in the process.
Answer:
4x + 32 = 4x + 4.8 = || 4. (x + 8) ||
Step-by-step explanation:
A bag contains tiles. 3 tiles of red, 6 tiles of green, 3 tiles are blue. A tile will be randomly selected from the bag. What is the probability In decimal form from the tile will be green?
Answer:
The probability is 0.5 tiles will be green
Step-by-step explanation:
Hope this helps
Find the midpoint of PQ
Answer:
?? ?? ?? ?? ?? ?? ?? ?? ?? ??
Which graph represents the solution to the system of equations?
Y=2x+5. Y=1/3x-2
Please help me
Answer:
I can help but I need better pic
Choose a course that you are currently taking in which the final exam is worth 100 points. Treating your score on the exam as if it were a contin- uous uncertain quantity, assess the subjective probability distribution for your score. After you have finished, check your assessed distribution for consistency by:
a. Choosing any two intervals you have judged to have equal probability content, and
b. Determining whether you would be willing to place small even- odds bets that your score would fall in one of the two intervals. (The bet would be called off if the score fell elsewhere. )
c. After assessing the continuous distribution, construct a three-point approximation to this distribution with the extended Pearson-Tukey method. Use the approximation to estimate your expected exam score.
d. Now construct an approximation using the extended Swanson-Megill method. Use this approximation to estimate your expected exam score. How does your answer compare with the estimate from part c?
In general, subjective probability distributions for exam scores may vary depending on an individual's confidence level, their preparation, and the difficulty level of the exam.
In the case of constructing an approximation using the extended Pearson-Tukey method, the three-point approximation is determined by selecting the 25th, 50th, and 75th percentiles of the distribution. On the other hand, the extended Swanson-Megill method involves selecting three equally spaced points that divide the area under the probability density function into four parts. The expected exam score can then be estimated by computing the weighted average of the three points. The estimate obtained from the Swanson-Megill method may differ from that of the Pearson-Tukey method due to the different ways in which the three points are selected.
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If f and f ◦g are one-to-one, does it follow that g is one-to-one? justify your answer.
If f and f ◦g are one-to-one, then g is one-to-one.
A function f is one-to-one if it has one and only one preimage in the domain. one-to-one functions are also called injective functions.
i.e., distinct points in the domain will have distinct images.
Mathematically, if f(x) = f(y), then x = y
So here f and f o g are one-to-one.
i.e., f(x) = f(y) ⇒ x = y
and (f o g)(x) = (f o g)(y) ⇒ x = y
So consider g(x) = g(y)
⇒ f(g(x) = f(g(y))
⇒ (f o g)(x) = (f o g)(y)
⇒ x = y [Since f o g is one-to-one]
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