in the presence of sulfuric acid, this alcohol is dehydrated to form a pair of alkenes through an e1 mechanism. draw either of the major alkene products of this reaction.

Answer:

45.8 CO2 = 1.0406843976868674mol

Explanation:

How many grams CO2 in 1 mol? The answer is 44.0095. We assume you are converting between grams CO2 and mole. You can view more details on each measurement unit: molecular weight of CO2 or mol This compound is also known as Carbon Dioxide.

Credit;

Convert grams CO2 to moles - Conversion of Measurement ...

The number of moles of edta used in the titration is 0.0225 mol/L x 0.01972 L = 0.0004446 mol edta and the mass of zinc titrated is 0.029 g.

First, let's calculate the number of moles of edta used in the titration:

0.0225 mol/L x 0.01972 L = 0.0004446 mol edta

Since edta has a 1:1 mole ratio with Zn, we know that the number of moles of edta used is also equal to the number of moles of Zn in the sample. So:

moles of Zn = 0.0004446 mol

Now we can calculate the mass of Zn titrated:

mass of Zn = moles of Zn x molar mass of Zn

mass of Zn = 0.0004446 mol x 65.38 g/mol

mass of Zn = 0.029 g

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Answer:

where is the questions........

Answer:Wavelength can be defined as the distance between two successive crests or troughs of a wave. It is measured in the direction of the wave. Description: Wavelength is the distance from one crest to another, or from one trough to another, of a wave (which may be an electromagnetic wave, a sound wave, or any other wave).

Formation of protective oxide on the metal. Passivation involves the formation of a thin, protective layer of oxide on the surface of a metal.  

The correct answer to the question is c.

Passivation involves the formation of a thin, protective layer of oxide on the surface of a metal. This layer is formed through exposure to an oxidizing agent, which reacts with the metal to create the oxide layer. The oxide layer that is formed during passivation is stable and non-reactive, and it protects the metal from further corrosion. It is important to choose the right metal for a particular environment in order to ensure that passivation is effective.

Metals that naturally form a protective oxide layer, such as stainless steel, are often used in environments where corrosion is a concern .It's important to note that other methods like applying polymer coatings or adding inhibitors to the electrochemical environment can also help in preventing corrosion, but they are not directly related to the concept of passivation.

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Answer:

hypothesis testing center of the year with 32 days

Answer:

Helium Nucleus

Explanation:

Answer:

Helium Nucleus

Explanation:

Answer:

I do not know. I think there is .as we are the living creatures in this earth. maybe aliens are creatures of other planet or galaxies. I am not scientists to prove it.sorry.

The unrealized gains and losses on available-for-sale securities are: The correct answer is: reported on the portfolio of investments.

Unrealized gains and losses on available-for-sale securities are reported on the portfolio of investments. Available-for-sale securities are financial instruments that are not classified as trading securities or held-to-maturity securities. These securities are typically held by companies as investments for an extended period. When it comes to available-for-sale securities, their fair values fluctuate over time. These fluctuations lead to unrealized gains or losses. However, unlike trading securities, which are actively bought and sold for short-term gains, available-for-sale securities are intended for longer-term investment purposes.

Accounting standards require that the unrealized gains and losses on available-for-sale securities be reported as a separate component of comprehensive income. This means that these gains and losses are not recognized in the income statement but are reported as part of the comprehensive income statement or in the equity section of the balance sheet. Therefore, the most accurate statement is that the unrealized gains and losses on available-for-sale securities are reported on the portfolio of investments, reflecting the overall performance of the investment portfolio rather than on individual securities.

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The mass percent of the solute in the solution is approximately 11.45%.

To calculate the mass percent of the solute in the solution, we can use the following formula:

Mass percent = (Mass of solute / Total mass of solution) * 100

Mass of solute = 1.50 g

Mass of solvent = 11.6 g

Total mass of the solution = Mass of solute + Mass of solvent

Total mass of the solution = 1.50 g + 11.6 g = 13.10 g

Now, we can substitute the values into the formula:

Mass percent = (1.50 g / 13.10 g) * 100

Calculating the expression:

Mass percent = 0.1145 * 100

Mass percent ≈ 11.45%

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Answer:

B. Lava flows may cause tsunamis.

Answer:

true I think ?38363849472

Answer:

true

Explanation:

Answer:

The answer is True.

Explanation:

You can use similar processes when converting from smaller to larger units. When converting a larger unit to a smaller one, you multiply; when you convert a smaller unit to a larger one, you divide.

The criterion of -850mV is referenced to the silver-silver chloride electrode (Ag/AgCl).  Therefore the correct option is option C.

In electrochemistry, the silver-silver chloride electrode is frequently used as a standard reference electrode in studies of corrosion and other electrochemical reactions.

The potential of the silver-silver chloride electrode, which is defined at 0.1976 V vs the standard hydrogen electrode (SHE) at 25°C, is stable and repeatable.

In investigations on corrosion, the corrosion potential—the potential at which the rate of corrosion is minimized—is frequently determined using the criterion of -850 mV.

The corrosion potential is normally evaluated in relation to the silver-silver chloride electrode, and a corrosion study's standard criterion is typically a potential of -850 mV versus Ag/AgCl. Therefore the correct option is option C.

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48 g SO₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

0.75 mol SO₂

Step 2: Identify Conversions

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of SO₂ - 32.07 + 2(16.00) = 64.07 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

48.0525 g SO₂ ≈ 48 g SO₂

The correct answer is 4. SiO2(s) (silicon dioxide).

SiO2 is a superb example of a covalent organization strong, often known as a monster covalent or macromolecular strong. Particles in a covalent organization are interconnected regions of strength by bonds, forming a wide organization or grid structure.

Due to SiO2, each silicon iota is clung to four oxygen molecules, and each oxygen particle is clung to two silicon iotas. Throughout the strong, this results in a three-layered organization of linked silicon and oxygen molecules.

Because of the strength of the covalent bonds, covalent organization solids have high dissolving and limitations, and they are usually hard and insoluble in many solvents.

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Among the given options, silicon dioxide (SiO2) is a covalent network solid.

A covalent network solid is a type of solid in which the atoms are held together by a network of covalent bonds. These solids have high melting points, are insoluble in water, and are generally hard and brittle. Among the given options, silicon dioxide (SiO2) is a covalent network solid.

SiO2, also known as quartz, forms a three-dimensional network of silicon and oxygen atoms bonded together by strong covalent bonds. This network structure gives SiO2 its characteristic properties, such as its high melting point and hardness.

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The NO molecule has a doubly degenerate fundamental electronic level and a doubly degenerate first excited level at 121.1 cm-1.

To determine the contribution of electronic degrees of freedom to the standard molar entropy of NO, we need to consider the Boltzmann distribution. The relative population of the excited state to the fundamental state is given by the Boltzmann factor: e^(-ΔE/kT), where ΔE is the energy difference between the states, k is the Boltzmann constant, and T is the temperature. Since both levels are doubly degenerate, the total electronic partition function (q_e) is 2 + 2e^(-ΔE/kT). The molar electronic entropy (S_e) can be calculated using S_e = Rln(q_e). At room temperature (298 K), S_e ≈ Rln(4), as the excited state's population is much smaller compared to the fundamental state. The comparison of S_e to Rln(4) shows that, at room temperature, the electronic entropy of NO is mainly determined by its doubly degenerate ground state and excited state, and the higher energy states contribute negligibly to the entropy. Hydrogen bonds are present in water molecules. When a hydrogen (H) atom is bonded to an atom with a strong electronegative charge, it forms a hydrogen bond, which attracts polar groups.

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Answer:

true

Explanation:

Answer:

Ionization energy

Explanation:

Answer:

The last arrow is what I choose. The hot steam is in the air so I pick that arrow.

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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Hence option C is the correct option.

Therefore, the formula of the hydrate is MgCO3•0.449H2O.

The formula of the hydrate can be determined by calculating the number of moles of water driven off during the heating process and then using this information to determine the formula of the hydrate.

First, calculate the number of moles of water driven off:

15.67 g - 7.58 g = 8.09 g

Next, convert the mass of water driven off to moles:

8.09 g / (18.015 g/mol) = 0.449 mol

Finally, use the number of moles of water driven off to determine the formula of the hydrate:

(0.449 mol H2O) / (1 mol MgCO3•xH2O) = x

x = 0.449

So, the formula of the hydrate is MgCO3•0.449H2O.

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Answer:

The flow of thermal energy in a system, at constant atmospheric pressure AND at thermodynamic standard temperature and pressure.

This refers to the material that is made when different substances mix up physically and causes a reaction.

You can make on the project of Mixture -

This refers to the chemical bond that holds different atoms tightly

You can make on the project of Compound -

Based on the fact that the atom is the smallest indivisible part of an element, elements like phosphorous cannot be further broken down.

You can make on the project of Elements -

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To classify these molecules based on whether the substituent group is ortho/para directing or meta directing for electrophilic aromatic substitution, you need to first identify the nature of the substituent group. Here's a step-by-step explanation:

1. Identify the substituent group on the aromatic ring.
2. Determine whether the substituent group is electron-donating or electron-withdrawing.
3. Classify the substituent group accordingly:

- Ortho/para directing: If the substituent group is electron-donating, it usually directs the incoming electrophile to the ortho or para position relative to itself. Common examples of ortho/para directing groups include -OH, -NH2, -OCH3, -CH3.

- Meta directing: If the substituent group is electron-withdrawing, it usually directs the incoming electrophile to the meta position relative to itself. Common examples of meta directing groups include -NO2, -CN, -COOH, -SO3H.

Once you have classified the substituent group, you can place it in the appropriate category (either ortho/para directing or meta directing) based on its directing properties.

Answer:

NaCIO (chemical formula for bleach)

Answer:

mu answer is A

Explanation:

i think it is a popular opinion because its the opinion of a country