in the primitive yo-yo apparatus (figure 1), you replace the solid cylinder with a hollow cylinder of mass m , outer radius r , and inner radius r/2 . find the magnitude of the downward acceleration of the hollow cylinder.

Most photons that leave the sun's surface have a surface temperature of 6,000 K, which corresponds to the visible light region of the electromagnetic spectrum.

The electromagnetic spectrum is a continuous range of wavelengths and frequencies that includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The wavelengths and frequencies of these different types of electromagnetic radiation are all different and correspond to different regions of the spectrum.

The visible light region of the electromagnetic spectrum is the portion of the spectrum that can be seen by the human eye. It ranges from about 400 nanometers (nm) to about 700 nm in wavelength, and corresponds to frequencies of about 7.5 x 10^14 Hz to about 4.3 x 10^14 Hz. Photons with wavelengths and frequencies in this range have enough energy to excite the photoreceptors in the human eye, allowing us to see them.

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Answer:

5.06 m/s

Explanation:

velocity = distance / time

             = ( 25.6 - - 14.4) / 7.90 = 5.06 m/s

None of the above is right option for the same. A wave in which particles of the medium undergo a circular motion is known as a Surface wave.

A surface wave is a wave in which the medium's particles move in a circular pattern. Surface waves are neither transverse nor longitudinal. All of the particles in the bulk of the medium travel parallel to and perpendicular to the direction of energy transport in longitudinal and transverse waves, respectively.

Only the particles at the medium's surface move in a circular motion during a surface wave. As one moves farther away from the surface, the mobility of the particles tends to slow down.

Every wave that travels across a medium has its origin. One of the particles was initially displaced somewhere along the medium.

It is typically the first coil on a slinky wave that is moved by a person's hand. The first air particle to vibrate during the creation of a sound wave is often caused by the vocal chords or a guitar string. The particles that are displaced from their equilibrium position at the point where the wave is introduced into the medium always move in the same direction as the vibration's source.

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Answer:

The charge of a current in a given period of time is calculated by multiplying the current and the duration of that current. Since in the problem charge would be constant, we can relate the first conditions to the second conditions.

q = IT

q1 = q2

I1T1 = I2T2

8.4(240)=(10.5)(T2)

T2 = 192 seconds

When it is dropping into the sand point the energy of the ball transform from potential energy to kinetic energy.

The energy of motion is known as kinetic energy, and it is manifested in the motion of a particle, an object, or a collection of particles. Any object that moves, such as a person walking, a ball being thrown, food falling from a table, or a charge particle in an electric field, utilizes kinetic energy.

Radiant, thermal, auditory, electrical, and mechanical kinetic energies are the basic categories. Gamma radiation and ultraviolet light, which are constantly travelling through the universe, are instances of radiant energy. Sound energy is kinetic energy that manifests as vibrations, such as when someone plays the drums

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1. Force  necessary to stretch an ideal spring with a spring constant of 125 N/m by 35 cm is 437.5 N.

2. The mass of a fish that would stretch the spring by 7.55 cm from its normal length is 5.10 kg.

3. Spring constant is 267.94 N/m.

4. Spring constant is 285.71 N/m.

5. Distance will be 0.115 m.

6. Distance will be 1.986 m.

7. Spring constant is calculated to be 183.38 N/m.

8. Original length becomes 80 cm.

9. Distance covers to be 0.1924 m.

10. Equivalent spring constant becomes 150 N/m

1. The force necessary to stretch the spring can be calculated using Hooke's law, which states that F = kx, where F is the force applied, k is the spring constant, and x is the displacement from the equilibrium position.

Thus, F = kx

F = (125 N/m)(0.35 m)

F = 43.75 N.

2. Using Hooke's law again, we have

F = kx

F = (650 N/m)(0.0755 m)

F = 49.98 N.

This force is equal to the weight of the fish, so we can find its mass by dividing by the acceleration due to gravity:

m = F/g

m = 5.10 kg.

3. We can use Hooke's law once more to find the spring constant:

k = F/x

k = (43 kg)(9.81 m/s²)/(0.16 m)

k = 267.94 N/m.

4. Hooke's law gives us k = F/x

k = (80 N)/(0.28 m)

k = 285.71 N/m.

5. We can use Hooke's law to set up a proportion: F1/x1 = F2/x2, where F1 and x1 are the initial force and displacement, and F2 and x2 are the new force and displacement. Solving for x2, we get

x2 = (F2/F1)x1

x2 = (23 N/16 N)(0.08 m)

x2 = 0.115 m.

6. Hooke's law gives us F = kx = (36 N/cm)(0.073 m) = 2.628 N. This is the force required to stretch the spring by 1 cm, so the total displacement is

x = (7.3 kg)(9.81 m/s²)/(36 N/cm)

= 1.986 m.

7. We can use Hooke's law to set up an equation: mg = kx, where m is the mass, g is the acceleration due to gravity, and x is the displacement from the equilibrium position. Solving for k, we get

k = mg/x

k = (15 kg)(9.81 m/s²)/(0.80 m)

k = 183.38 N/m.

8. The original length of the cord is simply the length when no mass is attached, so it is 80 cm.

9. The total force on the bottom spring is the sum of the weights of the two springs and the mass, so

F = (0.58 kg)(9.81 m/s²) + (50 N/m + 100 N/m)(x), where x is the displacement of the two springs together. Using Hooke's law, we can write this as F = 19.24 N + 150 x.

Setting this equal to kx and solving for x, we get

x = F/(k1 + k2)

x = (19.24 N)/(50 N/m + 100 N/m)

x = 0.1924 m.

10. The spring constant of the system of springs is simply the sum of the individual spring constants, so

k = k1 + k2

k = 50 N/m + 100 N/m

k = 150 N/m.

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The third charge is in equilibrium, 2a/3

An electric property associated with each point in space when charge is present in any form.

The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.

According to the question,

force on it due to +4e= force due to +e

\(\frac{ k(4e)q}{x^{2} } = \frac{ k(e)q}{(a-x)^2}\)

4(a-x)² = x²

2(a-x)=x

2a-2x =x

x= \(\frac{2a}{3}\)

Therefore,

The position along the line XY is \(\frac{2a}{3}\)

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Answer:

B. Solid rock breaks apart.

Explanation:

Answer:

B

Explanation:

I did it on a test lol

By definition, Weight is a measure of the force of gravity pulling down on an object. it is measured in newtons (N), the common unit for measuring force.

Weight is called the action exerted by the force of gravity on the body.

The mass (amount of matter that a body contains) of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The formula that allows you to calculate the weight of any body is:

P = m×g

where:

Then, the weight of an object is the force of gravity on the object, that is, the weight will vary according to the force of gravity that acts on it. So the correct answer is:

Weight is a measure of the force of gravity pulling down on an object. it is measured in newtons (N), the common unit for measuring force.

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Answer:

C

Explanation:

You will hear a lower pitch of sound than your teacher who is directly below the bell.

The pitch of a sound refers to how high or low the sound is. If a sound is high we say that it has a high pitch and vice versa.

We must note that the closer you are the bell the higher the pitch of the bell sound you hear. Hence, you will hear a lower pitch of sound than your teacher who is directly below the bell.

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the correct answer is option a. m^2, as it is the proper unit for the second moment of area (q) in the shear formula.

In the shear formula, τ=vqit, q represents the area over which the shear force is applied. The units of q should be in square meters (m^2) to ensure that the overall unit of the formula is in Newtons per square meter (N/m^2) or Pascals (Pa). Therefore, option (e) m^2 is the proper unit of q. Option (a) m^2 is also correct but it is not specifically labeled as a unit.

Option (b) m^4 is incorrect because it is a unit of volume. Option (c) dimensions and option (d) me are not valid units of area. Lastly, option (f) None of these is incorrect since option (e) m^2 is the correct answer. The proper unit of q in the shear formula τ = vqit is "m^2".

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a). Impedance of the circuit Incorrect:  Z = 85.9 ohms

(b) Rms current in the circuit: 0.69 A

c) Average power delivered to the circuit: 35.88 W

Due to the fact that DC current is a sort of continuous current, its frequency is 0 hertz. Therefore, AC current is not limited to zero Hz as its rest frequency.

Given : 85 sin(260t)

C = 28mF = 28x 10⁻³ F

Inductance = L = 0.250 H

a) Inductive reactance = X(L) = ω L = (350)(0.2) = 70 ohms

Capacitive reactance = X(C) = 1 / ωC = 0.114 ohms

Reactance = Z = \(\sqrt{R^{2} + (X_{L} - X_{C} ) }\)

                  =  \(\sqrt{52^{2} +(70 -0.114)^{2} }\)

                  =85.9

B )  current = I = 85 / 85.9 = 0.98 A

Irms = 0.98 / \(\sqrt{2}\) = 0.69 A

c) P =  R = (0.69)(52) = 35.88 W

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Answer:

constant acceleration

Explanation:

I may be wrong, but I'm almost positive cuz I am also taking physics. ;)

Answer:

Constant acceleration in the positive direction.

Explanation:

Because it is a straight line with a positive slope, we can infer that the rate of acceleration remains constant as the line is linear, and as it states in the question, the slope is positive; therefore, it is moving in a positive direction.

Rutherford's detailed observations proved that the majority of alpha particles passed straight through the gold foil, while a small fraction were deflected at large angles.

This led to the conclusion that the positive charge of an atom was concentrated in a tiny, dense nucleus at the center, surrounded by mostly empty space where the negatively charged electrons orbit. This model became known as the nuclear model of the atom.

Here's a step-by-step explanation:

1. Rutherford directed a beam of alpha particles at a thin gold foil.
2. Most alpha particles passed straight through the foil, indicating that the majority of an atom's volume is empty space.
3. Some alpha particles were deflected at various angles, suggesting the presence of a positively charged center that repelled the positively charged alpha particles.
4. A very few alpha particles were deflected almost directly backward, which confirmed the existence of a small, dense nucleus.

These observations led to the development of Rutherford's nuclear model of the atom, which replaced the previously accepted "plum pudding" model.

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Answer:

\(50\:\mathrm{m\: North}\\50\sqrt{3}\:\mathrm{m\: East}\)

Explanation:

We can create a 30-60-90 triangle. The distance she walked is then the hypotenuse of the triangle, and using 30-60-90 triangle rules, we have the following:

The North leg is opposite to the \(30^{\circ}\) angle. Therefore, if we call this distance \(y_N\), we have the following:

\(\sin 30^{\circ}=\frac{y_N}{100},\\\frac{1}{2}=\frac{y_N}{100},\\y_N=\fbox{$50\:\mathrm{m}$}\).

The East leg is opposite to the \(60^{\circ}\\\) angle. If we call this distance \(x_E\), we have:

\(\sin 60^{\circ}=\frac{x_E}{100},\\\frac{\sqrt{3}}{2}=\frac{x_E}{100},\\x_E=\fbox{$50\sqrt{3}\:\mathrm{m}$}\).

The student could have used **option C**, a slow-motion camera that filmed the disk to determine the amount of time it took a particular point on the disk to make its first revolution after the disk was set into motion.

In this scenario, the student is trying to approximate the initial angular velocity (ωD) of the rotating disk. By using a slow-motion camera, they can accurately measure the time it takes for a specific point on the disk to complete one full revolution. This information, combined with the disk's radius, allows the student to calculate the angular velocity using the formula ω = θ/t, where ω is the angular velocity, θ is the angle of rotation (in this case, 2π radians for one full revolution), and t is the time taken for the revolution. Other options, such as linear position data or a stopwatch, would not provide the necessary information to calculate the initial angular velocity accurately.

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Answer: the volume quadruples

Explanation:

The question relies on conservation of energy

2 Energy equations:

Kinetic Energy = 1/2mv^2

Gravitational potential energy = mgh

Initial energy = final energy

1/2m(v0)^2 = mgh + 1/2m(vf)^2

Divide mass out to save time

1/2(v0)^2 = gh + 1/2(vf)^2

PLug in what we know:

v0 = 39 m/s

h = 21 meters

1/2(39)^2 = 9.8(21) + 1/2(vf)^2

1/2(39)^2 - 9.8(21) = 1/2(vf)^2

554.7 = 1/2(vf)^2

1109.4 = (vf)^2

vf = 33.3076 m/s

(a) A = B × r is a vector potential for B, where r = {x, y, 0}.

(b) The flux through a surface S can be calculated as Φ = ∫B·dA, where B is the magnetic field and dA is an infinitesimal area vector perpendicular to the surface.

(a) To verify that A = B × r is a vector potential for B, we need to show that ∇ × A = B.

Using the cross product property, we have ∇ × A = ∇ × (B × r). Applying the vector identity (A × B) × C = B(A · C) - C(A · B), we get ∇ × (B × r) = B(∇ · r) - r(∇ · B).

Since ∇ · r = 0 (as r = {x, y, 0}), and ∇ · B = 0 (as B has a constant magnitude in the z-direction), we find that ∇ × A = B, verifying A = B × r as the vector potential for B.

(b) The flux through a surface S can be calculated as Φ = ∫B·dA, where B is the magnetic field and dA is an infinitesimal area vector perpendicular to the surface.

Given that B has a constant strength b teslas in the z-direction, the flux through surface S will be Φ = ∫B·dA = ∫(0, 0, b) · (dxdy) = b∫dxdy = bA, where A is the area of the surface S.

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Answer:

Significant

Explanation:

As the word suggests, significant figures or digits are numbers that are valid in measurement.

Answer:

SIGNIFICANT DIGITS

Explanation:

MARK ME BRAINLIEST PLZZZ

Suki can go 0.854 meters to the end before the beam starts to tilt.

Beam length: L = 6.5 m

Beam weight: W b = 336 N

Suki's weight is W s = 590 N.

Suki stands in the middle of the steel beam and moves toward the end. Since the beam is supported by two posts that are spaced three meters apart, the distance she may go before the beam starts to lean is determined by how far she moves from the left support.

Thus;

according to formula

Wb × (3/2) = (Ws × x)

where:

Wb= Beam weight

Ws= Suki's weight

Adding the necessary values results in;

336 × 1.5 = 590 × x

x = (336 × 1.5)/590

x = 0.854 m

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The streamlines equations are \(x^2 - y^2 = c_1\) and \(xy = c_2\), where \(c_1\) and \(c_2\) are constants.

The velocity field is given by,

\(V_x = x (x^2 + y^2)^-^1^/^2\)

\(V_y = y (x^2+ y^2)^-^1^/^2\)

Now, we know that the tangent to a streamline is always parallel to the velocity vector. Hence, for the streamline equations, we must have

\(dx/dy = V_x/V_y\)

Therefore,\((x/y) = V_x/V_y = x/y\)

⇒ \(x^2 - y^2 = c_1\)

or, \((x+y)(x-y) = c_1\)

Hence, the equation of the streamlines are given by \(x^2 - y^2 = c_1\)

Now, for the other streamline equation, let's differentiate both sides of \(V_x\)= constant along the streamline:

\(dx/ds = constant/y\)

And differentiate both sides of \(V_y\) = constant along the streamline:

\(dy/ds = constant/x\)

Multiplying both equations, we get

\(xdx/ds = ydy/ds\)

or,\(xdx = ydy\)

Integrating, we get

\(x^2/2 = y^2/2 + c_2\)

or,\(xy = c_2\)

Thus, the equations of the streamlines are \(x^2 - y^2 = c_1\) and \(xy = c_2\)

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Answer:

Install sound absorbers such as foam or acoustical panels

Explanation:

They could install some sound absorbers such as foam or acoustical panels in the walls, floors, and ceiling of the conference room.

Answer:

Distance =400m

Time=20s

As we know that

\({\boxed{\sf speed \dfrac {Distance {}_{(d)}}{Time {}_{(t)}}}}\)

\(\LARGE\leadsto\sf speed=\dfrac {400}{20}\)

\(\LARGE\leadsto\sf 20m/s\)

The angle of refraction when a ray of light passes from air into water at an angle of 50.0° to the surface of the water is approximately 34.4°, and the speed of light in water is about 2.26 x 10⁸ m/s.

When light passes from one medium to another, it undergoes refraction, which involves a change in direction and speed. The angle of refraction is determined by Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the speeds of light in the two media.

In this case, the angle of incidence is 50.0° and the medium changes from air to water. By applying Snell's law, we can calculate the angle of refraction to be approximately 34.4°.

The speed of light in a medium is determined by the refractive index, which is the ratio of the speed of light in vacuum to the speed of light in the medium. The refractive index of water is approximately 1.33.

Therefore, the speed of light in water can be found by dividing the speed of light in vacuum (approximately 3 x 10⁸ m/s) by the refractive index, resulting in approximately 2.26 x 10⁸ m/s.

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Answer: c a d b

Explanation:

Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers thus, The pattern they predict in the markers over time would be C D A B.

In some parts of the world, glaciers are an important natural resource because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.

Due to this, Glaciologists monitor and try to predict the movement and morphology of glaciers.

One of the techniques used by "Glaciologists" in the monitoring and prediction of glaciers in the use of markers.

The movement of markers is measured relative to the edges of the valley down which the glacier flows.

Thus, The movement of the markers are then predicted using the Glen–Nye Flow Law.

The pattern they predict in the markers over time would be C D A B.

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