In this assignment, you will explore the important factors in designing a tile drainage system. Make sure to include graphs, code, spreadsheets, a sketch of the system, etc to support you answers.
For the base case, assume the following characteristics
you will construct the system using corrugated plastic drains with a radius of 89 mm
the soil is a silt loam with a hydraulic conductivity of 0.1 m/d
the tile drains are installed at a depth of 1.2m below the land surface
there is an impermeable unit 5m below the land surface
Design the system such that it has a drainage coefficient of 13 mm/day.
What does the drainage coefficient mean and why would you design to this?
Assuming a parallel array, what spacing between the laterals is required?
Answers
The drainage coefficient indicates the drainage rate from a unit area of the soil. For instance, a drainage coefficient of 13 mm/day implies that 13 mm of water drains from each square meter of soil per day. The drainage coefficient is critical in the design of tile drainage systems because it aids in the determination of the number and size of tiles required to drain a given area, as well as the spacing between the tiles.
S p = K D (A/D) where S p is the spacing between laterals, K is the hydraulic conductivity, D is the depth of the laterals, and A is the area of influence of the drain.
According to the base case, K = 0.1 m/d and D = 1.2 m.
We will calculate A by equating the drainage coefficient with the infiltration rate.
According to Darcy's law, the infiltration rate (I) is calculated as follows: I = K h where h is the hydraulic head. The hydraulic head is the difference in height between the water table and the soil surface, which is 5m for the given scenario.
Since the hydraulic conductivity (K) is 0.1 m/d, the infiltration rate (I) may be calculated as follows: I = K h= 0.1 * 5= 0.5 m/d= 500 mm/d.
Therefore, the area of influence (A) of the drain may be calculated as follows: A = (1000/13) * 500= 38,461.54 m²Now that we know A, we can calculate the spacing between laterals using the above formula. Sp = K D (A/D)= 0.1 * 1.2 (38,461.54/1.2)= 10000 m²Spacing between laterals for a parallel array is 10000 m².
Related Questions
The simply supported beam in the Figure has a rectangular cross-section 150 mm wide and 240 mm high.
(1) Compute the maximum bending stress in the beam.
(2) Sketch the bending stress distribution over the cross-section on which the maximum bending stress occurs.
(3) Compute the bending stress at a point on section B that is 35 mm below the top of the beam.
Answers
Before we can find the maximum bending stress in the beam, we must find the maximum bending moment.
\($I=\frac{b h^{3}}{12}=\frac{0.12(0.2)^{3}}{12}=80.0 \times 10^{-6} \mathrm{~m}^{4}$\)
1) The maximum bending stress in the beam occurs on the cross section that carries the largest
\($\sigma_{\max }=\frac{|M|_{\max } c}{I}=\frac{\left(16 \times 10^{3}\right)(0.1)}{80.0 \times 10^{-6}}=20.0 \times 10^{6} \mathrm{~Pa}=20.0 \mathrm{MPa}$$\)
What is the bending stress formula?The bending stress is computed for the rail by the equation Sb = Mc/I, where Sb is the bending stress in pounds per square inch, M is the maximum bending moment in pound-inches, I is the moment of inertia of the rail in (inches)4, and c is the distance in inches from the base of rail to its neutral axis.
2) The stress distribution on the cross section at D is shown in Fig. (d). When drawing the figure, we were guided by the following observations: (i) the bending stress varies linearly with distance from the neutral axis; (ii) because M_{max} is positive, the top half of the cross section is in compression and the bottom half is in tension; and (iii) due to symmetry of the cross section about the neutral axis, the maximum tensile and compressive stresses are equal in magnitude.
3) the bending stress at a point on section B that is 35 mm below the top of the beam.
\($\sigma=-\frac{M y}{I}=-\frac{\left(9.28 \times 10^{3}\right)(0.075)}{80.0 \times 10^{-6}}=-8.70 \times 10^{6} \mathrm{~Pa}=-8.70 \mathrm{MPa}$$\)
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Warning danger ahead sign
Answers
Answer: okiiiii
Explanation:
Ok
Explanation
An AC sine wave has an RMS value of 100 V. What's the average of the waveform?
A. 90 V
B. 80 V
C. 102 V
D. 92.6 V
Answers
Just took the test and it ISN'T 92.6 V, my guess is 80 V but I dont know because it only says if I got it wrong.
A pile driver of mass 300 kg is used to drive a pile of mass 500 kg vertically into the ground. The pile driver falls freely through a distance of 54.0 m, rebounding with a velocity relative to the pile and equal to the relative velocity immediately before impact. Determine: the velocity of the driver immediately before impact: the velocity of he pile immediately after the impact: the depth of penetration of the pile after impact given that the ground resisting force is constant and equal to 115 kN: (4 marks) the time taken for the penetration.
Answers
performance of novel thermal energy storage engineered cementitious composites incorporating a paraffin/diatomite composite phase change material
Answers
Thermal energy storage (TES) systems have become increasingly popular in recent years because of their capacity to store thermal energy, which is later released when needed.
These systems can decrease the energy consumption of buildings, reduce greenhouse gas emissions, and improve energy utilization effectiveness.
PCMs (phase change materials) have been found to be an effective solution for TES,
and they are being investigated for their use in concrete.
They are materials that can store and release thermal energy through phase changes.
The efficiency of TES systems is determined by the heat storage capacity of the PCMs,
their melting and freezing temperatures, and their thermal conductivity.
Paraffin is a widely used PCM in TES systems because of its high latent heat capacity.
When paraffin melts, it absorbs heat from the surrounding environment, resulting in a temperature decrease.
When it solidifies, it releases stored heat, resulting in a temperature rise.
In conclusion, the incorporation of PCM into the cementitious composite matrix has shown to be an effective way to increase the thermal storage capability of the composite.
The results show that the composite material has good thermal energy storage capacity and improved mechanical properties.
This novel thermal energy storage engineered cementitious composites incorporating a paraffin/diatomite composite phase change material can be used as an efficient building material for TES systems.
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Water is pumped from a lake to a storage tank 18 m above at a rate of 70 L/s while consuming 20.4 kW of electric power. Disregard any frictional losses in the pipes and any changes in kinetic energy, determine (a) the overall efficiency of the pump-motor unit (5-point), and (b) the pressure difference between the inlet and the exit of the pump (5-point).
Answers
Part A
For each method,a function to model the expected number of plants for each year
Part B
Use the Functions to Find the expected number of plants in 10 years for each method.
Part C
Un vendedor de camiones quiere suspender un vehículo de 4000 kg como se muestra en la figura, con fines publicitarios. La distancia b =15 m y la suma de las longitudes de los cables AB y BC es de 42 m. Los puntos A y C tienen una altura de 20 m . ¿Cuáles son las tensiones en los cables?
Answers
Answer:
english
Explanation:
the most perfect method of scavenging??
Answers
The "most perfect" method of scavenging will depend on the specific materials or resources being scavenged, as well as the context in which the scavenging is occurring.
What is scavenging?Scavenging refers to the process of collecting and using materials or resources that have been discarded or abandoned by others.
Therefore, In knowing what you're looking for: Before you start scavenging, it's important to have a clear idea of the materials or resources you need and where you might be able to find them. This will help you focus your search and make it more efficient.
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which indoor pollutant is commonly used in building materials, carpet backing, furniture, foam insulation, plywood, and particle board?
Answers
Formaldehyde is a indoor pollutant is commonly used in building materials, carpet backing, furniture, foam insulation, plywood, and particle board.
Pesticides are made comprised of both the active ingredient and chemicals that are used to transport the active agent. These carrier agents are referred to as "inerts" in pesticides because they are not poisonous to the insect that is being targeted, yet some inerts have the potential to harm human health. These substances, referred to as mutagens, work by directly changing the DNA sequence of a cell. Due to their size or structural characteristics, many mutagens are able to pass through nuclear and cellular membranes and interact directly with DNA, usually causing damage. A mixture of tiny liquid and solid particles that are in the air we breathe is referred to as particle pollution.
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37. WHICH OF THESE STATEMENTS IS TRUE ABOUT KEEPING CHILDREN SAFE IN
VEHICLES?
A. Infants should not ride in the front seat of vehicles
B. Children under one year and over 20 lbs. should ride buckled up in the front seat
C. The back seat is generally not the safest place in the car for all children 12 years and younger
Answers
A
It would be B but I say that it isn't because children under 3 should be riding a buckle up just for safety
Fuel-efficient electric and gas/electric hybrid vehicles produce very little sound at normal driving speeds, and are thus difficult for the visually impaired to detect. Does this raise problems for engineers similar to those raised by roundabouts? In what ways are these problems similar? In what ways are they different?
Answers
The issue of electric and hybrid vehicles being difficult for the visually impaired to detect does indeed raise problems for engineers, similar to those raised by roundabouts. Both issues involve the need to balance different design considerations, including safety, accessibility, and sustainability.
One similarity between the problems is that both involve designing for the needs of vulnerable road users, such as the visually impaired or pedestrians. In the case of roundabouts, engineers must consider factors such as crosswalk placement, pedestrian signals, and traffic speeds to ensure that the roundabout is safe and accessible for all users. Similarly, in the case of electric and hybrid vehicles, engineers must consider strategies for making these vehicles more detectable to visually impaired pedestrians, such as adding noise-making devices or using special road markings.
However, there are also some differences between the problems. With roundabouts, the focus is on designing a physical infrastructure that is safe and accessible for all users. With electric and hybrid vehicles, the focus is on designing a vehicle that is both fuel-efficient and safe for all users, including pedestrians. This requires a different set of design considerations and trade-offs.
Another difference is that the problem of electric and hybrid vehicles being difficult to detect is a relatively new issue, while roundabouts have been in use for many years. As a result, the solutions to the problems may require different approaches and may involve more experimentation and testing with new technologies.
Overall, both the issues of roundabouts and electric/hybrid vehicles highlight the need for engineers to consider the needs of all users when designing transportation infrastructure and vehicles. By balancing safety, accessibility, and sustainability, engineers can create solutions that meet the needs of a diverse range of users and help create more inclusive and sustainable communities.
If the load P on the beam causes the end C to be displaced 10mm downward, determine the normal strain in wires CE and BD.
Answers
aehhkl;sj,ldmdfm.nxtg,W{Glw4atokgh,h,rn
The normal strain in wire CE is equal to 10 mm 10 m = 0.001.
What is normal strain?Normal strain is a type of strain that occurs when an object is subjected to a stress where the stress is applied in a direction that is perpendicular to the surface of the object. This type of strain is also known as shear strain or transverse strain.
Normal strain is defined as the ratio of the change in length to the original length of the wire.
For wire CE, the original length L is equal to the length of the beam between points C and E, which is 10m. The change in length is equal to the downward displacement of end C, which is 10mm.
Therefore, the normal strain in wire CE is equal to $\frac{10 mm}{10 m} = 0.001$.
For wire BD, the original length L is equal to the length of the beam between points B and D, which is 10m. The change in length is equal to zero since point B is not displaced.
Therefore, the normal strain in wire BD is equal to 0.
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A four-cylinder, four-stroke internal combustion engine has a bore of 3.7 in. and a stroke of 3.4 in. The clearance volume is 16% of the cylinder volume at bottom dead center and the crankshaft rotates at 2400 RPM. The processes within each cylinder are modeled as an air-standard Otto cycle with a pressure of 14.5 lbf/in. 2 and a temperature of 60 8 F at the beginning of compression. The maximum temperature in the cycle is 5200 8 R.
Based on this model,
1- Write possible Assumptions no less than three assumptions
2- Draw clear schematic for this problem
3- Determine possible Assumptions no less than three assumptions
4- Draw clear schematic for this problem.
5- calculate the net work per cycle, in Btu, and the power developed by the engine, in horsepower.
Answers
Answer:
1) The three possible assumptions are
a) All processes are reversible internally
b) Air, which is the working fluid circulates continuously in a closed loop
cycle
c) The process of combustion is depicted as a heat addition process
2) The diagrams are attached
5) The net work per cycle is 845.88 kJ/kg
The power developed in horsepower ≈ 45374 hP
Explanation:
1) The three possible assumptions are
a) All processes are reversible internally
b) Air, which is the working fluid circulates continuously in a closed loop
cycle
c) The process of combustion is depicted as a heat addition process
2) The diagrams are attached
5) The dimension of the cylinder bore diameter = 3.7 in. = 0.09398 m
Stroke length = 3.4 in. = 0.08636 m.
The volume of the cylinder v₁= 0.08636 ×(0.09398²)/4 = 5.99×10⁻⁴ m³
The clearance volume = 16% of cylinder volume = 0.16×5.99×10⁻⁴ m³
The clearance volume, v₂ = 9.59 × 10⁻⁵ m³
p₁ = 14.5 lbf/in.² = 99973.981 Pa
T₁ = 60 F = 288.706 K
\(\dfrac{T_{2}}{T_{1}} = \left (\dfrac{v_{1}}{v_{2}} \right )^{K-1}\)
Otto cycle T-S diagram
T₂ = 288.706*\(6.25^{0.393}\) = 592.984 K
The maximum temperature = T₃ = 5200 R = 2888.89 K
\(\dfrac{T_{3}}{T_{4}} = \left (\dfrac{v_{4}}{v_{3}} \right )^{K-1}\)
T₄ = 2888.89 / \(6.25^{0.393}\) = 1406.5 K
Work done, W = \(c_v\)×(T₃ - T₂) - \(c_v\)×(T₄ - T₁)
0.718×(2888.89 - 592.984) - 0.718×(1406.5 - 288.706) = 845.88 kJ/kg
The power developed in an Otto cycle = W×Cycle per second
= 845.88 × 2400 / 60 = 33,835.377 kW = 45373.99 ≈ 45374 hP.
What happens to the speed of light if the IOR increases?
Answers
69.48 / 7.2 = 965 use number sense
Answers
Answer: See explanation
Explanation:
69.48 / 7.2 = 965 as written in the question isn't correct. The correct answer should have been:
69.48 / 7.2 = 9.65
It should be noted that when we divide, the answer that one gets cannot be more than the two numbers that were used for the division. Hence, there's no way that 965 would be more than 69.48 and 7.2.
a load of 12tonnes is put along a horizontal plane by a force at 30°to and above the flat. if the coefficient of sliding friction is 0.2 find the frictional force
Answers
Answer:
20368.917N
Explanation:
Frictional force (F) is the product of the Coefficient of friction and the normal reaction.
F = μN
Coefficient of friction, μ = 0.2
Normal reaction = MgCosθ
Mass, m = 12 tonnes = 12 * 1000 = 12000 kg
N = 12000 * 9.8 * cos30
N = 101844.58
F = 0.2 * 101844.58
F = 20368.917N
onsider a venturi with a throat-to-inlet area ratio of 0.8, mounted on the side of an airplane fuselage. the airplane is in flight at standard sea level. if the static pressure at the throat is 2100 lb/ft2, calculate the velocity of the airplane.
Answers
I really need help on this!
Which of the following is a term for a comparison between product metrics and values to industry standards and competitions metrics and values?
A: ideal value
B: competitive analysis
C: benchmark
D: marginally accepted value
Answers
Plz mark brainliest
Given: the coordinates of the points in fig. 1. A1: (-9,-46); a2: (20,-29); and a3: (28,17). Find: the length of r2
Answers
According to the given Figure(See Picture), the length of \(r_2 = O_2A_1=O_2A_2=O_2A_3\) is 47.85 units.
Since points A₁, A₂, A₃ are in circle , so we can apply circle equation
\(x^2 + y^{2} + 2gx + 2fy + c = 0\) __________(1)
Now substituting coordinates of point A₁ (-9,-46) in equation (1)
\(2197-18g-92f+c=0\) __________(2)
Substitute point A₂ (20,-29) in (1)
\(1241+40g-58f+c=0\) __________(3)
Substitute point A₃ (28,17) in (1)
\(1073+56g+34f+c=0\) ___________(4)
Solving (2), (3), (4)
g = 17.1619
f = -1.1586
c = -1994.6761
Now as per question,
\(r_2 = \sqrt{g^{2}+f^{2}-c}\)
\(r_2=\sqrt{(17.1619)^2+(-1.1586)^2-(-199.6761)}\)
\(r_2 = 47.85\)
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The complete question is:
Given the coordinates of the points in Fig. 1(See Picture). A1: (-9,-46); A2: (20,-29); and A3: (28,17). Find the length of \(r_2 = O_2A_1=O_2A_2=O_2A_3\).
An electric train is moving north at 100 mph and a wind is blowing to the west at 10 mph. Which way does the smoke blow?
Answers
there is no smoke its a electric train
Where in the 5nd intercostal space do you insert a needle in the right midclavicular line and what layers does it pass through?
Answers
The needle should be inserted in the 5th intercostal space in the right midclavicular line. It passes through the skin, subcutaneous tissue, intercostal muscles, and pleura.
In the 5th intercostal space, which is the space between the 5th and 6th ribs, you will locate the midclavicular line. This line can be found by drawing an imaginary line down from the middle of the clavicle (collarbone) towards the ribcage. Once you have identified the midclavicular line, you can measure down to the 5th intercostal space.
To insert the needle, you will first puncture the skin, which is the outermost layer. Then, you will pass through the subcutaneous tissue, which is the layer of fat beneath the skin. Next, you will encounter the intercostal muscles, which are the muscles between the ribs. Finally, the needle will penetrate the pleura, which is the thin membrane that covers the lungs. It is important to be careful when puncturing the pleura to avoid any damage to the lungs.
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A ball of mass m is dropped vertically from a height h0 above the ground.
If it rebounds to a height of h1, determine the coefficient of restitution between the ball and the ground.
Express your answer in terms of some or all of the variables m, h0, and h1.
Answers
The ball of mass m is dropped from a height h0 above the ground and falls to a height h1. The change in height can be expressed as h1 - h0. The mass of the ball, m, is a constant in this scenario and does not affect the distance the ball falls. The distance the ball falls is determined by the height it is dropped from (h0) and the gravitational force of the earth. Therefore, the distance the ball falls can be expressed as d = h1 - h0 = 1/2 gt^2, where g is the acceleration due to gravity and t is the time it takes for the ball to fall. The variables in this scenario are the initial height (h0), the final height (h1), and acceleration due to gravity.
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8. Which of these plastics is a themoplastic - melts or softens with heat.
Acrylic
Bakelite
Polyester resin
Melamine
Epoxy Resin
Could someone please help me, this is very urgent, I will pay an extra bonus if done correct.
Answers
Answer:
Acryclic
Explanation:
Hope it helps you!
Wire gages in an automobile generally range from gage 0 to gage ____.
A.
24
B.
18
C.
20
D.
30
Answers
Answer:
18 gauge
Explanation:
Standard automotive primary wire is 18 gauge. (internet search) Hope this helps
Drag the tiles to the correct boxes to complete the pairs.
Match the type of manufacturing system to its description.
agile manufacturing system
assembly line production system
lean manufacturing system
mass production system
focuses on manufacturing large and
continuous product runs.
arrowRight
focuses on the reduction of waste in the
manufacturing process
arrowRight
focuses on the ability to adapt to
customer and market changes
arrowRight
focuses on improving worker efficiency
by making tasks short and repetitive
arrowRight
Answers
The correct matching would be:
Mass production system -> focuses on manufacturing large and continuous product runs.
The other matching pairsLean manufacturing system -> focuses on the reduction of waste in the manufacturing process.
Agile manufacturing system -> focuses on the ability to adapt to customer and market changes.
Assembly line production system -> focuses on improving worker efficiency by making tasks short and repetitive.
The mass production system emphasizes the production of a high volume of products in a consistent manner. The lean manufacturing system has the objective of minimizing or eliminating waste.
The agile manufacturing system places great importance on accommodating alterations from customers and the market. The assembly line manufacturing technique enhances worker productivity by assigning brief and repetitive tasks.
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computer system analyst advantage
Answers
Answer:
They help an organization realize the maximum benefit from its investment in equipment, personnel, and business processes. They use and analyze systems, interpret data, and customize systems to better meet the organization's needs.
Explanation:
brainliest plz
Answer:
ục tiêu của pháp y máy tính là kiểm tra phương tiện kỹ thuật số theo cách thức pháp y với mục đích xác định, bảo tồn, phục hồi, phân tích và trình bày các sự kiện và ý kiến về thông tin kỹ thuật số
Explanation:
Program Increment (PI) Planning is a major event that requires preparation, coordination, and communication. What are two key areas a Release Train Engineer should focus on to support a successful PI Planning event? (Choose two.)
a) Architectural readiness - Defining the Architectural Runway
b) Organizational readiness - Strategic alignment; roles, teams, and train setup
c) Operational readiness - Facilitating PI events such as scrum of scrums, Iteration Planning, and System Demo
d) Facilities readiness - Space and logistics for the event
e) Process readiness - The operational rhythm that enables SAFe governance
Answers
Organizational readiness - Strategic alignment; roles, teams, and train setup:Organizational readiness is another essential area that Release Train Engineer should focus on for a successful PI Planning event. Organizational readiness involves the following:Strategic alignment - PI planning requires collaboration between different organizations within the enterprise.
Program Increment (PI) Planning is a major event that requires preparation, coordination, and communication. Following are the two key areas a Release Train Engineer should focus on to support a successful PI Planning event:Architectural readiness - Defining the Architectural RunwayOrganizational readiness - Strategic alignment; roles, teams, and train setup.A. Architectural readiness - Defining the Architectural Runway: Architectural readiness is one of the two critical areas for Release Train Engineer should focus on to support a successful PI Planning event. Architectural readiness requires defining the Architectural Runway, which is a long-range architectural plan that helps the development organization define the initiative's technical and architectural direction. A successful PI Planning event begins with the team's knowledge of the architectural direction, its scope, and the corresponding user story assumptions. Defining the Architectural Runway also helps teams identify architectural epics that support the product backlog. Thus, Architectural readiness is an essential element in the SAFe Framework that ensures a successful PI Planning event.B. Thus, strategic alignment is critical to ensure that all stakeholders have a shared understanding of the program objectives and how each department contributes to achieving those objectives.Roles, teams, and train setup - For a successful PI Planning event, a well-defined roles and responsibilities and a well-structured team is essential. Therefore, the Release Train Engineer must ensure that all team members understand their roles and responsibilities and ensure a well-structured team that facilitates a successful PI Planning event.
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Consider the titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl.
For each volume of HCl added, decide which of the components is a major species after the HCl has reacted completely.
Kb for CH3NH2 = 4.4 x 10-4.
What species are present based off what is being added?
200.00 mL HCl added
yes no H+
yes no H2O
yes no Cl-
yes no CH3NH2
yes no CH3NH3+
300.00 mL HCl added
yes no H+
yes no H2O
yes no Cl-
yes no CH3NH2
yes no CH3NH3+
Calculate the pH at the equivalence point for this titration?
Answers
Answer:
The answers are in the explanation. The pH is 5.91
Explanation:
The CH3NH2 reacts with HCl as follows:
CH3NH2 + HCl → CH3NH3⁺ + Cl⁻
When 200mL of HCl are added, the moles of CH3NH2 and HCl are reacting completely producing CH3NH3+ and Cl-. That means the species present are:
no H+. All reacted
yes H2O. Because the water is present in the solutions of HCl and CH3NH2
yes Cl-. Is a product of the reaction
Yes CH3NH2. Is consumed in the reaction but comes from the equilibrium of CH3NH3+
yes CH3NH3+. Is the other product of the reaction. MAJOR SPECIES
When 300.00mL of HCl are added, 100mL are in excess:
yes H+. Is in excess: H+ + Cl- = HCl in water. MAJOR SPECIES. Determine the pH of the solution.
yes H2O. Is present because the reactants are diluted.
yes Cl-. Is a product of reaction and comes from HCl.
Yes CH3NH2. The reactant is over but comes from the equilibrium of CH3NH3+
yes no CH3NH3+. Yes. Is a product and remains despite HCl is in excess.
To find the pH:
At equivalence point the ion that determines pH is CH3NH3+. Its concentration is:
0.100L * (0.200mol/L) = 0.0200 moles / 0.300L = 0.0667M CH3NH3+
The equilibrium of CH3NH3+ is:
Ka = Kw/kb = 1x10-14/4.4x10-4 = 2.273x10-11 = [H+] [CH3NH2] / [CH3NH3+]
As both [H+] [CH3NH2] comes from the same equilibrium:
[H+] = [CH3NH2] = X
2.273x10-11 = [X] [X] / [0.0667M]
1.5159x10-12 = X²
X = 1.23x10-6M = [H+]
As pH = -log [H+]
pH = 5.91
The pH at the equivalent point for this titration is "5.91".
pH Calculation:\(CH_3NH_2 = 0.200\ M\\\\ \text{volume} = 100.0\ mL = 0.100\ L\\\\HCl = 0.100\ M\\\\\)
We must now quantify the pH well at the equivalence point.
We know that even at the point of equivalence, moles of acid and moles of the base are equivalent. As such, first, we must calculate the number of moles of the given base.
Calculating the Moles in \(CH_3NH_2 = 0.200\ M \times 0.100\ L = 0.0200\ moles\)
Calculating the Moles in \(HCl = 0.0200 \ moles\)
Calculating the volume of \(HCl\):
\(\to \text{Molarity} = \frac{ \text{moles}}{\text{volume \ (L)}} \\\\\to \text{Volume} = \frac{\text{moles}}{\text{molarity}}\\\\\)
\(= \frac{0.0200 \ moles}{ 0.100\ M}\\\\= 0.200 \ L\\\\= 200 \ mL\\\\\)
Calculating the reaction among the acid and base:
\(CH_3NH_2 + HCl \longrightarrow CH_3NH_3^{+} + Cl^-\)
\(0.0200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.0200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.0200\)
Therefore the conjugate acid of the bases exists at the standard solution.
Then we must calculate the new molar mass of \(CH_3NH_3^+\).
Total volume\(= 100 + 200 = 300\ mL = 0.300\ L\)
\([CH_3NH_3^+] = \frac{0.0200\ mole}{ 0.300\ L}= 0.0667\ M\)
Using the ICE table
\(CH_3NH_3^+ + H_2O \longrightarrow CH_3NH_2 + H_3O^+\)
\(I \ \ \ \ \ \ \ \ \ \ 0.0667 \ \ \ \ \ \ \ \ \ 0\ \ \ \ \ \ \ \ \ 0\\\\C\ \ \ \ \ \ \ \ -x\ \ \ \ \ \ \ \ +x \ \ \ \ \ \ \ \ +x\\\\E \ \ \ \ \ \ \ \ \ \ \ \ 0.0667-x \ \ \ \ \ \ \ \ \ \ \ \ +x \ \ \ \ \ \ \ \ \ \ \ \+x\\\\\to Ka = \frac{[CH_3NH_2] [H_3O^+] }{[CH_3NH_3^+]}\)
Calculating \(K_a\) from \(K_b\)
\(\to K_a \times K_b = 1\times 10^{-14}\\\\\to K_a = \frac{1\times 10^{-14}}{4.4\times 10^{-4}} = 2.27\times 10^{-11}\\\\\)
\(= 2.27\times 10^{-11} \\\\= x\times \frac{x}{(0.0667-x)}\)
The x in the 0.0667-x can be ignored since the Ka value is just too small and it also does not follow the five percent criteria.
\(\to 2.27 \times 10^{-11} \times 0.0667 = x_2\\\\\to x_2 = 1.515\times 10^{-12}\\\\\to x = 1.23\times 10^{-6}\ M\\\\\to [H_3O^+] = x = 1.23\times 10^{-6}\ M\\\\\)
We have the formula to calculate pH.
\(\to pH = - \log [H_3O^+] = - \log 1.23\times 10^{-6}\ M= 5.91\)
The pH at the equivalent point for this titration is "5.91".
Find out more information about the pH here:
brainly.com/question/15289741
Special impact sockets and extensions are easily
identified because they are:
(A) chrome.
(B) aluminum.
(C) flat black
Durant la sto
(D) hard rubber.
les
Answers
Answer:
C
Explanation:
they are flat black
Determine the enthalpy, volume and density of 1.0 kg of steam at a pressure of 0.5 MN/m2 and with a dryness fraction of 0.96
Answers
Answer:
Enthalpy, hsteam = 2663.7 kJ/kg
Volume, Vsteam = 0.3598613 m^3 / kg
Density = 2.67 kg/ m^3
Explanation:
Mass of steam, m = 1 kg
Pressure of the steam, P = 0.5 MN/m^2
Dryness fraction, x = 0.96
At P = 0.5 MPa:
Tsat = 151.831°C
Vf = 0.00109255 m^3 / kg
Vg = 0.37481 m^3 / kg
hf = 640.09 kJ/kg
hg = 2748.1 kJ/kg
hfg = 2108 kJ/kg
The enthalpy can be given by the formula:
hsteam = hf + x * hfg
hsteam = 640.09 + ( 0.96 * 2108)
hsteam = 2663.7 kJ/kg
The volume of the steam can be given as:
Vsteam = Vf + x(Vg - Vf)
Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)
Vsteam = 0.3598613 m^3 / kg
From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3