Radioactive decay is a spontaneous process in which unstable nuclei emit radioactive particles and energy. Fission occurs as the result of high-energy bombardment of nuclei that cause them to break into smaller nuclei, radioactive particles, and energy. All fission events are not the same. The nuclei split in a number of ways to produce several different products.
What is Radioactive?The process through which an unstable atomic nucleus loses energy through radiation is known as radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration. A substance that has unstable nuclei is regarded as radioactive. Alpha decay, beta decay, and gamma decay are three of the most frequent kinds of decay, and they all entail the emission of one or more particles.
Beta decay is a result of the weak force, while the nuclear force and electromagnetism are in charge of the other two mechanisms. The capture of an inner electron from one of the electron shells by an unstable nucleus is the fourth prevalent form of decay. A series of electrons drop as a result of that electron being lost from the shell.
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Calculate the destiny of the object that has a mass of 453 g and occupies the volume of 225 cm3
A ( 2.01g/cm3
B( 5.00 g/cm3
C( 453 g/cm3
D( 228 g/cm3
density = 2.013g/cm3
Explanation:
density = mass/volume
density = 453g/225cm3
density = 2.013g/cm3
Given: K = °C 273. 15 What is the temperature of the flame in degrees Celsius? You measure the flame of a candle and get a reading of 1,376. 06 K. This value is equal to °C.
Temperature is a physical quantity measured by Celsius and Kelvin. The temperature of the candle flame is \(\rm 1102.91^{\circ}C\).
What are Celsius and Kelvin?Celsius and Kelvin are the degree unit of temperature and is used for measuring the hotness and coldness of the substance.
The formula for calculating temperature in Celsius is:
\(\rm K = ^{\circ}C + 273.15\)
Given,
K = \(\rm ^{\circ} C + 273.15\)K = 1,376.06Substituting values in the formula:
\(\begin{aligned}1,376.06 &= ^{\circ}\rm C + 273.15\\\\^{\circ}\rm C &= 1,376.06 - 273.15\\\\&= \rm 1102.91^{\circ}C\end{aligned}\)
Thus, \(\rm 1102.91^{\circ}C\) is the temperature of the burning candle.
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Caiculate the mass of moist air that has 8 Nitrogen molecules, 3 Oxygen molecules and 3 Water Vapour molecules. From the Periodic table, Nitrogen molar mass is 14 g/mol, Oxygen 16 g/mol, Hydrogen 1 g/mol
The mass of the moist air is calculated by multiplying the number of molecules of each component by their respective molar masses and summing them up. In this case, the total mass is 374 grams.
To calculate the mass of moist air, we need to determine the molar mass of each component and then calculate the total mass.
Molar mass of Nitrogen (N2) = 2(N) = 2(14 g/mol) = 28 g/mol
Molar mass of Oxygen (O2) = 2(O) = 2(16 g/mol) = 32 g/mol
Molar mass of Water Vapor (H2O) = 2(H) + 16(O) = 2(1 g/mol) + 16 g/mol = 18 g/mol
Now, let's calculate the total mass of the given molecules:
Number of Nitrogen molecules = 8
Number of Oxygen molecules = 3
Number of Water Vapor molecules = 3
Total mass = (8 molecules)(28 g/mol) + (3 molecules)(32 g/mol) + (3 molecules)(18 g/mol)
Simplifying the equation:
Total mass = 224 g + 96 g + 54 g
Total mass = 374 g
Therefore, the mass of the moist air with the given composition is 374 grams.
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100 POINTS HELP PLEASE WILL MARK BRAINLIEST The data set has a 22% error and very small range of 0.1 g/cm3.
Which set of terms correctly describes the data?
A. The data is both accurate and precise.
B. The data is not accurate but is precise.
C. The data is accurate but not precise.
D. The data is neither accurate nor precise.
Answer:
B
That right...........
The data is not accurate but is precise. The 22% error indicates inaccuracy, but the small range suggests high precision and reproducibility.
Option (B) is correct.
Accuracy and precision are two important aspects in evaluating the quality of data.
Accuracy refers to how close the measured values are to the true or target value. In this case, the data set has a 22% error, indicating that it is not accurate. The error suggests that the measured values deviate significantly from the true values or the accepted standard.
Precision, on the other hand, refers to the degree of reproducibility or consistency of the measured values. The small range of 0.1 g/cm³ indicates that the data points are closely clustered together, making the data precise.
Based on these definitions, the correct description for the data set is option B. It is not accurate due to the presence of a significant error, but it is precise because the measured values have a small range and are reproducible.
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Which of the following would electrolysis NOT be used for?
A. Producing electricity
B. Extracting reactive metals
C. Plating metals onto other metals
D. Producing hydrogen gas
Answer:
D
Explanation:
Please mark me as brainlyest
Producing hydrogen gas. Hence, option D is correct.
What is electrolysis?Electrolysis is described by two half-reactions. These half reaction are the oxidation half-reaction and reduction half-reaction.
Electrolysis involves the transfer of electrons. Each half reaction is characterized by the loss or gain of electrons.
The only reason why producing hydrogen gas is not used most of the time is because electrolysis has very low efficiency, most of the energy finishes up being converted to heat and 95% of the hydrogen is produced by steam reforming.
Hence, option D is correct.
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The mass In grams of fluorine in a sample of MgF 2 that contains 20.1 grams of magnesium is:A)10.6 grams B)6.4 grams C)42.4 grams D)16.5 grams
1. In order to answer this one and the next one, we will use mass percentage as our guide, since every compound has a mass percentage for each element, and this is found by checking the total mass and the separate masses of each element, for example, MgF2, the mass percentage is 39% for Mg and 61% for F2, this is due to their molar mass, 24g for Mg and 38g for F2
We have 27.1 g of Mg, and this will always correspond for 39% of the total mass of the compound, so we can do the following math:
100% = x
39% = 27.1g
x = 69.5 grams is the total mass of MgF2, now we only have to subtract the value of Mg and then we will have F2
69.5 - 27.1 = 42.4 grams, this is the mass of Fluorine
2. The same step by step from the previous question, 36% of the total mass is Al and 64% is S, but this question has a little difference, now we have the mass of the compound, but the process is very similar
100% = 50.2 grams
64% = x grams
x = 32.1 grams, which can be considered as letter A
Which organs are responsible for getting rid of waste from the human body?
Brain and pancreas
Kidneys and bladder
Heart and lungs
Muscles and bones
Answer:
Kidneys and Bladder is the organ responsible for getting rid of waste from the human body
Answer:
kidney and bladder
Explanation:
the kidney and bladder are the organs responsible for getting rid of waste in the human body
express your answer in complete form in the order of orbital filling as a string without blank space between orbitals.
Silicon contains 14 electrons and thus, its electronic configuration is written as follows:
1s², 2s², 2p⁶, 3s², 3p².
What is electronic configuration?The filling of electron in different orbitals of an atom is called electronic configuration of the element. The electrons fill from the lowest energy levels to highest energy level.
The atomic number of an element is the number of its electron in its atomic state. Silicon is 14th element in periodic table. Hence, silicon contains 14 electrons.
The capacity of s orbital is 2 and that of p orbital is 6. Thus the electronic configuration of silicon can be written as: 1s², 2s², 2p⁶, 3s², 3p².
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Your question is incomplete but your complete question was as follows:
Si, express your answer in complete form in the order of orbital filling as a string without blank space between orbitals.
a chemist must prepare of aqueous iron(iii) bromide working solution. he'll do this by pouring out some aqueous iron(iii) bromide stock solution into a graduated cylinder and diluting it with distilled water. calculate the volume in of the iron(iii) bromide stock solution that the chemist should pour out. be sure your answer has the correct number of significant digits.
The volume of the iron(iii) bromide stock solution that the chemist should pour out will be 137 ml.
Initial volume of Iron (III) Bromide (FeBr3) solution (V1) = 475 ml
Initial molarity of Iron (III) Bromide (FeBr3) solution (M1) = 1.0 M
Final molarity of Iron (III) Bromide (FeBr3) solution (M2) = 3.47 M
Final volume of Iron (III) Bromide (FeBr3) solution (V2) = ?
To find out the final volume (V2) we will use the following equation
M1V1 = M2V2
Rearrange the equation for final volume (V2)
V2 = M1V1 / M2
Put the values in the above equation
V2 = 1.0 M × 475 ml / 3.47 M
V2 = 475 / 3.47 ml
V2 = 137 ml
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Juan carlos placed 35 grams of ice into a dry, 200-gram container. The top of the container was attached tightly. When the ice was completely melted, he measured the mass of the container with the liquid water. What should the mass of the liquid water in the container be?.
To find the mass of the liquid water in the container, we need to consider the principle of conservation of mass. The total mass before and after the ice melts should be the same.
First, let's find the mass of the ice. Juan Carlos placed 35 grams of ice into the container. Next, let's find the total mass of the ice and the container before the ice melts. The mass of the container is given as 200 grams. Therefore, the total mass before the ice melts is 35 grams (mass of ice) + 200 grams (mass of container) = 235 grams.
Since the ice has completely melted, the mass of the liquid water should be the same as the total mass before the ice melts, which is 235 grams. So, the mass of the liquid water in the container should be 235 grams.
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How many absorptions would you expect to observe in the 13C NMR spectra of the following molecules?a) 2-Methyl-2-buteneb) trans-1,3-Dimethylcyclohexan
The absorptions would you expect to observe in the ¹³C NMR spectra of the molecules a) 2-Methyl-2-butene is 5 signals
b) trans-1,3-Dimethylcyclohexan is 8 signals.
The proton which have equivalent chemical environment will gives one signal in ¹³C NMR. the ¹³C NMR signals will tell us about the number of different set of carbon which is in equivalent environment.
a) 2-Methyl-2-butene - in this compound there are 5 carbon atoms present . all the 5 carbon atoms are having the different chemical environment ,so the ¹³C NMR will show 5 signals.
b) trans-1,3-Dimethylcyclohexan - in this compound there are 5 carbon atoms present . all the 8 carbon atoms are having the different chemical environment ,so the ¹³C NMR will show 8 signals.
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A balanced chemical equation always obeys law of conservation of ___.
A balanced chemical equation always obeys law of conservation of mass.
A balanced chemical equation generally obeys to law of conservation of mass. As per this regulation the mass of items should be equivalent to the mass of reactants. A response is supposed to be adjusted when the complete mass of particles on the two sides of the substance response is equal.According to the law of conservation of mass, the mass of the items in a synthetic response should rise to the mass of the reactants.
The law of conservation of mass is helpful for various computations and can be utilized to tackle for obscure masses, such how much gas consumed or delivered during a reaction.They should submit to the Law of conservation of Mass that expresses that matter can't be made or obliterated, it is saved. The mass of the reactants should rise to the mass of the products.Thus, the mass of substances created in a synthetic response is consistently equivalent to the mass of responding substances. Consequently, you really want to have a similar number of each kind of component on each side of a synthetic condition. This is the entire reason for adjusting a synthetic condition.
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Explain the term rate of a chemical reaction.
Answer:
The rate of a reaction is a measure of how quickly a reactant is used up, or a product is formed.
Explanation:
A 25.0 g piece of brass at 325 °C was placed into a sample of water. The final temperature of the water and brass was 42.0 °C. How much energy is released by the brass?
The energy released by the brass is an example of the heat of fusion.
How much energy is released by the brass?The heat released by the brass can be calculated using the equation:q = m × c × ΔTwhere q is the amount of energy released (in Joules), m is the mass of the brass (25.0 g), c is the specific heat capacity of brass (0.385 J/g•°C), and ΔT is the change in temperature (325 °C - 42.0 °C = 283 °C).Therefore, the energy released by the brass is:q = (25.0 g) × (0.385 J/g•°C) × (283 °C)q = 29,202.5 JHeat of fusion is the amount of energy released or absorbed when a substance changes from a solid to a liquid or vice versa. In this case, the brass is changing from a solid to a liquid and releasing energy in the process. The energy released can be calculated using the formula: q = m·ΔT·c, where q is the heat of fusion, m is the mass of the brass, ΔT is the change in temperature, and c is the specific heat capacity of the brass.The mass of the brass is 25.0 g. The change in temperature is 325 °C - 42.0 °C, or 283 K. The specific heat capacity of brass is 0.387 J/g·K. Plugging these values into the equation gives us a heat of fusion of 2,969.2 joules. This is the amount of energy released by the brass when it changed from a solid to a liquid.To learn more about The mass of the brass refer to:
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Answer:
-283 C
Explanation:
I got it right
Please help me solve this questionn as fast as possible oofff
Answer:
sorry I don't know it I'm only 7 th grade
the alkene mixture obtained on dehydration of 2,2-dimethylcyclohexanol contains a significant amount of 1,2-dimethylcyclohexene draw the structure of 1,2-dimethylcyclohexene show a mechanism for the formation of this alkene product draw the structures and give the names of any other alkene products, explaining how they could arise from the dehydration reaction
1,2-Dimethylcyclohexene is formed as a significant product during the dehydration of 2,2-dimethylcyclohexanol. Other alkene products that can arise from this reaction include 1-methylcyclohexene and 3-methylcyclohexene.
The structure of 1,2-dimethylcyclohexene can be represented as follows:
CH3 CH3
| |
C = C
The formation of 1,2-dimethylcyclohexene involves an E1 elimination reaction, where the hydroxyl group (-OH) is eliminated from 2,2-dimethylcyclohexanol. The reaction proceeds through a carbocation intermediate. The mechanism can be summarized as follows:
1. Protonation: The acid-catalyzed reaction begins with the protonation of the hydroxyl group, generating a protonated alcohol.
2. Carbocation formation: The protonated alcohol undergoes heterolysis, leading to the formation of a carbocation intermediate.
3. Carbocation rearrangement: The carbocation intermediate can undergo rearrangement to form a more stable carbocation through hydride or alkyl shifts.
4. Dehydration: The carbocation reacts with a neighboring hydrogen on a carbon atom to form a double bond, resulting in the formation of 1,2-dimethylcyclohexene.
In addition to 1,2-dimethylcyclohexene, other alkene products that can be formed during the dehydration of 2,2-dimethylcyclohexanol include 1-methylcyclohexene and 3-methylcyclohexene. These isomeric products arise from the different positions where the hydrogen atom can be eliminated, resulting in different regioisomers.
Overall, the dehydration of 2,2-dimethylcyclohexanol leads to the formation of 1,2-dimethylcyclohexene as a major product, along with other alkene isomers.
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When Mendel crossed a plant with green peas and a plant with yellow peas, what color peas did the offspring have?
A. All offspring had green
peas.
B. All offspring had yellow
peas.
C. Half of the offspring had
yellow peas and half had
green peas.
D. Some of the offspring had
yellow peas and some had
yellow-green peas.
PLEASE HURRY
Answer: B have a bless day.
Explanation:
What gives a pant cell a rigid shape?
A: Chloroplast
B: Vacuole
C: Cell wall
D: Cell membrane
Help me please
Extra points & brainlest
Answer:
Cell Wall
Explanation:
In plant cells, the cell wall is rigid the outer structure that protects the plant cell.
an athlete has 15% body fat by mass. What is the weight of fat, in pounds, of a 74 kg-athlete?
The weight of fat is 24.27 pounds of a 74 kg athletes.
How to find the weight of substance ?15% by mass means 15 g of fat is present in 100g of mass.
Convert kg into grams
1 kg = 1000 gram
74 kg = 74000 g
Now,
Mass of body = \(\frac{74000 g \times 15\ g}{100}\)
= 740 × 15
= 11100 g
Convert g into kg
11100 g = 11.1 g
Convert kg into pounds
1 kg = 2.205 pounds
11.1 kg = 11.1 × 2.205
= 24.47 pounds
Thus from above conclusion we can say that the weight of fat is 24.27 pounds of a 74 kg athletes.
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what is an magnetic pole
Answer:
Earth's magnetic field, also known as the geomagnetic field, is the magnetic field that extends from the Earth's interior out into space, where it interacts with the solar wind, a stream of charged particles emanating from the Sun.
calculate the number of moles of 252g of nitric acid
Answer:
Divide the amount of HNO3 by 63 to determine how many moles there are in the amount of HNO3 you are using for your calculations. For example, if there are 1,000 grams of HNO3, divide 1000 by 63; the result will be the number of moles contained in 1,000 grams of HNO3, which is 15.87 moles.
Explanation:
Answer:
1 grams Nitric Acid is equal to 0.015869781460413 mole. Multiple 252 grams by 0.015869781460413. The answer is 3.999184928024076. Don't round as it may create errors.
For future reference, just look online for a converter (Unless of course your teacher taught you the conversions, then use those.)
The sharing amongst atoms is what type of bond
Answer:
Covalent bond
Explanation:
The sharing amongst atoms leads to the formation of covalent bonds.
Covalent bonds are bonds formed between two or more atoms having zero or very small electronegativity difference. Such bonds exists in the molecules of non-metals.
Each of the atom tends to share the valence electrons in their outer energy levels to be able to mimic the noble gas structure. For the formation of this bond type, each of the atom requires odd or unpaired electrons.
Given: 4.0 mL of methyl salicylate
a) Calculate the theoretical yield of salicylic acid from the given starting mass of methyl salicylate. Please also include the units from the calculations.
b) What key change do you expect to see in the IR spectrum when the ester starting material is converted to the carboxylic acid?
c) What key change do you expect to see in the 1H NMR spectrum when the ester starting material is converted to the carboxylic acid?
a)
To calculate the theoretical yield of salicylic acid from the given starting mass of methyl salicylate,
Explanation :
follow these steps:
1. Determine the molecular weights of methyl salicylate (C8H8O3) and salicylic acid (C7H6O3).
Methyl salicylate: 152.15 g/mol;
Salicylic acid: 138.12 g/mol
2. Calculate the mass of the 4.0 mL of methyl salicylate.
Assuming its density is 1.174 g/mL (check the actual density if available), mass = volume x density = 4.0 mL x 1.174 g/mL = 4.696 g.
3. Determine themoles of methyl salicylate:
moles = mass/mmolecular weight = 4.696 g/152.15 g/mol = 0.03083 mol.
4. Since the reaction between methyl salicylate and salicylic acid has a 1:1 stoichiometry, the moles of salicylic acid will be the same as the moles of methyl salicylate: 0.03083 mol.
5. Calculate the theoretical yield of salicylic acid: mass = moles x molecular weight = 0.03083 mol x 138.12 g/mol = 4.261 g.
The theoretical yield of salicylic acid from the given starting mass of methyl salicylate is 4.261 grams.
b)
In the IR spectrum, the key change when theester starting material (methyl salicylate) is converted to the carboxylic acid (salicylic acid) is the appearance of a broad O-H stretching band at around 2500–3300 cm1, indicating the presence of the carboxylic acid group.
c)
In the 1H NMR spectrum, the key change when the ester starting material (methyl salicylate) is converted to the carboxylic acid (salicylic acid) is the disappearance of the singlet peak corresponding to the methyl protons of the ester group (3.8 ppm) and the appearance of a new peak corresponding to the carboxylic acid proton (10–12 ppm).
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The density of an object is 7.3 g/mL and the volume is 0.94
mL. What is the mass of the object?
Answer:
The answer is 6.86 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
volume = 0.94 mL
density = 7.3 g/mL
We have
mass = 7.3 × 0.94 = 6.862
We have the final answer as
6.86 gHope this helps you
A solution of NaCl was prepared in the following manner: 0.0842 g of NaCl is massed out on an analytical balance. The solid is transferred to a 25.00 mL volumetric flask. Deionized water is added to the flask such that the bottom of the meniscus is at the line. A 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask using a volumetric pipet and diluted to volume. 6. Calculate the concentration of NaCl in the resulting solution in mg/L NaCl. (answer = 67.4 mg/L) 7. Calculate the concentration of NaCl in the resulting solution using propagation of error through the calculation. Use the manufacturer's tolerance values as the absolute error. The tolerances can be found in Chapter 2 of the Harris text. Assume a Class 1 balance and Class A glassware. Treat the tolerances as random error. (answer = 67.4+0.4 mg/L) 8. Identify 2 possible sources of random (indeterminate) error. Identify 2 possible sourses of systematic (determinate) error.
Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl
To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7. Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.
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The introduction of DDT (dichlorodiphenyltrichloroethane) and other ____________ pesticides into agriculture after World war II changed pest control and food production
The introduction of DDT (dichlorodiphenyltrichloroethane) and other synthetic pesticides into agriculture after World War II changed pest control and food production. What are pesticides? Pesticides are chemicals that are used to kill pests. Pests are defined as any organism that interferes with human activity, like insects that damage crops or rodents that spread disease. Synthetic pesticides were created after World War II.
They include DDT (dichlorodiphenyltrichloroethane) and other synthetic pesticides. What was the impact of the introduction of synthetic pesticides? The introduction of synthetic pesticides like DDT had a major impact on pest control and food production. These pesticides allowed for increased crop yields and better control over insect and rodent populations.
However, they also had negative effects on the environment and human health. Pesticides can contaminate soil and water, harm beneficial organisms, and lead to the development of pesticide-resistant pests. They can also cause health problems for humans, including cancer, reproductive issues, and neurological damage.
The use of synthetic pesticides continues to be a controversial issue, with advocates for both sides of the argument. Some argue that they are necessary for efficient food production, while others argue that they are too harmful to be used safely.
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You have a mixture that contains 0. 350 moles of Ne(g), 0. 250 moles of He(g), and 0. 400 moles CH4(g) at 400 K and 2 atm. What is the partial pressure of He?
The partial pressure of He is 0.5 atm.
To find the partial pressure of He, we first need to calculate the total moles of gas in the mixture:
Total moles of gas = 0.350 moles Ne(g) + 0.250 moles He(g) + 0.400 moles CH₄(g) = 1.0 moles of gas
Next, we can use the mole fraction of He to calculate its partial pressure:
Mole fraction of He = moles of He / total moles of gas
Mole fraction of He = 0.250 moles He(g) / 1.0 moles of gas = 0.25
The partial pressure of He can be calculated using the following equation:
Partial pressure of He = mole fraction of He x total pressure
Partial pressure of He = 0.25 x 2 atm = 0.5 atm
Therefore, the partial pressure of He in the mixture is 0.5 atm.
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Molecular scale for gas
El volumen de un gas en un recipiente cerrado es de 3.5 litros a una temperatura de 25oC y una atmósfera constante de presión. ¿ Cuál es el volumen del gas en el recipiente si se disminuye la temperatura a 7oC?
Answer:
El volumen del gas en el recipiente es 3.29 L si se disminuye la temperatura a 7°C
Explanation:
La Ley de Charles es una ley de los gases que relaciona el volumen y la temperatura de una cierta cantidad de gas a presión constante.
Esta ley establece que el volumen es directamente proporcional a la temperatura del gas. Es decir que si la temperatura aumenta, el volumen del gas aumenta, mientras que si la temperatura del gas disminuye, el volumen disminuye.
Matemáticamente, si la cantidad de gas y la presión permanecen constantes, el cociente entre el volumen y la temperatura siempre tiene el mismo valor:
\(\frac{V}{T}=k\)
Suponiendo un cierto volumen de gas V1 que se encuentra a una temperatura T1 al comienzo del experimento, al variar el volumen de gas hasta un nuevo valor V2, entonces la temperatura cambiará a T2, y se cumplirá:
\(\frac{V1}{T1}=\frac{V2}{T2}\)
En este caso, sabes:
V1= 3.5 LT1= 25 °C=298 °K (siendo 0°C=273°K)V2=?T2=7 °C=280 °KReemplazando:
\(\frac{3.5 L}{298 K}=\frac{V2}{280 K}\)
Y resolviendo obtienes:
\(V2=280 K*\frac{3.5 L}{298 K}\)
V2= 3.29 L
El volumen del gas en el recipiente es 3.29 L si se disminuye la temperatura a 7°C
Predict the product of the reaction of 1-butene with bromine. Enter the IUPAC name. View Available Hint(s) Submit Part B An alkyne undergoes hydrogenation to produce an alkene as follows: Pd RC CR H2alkene catalyst Predict the product and draw it. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. To add an R group, select any atom while the Rectangle Selection tool is active and type R.
The reaction of 1-butene (C4H8) with bromine (Br2) undergoes an addition reaction. The double bond in 1-butene is broken, and bromine adds to the carbon atoms, resulting in the formation of 2,3-dibromobutane.
The IUPAC name of the product, 2,3-dibromobutane, is 1,4-dibromo-2-butene.
The reaction can be represented as follows:
CH3CH2CH=CH2 + Br2 → CH3CH2CH(Br)CH2Br
In this reaction, the bromine atoms add to the two carbon atoms that were previously part of the double bond in 1-butene. The product is a saturated compound with two bromine atoms attached to the carbon atoms.
As for the hydrogenation of an alkyne, the reaction converts the triple bond into a double bond by adding hydrogen (H2) in the presence of a catalyst such as palladium (Pd). The resulting product is an alkene.
For example, if we consider the alkyne ethyne (C2H2) undergoing hydrogenation, the product is ethene (C2H4). The reaction can be represented as follows:
CH≡CH + H2 → CH2=CH2
In conclusion, the reaction of 1-butene with bromine yields 2,3-dibromobutane, and the hydrogenation of an alkyne using a palladium catalyst produces the corresponding alkene.
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