Increasing strain rate tends to have which one of the following effects on flow stress during hot forming of metal? (a) decreases flow stress, (b) has no effect, or (c) increases flow stress.

Answer:

I think it is D.service manual

Explanation:

Because it is the vehicle identification

Answer:

1) The power developed by the engine is 14705.7739 kW

2) The thermal efficiency is approximately 61.5%

Explanation:

The given parameters are;

P₁ = 95 kPa

T₁ = 22°C

V₁ = 3.17 liters

The cutoff ratio = 2.5

Displacement volume = 3 liters

The number of times the cycle is executed per minute = 1000 times per minute

We have;

The displacement volume = V₁ - V₂ = 3 l

V₁ = 3.17 l

V₂ = 3 - 3.17 = 0.17 l

Compression ratio = V₁/V₂ = 3.17/0.17 ≈ 18.65

P₂/P₁ = P₂/(95 kPa) =  (V₁/V₂)^(k) = 18.65^1.4

P₂ = (95×18.65^(1.4)) ≈ 5710.5 kPa

T₂/T₁ = (V₁/V₂)^(k - 1)

T₂/(295 K)= (18.65)^(1.4 - 1)

T₂ = 295 * (18.65)^(1.4 - 1) = 950.81 K

The cutoff ratio = V₃/V₂ = 2.5

T₃ = T₂ × V₃/V₂  = 2.5 * 950.81 K = 2377.025 K

\(Q_{in}\) = \(C_p\)×(T₃ - T₂) = 1.006 × (2377.025 - 950.81) = 1,434.77 kJ/kg

T₄ = T₃ × (V₃/V₄)^(k-1) =

Therefore,

\(T_4 = T_3 \times \left (\dfrac{r_c}{r} \right )^{k - 1} = 2377.025 \times \left( \dfrac{2.5}{18.65} \right )^{1.4 - 1} \approx 1064 \ K\)

T₄ ≈ 1064 K

\(Q_{out}\) = \(-C_v \times (T_4 - T_1)\)

\(C_v = C_p/k = 1.006/1.4 \approx 0.7186 \ kJ/kg\)

∴ \(Q_{out}\) = 0.7186×(1064 - 295) = 552.6034 kJ/kg

1) The net work = \(Q_{in}\) - \(Q_{out}\) = 1,434.77 kJ/kg - 552.6034 kJ/kg ≈ 882.17 kJ/kg

The number of cycle per minute = 1000 rpm

The number of cycle per minute = 1000 rpm/60 = 16.67 cycles per second

The power developed by the engine = The number of cycles per second × The net work of the engine

Therefore;

The power developed by the engine = 16.67 cycles/second  × 882.17 kJ/kg

The power developed by the engine = 14705.7739 kW

2) Efficiency, \(\eta _{th}\), is given as follows;

\(\eta _{th} = \dfrac{Q_{in}-Q_{out}}{Q_{in}} \times 100 = 1 - \dfrac{Q_{out}}{Q_{in}} \times 100= 1 - \dfrac{552.6034}{1434.77}\times 100 \approx 61.5\%\)

Therefore, the thermal efficiency ≈ 61.5%.

Answer:

volunteer coordinator

Explanation:

because they are volunteering for that and in most of the cases they do not expect to be paid

The height of point P can be determined using trigonometry and the geometric relationship between the crankshaft, connecting rod, and point P, allowing us to express it as a function of the angle u.

In a car engine, the pistons move up and down to rotate the crankshaft, which converts linear motion into rotational motion. To find the height of point P above the center O of the crankshaft in terms of the angle u, we need to consider the geometry of the engine mechanism.

Assuming a simple crank-slider mechanism, where the crankshaft is represented by a rotating rod and the piston is attached to a connecting rod, the height of point P can be determined using trigonometry. As the crankshaft rotates, the connecting rod swings back and forth, causing the piston to move up and down.

By observing the right triangle formed by the crankshaft, connecting rod, and the line connecting point P to the center O, we can express the height of point P as a function of the angle u. The trigonometric relationship between the angle u, the length of the connecting rod, and the height of point P can be established using sine or cosine functions.

By analyzing this relationship, we can derive a mathematical expression that relates the angle u to the height of point P. This expression allows us to determine the height of point P at any given angle u during the engine's operation.

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Answer:false

Explanation:

Bc

To replace the missing code in the code segment the correct choice is option B.

In the given code, you need to find the greatest number of pages in any Book object in the array bookArr. To do this, you can use the enhanced for loop as given, and then use the getPages() method to access the private variable pages.

The correct missing code should be:

```
if (b.getPages() > maxPages) {
   maxPages = b.getPages();
}
```

This code compares the current book's pages (using b.getPages()) with maxPages, and if the current book has more pages, it updates maxPages with the new value. This way, at the end of the loop, maxPages will hold the greatest number of pages found in any Book object in the array. Option B is the correct choice to replace the missing code in the code segment.

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Answer:

A.) 1mv = 2000N

B.) Impulse = 60Ns

C.) Acceleration = 66.67 m/s^2

Velocity = 4 m/s

Displacement = 0.075 metre

Absorbed energy = 60 J

Explanation:

A.) Using a mathematical linear equation,

Y = MX + C

Where M = (2000 - 0)/( 898 - 0 )

M = 2000/898

M = 2.23

Let Y = 2000 and X = 898

2000 = 2.23(898) + C

2000 = 2000 + C

C = 0

We can therefore conclude that

1 mV = 2000N

B.) Impulse is the product of force and time.

Also, impulse = momentum

Given that

Mass M = 30kg

Velocity V = 2 m/s

Impulse = M × V = momentum

Impulse = 30 × 2 = 60 Ns

C.) Force = mass × acceleration

F = ma

Substitute force and mass into the formula

2000 = 30a

Make a the subject of formula

a = 2000/30

acceleration a = 66.67 m/s^2

Since impulse = 60 Ns

From Newton 2nd law,

Force = rate of change in momentum

Where

change in momentum = -MV - (- MU)

Impulse = -MV + MU

Where U = initial velocity

60 = -60 + MU

30U = 120

U = 120/30

U = 4 m/s

Force = 2000N

Impulse = Ft

Substitute force and impulse to get time

60 = 2000t

t = 60/2000

t = 0.03 second

Using third equation of motion

V^2 = U^2 + 2as

Where S = displacement

4^2 = 2^2 + 2 × 66.67S

16 = 4 + 133.4S

133.4S = 10

S = 10/133.4

S = 0.075 metre

D.) Energy = 1/2 mV^2

Energy = 0.5 × 30 × 2^2

Energy = 15 × 4 = 60J

Answer:

She chose Peeta to protect her family and friends.

Explanation:

If she chose Gale, her family would've been killed by President Snow. So, she chose Peeta so her mom and sister weren't killed.

Answer:

Because he's obviously the better choice :)

Explanation:

President Snow was mad that both Peeta and Katniss won the Games so they had to act in love to protect their loved ones from Snow. And also, Gale's trash ;)

Answer:

  c.  25 μA

Explanation:

The dependent current source means that 31 times i1 will flow through the 6kΩ resistor, effectively increasing its voltage drop to 31 times that which would result from i1 alone. In effect, the 6kΩ resistor behaves in the left-side circuit loop as though it were 31×6kΩ = 186kΩ (with no dependent current source).

Then the current i1 is equivalent to that created by a 5+1 = 6V source through a 54kΩ +186kΩ = 240kΩ circuit impedance.

  (6V)/(240kΩ) = 25 μA

_____

Additional comment

The voltage across the 6kΩ resistor is (186/240)·6V = 4.65V, and the 25 μA current generates a voltage of 30·(25 μA)(1.8kΩ) = 1.35V across the 1.8kΩ resistor. This means the voltage source at the right side of the diagram needs to be at least 4.65 +1.35 = 6.0V in order to support the calculated voltage drops.

The charge divided by the time gives the current in the element. Power divided by current equals voltage. Power compounded by time equals energy.

By dividing the charge by the time interval, the current in the element may be determined using the calculation for the charge entering the positive terminal. By dividing the power given to the element by the current flowing through it, the voltage across the element can be computed. By multiplying the power given to the element by the time interval, one can compute the energy delivered to it during the time interval of 0 t 100 ms. The quantity of energy used by the element over a specific time period can be calculated with the use of this computation. It is crucial to remember that as the charge entering the positive terminal may not stay constant, the power and current in the element may change over time.

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Answer:

OBJECTLINE

HIDDEN LINE

SECTION LINE

CENTER LINE

Explanation:

Explanation:

A business man who really focus on victory achieved through a right procedure will focus on long-term planning.

Let us understand what a short-term and long-term planning is.

Short-term will plan only for two-three years. But a long-term plan will look for future five years income projection, plan of expansion, bigger goals, etc.

A business man is the person who take risks and achieve more. A victory can be achieved in many ways one is taking bigger risks, next is focusing on long-term plans

If this is wrong, give me the answer choices so I know what's right or wrong. I'll edit the question if given to me.

Answer:

A motor burnout is formed when a hermetic motor burns while in use.

a. True. Because these activities require very little processing power. A basic processor such as an Intel Celeron or AMD Athlon will be more than sufficient for most web browsing and email-checking tasks.

A processor is a part of a computer that carries out operations and carries out instructions. It is in charge of carrying out the calculations and data manipulation necessary for a computer to work. It is the most crucial part of a computer system and is frequently referred to as the "brain" of the computer.

The processor contains an Arithmetic Logic Unit (ALU) which is responsible for carrying out arithmetic and logical operations. It also contains a Control Unit (CU) which is responsible for managing the flow of instructions and data to and from the various components of the computer.

The processor also contains a number of registers which are used to store intermediate results during calculations. The processor also contains several cache levels, which are used to store frequently accessed data and instructions in order to speed up the execution of programs.

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The reason that many organizations use the hybrid and multi-Cloud approach is option D: It allows businesses to share control of their data with other businesses.

Improved data management efficiency across all resources that operate across multiple platforms and will be managed via cloud orchestration, reducing the overhead of switching from one infrastructure to another to pursue data or resources, is one of the main reasons for adopting a hybrid multi-cloud strategy.

Therefore, in the context of the above question, it is used because, Organizations may orchestrate processes across various applications, coordinate workloads amongst networked computing environments, and exert more control and governance over resources thanks to this.

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If the oil light on your dashboard illuminates, the best thing to do is to immediately stop the engine and check the oil level.

When the oil light on the dashboard comes on, it typically indicates low oil pressure. Low oil pressure can be caused by a variety of issues, such as low oil level, a faulty oil pump, or an oil leak. Ignoring the oil light and continuing to drive can lead to severe engine damage due to inadequate lubrication. Therefore, it is crucial to stop the engine as soon as possible to prevent further harm. After stopping, check the oil level using the dipstick and add oil if necessary. If the oil level is sufficient, it is advisable to seek professional assistance to diagnose and resolve the underlying issue.

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Answer:

The correct answer will be "18 degrees AOB".

Explanation:

The given value is:

KTAS = 120

For determining bank angles through standard rate switches, as we understand

⇒  \(10 \ percent \ of KTAS +\frac{1}{2} \ of \ the \ number\)

On substituting the given value of KTAS, we get

⇒  \(10 \ percent \ of 120+\frac{1}{2} \ of \ the \ number\)

⇒  \(12+6\)

⇒  \(18 \ degree \ angle \ of \ bank\)

Answer:

Explanation:

From the given information:

The square foundation = 3m by 3m

capacity q = 165 kPa

depth = 1.5 m

assuming soil unit weight = 17.5 kN

q = 17.5 × 1.5

q = 26.25 kPa

Settlement \(Se = C_1C_2 (\overline q - q) (\dfrac{I_z}{E_s})D_f\)

where;

\(c_1 = 1-0.5 (\dfrac{q}{\overline q -q})\)

\(c_1 = 0.905\)

\(c_2 = 1+ 0.2 log ( \dfrac{t}{0.1})\)

suppose t = 1year

\(c_2 = 1+ 0.2 log ( \dfrac{1}{0.1})\)

\(c_2 = 1.2\)

Using Schertmann method.

\(\mathtt{ I_t = 0.5 }\)

\(\dfrac{length }{breadth } = \dfrac{3}{3}=1\)

∴

E⁵ = \(2.5 q_e\)

E⁵ = 2.5 × 165

E⁵ = 412.5 kPa

Hence: \(Se = C_1C_2 (\overline q - q) (\dfrac{I_z}{E_s})D_f\)

\(Se = 0.905 * 1.2(165-26.25) (\dfrac{0.5}{412.5})*1.5\)

\(\mathbf{Se = 0.273 \ m}\)

The actual dimensions for the given nominal dimensions 1x2 stick of lumber, a 2x4 stick of lumber are;

Actual dimension of 1 x 2 stick of lumber = ³/₄'' × 3¹/₂''

Actual dimension of 2 x 4 stick of lumber = 1¹/₂'' × 3¹/₂''

The nominal dimension for a sheet of plywood is; 4' x 8'

Lumber sticks are sticks made from timber in forms used mainly in building construction as formwork support for the sheets of plywood used.

There could also be other uses of lumber sticks like making of some basic home furniture's but they are primarily used in building construction.

Now, Lumber sticks could come in different nominal dimensions such as;

Now, in the question, we are dealing with 1x2 stick of lumber and a 2x4 stick of lumber. From general cutting standards in most workshops, the actual sizes are respectively;

Actual size of 1 x 2 stick of lumber = ³/₄'' × 3¹/₂''

Actual size of 2 x 4 stick of lumber = 1¹/₂'' × 3¹/₂''

Now, for a sheet of plywood, the standard size of a sheet of plywood is 4' × 8'.

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1) the source voltage Vs referred to the low voltage side is Vs = 480 V

2) the transmission line current iTL is 26.67 - j20 A

3) the load current il is  0.00833 + j0.00625 A

4) the voltage drop across the transmission line Vdrop is 4.8006 + j5.3248 V

5) the load voltage VL is 48 V

To solve the given problem, we'll use the given information and apply relevant formulas. Let's go through each step:

1) Finding the source voltage Vs referred to the low voltage side:

We know that the turns ratio of the transformer is 10:1. Therefore, the voltage transformation ratio is also 10:1. So, we can write:

Vs/V2 = Ns/N2 = 10

Vs/4800 = 10

Vs = 4800/10

Vs = 480 V

2) Finding the transmission line current iTL:

The transmission line current can be calculated using Ohm's Law:

iTL = V2 / Zline

iTL = 4800 / (0.18 + j0.24)

iTL = (4800 / 0.18) - j(4800 / 0.24)

iTL = 26.67 - j20

3) Finding the load current il:

To find the load current, we can use the apparent power formula:

S = V * I*

Where S is the complex power, V is the voltage, and I* is the conjugate of the current.

Given that the apparent power S is 4 + j3 VA, and the voltage V is 480 V, we can solve for the load current il:

4 + j3 = 480 * il*

il = (4 + j3) / 480

il = (4/480) + (j3/480)

il = 0.00833 + j0.00625

4) Finding the voltage drop across the transmission line:

The voltage drop across the transmission line can be calculated using Ohm's Law:

Vdrop = iTL * Zline

Vdrop = (26.67 - j20) * (0.18 + j0.24)

Vdrop = (26.67 * 0.18) + j(26.67 * 0.24) - j(20 * 0.18) - 0.24 * 20

Vdrop = 4.8006 + j5.3248

5) Finding the load voltage VL:

The load voltage can be calculated using the voltage transformation ratio:

VL/Vs = N2/N1 = 1/10

VL/480 = 1/10

VL = 480/10

VL = 48 V

So, the answers to the given questions are as follows:

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Answer:

PLASTICITY CHARACTERISTICS OF SOILS

The plasticity of a soil is its ability to undergo deformation without cracking. It is an

important index property of fine grained soil, especially for clayey soils. The adsorbed

water in clayey soils is leads to the plasticity of soil. Adsorbed water in the clay

particles allow the particles to slip over one another. The particles do not return to its

original position following the deformation of soil. The soil becomes plastic only when it

has clay minerals.

ATTERBERG LIMITS

1n 1911, A Swedish agriculture engineer Atterberg mentioned that a fine grained soil

can exist in four states, namely, liquid, plastic, semi-solid or solid. The water content at

which the soil changes from one state to other are known as Atterberg limits or

Consistency limits.

It is very important properties of fine grained soils.

There are three atterberg limits:

Liquid limit: The water content at which the soil changes from the liquid state to

plastic state is known as liquid limit. In other words, the liquid limit is the water

content at which the soil ceases to be liquid.

Plastic Limit: The water content at which the soil becomes semi-solid is known as

plastic limit.

Shrinkage Limit: The water content at which the soil changes from semi-solid to solid

state is known as the shrinkage limit.

DETERMINATION OF SHRINKAGE LIMIT

Shrinkage limit is the smallest water content at which the soil is saturated. It is also

define as the maximum water content at which a reduction of water content will not

cause a decrease in the volume of the soil mass

Weight of water in stage (I), = −

Loss of weight of water from stage (I) to stage (II), = 1 − 2

Weight of water in stage (II), = 1 − − 1 − 2

From definition, shrinkage limit = water content in stage (II),

= 1 − − 1 − 2

= 1 − 1 − 2

Where, 1 is the water content in stage

Consider an area-source box model for air pollution above a peninsula of land. The length of the box is 15 km, its width is 80 km, and a radiation inversion restricts mixing to 15 m. Wind is blowing clean air into the long dimension of the box at 0.5 m/s. On average, there are 250,000 vehicles on the road, each being driven 40 km in 2 hours and each emitting 4 g/km of CO.

Required:

a. Estimate the steady-state concentration of CO in the air. Should the city be designated as "nonattainment" (i.e., steady-state concentration is over the NAAQS standard)?

b. Find the average rate of CO emissions during this two-hour period.

c. If the windspeed is zero, use the formula to derive relationship between CO and time and use it to find the CO over the peninsula at 6pmConsider an area-source box model for air pollution above a peninsula of land. The length of the box is 15 km, its width is 80 km, and a radiation inversion restricts mixing to 15 m. Wind is blowing clean air into the long dimension of the box at 0.5 m/s. On average, there are 250,000 vehicles on the road, each being driven 40 km in 2 hours and each emitting 4 g/km of CO.

Required:

a. Estimate the steady-state concentration of CO in the air. Should the city be designated as "nonattainment" (i.e., steady-state concentration is over the NAAQS standard)?

b. Find the average rate of CO emissions during this two-hour period.

c. If the windspeed is zero, use the formula to derive relationship between CO and time and use it to find the CO over the peninsula at 6pmConsider an area-source box model for air pollution above a peninsula of land. The length of the box is 15 km, its width is 80 km, and a radiation inversion restricts mixing to 15 m. Wind is blowing clean air into the long dimension of the box at 0.5 m/s. On average, there are 250,000 vehicles on the road, each being driven 40 km in 2 hours and each emitting 4 g/km of CO.

Required:

a. Estimate the steady-state concentration of CO in the air. Should the city be designated as "nonattainment" (i.e., steady-state concentration is over the NAAQS standard)?

b. Find the average rate of CO emissions during this two-hour period.

c. If the windspeed is zero, use the formula to derive relationship between CO and time and use it to find the CO over the peninsula at 6pm

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follow me.............,...

Answer:

I think the answer is d: underground tunnel

Explanation:

Hope this helps

The Robertson screwdriver has the largest tip size among screwdrivers because of its design.

The tip of a Robertson screwdriver has a square-shaped socket that fits perfectly with the corresponding square recess on the head of a Robertson screw. This design provides a secure and tight fit between the screw and the screwdriver, which prevents slippage and stripping of the screw head.

The square-shaped socket of the Robertson screwdriver also allows for greater torque transfer, meaning that the screwdriver can apply greater force to turn the screw, which is useful when working with larger or more stubborn screws.

In general, the size of a screwdriver tip is determined by the size of the screw head it is designed to fit. The Robertson screw was designed with a larger head to provide a stronger and more secure connection, and as a result, the corresponding Robertson screwdriver also has a larger tip size to match.

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Conductors in Parallel is covered in 310.10(H). Often when working with higher ampacities, we find it to be cumbersome and expensive to keep increasing the size of the wire and conduit. The solution is often to use multiple runs that are connected to a common location on each end. Notice in the 2011 edition of the code that much of this section is highlighted gray, indicating new or revised text. The change here was that the previous code stated that you were permitted to parallel conductors 1/0 AWG and larger; however, it didn’t specifically prohibit you from paralleling smaller conductors, which was the intent and the way it was enforced in all my years of enforcement. However, that’s not what the actual language said, and ambiguous language cancause enforcement issues; therefore, in the 2011 code it was made clear that you are only allowed to parallel conductors 1/0 AWG and larger.

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Sure! Here's an example MATLAB program that solves a system of linear equations using Cramer's Rule for a 3x4 matrix:

```matlab

% Input the coefficient matrix

A = input('Enter the coefficient matrix A (3x3): ');

% Input the constant matrix

B = input('Enter the constant matrix B (3x1): ');

% Calculate the determinant of the coefficient matrix

det_A = det(A);

% Initialize the solution vector

X = zeros(3, 1);

% Apply Cramer's Rule

for i = 1:3

   % Create a temporary matrix by replacing the i-th column with the constant matrix

   temp_A = A;

   temp_A(:, i) = B;

   % Calculate the determinant of the temporary matrix

   det_temp_A = det(temp_A);

   % Calculate the solution for the i-th variable

   X(i) = det_temp_A / det_A;

end

% Display the solution

disp('The solution for the system of linear equations:');

disp(X);

```

In this program, the user is prompted to enter the coefficient matrix `A` (3x3) and the constant matrix `B` (3x1). The determinant of matrix `A` is calculated using the `det` function in MATLAB. The program then uses a loop to apply Cramer's Rule by replacing each column of `A` with `B` and calculating the determinants of the resulting matrices. Finally, the solution vector `X` is displayed, representing the values of the variables in the system of linear equations.

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