Initial velocity= 32 m/s Final Velocity=23 m/s Time=? Distance=110 m
Acceleration=?*
O Time = 4 meters per second
O Acceleration = 2.25 meters per second squared
O Time = 2 seconds
O Acceleration = -2.25 meters per second squared

Answers

Answer 1

Explanation:

Acceleration = -2.25 meters per and time taken is 4meter second...


Related Questions

A light bulb consumes 1800 watt-hours per day. How long does it take to consume 8100 watt-hours? days
hours X 5

Answers

It 4.5 hours for the light bulb to consume 8100 watt-hours of power.

The energy consumed by the light blub = 8100 watt-hours.

Let the time taken be t hours.

We know that;

Energy = power × time

Energy (E) =  8100 watt-hours

Power (P) = 1800 watt

Time (t) =?

8100 =  1800 × t

= 8100 / 1800

= 4.5 hours

The time taken by the light bulb is 4.5 hours.

Therefore, it could take 4.5 hours for the light bulb to consume 8100 watt-hours.

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A 48 cm long metal rod is oriented horizontally in a uniform magnetic field with magnetic flux density of 340 g. The magnetic field is directed vertically down into the ground. The metal rod is moved with a speed of 13 m/s in a horizontal direction perpendicular to the length of the rod. Neglect the magnetic field of earth at the location of this apparatus. Determine the potential difference induced in the rod. Calculate the answer in the units of v. Write your answer in decimal form with three digits to the right of the decimal point (e. G. 5. 374); do not write any units

Answers

The potential difference induced in the rod is approximately -6.912 v. In general, the potential energy of an object is equal to the work done to move the object to its current position, against the forces acting on it.

Potential energy is a form of energy that an object possesses due to its position in a gravitational field or due to its configuration. It is the energy that an object has due to its position in a system, rather than its motion.

The potential difference induced in the rod is given by Faraday's law of electromagnetic induction:

ΔV = -(BLv)

where B is the magnetic flux density, L is the length of the rod, and v is the speed at which the rod moves through the magnetic field.

Plugging in the given values, we have:

ΔV = -(340 g * 48 cm * 13 m/s)

Converting the length to meters and the magnetic flux density to teslas, we have:

ΔV = -(0.34 T * 0.48 m * 13 m/s)

= -6.912 v

So the potential difference induced in the rod is approximately -6.912 v.

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Johnny Hotfoot slams on the brakes of his car mov- ing at 60 mph (26.7 m/s) and skids to a stop in 4 s. (a) What is the deceleration of the car? (b) How far does it skid?

Answers

At 60 mph (26.7 m/s), Johnny Hotfoot slams on the brakes of his car and skids to a stop in 4 s. (A) How fast is the car slowing down? (b) The extent of the skid.

If the car had been traveling at 40.0 m/s, it would have slid 27.2 m.

The frictional force opposes the linear force pulling on the automobile. Consequently, m is the vehicle's mass, an is its acceleration, and c is its coefficient of friction.

The normal force is R.

given the aforementioned variables

Find the length of the skid if the vehicle had been traveling at 40.0 m/s.

The car would have skidded 27.2 meters if it had been driving at 40.0 meters per second.

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How many moles are there in
200.00 g Na?

Answers

3.32107808 × 10^-22 moles

Molecular mass of Na=23g/mole
No. of mole= molar mass
​In 200g of Na
n= 23g/mole

That’s leaves this being ur answer I think
n=8.69molesofNa

I’m sorry if it doesn’t really make sense, I’m not very good at explaining things

Any planet that you have NOT crossed out above should have a Magnetic Field. Circle any planet above that yoa have NOT crossed out. Do the data in Table 7.3 support your choice(s)? lio 1 No (circle one) TUTORIAL REVIEW QUESTIONS 1. What is (are) the main factor(s) that affect(s) the amount and duration of geological activity on a terrestrial planet? 2. What is (are) the main factor(s) that affect(s) atmospheric conditions on a terrestrial planet? 3. The moons of the giant Jovian planets are small rocky-metal bodies that are, at the largest, about the size of Mercury (but most are smaller). Based on this and what you have learned about the factors that affect geologic activity and atmospheres on similar objects (Terrestrial planets), what geologic and atmospheric conditions would you expect to find on the surface of a typical Jovian moon?

Answers

The main factor that affects the amount and duration of geological activity on a terrestrial planet is its internal heat. This heat is generated through various processes such as radioactive decay and residual heat from planetary formation.

The presence of a molten core and active mantle circulation contributes to geological activity, including tectonic plate movements, volcanic eruptions, and mountain building. Other factors like the planet's size, composition, and distance from the Sun can also influence geological activity to some extent.

The main factors that affect atmospheric conditions on a terrestrial planet are its distance from the Sun, the composition of its atmosphere, and the presence of greenhouse gases. The proximity to the Sun determines the amount of solar energy received, which affects temperature and weather patterns. The composition of the atmosphere, including the presence of gases like oxygen, nitrogen, carbon dioxide, and water vapor, determines the planet's climate and the ability to support life. Greenhouse gases trap heat in the atmosphere, contributing to the greenhouse effect and influencing temperature regulation.

Based on what we know about the factors that affect geologic activity and atmospheres on terrestrial planets, we can expect that typical Jovian moons, being small rocky-metal bodies, would have limited geological activity and thin atmospheres, if any. The smaller size of these moons compared to terrestrial planets means that they have a lower heat-producing capability and less internal energy. Additionally, their lower gravitational forces make it challenging to retain substantial atmospheres. While some Jovian moons may have evidence of geological activity, such as cryovolcanism or tidal heating, they generally exhibit less dynamic geologic and atmospheric conditions compared to larger terrestrial planets.

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The histogram shows some information about the weights of a sample of apples. work out the proportion of apples in the sample with a weight between 140 grams and 200 grams. input note: give your answer as a fraction.

Answers

To find the proportion of apples in the sample with a weight between 140 grams and 200 grams, we need to calculate the area under the histogram between these two weights.

Since the histogram represents a frequency distribution, the area under the histogram represents the proportion or percentage. To calculate the proportion, we need to find the area of the rectangle that represents the weights between 140 grams and 200 grams. The width of the rectangle is 200 - 140 = 60 grams, and the height of the rectangle is the frequency of apples within this weight range.

Let's assume the frequency is represented by 'f'. Therefore, the area of the rectangle is 60 * f square grams. To get the proportion, we need to divide this area by the total area under the histogram. Let's assume the total area is represented by 'T'. So, the proportion of apples in the sample with a weight between 140 grams and 200 grams is (60 * f) / T. Note that without specific values for the frequency and total area, we cannot provide a specific fraction as an answer.

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based on your answer,what idea comes in to your mind?​

Answers

Answer:

Homework · Free food · Loosing and robbing pencil · Forgetting book at home · Waiting for a Play time · My first bit · Lunch sharing · Assembly lines- standing in last just ...

Explanation:

describe relative motion with an examples​

Answers

Answer:

The measurement of an object's motion with respect to any other object that is moving or stationary is called Relative Motion.

which of the following will most likely happen if you apply unbalanced forces to an object?

Answers

Answer:

The object will likely start moving with a nonzero acceleration.

How much energy is stored in the combination if the charge on the combination is 4.0 x 10-4 C and the capacitors are connected in series? In parallel? Enter your answers in joules separated by a comma.

Answers

The energy stored in the combination of capacitors when they are connected in series is 0.0719 joules or 71.9 mJ.

To calculate the energy stored in the combination of capacitors when they are connected in series, we need to first calculate the equivalent capacitance of the combination using the formula:

1/Ceq = 1/C₁ + 1/C₂

Substituting the given values, we get:

1/Ceq = 1/1.50 uF + 1/4.00 uF

Ceq = 1.071 uF

Next, we need to calculate the voltage across each capacitor using the formula:

Q = Ceq × V

where Q is the charge on the combination of capacitors, and V is the voltage across the combination.

Substituting the given values, we get:

V = Q / Ceq = (4.0 x 10⁻⁴ C) / (1.071 uF) = 373.3 V

Now, we can calculate the energy stored in the combination using the formula:

U = 0.5 × Ceq * V²

Substituting the calculated values, we get:

U = 0.5 × (1.071 uF) × (373.3 V)² = 71.9 mJ

Question - You Connect Two Capacitors, C₁ = 1.50 UF And C₂ = 4.00 UF. How much energy is stored in the combination if the charge on the combination is 4.0 x 10⁻⁴ C and the capacitors are connected in series?

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a 5.00-m-long ladder, weighing 200 n, rests against a smooth vertical wall with its base on a horizontal rough floor, a distance of 1.20 m away from the wall. the center of mass of the ladder is 2.50 m from its base, and the coefficient of static friction between the ladder and the floor is 0.200. how far up the ladder, measured along the ladder, can a 600-n person climb before the ladder begins to slip?

Answers

Answer: 0.488  m

Explanation: I have my ways ;>

Describe JJ Thomson's experiment of the atom in a way where anyone can understand.

Answers

Answer: In this experiment, he showed/proved that all atoms contain negatively charged electrons, which are smaller than protons and neutrons(protons: positively charged; neutrons: Neither positive nor negative charge), and live on the outside of the Nucleus in a cell. Electrons always have a negative charge, and are also classified as subatomic particles. This helped with multiple experiments of JJ Thomson's. He discovered the electron by experimenting with Crooks, or cathode ray, tube.

Explanation:

PLS ANSWER FAST
California sea lions communicate underwater at frequencies ranging from 500 to 4,000 hertz. The speed of sound in sea water is approximately 1,500 m/s. What are the approximate wavelengths of sound
with which the California sea lions communicate? (1 point)
O 750,000 to 6,000,000 meters
O2,000 to 5,500 meters
O 0.33 to 2.66 meters
O 0.375 to 3 meters

Answers

The California sea lions communicate  is  option C: 0.375 to 3 meters.

To calculate the approximate wavelengths of sound with which the California sea lions communicate, we can use the formula:

Wavelength = Speed of Sound / Frequency

Given:

Speed of Sound in Sea Water = 1,500 m/s

Frequency Range = 500 Hz to 4,000 Hz

For the lower frequency of 500 Hz:

Wavelength = 1,500 m/s / 500 Hz = 3 meters

For the higher frequency of 4,000 Hz:

Wavelength = 1,500 m/s / 4,000 Hz = 0.375 meters

Therefore, the approximate wavelengths of sound with which the California sea lions communicate are approximately 0.375 to 3 meters.

So, the correct answer is option C: 0.375 to 3 meters.

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what was the important discovery that physicists michael faraday and joseph henry made at about the same time

Answers

Physicists Michael Faraday and Joseph Henry made important discoveries in the field of electromagnetism at about the same time during the early 19th century.

They both independently discovered electromagnetic induction, which is the principle behind the operation of electric generators and transformers.

Electromagnetic induction refers to the process of generating an electric current in a conductor by varying the magnetic field around it.

Faraday and Henry separately demonstrated that a changing magnetic field induces an electric current in a nearby conductor.

Faraday's experiments and discoveries in the 1830s laid the foundation for the concept of electromagnetic induction.

He demonstrated that by moving a magnet in and out of a coil of wire, he could generate an electric current in the wire. Faraday's work also led to the development of the first electric generator.

Around the same time, Joseph Henry, an American physicist, independently discovered electromagnetic induction and made similar observations.

He demonstrated that passing an electric current through a coil of wire produced a magnetic field and that stopping or varying the current induced an electric current in a neighboring coil.

Both Faraday and Henry's discoveries were crucial in establishing the relationship between electricity and magnetism and laid the groundwork for the development of electrical technology and power generation.

Their work formed the basis of modern electromagnetism and had significant implications for the advancement of physics and engineering.

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4 Mine cart Collision Two mine carts begin motionless on opposite hills of heights hị and h2 above a level valley between them. The carts begin rolling frictionlessly down the hills and collide at the bottom and couple together. mi m2 = ? hi h2 If mine cart 1 has mass mi, what must the mass of cart 2 be so that the two carts are stopped by the collision? Answer in terms of mi, hi, and h2.

Answers

To stop two mine carts, starting from rest on opposite hills of heights h₁ and h₂, and colliding at the bottom, the mass of cart 2 (m₂) must be equal to the mass of cart 1 (m₁). This means m₂ = m₁.

In this scenario, we can consider the conservation of mechanical energy to determine the relationship between the masses of the two carts. The total mechanical energy at the top of each hill is given by the sum of potential energy and kinetic energy.

For cart 1 at height h₁, the total mechanical energy is E₁ = m₁gh₁, where g is the acceleration due to gravity.

For cart 2 at height h₂, the total mechanical energy is E₂ = m₂gh₂.

When the two carts collide at the bottom, they couple together, and their combined mass becomes (m₁ + m₂). The total mechanical energy at the bottom is then E = (m₁ + m₂)gh.

Since the carts come to a stop after the collision, their total mechanical energy at the bottom is zero. Therefore, we can equate the initial energy at the top of the hills to zero: E₁ + E₂ = 0.

Substituting the expressions for E₁ and E₂, we get m₁gh₁ + m₂gh₂ = 0.

Since h₁ and h₂ are positive values, in order for the equation to hold, m₁ and m₂ must have opposite signs. However, since mass cannot be negative, the only solution is if m₂ = -m₁. In other words, the mass of cart 2 (m₂) must be equal to the mass of cart 1 (m₁) in order for the two carts to stop after colliding.

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If a hot air balloon is seen rising above the top of a hill, what is the top of the hill called? Question 2 options: delta point distance system coordinate system reference point.

Answers

If a hot air balloon has shown rising above the top of a hill, the top of the hill is considered as a reference point.

Reference Point:

It is a point that is used to standardize a experiment. The reference point is a constant point.

In the given problem:

The hot air balloon is rising above the top of the hill. Here, the hill is a standard point that has a fixed (constant) height.Some other reference points are the top of the Eifel Tower or a famous shop which a person use to denote a certain distance.

Therefore, "If a hot air balloon has shown rising above the top of a hill" the top of the hill is considered as a reference point.

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Answer:

the answer is reference point

the partial pressures of gases in cells of systemic tissues result from

Answers

The partial pressures of gases in cells of systemic tissues result from the process of gas exchange and cellular respiration.

The partial pressures of gases in cells of systemic tissues result from the process of gas exchange and cellular respiration.

During cellular respiration, cells metabolize glucose and produce carbon dioxide (CO2) as a waste product. At the same time, oxygen (O2) is required for cellular respiration to occur.

The partial pressure of a gas refers to the pressure exerted by that gas in a mixture. In systemic tissues, oxygen diffuses from the bloodstream into the cells, where it is consumed in cellular respiration. As a result, the partial pressure of oxygen decreases in the cells.

Conversely, carbon dioxide produced by cellular respiration diffuses out of the cells into the bloodstream, leading to an increase in the partial pressure of carbon dioxide in the cells.

The partial pressures of gases in cells of systemic tissues are determined by the balance between gas diffusion and the metabolic activities of the cells. This allows for efficient gas exchange and the supply of oxygen for cellular respiration while removing carbon dioxide waste from the cells.

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What is the weight of a 2. 00-kilogram object on the surface of earth?.

Answers

Solution:

Mass of the object on the surface of the earth = 2 KgAcceleration due to gravity on earth = 9.8 m/s²We know, weight of a body = mass of the body on earth × acceleration due to gravity on earthTherefore, weight of the object= 2 Kg × 9.8 m/s²= 19.6 N

Answer:

The weight of the 2 Kg object on the surface of the Earth is 19.6 N and this force acting vertically downwards.

Hope you could understand.

If you have any query, feel free to ask.

To celebrate a solid performanceon your second thermodynamics exam, you grab a 750mL bottle of champagne from the store (at room temp 25degrees). Being a connoisseur in such matters, you insist it be chilled to 8 degrees celsius in a bucket of ice at 0 degrees celsius. How much ice must melt before you pop the bubbly? (The subject is thermodynamics)

Answers

In order to chill a 750mL bottle of champagne using a bucket of ice at 0 degrees Celsius, approximately 249 grams of ice must melt. The specific heat capacity of ice is approximately 2.09 J/g°C.

To determine the amount of ice that needs to melt, we can use the principles of thermodynamics. First, we need to calculate the heat lost by the champagne and the heat gained by the melting ice. The heat lost by the champagne can be calculated using the equation Q = mcΔT, where Q is the heat lost, m is the mass of the champagne, c is the specific heat capacity of champagne, and ΔT is the change in temperature. Similarly, the heat gained by the ice can be calculated using the same equation, where m is the mass of the ice and c is the specific heat capacity of ice.

Given that the initial temperature of the champagne is 25 degrees Celsius and the final temperature is 8 degrees Celsius, ΔT for the champagne is 25 - 8 = 17 degrees Celsius. The specific heat capacity of champagne is approximately the same as water, which is 4.18 J/g°C. Therefore, the heat lost by the champagne is Q = (750g)(4.18 J/g°C)(17°C) = 53,595 J.

Since the ice is at 0 degrees Celsius, ΔT for the ice is 0 - (-8) = 8 degrees Celsius. The specific heat capacity of ice is approximately 2.09 J/g°C. Therefore, the heat gained by the ice is equal to the heat lost by the champagne, which is 53,595 J. Using the equation Q = mcΔT and solving for the mass of ice (m), we can rearrange the equation to m = Q / (cΔT). Plugging in the values, we get m = 53,595 J / (2.09 J/g°C * 8°C) ≈ 249 grams.

Therefore, approximately 249 grams of ice must melt in order to chill the champagne from 25 degrees Celsius to 8 degrees Celsius in a bucket of ice at 0 degrees Celsius.

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Which statement describes how electrical power is calculated? ​

Which statement describes how electrical power is calculated?

Answers

Answer:

D. Power is the product of voltage and current.

Explanation:

Electrical power is derived from the product of current and voltage;

  Power  = current x voltage  = I V

I is the current

V is the voltage

R is the resistance

Now;

   V = IR;

     So;

  Power  = I x (IR) = I²R

Also,

   Power  = \(\frac{V^{2} }{R}\)  

The right choice is D

1. A 500.0 g metal block absorbs 5.875 × 103 J of heat to raise its temperature by 50.0 K. What is the substance? Show your work.
Specific Heats of Selected Substances
Substance
C [J/(kg·K)]
Water (ice)
2,060
Iron
450
Aluminum
897
Gold
130
Copper
385
Silver
235
Ammonia (liquid)
4,700
Water (liquid)
4,180
Water (steam)
2,020
Lead
128

Answers

The name of the substance is silver based on the specific heat capacity value.

What is the specific heat capacity of the substance?

The specific heat capacity of the substance is calculated by applying the following formula for heat capacity.

Q = mcΔθ

where;

m is the mass of the substancec is the specific heat capacity of the substanceΔθ is the change in temperature

c = Q / mΔθ

The specific heat capacity of the substance is calculated as;

c = (5875 J ) / ( 500 g x 50 )

c = 0.235 J/kgK

The substance that has the same specific heat capacity calculated above is silver.

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The orbital radius of a star orbiting Sgr A* is
1.66×1012 kilometers. Observed from a distance of 9.25
kpc, what is its angular size in arcseconds?

Answers

The angular size of the star orbiting Sgr A* is 5.4 × 10⁻⁴ arcseconds.

The orbital radius of a star orbiting Sgr A* is 1.66 × 1012 kilometers, and it is observed from a distance of 9.25 kpc. We need to find its angular size in arcseconds.

The formula for calculating the angular size of an object is given as,θ = (d / D) × (180 / π) × 3600

Where,θ = angular size of object in arcseconds.

d = size of object in kilometers.

D = distance from the observer to the object in kilometers.

π = 22 / 7 or 3.14

As per the given information, size of object (d) = 1.66 × 10¹² kilometers.

Distance from the observer (D) = 9.25 kpc = 9.25 × 3.086 × 10¹³ km = 2.85 × 10²⁰ km.

Using the above formula and substituting the values

,θ = (1.66 × 10¹² / 2.85 × 10²⁰) × (180 / 3.14) × 3600

θ ≈ 5.4 × 10⁻⁴ arcseconds.

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A car of mass 1470 kg is on an icy driveway
inclined at an angle of 40◦. The acceleration of gravity is 9.8 m.
If the incline is frictionless, what is the acceleration of the car Answer in units of m/s

Answers

Answer:

  a = 7.5 m / s²

Explanation:

For this exercise let's use Newton's second law, let's create a coordinate system with the x axis parallel to the plane and the y axis perpendicular to the plane

Y axis

       N - W cos θ = 0

       N = mg cos θ

X axis

       W sin θ = m a

 

       mg sin θ = m a

        a = g sin θ

let's calculate

        a = 9.8 cos 40

        a = 7.5 m / s²

Your nephew rides a kiddy train at the local carnival. The train, which has a mass of , rounds a curve with a radius of . The rails can exert a maximum force of in the radial direction. What is the maximum speed of the train without derailing?

Answers

In this particular case, the kiddy train can travel at a maximum speed of 8 meters per second without derailing when it rounds the curved track with a given radius and mass, while the rails exert the maximum radial force they can handle.

What is the formula to calculate the maximum speed of a train rounding a curve without derailing?

To determine the maximum speed of the train without derailing, we need to consider the balance between the centrifugal force and the force of friction. The centrifugal force tries to pull the train off the rails while the force of friction keeps it on the rails.

If the centrifugal force exceeds the force of friction, the train will derail. The maximum speed of the train without derailing can be calculated using the formula v = √(rg), where r is the radius of the curve and g is the acceleration due to gravity.

For instance, if the mass of the train is 500 kg, and the radius of the curve is 10 meters, and the maximum force in the radial direction that the rails can exert is 2000 N, the maximum speed of the train without derailing can be calculated as follows:

v = √((r * F) / m)

v = √((10 * 2000) / 500)

v = 8 m/s

Therefore, the maximum speed of the train without derailing in this scenario is 8 m/s.

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Una niña tira de un carrito por medio de una soga. Si realiza una fuerza de 10 N qué forma un ángulo de 30° con la dirección de desplazamiento. ¿Qué trabajo hace al desplazar 300cm?

Answers

Answer:

El trabajo realizado por la niña es 25.9 J.

Explanation:

El trabajo ue hace la niña viene dado por:

\( W = |F|*|d|*cos(\theta) \)    

En donde:

F: es la fuerza realizada = 10 N

d: es el desplazamiento = 300 cm

θ: es el ángulo entre la fuerza y el desplazamiento = 30°

Entonces, el trabajo es:

\( W = |F|*|d|*cos(\theta) = 10 N*3 m*cos(30) = 25.9 J \)    

Por lo tanto, el trabajo realizado por la niña es 25.9 J.

Espero que te sea de utilidad!        

S
6
Electric Pencil
Sharpener:
Moving electrons cause the
blades to spin.
Game Controller:
The gamer manually
manipulates the joystick and
the movements are translated
into electrical impulses that
travel to the gaming system
through the wires.
→>

Answers

An electric pencil sharpener is a small motorized appliance for sharpening or refreshing the points on lead pencils.

An electric pencil sharpener is a small motorized equipment for polishing or fresh the factors on lead pencils. Within the hollow, a small electric powered motor turns a blade meeting at high velocity. The blades shave wooden and lead from the pencil's cease, bringing it to some extent.

The old-fashioned pencil sharpeners which are established to the wall and cranked through a manage are an instance of a compound system that is composed  simple machines: the wheel and axle and a wedge.

You could sharpen colored pencils in an electric sharpener, however make certain to be very mild with your pencils and often easy your sharpener to put off any wax increase. If performed improperly, sharpening your colored pencils in an electric sharpener can harm each your pencils and your sharpener.

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You make yourself and your friend a cup of hot chocolate and add vanilla ice cream. You quickly enjoy yours, but your friend takes a long time to come, so you get to observe theirs as a science experiment.
In what direction does the heat flow? (2 points)

Describe how the kinetic energy of the hot chocolate changes once you add the ice cream. (2 points)

How does the kinetic energy of the ice cream change once you put it in the hot chocolate? (2 points)

What happens to the temperature of each substance? Be specific. (2 points)

When will the temperature of the ice cream and the hot chocolate stop changing? (2 points)

Answers

Answer:

How does the kinetic energy of the ice cream change once you put it in the hot chocolate?

Explanation: ice cream is cold when the hot chocolate is hot  

Answer:

Explanation:

Heat always flows from HOT to COLD.

KE of hot chocolate decreases.

KE of ice cream increases.

Temp. of hot chocolate decreases (it cools down), temp. of ice cream increases (it warms up).

Temp. of each will stop changing when the 2 substances reach equilibrium (no more flow of heat).

The armature of a small generator consists of a flat, square coil with 190 turns and sides with a length of 1.85 cm . The coil rotates in a magnetic field of 7.55×10 ?2 T. What is the angular speed of the coil if the maximum emf produced is 3.00×10 ?2 V ?

Answers

The armature of a small generator consists of a flat ,the angular speed of the coil in the small generator is 1522.4 rad/s.

The angular speed of the coil in the small generator can be calculated by dividing the maximum emf produced by the product of the number of turns in the coil and the magnetic field strength.

The emf (electromotive force) induced in a coil rotating in a magnetic field is given by the formula:

\(emf = NAB\)ω

where emf is the electromotive force, N is the number of turns in the coil, A is the area of the coil, B is the magnetic field strength, and ω is the angular speed of the coil. where N is the number of turns in the coil, B is the magnetic field strength, A is the area of the coil, and ω is the angular speed of the coil. Rearranging this equation to solve for ω, we get

ω = \(\frac{e}{NBA}\)

Substituting the given values, we get ω = (3.00×10² V)/(190 × 1.85×10 ⁻⁴ m2 × 7.55×10² T) = 1522.4 rad/s. Therefore, the angular speed of the coil in the small generator is 1522.4 rad/s.

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How can we create a new element by combining all the other elements

Answers

Answer:

In order to create a new element you have to change the number of protons in a nucleus.

find the linear acceleration of block aa if there is no slipping between the cord and the surface of the wheel. express your answer in meters per second squared.

Answers

Linear acceleration of block aa is \(1.062 m/s^2\\\).

Given,

Radius R=0.11 m

Moment of inertia I= 0.3kg\(m^2\)

Net torque \(T_n_e_t = I\alpha\)

\(= (I\alpha )/R\)

So since there is no slipping, whatever is the acceleration of the block is the acceleration of the cord. And that acceleration will be the linear acceleration of the this linear acceleration of the pulley.

So let's just assume Ta. Is greater than Tb.

Ta \(\ge\) Tb

(Ta-Tb)×R= I×(a/\(R\))

Ta-Tb=(0.3×a)/\(0.11^2\)

Ta-Tb = 24.8a      ............(1)

(5.5×9.8) - Ta= 5.5a    .......(2)

Tb-(2×9.8)=2a       ............(3)

adding equation 1, 2, and 3 we get,

\(a_A=1.062 m/s^2\)

\(a_B=1.062 m/s^2\)

\(a=R\alpha\)

\(\alpha =9.654 red/s^2\)

T=(2×1.062)+19.6

Tb=21.724 N

Ta=48.06 N

Hence,  Linear acceleration of block aa is \(1.062 m/s^2\\\).

To know more about linear acceleration here:

https://brainly.com/question/14214161

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