installing conductive elements in or under a surface, connecting all the conductive elements together and bonding it to the electrical grounding system will reduce voltage gradients and establish an .

Rate of discharge in cumecs: 0.0048m³/s.

Velocity flow: 24m/s.

a. Convert from litres to m³.
120L*1000= 120000mL

120000mL=120000cm³

120000cm³/100³=0.12 m³.

b. Rate of discharge.

If  0.12 m³ where discharged in 25 seconds, the rate of discharge is:

0.12m³/25s = 0.0048m³/s.

Let's refer to the fluid mechanics equation that relates volume flow, area and velocity. This is the formula:

\(\frac{dV}{dt}=Av\); where the expression \(\frac{dV}{dt}\) is the volume flow rate (in m³/s); A is the cross-sectional area of the pipe (in m²), and v is the velocity flow (in m/s).

a. Solve the equation for v.

\(\frac{dV}{dt}=Av\\ \\(\frac{dV}{dt})/A=v\\ \\v=(\frac{dV}{dt})/A\)

b. Calculate the cross-sectional area of the pipe.

The cross-sectional area of the pipe is a circle. Hence, the formula of this area is:

\(A=\pi r^{2}\)

We'll have to convert the diameter to meters, because the formula for flow velocity needs the area in m². Let's go ahead and do that.

\(50mm/1000=0.05m\).

We were given the diameter, and the formula uses the radius, but the radius is just half of the diameter, therefore, we can substitute in toe formula like this:

\(A=\pi (\frac{0.05}{2} )^{2}=0.0020m^{2}\)

c. Substitute in the new expression for velocity flow and calculate.

\(v=(\frac{dV}{dt})/A\\ \\v=(\frac{0.048m^{3} }{1s})/(0.0020m^{2} )\\\\ v= 24m/s\)

Answer:

Explanation:

The rotation speed depends on the force applied to the coil, and on the mass (moment of inertia) of the coil. The force can be increased by ...

  increasing the magnetic field strength

  increasing the coil current

And the moment of inertia can be decreased by ...

  making the coil lighter

  making the coil more compact.

Any of these changes will increase the rotation speed.

The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.

To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)

Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).

Therefore, Cseries = 330 microfarads.

Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).

Using the following formula:
Rtotal = R + 1/Xc

Where Xc = 1/2πfC,

f is the frequency and C is the capacitance.

For this problem,

Xc = 1/2π(50)(330 x 10-6)

=> 100 kilo-ohm.

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To overcome this challenge, companies need to ensure that their systems are compatible with each other.

Extranet is a platform that allows businesses to interact and exchange data with their partners. This allows the sharing of information between the companies and reduces internetworking costs. The extranet helps to increase coordination between business partners in the following ways:Encourages sharing of information: The extranet allows companies to share data with their partners. This allows the partners to stay updated on the latest trends in the market and come up with new business ideas. It also allows companies to improve their supply chain and speed up delivery times. Improves communication: The extranet allows companies to communicate more effectively with their partners. This is done through the use of chat rooms, message boards, and email. This allows partners to exchange ideas and discuss business strategies in real-time.Identify two companies that use extranets as an internetworking platform:Two companies that use extranets as an internetworking platform are:a. Walmart: Walmart uses an extranet to manage its supply chain.

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Explanation:

In this series, the professionals at the B.O.L.D. Company will take you through the process of building a custom home in the Greater Cincinnati – Northern Kentucky area. From plan and lot selection, to mortgage approval, to the actual construction, we’ll take you behind-the-scenes each week for an inside look at a different part of the process.

Answer:

To calculate the moment of resistance in each case, we need to consider the properties and stresses of both the timber beam and the steel flitches.

Given data:

Width of timber beam (b): 100 mm

Depth of timber beam (d): 200 mm

Size of steel flitches (b1 x d1): 150 mm x 12.5 mm

Allowable stress in timber (σt): 6 N/mm²

Modulus of elasticity for steel (Es): 200,000 N/mm²

Modulus of elasticity for timber (Et): 10,000 N/mm²

Let's calculate the moment of resistance in each case:

(a) Flitches attached symmetrically at the top and bottom:

In this case, the steel flitches are attached to the top and bottom faces of the timber beam.

Calculation of moment of resistance:

The moment of resistance is given by the formula:

M = σt * Zt

where M is the moment of resistance and Zt is the section modulus of the timber beam.

The section modulus of a rectangular section is calculated as:

Zt = (b * d^2) / 6

Plugging in the values:

Zt = (100 * 200^2) / 6 = 6,666,667 mm^3

Now, let's calculate the maximum stress in the steel flitches:

Calculation of maximum stress in steel:

The stress in the steel flitches can be calculated using the formula:

σs = (M * Es) / Zs

where σs is the stress in the steel and Zs is the section modulus of the steel flitches.

The section modulus of a rectangular section is calculated as:

Zs = (b1 * d1^2) / 6

Plugging in the values:

Zs = (150 * 12.5^2) / 6 = 520.833 mm^3

Now, let's calculate the maximum stress in the steel:

σs = (M * Es) / Zs

= (σt * Zt * Es) / Zs

Plugging in the values:

σs = (6 * 6,666,667 * 200,000) / 520.833

= 45,454.5 N/mm²

Therefore, the maximum stress in the steel when flitches are attached symmetrically at the top and bottom is 45,454.5 N/mm².

(b) Flitches attached symmetrically at the sides:

In this case, the steel flitches are attached to the sides of the timber beam.

Calculation of moment of resistance:

The section modulus of the timber beam remains the same as in case (a).

Zt = 6,666,667 mm^3

Now, let's calculate the maximum stress in the steel flitches:

Calculation of maximum stress in steel:

The section modulus of the steel flitches changes as they are now attached differently. Since the flitches are attached symmetrically at the sides, their effective section modulus becomes:

Zs = (b1^2 * d1) / 6

Plugging in the values:

Zs = (150^2 * 12.5) / 6 = 46,875 mm^3

Now, let's calculate the maximum stress in the steel:

σs = (M * Es) / Zs

= (σt * Zt * Es) / Zs

Plugging in the values:

σs = (6 * 6,666,667 * 200,000) / 46,875

= 40,000 N/mm²

Therefore, the maximum stress in the steel when flitches are attached symmetrically at the sides is 40,000 N/mm².

To summarize:

(a) Flitches attached symmetrically at the top and bottom:

Moment of resistance: Calculated using σt and Zt.

Maximum stress in steel: 45,454.5 N/mm²

(b) Flitches attached symmetrically at the sides:

Moment of resistance: Calculated using σt and Zt.

Maximum stress in steel: 40,000 N/mm²

The value of the UCS when a rock core 50 mm in diameter and 150 mm long was tested to destruction in a laboratory is 31.24.

A unified computing system (UCS) is a data center architecture that combines computing, networking, and storage resources to improve efficiency and enable centralized management. The Unified Computing System is a data center server computer product line comprised of server hardware, software, and services.

In this case, a rock core 50 mm in diameter and 150 mm in length was destroyed in a laboratory. The measurements displayed in the table to the right were taken during the test. The answer is 31.24.

Please see the attached.

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ATDs can be a useful tool for researchers but it is important to bear these limitations in mind

Alternating Treatment Designs (ATDs) have a few limitations which must be taken into consideration when designing a study. Firstly, it is susceptible to multiple treatment interference, which is when the effects of multiple treatments interact with each other. This can invalidate results or lead to incorrect conclusions. Secondly, rapid back-and-forth switching of treatments does not reflect the typical manner in which interventions are applied and may be viewed as artificial and undesirable. Finally, it is limited to a maximum of four different treatment conditions, meaning that complex interventions are difficult to evaluate.

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Answer:

The total contraction on the bar is 1.2277 mm

Note: Kindly find an attached copy of part of the solution given below

Explanation:

Solution

Recall that:

The giving data for aluminum bar is sated below:

The total length = 600 mm

The diameter = 40 mm

The hole = 30 mm

The length of the hole = 100 mm

The elasticity (E) = 85 * 10^9 GPa

= 85 * 10^3 N /mm²

Now,

To determine the contraction we apply he following formula given below:

δL = Load *L/A * E

Answer:

b. 336,000.

Explanation:

Step 1: Calculate the molecular weight of the monomer

Polyethilene is a polymer with the formula (C₂H₄)ₙ, where C₂H₄ is the monomer and n is the number of monomers in the polymer. We can calculate the molecular weight of the monomer by addition of the weights of the atoms that form it.

MC₂H₄ = 2 × MC + 4 × MH

MC₂H₄ = 2 × 12 + 4 × 1 = 28

Step 2: Calculate the average molecular weight of polyethylene

The average degree of polymerization (DP) of polyethylene is 12,000. We can calculate the average molecular weight of polyethylene using the following expression.

DP = M(C₂H₄)ₙ/MC₂H₄

M(C₂H₄)ₙ = DP × MC₂H₄

M(C₂H₄)ₙ = 12,000 × 28 = 336,000

Answer:

ere el merjor 5iyer

Explanation:

yyhh espero ayuder 8 mucho 666

Answer:

Then miss try to get your school to banned it for your district like forbid then from the web site then it will not allow them to use it. then sometimes use it to help other people who needs help like teachers do or we need help with something we dont know so we ask for help for a better understanding of it.

Explanation:

^-^ hope you have a good day miss or sir

Answer:

So I would love to say that you and your team at your school had banned brainly and why are you using brainly here, then you shouldn't use brainly, and brainly all students around the world gets help even you is one.

Answer:

mano não sei mas acho que vai dar certo porque isso aí é muito top mas é isso aí mano o cara tem que ser confiar mesmo viu que negócio é desse jeito mesmo entendeu porque sabe como é que é as coisas né nada é fácil mesmo hein mas é isso aí mano continua tentando aí mano porque Rapaz tu é louco doido agora tá difícil mesmo mas é isso aí o cara tem que ir saber se ele tá ligado eu deixei isso mesmo né mas é isso aí meu truta

Explanation:

É isso aí mano Espero que tenho ajudado aí beleza manda a tua pergunta aí beleza é isso aí mano É isso aí continua hein p

Answer:

In antagonistic combination of drugs, the effects of ine drug cancel or diminish the effects of another

The total present worth is $19,783.01

The present worth of a series of cash flow is the value of the cash flows in year 0 (today)

Cash flow in year 0 = 5330

Cash flow in year 1 = 0

Cash flow in year 2 = 0

Cash flow in year 3 = 13075 / (1.02)^3 = 12,320.86

Cash flow in year 4 = 2308 / (1.02)^4 = 2,132.24

Present worth = $19,783.01

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Answer:

Draw up the contract for construction management.

Answer:

Work with construction management to solve specific problems as they arise.

Ensure compliance with safety standards.

Explanation:

It is important to keep welders properly tuned because it "Reduces air pollution" (Option A).

Welding machinery, welding guns, and welders are among the most important items for a welding expert to have. Welding machines provide heat that melts steel pieces, allowing them to be bonded.

Most welders also use an angle grinder to smooth out joints, wire brushes to clean or abrade steel surfaces before welding etc.

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Full Question:

Why is it important to keep portable welders properly tuned?

a-Reduce air pollution

b-So they run quieter

c-To produce smoother welding current

d-All of the above

Answer:

please give me brainlist and follow

Explanation:

Mild steel can be converted into high carbons steel by which of the following heat treatment process? Explanation: Case hardening, also referred as carburizing increases carbon content of steel, thus, imparting hardness to steel.

Answer:

2/4

7/2

92/1

83/1

9/1

93/0

Explanation:

R

K

K

R

K

R

I don't really know the answer

Answer:

fggffgethjbdxvgrsbjb you are my world I see the attached resume

9514 1404 393

Answer:

  1

Explanation:

Only one such circle can be drawn. The diameter of the 10" circle will be a radius of the semicircle. In order for the 10" circle to be wholly contained, the flat side of the semicircle must be tangent to the 10" circle. There is only one position in the figure where that can happen. (see attached).

Answer:

When we say that a data structure is immutable in Python, it means that its values cannot be changed after it has been created. Any attempt to modify an immutable object will result in the creation of a new object with the updated value, rather than changing the original object. This property of immutability is useful for ensuring data integrity and avoiding accidental modifications to important data. Examples of immutable data structures in Python include strings, tuples, and frozensets.

In Python, an immutable data structure is a data structure that cannot be changed once it is created. This means that if a value is assigned to an immutable data structure, it cannot be modified later, and any operation that attempts to modify the data structure will create a new object with the modified value.For example, tuples in Python are immutable data structures. Once a tuple is created, its contents cannot be changed. If you try to modify a tuple, Python will raise a TypeError.

my_tuple = (1, 2, 3)

my_tuple[0] = 4  # This will raise a TypeError because tuples are immutable

In contrast, mutable data structures, such as lists and dictionaries, can be modified after they are created. This means that you can add, remove, or modify elements in a list or dictionary after they are created.Overall, immutability is a useful property in programming because it makes it easier to reason about the behavior of code and reduces the risk of unintended side effects. In Python, when we say that a data structure is immutable, it means that the elements within the data structure cannot be changed or modified after they are created. Some examples of immutable data structures are strings and tuples. Once an immutable object is created, its state and contents remain constant throughout its lifetime.

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Answer:

La potencia disipada por el resistor es 200 watts.

Explanation:

Supóngase que el resistor trabaja en corriente continua (CC). La potencia disipada por el resistor (\(\dot W\)), medida en watts, es definida por la siguiente ecuación matemática:

\(\dot W = i^{2}\cdot R\) (1)

Donde:

\(i\) - Corriente eléctrica, medida en amperios.

\(R\) - Resistencia eléctrica, medida en ohms.

Si sabemos que \(R = 10000\,\Omega\) y \(i = 20\times 10^{-3}\,A\), la potencia disipada por el resistor es:

\(\dot W = (20\times 10^{-3}\,A)\cdot (10000\,\Omega)\)

\(\dot W = 200\,W\)

La potencia disipada por el resistor es 200 watts.

Answer:

True

Explanation:

Answer:

59°C

Explanation:

Given that, Cc = McCp,c = 5000 /3600 × 4178 = 5803.2(W/K)

and Ch = MhCp,h = 10000 / 3600 × 4188 = 11634.3(W/K)

Therefore the minimum and maximum heat capacities are:

Cmin = Cc = 5803.2(W/K)

Cmax = Ch = 11634.3(W/K)

The capacity ratio is:

Cr = Cmin / Cmax = 0.499 = 0.5

The maximum possible heat transfer rate is:

Qmax = Cmin (Th,i - Tc,i) = 5803.2 (80 - 20) = 348192(W)

And the number of transfer units is: NTU = UA / Cmin = 11600 / 5803.2 = 1.99

Given that from the appropriate graph in the handouts we can read  = 0.7. So the actual heat transfer rate is: Qact = Qmax = 0.7 × 348192 = 243734.4(W)

Hence, the outlet hot temperature is: Th,o = Th,i - Qact / Ch = 59°C

Answer:

4.75m^2

Explanation:

Given:-

- Temperature of hot fluid at inlet:  \(T_h_i = 300\) °C

- Temperature of cold fluid at outlet: \(T_c_o = 120\) °C

- Temperature of cold fluid at inlet: \(T_c_i = 35\) °C

- The overall heat transfer coefficient: U = 1500 W / m^2 K

- The flow rate of cold fluid: m_c = 10,00 kg/ h

- The flow rate of hot fluid: m_h = 5,000 kg/h

Solution:-

- We will evaluate water properties at median temperatures of each fluid using table A-4.

Cold fluid:   Tci = 35°C , Tco = 35°C

                            Tcm = 77.5 °C ≈ 350 K  --- > \(C_p_c = 4195 \frac{J}{kg.K}\)

 Hot fluid:     Thi = 300°C , Tho = 150°C ( assumed )

                             Thm = 225 °C ≈ 500 K --- > \(C_p_h = 4660 \frac{J}{kg.K}\)

- We will use logarithmic - mean temperature rate equation as follows:

                             \(A_s = \frac{q}{U*dT_l_m}\)

Where,

                 A_s : The surface area of heat exchange

                 ΔT_lm: the logarithmic differential mean temperature

                 q: The rate of heat transfer

- Apply the energy balance on cold fluid as follows:

                   \(q = m_c * C_p_c * ( T_c_o - T_c_i )\\\\q = \frac{10,000}{3600} * 4195 * ( 120 - 35 )\\\\q = 9.905*10^5 W\)

- Similarly, apply the heat balance on hot fluid and evaluate the outlet temperature ( Tho ) :

                   \(T_h_o = T_h_i - \frac{q}{m_h * C_p_h} \\\\T_h_o = 300 - \frac{9.905*10^5}{\frac{5000}{3600} * 4660} \\\\T_h_o = 147 C\)

- We will use the experimental results of counter flow ( unmixed - unmixed ) plotted as figure ( Fig . 11.11 ) of the " The fundamentals to heat transfer" and determine the value of ( P , R , F ).

- So the relations from the figure 11.11 are:

                  \(P = \frac{T_c_o - T_c_i}{T_h_i - T_c_i} \\\\P = \frac{120 - 35}{300 - 35} \\\\P = 0.32\)    

                 \(R = \frac{T_h_i - T_h_o}{T_c_o - T_c_i} \\\\R = \frac{300 - 147}{120 - 35} \\\\R = 1.8\)

Therefore,         P = 0.32 , R = 1.8 ---- > F ≈ 0.97

- The log-mean temperature ( ΔT_lm - cf ) for counter-flow heat exchange can be determined from the relation:

                        \(dT_l_m = \frac{( T_h_i - T_c_o ) - ( T_h_o - T_c_i ) }{Ln ( \frac{( T_h_i - T_c_o )}{( T_h_o - T_c_i )} ) } \\\\dT_l_m = \frac{( 300 - 120 ) - ( 147 - 35 ) }{Ln ( \frac{( 300-120 )}{( 147-35)} ) } \\\\dT_l_m = 143.3 K\)

- The log - mean differential temperature for counter flow is multiplied by the factor of ( F ) to get the standardized value of log - mean differential temperature:

                       \(dT_l = F*dT_l_m = 0.97*143.3 = 139 K\)

- The required heat exchange area ( A_s ) can now be calculated:

                     \(A_s = \frac{9.905*10^5 }{1500*139} \\\\A_s = 4.75 m^2\)

Explanation:

for checking in customers who bring their cars in to be serviced. The employees are currently using legal pads to write down the customers’ information, the reason they need service, and identifying information about the car, such as the license plate number. Which wireless technology would help streamline the employees’ work duties and reduce errors from poor handwriting or lost/misplaced paper?

Answer:

Option B: Tablet computer.

Explanation:

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B) transistor. Typically a constant voltage CP rectifier will NOT have transistor.

A constant voltage CP (controlled potential) rectifier is a type of rectifier used in electrochemical processes. It typically consists of a transformer, a rectifying element (such as diodes), voltage taps, and other components. However, it does not typically include a transistor, as transistors are not commonly used in CP rectifiers. Transistors are electronic devices used for amplification and switching of electrical signals, and they are not necessary for the operation of a typical constant voltage CP rectifier, which primarily functions to provide a stable DC output voltage for electrochemical processes.

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