Into a 125 mL Erlenmeyer flask was added some KI and H2SO4 as described in the procedure section of this experiment. Then 3.0 mL of bleach solution was added to the flask and it was immediately titrated with 0.1261 M sodium thiosulfate solution. It required 41.26 mL of this sodium thiosulfate solution to reach the end point of the titration. What is the percentage of NaOCl in the bleach

There will be 0.4589 mL of ethyl acetate left in the space after evaporation.

The conversion of a liquid substance into a gas is known as evaporation. As a result of the liquid absorbing energy from its surroundings, molecules begin to travel faster and faster until they finally become a vapour and escape into the environment. Usually, the energy is absorbed as heat, but it can also be in the form of light or electricity.

No, the ethyl acetate won't all evaporate. The amount of ethyl acetate that will stay in the space after evaporation can be determined using the ideal gas law. As per the ideal gas law, PV = nRT

P is the overall system pressure, V is the room's volume, n is the amount of ethyl acetate in moles, R is the ideal gas constant, and T is the temperature.

To solve for n, the quantity of moles of ethyl acetate, we can rearrange the equation as follows: n = PV/RT

When the values are plugged in, we get:

n = (94.9 torr)(7.25 m x 2.75 m x 2.75 m)/(8.314 J/K mol)(298 K)

\(n = 4.666 \times 10^{-3} mol\)

The molar mass of ethyl acetate (88.11 g/mol) can then be used to compute the mass of ethyl acetate:

Mass = \(n \times M = (4.666 x 10^{-3} mol)(88.11 g/mol)\) = 0.4125 g

Using the density of ethyl acetate (0.901 g/mL), it is possible to determine the volume of the liquid that is still present:

Volume = mass/density = (0.4125 g)/(0.901 g/mL) = 0.4589 mL

As a result, there will be 0.4589 mL of ethyl acetate left in the space after evaporation.

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Answer:

C.

Explanation:

Answer:

C

Explanation:

Answer:

\(n_{O_2}=18.1molO_2\)

Explanation:

Hello there!

In this case, according to the combustion of octane:

\(C_8H_1_8+25/2O_2\rightarrow 8CO_2+9H_2O\)

We can see there is a 1:25/2 mole ratio of octane to oxygen; therefore, we can calculate the moles of oxygen via the following stoichiometric factor:

\(n_{O_2}=1.45molC_8H_1_8*\frac{25/2molO_2}{1molC_8H_1_8} \\\\n_{O_2}=18.1molO_2\)

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Answer:

B

Explanation:

Answer:

B.

radiant ---> thermal

Explanation:

Answer:

The reaction of 4-acetyl anisole (also known as p-methoxyacetophenone) with hydroiodic acid (HI) results in the cleavage of the O-methyl group of the anisole ring, leading to the formation of iodobenzene and acetophenone. The balanced equation for this reaction is C9H10O2 + HI → C6H5I + C8H8O.

So, the product of the reaction of 4-acetyl anisole with HI is a mixture of iodobenzene and acetophenone. The specific ratio of these products will depend on the reaction conditions, such as the temperature and concentration of the reactants.

It's worth noting that the reaction between 4-acetyl anisole and HI is an example of a nucleophilic aromatic substitution reaction, which involves the replacement of a leaving group (in this case, the O-methyl group) on an aromatic ring by a nucleophile (the iodide ion from HI).

Answer:

See explanation and image attached

Explanation:

The reaction of bromine molecule with an alkene passes through a bridged intermediate known as the brominium ion.

It is a cyclic intermediate that contains a positively charged bromine ion as i have shown in the image attached.

The brominium ion is first formed during the bromininaton of alkenes.

An unknown compound is analyzed gravimetrically and found to contain 77.6 ± 0.1 % of bromine. Molecular formula is NaBr (sodium bromide)

This is further explained below.

Generally,  Here given the 77.6+1-0.1 \%bromine Mass percentage of \($\mathrm{Br}$ in $\mathrm{NaBr}=\frac{79.9}{102.89} \times 100$\)

=0.776 *100

=77.6%

Therefore the mass percentage of Br in NaBr is 77.6 % matched with the given bromine mass percentage 77.6 \(\pm\)0.1 %

Mass percentage of

\($$\begin{aligned}\mathrm{Br} \text { in } \mathrm{KBr} &=\frac{79.9}{119} \times 100 \\&=0.671 \times 100 \\&=67.1 \%\end{aligned}$$\)

Mass percentage of Br in CaBr_2\(=\frac{159.8}{199.8} \times 100$$=79.9 \%$\)

Therefore, the mass % of B_r in k B r on d CaBr_2 is a hot match with the given mass % $77.6\(\pm\) 0.10%

Therefore, the Molecular formula of an unknown salt is NaBr

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The immediate cause for the United States' entry into World War II was the attack on Pearl Harbor by Japan on December 7, 1941.

World War II was a global war that lasted from 1939 to 1945. It involved the majority of the world's nations, including all of the great powers, organized into two opposing military alliances: the Allies and the Axis.

Prior to this attack, the United States had maintained a policy of neutrality and had provided support to the Allies in the form of aid and supplies. However, the attack on Pearl Harbor, which resulted in the deaths of over 2,400 Americans, led to a declaration of war against Japan by the United States, and ultimately to the country's involvement in the larger global conflict.

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Based on the description of the potential energy diagram provided, the diagram made by the student appears to be correct.

The potential energy diagram represents the energy changes that occur during a chemical reaction. In an endothermic reaction, the products have higher potential energy than the reactants, meaning energy is absorbed from the surroundings.

The curve line on the graph indicates the energy changes throughout the reaction pathway. It starts at a higher level, representing the initial potential energy of the reactants. As the reaction progresses, the potential energy decreases, indicating the formation of products with lower potential energy.

The broken horizontal line from point X on the y-axis to the point where the curve begins represents the activation energy (Ea) of the reaction. Activation energy is the energy barrier that must be overcome for the reactants to convert into products.

Point X on the y-axis indicates the potential energy of the reactants at the start of the reaction, and the broken line shows the energy required to initiate the reaction.

The broken horizontal line from point Y on the y-axis to the point where the curve ends represents the potential energy of the products. Point Y represents the potential energy of the products at the end of the reaction.

Overall, the student's diagram correctly represents an endothermic reaction, showing the potential energy changes, the activation energy, and the final potential energy of the products. The curve line starts at a higher level (representing the higher potential energy of the reactants) and ends at a slightly lower level (representing the lower potential energy of the products).

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The volume of \(SO_{3}\) would be produced by complete reaction of 100cm3 of \(H_{2}O\)with \(O_{2}\) is at STP is 60.03L.

22.4 L divided by 2.68 moles per mole yields 60.03 L \(SO_{3}\).

describing the elements contributing to the response,

\(2SO_{2(g)}+ O_{2} = 2SO_{3}\)

In this instance, \(SO_{3}\) and \(O_{2}\) have a mole ratio of 2:1. Assume the reaction takes place at STP, where 1 mole of any gas has a volume of 22.4 L. Consequently, 30 \(dm^{3}\)of \(O_{2}\) (1 dm3 = 1 L) equals 30 L of \(O_{2}\) and 30 L/22.4 L times 1 mole equals 1.34 moles of \(O_{2}\).

According to stoichiometry, when 1.34 moles of \(O_{2}\)are reacted with \(SO_{2}\), 2.68 moles of \(SO_{3}\) are created, or 2/1 x 1.34 moles of \(SO_{3}\).

This means that the amount of \(SO_{3}\)produced will be (2.68 moles/1 mole) x 22.4 L = 60.03 L \(SO_{3}\).

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The substance in red blood cells that carbon monoxide from cigarette smoke combines with is called hemoglobin.

Hemoglobin is a protein molecule found in red blood cells that is responsible for transporting oxygen from the lungs to the rest of the body. Hemoglobin consists of four subunits, each containing a heme group. The heme group contains an iron ion, which binds to oxygen molecules in the lungs.

Carbon monoxide (CO) from cigarette smoke can bind to the iron ion in the heme group with a much greater affinity than oxygen. When CO binds to hemoglobin, it forms a stable complex called carboxyhemoglobin (COHb).

This reduces the amount of hemoglobin available for binding with oxygen, which can lead to a reduction in the amount of oxygen that can be transported to the tissues.

The formation of COHb can also affect the release of oxygen from hemoglobin in the tissues. Hemoglobin releases oxygen in response to a decrease in oxygen concentration, which is sensed by the heme group. However, when CO binds to the heme group, it alters the shape of the hemoglobin molecule and reduces its ability to release oxygen.

As a result, the presence of carbon monoxide in the blood can lead to a range of health problems, including headaches, dizziness, shortness of breath, and even death in severe cases.

The best way to prevent carbon monoxide poisoning is to avoid exposure to smoke from tobacco products and other sources of combustion, such as gas heaters and stoves.

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Answer:

B: geothermal energy comes from eternal heat of earth.

Explanation:

INFORMATION:

We have the following ionic compounds:

- barium sulfate

- lithium nitrate

- cesium sulfide

And we must write their formulas

STEP BY STEP EXPLANATION:

1. Barium sulfate:

To write its formula, we need to use that:

- the element symbol for Barium is Ba, and it has a charge of 2+

- in the given table, sulfate is a polyatomic ion represented by SO4, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

Since the compound has a net charge of zero, we can write its formula as

2. Lithium nitrate:

To write its formula, we need to use that:

- the element symbol for Lithium is Li, and it has a charge of 1+

- in the given table, nitrate is a polyatomic ion represented by NO3, and it has a charge of 1-

Now, we must add up the charges to verify if the ionic compound is neutral

Since the compound has a net charge of zero, we can write its formula as

3. Cesium sulfide:

To write its formula, we need to use that:

- the element symbol for Cesium is Cs, and it has a charge of 1+

- the element symbol for sulfide is S, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

Since the compound has a net different from zero, we need to analyze the compound.

So, if we have just one atom of Cs, the charge would be 1+, but if we take two atoms the charge would be 2(1+) = 2+

Now, verifying the net charge

Now, we can write its formula as

ANSWER:

barium sulfate:

lithium nitrate :

cesium sulfide:

Therefore, 21.3 g of iron (II) sulfate has been formed in the reaction.

The balanced chemical equation for the reaction is:

Fe(s) + CuSO4(aq) → Cu(s) + FeSO4(aq)

To find the amount of iron (II) sulfate formed, we first need to determine which reactant is limiting. We can do this by calculating the amount of copper (II) sulfate that reacts with the iron strip:

m(CuSO4) = 21.0 g

m(Fe) = 15.5 g - 8.5 g = 7.0 g

M(CuSO4) = 159.6 g/mol

M(Fe) = 55.8 g/mol

n(CuSO4) = m(CuSO4) / M(CuSO4) = 21.0 g / 159.6 g/mol = 0.1314 mol

n(Fe) = m(Fe) / M(Fe) = 7.0 g / 55.8 g/mol = 0.1255 mol

From the balanced equation, we see that one mole of iron reacts with one mole of copper (II) sulfate to form one mole of iron (II) sulfate. Therefore, since the moles of iron are slightly less than the moles of copper (II) sulfate, iron is the limiting reactant. This means that all of the copper (II) sulfate has reacted and the reaction has stopped.

The mass of iron (II) sulfate formed can be calculated using the mass of iron that reacted:

m(FeSO4) = n(Fe) x M(FeSO4) = 0.1255 mol x (55.8 g/mol + 2(16.0 g/mol)) = 21.3 g

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The observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

From the observation that the hole in the window is smaller on the outside than on the inside, Becca, as a forensic technician, might deduce the following:

The hole was caused by an impact from the outside: The smaller outside hole suggests that the force that created the hole originated from the outside and exerted more pressure on the window surface facing inward.

The object causing the hole was larger on the inside: The discrepancy in hole sizes implies that the object that struck the window had a larger size or diameter on the inside, and as it penetrated the glass, it compressed or fragmented the glass, resulting in a larger hole on the inside.

The object may have passed through the window: The difference in hole sizes indicates that the object may have penetrated the window, potentially passing through to the inside. This could suggest a break-in or an incident involving the window being struck from the outside.

Overall, the observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

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Answer:

3.0 x 10²⁴molecules

Explanation:

Given parameters:

Number of moles of compound  = 5moles

Unknown:

Number of molecules  = ?

Solution:

A mole is substance that contains the Avogadro's number of particles;

   1 mole  = 6.02 x 10²³ molecules

   5 moles of the compound will give 5 x 6.02 x 10²³ molecules

                = 3.0 x 10²⁴molecules

When copper is placed in water, it reacts with the water molecules to form copper(II) ions and hydrogen gas. The reaction is exothermic, which means it releases heat energy into the surroundings. By measuring the temperature changes that occur, we can determine the amount of heat that is released by the reaction.

The temperature changes can be measured using a thermometer. We can place the copper metal in a container of water and take the initial temperature reading. Then, we can add the copper to the water and record the temperature change over time. By monitoring the temperature changes, we can observe the exothermic reaction taking place.

The heat released by the reaction between copper and water has many practical applications, including in the design of power plants and in the production of steam for heating and electricity generation. Therefore, understanding the heat released during this reaction is important for a variety of scientific and engineering fields.

In conclusion, step 7 of putting copper metal in water and measuring the temperature changes allows us to observe and measure the heat released by the exothermic reaction between copper and water, which has important applications in various scientific and engineering fields.

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Answer:

Aluminum

copper

Iron

Lead

The Final Slide:

Aluminum- 0.90

Copper- 0.35

Iron- 0.44

Lead- 0.12

Explanation:

I hope this helps! :))))

Answer: Well, the volume of the copper is (63.4 - 40.0) * mL = 23.4 * mL

Explanation:

Do you agree? The copper displaces the given volume of water.

Now  ρ Cu =  8.90  ⋅  g  ⋅  c m 3  OR  ρ Cu  =  8.90  ⋅  g  ⋅  m L − 1, i.e.  1 ⋅  m L  ≡  1  ⋅  c m 3

But by definition,  ρ  density  =  mass  volume

And thus  mass  =  ρ  ×  volume  =  8.90  ⋅  g  ⋅  m  L  −  1  ×  23.4  ⋅  m  L

= 208.3 * G

The specific heat capacity of the granite is 0.796 J/gºC

We'll begin by calculating the heat absorbed by the water. This can be obtained as follow:

Mass of water (M) = 400 g

Initial temperature of water (T₁) = 20 °C

Final temperature (T₂) = 28.5 °C

Change in temperature (ΔT) = T₂ – T₁ = 28.5 – 20 = 8.5 °C

Specific heat capacity of water (C) = 4.184 J/gºC

Q = MCΔT

Q = 400 × 4.184 × 8.5

Thus, the heat absorbed by the water is 14225.6 J

Heat absorbed = Heat released

Heat absorbed = 14225.6 J

Mass of granite (M) = 250 g

Initial temperature of granite (T₁) = 100 °C

Final temperature (T₂) = 28.5 °C

Change in temperature (ΔT) = T₂ – T₁ = 28.5 – 100 = –71.5 °C

Q = MCΔT

–14225.6 = 250 × C × –71.5

–14225.6 = –17875 × C

Divide both side by –17875

C = –14225.6 / –17875

Therefore, the specific heat capacity of the granite is 0.796 J/gºC

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Answer:

Reagents: 1) \(BH_3\) 2) \(H_2_O2\), \(OH^-\)

Mechanism: Hydroboration

Explanation:

In this case, we have a hydration of alkenes reaction. But, in this example, we have an anti-Markovnikov reaction. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: "hydroboration".

The first step of this reaction is the addition of borane (\(BH_3\)) to the double bond. Then in the second step, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the third step, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "\(BH_2-O-OH\)". In step number 4 we have the migration of the C-B bond to oxygen. Then in step number 5, we have the attack of \(OH^-\) on the \(O-BH_2\) to produce an alkoxide. Finally, the water molecule produce in step 2 will protonate the molecule to produce the alcohol.

See figure 1

I hope it helps!

This is an exercise in the General Combined Gas Law.

To start solving this exercise, we obtain the following data:

We apply the following formula:

Where:

We clear for final pressure (P2)

\(\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}\)

We substitute our data into the formula:

\(\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})} \end{gathered}$}\)

\(\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 } \end{gathered}$}\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}\)

Answer: The new canister pressure is 539.224 mmHg.

The new pressure of the balloon, given that  the temperature increases to 32 °C causing the balloon to expand to 2.2 L is 268.97 atm

From the question given above, the following data were obtained:

The combined gas equation states shown as below:

P₁V₁ / T₁ = P₂V₂ / T₂

Inputting the various parameters, we can obtain the new pressure as follow:

(385 × 1.5) / 298 = (P₂ × 2.2) / 305

Cross multiply

298 × 2.2 × P₂ = 385 × 1.5 × 305

Divide both sides by (298 × 2.2)

P₂ = (385 × 1.5 × 305) / (298 × 2.2)

P₂ = 268.97 atm

Thus, from the above calculation, it is evident tha the new pressure of the balloon is 268.97 atm

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Answer:

analyze

Explanation:

After testing is analyzing your data then you compare your data to your hypothesis to see if they match  

Answer:

Compact cars with smaller engines can't achieve more than 30 mpg because of the weight difference

Hope This Helped

The correct option is D. 2-butanone organic compound has a branched hydrocarbon group.

Natural compounds are a substance that consists of covalently- bonded carbon and hydrogen and frequently with other elements. organic compounds examples are benzoic Acid, fragrant compounds, benzoic aldehyde, propanoic acid, butanoic acid, malonic acid, amines, heterocyclic compounds, VOC, benzoic acid, and diethyl malonate.

In chemistry, many authors bear in mind that an organic compound is any chemical compound that includes carbon-hydrogen or carbon-carbon bonds, although, the definition of "natural" versus "inorganic" varies from author to writer, and it's far a subject of debate. The chemicals of living matter are called organic compounds due to their affiliation with organisms and due to the fact they're carbon-containing compounds. organic compounds, which are the compounds associated with existence procedures, are the difficult count of a number of natural chemistry.

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Answer:

Hi..? All three elements are in group 1 thus they have 1 valence electron which is easy to lose due to shielding.As Pottasium is larger than the rest,Pottasium's valence electron is at a greater distance from the attractive nucleus and is so removed more easily than Sodium's and Lithium's valence electrons.As it is removed more easily it requires less energy and can be said to be more reactive