Answer:
The speed at which Carol needs to drive to meet Irvin at Bananatown at exactly the same time is approximately 47.188 miles per hour
Step-by-step explanation:
The given information are;
The location of Bananatown from Appletown = 143 miles east and 45 miles north
The location of Coconutville from Appletown = 98 miles east and 32 miles south
Taking Appletown as the origin, we have;
The slope, gradient of highway 42 = 45/143
The equation of a line representing highway 42 is given as follows;
y - 0 = 45/143 × (x - 0)
y = 45/143·x
Therefore, at Coconutville, where x = 98, we have, y = 45/143 × 98 ≈ 30.84 miles north
Total distance north Carol has to drive to get to highway 42 = 32 + 30.84 = 62.84 miles
Total distance along highway 42 Carol will drive to get to Bananatown = √((143 - 98)² + (45 - 30.84)²) ≈ 47.175 miles
Total distance Carol drives to Bananatown = 47.175 miles + 62.84 miles ≈ 110.015 miles
The total distance Irvin needs to drive to arrive at Bananatown = √(143² + 45²) ≈ 149.91
The total distance Irvin needs to drive to arrive at Bananatown ≈ 149.91 miles
The time it takes Irvin to arrive at Bananatown = (149.91 miles)/(45 mph) ≈ 3.33 hours
The time he arrives at Bananatown = 8 a.m. + 3.33 hours ≈ 11.33 a.m.
The time available for Carol to meet Irvin at Bananatown at exactly the same time = 11.33 a.m. - 9 a.m. = 2.33 hours
Therefore, the speed at which Carol needs to drive = (110.015 miles)/2.33 hour ≈ 47.188 miles per hour
The speed at which Carol needs to drive to meet Irvin at Bananatown at exactly the same time ≈ 47.188 miles per hour.
HELP PLEASE!! 2 part question
Answer: B. 1 1/2
Step-by-step explanation:
What are advantages and disadvanteges when using percent to measure change?
Answer:
Step-by-step explanation:
Percentages are a powerful way to compare samples with different numbers of observations. By standardising measures using a scale of 0 to 100, samples can be compared quickly and easily. Any graph of the data, however, must include the full range of 0 to 100 to ensure that false impressions are not created.
Write a function representing the line that includes the points (3,3) and (-6,15)
A function representing the line that includes the points (3,3) and (-6,15) is 3y=-4x+21.
The given coordinate points are (3,3) and (-6,15).
What is the slope intercept form?The slope intercept form of a straight line is one of the most common forms used to represent the equation of a line. The slope intercept formula can be used to find the equation of a line when given the slope of the straight line and the y-intercept.
The standard form of the slope intercept form is y=mx+c.
Now, slope=(y2-y1)/(x2-x1)
= (15-3)/(-6-3)
= 12/(-9)
= -4/3
Substitute m=-4/3 and (x, y)=(3, 3) in y=mx+c, we get
3=-4/3 (3) +c
c=7
Put, m=-4/3 and c=7 in y=mx+c, we get
y=-4/3 x+7
3y=-4x+21
Therefore, a function representing the line that includes the points (3,3) and (-6,15) is 3y=-4x+21.
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A uniformly distributed continuous random variable is defined by the density function f(x)=0 on the interval [8,10]. What is P(8,3
O 0.6
O 0.9
O 0.8
O 0.5
P(8, 3 < X < 9) = 0.5. So, option (D) is correct.
A uniformly distributed continuous random variable is defined by the density function f(x) = 0 on the interval [8, 10]. So, we have to find P(8, 3 < X < 9).
We know that a uniformly distributed continuous random variable is defined as
f(x) = 1 / (b - a) for a ≤ x ≤ b
Where,b - a is the interval on which the distribution is defined.
P(a ≤ X ≤ b) = ∫f(x) dx over a to b
Now, as given, f(x) = 0 on [8,10].
Therefore, we can say, P(8 ≤ X ≤ 10) = ∫ f(x) dx over 8 to 10= ∫0 dx over 8 to 10= 0
Thus, P(8, 3 < X < 9) = P(X ≤ 9) - P(X ≤ 3)P(3 < X < 9) = 0 - 0 = 0
Hence, the correct answer is 0.5. Thus, we have P(8, 3 < X < 9) = 0.5. So, option (D) is correct.
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what is the range of the function y=3x-2 if the domain is {0,1,2}
Answer: 2
Step-by-step explanation:
Owen has enough materials to build up to 10 birdhouses in shop class. each birdhouse needs 12 square feet of wood. the function w(b) = 12b represents the total amount of wood that owen would need to build b birdhouses. what domain and range are reasonable for the function?
Domain of the function is \(0\leq b\leq 10\) and range of the function is \(0\leq W\leq 120\).
What is domain and range of a function?The range of values that we are permitted to enter into our function is known as the domain of a function.
A function's range is the collection of values it can take as input.
Each birdhouse uses 12 square feet of wood. Owen has enough to build 10 birdhouses, so he has 120 square feet of wood.
The function has an input of the number of birdhouses, b, and W as an output of the amount of wood needed. b is domain, and W is the range. The domain is 0 to 10 and range is 0 to 120.
Therefore, the domain of the function is \(0\leq b\leq 10\) and the range of the function is \(0\leq W\leq 120\).
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Remember
to estimate first
by rounding and multiplying
to find where the first digit
goes in the quotient.
1. 1,593/13
Answer:
Step-by-step explanation:
1593/13
122.538
answer: 122.5
A 22-year old college student sets up an IRA (individual retirement account) with an APR of 6%. They deposit $55 into the account each month and plan on retiring at age 65. (Simplify your answers and round to two decimal places.) a. The IRA will contain at retirement.
The IRA (individual retirement account) of a 22-year-old college student, who deposits $55 into the account each month, will have a total balance at retirement. To calculate this, we need to consider the time period, the monthly deposit, and the annual percentage rate (APR).
The student plans on retiring at age 65, which means the IRA will have 65 - 22 = 43 years to grow. Since the student deposits $55 each month, we can calculate the total number of deposits over the 43-year period: 43 years * 12 months/year = 516 deposits.
To calculate the total balance at retirement, we need to consider the growth of the account due to the APR. The annual growth rate is 6%, which can be expressed as 0.06 in decimal form. To calculate the monthly growth rate, we divide the annual growth rate by 12: 0.06/12 = 0.005.
Using the formula for the future value of an ordinary annuity, we can calculate the total balance at retirement:
FV = PMT * [(1 + r)^n - 1] / r
Where:
FV = future value (total balance at retirement)
PMT = monthly deposit ($55)
r = monthly interest rate (0.005)
n = number of deposits (516)
Plugging in these values into the formula:
FV = 55 * [(1 + 0.005)^516 - 1] / 0.005
Calculating this equation, the IRA will contain $287,740.73 at retirement.
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Solve for x
(X^2-5x)=(9x-12)
Answer:
x = 13.08 or 0.917
Step-by-step explanation:
\(x^{2} -5x=9x-12\)
First, subtract 9x by both sides.
\(x^{2} -5x-9x=-12\\x^{2} -14x=-12\)
And now we can use completing square method to solve for x.
\(x^{2} -14x=-12\)
Add (14/2)² to both sides of the equation.
\(x^{2} -14x+(14/2)^{2} =-12+(14/2)^{2} \\\\x^{2} -14x+49=-12+49\\\\x^{2} -14x+49=37\)
Factor the left side of the equation into a perfect square.
\((x-7)^{2} =37\)
Square root both sides of the equation and solve for x.
\(x-7=\±\sqrt{37}\)
Add 7 to both sides.
\(x = \±\sqrt{37} +7\)
Therefore,
x = √37 + 7
x = 13.08
or
x = -√37 + 7
x = 0.917
Find the new dimensions of the figure given at right when it is enlarged by scale factor of 2.5 then find the perimeter and area of the original and enlarge it figure
The perimeter and area of the original are 20 ft and 23.5 square ft and the enlarged figure are50 ft and 146.875 square ft.
What is Geometry?It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
The figure is the combination of a triangle and a square.
The area of the original (A₀) figure will be
\(\rm A_o = \dfrac{1}{2} \times 3 \times 5 + 4 \times 4\\\\A_o = 23.5 \ ft^2\)
The perimeter of the original figure (P₀) will be
\(\rm P_o = 3 + 5 + 4 + 4 + 4\\\\P_o = 20 \ ft\)
The scale factor is 2.5.
Then the dimension of the triangle will be
h = 2.5 × 3 = 7.5 ft
b = 2.5 × 5 = 12.5 ft
Then the dimension of the square will be
a = 2.5 × 4
a = 10 ft
The area of the new figure will be
\(\rm A = \dfrac{1}{2} \times 7.5\times 12.5 + 10*10\\\\ A = 146.875 \ ft^2\)
The perimeter of the new figure will be
\(\rm P= 7.5 + 12.5 + 10+ 10+ 10\\\\P = 50 \ ft\)
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Answer:
To find the perimeter of an enlarged figure, you can multiply the original figure’s perimeter by the scale factor. You could also multiply each dimension of the original figure by the scale factor to find the dimensions of the enlarged figure, and then add to find the perimeter.
what does Csc²x equal to?
A- 1
B- 1 + sec²x
C- 1 / sin²x
D- 1-cos x
Answer:
C - 1 / sin^2x
Step-by-step explanation:
as csc x = 1 / sin x
so, csc^2 x = 1 / sin^ 2x
Identify two factors that have a product of 1 7/8 so to factors that you multiply to get 1 7/8
Please help me solve this triangle so I know I’m doing it right.
Let the given sides be,
x=7
y=11
z=6
To find:
\(\angle X,\angle Y,\angle Z\)Using the formula,
\(\cos X=\frac{y^2+z^2-x^2}{2yz}\)On substitution we get,
\(\begin{gathered} \cos X=\frac{11^2+6^2-7^2}{2(11)(6)} \\ \cos X=\frac{121+36-49^{}}{132} \\ \cos X=0.81818 \\ X=\cos ^{-1}(0.81818) \\ X=35.1^{\circ} \end{gathered}\)Hence, the ange of X is,
\(\angle X=35.1^{\circ}\)Next, we need to find the angle of y:
Using the formula,
\(\cos Y=\frac{x^2+z^2-y^2}{2xz}\)On substitution we get,
\(\begin{gathered} \cos Y=\frac{7^2+6^2-11^2}{2(7)(6)} \\ \cos Y=\frac{49+36-121^{}}{84} \\ \cos Y=-0.42857 \\ Y=\cos ^{-1}(-0.42857) \\ Y=115.4^{\circ} \end{gathered}\)Hence, the ange of Y is,
\(\angle Y=115.4^{\circ}\)Next, we need to find the angle of Z:
Using the formula,
\(\cos Z=\frac{x^2+y^2-z^2}{2xy}\)On substitution we get,
\(\begin{gathered} \cos Z=\frac{7^2+11^2-6^2}{2(7)(11)} \\ \cos Z=\frac{49+121-36^{}}{154} \\ \cos Z=0.87012 \\ Z=\cos ^{-1}(0.87012) \\ Z=29.5^{\circ} \end{gathered}\)Hence, the ange of Z is,
\(\angle Z=29.5^{\circ}\)I really need help!!
Answer:
the answer is c you welcome
solve the questio given in the image
Solving a system of equations, we can see that the rational number is 7/15.
How to find the rational number?Let's define the variables:
x = numerator.
y = denominator.
First, we know that the denominator is greater than the numerator by 8, so:
y = x+ 8.
Then we also can write:
(x + 17)/(y + 1) = 3/2
So we have a system of equations, we can rewrite the second equation to get:
(x + 17) = (3/2)*(y + 1)
x + 17 = (3/2)*y + 3/2
Now we can replace the first equation here, we will get:
x + 17 = (3/2)*(x + 8) + 3/2
x + 17 = (3/2)*x + 12 + 3/2
17 - 12 - 3/2 = (3/2)*x - x
5 - 3/2 = (1/2)*x
2*(5 - 3/2) = x
10 - 3 = x
7 = x
then the denominator is:
y = x + 8 = 7 + 8 = 15
The rational number is 7/15.
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20. Which formula would you use to calculate the floor space of Firm 3's structure? Explain your choice. (Refer to the Formula table on page 3.) (2 points: 1 point for the formula, 1 point for the explanation)
The formula would you use to calculate the floor space of Firm 3's structure is πr²h.
How to depict the formula?It should be noted that the formula that can be used on this scenario will be:
= πr²h
where,
h = 60
r = 70/2 = 35
The volume will be:
= πr²h
= 3.14 × 35² × 60
= 230790 feet ³
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Given f(x)=x5−4x3+10, find the x-coordinates of all local minima using the second derivative test. If there are multiple values, give them separated by commas. Calculate If there are no local minima, enter ∅.
There are two local minima which are: x = sqrt(12/5), x = -sqrt(12/5)
To find the x-coordinates of all local minima using the second derivative test;
1. Find the first derivative of f(x): f'(x)
2. Set f'(x) to 0 and solve for x to find critical points
3. Find the second derivative of f(x): f''(x)
4. Evaluate f''(x) at the critical points
5. If f''(x) > 0 at a critical point, it is a local minimum
Find the first derivative of f(x) = x^5 - 4x³ + 10:
f'(x) = 5x^4 - 12x²
Set f'(x) to 0 and solve for x:
0 = 5x^4 - 12x²
x² (5x² - 12) = 0
Solutions: x = 0, x = sqrt(12/5), x = -sqrt(12/5)
Find the second derivative of f(x):
f''(x) = 20x³ - 24x
Evaluate f''(x) at the critical points:
f''(0) = 0
f''(sqrt(12/5)) = 20(sqrt(12/5))³ - 24(sqrt(12/5))
f''(-sqrt(12/5)) = -20(sqrt(12/5))³ - 24(-sqrt(12/5))
Determine if the critical points are local minima:
f''(0) = 0, inconclusive
f''(sqrt(12/5)) > 0, local minimum
f''(-sqrt(12/5)) > 0, local minimum
So, there are two local minima: x = sqrt(12/5), x = -sqrt(12/5)
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HELP ASAP!!!!!!!
What is the width of a rectangle if the area is 2x^2-x-6 and the length is 2x+3?
how would your conclusion change if your sample mean had been 1.355 mg/l? what point does this make about statistical significance?
A small change in x can change the conclusion of our test.
Given :
how would your conclusion change if your sample mean had been 1.355 mg/l.
t - test :
A t-test is a statistical test that compares the means of two samples. It is used in hypothesis testing, with a null hypothesis that the difference in group means is zero and an alternate hypothesis that the difference in group means is different from zero.
if x = 1.355
t = 1.355 - 1.3 / 0.18 / \(\sqrt{30}\)
= 0.055 / 0.18 / \(\sqrt{30}\)
= 0.055 * \(\sqrt{30}\) / 0.18
= 1.67
df = n - 1
= 30 - 1
= 29
P - value from t table :
p = 0.525
fail to reject \(H_0\)
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Full question :
The Environmental Protection Agency has determined that safe drinking water should contain no more than 1.3 mg/liter of copper. You are testing water from a new source, and take 30 water samples. The mean copper content in your samples is 1.36 mg/l and the standard deviation is 0.18 mg/l. There do not appear to be any outliers in your data .
how would your conclusion change if your sample mean had been 1.355 mg/l? what point does this make about statistical significance?
Need help on this question asap please sorry
Answer:
D
Step-by-step explanation:
In picture
Brainliest please ~
Answer:
The answer is most likely the last option.
Step-by-step explanation:
While the 2 triangles have different orientations, the two triangles are similar to one another. From my perspective, the scale would most likely be:
\( \frac{ab}{de} = \frac{bc}{ef} = \frac{ca}{fd} \)
Note that the fractions can be flipped the other way around too.
\( \frac{de}{ab} = \frac{ef}{bc} = \frac{fd}{ca} \)
Now, I can add in the values into the equation
This will give the answer
\( \frac{15}{22.5} = \frac{18.75}{bc} = \frac{fd}{ca} \)
We are only looking at the first 2 fractions which were given, and the final option is the answer.
State if the given binomial is a factor of the given polynomial
Answer:
B - yes
Step-by-step explanation:
If (n - 9) is a factor then when evaluated at n = 9, if the result is zero then it is a factor of the polynomial, that is
9³ + 9² - 84(9) - 54
= 729 + 81 - 756 - 54
= 0
Since the result is zero then (n - 9) is a factor of the polynomial
Find the measure of the indicated angle to the nearest degree
Answer:
61.92°
Step-by-step explanation:
Sine Inverse of (75/85)
=61.92°
Here are 5 lines on a coordinate grid:Wrire equations for lines a,b,c,d and e a:b:c:d:e:
equation A
we have that
Its a vertical line
x=-4
equation B
Its a vertical line
x=4
equation C
Its a horizontal line
y=4
equation D
Its a horizontal line
y=-2
equation E
we need tow points to calculate the slope
we have the points (-4,4) and (4,-2)
the slope is equal to
m=(-2-4)/(4+4)
m=-6/8
m=-3/4
Find the equation of the line in slope intercept form
y=mx+b
we have
m=-3/4
point (4,-2)
substitute
-2=(-3/4)*(4)+b
solve for b
-2=-3+b
b=1
the equation is
y=(-3/4)x+1
BE
BB
What is the radius of a circle whose equation is (x + 5)2 + (y - 3)2 = 42?
2 units
4 units
8 units
16 units
Answer:
4
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
During a walk, walkers discover a car that has fallen to the bottom of a 20m high vertical cliff. It is 10m from the foot of the cliff. The police investigation reveals that the braking marks (perpendicular to the edge) start at 7.5m from the upper (horizontal) edge of the cliff and that the acceleration (braking!) was -5m/s. The chief sergeant concludes an accident. Calculate the speed of the car before the start of braking and the duration of the driver's anxiety (braking & fall).After the calculation, I got t1 from cliff = 2 sec, I got the Vf from the baking = 5m/s, I need to find V0 before baking (using this formula = d=v0t+1/2at^2),
Given, Height of the cliff = 20 m Distance of the car from the foot of the cliff = 10 m.
The time taken by the car to fall from the cliff can be found using the formula:
\(`h = (1/2) g t^2`\)
Where h is the height of the cliff, g is the acceleration due to gravity and t is the time taken by the car to fall from the cliff.
Substituting the given values,`20 = (1/2) × 9.8 × t^2`
Solving for t, `t = sqrt(20/4.9)` = 2.02 s
Let the initial velocity of the car be V0 and the time taken for the car to come to rest after applying brakes be t1.
Distance covered by the car before coming to rest can be found using the formula: `\(s = V0t1 + (1/2) (-5) t1^2\)`
Where s is the distance covered by the car before coming to rest.
Simplifying the above equation,\(`2.5 = V0 t1 - (5/2) t1^2`\)
Substituting the given values,`5 = V0 - 5 t1`
Solving the above two equations,\(`V0 = 32.5/2 t1`\)
Simplifying the above equation,`V0 = 16.25 t1`
Substituting the value o\(f t1,`V0 = 16.25 × 2` = 32.5 m/s\)
Therefore, the speed of the car before the start of braking is 32.5 m/s.
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The mean number of goals a netball team scores
per match in the first 9 matches of a competition
is 4.
a) How many goals does the team score in total in
the first 9 matches of the competition?
b) If the team scores 3 goals in their next match,
what would their mean number of goals after 10
matches be?
The goals does the team score in total in the first 9 matches of the competition is 36 and their mean number of goals after 10 matches is 3.9.
What is the total goals scored by the team in 9 matches ?Given that the mean number of goals a netball team scores per match in the first 9 matches of a competition is 4.
Thus the average of the goals in 9 matches is 4.
Total number of goals is = 9*4 = 36 goals .
What is the mean number of goals after 10 matches ?Given that the team scores 3 goals in their next match .
Thus the total number of goals scored in 10 matches is 36 + 3 = 39 goals,
Required mean = Total goals / 10 matches .
∴ Required mean = 39/10 = 3.9 .
Therefore, the goals does the team score in total in the first 9 matches of the competition is 36 and their mean number of goals after 10 matches is 3.9.
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Please help!!!! With 8 and 9
Answer:
8. slope: = 1/2
9. equation: y=1/2x
PLease help!! I will give brainliest for the right answer!!
Answer:
angle CDE is 10 degree
Step-by-step explanation:
As angle C is 90
Angle E is equal to angle B which is 80 (180-100)
so 90+80+X=180
X=180-170
X=10
the bilateral and unilateral laplace transforms for the signal x(t) = e −tδ(t)e −2tu(t). (2 pts)
The bilateral and unilateral Laplace transforms for the signal x(t) = e^(-t)δ(t)e^(-2tu(t)) are as follows:
Bilateral Laplace Transform: X(s) = 1/(s + 1)(s + 2)
Unilateral Laplace Transform: X(s) = 1/(s + 1), Re(s) > -1
To find the bilateral and unilateral Laplace transforms of the given signal, we apply the definitions and properties of Laplace transforms.
The bilateral Laplace transform is used when the signal x(t) is defined for both positive and negative values of t. For the given signal, x(t) = e^(-t)δ(t)e^(-2tu(t)), where e^(-t) represents the decay factor, δ(t) is the Dirac delta function, and e^(-2tu(t)) represents the unit step function.
Using the properties of Laplace transforms, we can separate the terms and find the individual transforms. The Laplace transform of e^(-t)δ(t) is 1/(s + 1), and the Laplace transform of e^(-2tu(t)) is 1/(s + 2).
Thus, the bilateral Laplace transform of x(t) is given by:
X(s) = 1/(s + 1)(s + 2)
On the other hand, the unilateral Laplace transform is used when the signal x(t) is defined only for t ≥ 0. In this case, we consider the Laplace transform of e^(-t)δ(t)e^(-2tu(t)) with the restriction Re(s) > -1.
Therefore, the unilateral Laplace transform of x(t) is:
X(s) = 1/(s + 1), Re(s) > -1
The bilateral Laplace transform of x(t) = e^(-t)δ(t)e^(-2tu(t)) is X(s)
= 1/(s + 1)(s + 2), while the unilateral Laplace transform is X(s) = 1/(s + 1), Re(s) > -1. These transforms allow us to represent the signal x(t) in the frequency domain and facilitate analysis and calculations involving the signal in the Laplace domain.
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to calculate mad and summing up the forecasts errors, the value used for ||18−20|| in the calculation is? multiple choice question. either 2 or -2 2 -2 cannot be computed
The sum of forecast errors is also known as total forecast error. Therefore, the correct answer is option A, which is "2."
The absolute error of the given data is calculated by subtracting the actual value from the forecasted value, followed by the absolute value.
The errors are then summed up to get the mean absolute deviation. The value used for ||18−20|| in the calculation of MAD and summing up the forecast errors is 2.
Therefore, the correct answer is option A, which is "2."Formula for calculating MAD:MAD = Σ ( | A_i - F_i | ) / n
Where: MAD is the mean absolute deviation|A_i - F_i| represents the absolute error between the actual value (A) and the forecasted value (F)n is the total number of observations, Sum of forecast errors:Σ ( A_i - F_i )Where: A_i is the actual valueF_i is the forecasted value
The sum of forecast errors is also known as total forecast error.
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