is C5H10 ionic or covalent?

Answers

Answer 1
Covalent because it is 5 and 10 so there even numbers I think
Answer 2
covalent. there is 5 c-c bonds 2 hydrogen atoms attach to each. total # of bonds is 15

Related Questions

How many grams of hydrogen are in 6.0g of sucrose?

Answers

Answer:

The formula for sucrose is

C12H22O11

moles sucrose = mass / molar mass  

= 6.0 g / 342.30 g/mol

= 0.017528 mol

the formula shows that each sucrose molecule has 22 H atoms

so moles H = 22 x moles sucrose

= 0.3856 mol

mass H = molar mass x moles

= 1.008 g/mol x 0.3856 mol

= 0.3887 g

= 0.39 g ( 2 sig figs)

The rotational spectrum of 79BrºF shows a series of equidistant lines spaced 0-714 33 cm - apart. Calculate the rotational constant B, and hence the moment of inertia and bond length of the molecule. Determine the wavenumber of the J = 9+= 10 transition, and find which transition gives rise to the most intense spectral line at room temperature (say 300 K).
and calculate the number of revolutions per second which the Brf molecule undergoes when in (a) the J = 0 state, (b) the J = 1 state, and (c) the J = 10 state. Hint: Use E = {lwin conjunction with Eqs (2.10) and (2.13), but remember that here w is in radians per second.[its Q season 2 from fundamentals of molcular spectruscopy . banwell.c.n]​

Answers

In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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Determine if the following salt is neutral, acidic or basic. If acidic or basic, write the appropriate equilibrium equation for the acid or base that exists when the salt is dissolved in aqueous solution. If neutral, simply write only NR.
HONH₃NO₃
KC₃H₅O₃

Answers

HONH₃NO₃ is acidic in nature and KC₃H₅O₃ is basic in nature.

What are pHs of acidic and basic?

The pH scale really measures the concentration of free hydrogen and hydroxyl ions in water.

The difference between an acid and a base in chemistry is that an acid has a higher pH than a base. There are numerous varieties of acids, as well as vinegar. The word "acid," which was originally used to refer to something with a vinegar taste, comes from the Latin adjective "acidus," which meaning "sour or harsh."

1.This salt is produced by the reaction of hydroxylamine and nitric acid.

HN₂OH + HNO₃ → OHNH₃×NO₃⁻

Since HNO₃ is a potent acid and HN₂OH is a weak base, a solution of the salt will be acidic.

The equilibrium would be:

OHNH₃⁺ + H₂O ↔ H₃O⁺ + OHNH₂

The equilibrium equation would be:

Keq = [H₃O⁺][OHNH₂] / [OHNH₃⁺]

2.Basic equilibrium equation is

2 Cu(C₃H₃O₃)₃+4 KI = 4 KC₃H₃O₃+ 2 CUI

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13. What is the acid ionization reaction for HNO3?

A. 2HNO3 ↔ H2 + N2 + 2O3
B. HNO3 ↔ H+ + NO3
C. HNO3 (aq) ↔ H+ (aq) + NO3 (aq)
D. HNO3 (aq) ↔ H+ (aq) + NO3– (aq)
E. None of the Above

Answers

Explanation:

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Hydrochloric acid and oxygen gas form water and chlorine gas. How many moles of oxygen are required to produce 4.59 moles of chlorine gas.

Answers

Answer:

2.295 moles of O2 are needed.

Explanation:

1st) It is necessary to write and balance the chemical reaction:

\(4HCl+O_2\rightarrow2H_2O+2Cl_2\)

2nd) From the balanced reaction we can see that to produce 2 moles of chlorine gas (Cl2), 1 mole of oxygen gas (O2) is needed. So, with a mathematical rule of three we can calculate the amount of oxygen gas moles needed to produce 4.59 moles of Cl2:

\(\begin{gathered} 2\text{ moles Cl}_2-1\text{ mole O}_2 \\ 4.59\text{ moles Cl}_2-x=\frac{4.59\text{ moles Cl}_2*1\text{ mole O}_2}{2\text{ moles Cl}_2} \\ x=2.295\text{ moles O}_2 \end{gathered}\)

Finally, 2.295 moles of O2 are needed

How many grams of carbon dioxide (CO2) are produced from the combustion of 13.00 g of CH4?

Answers

Answer:

35.68g CO2

Explanation:

we use the combustion equation with CH4:

CH4+ O2= CO2 + H2O

And then balance it:

CH4+ 2O2= CO2 + 2H2O

Using this equation we can use sociometry:

\(13g CH4*\frac{1molCH4}{16.032gCH4} *\frac{1mol CO2}{1molCH4} *\frac{44g CO2}{1mol CO2}=35.68g CO2\)

We know that  16.032 is how many grams there are in one mole of CH4 by adding the weights of the atoms (12 +1.008+1.008+1.008+1.008). These weights can be found on the periodic table. The same goes for the amount of grams per CO2.

The important thing about sociometry is to make sure your units cancel out until you are only left with the unit you want. If grams of CH4 is in the numerator, the next fraction you multiply by should have grams of Ch4 in the denominator. If moles of CO2 are in the numerator, the next fraction should have moles of CO2 in the denominator.  

name the main form of energy released by the reaction between hydrogen and oxygen inside a combustion engine

Answers

Answer:

When molecular hydrogen (H2) and oxygen (O2) are combined and allowed to react together, energy is released and the molecules of hydrogen and oxygen can combine to form either water or hydrogen peroxide . These two processes are represented by the two chemical equations shown at right.

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Which type of biochemical is shown in this illustration?


carbohydrate

nucleic acid

lipid

protein

Which type of biochemical is shown in this illustration?carbohydratenucleic acidlipidprotein

Answers

Option b is the correct answer. Nucleic acid is a type of biochemical is shown in this illustration.

The representation gave is an improved on variant of the design of a nucleotide, which is a structure block of nucleic acids like DNA and RNA. The nucleotide comprises of three parts: a sugar particle (displayed in the representation as CH2OH), a nitrogenous base (not displayed in this delineation), and a phosphate bunch (displayed in the representation as - O-P=O). The phosphate bunch is adversely charged and can shape hydrogen bonds with different nucleotides to make the foundation of the nucleic corrosive strand. The plan of nucleotides and the arrangement of the nitrogenous bases decide the hereditary code and capability of the nucleic corrosive.

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Why does an increased temperature cause a reaction to occur slower? A. The increased temperature makes the molecules more resistant to sucessful collision, they bounce off of each other more often. B. The increased kinetic energy causes the particles to move faster, causing more collisions. C. It does not. The increased temperature causes the reaction to occur more quickly. D. The increased potential energy in the particles means more energy is needed from the environment for the activation energy.

Answers

An increased temperature generally causes a reaction to occur faster rather than slower. Therefore option C is correct.

The increased temperature leads to a higher average kinetic energy of the molecules, which results in more frequent and energetic collisions between the reactant particles.

This increased collision frequency and energy facilitate the breaking of chemical bonds and the formation of new bonds, leading to an accelerated reaction rate.

When the temperature is raised, the kinetic energy of the molecules increases. This means that the individual molecules move faster and possess a greater amount of energy. As a result, the molecules collide more frequently and with higher energy, enhancing the likelihood of successful collisions that lead to a reaction.

In summary, an increased temperature leads to a faster reaction rate by increasing the average kinetic energy of the particles, causing more frequent and energetic collisions.

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In each of the following reactions identify an acid (if there is one) and then specify whether it is
an acid according to the Arrhenius definitions or the Bronsted-Lowry definitions or both.
a) H2CO3 + CN- HCN + HCO3-
b) F- + HSO4- HF + SO42-
c) HSO4- + H2O H3O+ + SO42-

Answers

a) In the reaction \(H_2CO_3 + CN^- = HCN + HCO^{3-}\), \(H_2CO_3\) acts as an acid by donating a proton (\(H^+\)) to \(CN^-\).

b) In the reaction \(F^- + HSO_4^{-} = HF + SO_4^{2-}\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(F^-\).

c) In the reaction \(HSO_4^- + H_2O = H_3O^+ + SO_4^{2-\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(H_2O\).

a) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

b) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

c) The acid is a Bronsted-Lowry acid (donates a proton to a base) but not an Arrhenius acid because it does not produce \(H^+\) ions in water. However, the \(H_3O^+\) ion that is formed can be considered an Arrhenius acid because it produces \(H^+\) ions in water.

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PLEASE HELP ME WITH THE QUESTION IN THE IMAGE BELOW I WILL MAKE YOU BRAINLIEST AND GIVE YOU 17 POINTS!

PLEASE HELP ME WITH THE QUESTION IN THE IMAGE BELOW I WILL MAKE YOU BRAINLIEST AND GIVE YOU 17 POINTS!

Answers

Answer:

The sound playing from the first graph is louder, while the sound from the second graph is deeper, both of which have the same pitch.

Explanation:

First let's analyze the graphs,
Comparing the first graph to the second

It has a higher amplitude, so it should be relatively louder They both have the smaller wavelength, so they have the same number of cycles per second, which means the same frequency and the same pitch

Concluding from the above observations, the sound playing from the first graph is louder, while the sound from the second graph is deeper, both of which have the same pitch.

Vitamin C contains the elements C, H, and O. It is known to contain 40.9% C and 4.58% H by mass. The molar mass of vitamin C has been found to be about 180 g/mol. The molecular formula for vitamin C is _________

Answers

Answer:

C₆H₈O₆

Explanation:

First off, the percent of oxygen by mass of vitamin C is:

100 - (40.9+4.58) = 54.52 %

Assume we have one mol of vitamin C. Then we would have 180 grams, of which:

180 * 40.9/100 = 73.62 grams are of Carbon180 * 4.58/100 = 8.224 grams are of Hydrogen180 * 54.52/100 = 98.136 grams are of Oxygen

Now we convert each of those masses to moles, using the elements' respective atomic mass:

C ⇒ 73.62 g ÷ 12 g/mol = 6.135 mol C ≅ 6 mol CH ⇒ 8.224 g ÷ 1 g/mol = 8.224 mol H ≅ 8 mol HO ⇒ 98.136 g ÷ 16 g/mol = 6.134 mol O ≅ 6 mol O

So the molecular formula for vitamin C is C₆H₈O₆

2.(a) Draw the structural formula of octan-1-ol (C8H17OH). (b)What class of organic molecule is octan-1-ol? Explain your reasoning. (Classes of organic molecules include alkanes, alkenes, alkynes, alcohols, carboxylic acids, aldehydes, ketones, esters, ethers, amines, & amides.)(c)Define the term “isomer”.(d)Draw an isomer of octan-1-ol.

Answers

Explanations

2a) Structural formulas are defined as the way atoms and elements are arranged in a compound.

For octan-1-ol which can also be called octanol with formula C8H17OH, the structural formula is as shown below;

b) The class of organic molecules that octan-1-ol falls in is alkanol or alcohol. This is due to the presence of the -OH group present in the molecule of octan-1-ol

c) Isomers are molecules having the same molecular formula but different structural formulas. For instance, the isomer of butane is n-butane and isobutane.

d) One of the isomers of octan-1-ol is 2-methylheptanol as shown below in the image attached;

2.(a) Draw the structural formula of octan-1-ol (C8H17OH). (b)What class of organic molecule is octan-1-ol?
2.(a) Draw the structural formula of octan-1-ol (C8H17OH). (b)What class of organic molecule is octan-1-ol?

What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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BRAINLIEST!!!!!!!!!


What does the diagram represent?

A) A neutral oxygen atom
B) An oxygen atom with 7 protons
C) An oxygen ion with a +2 charge
D) An oxygen ion with a -2 charge​

BRAINLIEST!!!!!!!!!What does the diagram represent?A) A neutral oxygen atomB) An oxygen atom with 7 protonsC)

Answers

Answer:

an oxygen ion with -2 charge

Explanation:

because a neutral oxygen atom has 8 electrons

and in the first orbit there'll be 2 electrons

and in the second orbit there'll be 6 electrons

but here there are 8 electrons in the outermost orbit and normally there'll be only 6

which means there are extra 2 electrons

and extra electrons means negatively charged

BRAINLIEST!!!!!!!!!What does the diagram represent?A) A neutral oxygen atomB) An oxygen atom with 7 protonsC)

Consider the following reaction: 2N2O5(g) → 4NO2(g) + O2(g) Calculate the volume N2O5 that must decompose completely to produce 9.64 L nitrogen dioxide.​

Answers

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

The given chemical equation is \(2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\) .The volume of \(N_2O_5\) that decomposes completely to form 9.64 L of \(NO_2\) is to be calculated. For this, we can use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a balanced chemical equation.To calculate the volume of \(N_2O_5\) that is needed to produce 9.64 L of \(NO_2\), we will first determine the number of moles of NO2 produced in the reaction. For this, we can use the ideal gas equation, PV = nRT. Here, we have the volume of NO2 and we can assume the pressure and temperature to be constant. Thus, we have PV = nRT, where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature. Substituting the given values in the ideal gas equation, we get,n = PV/RT = (1 atm × 9.64 L)/(0.0821 L atm K-1 mol-1 × 300 K) = 0.404 molFrom the chemical equation, we see that 2 moles of \(N_2O_5\) give 4 moles of \(NO_2\). Thus, 0.404 mol of \(NO_2\) must have been produced from (0.404/2) = 0.202 mol of \(N_2O_5\). Using the ideal gas equation, we can also find the volume of 0.202 mol of \(N_2O_5\) at the given conditions. Thus, V = nRT/P = (0.202 mol × 0.0821 L atm K-1 mol-1 × 300 K)/1 atm = 4.97 L. Thus, the volume of \(N_2O_5\) that must decompose completely to produce 9.64 L nitrogen dioxide is 4.97 L.

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When using PCR to study DNA, primers attach to the exposed base pairs and begin to form double-stranded DNA. What stage of the process does this MOST accurately describe

Answers

The stage that this most accurately describes while using the PCR is the initiation of DNA synthesis, also known as the denaturation stage.

What occurs in the denaturation stage?

In the denaturation stage of Polymerase Chain Reaction (PCR), the double-stranded DNA template is heated to a high temperature to separate the two complementary strands and create single-stranded DNA. The denaturation stage is the first step in the PCR cycle.

In this stage, the heat-stable DNA polymerase denatures the DNA and the primers anneal to the complementary single-stranded template. This marks the beginning of the extension stage, where the DNA polymerase synthesizes new complementary strands along the template DNA.

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other m Ammonium nitrate decomposes to nitrogen(1) oxide and water. 9. Some oxides of nitrogen are atmospheric pollutants. and oxygen. Revision Exercise When compound X is heated, a red-brown gas is evolved and a yellow residue is left on cooling. Name: (i) The red-brown gas. (ii) The ions present in the residue. (ui) Compound X.

Answers

We can determine the following based on the provided information:

Metal nitrate A is a compound that, when heated, transforms into colourless gas, brown gas B, and a metal oxide with a yellowish brown hue. B. C: Colourless petrol C. B: Brown petrol C. D: Compound D, a yellow precipitate produced by the reaction of potassium iodide with an aqueous solution of compound A.

We may deduce that A is probably lead nitrate (Pb(NO3)2) because lead is frequently used in soldering alloys and the metal contained in A is utilised in an alloy for soldering purposes.

Identifications:

Lead nitrate, or Pb(NO3)2,

N2O: Nitrogen dioxide

B: Carbon (CO)

D: PbI2, or lead iodide.

Thus, this can be concluded regarding the given scenario.

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Your question seems incomplete, the probable complete question is:

A metal nitrate A on heating gives a yellowish brown coloured metal oxide along with brown gas B and a colourless gas C. An aqueous solution of A on reaction with potassium iodide forms a yellow precipitate of compound D. Identify A, B, C and D. Also, identify the types of reactions taking place. Metal present in A is used in an alloy which is used for soldering purposes.

assume that a soil has a water content of 40 percent by weight and a bulk density of 1.3g per cubic centimeter. if the soil dries to 20 percent by weight and shrinks by an amount equal to the water loss, calculate the bulk density at 20 percent moisture

Answers

The bulk density at 20 percent moisture, given that the soil dries to 20 percent by weight is 1.4 g/cm³

How do i determine the bulk density?

First, we shall obtain the initial volume of the soil. Details below:

Total mass = 100 gBulk density = 1.3 g/cm³Initial volume of soil =?

Volume = mass / density

Initial volume of soil = 100 / 1.3

Initial volume of soil = 76.93 cm³

Next, we shall obtain the volume after the soil dries to 20 percent by weight. Details below:

We were told that the soil shrinks by an amount equal to the water loss, thus we have

Initial mass of water = 40% = 40 g

Water lost = 20% = 20 g

New mass of water = 40 - 20 = 20 g

Thus,

Volume = Equal value of mass of water lost = 20 cm³

Finally, we shall obtain the bulk density at 20 percent moisture. Details below:

Mass of dry soil = 60 gNew of mass water = 20 gTotal mass = 20 + 60 = 80 gramsInitial volume = 76.93 cm³Volume at 20 percent moisture = 20 cm³New volume = 76.93 - 20 = 56.93 cm³Bulk density at 20 percent moisture =?

Bulk density at 20 percent moisture = Total mass / new volume

Bulk density at 20 percent moisture = 80 /  5.93

Bulk density at 20 percent moisture = 1.4 g/cm³

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You have 85.63 g of CO2, how many molecules of CO2 are in that
container?
Ans:
______X 1024 molecules of CO2

Answers

Explanation:

1.17×10^24 molecules of co2

The following statements are about elements in the Periodic Table.
1 Their atoms have a full outer shell of electrons.
2 They are unstable .
3 They are found in Group
4 They are present in small quantities in the air.
Which statements are correct for the noble gases? *
A) 1, 2 and 3
B) 1, 2 and 4
C) 1,3 and 4
D) 2, 3 and 4 ​

Answers

Answer:

D) 2,3 and 4

Option A is not correct because not all elements in the periodic table have a full outer shell of electrons

why does lead exist in a higher amount in brown algae than plankton?​

Answers

Lead levels in plankton and algae are high, mostly as a result of environmental pollution brought on by human activity. While it is true that some brown algae species have the ability to accumulate heavy metals like lead.

Plankton and algae have high levels of lead, mostly as a result of environmental contamination brought on by human activities including mining, industrial operations, and the burning of fossil fuels.

Due to the fact that plankton and algae take up trace quantities of lead from the surrounding water, their tissues contain greater concentrations of the metal.

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Which of the following is not a base :CaSO4, Al(OH)3, Ca(OH)2, KOH

Answers

Answer:

among these which is not a base is CaSO4

How many moles are in 88 g of propaņe, C3H8.

Answers

Answer:

2 MOLES

Explanation:

FIRSTLY CALCULATE GMM OF PROPANE WHICH IS

(12)*3 + 1*8 = 44 GM

THEN, MOLES= GIVEN MASS/44

WHICH IS 88/44=2 MOLES

9. A 125.0-g sample of metal is heated to 100.0 °C and placed in a calorimeter that contains 250.0 g
of water. The temperature rises from 24.3 °C to 27.2 °C. What is the specific heat capacity of the
metal? Ignore the calorimeter in your analysis.
10. A 750.0-g sample of a metal is heated to 100.0 °C and placed in a calorimeter that contains
1,000.0 grams of water. The temperature starts out at 24.9 °C and ends at 26.5 °C. If the
calorimeter has a heat capacity of 1,101 J/°C, what is the specific heat of the metal?

Answers

9. The specific heat capacity of the metal is approximately 0.47 J/g°C, 10. The specific heat of the metal is approximately 0.52 J/g°C.

9-To determine the specific heat capacity of the metal, we can use the formula:

q = mmetal × cmetal × ΔTmetal + mwater × cwater × ΔTwater

where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

cmetal = q/(mmetal × ΔTmetal)

q = mwater × cwater × ΔTwater = (250.0 g) × (4.184 J/g°C) × (27.2°C - 24.3°C) = 3111.8 J

mmetal = 125.0 g

ΔTmetal = 27.2°C - 100.0°C = -72.8°C

cmetal = 3111.8 J/(125.0 g × -72.8°C) ≈ 0.47 J/g°C

10- To solve for the specific heat of the metal, we need to account for the heat capacity of the calorimeter as well. The heat transferred from the metal to the water is given by:

q = (mmetal × cmetal + Ccalorimeter) × ΔT + mwater × cwater × ΔT

cmetal = (q - Ccalorimeter × ΔT)/(mmetal × ΔT)

q = (1000.0 g) × (4.184 J/g°C) × (26.5°C - 24.9°C) = 1253.44 J

Ccalorimeter = 1101 J/°C

mmetal = 750.0 g

ΔT = 26.5°C - 100.0°C = -73.5°C

cmetal = (1253.44 J - 1101 J/°C × -73.5°C)/(750.0 g × -73.5°C) ≈ 0.52 J/g°C

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Calculate the mass of boron present in 30 g of borax. ​

Answers

the mass of boron present in 30 g of borax is ​1.991×10²⁴

Chemical element boron has the atomic number 5 and the letter B in its symbol. It is an amorphous brown powder and a brittle, black, glossy metalloid in its crystalline form. There may be antioxidant effects of boron. Boron is frequently used to treat vaginal yeast infections and boron insufficiency. Additionally, it is used to treat menstrual cramps, osteoarthritis, osteoporosis, and numerous other ailments, but many of these applications lack strong scientific backing.

Molar mass of B = 10.81g/mol

So, 1 mole of B = 10.81g

and 1 mole = NA= 6.023×10²³

By combining,

10.81g of B = 6.023×10²³ atoms of B thus,

35.76g of B = 6.023×10²³

10.81×35.76

35.76g of B

= 1.991*10²⁴

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what is the chemical reaction that occurred in the leaf disks? write out the reactants and products.

Answers

The chemical reaction that occurred in the leaf disks NaHCO₃ + H⁺⇒ Na + H₂O + CO₂. The reactant is sodium bicarbonate  and the product is water and carbon dioxide.

To measure the net rate of photosynthesis under varying illumination conditions using leaf disks. Normally, leaf disks float; however, when carbon dioxide is introduced into the air gaps, the lead disk's overall density rises, and the leaf disk sinks. The leaf disks sink when sodium bicarbonate is added to the water because the bicarbonate ion serves as a carbon source for photosynthesis.

The process of photosynthesis results in the release of oxygen into the leaf's interior, which alters the buoyancy of the leaf and causes the disk to rise. Because cellular respiration occurs concurrently in the leaf, the oxygen produced by photosynthesis is used up. As a result, the net rate of photosynthesis is indirectly related to the pace at which the disks are rising.

We can investigate the effects of carbon dioxide supplies on the rate of photosynthesis because photosynthesis requires carbon dioxide as well. Water often contains some dissolved oxygen in modest amounts. By boosting the amount of carbon dioxide in the water, sodium bicarbonate or baking soda will make it more readily available to the leaves of our plants.

NaHCO₃ + H⁺⇒ Na + H₂O + CO₂

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what is the chemical reaction that occurred in the leaf disks? write out the reactants and products.

An experiment is repeated five times resulting in five replicate data points. The average deviation of the replicate data point is a measure of:
a Precision
b Accuracy

Answers

Essentially, precision and accuracy are the same thing; they have very alike denotations. However, for this question, the average deviation of the replicate data point is a measure of accuracy.

What is the difference?

The difference between precision and accuracy is very slim, considering they can be used as interchangeable terms for each other. The overlying separation of the definition of accuracy from precision is that accuracy deals more with a point’s exactness in comparison to an initial point. Precision on the contrary is a measure of how closely or far off data is distributed.

In this question, it is mentioned that replicate points (of the initial data points) are created after 5 experiments. Because the replications are being compared to the initial point, a measure of accuracy is being shown.

The average deviation of the replicate data point is a measure of accuracy.

Select the best answer for the question.
10. What's the structure of PF,? Is it polar or non-polar?
O A. Trigonal bipyramidal, non-polar
OB. Square pyramid, polar
O C. Square pyramid, non-polar
O D. Trigonal bipyramidal, polar

Answers

It’s option A trigonal bipyramidal non polar

Which element(s) would you expect to behave similarly to Gadolinium? What properties of would you expect to be the same, what would be different?

Answers

The elements in the lanthanide series are similar to gadolinium.

The periodic table is arranged in groups and periods. Elements in the same group have similar properties. At the bottom row of the periodic table lies a group of elements that have unique properties called the lanthanides. This is where Gadolinium belongs.

The elements in the lanthanide series such as europium and terbium are similar to gadolinium. The lanthanides are similar in chemical reactivity and appearance. However, the density of the metals differ because it increases with increase in atomic number.

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