Is each of the following very soluble in water? Explain.
(b) Glycine, H₂NCH₂COOH

If a substance has a pH greater than 7, it means that the substance is basic or alkaline.

The pH scale measures the acidity or alkalinity of a solution and ranges from 0 to 14.

A pH value greater than 7 indicates that the concentration of hydroxide ions (OH-) in the solution is higher than the concentration of hydrogen ions (H+).

In a basic solution, hydroxide ions are predominant, and it has fewer hydrogen ions.

When a basic substance dissolves in water, it releases hydroxide ions that can accept hydrogen ions, thus reducing the concentration of H+ ions in the solution.

The step-by-step explanation involves the dissociation of water and the presence of hydroxide ions.

In water, a small fraction of water molecules dissociate into hydrogen ions (H+) and hydroxide ions (OH-).

In an alkaline solution, the concentration of hydroxide ions is higher than the concentration of hydrogen ions.

A pH value greater than 7 indicates a basic solution where the concentration of hydroxide ions is relatively higher than hydrogen ions.

This is typically seen in substances like soaps, bleach, baking soda, and ammonia solutions.

These substances can act as bases, neutralize acids, and often have a bitter taste.

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Ca(OH)2 (aq) because of elements oxygen and hydrogen

Ca(OH)2(aq)+H2SO4(aq)—→ CaSO4(s)+ 2H2O(l)

Answer:

your answer is D

Explanation:

Chemical equilibrium can be disturbed by changes in the concentration of one or more substances or by changes in the pressure or temperature.

Chemical equilibrium is a state in a reversible chemical reaction where the forward and backward reaction rates are equal. It is governed by the equilibrium constant, which is determined by the concentrations of the reactants and products. Any changes that affect these concentrations can disturb the equilibrium.

Changes in concentration: Altering the concentration of reactants or products can shift the equilibrium position. Increasing the concentration of a reactant will drive the reaction towards the product side, while increasing the concentration of a product will favor the reactant side. Decreasing the concentration of a species will have the opposite effect.

Changes in pressure: Only applicable to reactions involving gases, changes in pressure can impact equilibrium. According to Le Chatelier's principle, an increase in pressure will shift the equilibrium towards the side with fewer moles of gas, while a decrease in pressure will favor the side with more gas molecules.

Changes in temperature: Altering the temperature affects the equilibrium constant. Endothermic reactions absorb heat, so increasing the temperature will favor the product side, while decreasing the temperature will favor the reactant side. Exothermic reactions release heat, so the opposite temperature effects occur.

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Moving an electron within an electric field would change the potential energy of the electron. This is because the electric field exerts a force on the electron, causing it to move and gain potential energy. However, the mass of the electron remains constant regardless of its location within the electric field.
When an electron is moved within an electric field, its position changes relative to the source of the electric field. This change in position alters the electron's potential energy, while its mass and the amount of charge on it remain constant.

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Answer:

The pressure is doubled, 4.0atm

Explanation:

Based on Boyle's law, the pressure of a gas is inversely proportional to its volume at constant temperature. The equation that describes this law is:

P1V1 = P2V2

Where P is pressure and V volume at 1, initial state and 2, final state of the gas.

Computing the values of the problem:

P1 = 2.0atm

V1 = 3.0L

P2 = ?

V2 = 3.0L / 2 = 1.5L

Replacing:

2.0atm*3.0L = P2*1.5L

6.0atmL / 1.5L = P2

4.0atm = P2

Solution :

Homeostasis of a human body refers to the ability of the body to maintain the stable internal conditions of the changing environment. It help an organism to survive.

The Human Homeostasis Gizmo helps a person to explore and see the human body adapts itself at a nearly constant temperatures in various conditions.

The advantages of the model of the human homeostasis used in the gizmo is that it can explore and predict how the human body maintains its normal condition as to approximation. One of the disadvantage is that it cannot predict the actual conditions for the survival of the organisms that it needs to maintain its body temperature or conditions.

Answer:

there the start of the food chain for little fish and other fish that are bigger and keep the ocean chain moveing. hope this helps?

Pure water has a vapour pressure of 23.76 torr at 25 degrees Celsius.

According to Raoult's law, a solution's vapor pressure varies in direct proportion to the amount of solvent it contains by mole.

Vapor pressure is the force that a vapor applies on the condensed phases (solid or liquid) in a closed system when they are in thermodynamic equilibrium at a particular temperature (or equilibrium vapor pressure).

It is thought that the vapor is exerting pressure on the atmosphere. In other words, the higher the vapor pressure, the faster the evaporation of a liquid.

A liquid's vapor pressure is one of its properties and depends on the strength of its intermolecular forces. Liquids have higher vapor pressure and are easier to evaporate due to weak intermolecular interactions. Lower vapor is produced by a liquid with higher intermolecular interactions.

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The balanced reduction half reaction is:

8H+ + 5e- + \(MnO_4\)- → \(Mn^2\)+ + \(_4H_2O\)

1. Identify the elements undergoing oxidation and reduction in the given reaction:

  - \(MN^2\)+ is being oxidized to \(MN^4\)+.

  - \(H_2SO_3\) is being reduced to \(HNO_2\).

2. Write the half-reactions for each process:

  Oxidation half-reaction: \(MN^2\) + → \(MN^4\) + + 2e-

  Reduction half-reaction: \(H_2SO_3\) + 2H+ + 2e- → \(HNO_2\) + \(H_2O\)

3. Balance the number of atoms in each half-reaction:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_2HNO_2\) + \(_2H_2O\)

4. Balance the number of hydrogen atoms by adding H+ ions to the side lacking hydrogen:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_ 2HNO_2\) + \(_2H_2O\)

5. Balance the number of oxygen atoms by adding H2O molecules to the side lacking oxygen:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- →\(_ 2HNO_2\) + \(_2H_2O\)

6. Balance the charge on both sides of the equation by adding electrons:

  Oxidation half-reaction: \(MN^2\)+ → \(MN^4\)+ + 2e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_2HNO_2\) + \(_2H_2O\)

7. Multiply each half-reaction by the appropriate factor to equalize the number of electrons transferred:

  Oxidation half-reaction: \(2MN^2\)+ → \(2MN^4\)+ + 4e-

  Reduction half-reaction: \(_2H_2SO_3\) + 4H+ + 4e- → \(_2HNO_2\) + \(_2H_2O\)

8. Finally, combine the half-reactions and cancel out any common terms:

  2\(MN^2\)+ + \(_2H_2SO_3\) + 4H+ + 4e- → \(2MN^4\)+ + \(_2HNO_2\) + \(_2H_2O\)

9. Simplify the equation by dividing through by 2:

  \(MN^2\)+ + \(H_2SO_3\) + 2H+ + 2e- → \(MN^4\)+ + \(HNO_2\) + \(H_2O\)

Therefore, the balanced reduction half-reaction is:

8H+ + 5e- + \(MnO_4\)- → \(MN^2\)+ + \(4H_2O\)

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Reducing half-reaction:\(MN^2+ + 4H^+ + 2e^- → MnO2 + 2H2O\)

To write the balanced reduction half-reaction, we need to identify the species that undergoes reduction, which is the one that gains electrons. In this case,\(MN^2+\)is reduced to \(MnO2\).

To balance the reduction half-reaction, we first balance the atoms of all elements except hydrogen and oxygen. Then, we balance the oxygen atoms by adding \(H2O\) to the side that lacks oxygen. Finally, we balance the hydrogen atoms by adding H^+ to the opposite side. We also add electrons to balance the charge. In this case, the balanced reduction half-reaction requires 2 electrons.

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The transition metals are elements with partially filled d subshells. These elements are found in the middle of the periodic table.

Transition metals are elements with partially filled d subshells. These elements are found in the middle of the periodic table, between the alkali and alkaline earth metals on the left and the metalloids and non-metals on the right. The transition metals include elements like iron, copper, silver, and gold. They are known for their ability to form multiple oxidation states, which allows them to participate in a wide range of chemical reactions. The d subshell in transition metals is responsible for these unique properties, and it is partially filled with electrons.

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When a solution of iron(III) nitrate (Fe(NO3)3) is mixed with a solution of sodium hydroxide (NaOH), a rust-colored precipitate is formed. This precipitate is most likely iron(III) hydroxide (Fe(OH)3), also known as ferric hydroxide.

The reaction between iron(III) nitrate and sodium hydroxide can be represented by the following balanced chemical equation:

Fe(NO3)3 + 3NaOH → Fe(OH)3 + 3NaNO3

In this reaction, iron(III) ions (Fe3+) from iron(III) nitrate react with hydroxide ions (OH-) from sodium hydroxide to form iron(III) hydroxide, which is insoluble in water. The rust color of the precipitate is a characteristic color of iron(III) compounds.

Therefore, when iron(III) nitrate is mixed with sodium hydroxide, the formation of a rust-colored precipitate indicates the presence of iron(III) hydroxide (Fe(OH)3).

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Answer:

I think it's (a.crushing waves)

The organisms living in an intertidal zone must have adaptations to deal with crushing waves, dehydration with rising and falling tides, and exposure to air at low tides.

The intertidal zone can be described as the area above water level at low tide and underwater at high tide. This region can include many types of habitats with several species of life, such as sea urchins, seastars, and species of coral with regional differences in biodiversity.

The area can be a narrow strip such as in Pacific islands that have only a narrow tidal range or can include several meters of shoreline where shallow beach slopes interact with the high tidal excursion.

In the intertidal zone, organisms are adapted to an environment of harsh extremes, living in water pressure with high potential. The intertidal zone is home to many species from different phyla.

Water is regularly available with the tides that vary from brackish waters, fresh with rain, to highly saline and dry salt, with drying between tides.

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Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 83.23g of calcium chloride are formed when 15g of calcium metal react with hydrochloric acid.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

mole of calcium=15g/ 20

                         =0.75moles

Ca +2HCl → CaCl\(_2\) + H\(_2\)

thee mole ratio between calcium and calcium chloride is 1:1

mole of calcium chloride=0.75moles

mass of calcium chloride= 0.75moles ×110.983 g/mol.

                                         =83.23g

Therefore, 83.23g of calcium chloride are formed when 15g of calcium metal react with hydrochloric acid.

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Answer:

A molecular compound is usually composed of two or more nonmetal elements. Molecular compounds are named with the first element first and then the second element by using the stem of the element name plus the suffix -ide.

Answer:

120.366 g/mol

Explanation:

MAGNESIUM SULPHATE HEPTAHYDRATE Magnesium sulfate is an inorganic salt containing magnesium, sulfur and oxygen, with the formula MgSO4. Molar mass: 120.366 g/mol

Answer:

sulfur and oxygen, with the formula MgSO4. Molar mass: 120.366 g/mol

Explanation:

Hi its me a another me lol

The GroEL/ES system, a type of chaperonin, functions in an ATP-dependent fashion. It is not limited to thermophilic proteins, low pH conditions, or in vitro environments. Moreover, chaperonins like GroEL/ES operate in an aqueous environment, not a non-aqueous one.

Chaperonins, such as the GroEL/ES system, play a crucial role in protein folding and assembly. They assist in the folding of newly synthesized or denatured proteins, ensuring proper conformation and preventing aggregation. The GroEL/ES system functions through an ATP-dependent mechanism. ATP binding and hydrolysis provide the energy necessary for conformational changes and the release of folded proteins. Unlike some other chaperones that may be specific to thermophilic proteins, the GroEL/ES system is not limited to such proteins. It can assist in the folding of a wide range of substrates. Similarly, chaperonins like GroEL/ES are not confined to low pH conditions. While changes in pH can influence protein stability and folding, chaperonins operate efficiently across a broad pH range. Furthermore, chaperonins function in vivo within the cellular environment, ensuring proper protein folding and preventing misfolding or aggregation. While they can also be studied in vitro, their primary role is to assist in protein folding in living cells. Additionally, chaperonins like GroEL/ES operate in an aqueous environment, as proteins require water for their proper folding and function. Non-aqueous environments are generally unsuitable for protein folding and can disrupt the folding process. In summary, the GroEL/ES system functions in an ATP-dependent manner, assisting in the folding of a diverse range of proteins within the aqueous environment of living cells. It is not limited to thermophilic proteins, low pH conditions, or in vitro studies.

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The proper description of the silicon-oxygen tetrahedron is "a pyramidal shape with four triangular faces, an oxygen ion at each vertex, and a silicon ion at the center of the pyramid."

The silicon-oxygen tetrahedron is the fundamental building block of silicate minerals, which make up most of the Earth's crust. It consists of a central silicon ion bonded to four oxygen ions arranged in a tetrahedral shape. Each oxygen ion shares two electrons with the silicon ion, forming a covalent bond. The resulting structure is a pyramidal shape with four triangular faces, an oxygen ion at each vertex, and a silicon ion at the center of the pyramid. This structure is responsible for the unique physical and chemical properties of silicate minerals.

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Answer:

D.

Explanation:

In a Galvanic cell:

1) Spontaneous reactions take place

2) Chemical Energy is converted to some useful electrical energy

A "cell" might be a better name for the torch battery. A "battery" is a collection of connected cells. Another example of an electric cell is a lemon with two strips of different metals (for instance, zinc & copper) inserted into it. The correct option is B.

A primary cell in a dry-cell battery is one that cannot be recycled. Each dry-cell battery has a cathode and an anode for operation. Remote controls, clocks, and calculators are a few examples of modern-day items that employ dry-cell batteries.

Alkaline and lithium batteries are the two most typical types found in flashlights. A "dry" cell used in a torch has a finite lifespan.

Thus the correct option is B.

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Answer:

Explanation:

Answer: D. Solid

The intensity of the wave is proportional to the square of the amplitude. so it becomes four times larger.

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There are two characteristics of molecules, one is geometry and other is shape. Shape is excluding lone pair surrounding the central element and geometry is including the lone pair. Therefore, the bond angle is less than proper 120°.

VSEPR stands for valence shell electron pair repulsions. VSEPR theory is used to predict the shape and geometry of molecules on the basis of valence electrons pairs that are present around the central element of the molecule.

According to VSEPR theory, Lone pair lone pair repulsion is greater than bond pair bond pair repulsion. There are so many limitations of VSEPR theory. There is a repulsion between bond pair electrons and lone pairs present on the central element.

If the molecular geometry were bent and had only one lone pair of electrons, then the bond angle is less than proper 120° angle due to lone pair and bond pair repulsion according to VSEPR theory.

Therefore, the bond angle is less than proper 120°.

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Answer:

H2 & F2

Explanation:

A covalent bond is formed when an electron is shared between two atoms. The two electrons of the covalent bond are positioned between the nuclei of the both bonding atoms. The electron pair of the bond may be equidistant from the nucleus of the two atoms or nearer to the nucleus of one of the bonding atoms than the other depending on the relative electro negativities of the both bonding atoms.

For homonuclear covalent bonds, there is no electro negativity difference between the bonding atoms. A single line may be used to indicate the shared electron pair between the two atoms.

Hydrogen and fluorine form homonuclear covalent diatomic compounds in which only a single electron pair is shared between bonding atoms. A single covalent bond is found connecting the two bonding atoms, hence the answer.

The percentage yield of the reaction of hydrazine with oxygen to form nitrogen and water is 34% .

The balanced chemical equation for the reaction of hydrazine with oxygen to form nitrogen and water can be written as follows : N2H4 + O2 → N2 + 2H2O

Convert the given mass of N2H4 to moles using the molar mass of N2H4 as follows :

Molar mass of N2H4 = 2(14.006) + 4(1.008) = 32.045 g/mol

Number of moles of N2H4 = Mass/Molar mass = 3.35 g / 32.045 g/mol = 0.1044 mol

According to the balanced chemical equation, 1 mole of N2H4 produces 1 mole of N2. Therefore, the number of moles of N2 produced by 0.1044 mol of N2H4 is also 0.1044 mol.

The ideal gas equation can be used to calculate the volume of the N2 produced : PV = nRT

=> V=nRT/P

Number of moles (n) = 0.1044 mol ; R = Universal gas constant = 0.0821 L atm K^-1 mol^-1 ; T = Temperature = 295 K ;

P = Pressure = 1.00 atm ; V = ?

Substituting the values into the equation, we get :

V = nRT/P = 0.1044 x 0.0821 x 295/1.00 = 2.52 L

The actual yield of the reaction is given as 0.850 L.

Percentage yield = (Actual yield/Theoretical yield) x 100= (0.850/2.52) x 100 = 34%

Therefore, the percentage yield of the reaction of hydrazine with oxygen to form nitrogen and water is 34%.

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The reaction exists as follows:

Reducing Sugar + Benedict's Solution → Brick-red Precipitate + Oxidized Benedict's Solution

A straightforward chemistry test called Benedict's test is performed to find reducing sugars. Carbohydrates known as reducing sugars have a free aldehyde or ketone functional group in their chemical structure. They include both disaccharides like lactose and maltose and monosaccharides like glucose and fructose.

Benedict's solution will react by creating a brick-red precipitate when a sample contains a very high concentration of reducing sugar.

This precipitate's existence signifies a successful test and demonstrates that the sample has a sizable concentration of reducing sugar. The reducing sugar is oxidized in this reaction, which is an example of an oxidation-reduction reaction, and Benedict's solution is reduced.

The reaction exists as follows:

Reducing Sugar + Benedict's Solution → Brick-red Precipitate + Oxidized Benedict's Solution

Therefore, the correct answer is option b. Brick-red precipitate is formed.

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The reaction exists as follows:

Reducing Sugar + Benedict's Solution → Brick-red Precipitate + Oxidized Benedict's Solution

To identify reducing sugars, a simple chemistry test known as Benedict's test is used. The chemical structure of the carbohydrates referred to as reducing sugars contains a free aldehyde or ketone functional group. They consist of monosaccharides like glucose and fructose as well as disaccharides like lactose and maltose.

When a sample has a very high concentration of reducing sugar, Benedict's solution will react and produce a brick-red precipitate.

The presence of this precipitate indicates that the test was successful and shows that the sample contains a significant amount of reducing sugar. In this reaction, which is an illustration of an oxidation-reduction reaction, the reducing sugar is oxidised and Benedict's solution is reduced.

Reducing Sugar + Benedict's Solution → Brick-red Precipitate + Oxidized Benedict's Solution

Therefore, the correct answer is option b. Brick-red precipitate is formed.

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The concentration of the HCI solution : 0.767 M

Reaction

Na₂CO₃ (aq) + 2 HCl (aq) → 2 NaCl (aq) + CO₂ (g) + H₂O (l)

mass of CO₂ = 11.1 g

mol of CO₂ (MW= 44,01 g/mol) :

\(\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{11.1}{ 44,01}\\\\mol=0.252\)

From the equation above, mol ratio of HCl : CO₂ = 2 : 1, so mol HCl :

\(\tt mol~HCl=\dfrac{2}{1}\times 0.252=0.504\)

Molarity shows the number of moles of solute in every 1 liter of solution.

\(\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}\)

The molarity of unknown HCl :

mol=n=0.504

volume=V=657 ml=0.657 L

\(\tt M=\dfrac{0.504}{0.657}\\\\M=0.767\)