_____ is the element from which iron is taken.

Carbon
Quartz
Hematite

Answer:

107.8682U is the molar mass of ag

The final temperature of the dinitrogen monoxide gas is  282.5 K.

According to Charles' law, an ideal gas's volume will change at constant pressure by the same amount that its temperature changes on the absolute temperature scale (measured in kelvins).

The volume of a gas is directly proportional to its absolute temperature when the pressure and the amount of gas are kept constant.

By the use of the Charles law;

V1/T1 = V2/T2

V2T1 = V1T2

T2 = V2T1/V1

= 69.77 * 319.84/ 78.982

= 282.5 K

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Answer:

Nothing is happening.

Explanation:

As written, nothing is going on.  H2+O2+H2O represents a mixture of H2, O2, and H2O.  We aren't even given the states, so they may all be gases, liquids/solids, or dissolved gases in a liquid (water).

If we had H2+O2 → H2O, we could say that hydrogen and oxygen are combining to form H2O, water.  We should note, however, that the chemical equation is not balanced.  There are two oxygen atoms on the reactant side, but only one on the product side.  A balanced equation would read:

2H2 + O2 → 2H2O

It would be nice to indicate the physical states, such as:

2H2(g) + O2(g) → 2H2O(l)

Two gases, oxygen and hydrogen, combine to form liquid water.

Also missing from this equation is the energy that may be consumed, or released in this reaction. It would be nice to know, for example, that this reaction releases a lot of energy.  Otherwise, we might wind up in the local headlines.

Answer:

Magnesium I’m pretty sure

Explanation:

Answer:

taxonomy

Explanation:

Answer:

Taxonomy

Explanation:

The taxonometric way of classifying organisms is based on similarities between different organisms. A biologist named Carolus Linnaeus started this naming system. He also chose to use Latin words.

Three significant figures, the caloric value of the potato chips is approximately 54.9 kcal/g.

To determine the caloric value of the potato chips, we need to calculate the amount of heat transferred from the burning process to the water. The formula to calculate heat transfer is:

q = m * c * ΔT

where:

q is the heat transferred,

m is the mass of the water,

c is the specific heat capacity of water,

ΔT is the change in temperature.

Given:

m (mass of water) = 34.3 g

c (specific heat capacity of water) = 1 cal/g°C

ΔT (change in temperature) = 20.1°C - 16.1°C = 4°C

Substituting these values into the formula, we have:

q = 34.3 g * 1 cal/g°C * 4°C = 137.2 cal

Since 1 kcal = 1000 cal, the caloric value of the potato chips can be calculated as:

Caloric value = q (heat transferred) / mass of potato chips

Assuming complete combustion, the heat transferred is equal to the caloric value of the potato chips. Therefore:

Caloric value = 137.2 cal / 2.5 g = 54.88 kcal/g

Rounding to three significant figures, the caloric value of the potato chips is approximately 54.9 kcal/g.

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The theoretical yield of Fe₂O₃ is 0.0059 moles and the percent Yield is 44.2%

Using stoichiometry to calculate the theoretical yield of Fe₂O₃:

From the balanced chemical equation, 4 moles of Fe react with 3 moles of O₂ to produce 2 moles of Fe₂O₃. Therefore, set up the following proportion:

3.4 g O₂ / 32 g/mol O₂ = x mol Fe₂O₃ / (2 mol Fe / 4 mol O₂ x 55.85 g/mol Fe)

Solving for x:

x = 3.4/32 x 4/3 x 1/55.85 x 2 = 0.0059 moles Fe₂O₃

Therefore, the theoretical yield of Fe₂O₃ is 0.0059 moles.

From the balanced chemical equation, 4 moles of Fe react with 3 moles of O₂ to produce 2 moles of Fe₂O₃. Therefore, for every 4 moles of Fe that react, expect to produce 2 moles of Fe₂O₃.

Using this information, set up the following proportion:

4 mol Fe / 55.85 g/mol Fe = 0.0059 mol Fe₂O₃ / x

Solving for x:

x = 55.85 x 0.0059 / 4 = 0.082 g Fe

Therefore, the theoretical yield of Fe is 0.082 g.

To calculate the percent yield, use the following formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

Substituting the values calculated:

Percent Yield = (0.0059 mol Fe₂O₃ / 0.082 g Fe) x 100% x (1.5 moles H₂O / 2 moles Fe₂O₃)

Percent Yield = 44.2%

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Answer:

Q = 52668 J

Explanation:

Given data:

Amount of heat required = ?

Mass of water = 350 g

Initial temperature = 20°C

Final temperature = 56°C

Specific heat capacity of water = 4.18 J/g°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 56°C - 20°C

ΔT = 36°C

Q = 350 g× 4.18 J/g°C ×36°C

Q = 52668 J

The first occasion a Rh-negative patient receives Rh-positive blood, a transfusion reaction does not happen also because Rh-negative patient has not had time to develop antibodies against by the Rh-positive blood.

Some patients can have negative reactions towards the plasma they obtain after a donation, even when the right blood type is used. Some of the symptoms under these circumstances include hives and itching. Like other allergic reactions, this can be managed with medications. However, a professional should be sought if the reaction gets worse.

An acute immune hemolytic event, a very hazardous but unusual occurrence, can occur when the immune system rejects the directly injected red blood cells. The attack causes the discharge of a substance that damages the kidneys.

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The Complete the steps for converting the density of mercury is

13.6 g x  1 Kg    x   10⁶ cm³ = 13600Kg

 cm³     1000g            m³

the method of changing 13.6 g/cm3 to kg/m3

A kilogram is equal to one thousand grams.

Consequently, it may be written as

1 Kg = 1000g

1g =  1kg  

      1000

Therefore, 1 kg will be entered into the first blank (numerator).

Currently, 100 centimeters make up 1 meter.

Thus,

1 m³ = (100)³ cm³

1cm³ = 1m³

          10⁶

so  the second blank (numerator). will be filled with 10⁶

Additionally, the third blank will be filled with 1 m³

And 13600 will be the final blank.

The final equation will look like this:

13.6 g x  1 Kg    x   10⁶ cm³ = 13600Kg

 cm³     1000g            m³

Your question is incomplete but most probably your full question attached below

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Answer:

Shift it to the left toward the reactants

Explanation:

The direction of movement of a reaction at equilibrium has been explained by a man called HENRY LOUIS in his principle. According to this principle, a reaction will shift in response to a stress on equilibrium. The stress can either be effects of temperature, pressure, concentration etc on the reaction equilibrium.

- An addition of a reactant or product will cause the reaction to shift towards the opposite direction of the substance added. For example, in this question, the following reaction was given:

A + B ----> C + D

C is a product, meaning that if more of product C were added to this reaction, the reaction will shift towards the left (reactant side) because there are now more products. In other words, the reactants will be favored if there is an increase in the concentration of the products.

i think it is D

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There are 4.48 × 10-3 moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution if Ksp for AgBr is 3.3 × 10-13 and Kf for the complex ion \([Ag(S_{2}O_{3})_{2}]^{3-}\).

AgBr dissociates in water, and we can write the reaction as shown below:

\(AgBr = Ag^{+} + Br{-}\)

Since \(Ksp = [Ag^{+}][Br^{-}]\), we can obtain the equilibrium concentrations of \(Ag^{+}\) and \(Br^{-}\) from the Ksp value, using the stoichiometry of the balanced equation. Here, the concentration of  \(Br^{-}\)  is equal to that of \(Ag^{+}\).

Therefore, \(Ag^{+}\) =  \(Br^{-}\)  = √Ksp = √3.3 × 10-13 M\(\sqrt{Ksp} = \sqrt{3.3 * 10^{-13}} M\)  \(5.74 * 10^{-7}\) M. To determine the number of moles of \(Na_{2}S_{2}O_{3}\) required to dissolve 0.35 mol of AgBr in a 1.0 L solution, we must calculate the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) ion first.

Kf = \([Ag(S_{2}O_{3})_{2}]^{3-}\)./(\(Ag^{+}\)\([S_{2}O_{3}^{-2}]\))

For \(Ag^{+}\), we use the concentration obtained from Ksp:

\(Ag^{+}\)= \(5.74 * 10^{-7}\) M

Kf =  \(4.7 * 10^{13}\) mol-1L-3

\([Ag(S_{2}O_{3})_{2}]^{3-}\)= Kf × \([Ag(S_{2}O_{3})_{2}]^{3-}\)

=  \(Ag^{+}\)/Kf

\([Ag(S_{2}O_{3})_{2}]^{3-}\)

= (\(5.74 * 10^{-7}\) M)/(\(4.7 * 10^{13}\)  mol-1L-3 × (\(5.74 * 10^{-7}\) M)2)

= \(4.48 * 10^{-3}\) M

To find the number of moles of \(Na_{2}S_{2}O_{3}\) required to dissolve AgBr in 1 L of solution, multiply the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) by the volume of the solution:

\(4.48 * 10^{-3}\)  M × 1 L = \(4.48 * 10^{-3}\) moles \(Na_{2}S_{2}O_{3}\).

\(4.48 * 10^{-3}\) moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution.

We used the stoichiometry of the balanced equation and the Ksp value to determine the concentration of [Ag+] and [Br-]. Then, we calculated the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\). from the Kf value and the [Ag+] value obtained from Ksp.

Finally, we multiplied the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) by the volume of the solution to obtain the number of moles of \(Na_{2}S_{2}O_{3}\) needed to dissolve 0.35 mol of AgBr in a 1.0 L solution.

4.48 × 10-3 moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution if Ksp for AgBr is  \(3.3 * 10^{-13}\) and Kf for the complex ion \([Ag(S_{2}O_{3})_{2}]^{3-}\) is \(4.7 * 10^{13}\)  mol-1L-3.

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Explanation:

Blood Provides the Body's Cells with Oxygen and Removes Carbon Dioxide. Blood absorbs oxygen from air in the lungs. It transports the oxygen to cells throughout the body, and it removes waste carbon dioxide from the cells.

Your blood carries oxygen and nutrients to all of the cells in your body. Blood cells also fight infection and control bleeding.

Answer:

15.5g

Explanation:

"The total mass of both chemicals and the containers they are in is 15.5 g." After a chemical reaction, by conservation of mass, the total mass of the products and the two containers after reaction is the same at 15.5g.

Answer:

15.5

Explanation:

in a chemical reaction, mass is conserved

so mass after reaction = mass before reaction = 15.5 g

Answer:

B - To increase the rate of the reaction

Explanation:

Catalysts speed up the reaction without being reactants or products, so aren't used up in the reaction.

Answer: Troposphere

Explanation:

In the troposphere, as altitude increases in the troposphere, the amount of water vapor decreases.

Answer:

32.73%

Explanation:

To solve this problem, first find the molar mass of Al(OH)₃.2H₂O

 Atomic mass of Al  = 27g/mol

                            O = 16g/mol

                            H  = 1g/mol

Molar mass = 27 + 3(16 + 1) + 2(2(1) + 16)

                    = 27 + 51 + 36

                   = 114g/mol

Percentage composition  = \(\frac{36}{114}\) x 100 = 32.73%

Answer:

ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.

Explanation:

Based on the given information, it cannot be determined which unknown solution contained more copper(ii) sulfate. The experiments performed only involved a copper solution and did not provide any comparative measurements or quantities of copper(ii) sulfate in the unknown solutions. Therefore, further testing or analysis would be necessary to determine which unknown solution contained more copper(ii) sulfate.

To determine the amount of copper(II) sulfate in a solution, one could perform a quantitative analysis such as titration or gravimetric analysis. Without such experiments, it is impossible to determine which solution contained more copper(II) sulfate.The given information only suggests that there were two unknown solutions, and one of them contained copper(II) sulfate. Therefore, the only conclusion that can be made is that the copper solution contained copper(II) sulfate.

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The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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Answer:

Box A.

Explanation:

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

\(Density = \frac{mass}{volume}\)

In this scenario, Box A and Box B have the same density. However, Box A had more volume. Therefore, the box that would have more mass would be Box A because it has more capacity or volume to hold more matter.

This ultimately implies that, the volume of a box is directly proportional to its mass (amount of matter it can hold); the higher the volume of the box, the higher its mass (more mass).

It's density would be;

\(Density = \frac{50}{25}\)

Density = 2kg/cm³

It's density would be;

\(Density = \frac{20}{10}\)

Density = 2kg/cm³

Therefore, it can be deduced that even though Box A and Box B have the same density; Box A had more volume and consequently, more mass.

Copper and tin wire are both ductile and able to be stretched.

The standard enthalpy change for the given reaction is approximately -156.87 kJ.

To calculate the standard enthalpy change (ΔH°) for the given reaction using standard heats of formation, the balanced equation for the reaction is:

Fe(s) + 2HCl(aq) → \(FeCl_2\)(s) + \(H_2\)(g)

The standard heats of formation (ΔH°f) for the compounds involved are as follows:

Fe(s): 0 kJ/mol

HCl(aq): -92.31 kJ/mol (source: NIST Chemistry WebBook)

\(FeCl_2\)(s): -341.49 kJ/mol (source: NIST Chemistry WebBook)

\(H_2\)(g): 0 kJ/mol

Now, let's calculate the standard enthalpy change (ΔH°):

ΔH° = Σ(ΔH°f products) - Σ(ΔH°f reactants)

ΔH° = [ΔH°f(\(FeCl_2\)) + ΔH°f(\(H_2\))] - [ΔH°f(Fe) + 2ΔH°f(HCl)]

ΔH° = [-341.49 kJ/mol + 0 kJ/mol] - [0 kJ/mol + 2(-92.31 kJ/mol)]

ΔH° = -341.49 kJ/mol + 2(92.31 kJ/mol)

ΔH° = -341.49 kJ/mol + 184.62 kJ/mol

ΔH° = -156.87 kJ/mol

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Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

106.66 grams of O2 reacting produces 4.01 x 10^24 particles of H2O.

We can start by balancing the chemical equation for the reaction between oxygen (O2) and hydrogen (H2) to form water (H2O):

2H2 + O2 → 2H2O

The balanced equation tells us that 1 mole of O2 reacts with 2 moles of H2 to form 2 moles of H2O.

To determine the number of particles of H2O produced from 106.66 grams of O2, we need to convert the mass of O2 to moles using its molar mass:

Molar mass of O2 = 32.00 g/mol

Number of moles of O2 = mass / molar mass

Number of moles of O2 = 106.66 g / 32.00 g/mol

Number of moles of O2 = 3.33 mol

Since the balanced equation tells us that 1 mole of O2 reacts with 2 moles of H2O, we can use stoichiometry to determine the number of moles of H2O produced:

Number of moles of H2O = (number of moles of O2) x (2 moles of H2O / 1 mole of O2)

Number of moles of H2O = 3.33 mol x 2

Number of moles of H2O = 6.66 mol

Finally, we can use Avogadro's number to convert the number of moles of H2O to the number of particles:

Number of particles of H2O = (number of moles of H2O) x (6.02 x 10^23 particles/mol)

Number of particles of H2O = 6.66 mol x 6.02 x 10^23 particles/mol

Number of particles of H2O = 4.01 x 10^24 particles

Therefore, 106.66 grams of O2 reacting produces 4.01 x 10^24 particles of H2O.

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Answer:

Land plants are also known as Embryophytes. Embryophytes are complex multicellular eukaryotes with specialized reproductive organs. The name derives from their innovative characteristic of nurturing the young embryo sporophyte during the early stages of its multicellular development within the tissues of the parent gametophyte.

Explanation:

Answer:

there used for mountains , wait I'm just trynna get points ya feel me

Explanation:

When alkaline hydrolysis was first invented, people were hired for various roles related to the process and implementation of this technology. Some of the jobs that emerged include Chemical engineers, Technicians and operators, Waste management specialists, Scientists and researchers.

Chemical engineers: These professionals played a crucial role in developing and optimizing the alkaline hydrolysis process. They were responsible for designing the equipment, developing the necessary chemical reactions, and ensuring the efficient operation of the system.

Technicians and operators: Skilled technicians and operators were hired to operate and maintain the alkaline hydrolysis equipment. They were trained to monitor the process parameters, handle the chemicals involved, and ensure the proper functioning of the system.

Waste management specialists: With the introduction of alkaline hydrolysis as a method for disposal of organic waste, specialized professionals in waste management were employed to oversee the proper handling and treatment of the waste materials. They were responsible for implementing safety protocols, managing waste streams, and complying with environmental regulations.

Scientists and researchers: Alkaline hydrolysis required scientific expertise for continuous improvement and innovation. Scientists and researchers were hired to study the process, analyze the results, and explore potential applications in various fields such as biofuel production and chemical synthesis.

Overall, the introduction of alkaline hydrolysis created employment opportunities for professionals in engineering, chemistry, waste management, and research, among others, as this technology gained recognition and adoption.

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Between OH and C=O, the strong nucleophile is OH and the strong electrophile is C=O.

1. OH (hydroxide ion) is a strong nucleophile because it has a negative charge on the oxygen atom, which allows it to donate its lone pair of electrons to an electrophilic center.
2. C=O (carbonyl group) is a strong electrophile because the carbon atom has a partial positive charge due to the electronegativity difference between carbon and oxygen atoms in the double bond. This makes the carbon atom highly susceptible to nucleophilic attack.

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