Is this a function of not

Answer:

Ax + By = C is standard form.

y + 1 = (2/3)(x - 8)

distribute the (2/3)

y + 1 = (2/3)x - (16/3)

Multiply each term by 3 to clear the fractions.

3y + 3 = 2x - 16

Subtract 2x from both sides.

-2x + 3y + 3 = - 16

Subtract 3 from both sides.

-2x + 3y = - 19

Correct form typically has the leading coefficient as a positive number so multiply each term by - 1.

2x - 3y = 19

Step-by-step explanation:

Answer:

The answer is 2x + -3y = 19

Step-by-step explanation:

got it right on edge

Answer:

\(x=35\)

Step-by-step explanation:

Set the two equations equal:

\(4x+7=6x-63\)

Add 63 to both sides:

\(4x+70=6x\)

Subtract 4x from both sides:

\(70=2x\)

Divide both sides by 2:

\(x=35\)

Answer:

2+9 is 11

so write any expression that equals 11  like...

1+10=11

2+9=11

3+8=11

4+7=11

5+6=11

and those above are all example of expression that is equivalent to 2+9

Answer: C ON EDGE 2021

Step-by-step explanation:

A cord of roughly 13.04 feet is demanded to support the 11 ft roof wall and anchor it 7 feet from the base of the roof.

We can use the Pythagorean theorem to break this problem.

Let the length of the cord be represented by the variable c. We know that the height of the roof wall is 11ft and the distance from the base of the roof to where the cord will be anchored is 7ft. We can use these values to form a right triangle, where the length of the cord is the hypotenuse

Using the Pythagorean theorem, we have

c^2 = 7^2 + 11^2

c^2 = 49 + 121

c^2 = 170

Taking the square root of both sides, we get

c = sqrt( 170)

c is roughly 13.04 feet.

thus, a cord of roughly 13.04 feet is demanded to support the 11- ft roof wall and anchor it 7 feet from the base of the roof.

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Answer:

Width=3 cm

Length=5 cm

Since y_1(0) = 1, it satisfies the initial condition. However, y_2(0) = 0 does not satisfy the initial condition, as it should be y(0) = 1. Therefore, only y_1(t) is a solution of the initial value problem.

To verify that both y_1(t) = 1 - t and y_2(t) = -t^2/4 are solutions of the initial value problem, we first need to understand what the problem is. An initial value problem is a differential equation that includes an initial condition. In this case, we can assume that the initial condition is y(0) = 1.
Now, let's substitute both y_1(t) and y_2(t) into the differential equation and see if they satisfy the initial condition. The differential equation is not provided, but assuming it is y'(t) = -t/2, we have:
y_1'(t) = -1
y_2'(t) = -t/2
Substituting y_1(t) and y_2(t) into the differential equation gives:
y_1'(t) = -1

= -t/2 (when t = 2)
y_2'(t) = -t/2

= -t/2 (for all t)
Thus, both y_1(t) and y_2(t) satisfy the differential equation. Now, let's check if they satisfy the initial condition.
y_1(0) = 1 - 0

= 1
y_2(0) = -0^2/4

= 0
In conclusion, y_1(t) = 1 - t is the only solution that satisfies the differential equation and initial condition, while y_2(t) = -t^2/4 is not a solution since it does not satisfy the initial condition.

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Yes, that is correct. First-order logic includes all of the connectives available in propositional logic, such as "and," "or," "not," "implies," and "if and only if."

However, first-order logic also goes beyond propositional logic by introducing quantifiers and variables to allow for more complex expressions and reasoning.
The relationship between first-order logic, connectives, and propositional logic. First-order logic indeed includes all the connectives available in propositional logic, allowing us to form more complex sentences.
In propositional logic, we use simple statements or propositions that can be true or false. Connectives, such as AND, OR, NOT, and IMPLIES, are used to combine these propositions into more complex expressions.
First-order logic expands upon propositional logic by introducing quantifiers like "for all" (∀) and "there exists" (∃) and predicates, which are relations or properties involving one or more variables. This allows us to represent more complex statements and relationships.
Since first-order logic includes connectives from propositional logic, we can form sentences that combine both quantifiers and connectives, allowing for richer and more expressive representations of information.

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The horizontal distance from point A to point B is approximately 160.1 ft, The correct option is (D).

To determine the horizontal distance between points A and B, we need to use trigonometry and the concept of right triangles. Let's denote the horizontal distance as x.

In a right triangle, the hypotenuse represents the inclined line connecting points A and B, the vertical side represents the elevation difference (40 ft), and the horizontal side represents the unknown distance (x ft). We can use the Pythagorean theorem to relate these sides:

(x ft)² + (40 ft)² = (165 ft)²

Simplifying the equation, we get:

x² + 1600 = 27225

x² = 27225 - 1600

x²= 25625

Taking the square root of both sides, we find:

x = √25625

x ≈ 160.1 ft

Therefore, the horizontal distance from point A to point B is approximately 160.1 ft.

So the correct answer is D. 160.1 ft.

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Answer: y=(x-1)(x+3)+6

Step-by-step explanation: you do opposite x-values and then you add the y-intercept.

Answer:

1/3

Step-by-step explanation:

Edna should leave at 2:07 PM in order to arrive at Jake's party by 2:30 PM

To determine the time Edna should leave, we need to subtract the travel time from the desired arrival time.

If Edna needs to be at Jake's party at 2:30 PM and it takes her 23 minutes to drive there, she should leave 23 minutes before 2:30 PM.

To calculate the departure time, we subtract 23 minutes from 2:30 PM:

2:30 PM - 23 minutes = 2:07 PM

Therefore, Edna should leave at 2:07 PM in order to arrive at Jake's party by 2:30 PM

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a. The private, nonprofit four-year colleges and universities have a larger relative variability because their coefficient of variation is higher than that of public four-year colleges and universities.

b. The largest and smallest amount paid at the​ four-year private, nonprofit colleges and universities is $32,315

a. To determine whether private, nonprofit four-year colleges and universities have larger relative variability, we can compare the coefficients of variation (CV) for both groups. The coefficient of variation is calculated as the ratio of the standard deviation to the mean, multiplied by 100 to express it as a percentage.

For public four-year colleges and universities:

CV = (Standard Deviation / Mean) * 100

CV = ($4,250 / $31,090) * 100 ≈ 13.67%

For private, nonprofit four-year colleges and universities:

CV = (Standard Deviation / Mean) * 100

CV = ($12,150 / $32,315) * 100 ≈ 37.63%

Comparing the coefficients of variation, we can see that private, nonprofit four-year colleges and universities have a larger relative variability because their coefficient of variation is higher than that of public four-year colleges and universities.

b. If the data on published tuition and fees were bell-shaped, the largest and smallest amounts paid at the four-year private, nonprofit colleges and universities would be determined using the z-scores and the mean and standard deviation.

Assuming a normal distribution, we can use z-scores to find the corresponding values.

For the largest amount:

z = (Amount - Mean) / Standard Deviation

z = (X - $32,315) / $12,150

By looking up the corresponding z-value in the z-table, we can determine the proportion of data beyond that value. Since we want the largest amount, the proportion beyond that value would be 0 (or close to 0). Therefore, the largest amount would be a very high value, possibly an outlier.

For the smallest amount:

z = (Amount - Mean) / Standard Deviation

z = (X - $32,315) / $12,150

By looking up the corresponding z-value in the z-table, we can determine the proportion of data below that value. Since we want the smallest amount, the proportion below that value would be 0. So the smallest amount would be a very low value, possibly an outlier.

Original Question

Each​ fall, a certain organization releases survey results on how much colleges and universities are charging undergraduate students in the new academic year. The survey indicated that the average published tuition and fees for a certain academic year were​ $310 9,310 at public​ four-year colleges and universities and ​$32,315 at​ private, nonprofit​ four-year colleges and universities. Assume that the standard deviation was approximately ​$4,250 at public​ four-year colleges and universities and approximately ​$12,150 for private colleges and universities. Complete parts a and b.

a. Do the​ private, nonprofit​ four-year colleges and universities have the larger relative​ variability? Select the correct choice below and fill in the answer box to complete your choice

b. If the data on published tuition and fees were​ bell-shaped, determine the largest and smallest amount paid at the​ four-year private, nonprofit colleges and universities.

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Both options a. A = 129.9° and b. A = 53.1° are correct.

To find the possible values for angle A in triangle ABC, we can use the Law of Sines, which states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant.

Using the Law of Sines, we have sin(A)/a = sin(B)/b. Plugging in the given values, we get sin(A)/36 = sin(51°)/35.

To find the two possible values for angle A, we can solve the equation sin(A)/36 = sin(51°)/35. Taking the arcsine of both sides, we have A = arcsin((sin(51°)/35)*36).

Calculating this expression, we find two possible values for angle A:

A ≈ 53.1° (rounded to the nearest tenth)

A ≈ 129.9° (rounded to the nearest tenth)

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Answer:hi

Step-by-step explanation:

Given:

The inequality is:

\(4x+1<5x\leq 3(x+2)\)

To find:

The integer solutions to the given inequality.

Solution:

We have,

\(4x+1<5x\leq 3(x+2)\)

This compound inequality can be written as two separate inequalities \(4x+1<5x\) and \(5x\leq 3(x+2)\).

Now,

\(1<5x-4x\)

\(1<x\)                 ...(i)

And,

\(5x\leq 3(x+2)\)

\(5x\leq 3(x)+3(2)\)

\(5x-3x\leq 6\)

\(2x\leq 6\)

Divide both sides by 2.

\(x\leq \dfrac{6}{2}\)

\(x\leq 3\)               ...(ii)

From (i) and (ii), we get

\(1<x\leq 3\)

Here, 1 is excluded and 3 is included in the solution set. There two integer values 2 and 3 in \(1<x\leq 3\).

Therefore, the integer solution for the given inequality are 2 and 3.

Answer:

2

Step-by-step explanation:

Step 1: Write out equation g(f(a))

1/√a

Step 2: Plug in 0.25 for a

1/√0.25

You answer should be 2

Answer: answers down below in the picture

lol i tried my best placing the dots and labeling .. sorry.. if you don't understand pls let me know

Photo Attached :)

I hope I did it correctly, just a little tedious.

Answer:

Hello,

Step-by-step explanation:

Since the three parts are in AP,

the parts are a,a+r,a+2r

a+a+r+a+2r=207

3a+3r=207

a+r=69

The product of the two smaller parts is 4623​:

a*(a+r)=4623

a*69=4623

a=67

r=69-a=69-37

r=2

The 3 parts are 67,69,71

Proof:

67+69+71=207

67*69=4623

Answer:NM=8

Step-by-step explanation:

JN is half of JL so x + 3 times 2 is equal to 3x + 1

then u just do the work

2x+6=3x+1

5=x

then you just plug in the answers and JN is equal to 8 therefore NM is also equal to 8

To solve the problem we must know about the properties of the diagonals of a rectangle.

The correct statement from all the given options is D.

Given to us

JN = x+3

JL = 3x+1

We know that the diagonals of the rectangle bisect each other at two equal parts, therefore, JN=NL, also

\(JL = JN + NL\\\\\text{Substituting the values,}\\\\3x+1 = x+3 + NL\\\\3x+1 = x+3 + NL\\\\3x-x=3-1+NL \ \ \ \ \ [JN=NL]\\\\2x = 2 + JN\\\\2x = 2 + x+3\\\\2x-x=5\\\\x = 5\)

As we know the values of the diagonals are equal, therefore,

JL = KM = 3x + 1

JL = KM = 3(5) + 1

JL = KM = 16

We know that the diagonals of the rectangle bisect each other at two equal parts, also the diagonal are equal therefore all the four parts of the two diagonals will be equal.

JN = NL = KN = NM = x+3

JN = NL = KN = NM = 5+3

JN = NL = KN = NM = 8

Hence, the correct statement from all the given options is D.

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Answer:

1

Step-by-step explanation:

2-5=x-4

subtract the common factors

-3 = x-4

add 4 to both sides so get x by itself

1 = x

Answer:

c.32/3π units ³

Step-by-step explanation:

V= 4/3πr³

r=4/2=2units

V= 4/3π(2)³

V= 4/3π *8

V= 32/3π units ³

Answer:

V≈32/3

Step-by-step explanation:

V=4 /3πr3=4 /3·π·23≈33.51032

33.5/3.14=10.6

32/3=10.6

Please brainliest! I worked so hard!

4(x+1)+7(x+3)=

4x+4+7x+21=

-Hunter

Answer:

11x + 25

Step-by-step explanation:

\(4(x + 1) + 7(x + 3)\)

expand brackets:

\(\implies 4x+4+7x+21\)

Collect and combine like terms:

\(\implies 11x+25\)

The values for random variables in a Monte Carlo simulation area that were chosen at random from probability distributions are the right answer.

What is Monte Carlo Simulation ?

The Monte Carlo Method, also referred to as the Monte Carlo Simulation or a multiple probability simulation, is a mathematical method for predicting potential outcomes of an uncertain event. To help people make better decisions when faced with uncertainty, John von Neumann and Stanislaw Ulam developed the Monte Carlo Method during World War II.

Therefore, the values for random variables in a Monte Carlo simulation area that were generated at random from probability distributions are the right answer.

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The correct response is the set of values for random variables in a Monte Carlo simulation region that were randomly selected from probability distributions.

In order to represent uncertainty in a model that represents a real system and computes the values of model outputs, a Monte Carlo technique is used. During World War II, John von Neumann and Stanislaw Ulam created the Monte Carlo Method to aid people in making better judgments when faced with uncertainty.

As a result, the correct response is the random values for random variables that were produced using probability distributions in a Monte Carlo simulation area.

Answer:

0 = 2×3 - 30

= 6-30

= -24

is the right answer

This question has no solution, but If you want to to compare, then it's False because 0 doesn't equal -24

To find the vertices and the foci of the ellipse with the given equation 5x² +2y² =10, we will use the standard form of the equation of an ellipse, x²/a²+y²/b²=1.

In this equation, a represents the horizontal distance from the center to the vertex or the foci and b represents the vertical distance from the center to the vertex or the foci.

For this problem, we can see that the major axis is along the x-axis since the coefficient of x² is larger than the coefficient of y². Therefore, a²=10/5=2 and b²=10/2=5.

This means that a=√2 and b=√5. The center of the ellipse is (0,0). Therefore, the vertices of the ellipse are (±√2,0), and the foci of the ellipse are (±√3,0).To draw the graph, we can first plot the center of the ellipse at (0,0). Then, we can draw the major axis, which is a horizontal line passing through the center and has a length of 2√2. This line passes through the vertices (±√2,0).

Then, we can draw the minor axis, which is a vertical line passing through the center and has a length of 2√5. This line passes through the points (0,±√5). Finally, we can draw the ellipse by sketching a curve that smoothly connects the vertices and the ends of the minor axis.To find the vertices and the foci of an ellipse from its given equation, we first need to check its standard form.

An ellipse is the set of all points in a plane such that the sum of their distances from two fixed points (called foci) is constant. Therefore, the equation of an ellipse must have the form x²/a²+y²/b²=1 or y²/a²+x²/b²=1, where a represents the horizontal distance from the center to the vertex or the foci and b represents the vertical distance from the center to the vertex or the foci.

In this case, the given equation is 5x²+2y²=10, which can be rewritten as x²/2+y²/5=1 by dividing both sides by 10. Therefore, we can see that a²=2 and b²=5. This means that a=√2 and b=√5.

The center of the ellipse is (0,0). Therefore, the vertices of the ellipse are (±√2,0), and the foci of the ellipse are (±√3,0).To draw the graph of the ellipse, we can first plot the center of the ellipse at (0,0).

Then, we can draw the major axis, which is a horizontal line passing through the center and has a length of 2√2. This line passes through the vertices (±√2,0). Then, we can draw the minor axis, which is a vertical line passing through the center and has a length of 2√5. This line passes through the points (0,±√5). Finally, we can draw the ellipse by sketching a curve that smoothly connects the vertices and the ends of the minor axis. This curve should have a shape that is somewhat similar to a stretched-out circle.

Therefore, the vertices of the given ellipse are (±√2,0), and the foci of the given ellipse are (±√3,0). The graph of the ellipse can be drawn by plotting the center at (0,0), drawing the major and minor axes passing through the center and having lengths of 2√2 and 2√5, respectively, and then sketching a curve that connects the vertices and the ends of the minor axis.

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Answer:

(17, -11)

Step-by-step explanation:

Please see the attached picture for full solution.

The area of figure is 272.52 square units.

The given figure consist:

A parallelogram of,

length = 12

width   = 18

Since we know that,

Area of parallelogram  = length x width

                                      = 12 x 18

                                      = 216 square units

And it consist of a semicircle of,

radius = 12/2

          = 6

Since we know that,

Area of semicircle is = πr²/2

                                  = 3.14 x 6 x 6/2

                                  = 56.52 square units

Thus,

The area of figure is sum of both areas,

⇒ 216 + 56.52

Hence, area is

⇒ 272.52 square units

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Answer:

70 ounces

Step-by-step explanation:

We can solve the weight of 35 candy bars by first finding the weight of one and multiplying by 35.

If 13 candy bars each weigh 26 ounces, one will weigh 2. We can write this out as shown:

13x = 26

x = 2

Now we simply multiply by 35 to get the total weight of 35 candy bars:

35x = 35(2) = 70