Is this equation balanced? 2HCl + CaCO3 → CaCl2 + H2O + CO2

Answer:

Explanation:

  a )

from lens makers formula

\(\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})\)

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

\(\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})\)

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\(\frac{1}{v} - \frac{1}{u} = \frac{1}{f}\)

\(\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}\)

\(\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}\)

.5555 - .04

= .515

v = 1.94 cm

c )

magnification = v / u

= 1.94 / 25

= .0776

size of image = .0776 x size of object

= .0776 x 10 mm

= .776 mm

It will be a real image and it will be inverted.

Answer:

I know you said not to do this but I am doing a challenge and You asked this an hour ago. PLS DON'T REPORT ME.

Explanation: Sorry

Answer:

Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789

The total energy at each point in the path of the skier is constant as the

skier travels down the slope.

Reasons:

1) Given that the total mechanical energy, M.E. is constant, we have;

M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant

M.E. = K.E. + P.E.

At the start, we have;

P.E. = 25,000 J

K.E. = 0 J

Therefore;

M.E. = 25,000 J + 0 J = 25,000 J

At point 1A, we have, K.E = 10,000 J

P.E. = M.E. - K.E.

Therefore;

P.E. = 25,000 - 10,000 = 15,000

The potential energy at point 1A, P.E. = 15,000 J

At point 1B, we have; PE = 6000 J

K.E. = M.E. - P.E.

Therefore;

K.E. = 25,000 J - 6,000 J = 19,000 J

At 1B, K.E. = 19,000 J

At point 1C, we have; K.E. = 25,000 J

Therefore;

P.E. = 25,000 J - 25,000 J = 0 J

At 1C P.E. = 0 J

2) The Law of Conservation of Energy states that the energy in a closed

system is constant.

The energy transformation follows the Law of Conservation of energy

given that the total mechanical energy is constant at all points along the

path.

3) The energy of a system is not conserved when a external force is

applied.

If the skier experiences friction, the force of friction does work to reduce

the speed of the skier, thereby reducing the kinetic energy at a point

downslope, where the potential energy has already been reduced,

resulting in an reduction in the mechanical energy of the system.

Therefore, if the skier experiences friction, the total energy of the system is

not conserved, as energy will be consumed in the work done by friction

which is converted to heat and sound energies.

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➝ Density of block = 10.5 g/cm³

➝ Volume of block = 30 cm³

We have to find mass of block\(.\)

➠ Density is defined as mass of substance per unit volume\(.\)

\(\dag\:\boxed{\bf{Density=\dfrac{Mass}{Volume}}}\)

\(:\implies\sf\:Mass=Density\times Volume\)

\(:\implies\sf\:Mass=10.5\times 30\)

\(:\implies\boxed{\boxed{\bf{\red{Mass=315\:g}}}}\)

Answer:

K = 1800 kJ

Explanation:

Given that,

The speed of the object, v = 30 m/s

Mass of the object, m = 4000 kg

We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :

\(K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ\)

So, the required kinetic energy is equal to 1800 kJ.

The tension force in the string is 98.72 N.

The angular speed of the ball is calculated as follows;

ω = 2πf

ω = 2π x 5

ω = 31.42 rad/s

The tension force in the string is calculated as follows;

F = T = mω²r

T = 0.04 x (31.42)² x 2.5

T = 98.72 N

Thus, the tension force in the string is 98.72 N.

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Answer:

d. 4.3 x 10²⁸ kg.

Explanation:

       \(F_{c} = m_{s}* \frac{v^{2}}{r} (1)\)

       \(F_{g} = G*\frac{m_{s}*m_{p} }{r^{2}} (2)\)

       \(T = \frac{\Delta s }{v} = \frac{2*\pi *r}{v} (3)\)

The mass of planet Nutron is ; ( D ) \(M_{b} = 4.3 * 10^{28} kg\)

Given data :

Satellite period of circling ( T )  = 84 secs

Radius ( r ) = 8.0 * 10⁶ m

Determine the mass of the planet Nutron

we will apply the equation representing the centripetal force

Centripetal force ( Fc ) = \(m_{s} * \frac{v^2}{r} ----- ( 1 )\)

applying Newton's universal law of Gravitation to equation ( 1 )

Fg = \(G * \frac{m_{s} * m_{b} }{r^2}\)   ------ ( 2 ).

note : equation ( 1 ) equals equation ( 2 )

First step : express T in terms of v and change in position ( Δs )

Given that v ( linear speed ) is unknown

T = Δs / v = \(\frac{2\pi r}{v}\)   --- ( 3 )

∴ v = [ 2 * π * ( 8 * 10⁶ ) ] /  ( 84 )

     = 598639.45 m/s

Input result in equation ( 1 ) and solve for the mass of planet Nutron in equation 2

∴  Mass of planet Nutron = \(M_{b} = 4.3 * 10^{28} kg\)

Hence we can conclude that The mass of planet Nutron is ; ( D ) \(M_{b} = 4.3 * 10^{28} kg\)

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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:

NO 21 days wouldn't be enough because it takes at least one month to observe all of the moon's phases.

Explanation:

Hope this helps!!

Answer:

The answer is 2,475$+948= add you will get the answer rn

The weight we experience on a surface is the product of our mass and acceleration due to gravity on that surface. The mass of the astronaut in earth was 60 kg . Then his mass at moon will be 9.76 kg.

The gravitational force is the force by which an object attracts other objects into its center of mass. Earth attracts every objects into its center. That why we are all standing on the ground.

The weight we experience on earth is due to the gravity. That is the product of mass and acceleration due to gravity of a planet is the weight on the planet.

The weight of astronaut in earth = 60 kg

acceleration due to gravity on earth = 9.8 m/s²

mass = 60/9.8 m/s² = 6.19 kg

Acceleration due gravity on moon = 1.6 m/s²

then weight on moon = 1.6 m/s² ×6.19 kg = 9.7 kg.

Therefore, the weight of the astronaut in moon will be 9.7 kg.

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Answer:

After the inelastic collision, the velocity of the 8 kg mass would be the same as the center of mass velocity. Which is the velocity of the combined system of both masses. To find the velocity of the center of mass, we can use the following formula:

vcm = (m1v1 + m2v2) / (m1+m2)

where m1 = 8kg, v1 = 9.6 m/s east, m2 = 6kg, v2 = 14.8 m/s west

vcm = (89.6 + 6(-14.8)) / (8 + 6) = -0.8 m/s (west)

Therefore, after the inelastic collision, the velocity of the 8 kg mass would be -0.8 m/s (west)

"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."

It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.

When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.

Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.

Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.

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The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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Answer:

A: An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

Explanation:

Answer:

rocks, sediments, boreholes, ice sheets, tree rings, corals, shells, and microfossils.

Explanation:

Answer:

These tools include sediment cores, ocean cores, ice cores, geologic features and stratigraphy, cave deposits (speleothems), tree rings (dendrochronology), and fossil coral. Each of these different tools contains useful proxies, which provide clues about different aspects of past climates.

Explanation:

Answer:

x < -3

Step-by-step explanation:

the other one was taken by a bot so im using this one

4x + 6 < -6

subtract 6 from both sides

4x + 6 - 6 < -6 - 6

Simplify

4x < -12

divide both sides by 4

4x/4 < -12/4

Simplify

x < -3

Displacement is a vector quantity. The distance and displacement of the given object are 10 ft and 7.07 ft respectively.

It can be defined as the change in position of the object. It is a scalar quantity.

Displacement = 4+6

Displacement = 10 ft

\(\rm Dislacement =\sqrt { 4^2 +6^2}\\\\ \rm Dislacement = 7.07 ft\)

Therefore, the distance and displacement of the given object are 10 ft and 7.07 ft respectively.

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The work that is done by the gas can be obtained as 110 J.

There is not enough information in the question to determine part B.

We know that a gas is said to do work whenever the gas expands. The expansion of a gas mans that the gas is able to increase its volume and we can see from the question that the volume of the gas was quite able to move from a value of  450 mL to 810 mL .

How then can be be able to obtain the work that has been done by the gas in this case? We are aware that we do have the following parameters from the question;

Pressure of the gas = 3.1 atm

Initial volume of the gas = 450 mL or 0.45 L

Final volume of the gas = 810 mL or 0.81 L

The we have the formula;

W =PΔV

W = work done

P = pressure of the gas

ΔV = change in the volume of the gas

Thus;

W = 3.1 (0.81 - 0.45)

W = 1.12 atm L or 110 J

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Answer:

C.

would adapt if the dress were held completely still

Explanation:

Claire keeps rubbing it with her fingers because the tactile sense would adapt if the dress were held completely still. Therefore, option (C) is correct.

Tactile receptors are identified by the sensation of touch and are all over our bodies in our skin. Some areas of the human skin have more tactile receptors such as the mouth and hands. The tactile senses identify touch, pressure, pain, temperature, and texture.

Tactile stimulation involves the active nerve signals under the skin's surface that inform the body of texture, temperature, and other touch sensations. The nervous system collects data from receptors to determine the sensation of in-between temperatures.

Sensations start as signals created by touch receptors in the skin. They travel along sensory nerves composed of bundled fibers that connect to neurons in the spinal cord.

The tactile activities such as rubbing different textures against the skin, rolling over different textured surfaces, and handling different textured objects like rough and smooth.

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If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.

To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).

Saturn's density can be computed using the following formula:

density equals mass divided by volume

Saturn's mass and volume may be computed given its mass and radius.

The volume of Saturn can be determined using the sphere volume formula:

volume =\((4/3) \pi (r^3)\)

where r is Saturn's radius.

Filling in the blanks:

volume = \((4/3) \pi (5.6 \times 107) m^3\)

8.27 x 1023 \(m^3\)volume

Saturn's mass is given as \(5.68 \times 10^{26} kg.\)

We can now compute Saturn's density:

density equals mass divided by volume

density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)

This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.

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Answer:

They are trying to jump-start a car using a kite and lightning connected to the battery. This will not work because there is no positive or negative charged side to the circuit.

Explanation:

Answer:

It will go to the right way 500N.

Explanation:

Because, up and down is 300 and 300 so it minus each other and get zero, that made the resultant force will never go up or down. And now we are focusing on the left and right. 900 is more than 400, so it will go to the right. But we also pull to the left too!! That make the resultant force is 500 to the right.

Answer:

oxygen silicon aluminun iron

Answer:

How to write a powerful design brief in 9 easy steps

Start with an overview of the business.

Cover the scope.

Define the audience.

Understand the competition.

Set specific goals.

Take inventory of what you already have.

Set the schedule.

Determine the budget.

Explanation:

Answer:

θ = 39.7º

Explanation:

In this exercise we must use Newton's second law for the sphere, at the equilibrium point we write the equations in each exercise; we will assume that plate 1 is on the left

Y Axis

       \(T_{y}\) -W = 0

       \(T_{y}\) = W

X axis

         -\(F_{e1}\) - F_{e2} + Tₓ = 0

let's use trigonometry to find the components of the tension, we measure the angle with respect to the vertical

         sin θ = Tₓ / T

         cos θ = T_{y} / t

         Tₓ = T sin θ

         T_{y} = T cos θ

let's use gauss's law to find the electric field of each leaf; We define a Gaussian surface formed by a cylinder, so the component of the field perpendicular to the base of the cylinder is the one with electric flow.

         F = ∫ E. dA = \(q_{int}\) / ε₀

  in this case the scalar product is reduced to the algebraic product, the flow is towards both sides of the plate

        F = 2E A = q_{int} / ε₀

let's use the concept of surface charge density

        σ = q_{int} / A

we substitute

        2E A = σ A /ε₀

          E = σ / 2ε₀

this is the field created by each plate. The electric force is

        \(F_{e}\) = q E

for plate 1 with σ₁ = -30 10⁻⁶ C / m²

         F_{e1}  = q σ₁ /2ε₀

for plate 2 with s2 = ab 10⁻⁶ C / m², for the calculations a value of this charge density is needed, suppose s2 = 10 10⁻⁶ C / m²

          F_{e2} = q σ₂ /2ε₀

we substitute and write the system of equations

           T cos θ = mg

          - q σ₁ / 2ε₀  - q σ₂ /2ε₀  + T sinθ = 0

we introduce t in the second equations

          - q /2 ε₀  (σ₁ + σ₂) + (mg / cos θ) sin θ = 0

          mg tan θ = q /2ε₀   (σ₁ + σ₂)

          θ = tan -1 (q / 2ε₀ mg (σ₁ + σ₂)

data indicates the mass of 0.25 g = 0.25 10⁻³ kg

give the charge density on plate 2, suppose ab = 10 10⁻⁶ C / m²

let's calculate

         θ = tan⁻¹ (9.0 10⁻¹⁰ (30 + 10) 10⁻⁶ / (2  8.85 10⁻¹² 0.25 10⁻³ 9.8))

         θ = tan⁻¹ 8.3 10⁻¹)

         θ = 39.7º

Answer:

Wavelength

Explanation:

Answer:

sandy loam

Explanation:

The best soil for most plants to ensure optimum growth is a rich, sandy loam. This soil is an even mixture of all three main types of soil. In most cases, you'll need to amend the soil with compost. Depending on how compact the soil is, you may need to add peat moss and sand.

Answer:

1111

1Explanation:

111111

1

Answer: energy transfer. or, kinetic energy.

Explanation:

when something collides with another, it transfers kinetic energy to the other it collided with, making it move.