Answer:
7.16 × 10⁻³ M
Explanation:
Let's consider the reduction reaction of copper during the electroplating.
Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)
We can calculate the moles of Cu²⁺ present in the solution using the following relations.
1 A = 1 C/s.1 min = 60 s.1 mole of electrons has a charge of 96486 C (Faraday's constant).1 mole of Cu²⁺ is reduced when 2 moles of electrons are gained.The moles of Cu²⁺ reduced are:
\(2.30 min \times \frac{60s}{1min} \times \frac{3.00C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molCu^{2+} }{2mole^{-} } = 2.15 \times 10^{-3} molCu^{2+}\)
\(2.15 \times 10^{-3} moles\) of Cu²⁺ are in 0.300 L of solution.
[Cu²⁺] = 2.15 × 10⁻³ mol/0.300 L = 7.16 × 10⁻³ M
Find the oxidation numbersp) Oxidation number of Pb in Pb(Cr2O7)2q) Oxidation number of Cr in Pb(Cr2O7)2r) Oxidation number of O in Pb(Cr2O7)2
To find the oxidation number we can check the periodic table of the elements. There are some elements that have only one oxidation state, others can have more than one.
We must take into account that the total oxidation state of the molecule must be 0, so the sum of the oxidation states of the elements must equal 0.
To start, let's identify the possible oxidation states of elements in molecules.
Pb: +4, +2
Cr: +6, +3, +2
Or: -2
Oxygen has only one oxidation state equal to -2 so we'll start by placing that. Regarding chromium, in this case, the only possibility is that it has an oxidation state of +6 since if the oxidation state is lower, the molecule could not be neutralized with a single Pb atom.
With an oxidation state of oxygen of -2, of Cr equal to +6, the lead must have an oxidation state of +4. To understand it we can see the following table:
Therefore, the answer will be:
p) Oxidation number of Pb in Pb(Cr2O7)2: +4
q) Oxidation number of Cr in Pb(Cr2O7)2: +6
r) Oxidation number of O in Pb(Cr2O7)2: -2
Use your model to predict the relative positions of the earth, sun, and moon when the moon is full. Select the correct description below.
The moon will be positioned so that the earth is between the moon and the sun and the illuminated side of the moon is facing the earth.
The moon will be positioned between the sun and earth so that the illuminated side is facing the sun.
The moon will be positioned at a right angle compared to the earth and the sun and you will see a portion of the illuminated side of the moon.
Answer:
The moon will be positioned so that the earth is between the moon and the sun
I NEED HELP PLS:(
10 mL of 1 M HBr at 20 °C is mixed with 25 mL of 1 M NaOH at 20 °C in a calorimeter. The temperature increases to 23°C.How much heat was released? The density of water is 1g/mL. The specific heat of water is 4.18 J/g˚C.
The heat released is 439.5 J during the reaction.
The heat released can be calculated using the formula:
q = mCΔTwhere q is the heat released, m is the mass of the solution, C is the specific heat of water, and ΔT is the change in temperature.
First, we need to calculate the total mass of the solution:
10 mL HBr + 25 mL NaOH = 35 mLThe density of water is 1 g/mL, so the mass of the solution is 35 g.
Next, we can calculate the change in temperature:
ΔT = final temperature - initial temperatureΔT = 23°C - 20°CΔT = 3°CFinally, we can substitute these values into the formula:
q = 35 g * 4.18 J/g°C * 3°Cq = 439.5 JTherefore, 439.5 J of heat was released during the reaction.
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Q2 A solution has a (OH-) = 4.0x10^-5 M. What are the [H30+) and the pH of the
solution?
Answer:
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
pH = 9.6
Explanation:
Step 1: Given data
Concentration of OH⁻ in the solution ([OH⁻]): 4.0 × 10⁻⁵ M
Step 2: Calculate the concentration of H₃O⁺ in the solution
Let's consider the self-ionization of water.
2 H₂O(l) ⇄ H₃O⁺(aq) + OH⁻(aq)
The ion-product of water (Kw) is:
Kw = 1.0 × 10⁻¹⁴ = [H₃O⁺] × [OH⁻]
[H₃O⁺] = 1.0 × 10⁻¹⁴/[OH⁻]
[H₃O⁺] = 1.0 × 10⁻¹⁴/4.0 × 10⁻⁵
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
Step 3: Calculate the pH of the solution
We will use the following expression.
pH = -log [H₃O⁺]
pH = -log 2.5 × 10⁻¹⁰
pH = 9.6
Taking into account the definition of pH and pOH, the pH and [H₃O⁺] of the solution is 9.602 and 2.5×10⁻¹⁰ M respectively.
First of all, pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
The following relationship can be established between pH and pOH:
pH + pOH= 14
In this case, you know that [OH⁻]= 4×10⁻⁵ M. For this concentration, the pOH is calculated as:
pOH= - log (4×10⁻⁵ M)
pOH= 4.398
Then, pH can be calculated as:
pH + 4.398= 14
pH= 14 - 4.398
pH= 9.602
So, the [H₃O⁺] is calculated as:
9.602= - log [H₃O⁺]
[H₃O⁺]= 10⁻⁹ ⁶⁰²
[H₃O⁺]= 2.5×10⁻¹⁰ M
Finally, the pH and [H₃O⁺] of the solution is 9.602 and 2.5×10⁻¹⁰ M respectively.
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brainly.com/question/13557815?referrer=searchResultsA game of tug-of-war, in which two teams pull on opposite ends of a rope is shown here. What needs to happen to make the center of the rope go in one direction?
The ground needs to provide more friction for both teams.
Both teams have the same amount of people.
The rope needs to have no mass of its own.
One team pulls with more force than the other.
Answer:
One team pulls with more force than the other
Two asteroids are 75,000 m apart one has a mass of 8 x 10^7 N what is the mass of the other asteroid
The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg
To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:
F = (G * m1 * m2) / \(r^{2}\)
where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.
Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):
1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)
Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.
The question was incomplete. find the full content below:
Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid
A. 3.4 x \(10^{11}\) kg
B. 8.3 x \(10^{12}\) kg
C. 1.2 x \(10^{12}\) kg
D. 1.2 x \(10^{10}\) kg
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PLEASE HELP ME!
WILL MARK BRAINLIEST
Water Cycle
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, some have more details available when you click on them. Drag and drop each label to the corresponding area it identifies in the image.
The one on the top left corner is condensation. The one below that is evaporation. The one below that in the water is accumulation. The one next to accumulation is ground flow. The one on the trees is transpiration. The one above transpiration is surface flow. The one above surface flow is precipitation and above precipitation it’s condensation. Lmk if you were able to get that.
TRUE or FALSE: recessive alleles of the same gene are named with a
DIFFERENT letter than dominant alleles.
When 3.93 grams of lactic acid, CHoOs(s), are burned in a bomb
calorimeter that has a total heat capacity of 10.80 kJ-K-1, the
temperature of the calorimeter increases by 5.43 K. Assume AHrxn
=
AErxn. Given that AH°f of H¿O(I) = -285.8 kJ-mol-1 and AH°f of CO:(g)
= -393.5 kJ• mol-1, calculate the AH°f of lactic acid.
The heat released in the combustion of lactic acid is absorbed by the
calorimeter and in the decomposition of the lactic acid.
ΔH°f of lactic acid is approximately -716.2 kJ
Reasons:
Known parameters are;
Mass of the lactic acid = 3.93 grams
Heat capacity of the bomb calorimeter = 10.80 kJ·K⁻¹
Change in temperature of the calorimeter, ΔT = 5.34 K
ΔHrxn = ΔErxn
ΔH°f of H₂O(l) = -285.8 kJ·mol⁻¹
ΔH°f of CO₂(g) = -393.5 kJ·mol⁻¹
The chemical equation for the reaction is presented as follows;
C₃H₆O₃ + 2O₂ → 3CO₂ + 3H₂OThe heat of the reaction = 10.80 kJ·K⁻¹ × 5.34 K = 57.672 kJ
Molar mass of C₃H₆O₃ = 90.07 g/mol
Number of moles of C₃H₆O₃ = \(\dfrac{3.93 \, g}{90.07 \, g/mol}\) = 0.043633 moles
Number of moles of CO₂ produced = 3 × 0.043633 moles = 0.130899 moles
Heat produced = 0.130899 mole × -285.8 kJ·mol⁻¹ = -37.4109342 kJ
Moles of H₂O produced = 0.130899 moles
Heat produced = 0.130899 mole × -393.5 ≈ -51.51 kJ
Therefore, we have;
Heat absorbed by the lactic acid = ΔH°f of H₂O + ΔH°f of CO₂ + Heat absorbed by the calorimeter
Which gives;
Heat absorbed by lactic acid = -37.4109342 kJ - 51.51 kJ + 57.672 kJ ≈ -31.249 kJ
The heat absorbed by the lactic acid ≈ -31.249 kJ
\(\Delta H^{\circ}f \ of \ C_3H_6O_3 = \dfrac{-31.249}{0.043633} \approx -716.2\)
ΔH°f of C₃H₆O₃ ≈ -716.2 kJ
Heat of formation of lactic acid ≈ -716.2 kJ.
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out of all of the planetary health measures shown in the images provided which one shows if humans have already exceeded?A. global average surface temperature B. ocean ph C. atmospheric carbon dioxide D. sea level
According to the picture, Global average surface temperature, is in extreme levels and shows that human actions contributed to this increase in global temperature.
which elements are radioactive?
Answer:
uranium U
radium. RA
thorium TH
polonium PO
radium. RN
carbon. C
3Ba(ClO3)2 number of atoms for each element
Answer:
3 atoms of Ba
2 x 1 = 2 atoms of Cl
2 x 3 = 6 atoms of O
So, the total number of atoms for each element in 3Ba(ClO3)2 are:
Barium (Ba): 3 atoms
Chlorine (Cl): 2 atoms
Oxygen (O): 6 atoms
Explanation:
What volume of CO2(g), measured at STP is produced if 15.2 grams of CaCO(s) is heated?
Answer:
Volume = 3.4 L
Explanation:
In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:
CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)
Now, let's calculate the number of moles in 15.2 g CaCO₃:
mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)
= \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)
= 0.1518 moles
From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.
Hence, from the formula for the number of moles of a gas, we can calculate the volume of CO₂:
mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)
⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)
⇒ Volume = 0.1518 × 22.4
= 3.4 L
Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.
Calculate the number of gams of nitrogen dioxide that are produced from 4 moles of nitric oxide
2NO(g) + O2(g) → 2NO2(g)
PLZ ANSWERRR FAST
Answer: 184 g of nitrogen dioxide that are produced from 4 moles of nitric oxide
Explanation:
The balanced chemical reaction is:
\(2NO(g)+O_2(g)\rightarrow 2NO_2(g)\)
According to stoichiometry :
2 moles of \(NO\) produce = 2 moles of \(NO_2\)
Thus 4 moles of \(NO\) will require=\(\frac{2}{2}\times 4=4moles\) of \(NO_2\)
Mass of \(NO_2=moles\times {\text {Molar mass}}=4moles\times 46g/mol=184g\)
Thus 184 g of nitrogen dioxide that are produced from 4 moles of nitric oxide
Chemistry problems
1. 1.5 moles of potassium sulfate (K SO4) were dissolved in 1000 grams of water (H2O). Find the % and Cm.
2. 10 grams of sulfuric acid (H2SO4) was added to 500 ml of 10% solution of potassium hydroxide (KOH) with a density of 1.1 g/ml. Find the mass of potassium sulfate (K SO4) formed.
3. Find the mass of the salt formed by the reaction of 7.3 grams of hydrochloric acid (HCl) with 5.6 liters (5600 ml) of ammonia (NH3).
4. Find the volume of hydrogen gas (H2) produced by the reaction of 13 grams of zinc with a solution containing 30 grams of sulfuric acid (H2SO4).
5. How much of the concentrated original solution (70%) of acetic acid is needed to prepare 500 grams of 3% (percentage solution)?
1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.
2. 7.8 grams of potassium sulfate will be formed.
3. 10.7 grams of ammonium chloride will be formed.
4. The volume of hydrogen gas that will be produced is 3.86 liters.
5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.
What is the percentage concentration?1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g
Mass of water (H₂O) = 1000 g
% = (mass of solute/mass of solution) x 100
% = (261.39 g / (261.39 g + 1000 g)) x 100
% ≈ 20.7%
Cm = moles of solute / volume of solution
Moles of potassium sulfate (K2SO4) = 1.5 moles
Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L
Cm = 1.5 moles / 1 L
Cm = 1.5 M
2. The balanced equation for the reaction is:
H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O
Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol
Moles of sulfuric acid = 10 g / 98.09 g/mol
Moles of sulfuric acid = 0.102 mol
Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.
Molar mass of potassium sulfate = 174.26 g/mol
Mass of potassium sulfate = 0.102 mol x 174.26 g/mol
Mass of potassium sulfate ≈ 17.8 g
3. The balanced equation for the reaction is:
HCl + NH₃ → NH₄ClMolar mass of hydrochloric acid (HCl) = 36.46 g/mol
Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol
Moles of hydrochloric acid ≈ 0.2 mol
Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.
Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol
Mass of ammonium chloride = 0.2 mol x 53.49 g/mol
Mass of ammonium chloride ≈ 10.7 g
4. The balanced equation for the reaction is:
Zn + H₂SO₄ → ZnSO₄ + H₂Molar mass of zinc (Zn) = 65.38 g/mol
Moles of zinc = 13 g / 65.38 g/mol
Moles of zinc ≈ 0.199 mol
Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.
Volume of sulfuric acid = 30 g / (density of H₂SO₄ )
The density of H₂SO₄ is 1.84 g/mL
Volume of sulfuric acid = 30 g / 1.84 g/mL
Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L
Using the ideal gas law, the volume of hydrogen gas produced will be:
V = nRT / P
V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)
V ≈ 3.86 L
5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).
Mass of acetic acid = 500 g x (3/100) = 15 g
The concentrated original solution, however, is 70% acetic acid.
70% acetic acid (mass) = 100% acetic acid (unknown mass)
0.7 * (unknown mass) = 15 g
Solving for the unknown mass:
unknown mass = 15 g / 0.7
unknown mass ≈ 21.43 g
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Im not good at science :’)
Answer:
Annual precipitation
Explanation:
Annual precipitation seems like the correct one
describe radioisotope
Answer:
It is an unstable form of a chemical element that releases radiation as it breaks down and becomes more stable.
show workHow many grams of aluminum will react with 3.4 moles of chlorine?
ANSWER
STEP-BY-STEP EXPLANATION:
Given information
The number of moles of chlorine = 3.4 moles
Step 1: write a balanced equation of aluminum and chlorine
\(2Al+3Cl_2\rightarrow2AlCl_3\)Step 2: Find the number of moles of aluminum using a stoichiometry ratio
From the above reaction, you will see that 2 moles of aluminum react with 3 moles of chlorine to give 3 moles of aluminum chloride.
Let x represents the number of aluminum
\(undefined\)Balloons for a New Years Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 c and then hung outside. what is the volume of the balloon once they have cooled to the outside temperature of -34.0 c?
The volume of the balloon once they have cooled to the outside temperature of -34.0 c is 1.53 L.
Charles' law predicts the relationship between the volumes and the temperatures of a sample of an ideal gas at different conditions. For this equation to hold true, the number of molecules and the pressure must remain constant despite changes in the environment.
Determine the volume of the balloon outside, V2. We do this by applying Charles' law, such that we relate the volume, V, and the temperature, T, of a sample of gas as
V₁ /T₁ = V₂/ T₂
at two conditions. We are given the following values for the variables:
• V₁ = 1.90 L
T₁ = 22.0+ 273.15 = 295.15 K
T₂= 34.0+273.15= 239.15 K
We proceed with the solution.
V₁/T₁ = V₂/T₂
V₁ /T₁ × T₂ = V₂
1.90 L/295.15 K x 239.15 K = V₂
1.53 L =V₂
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The complete question is
Balloons for a New Year's Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 degrees Celsius and then hung outside where the temperature is -34.0 degrees Celsius. What is the volume of the balloons after they have cooled to the outside temperature? Assume that atmospheric pressure inside and outside the house is the same.
If your equation includes 7(CrO4)2, how many Cr's are there?
If your equation includes 7(CrO4)2, how many O's are there?
If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.
How to calculate number of atoms?The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.
According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:
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A frog sitting at the edge of a water puddle. The mud and dirt surrounding the pond is labeled A, the frog is labeled B, and the water is labeled C.
Fill in the blank with the correct sphere label.
A:
geosphere
B:
biospere
C:
hydrosphere
Part A is labeled as geosphere, B is biospere and C is hydrosphere.
What are the different division of the earth?
The Earth can be divided into four interconnected spheres: the geosphere, atmosphere, hydrosphere, and biosphere.
The geosphere refers to the solid, rocky part of the Earth, including the crust, mantle, and core. The mud and dirt surrounding the water puddle would be considered part of the geosphere.
The biosphere includes all living things on Earth and the environments in which they live. The frog sitting at the edge of the water puddle is part of the biosphere.
The hydrosphere refers to all the water on Earth, including oceans, lakes, rivers, and groundwater. The water in the puddle would be part of the hydrosphere.
These spheres are interconnected and influence each other. For example, the biosphere relies on the geosphere for nutrients and minerals, while the geosphere is shaped by the movement of water in the hydrosphere.
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Which of the following is a main metal O,C Ag or Rb?
In the Minnesota Department of Health set a health risk limit for benzene in groundwater of . Suppose an analytical chemist receives a sample of groundwater with a measured volume of . Calculate the maximum mass in milligrams of benzene which the chemist could measure in this sample and still certify that the groundwater from which it came met Minnesota Department of Health standards. Be sure your answer has the correct number of significant digits.
Answer:
3.10 × 10⁻⁴ mg
Explanation:
In the Minnesota Department of Health set a health risk limit for benzene in groundwater of 10.0 μg/L. Suppose an analytical chemist receives a sample of groundwater with a measured volume of 31.0 mL. Calculate the maximum mass in milligrams of benzene which the chemist could measure in this sample and still certify that the groundwater from which it came met Minnesota Department of Health standards. Be sure your answer has the correct number of significant digits.
Step 1: Given data
Concentration limit (C): 10.0 μg/LVolume of the sample (V): 31.0 mLStep 2: Convert "V" to L
We will use the conversion factor 1 L = 1000 mL.
31.0 mL × 1 L/1000 mL = 0.0310 L
Step 3: Calculate the maximum mass of benzene (m)
We will use the following expression.
m = C × V = 10.0 μg/L × 0.0310 L = 0.310 μg.
Step 4: Convert "m" to mg
We will use the conversion factor 1 mg = 1000 μg.
0.310 μg × 1 mg/1000 μg = 3.10 × 10⁻⁴ mg
What type of intermolecular forces occur between 2 oil molecules?
Answer:
The three main kinds of intermolecular interactions are dipole-dipole interactions, London dispersion forces, and hydrogen bonds
Explanation:
2- The vapor pressure of water at 80°C is 355 torr, Calculate the vapor
pressure of an aqueous solution made by dissolving 50 gm of ethylene
glycol (C₂H5O₂) in 50 gm of water. What is the vapor pressure lowering of
water in this solution?
The vapor pressure lowering of water in this solution is 1165 torr.
What is vapor pressure?
The pressure that a vapour exerts on its condensed phases in a closed system at a specific temperature is known as the vapour pressure or equilibrium vapour pressure. An indicator of a liquid's evaporation rate is the equilibrium vapour pressure. It has to do with how easily liquid-borne particles tend to elude detection (or solid). Volatile is a term used to describe a chemical that, at room temperature, has a high vapour pressure. Vapor pressure is the force that a vapour cloud exerts over a liquid surface. The kinetic energy of a liquid's molecules increases along with the temperature. The number of molecules vaporising also rises as a function of the molecules' rising kinetic energy, which raises the vapour pressure.
the vapor pressure of water and the mixture is 355 torr and 760 torrs. Therefore, the value of vapor pressure of oxygen would be,
Ptotal=PO2+PH2O
760=PO2+355
760−355=PO2
405=PO2
So, at the temperature, the vapor pressure of Ethylene is 405 torr.
When volume reduces to 50ml, the pressure of the oxygen would be,
P1V1=P2V2
where P1 and P2 are the pressure and V1 and V2 are the volumes.
P1V1=P2V2
P1V1/V2=P2
405×100 / 50=P2
810=P2
So, when the volume is 50ml the vapor pressure of the oxygen is 810 torr.
Now the total pressure of water-saturated oxygen at 50 ml volume is,
Ptotal=PO2+PH2O
Ptotal=810+355
Ptotal=1165
So, the total vapor pressure is 1165 torr.
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Name and describe the process by which stars create energy.
Answer: Nuclear fusion- The simple answer is that deep inside the core of the Sun, enough protons can collide into each other with enough speed that they stick together to form a helium nucleus and generate a tremendous amount of energy at the same time.
What can scientists learn from the chemical isotopes in leftover shells of foraminifera about the climate at the time the foraminifera lived?.
Answer:
From the chemical isotopes in leftover shells of foraminifera, scientists can estimate the ocean's temperature and are able to determine the air's carbon dioxide content.
What are isotopes?
Isotopes are the elements which have same atomic number but different mass number. For example - Carbon has three isotopes- C-12, C-13, C-14
In the three isotopes of carbon, all three isotopes have six protons, but carbon-12 has six neutrons, carbon-13 has seven neutrons, and carbon-14 has eight neutrons. Hence, Mass number differs in case of isotopes.
Scientists can learn about the climate at the time the foraminifera lived by analyzing the chemical isotopes in their leftover shells. Estimation of the ocean's temperature based on the ratio of oxygen isotopes in the shells can also be done. The amount of carbon dioxide in the air at the time based on the ratio of carbon isotopes in the shells can also be calculated.
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Your question is incomplete, but most probably your full question was,
What can scientists learn from the chemical isotopes in leftover shells of foraminifera about the climate at the time the foraminifera lived?
a. They can calculate the amount of carbon dioxide in the air.
b. They can estimate the ocean's temperature.
c. They can calculate the amount of rainfall.
d. They can estimate the air temperature.
How does adding a lone pair affect the position of existing atoms and lone pairs
Answer:
How does adding a lone pair affect the position of existing atoms and lone pairs? It decreases the angles between the atoms - the atoms are moving closer because they are being repelled further away from the lone pairs then they are from the other atoms
Explanation:
hope it helps!
Zack has noticed a lot of changes in his body. He has gained muscle mass and started to grow facial hair. His voice is also getting deeper.
In which stage of development is he?
childhood
adolescence
early adulthood
late adulthood
Answer:
b
Explanation:
How many molecules of ethanol, C2H5OH, are contained in a 150. gram sample?
1.96 x 1024
46.0
6.02 x 1023
5.1 x 10-25
Answer:
1.96 × 10²⁴ molecules
Explanation:
Step 1: Given data
Mass of ethanol (m): 150. g
Step 2: Calculate the number of moles (n) corresponding to 150. g of ethanol
The molar mass of ethanol is 46.07 g/mol.
150. g × 1 mol/46.07 g = 3.26 mol
Step 3: Calculate the number of molecules in 3.26 moles of ethanol
To convert moles into molecules, we need Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.
3.26 mol × 6.02 × 10²³ molecules/1 mol = 1.96 × 10²⁴ molecules