Answer:
Height of the empire building = 1505.57 ft
Step-by-step explanation:
Jada is visiting new York city to see the empire state building . She is 100 ft away when the she spots it. To see the top she has to look at an angle of 86.2° . The illustration forms a right angle triangle.
The height of the empire can be gotten below.
the adjacent side of the triangle formed = 100 ft
The side we are looking for is the opposite side which is the height of the empire state building. The angle formed is the angle of elevation from the ground to the top which is 86.2°
Using SOHCAHTOA principle the height can be gotten with the tangential degree.
tan 86.2° = opposite/adjacent
tan 86.2° = a/100
a = 100 tan 86.2
a = 100 × 15.0557227245
a = 1505.57227245
a ≈ 1505.57 ft
Height of the empire building = 1505.57 ft
PLEASE HELP, I NEED HELP ASAP
Answer:
45cm^2
Step-by-step explanation:
split the shape into a triangle and rectangle between points FE. Count how many squares up on the rectangle = 2cm
squares across = 9cm
2cm x 9cm = 18cm^2
for the triangle across would be 9cm
hight would be 6cm
9cm x 6cm = 54cm/2 = 27cm^2
18cm^2 + 27cm^2 = 45cm^2
Find the Inverse - f(x) = 5x - 6
Answer:
f⁻¹(x) =
Step-by-step explanation:
Given function,
→ f(x) = 5x - 6
We are supposed to find ths inverse of the given function. Consider the function, y = f(x).
→ y = 5x - 6
Add 6 to both sides.
→ y + 6 = 5x - 6 + 6
Solve the equation.
→ y + 6 = 5x
Division both sides by 5.
→ y + 6/5 = 5x/5
Solve the equation.
→ (y + 6)/5 = x
Can be re-written as,
→ x = (y + 6)/5
Now, recall f(x) = y, this implies x = f⁻¹(y).
→ f⁻¹(y) = (y + 6)/5
So the final answer is:
→ f⁻¹(x) = (x + 6)/5
2. C is at (-5.1) & D is at (7.6). Where is the midpoint on segment CD?
Answer:
1.25
Step-by-step explanation:
Find the average.
-5.1+7.6=2.5
2.5/2
1.25
Find the coordinates of the point after a 180∘ rotation about the origin.
(2,-3)
Answer: (-2,3)
Step-by-step explanation:
The formula for 180 degrees rotation is (-x,-y).
(2,-3). Plug the formula in, when plugging a positive and a negative, it's negative. When plugging a negative and a negative, it makes a positive.
So (-2, 3)
find a particular solution to the differential equation. 9. y" + 3y = -9 10. y" + 2y' - y = 10 11. y"(x) + y(x) = 24 12. 2x' + x = 312 13. y" – y + 9y = 3 sin 3t 14. 2z" +z = 9e2 dy dy 15. 5 +6y = xe 16. 0"() - 0(t) = sint dx² dx 17. y" + 4y = 8 sin 2t 18. y" – 2y + y = 8e 19. 4y" + 11y' – 3y = –21e31
We need to find the particular solution for the differential equations given below:
y" + 3y = -9
y" + 2y' - y = 101
y"(x) + y(x) = 24
2x' + x = 312
y" – y + 9y = 3 sin 3t
2z" +z = 9e2 dy dy
5 +6y = xe
0"() - 0(t) = sint dx² dx
y" + 4y = 8 sin 2t
y" – 2y + y = 8e
4y" + 11y' – 3y = –21e31
y" + 3y = -9
Homogeneous solution: Let
y = e^(mx)dy/dx = me^(mx)y" = m² e^(mx)y" + 3y = m² e^(mx) + 3e^(mx) = 0(m² + 3) e^(mx) = 0 or m² = -3m = + i√3 or - i√3
General solution: yh = c1 cos (√3 x) + c2 sin (√3 x)
Particular solution: For particular solution, let yp = A, so y'p = 0 and y''p = 0
Substitute the values in the differential equation.
y" + 3y = -9 0 + 3A = -9 A = -3
Therefore, the particular solution is yp = -3
General solution: y = c1 cos (√3 x) + c2 sin (√3 x) - 3
y" + 2y' - y = 10
Homogeneous solution: Let y = e^(mx)dy/dx = me^(mx)y" = m² e^(mx)y" + 2y' - y = m² e^(mx) + 2me^(mx) - e^(mx) = 0m² + 2m - 1 = 0 or m = -1 ± √2
General solution: yh = c1 e^(-x + √2 x) + c2 e^(-x - √2 x)
Particular solution: For particular solution, let
yp = Ax + B, so y'p = A and y''p = 0
Substitute the values in the differential equation.y" + 2y' - y = 10 0 + 2A - Ax - B = 10 2A - A = 10 and - A - B = 0 A = 5 and B = -5
Therefore, the particular solution is yp = 5x - 5General solution: y = c1 e^(-x + √2 x) + c2 e^(-x - √2 x) + 5x - 5
The given differential equations are solved to find the particular solution using the homogeneous solution. For homogeneous solutions, we let y = e^(mx) and find the general solution of the given differential equations. For particular solutions, we substitute the values in the given differential equations and solve for A, B, and other unknown constants. Finally, the general and particular solutions are added to get the solution of the given differential equations.
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Need Help ASAP please
A taxicab company charges a flat fee of $3.00, plus an additional fee of $2.50 per mile. How much is the fare for traveling 7 miles?
Answer:
38.5
Step-by-step explanation:
3.00 + 2.50= 5.50
5.50 x 7= 38.50
ans- 28.50 for 7 miles
Which equation has infinitely many solutions?
1/3(6x - 12) = 2(x-2)
1/2(4x+8)=2x+8
3(2x-7)= 6(x-4)-3
5 (2+1)= 3x + 2(x+1)+4
Answer: 1/3(6x-12)=2(x-2)
Step-by-step explanation:
Find the geometric mean between 3 and 15(Round to 1 decimal place)
Answer:
6.7
Step-by-step explanation:
Let x = the geometric mean
Then, 3/x = x/ 15
\(x^{2}\) = 45
x = \(\sqrt{45}\) = 6.7
Mitch ran 5/2 of a mile in 1/3 of an hour. How many hours will it take Mitch to run 1 mile?
It will take 15/2 hours for Mitch to run 1 mile. Cancelling out the common factors from numerator and denominator, the ratio reduces to 15/2.
Mitch ran 5/2 of a mile in 1/3 of an hour. To calculate how many hours it will take Mitch to run 1 mile, we need to use a ratio. The ratio is (5/2)/(1/3). To solve this, we need to multiply the numerator and denominator of the first fraction with the denominator of the second fraction, and then multiply the numerator and denominator of the second fraction with the denominator of the first fraction. So, the ratio becomes (5/2)*(3/1)/(1/3)*(2/1). Cancelling out the common factors from numerator and denominator, the ratio reduces to 15/2. This means that it will take 15/2 hours for Mitch to run 1 mile.
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A retailer anticipates selling 1,700 units of its product at a uniform rate over the next year. Each time the retailer places an order for x units, it is charged a flat fee of $25. Carrying costs are $34 per unit per year. How many times should the retailer reorder each year and what should be the lot size to minimize inventory costs? What is the minimum inventory cost? They should order units times a year. The minimum inventory cost is $
They should order 131.56 units 13 times a year. The minimum inventory cost is $2,557.68. A retailer anticipates selling 1,700 units of its product at a uniform rate over the next year. Flat fee of each order= $25, Inventory carrying cost per unit per year= $34.
Given that, A retailer anticipates selling 1,700 units of its product at a uniform rate over the next year.
Flat fee of each order= $25
Inventory carrying cost per unit per year= $34
Let the retailer order 'Q' units at a time. Then, The number of times that the retailer should order the inventory each year would be = Annual demand / Quantity of order Q
Each time that the order is placed, it is charged a flat fee of $25.
So, the total cost of ordering would be= Number of times that the retailer should order the inventory each year × flat fee of each order= (Annual demand / Quantity of order Q) × $25
The carrying cost is $34 per unit per year.
The inventory cost would be= Carrying cost per unit per year × average inventory during the year= $34 × (Q/2)
To minimize the inventory cost, the economic order quantity(Q*) would be given by the formula, Q* = √((2DS)/H),
where D = Annual demand, S = Setup cost per order, H = Holding cost per unit per year.
The order quantity 'Q' that minimizes the total inventory cost is called the economic order quantity
(EOQ).Q* = √((2DS)/H)= √((2 × 1,700 × $25) / $34)= 131.56
The EOQ is 131.56 units.
The number of orders that need to be placed each year would be given as= Annual demand / EOQ= 1,700 / 131.56= 12.92 (Approx 13 orders)
The minimum inventory cost would be = Total ordering cost + Total carrying cost
Total ordering cost = Number of orders per year × Setup cost per order= 13 × $25= $325
Total carrying cost = Carrying cost per unit per year × average inventory during the year= $34 × (131.56 / 2)= $2,232.68
Total cost = $325 + $2,232.68= $2,557.68
Hence, They should order 131.56 units 13 times a year. The minimum inventory cost is $2,557.68.
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solve the equation
pic:
The solution to the equation \((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\) is 10.3891
How to solve the equationFrom the question, we have the following parameters that can be used in our computation:
\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\)
Using the following trigonometry ratio
sin²(x) + cos²(x) = 1
We have
\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = (\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + 1 + e^2\)
The sum to infinity of a geometric series is
S = a/(1 - r)
So, we have
\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = \frac{1/2}{1 - 1/2} + \frac{9/10}{1 - 1/10} + 1 + e^2\)
So, we have
\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 1 + 1 + 1 + e^2\)
Evaluate the sum
\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 3 + e^2\)
This gives
\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 10.3891\)
Hence, the solution to the equation is 10.3891
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Provide an appropriate response.
A single six-sided die is rolled. Find the probability of rolling a number less than 3.
0.5
00.333
00.25
00.1
The probability of rolling a number less than 3 is 0.333.
We have,
Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event.
We know that, probability of an event = Number of favourable outcomes/Total number of outcomes.
Given that, a single, six-sided die is rolled.
Here, the sample space is {1, 2, 3, 4, 5, 6}
Total number of outcomes =6
we have, event is getting of a number less than 3.
Number of favorable outcomes =2
Probability of a number less than 3 = 2/6
= 1/3
=0.333
Therefore, the probability of rolling a number less than 3 is 0.333.
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A bag contains 16 cards numbered 1 through 16. A card is randomly chosen from the bag. What is the probability that the card has a multiple of 3 on it?
Answer:
Step-by-step explanation:
Probability is expressed as
Number of favorable outcomes/total number of possible outcomes
From the information given,
Total number of outcomes = 16
Starting from 1, the multiples of 3 between 1 and 16 are 3, 6, 9, 12 and 15
This means that the number of favorable outcomes is 5
Therefore, the probability that the card has a multiple of 3 on it is
5/16 = 0.3125
geometry help please ASAP
Answer:
861.56 km2
Step-by-step explanation:
the formula for the area of a trapazoid is
a= (a+b/2) + h
The John Jay Theater Dept has tickets at $6 for adults, $4 for teachers, and $2 for students. A total of 280 tickets were sold for one showing
with a total revenue of $1010. If the number of adult tickets sold was 10 less than twice the number of teacher tickets, how many of each
type of ticket were sold for the showing?
Define the variables for this situation. Use the variables a, t, and s.
Answer:
adults, a = 116
Students, s = 111
Teacher, t = 53
Step-by-step explanation:
Adult = $6
Teacher = $4
Students = $2
Let
Adults = a
Teacher = t
Students = s
Total revenue = $1010
Total tickets sold = 280
a = 2t - 10
a + s + t = 280
6a + 2s + 4t = 1010
Substitute a = 2t - 10 into the equation
2t - 10 + s + t = 280
6(2t - 10) + 2s + 4t = 1010
3t + s - 10 = 280
12t - 60 + 2s + 4t = 1010
3t + s = 280 + 10
16t + 2s = 1010 + 60
3t + s = 270 (1)
16t + 2s = 1070 (2)
Multiply (1) by 2
6t + 2s = 540 (3)
16t + 2s = 1070 (4)
Subtract (3) from (4)
16t - 6t = 1070 - 540
10t = 530
Divide both sides by 10
t = 530/10
= 53
t = 53
Substitute t =53 into (1)
3t + s = 270
3(53) + s = 270
159 + s = 270
s = 270 - 159
= 111
s = 111
Substitute the values of s = 111 and t = 53 into
a + s + t = 280
a + 111 + 53 = 280
a + 164 = 280
a = 280 - 164
= 116
adults, a = 116
Students, s = 111
Teacher, t = 53
The numerator of a fraction is 2 less then its denominator. If 2 is subtracted from the numerator and 1 is the added to the denominator then the fraction becomed 1/2. Find the fraction.
Answer:
Probably, 3/1.
Step-by-step explanation:
Just do the reverse of the instructions and you get your answer.
1+2=3
2-1=1
18 square root 10 times square root 2
In radical/ square root form
4√5 is the simplified form of square root of 10 times square root of 8 .
First, The square root of ten is √10
and, the square root of 8 is √8
Now, simplify square root of 10 times square root of 8.
= √10×√8
By radical property (√a×√b=√a×b
So,√10×√8=√(10×8)=√80
=√16×5
=4√5
Thus, 4√5 is the simplified form of square root of 10 times square root of 8 .
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Solve the following system of equations graphically on the set of axes below.
y=−x−8
3x−2y=6
Answer:
b
Step-by-step explanation:
b took the test np
A recycling truck begins its weekly route at the recycling plant at point A, as pictured on the coordinate plane below. It travels from point A to point B, then points C, D, and E, respectively, before returning to the recycling plant at point A at the end of the day. The truck’s route is illustrated on the coordinate plane below. If each unit on the coordinate plane represents one mile, what is the total distance the truck travels on its route?
Answer:
78
Step-by-step explanation:
Answer:
i need a photo
Step-by-step explanation:
find the common ratio for this geometric sequence 243, 27, 3
Answer:
The common ratio is 1/9
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
27/ 243
1/9
We can check by taking the third term and dividing by the second
3/27 = 1/9
PLEASE ANSWER TOADAY !!!!!!!!!!!!!!!!!
Answer:
most likely next spring
Step-by-step explanation:
Step-by-step explanation:
A middle school took all of its 6th grade students on a field trip to see a symphony at a theater that has 2400 seats. The students left 936 seats vacant. What percentage of the seats in the theater were filled by the 6th graders on the trip?
Answer:
61%
Step-by-step explanation:
2400-936= 1464 seats the kids filled.
1464filled ÷ 2400 total seats = .61 so 61%
Courtney sold 40 cantaloupes at the farmers' market and had 23 left. Which equation could be used to find x, the number of cantaloupes Courtney had originally?
Answer:
The equation that could be used to find \(x\), the number of cantaloupes Courtney had originally is \(x-40=23\) and the original number of cantaloupes are \(63\).
Step-by-step explanation:
Number of cantaloupes sold \(=40\).
Number of cantaloupes left \(=23\).
Let Courtney had \(x\) cantaloupes originally.
After selling \(40\) cantaloupes out of the total number of cantaloupes, Courtney is left with \(23\) cantaloupes.
So, the equation is \(x-40=23\).
\(\Rightarrow x=23+40\)
\(\Rightarrow x=63\)
Hence, the equation that could be used to find \(x\), the number of cantaloupes Courtney had originally is \(x-40=23\) and the original number of cantaloupes are \(63\).
1. If f(x) = (3x-2)/(2x+3), then f'(x) =
Answer:
\(f'(x)= \frac{13}{(2x+3)^2}\\\)
Step-by-step explanation:
\(f(x)= \frac{3x-2}{2x+3} \\\)
\(f'(x)=\frac{dy}{dx} = \frac{d}{dx}(\frac{3x-2}{2x+3})\\ f'(x)= \frac{(2x+3)\frac{d}{dx}(3x-2)-(3x-2)\frac{d}{dx}(2x+3) }{(2x+3)^{2} } \\f'(x)= \frac{(2x+3)(3)-(3x-2)(2)}{(2x+3)^{2} } \\\)
\(f'(x)= \frac{6x+9-6x+4}{(2x+3)^{2} }\\ f'(x)= \frac{13}{(2x+3)^2}\\\)
How are the triangles similar? Triangle 1 sides 68,54 Triangle 2 sides 63,68
A. SSS
B. SAS
C. AA
D. Not similar
A culture of bacteria has an initial population of 980 bacteria and doubles every 9 hours. Using the formula P_t = P_0\cdot 2^{\frac{t}{d}}P t =P 0 ⋅2 d t , where P_tP t is the population after t hours, P_0P 0 is the initial population, t is the time in hours and d is the doubling time, what is the population of bacteria in the culture after 13 hours, to the nearest whole number?
Answer: pt=2667.1484≈2667
Select the correct answer. Consider triangle EFG. A right triangle EFG with base EG of 10, Opposite EF of 8, and Hypotenuse FG of 12 What is the approximate measure of angle G
The approximate measure of angle G is 41.4° using laws of cosines. The correct option is C. 41.4°
From the question, we are to determine the measure of angle G
e = 12
f = 10
g = 8
From the law of cosines, we can write that
\(cos G = \frac{e^2 + f^2 - g^2}{2ef}\)
Putting the values into the equation
\(cos G = \frac{12^2 + 10^2 +8^2}{2\times 12 \times 10}\)
cosG = 0.75
G = cos⁻¹(0.75)
G = 41.4°
Hence, the approximate measure of angle G is 41.4°. The correct option is C. 41.4°
What are Law of cosines?When two sides of a triangle and their enclosed angle are known, the law of cosines can be used to compute the third side of the triangle as well as the angles of the triangle if all three sides are known.The law of cosines, sometimes referred to as the cosine formula, cosine rule, or al-theorem, Kashi's in trigonometry connects the lengths of a triangle's sides to the cosine of one of its angles.To learn more on Law of cosines with the given link
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Answer:
Step-by-step explanation:
The approximate measure of angle G is 41.4° using laws of cosines. The correct option is C. 41.4°
From the question, we are to determine the measure of angle G
e = 12
f = 10
g = 8
From the law of cosines, we can write that
Putting the values into the equation
cosG = 0.75
G = cos⁻¹(0.75)
G = 41.4°
Hence, the approximate measure of angle G is 41.4°. The correct option is C. 41.4°
What are Law of cosines?
When two sides of a triangle and their enclosed angle are known, the law of cosines can be used to compute the third side of the triangle as well as the angles of the triangle if all three sides are known.
The law of cosines, sometimes referred to as the cosine formula, cosine rule, or al-theorem, Kashi's in trigonometry connects the lengths of a triangle's sides to the cosine of one of its angles.
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If the equation of f(x) goes through (1, 4) and (4, 6), what points does f-1(x) go through?.
The positions through which the equation of f^-1(x) travels are: (4, 1), (6, 4)
What are equations?A mathematical statement called an equation is comprised of two expressions joined together with the equal sign.
A formula would just be 3x - 5 = 16, for instance.
When this equation is solved, we observe that the value of the variable x is 7.
So, (1, 4) and (4, 6) are points through which the equation of f(x) goes.
If the f (x) equation contains (x, y).
Therefore, the f^-1(x) equation is as follows: (y, x).
Here, the f (x) equation passes through the following points: (1, 4) and (4, 6).
So, (4, 1) and (6, 4) are the points through which the equation of f^-1(x) goes through.
Therefore, the positions through which the equation of f^-1(x) travels are:
(4, 1), (6, 4)
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Correct question:
If the equation of f(x) goes through (1,4) and (4,6), what points does f^-1(x) go through?
Use the circle to answer the questions.
A circle with radius 5.4 centimeters.
The diameter is
cm.
The circumference in terms of Pi is
Using 3.14 for Pi, the approximate circumference of the circle is
cm.
Answer:
157/270
Step-by-step explanation:
Answer:
10.8
10.8
33.9
Step-by-step explanation:
Hi! I need help FAST IM TIMED. The product of 84.12 and which number will have three decimal places?
4.22
10.51
14.163
19.3
PLEASE HELP!!
Step-by-step explanation:
The product of 84.12 and which number will have three decimal places?
4.22
10.51
14.163
19.3
84.12 * 19.3 = 1623.516