Answer:
The conditioned stimulus is the Luther Vandross
Explanation:
A conditioned stimulus is a stimulus that triggers a response in an organism that has been conditioned (or learned). In this case Jada's husband putting the song (conditioned stimulus) on every time they are sexually intimate has caused her response to the stimulus to be becoming aroused.
What happens to the amplitude of the resultant wave when two sound waves with equal amplitude constructively interfere?
Answer:
For two waves of equal amplitude interfering constructively, the resulting amplitude is twice as large as the amplitude of an individual wave. For 100 waves of the same amplitude interfering constructively, the resulting amplitude is 100 times larger than the amplitude of an individual wave.
Read the following paragraph and answer the question. "Ernest Cline is an American Screenwriter and author. Ernest was born in 1972. He started his writing career in 1992
doing spoken word poetry. His best known works include 'Dance Monkey Dance' and 'When I Was a Kid. He then moved to film, as the screenwriter of the film Fanboys. He then released one of the most entertaining novels of all time, Ready Player One. Today Cline is still working, writing for many projects." What is the structure of this paragraph?
A. Causeleffect
B. Sequence
C. Problem/solution
D. Comparison
The structure of the given paragraph about Ernest Cline is sequence writing.
The correct option is B.
What is sequence writing?Writing that organizes information or events in a certain order is known as sequence writing. In order for the reader to understand and follow the flow of events, sequence writing aims to convey information or events in a straightforward and logical manner.
For instance, the phases in a procedure are described sequentially in instructional writing to aid the reader in comprehending how to carry out a task. Events in narratives are presented chronologically to make it easier for the reader to follow the plot.
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importance of projectile
PLZZ ANSWER THE QUESTION
Answer:
I would say a but it could be b too. It’s definetly not the last two.
I say a because no reason to go up the hill and that’s not gonna give her speed going down so. Good luck!
Explanation:
At 3:00 P.M., a bank robber is spotted driving north on I-15 at milepost 129. His speed is 135.0 mi/h. At 3:37 P.M., he is spotted at milepost 182 doing 103.0 mi/h. (Assume a straight highway). Assume north to be positive. What is the bank robber’s displacement during this time interval? Enter a positive value if the displacement is toward north and enter a negative value if the displacement is toward south.
To find the displacement of the bank robber during this time interval, we need to calculate the distance he traveled in each direction and then find the vector difference between his initial and final positions.
From 3:00 P.M. to 3:37 P.M., the bank robber traveled for 37 minutes = 0.617 hours at a speed of 135.0 mi/h. Therefore, he traveled a distance of:
d1 = v1 x t1 = 135.0 mi/h x 0.617 h = 83.3 miles north
From 3:00 P.M. to 3:37 P.M., the bank robber traveled for 37 minutes = 0.617 hours at an average speed of 103.0 mi/h. Therefore, he traveled a distance of:
d2 = v2 x t2 = 103.0 mi/h x 0.617 h = 63.5 miles north
To find the displacement, we need to subtract the initial position from the final position. The initial position is at milepost 129 and the final position is at milepost 182. Therefore, the displacement is:
displacement = final position - initial position
displacement = 182 - 129 = 53 miles north
Since the displacement is in the positive direction, we enter a positive value. Therefore, the bank robber's displacement during this time interval is 53 miles north.
Maria read on an internet blog that infrared light is dangerous to humans. According to the blog, infrared light exposure is responsivle for a number of detrimental effects in humans. Which of these can actually be caused by exposure to infrared light?
a-overheating
b-skin cancer
c-radiation sickness
d-memory less
Of the options listed, the only effect that can be caused by exposure to infrared light is overheating (option a).
Infrared light is a form of electromagnetic radiation that is invisible to the human eye but can be detected as heat. When exposed to high levels of infrared light, such as in close proximity to a powerful infrared source, it can lead to overheating of the body or objects. Skin cancer (option b) is not directly caused by infrared light. It is primarily associated with overexposure to ultraviolet (UV) radiation from the sun or artificial sources like tanning beds. UV radiation falls in the higher energy range of the electromagnetic spectrum, while infrared radiation has lower energy. Radiation sickness (option c) is caused by exposure to high-energy ionizing radiation, such as gamma rays or X-rays. Infrared light does not possess enough energy to cause ionization and is therefore not capable of inducing radiation sickness. Memory loss (option d) is not a known effect of exposure to infrared light. Memory loss can be attributed to various factors, such as neurological conditions, head injuries, or aging, but not specifically to infrared light exposure. In summary, while exposure to high levels of infrared light can lead to overheating, it does not cause skin cancer, radiation sickness, or memory loss.
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If the leprechaun runs towards the point of origin and arrives in 0.5 seconds, what is his velocity?
32 m/s
20 m/s
12 m/s to the right
20 m/s to the right
Answer:
answer is 12 I'm pretty sure
How are particles behaving in solid vs gas when it comes to sound?
Answer:
Sound waves have to travel through solids, gases, and liquids. Sound waves vibrate through the air in matter. Molecules in solids are packed tightly. This allows sound to travel faster through a solid than gas.
The phase angle in a circuit is 45° what's the power factor of the circuit
Answer:the power factor of the circuit is 96% to 75%
Explanation:
A 50 kg girl is standing in a lift which is accelerating upwards at 3 m/s^2. What will be the upward force from the lift floor on the girl's feet (in N)?
Answer:
Approximately \(641\; {\rm N}\) (assuming that \(g = (-9.81)\; {\rm N \cdot kg^{-1}}\).)
Explanation:
Forces on this person:
Weight (downward, from the earth).Normal force (the upward force from the floor of the elevator.)Let \(m\) denote the mass of this person. It is given that \(m = 50\; {\rm kg}\). The weight of this person will be:
\(\begin{aligned}(\text{weight}) &= m\, g \\ &= (50\; {\rm kg})\, ((-9.81)\; {\rm N\cdot kg^{-1}}) \\ &\approx 490.5\; {\rm N}\end{aligned}\).
(The value of weight is negative since weight points downwards.)
Let \(a\) denote the acceleration of this person. It is given that \(a = 3\; {\rm m\cdot s^{-2}}\) (since this person is accelerating upwards, the value of \(a\) will be positive.) The net force on this person will be:
\(\begin{aligned}(\text{net force}) &= (\text{mass})\, (\text{acceleration})\\ &= (50\; {\rm kg})\, (3\; {\rm m\cdot s^{-2}}) \\ &\approx 150\; {\rm N}\end{aligned}\).
Note that this net force is also equal to the vector sum of all the forces on this person. In other words:
\(\begin{aligned}(\text{net force}) &= (\text{weight}) + (\text{normal force})\end{aligned}\).
Rearrange this equation to find \((\text{normal force})\):
\(\begin{aligned}(\text{normal force}) &= (\text{net force}) - (\text{weight}) \\ &\approx 150\; {\rm N} - ((-490.5)\; {\rm N}) \\ &\approx 641\; {\rm N}\end{aligned}\).
Hence, the upward force on this person from the floor of the elevator will be approximately \(641\; {\rm N}\).
A freight car with a mass of 10 metric tons is rolling at 108 km/h along a level track when it collides with another freight car, which is initially at rest. If the speed of the cars after they couple together is 36 km/h, what is the mass of the second car?1) 40 metric tons2) 20 metric tons3) 10 metric tons4) 5 metric tons
Given data:
* The mass of the first car is 10 metric tons.
* The initial speed of the first car is 108 km/h
* The speed of couple of both the cars after the collision is 36 km/h.
* The initial speed of the second car is zero. ial
Solution:
By the law of conservation of momentum,
\(mu_1+Mu_2=mv_1_{}_{}+Mv_2\)where m is the mass of first car, M is the mass of second car, u_1 is the initial velocity of first car, u_2 is the initial velocity of second car, v_1 is the final velocity of first car, and v_2 is the final velocity of second car,
Substituting the known values,
\(\begin{gathered} 10\times108+0=(m+M)\times36 \\ 1080=(10+M)\times36 \\ 10+M=30 \\ M=20\text{ metric tons} \end{gathered}\)Thus, the mass of the second car is 20 metric tons.
Hence, option 2 is the correct answer.
a mass of 2.00 kg rest on a rough horizontal table. The coefficient of static friction between the block and the table is 0.60. The block is attached to a hanging mass by a string that goes over a smooth pulley,as shown in the diagram. Determine the largest mass that can hang in this way without forcing the block to slide.
Answer:
1.2 kg
__________________________________________________________
We are given:
Mass of the block = 2 kg
Coefficient of Static Friction = 0.6
__________________________________________________________
Friction Force on the Block:
Finding the Normal Force:
We know that the normal force will be equal and opposite to the weight of the 2 kg block
So, Normal Force = mg
replacing the variables with the given values
Normal Force = (2)(9.8) [Taking g = 9.8]
Normal Force = 19.6 N
Friction force on the Block:
We know that:
Coefficient of Static Friction = Static Friction Force/Normal Force
replacing the variables
0.6 = Static Friction force / 19.6
Static Friction force = 0.6*19.6 N [Multiplying both sides by 19.6]
Static Friction force = 11.76 N
__________________________________________________________
Largest Mass that can Hang:
We know that the Static Friction force is 11.76 N, this means that a force of 11.76 N will be applied to keep the object at rest
So, if the weight of the second block is less than the static friction force, it will hang
Weight of the second block ≤ 11.76
We know that weight = mg
mg ≤ 11.76
m(9.8) ≤ 11.76 [since g = 9.8]
m ≤ 1.2 kg [dividing both sides by 9.8]
From this, we can say that the maximum mass of the second block is 1.2 Kg
Cells use nutrients and oxygen to supply the body with the energy it needs. What three-body systems are working together in this situation?
A
nervous, digestive, and circulatory systems
B
digestive, circulatory, and excretory systems
C
circulatory, immune, and respiratory systems
D
digestive, respiratory, and circulatory systems
Answer:
The respiratory system provides oxygen for cells, while the circulatory system transports oxygen to cells.
Explanation:
so the answer is D
A student must design an experiment to determine the gravitational mass of an object. Which of the following experiments could the student use? Select two answers.
Answer: a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Explanation:
The options are:
a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
b. Place the object on a surface of negligible friction and pull the object horizontally across the surface with a spring scale at a non constant speed such that a motion detector can measure how the objects speed as a function of time changes.
c. Place the object on a surface that provides friction between the object and the surface. Use a surface such that the coefficient of friction between the object and the surface is known. Pull the object horizontally across the surface with a spring scale at a nonconstant speed such that a motion detector can measure how the objects speed as a function of time changes.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Gravitational mass simply has to do with how the body responds to the force of gravity. From the options given, the correct options are A and D.
For option A, by balancing the torque, the mass can be calculated. Since the known mass and the distance has been given here, the unknown mass can be calculated.
For option D, here the gravitational force can be balanced by the spring force and hence the mass can be calculated.
The experiments which a student can use to determine the gravitational mass of an object are:
A. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium. D. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.According to the complete question, we can see that a student is trying to find the gravitational mass of an object and he has to perform a series of steps to get the answer he needs and we need to show the two experiments which would be valid.
As a result of this, a gravitational mass of an object is the feature of a system which affects the amount of gravitational force which acts on it.
WIth this in mind, we can see that gravitational mass of an object, we would use a fulcrum and a spring constant.
Therefore, the correct answers are options A and D
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Mass
7. If the mass of the diver is 75 kg. What is the height he jumped
from?
Answer:
The height from which the diver jumped can be calculated using the laws of motion and the principle of conservation of energy.
Let's assume that the diver jumped from a platform with an initial velocity of zero. The potential energy (PE) of the diver at the top of the platform is given by:
PE = mgh
Where m is the mass of the diver, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the diver jumped.
When the diver jumps, the potential energy is converted into kinetic energy (KE) as the diver moves downwards. The kinetic energy of the diver just before hitting the water is given by:
KE = (1/2)mv^2
Where v is the velocity of the diver just before hitting the water.
According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy just before hitting the water. Therefore, we can equate the two equations above and solve for h:
mgh = (1/2)mv^2
h = (1/2)v^2/g
We need to find the value of v to calculate h. We can use the kinematic equation:
v^2 = u^2 + 2as
Where u is the initial velocity (which is zero in this case), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance travelled by the diver (which is equal to h).
Substituting the values, we get:
v^2 = 2gh
v^2 = 2 * 9.8 * h
v^2 = 19.6h
Therefore:
h = v^2/(19.6)
Now, let's assume that the velocity of the diver just before hitting the water was 10 m/s (a reasonable value for a diving competition). Then:
h = (10^2)/(2*9.8) = 51 meters
Therefore, the height from which the diver jumped is approximately 51 meters.
Motion maps for two objects, Y & Z, are shown.
How many seconds does Object Z start before Object Y?
- 2
- 3
- 4
- 5
Answer: it’s 3 seconds
Explanation:
Answer:
B
Explanation:
3 seconds, hope it helps
How is a continuous spectra is formed?
Answer:
Hello There!!
Explanation:
They are produced by the photodissociation of negatively charged hydrogen ions (H−).
hope this helps,have a great day!!
~Pinky~
Can someone help me with this question AASP
You arrive at a crime scene in a high traffic area shortly after first responders have removed the victim. There are a number of bloody footprints at the scene. After ensuring that the scene is secured from further contamination, what is the most important step to take?
Group of answer choices
obtain the names of all medical personnel who had been at the site
obtain statements from witness
take photographs of all visible footprints
Search for more evidence
Answer:
It seems like c or d I'll say c
Answer:
I believe the answer to be D, search for more evidence. You have to gather evidence while it's still fresh
An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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why do astronauts weigh less on the moon than on earth
Answer:
Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.
Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.
Which description tells two processes scientists think move Earth's lithospheric plates?
Responses
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and friction between the plate and the asthenosphere
gravity acting on the edges of plates and friction between the plate and the asthenosphere
convection in the mantle and pressure of magma on the edge of the plate
The description that tells two processes that scientists think move Earth's lithospheric plates is convection in the mantle and pressure of magma on the edge of the plate.
What is the Earth's lithosphere?The Earth's lithosphere is the rocky outer part of Earth which is made up of the brittle crust and the top part of the upper mantle.
The Earth's lithosphere deflects the convections and as the convections churn clockwise of anticlockwise, they drag the lithosphere with it via friction an this is what is stipulated to cause tectonic plate movements.
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Answer: convection in the mantle and pressure of magma on the edge of the plate
Explanation: I took the unit test
Suggest one reason why the bricklayer needs a higher energy diet than the computer operator
Answer:
he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.
PLS HELP
Which sentence correctly explains the process and conditions needed for sleet to form?
During thunderstorms and extremely cold temperatures, water droplets freeze in layers and form balls or chunks of ice.
Both the temperature of the cloud and the temperature of the air must be below freezing in order for the flakes to fall from the sky.
A liquid form of precipitation that is formed in above freezing temperatures becomes heavier as it falls the ground in the form of raindrops.
Ice crystals melt as they fall through a warm layer of air and then refreeze into small ice pellets as they pass through a colder layer of air.
The statement 'Ice crystals melt as they fall through a warm layer of air and then refreeze into small ice pellets as they pass through a colder layer of air' is correct.
Describe the characteristics of a thunderstorm.A cloud that produces both rain & lightning is called a thunderstorm. Thunderstorms are dangerous in general. All thunderstorms produce lightning as a byproduct. In the United States, lightning annually results in an estimated of 300 injuries & 80 fatalities.
What occurs when a thunderstorm strikes?A thunderstorm is the small-scale storm that includes both thunder and lighting. Moreover, it frequently delivers heavy rain as well as violent gusts. Certain thunderstorms have a chance of producing hail and/or tornadoes. Localized big snow showers during the winter may also include thunder and lightning.
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What happens to the temperature of a substance while it is changing state?
Answer:
its temperature stays constant
Explanation:
A force of 64 N gives an object an acceleration of 23.53 m/s^2. What is the mass of the object?
A-2.00 kg
B-1505 kg
C-2.72 kg
D-736 kg
An object of mass 2kg moves in circles at radius 8m at uniform speed of 30m/s calculate. A_angular velocity B_ceritripetal force
The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.
The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.
Calculation:-
A. angular velocity ω = v/r
= 30 /8
= 3.75 m/s
B. Centripetal force = mv²/r
= 2×30²/8
= 225 N
There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.
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Say a funny joke and whoever makes me laugh the hardest gets brainliest or however u spell it haha
Answer:
i cant make funny joke
Explanation:
but i can be alive.
wait no, im failing at that currently.
An industrial/organizational psychologist wants to improve worker productivity for a client firm, but first he needs to gain a better understanding of the life of the typical white-collar professional. Fortunately, he has access to the 2020 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, which surveyed a sample of 650 white-collar professionals (250 legal professionals and 400 other professionals).
One of the survey questions was, "During the average workday, how many hours do you spend attending meetings?" For the subsample of legal professionals (n = 200), the mean response was M = 2.0 hours, with a sample standard deviation of s = 5.1 hours.
The estimated standard error is = 0.323.
The psychologist can be 99% confident that the interval from _____ to _____ includes the unknown population mean µ.
Based on the research data, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.
What is confidence Interval?A confidence interval is a range of values within which a researcher can be fairly certain that the true value of the mean can be found.
The confidence Interval of the survey above is calculated using the formula:
\( x ± z( σ/√n)\)
where
x is the sample mean,σ is the population standard deviation,n is the sample size, and z is the z-value for the selected confidence level.From the data provided;
x = 2.0
σ = 5.1
n = 200
z = 2.576 for 99% confidence
Therefore, the confidence Interval is:
\( 2.0 ± 2.576( 5.1/√200)\)
Confidence interval = 2.0 ± 0.93.
Therefore, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.
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Activity: I Remember! List all the Social Sciences you can remember from your class on Disciplines and Ideas in the Social Sciences.
Answer:
Anthropology, Economics and management, History, Human services, political science, psychology, sociology
Two spheres A and B of negligible dimensions and masses 1 kg and √3 kg respectively, are supported on the smooth circular surface, fixed to the ground with a centre O and radius of 0.1m. The spheres are joined by the cord shown in length π/20 m; determine the angles α and β corresponding to the position of equilibrium of the spheres with respect to the vertical passing through O.
Answer:
α = π/3
β = π/6
Explanation:
Use arc length equation to find the sum of the angles.
s = rθ
π/20 m = (0.1 m) (α + β)
π/2 = α + β
Draw a free body diagram for each sphere. Both spheres have three forces acting on them:
Weight force mg pulling down,
Normal force N pushing perpendicular to the surface,
and tension force T pulling tangential to the surface.
Sum of forces on A in the tangential direction:
∑F = ma
T − m₁g sin α = 0
T = m₁g sin α
Sum of forces on B in the tangential direction:
∑F = ma
T − m₂g sin β = 0
T = m₂g sin β
Substituting:
m₁g sin α = m₂g sin β
m₁ sin α = m₂ sin β
(1 kg) sin α = (√3 kg) sin (π/2 − α)
1 sin α = √3 cos α
tan α = √3
α = π/3
β = π/6