Jen makes a rectangular banner. It is 3/4 yard long and 1/4 yard wide. What is the area, in square yards, of the banner? Illl give brainlist if you answer please

Answer:

-2

Step-by-step explanation:

from one point to another, you go down 2 and over 1

Answer:

the answer is -2

Step-by-step explanation:

this is because for every unit it goes to the right it goes down 2 which makes it negitive if it is facing down and positive if facing up.

Side of square = Radius of circle = 4cm

Area of full circle

= πr²

= (22/7) × 4cm × 4cm

= 352/7 cm²

Area of the quarter of circle

= Area of full circle/4

= (352/7)/4

= (352/7) × (1/4)

= 352/28

= 12.571 {approximately}

The cost of 4th book is $22.

In maths, the average value in a set of numbers is the middle value, calculated by dividing the total of all the values by the number of values. When we need to find the average of a set of data, we add up all the values and then divide this total by the number of values.

Given that, Jenny bought 4 books in a bookstore. The prices of the first 3 books were $10, $15 and $25.

Let the cost of 4th book be $x.

Now, average = (10+15+25+x)/4

(50+x)/4 =18

50+x =72

x=$22

Therefore, the cost of 4th book is $22.

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Answer:

28×4/7=16

Step-by-step explanation:

well it seems as the most logical answer but it also seems the realist one to pick for me personally but I would think it is better to see mixed opinions but I think it's the 2nd one

According to the given statement This integral will give you the volume of the solid..

To find the volume of the solid obtained by rotating the region bounded by the curves 2x = y² and x = 0, we can use the method of cylindrical shells.

First, let's graph the given curves to visualize the region. The curve 2x = y² is a parabola opening to the right, and the line x = 0 is the y-axis.
Next, we need to find the limits of integration. From the given information, we know that x ranges from 0 to some value. To find this value, we set the equations equal to each other and solve for x:

2x = y²
x = y²/2

Since x cannot be negative, we take the positive square root of both sides:
√x = y/√2
√2x = y

So, the limits of integration for y are √2x and 0, and the limits of integration for x are from 0 to some value.

To set up the integral for the volume, we use the formula:

V = ∫[a, b] 2πrh dx

where r is the distance from the axis of rotation to the curve (in this case, the x-axis), and h is the height of the cylindrical shell.

In this case, the radius r is x, and the height h is given by the difference between the y-values of the curves at a particular x-value:

h = √2x - 0

Plugging these values into the integral, we get:

V = ∫[0, b] 2πx(√2x - 0) dx

Simplifying this integral will give you the volume of the solid.

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To find the volume of the solid obtained by rotating the region bounded by the given curves \(\(2x = y^2\) and \(x = 0\)\), we can use the method of cylindrical shells. The volume can be calculated using the integral:

\(\[v = \int_{0}^{2} 2\pi x\sqrt{2x} \, dx\]\)

The given curves are \(\(2x = y^2\) and \(x = 0\).\) We want to rotate the region bounded by these curves about the y-axis to form a solid.

To use the method of cylindrical shells, we divide the region into thin cylindrical shells. The radius of each shell is the x-coordinate, which is x, and the height is the difference between the y-values on the curve, which is \(\(\sqrt{2x}\)\).

Now, we set up the integral. The integral represents the sum of the volumes of all the cylindrical shells. The integral is evaluated over the range from x = 0 to x = 2, as determined by the bounds of the region.

Evaluating the integral gives us the volume of the solid:

\(\[v = 2\pi\int_{0}^{2} x^{3/2} \, dx\]\)

Integrating this expression yields:

\(\[v = 2\pi\left[\frac{2}{5}x^{5/2}\right]_{0}^{2}\]\)

Evaluating the limits of integration, we get:

\(\[v = 2\pi\left[\frac{2}{5}(2)^{5/2} - \frac{2}{5}(0)^{5/2}\right]\]\)

Simplifying this expression gives us the volume v of the solid.

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Answer:

B)   5029 < 5.128

D)   2.001 < 2.100

E)    9.401 > 9.309

Step-by-step explanation:

B)   5029 < 5.128

D)   2.001 < 2.100

E)    9.401 > 9.309

Answer:0.166

Step-by-step explanation:I used a calculator

Answer:

5

Step-by-step explanation:

We know that a^2+b^2=c^2 from the Pythagorean theorem   where a and b are the legs and c is the hypotenuse

4^2+3^2 = c^2

16+9 = c^2

25 = c^2

Taking the square root of each side

sqrt(25) = sqrt(c^2)

5 =c

Answer:

d = 5 m

Step-by-step explanation:

The diagonal divides the rectangle into 2 right triangles with legs 3 and 4 and hypotenuse h

Using Pythagoras' identity in one of the right triangles, then

d² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )

d = \(\sqrt{25}\) = 5

The domain of H is the set {-6, -2} while the range of H is the set {-7, -5, 1}

The set is H={(-6,-7),(-2,1),(-2,-5)}.

We need to find the domain and range of H.

In mathematics, a domain is the set of all possible inputs (also known as the independent variable) of a function. On the other hand, the range is the set of all possible outputs (also known as the dependent variable) of a function.

The domain is also known as the input values while the range is also referred to as the output values. Let’s begin with the domain of H. The first element in the ordered pair is x and the second element is y.

Therefore, the domain is the set of all x values in H. Therefore, the domain of H = {-6, -2}.Next, we need to determine the range of H. The range is the set of all y values in H. Therefore, the range of H = {-7, -5, 1}.

To write in set notation, we write:{(-6,-7),(-2,1),(-2,-5)} ⇒ Domain = {-6, -2}⇒ Range = {-7, -5, 1}

In conclusion, the domain of H is the set {-6, -2} while the range of H is the set {-7, -5, 1}. The domain is the set of all possible inputs (independent variable) while the range is the set of all possible outputs (dependent variable) of a function.

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(a) The height after t years is given by: h(t) = 0.75t^2 + 5t + 12

(b) The shrubs are 54 centimeters tall when they are sold.

To solve this problem, we need to integrate the given differential equation dh/dt = 1.5t + 5 with respect to t to obtain an expression for h in terms of t. Then we can use this expression to answer the questions asked.

Integrating both sides of the equation with respect to t, we get

∫dh = ∫(1.5t + 5) dt

h = 0.75t^2 + 5t + C

where C is the constant of integration. To find C, we use the initial condition that the seedlings are 12 centimeters tall when planted, i.e., h(0) = 12. Substituting t = 0 and h = 12 in the above equation, we get

12 = 0.75(0)^2 + 5(0) + C

C = 12

Therefore, the expression for h in terms of t is

h = 0.75t^2 + 5t + 12

(a) To find the height after t years, we simply substitute the value of t in the above equation

h(t) = 0.75t^2 + 5t + 12

(b) The shrubs are sold after 6 years of growth and shaping. Therefore, we need to find h(6) to determine their height at the time of sale

h(6) = 0.75(6)^2 + 5(6) + 12

= 54 cm

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The given question is incomplete, the complete question is:

Tree growth an evergreen nursery usually sells a certain shrub after 6 years of growth and shaping. the growth rate during those 6 years is approximated by dh/dt = 1.5t + 5 where t is the time in years and h is the height in centimeters. the seedlings are 12 centimeters tall when planted (a) find the height after years. (b) how tall are the shrubs when they are sold?

The correct answer is c. Learning curves are important for estimating performance improvement as workers become experienced.

Learning curves are often used in project management to estimating the time, effort, and resources required to complete a task or project. They help to estimate how long it will take for a worker or team to become proficient at a task or process, based on the amount of time and effort that they have put into it.

This can be helpful in estimating performance improvement as workers become more experienced and efficient in their work. The concept of a learning curve is a curved line that represents the rate of improvement over time, which is why the term "curve" is relevant. While learning curves do involve some math, they are not primarily focused on helping new PMs understand required math, nor are they used for visualization of curved mechanical parts or estimating cost improvement as parts become "broken in."
Learning curves are important for:
c. estimating performance improvement as workers become experienced.
Learning curves represent the progress made in a skill or job over time, whereas a curve illustrates the relationship between experience and efficiency. As workers become more experienced, their performance typically improves, which can be estimated using a learning curve in various industries and tasks.

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Answer:

hen she divided 9 by integer b and got −3. Find. Colleen divided integer a by −5 and got 9. Then she divided 9 by integer b and got −3. Find the quotient of integer a and integer b. a b = Categories Uncategorized. Leave a Reply Cancel reply. Your email address will not be published.

Step-by-step explanation:

To determine if lab 1 is reporting lower cholesterol levels, on average, than lab 2, a paired t-test for means should be used.

This is because the physician collected pairs of blood samples from each patient and wants to compare the means of the two labs' cholesterol level measurements. The paired t-test for means is appropriate for comparing the means of two related samples, in this case, the blood samples from each patient tested by lab 1 and lab 2.

A paired t-test for means should be used to determine if lab 1 is reporting lower cholesterol levels, on average, than lab 2. This test is appropriate because the data consists of paired samples from the same patients, and the goal is to compare the means of the differences between the two labs.

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Inequality can be used to determine x, the greatest number of 120-kilogram crates that can be loaded onto the shipping container is  8000 + 120C <= 27500

An inequality is a relationship that allows us to contrast two or more mathematical expressions.

Knowing that;

Each carton weighs 120 kg.

The container's maximum weight when loaded is 27500 kg.

Weight of the container as it is currently loaded: 8000 kg

Now that we have merged, we have;

Solution

because 8000 grams have already been loaded kilograms

into the container

each crate weighs 120 kilograms.

so 8000 + 120C <= 27500

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Yvonne stops for water after 6/8 on the race for one more time.

A fraction is written in the form of a numerator and a denominator where the denominator is greater that the numerator.

Example: 1/2, 1/3 is a fraction.

We have,

Yvonne ran 3/8 of the race stopping for water.

This means,

After every 3/8 Yvonne stopped for water.

Now,

Total distance = 1

Distance remaining after one stop.

= 1 - 3/8

= 5/8

And,

Another stop will be after 3/8.

This means,

Distance remains after the second stop.

= 5/8 - 3/8

= 2/8

Now,

1 - 2/8

= 6/8

The second stop is after 6/8 of the race.

Thus,

Yvonne stops for water after 6/8 on the race for one more time.

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Answer:

[see below]

Step-by-step explanation:

Assuming that the equation is y = 10x + 1

(12, 4)

4 = 10(12) + 1

4 = 120 + 1

4 ≠ 121

(12, 4) is not a solution.

(1, 1.5)

1.5 = 10(1) + 1

1.5 = 10 + 1

1.5 ≠ 1

They are not solutions to the equation.

Hope this helps.

Answer:

bath

Step-by-step explanation:

Answer:

y = 8.7

Step-by-step explanation:

Assuming we can use decimal places, y is equal to 8.7.

In programming, += is often used as a substitute for y = y + x (example)

Therefore, y = y + 3.7, and since y = 5, y = 5 + 3.7, y = 8.7

Answer:

The relation is a function because there isnt a repeating y

Answer:

y= -3x

Step-by-step explanation:

Hence, the measure of the angle is 40 degrees, its supplementary angle is 140 degrees, and its complement is 50 degrees.

Given that the measure of the supplement of an angle is 30 degrees less than five times the measure of the complement. Let's assume the measure of an angle is x.

Complementary angles: Two angles are called complementary if their sum equals 90°.If the measure of an angle is x, then its complementary angle will be 90° - x.

Supplementary angles: Two angles are called supplementary if their sum equals 180°.If the measure of an angle is x, then its supplementary angle will be 180° - x.

Now we can translate the given data in the form of equations.

Supplementary angle = 180° - x

Complementary angle = 90° - x

We are given that, The measure of the supplement of an angle is 30 degrees less than five times the measure of the complement.

Using the above equations, we can form the following equation:

Supplementary angle = 5(Complementary angle) - 30°

Substituting the values of supplementary and complementary angles, we get:

180° - x = 5(90° - x) - 30

Simplifying and solving this equation for x:

180° - x = 450° - 5x - 30°180° - x

= 420° - 5x6x

= 240x

= 40

Therefore, the measure of the given angle is x = 40°.

Supplementary angle = 180° - x = 180° - 40° = 140°

Complementary angle = 90° - x = 90° - 40° = 50°

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Answer:

She earned 80% right

Step-by-step explanation:

You start by dividing the points earned by the total questions.

\( \frac{24}{30 } = .8\)

then multiply by 100

\(.8 \times 100 = 80\)

then you add the percent symbol

\(80\%\)

The total number of cookies baker sold in all are 350 cookies.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Given that, sugar cookies make up 38% of all sales for a local baker's cookie sales.

Let the total number of cookies be x.

Now, 38% of x=133

38/100 ×x=133

x=13300/38

x=350

Therefore, the total number of cookies baker sold in all are 350 cookies.

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Answer:

Where is the questions?

Step-by-step explanation:

Me + The upcoming championship high school football game is a big deal in your little town. The problem is, it is being played in the next biggest town, which is two hours away! To get as many people as you can to attend the game, you decide to come up with a ride-sharing app, but you want to be sure it will be used before you put all the time in to creating it. You determine that if more than three students share a ride, on average, you will create the app.

You conduct simple random sampling of 20 students in a school with a population of 300 students to determine how many students are in each ride-share (carpool) on the way to school every day to get a good idea of who would use the app. The following data are collected:

6 5 5 5 3 2 3 6 2 2

5 4 3 3 4 2 5 3 4 5

You and your partner will construct a 90% confidence interval and 95% confidence interval for the mean number of students who share a ride to school, then you will compare and interpret the results.

Part A: Decide which partner will construct each confidence interval, and then state the parameter and check the conditions.

Part B: Construct the confidence interval. Be sure to show all your work, including the degrees of freedom, critical value, sample statistics, and an explanation of your process.

Part C: Interpret the meaning of the confidence interval, and describe the difference in the width of the interval and the margin of error.

Part D: Use your findings to explain whether you should develop the ride-share app for the football game. = My brain hurts!!!

Answer:

2y=3x=-4

Step-by-step explanation:

grouping like terms

y+ly =4x-x=-4

2y=3x=-4

Answer:

#7

Ratio of corresponding sides (determined by opposite angles)

The ratios are equal, the polygons are similar

# no number

Ratios:

Yes, similar

# 8

The triangles are isosceles.

The ratios of bases and sides:

B. ABC ~ MNO, SSS

A statistician would reply that this study does not provide enough evidence to make a conclusion about the efficacy of the generic drug.

The difference in the average reduction of blood pressure in the two groups is not statistically significant, and the standard deviations are very similar. It is possible that the difference in the results is due to random chance, not because one drug is more effective than the other.

To make a reliable conclusion, a larger sample size and a longer duration of the study may be necessary. Additionally, further analysis of the data should be done to determine if there are any other factors that could be influencing the results.

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(a) We have shown that there exists an element b ∈ B that is an upper bound for A.

(b) The statement in part (a) is not always the case if we only assume sup A ≤ sup B.

(a) If sup A < sup B, show that there exists an element b ∈ B that is an upper bound for A.

Proof:
1. By definition, sup A is the least upper bound for set A, and sup B is the least upper bound for set B.
2. Since sup A < sup B, there must be a value between sup A and sup B.
3. Let's call this value x, where sup A < x < sup B.
4. Now, since x < sup B and sup B is the least upper bound of set B, there must be an element b ∈ B such that b > x (otherwise, x would be the least upper bound for B, which contradicts the definition of sup B).
5. Since x > sup A and b > x, it follows that b > sup A.
6. As sup A is an upper bound for A, it implies that b is also an upper bound for A (b > sup A ≥ every element in A).

Thus, we have shown that there exists an element b ∈ B that is an upper bound for A.

(b) Give an example to show that this is not always the case if we only assume sup A ≤ sup B.

Example:
Let A = {1, 2, 3} and B = {3, 4, 5}.
Here, sup A = 3 and sup B = 5. We can see that sup A ≤ sup B, but there is no element b ∈ B that is an upper bound for A, as the smallest element in B (3) is equal to the largest element in A, but not greater than it.

This example shows that the statement in part (a) is not always the case if we only assume sup A ≤ sup B.

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The charge on the capacitor at time t is given by q(t) = -21292.5e^(-0.00878t) + 21292.5e^(-314.53t) + 626000 coulombs.

To find the charge on the capacitor, with the initial conditions q(0) = 0 coulombs and i(0) = 0 amperes, we use the given linear differential equation:

L d^2q/dt^2 + R dq/dt + 1/C q = E(t)

We can solve for q(t) by finding the roots of the characteristic equation, and assuming a particular solution. Then we use the initial conditions to solve for the constants in the general solution.

The solution to the differential equation is:

q(t) = -21292.5e^(-0.00878t) + 21292.5e^(-314.53t) + 626000

Therefore, the charge on the capacitor at time t is given by q(t) = -21292.5e^(-0.00878t) + 21292.5e^(-314.53t) + 626000 coulombs.

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