Jesse has a ribbon that is 12 4.6 yards long. He wants to cut it into pieces that are 1.4 yards long. How many 1.4 yard pieces will he get from the ribbon? will mark brainliest if you mark one here you will be reported just to get the points​

Answer:

x>3  here is your answer

Referring to the truth table, -P is false, and the only case with -P false is when both T and S are false.

This means that 5657 is not a triangular or square number.

(a) To create a truth table for the statement "If a number is triangular or square (T ∨ S), then it is not prime (-P)," we will have columns for T, S, T ∨ S, and -P.

Then we will consider all possible combinations of T and S (true and false) and fill out the remaining columns.
| T   | S   | T ∨ S | -P  |
|-----|-----|-------|-----|
| T   | T   | T     | T   |
| T   | F   | T     | T   |
| F   | T   | T     | T   |
| F   | F   | F     | F   |

(b) If the statement were false, a counterexample would need to have T ∨ S true, but -P false.

In other words, a number that is either triangular or square, and also prime. However, no such counterexample exists in the table, indicating that the statement is true.
(c) Since the statement is true, knowing that 5657 is prime (P) allows us to conclude that it is neither triangular (T) nor square (S).

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Answer:

B

Step-by-step explanation:

The length CT of the line segment is 38 units

From the question, we have the following parameters

CJ = 9x + 1

JT = 2x + 15

Also, we understand that:

Point J is the midpoint of segment CT.

This means that

CJ = CT

So, we have

9x + 1 = 2x + 15

Evaluate the like terms

7x = 14

So, we have

x = 2

Length CT is calculated as

CT = 9x + 1 + 2x + 15

So, we have

CT = 9 x 2 + 1 + 2 x 2 + 15

Evaluate

CT = 38

Hence, the length is 38 units

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Answer:

A = 864 m^2

Step-by-step explanation:

For a rectangle of length L and width W, the area is given by:

A = W*L

We know that the park has:

L = 60m

W = 40m

Now, if we surround the whole park with a path that is 4m wide, then the rectangle made by the park and the path has the dimensions:

L' = 60m + 2*4m

W' = 40m + 2*4m

(as you can see in the sketch at the end)

The area of the path will be equal to the difference between the area of the rectangle made of the park + the path, and the area of the park alone.

This is:

A = L'*W' - *W

A = ( 60m + 2*4m)*(40m + 2*4m) - 60m*40m

A = 68m*48m - 60m*40m

A = 864 m^2

The average payoff for a Lazy (L) teacher for Interested (1) type of students with strategy Not study (NS) and Not Interested (NI) type of students with strategy Study (S), i.e. Teacher's payoff for strategy (L,(NS,S)) is 2.5.

A Bayesian game is a game in which a player's type is private information. A Bayesian game is a standard game with incomplete information, where the types of the players are uncertain. Average payoff for a Lazy (L) teacher for Interested (1) type of students with strategy Not study (NS) and Not Interested (NI) type of students with strategy Study (S), i.e. Teacher's payoff for strategy (L,(NS,S)).

The strategy of a player is a complete plan of action for every contingency, including those that depend on the other player's strategy. A strategy of a player i is denoted by si, which maps each possible type ti of player i into a strategy si(ti)The player set is denoted by

I = {1,2, … , n}.Let t = (t1, t2, … , tn) be the vector of types.

Let T be the set of possible types for the players. The vector of types t follows a joint probability distribution over T.  The strategy profile is a collection of the players' strategies, one for each player.

The strategy profile is denoted by s = (s1, s2, … , sn).  

The payoff function of player i is denoted by ui, which maps the strategy profile of all players and the vector of types into a payoff for player i. The payoff function is denoted by ui(s,t).

Player-1: Teacher, Player-2: StudentStudent may be of two categories: INTERESTED (I) or NOT INTERESTED (NI) with probability 1/2. The probability of the student being interested is 1/2.

P(I)=1/2 and P(NI)=1/2

Action of Teacher: Hard work (H)/Lazy (L), Action of Student: Study (S)/ Not Study (NS)

Game Table:Teacher/Student | S | NSH 10,10 0,0L 5,5 5,0

Teacher/Student | S | NSH 5,5 0,5L 10,5 5,10

Teacher's payoff for strategy (L,(NS,S)):

P(NI) * [Lose] + P(I) * [Lose] = (1/2 * 0) + (1/2 * 5) = 2.5

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The value of ∫∫sF⋅ds, where S is the top half of the sphere x^2 + y^2 + z^2 = 1 oriented upwards, is 0.

The Divergence Theorem states that the flux of a vector field across a closed surface is equal to the triple integral of the divergence of the vector field over the volume enclosed by the surface. In this case, the vector field F(x, y, z) is given, and we need to evaluate the surface integral over the top half of the sphere.

To apply the Divergence Theorem, we first need to find the divergence of F. The divergence of a vector field F = P(x, y, z)i + Q(x, y, z)j + R(x, y, z)k is given by div(F) = ∂P/∂x + ∂Q/∂y + ∂R/∂z. In this case, we have F(x, y, z) = z^2xi + (1/3y^3 + tan(z))j + (x^2 + 4y^2)k. Therefore, the divergence of F is div(F) = 2z + tan(z).

Since the surface S is the top half of the sphere x^2 + y^2 + z^2 = 1 oriented upwards, we can parameterize it as x = cosθsinφ, y = sinθsinφ, z = cosφ, where θ ranges from 0 to 2π and φ ranges from 0 to π/2.

By applying the Divergence Theorem, the surface integral ∫∫sF⋅ds is equal to the triple integral ∭v div(F) dV over the volume enclosed by the surface S. Since the divergence of F is 2z + tan(z), we need to evaluate ∭v (2z + tan(z)) dV. However, the value of this triple integral turns out to be zero due to the symmetry of the surface and the divergence function. Therefore, the value of ∫∫sF⋅ds, where S is the top half of the sphere x^2 + y^2 + z^2 = 1 oriented upwards, is 0.

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The row for 20 degrees and the row for 70 degrees in the right triangle table have the same values, but in reverse order.

Specifically, the sine, cosine, and tangent of 20 degrees are the same as the cosine, sine, and tangent of 70 degrees, respectively. The same holds true for their reciprocals, the cosecant, secant, and cotangent.

It should be noted that to complete the row for 35 degrees in the right triangle table, we can use the same ratios as for the complementary angle of 55 degrees, but in reverse order. Specifically:

The adjacent leg ÷ hypotenuse ratio for 35 degrees is equal to the opposite leg ÷ hypotenuse ratio for 55 degrees, which is 0.819.

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The difference quotient for the given function is 9 -2/h.

The difference quotient for the given function can be calculated as:

[f(x+h) - f(x)]/h

= [(3(x+h)² - 2(x+h) + 5) - (3x² - 2x + 5)]/h

= (3x² + 6xh + 3h² - 2x - 2h + 5 - 3x² + 2x - 5)/h

= (6xh + 3h² - 2h)/h

= (6x + 3h -2)/h

Simplifying the expression further, we get:

(6x + 3h -2)/h = 6 + 3h/h -2/h

= 6 + 3 -2/h

= 9-2/h

Therefore, the difference quotient for the given function is 9 -2/h.

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"Your question is incomplete, probably the complete question/missing part is:"

Find the difference quotient [f(x+h)-f(x)]/h, where h≠0, for the function below.

f(x)=3x² -2x+5. Simplify your answer as much as possible.

Answer:

I thinkkk Roses -11 feet per min and Lucy is 10 feet per min

Step-by-step explanation:

The test that represents the best choice if you wanted to compare the average mean time to repair (mttr) of your office for the last month to the division’s mttr is one sample t-test

The purpose of the one sample t-test is to determine if a sample observations could follow a specific parameter like the mean.

This test is used to determine whether an unknown population mean is different from a specific value.

one sample t-test is used to compare the mean of a single group against that of a known mean.

We wanted to compare the average mean time to repair (mttr) of your office for the last month to the division’s mttr

So this test (one sample t-test ) would be the best choice to compare mttr.

Therefore, the test that represents the best choice if you wanted to compare the average mean time to repair (mttr) of your office for the last month to the division’s mttr is one sample t-test

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Answer:

yes they are

Step-by-step explanation:

an independent variable is a letter by itself not representing anything

Answer:

Hopes it helps

Step-by-step explanation:

Len

Simplifying

5(3 + -8x) = 0

(3 * 5 + -8x * 5) = 0

(15 + -40x) = 0

Solving

15 + -40x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-15' to each side of the equation.

15 + -15 + -40x = 0 + -15

Combine like terms: 15 + -15 = 0

0 + -40x = 0 + -15

-40x = 0 + -15

Combine like terms: 0 + -15 = -15

-40x = -15

Divide each side by '-40'.

x = 0.375

Simplifying

x = 0.375

Monty

Simplifying

7 + -2(-5x) = 0

Remove parenthesis around (-5x)

7 + -2 * -5x = 0

Multiply -2 * -5

7 + 10x = 0

Solving

7 + 10x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.

7 + -7 + 10x = 0 + -7

Combine like terms: 7 + -7 = 0

0 + 10x = 0 + -7

10x = 0 + -7

Combine like terms: 0 + -7 = -7

10x = -7

Divide each side by '10'.

x = -0.7

Simplifying

x = -0.7

Nailany

Simplifying

7 + -6 + -16x = 0

Combine like terms: 7 + -6 = 1

1 + -16x = 0

Solving

1 + -16x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + -1 + -16x = 0 + -1

Combine like terms: 1 + -1 = 0

0 + -16x = 0 + -1

-16x = 0 + -1

Combine like terms: 0 + -1 = -1

-16x = -1

Divide each side by '-16'.

x = 0.0625

Simplifying

x = 0.0625

Answer:

No

Step-by-step explanation:

Given:

6,3

4x+5y=-13

Solve:

4(6)+5(3)

24 + 15 = 39

Hence, No 6,3 isn't a solution to 4x+5y= - 13

~lenvy~

The aspect ratio of the desk is 3:2

Aspect ratio can be described as the ration of the width to the height of an object

The desk is 36 inches long

The width is 24 inches

The aspect ratio can be calculated as follows

= 36/24

= 6/4

= 3/2

Hence the aspect ratio is 3:2

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Now the angle in the degree is,

The linear approximation for the change in the predicted probability per degree increase in temperature is approximately 0.003.

Linear approximation is an estimation method that approximates a function by a linear function. Linear approximation is also known as the tangent line approximation method.

This method is useful for finding out the approximate value of the function at a point near the given point. The linear approximation of the change in predicted probability per degree increase in temperature can be found using the formula given below: Linear Approximation Formula: Linear approximation formula is given by the following equation: f(x) ≈ f(a) + f′(a)(x − a)Where f(x) is the function, f(a) is the value of the function at the point x=a, f′(a) is the first derivative of the function at x=a, and x is the point near the point a that we want to find the approximation.

Let us apply the linear approximation formula to find the linear approximation for the change in the predicted probability per degree increase in temperature.

Let f(t) be the function that gives the predicted probability of a particular event at a temperature t. Suppose that at a temperature of 100 °F, the predicted probability is 0.8. Let f′(t) be the first derivative of the function f(t).

We need to find the linear approximation of the change in predicted probability per degree increase in temperature when the temperature is 100 °F. We can use the following steps to find the linear approximation.

Step 1: Find the value of f(100)f(100) = 0.8This means that when the temperature is 100 °F, the predicted probability is 0.8.

Step 2: Find the value of f′(100)f′(100) = df/dt = 0.003 This means that the rate of change of predicted probability with respect to temperature at 100 °F is 0.003 per degree.

Step 3: Use the linear approximation formula to find the linear approximation of the change in predicted probability per degree increase in temperature. The linear approximation formula is given by: f(x) ≈ f(a) + f′(a)(x − a)Substitute a=100, f(100)=0.8, f′(100)=0.003, and x=101 into the formula. f(101) ≈ f(100) + f′(100)(101 − 100)f(101) ≈ 0.8 + 0.003(1)f(101) ≈ 0.803

This means that the predicted probability of the particular event when the temperature is 101 °F is approximately 0.803.

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Given information: Expected sales revenue = $57756Target labour cost percentage = 18%To find: How much money can you spend on labour that day? Solution: Let's assume the amount that can be spent on labour is x. According to the question, Target labour cost percentage is 18%.

Therefore, the amount that will be spent on labour cost = 18% of expected sales revenue. So, we can write it as:

x = 18% of expected sales revenue orx

= (18/100) × 57756Simplify it

,x = 10396.08 (rounded to two decimal places)Thus, the amount that can be spent on labour that day is $10,396.08.

Shawna and Beatrice, by virtue of their status as the offerees, had the option of accepting or rejecting the offer. The acceptance must meet the requirements of a valid contract.

The acceptance must be communicated clearly and immediately. In addition, the acceptance must conform to the offer's terms. In Hyde v Wrench (1840), the court held that an acceptance must be unconditional and absolute and that if the acceptance is not in line with the terms of the offer, it is a counteroffer that terminates the original offer. Since Shawna and Beatrice had not yet responded to the offer, there was no acceptance of the contract. Therefore, there was no legal agreement between the parties as a contract must have both an offer and an acceptance in order to be considered valid.

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Answer:

hcf=2 lcm=3696

Step-by-step explanation:

Answer:

If AB crosses at a right angle, it is called the "perpendicular bisector" of PQ. If it crosses at any other angle it is simply called a bisector. Drag the points A or B and see both types. For obvious reasons, the point F is called the midpoint of the line PQ. See also Angle bisector.

Answer:

Step-by-step explanation:

\(\frac{x^{5}y^{2} }{xy^{3} }\) use the rules that \(\frac{x^{a} }{x^{a} } =1\)and that \(x^{a+b} =x^{a} *x^{b}\)

\(\frac{x*x^{4}*y^{2} }{x*y*y^{2} }\)  simplify

\(\frac{x^{4} }{y}\)

Answer:

your answer will be C.63

The probabilities are:

\(P(A) = \frac{1}{120}\) and \(P(B) = \frac{1}{720}\).

To calculate the probabilities, we need to consider the total number of possible outcomes and the number of favorable outcomes for each event.

Event A: The first three prize winners are Soo, Ann, and Jim, regardless of order.

There are 10 people, so the total number of possible outcomes is 10P3 (permutations of 10 people taken 3 at a time).

This is calculated as 10! / (10-3)! = 10! / 7! = 10 * 9 * 8 = 720.

The number of favorable outcomes is 3! (permutations of 3 people), as the order doesn't matter.

So, the number of favorable outcomes is 3! = 3 * 2 = 6.

P(A) = favorable outcomes / total outcomes = 6 / 720 = 1 / 120.

Event B: Ann is the first prize winner, Lena is second, and Bob is third.

Similarly, there are 10P3 total outcomes, which is 720.

The number of favorable outcomes is 1, as there is only one specific arrangement where Ann is first, Lena is second, and Bob is third.

P(B) = favorable outcomes / total outcomes = 1 / 720.

Therefore, the probabilities are:

P(A) = 1 / 120

P(B) = 1 / 720.

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so the answer is x=2

Answer:

x=2

Step-by-step explanation:

2(x-4)+7=3

First, multiply the 2 to x-4.

2x-8+7=3

Simplify.

2x-1=3

Add x on both sides.

2x=4

Divide 2 on both sides.

x=2

The set A ∩ B = {3}

The intersection of sets, denoted as A ∩ B, refers to the set that contains elements that are common to both sets A and B. In this case, set A consists of the elements {1, 2, 3, 6}, and set B consists of the elements {3, 4, 5}.

The intersection of A and B, written as A ∩ B, represents the set of elements that appear in both sets simultaneously.

To find the intersection of sets A and B, we examine each element of set A and check if it is also present in set B. In this case, the element 3 is the only element that exists in both sets.

Therefore, the intersection of sets A and B is {3}.

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Point L is the midpoint

The midpoint is halfway between the two points. In this case, Point F and Point B are 10 units away from each other. The midpoint is the distance between the points (10) divided by 2.

Answer: False, not possible.

The human was never meant to calculate or go beyond their fingers in search of great numbers, taking count for themselves, giving them names, appropriating. If you wanted to go higher for a laugh, it was called guessing. "Give me ZERO of this, give me 14,739,628,837 of that" are words that nobody says and words that stand behind delusion.

The only "anyone" to be counting their whole life is a divine. Keep math, numbers, and geometry sacred.

CosA is negative for the largest angle in an obtuse triangle. Using the law of cosines, a²>b²+c², a>b, and a>c are derived.

Step 1: As the obtuse triangle has the largest angle A (more than 90 degrees), the cosine function's value is negative.

Step 2: By applying the Law of Cosines in the triangle, a²>b²+c², which is derived from a²=b²+c²-2bccosA, and hence a>b and a>c can be derived.

Step 3: From the previously derived inequality a²>b²+c², we can conclude that a>b and a>c as a²-b²>c². The value of a² is greater than both b² and c² when a>b and a>c.

Therefore, the largest angle of an obtuse triangle is opposite the longest side.

Step 4: In triangle ABC, A=103°, a=25, and c=30.

a² = b² + c² - 2bccos(A),

a² = b² + 900 - 900 cos(103),

a² = b² + 900 + 900 cos(77),

a² > b² + 900, so a > b.

Similarly, a² > c² + 900, so a > c.

Therefore, triangle ABC satisfies a>b and a>c.

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There are total 35 students in the class.

Given that,

Vikas ranks 9th in the class,

Assume that there are 'n' number of students in the class  

Therefore,

There are 8 students who have scored better than him.

So, The total number of students with a rank better or equal to Vikas,

= 8 + 1 (Vikas himself)

= 9.

Now, his friend got the 35th rank which is the last rank

This means that there are a total of 35 students in the class.

Also, also given that,

Vikas's rank from the last is 27th,

This means that there are 26 students who have scored lower than Vikas.

So, the total number of students with a rank worse or equal to Vikas,

= 26 + 1 (Vikas himself)

 = 27.

Therefore, The total number of students in the class = 35.

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