John ordered 1.25 kg of zinc for an experiment when he weighed it, he measured 1.13 kg what is the percent error of Johns measurement

Halogens are found in nature only in compounds because they are highly reactive and have a strong tendency to react with other elements to form compounds.

Halogens are a group of elements that are highly reactive, and they are located in Group 17 (VIIA) of the periodic table. These elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At).

The name halogen comes from the Greek word halos, which means "salt" and "producer."Halogens are very reactive because they have seven valence electrons in their outermost shell. These electrons make halogens highly reactive and prone to bond with other elements. This means that they have a strong tendency to react with other elements to form compounds.

These compounds are formed through a process called halogenation or halogenation reaction. This process involves the addition of halogen atoms to a molecule or compound to form a halogenated compound.

In conclusion, halogens are found in nature only in compounds because of their highly reactive nature and their strong tendency to react with other elements to form compounds.

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An atom's configuration based on its number of electrons ends at 3p. Another atom has seven more electrons. Starting at 3p, the remaining configuration is O3p445²3d5. Option C is correct answer.

The electron configuration of an element refers to the number of electrons in each of its atoms that are located in the shells around the atomic nucleus. Electrons in the same shell have similar energies; they are arranged in shells according to increasing energy levels.According to the question, the atom's configuration based on its number of electrons ends at 3p, and another atom has seven more electrons. Hence, the electron configuration of that atom should start with 3p since the question states starting at 3p. The remaining seven electrons should go into the 4s and 3d sub-shells. Therefore, the correct answer is:O3p445²3d5

The correct answer is C.

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Answer:

28

Explanation:

Matter can be classified into four categories, namely elements, compounds, homogeneous mixtures, and heterogeneous mixtures.

1. Element: Examples include hydrogen, oxygen, and gold. These substances cannot be broken down into simpler substances through chemical means.

2. Compound: Examples include water (H2O), carbon dioxide (CO2), and table salt (NaCl). Compounds have a fixed ratio of elements and can be broken down into their constituent elements through chemical reactions.

3. Homogeneous mixture: Examples include air, saline solution, and brass. The components of these mixtures are evenly distributed and cannot be seen individually.

4. Heterogeneous mixture: Examples include sand and water, oil and water, and a bowl of cereal. The components of these mixtures are unevenly distributed and can often be seen individually. Remember that the classification of matter depends on its composition and properties.

In summary, the classification of matter as an element, compound, homogeneous mixture, or heterogeneous mixture depends on the composition and uniformity of the sample.

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The Wittig reaction offers several advantages over many elimination reactions, including high selectivity and yields, mild reaction conditions, and versatility. These factors make it a popular choice for synthesizing alkenes in a wide range of applications.

The Wittig reaction is a useful method for synthesizing alkenes from aldehydes or ketones and phosphonium ylides. It is advantageous over many elimination reactions because it provides high selectivity and yields, and it avoids the formation of by-products. Unlike elimination reactions, which can lead to a mixture of products, the Wittig reaction provides a single product with a defined stereochemistry.
Another advantage of the Wittig reaction is that it is a milder process than many elimination reactions. It typically requires less harsh reaction conditions, such as high temperatures or strong acids or bases. This means that the reaction can be performed on a wider range of substrates, including those that are sensitive to harsh conditions.
Furthermore, the Wittig reaction is a highly versatile reaction that can be used to synthesize a wide range of alkenes, including complex and highly substituted compounds. It can also be used in combination with other reactions to create more complex molecules.
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it will take approximately 73.6 years for 317.5 mg of 3H to decay to 0.039 mg of 3H.

The decay of a radioactive substance can be modeled by the following exponential function:

N(t) = N₀ * \(e^(\)-λt)

t(1/2) = 12.3 years

λ = ln(2) / t(1/2) ≈ 0.0565 years⁻¹

Using the values we have, we can solve for t:

0.039 mg = 317.5 mg * \(e^(-0.0565\) years⁻¹ * t)

Taking the natural logarithm of both sides:

ln(0.039 mg/317.5 mg) = -0.0565 years⁻¹ * t

t = ln(0.039 mg/317.5 mg) / -0.0565 years⁻¹ ≈ 73.6 years

A radioactive substance is a material that contains unstable atomic nuclei that undergo radioactive decay. This means that the nucleus of the atom is not stable and spontaneously releases energy in the form of particles or electromagnetic radiation. These particles and radiation can be harmful to living organisms, causing damage to cells and genetic material.

The decay of a radioactive substance can occur through several processes, including alpha decay, beta decay, and gamma decay. Alpha decay involves the emission of alpha particles, which are made up of two protons and two neutrons. Beta decay involves the emission of beta particles, which are either electrons or positrons. Gamma decay involves the emission of gamma rays, which are high-energy photons.

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The molarity of the diprotic acid that requires 18.73 mL KOH is 1.405 M.

The chemical reaction between a diprotic acid and KOH is

H₂A + 2 KOH → K₂A + 2 H₂O

In stoichiometry, we learn the chemical reaction and the laws that work in it. According to Avogadro's law, the coefficient of a substance in a chemical reaction expresses the ratio of the number of moles of each substance.

\(M \:=\: \frac{n}{V}\)

n = MV

KOH

The number of moles for a diprotic acid

n KOH : n H₂A = 2 : 1
n H₂A = n KOH ÷ 2
n H₂A = 5.619 ÷ 2
n H₂A = 2.8095 mmol

The molarity of a diprotic acid

\(M \:=\: \frac{n}{V}\)
\(M \:=\: \frac{2.8095}{25.00}\)
M = 1.405 M

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Yes, nonpolar molecules generally diffuse more readily through the plasma membrane than polar molecules of the same size.

This is because the plasma membrane is composed of a lipid bilayer which has a hydrophobic interior, making it easier for nonpolar molecules to pass through.

The plasma membrane is a selectively permeable barrier that separates the cell from its external environment. It is composed of a lipid bilayer made up of phospholipids, cholesterol, and proteins.

The hydrophobic tails of the phospholipids form the interior of the membrane while the hydrophilic heads face outward, interacting with the surrounding aqueous environment.

Nonpolar molecules, such as oxygen and carbon dioxide, are able to pass through the lipid bilayer more easily than polar molecules like glucose and ions. This is because the hydrophobic interior of the membrane repels polar molecules while allowing nonpolar molecules to pass through.

When a molecule comes in contact with the plasma membrane, it will diffuse across the membrane if it is able to pass through the hydrophobic interior. The rate of diffusion is influenced by the size, polarity, and concentration gradient of the molecule.

Small nonpolar molecules, such as oxygen, diffuse rapidly through the membrane, while larger nonpolar molecules diffuse more slowly. Polar molecules, such as glucose, diffuse even more slowly, and ions require transport proteins to pass through the membrane.

Overall, nonpolar molecules diffuse more readily through the plasma membrane than polar molecules of the same size due to the hydrophobic interior of the lipid bilayer.

This property of the membrane plays an important role in regulating the movement of molecules into and out of the cell.

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Answer:

Reaction between an oxygen and  a phosphorus will produce oxides of phosphorus.

Explanation:

Reaction between oxygen and phosphorus produces four atoms of phosphorus with five atoms of oxygen. Sometimes it produces two atoms of phosphorus and five atoms of oxygen and sometimes four atoms of phosphorus and six atoms of oxygen. It does so depending upon the availability of oxygen. The size of phosphorus atom  interferes with the ability to form a double bonds to the other elements, such as nitrogen, oxygen, etc.

88226Ra→ 86222Rn + 24He is the reaction that describes an alpha emission because radiations are released.

Alpha radiation occurs when the nucleus of an atom becomes unstable and alpha particles are released in order to restore stability. Alpha decay occurs in elements that have high atomic numbers, such as uranium, radium, and thorium etc.

So we can conclude that 88226Ra→ 86222Rn + 24He is the reaction that describes an alpha emission because radiations are released.

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Answer:

A: 88226Ra→ 86222Rn + 24He

In the diagram, we see a distillation process. This is a separation process that takes advantage of differences in the boiling point of a mixture of liquids, so the more volatile liquid will evaporate and be recovered as distillate.

1) The first error seen is that the liquid solution mixture is not heated. In order to separate the liquids, we must heat the mixture by adding heat, and this heat is represented in the diagram with a flame.

2) The second mistake is the position of the thermometer, the thermometer must not be in contact with the liquid, it must be at the height of the bulb so that it is in contact with the vapor.

3) The third error is the exit of the coolant water. The water exchanges heat with the steam, so the steam cools and condenses and the water absorbs the heat, and its temperature increases, so it does not come out cold.

In the following figure we can see the mistakes:

Answer:

Krypton has 4 orbital shells

Extra Information:

Krypton has 36 electrons which are arranged in these 4 orbit shells,

The order in which electrons are arranged in these shells is 2,8,18,8

To calculate the number of moles of oxygen in copper oxide, we need to know the molar mass of oxygen and the amount of copper oxide present.

Given that the molar mass of oxygen is 16.00 g/mol, we can use this information to determine the number of moles of oxygen.

First, we need to determine the molar mass of copper oxide. Copper oxide consists of one copper atom (Cu) and one oxygen atom (O). The atomic mass of copper is 63.55 g/mol.

The molar mass of copper oxide can be calculated as follows:

Molar mass of copper oxide = (atomic mass of copper) + (atomic mass of oxygen)
                         = 63.55 g/mol + 16.00 g/mol
                         = 79.55 g/mol

Next, we need to know the amount of copper oxide present. Let's assume we have 100 grams of copper oxide.

To calculate the number of moles of oxygen, we can use the formula:

Number of moles = Mass of substance / Molar mass

Mass of oxygen = Mass of copper oxide - Mass of copper
             = 100 g - (63.55 g/mol * 1 mol)
             = 36.45 g

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen
                        = 36.45 g / 16.00 g/mol
                        ≈ 2.28 mol

The number of moles of oxygen in 100 grams of copper oxide is approximately 2.28 moles.

To calculate the number of moles of oxygen in copper oxide, we need to know the molar mass of oxygen and the mass of copper oxide. By using the formula for moles and the given information, we can determine that there are approximately 2.28 moles of oxygen in 100 grams of copper oxide.

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There are 0.125 moles of oxygen in 10 grams of copper oxide.

To calculate the number of moles of oxygen in the copper oxide, we need to know the mass of copper oxide and its chemical formula. Assuming the formula of copper oxide is CuO, we can use the molar mass of oxygen (16.00 g/mol) to calculate the number of moles.

1. Determine the mass of copper oxide.
2. Calculate the molar mass of copper oxide using the atomic masses of copper and oxygen.
3. Divide the mass of copper oxide by its molar mass to obtain the number of moles.

Let's say we have 10 grams of copper oxide.
1. The mass of copper oxide is 10 grams.
2. The molar mass of copper oxide (CuO) is the sum of the atomic masses of copper (Cu) and oxygen (O). The atomic mass of copper is 63.55 g/mol, and the atomic mass of oxygen is 16.00 g/mol. So the molar mass of copper oxide is 63.55 g/mol + 16.00 g/mol = 79.55 g/mol.
3. Divide the mass of copper oxide (10 grams) by its molar mass (79.55 g/mol) to get the number of moles of copper oxide.

So, the number of moles of copper oxide is 10 grams / 79.55 g/mol = 0.125 moles.

Therefore, there are 0.125 moles of oxygen in 10 grams of copper oxide.

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Answer:

C. A chemical reaction.

Explanation:

A chemical reaction can be defined as a chemical process which typically involves the transformation or rearrangement of the atomic, ionic or molecular structure of an element through the breakdown and formation of chemical bonds to produce a new compound or substance.

Since the Statue of Liberty is made out of copper and was once shiny and copper-colored. Over the years, the copper has gone through a process called oxidation, where it has changed into a new material. Thus, this is a chemical reaction.

In this case, occurred a CHEMICAL REACTION known as oxidation.

A chemical reaction is a process where one or more substances called reactants can react to be converted into one or more products.

In conclusion, in this case, occurred a CHEMICAL REACTION known as oxidation.

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The conjugate base of H2SO4 is SO42-, The conjugate base of HSO4- is SO42-, H3O+ dissociates in water to form H3O+ and H2O. The conjugate base of H3O+ is H2O, and NH4+ dissociates in water to form NH3 and H3O+. The conjugate base of NH4+ is NH3.

(a) The balanced equation for the dissociation of H2SO4 in water is:

H2SO4 + 2H2O → 2H3O+ + SO42-

The conjugate base of H2SO4 is SO42-.

(b) The balanced equation for the dissociation of HSO4- in water is:

HSO4- + H2O → H3O+ + SO42-

The conjugate base of HSO4- is SO42-.

(c) The balanced equation for the dissociation of H3O+ in water is:

H3O+ + H2O → H3O+ + H2O

The conjugate base of H3O+ is H2O.

(d) The balanced equation for the dissociation of NH4+ in water is:

NH4+ + H2O → NH3 + H3O+

The conjugate base of NH4+ is NH3.

In each case, the conjugate base is the species that remains after the acid donates a proton (H+) to water. The conjugate base carries a negative charge and is formed by removing a proton from the acid molecule.

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Answer:

B)The atoms form a bond with a bond length of 75 pm

Answer:

After three hours, concentration of C₂F₄ is 0.00208M

Explanation:

The rate constant of the reaction:

2 C2F4 → C4F8 is 0.0410M⁻¹s⁻¹

As the units are M⁻¹s⁻¹, this reaction is of second order. The integrated law of a second-order reaction is:

\(\frac{1}{[A]} =\frac{1}{[A]_0} +Kt\)

Where [A] and [A]₀ represents initial and final concentrations of the reactant (C₂F₄), K is rate constant (0.0410M⁻¹s⁻¹) and t is time of the reaction (In seconds).

3.00 hours are in seconds:

3 hours ₓ (3600 seconds / 1 hour) = 10800 seconds

Initial concentration of C2F4 is:

0.105mol / 4.00L = 0.02625M

Replacing in the integrated law:

\(\frac{1}{[A]_0}= \frac{1}{0.02625} +0.0410M^{-1}s^{-1}*10800s\\\frac{1}{[A]_0}=480.9M^{-1}\)

[A] = 0.00208M

Answer:

Yea.....where is the article and the 6 questions?

Answer:

Answering

Explanation:

do u want us to tell u what we got?

Answer:

Hey there!

Gold would have a greater mass, because density is mass/volume, and if the density is greater, so is the mass.

Let me know if this helps :)

Answer:carbon-14 levels in the atmosphere

Explanation:

When carrying out radiocarbon dating, the level of carbon-14 in a sample is compared with the level of carbon 14 in the atmosphere because, objects exchange carbon-14 with the atmosphere.

Comparison of the activities of carbon-14 in the atmosphere and in the sample gives the age of the sample since the half-life of carbon-14 is a constant.

The number of valence electrons in each of the atoms are;

B - 3

Al - 3

Cl - 7

Ne - 8

We define an atom as the smallest part of a substance that can take part in a chemical reaction. We know that when we begin to break down the elements that the atoms can be found in the element and there are sub atomic particles that can also be found inside the atom of the element.

The electrons that are found at the last shell or the outermost shell of the atom are the ones that we call the valence electrons that can be found in the atom.

The electronic configuration of boron is \(1s^2 2s^2 2p^1\) (the n =2 level is the valence shell)

The electronic configuration of Al is \(1s^2 2s^2 2p^6 3s^2 3p^1\)( the n= 3level is the valence shell)

The electron configuration of Cl is \(1s^2 2s^2 sp^6 3s^23p^5\) ( the n= 3level is the valence shell)

The electron configuration of Ne is \(1s^2 2s^2 2p^6\) (the n =2 level is the valence shell)

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when the temperature is raised to 325 K and the volume is increased to 1.8 L, the gas will occupy a pressure of approximately 1.08 atm.

To solve this problem, we can use the combined gas law equation, which relates the initial and final conditions of a gas when the amount of gas remains constant.

The combined gas law equation is given as:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

where P₁, V₁, and T₁ represent the initial pressure, volume, and temperature, respectively, and P₂, V₂, and T₂ represent the final pressure, volume, and temperature, respectively.

Given

Initial pressure (P₁) = 1.2 atm

Initial volume (V₁) = 0.9 L

Initial temperature (T₁) = 273 K

Final volume (V₂) = 1.8 L

Final temperature (T₂) = 325 K

We need to find the final pressure (P₂).

Substituting the given values into the combined gas law equation, we have:

(1.2 atm * 0.9 L) / 273 K = (P₂ * 1.8 L) / 325 K

Now, we can solve for P₂:

P₂ = (1.2 atm * 0.9 L * 325 K) / (273 K * 1.8 L)

= 1.08 atm

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HNO₂ (nitrous acid) is the Bronsted-Lowry acid which is not considered to be a strong acid in water.

Bronsted acid are those species that are capable of  donating a proton to other species.

HBr is as strong Bronsted-Lowry acid, that reacts completely according to the following reaction.

HBr + H₂O → Br⁻ + H₃O⁺

HNO₃ is as strong Bronsted-Lowry acid, that reacts completely according to the following reaction.

HNO₃ + H₂O → NO₃⁻ + H₃O⁺

But, HNO₂ cannot react completely. So, it is not a strong acid in water.

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Answer:

²³⁵₉₂U

Explanation:

The right symbol for the nuclei is ²³⁵₉₂U;

 For this chemical element, the atom is represented by the symbol U;

 To the superscript before the symbol is the mass number

 The subscript before the symbol is the atomic number

Mass number is the number of protons and neutrons

Atomic number is the number of protons.

Answer:

homogeneous mixture

Answer:

mass of the object and how much energy the object has

Answer:

A

Explanation:

Molality is term used for the amount of solute in moles per kilogram of solvent.

Generally, molality (m) is defined as the number of moles of solute per kilogram of solvent.

The formula for molality is given as:

Molality (m) = moles of solute / kilograms of solvent.

Students must remember that molality is used to measure the moles in relation to the mass of the solvent and not the mass of the solution.

Molality can also be defined as the “total moles of a solute contained in a kilogram of a solvent.” The other name of molality is also known as molal concentration which is a measure of solute concentration in a solution.

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