Jose reads his book at an average rate of


2. 5


2. 5 pages every four minutes. If Jose continues to read at exactly the same rate what method could be used to determine how long it would take him to read


20


20 pages?

Answer:

y= −2/3x−1

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

most energy don't enter the ecosystem through sunlight, there's water too, and air

The energy is recycled after flowing through ecosystems is not true, So option b is the correct answer.

The energy flow in the ecosystem is one of the most important factors for the survival of such a large number of organisms.

An ecosystem consists of all the organisms and the physical environment with which they interact. The ecosystem has two main components which are biotic and abiotic. They are connected through nutrient cycles and energy.

From the sunlight as a source of energy, it enters the system through photosynthesis. So, the energy is transferred between organisms. energy flows take place through the food chain and food web, which is not recycled in ecosystems and requires a continuous input of energy to sustain. Thus, the energy flow is unidirectional.

Therefore, b is the correct option that energy is recycled after flowing through ecosystems.

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Answer:

4 cubic inches

Step-by-step explanation:

We know that lwh=V

l=7

w=12

h=?

V=336

7(12)=84

336/84=h

h=4 cubic inches

Answer:

4 cubic inces

Step-by-step explanation:

I'm just built different

Answer:

The answer is flint sickles

Step-by-step explanation:

To determine customer opinion of their musical variety, sony randomly selects 120 concerts during a certain week and surveys all concertgoers. The type of sampling is used is "Cluster."

A survey is a technique of gathering information from a sample of people by asking relevant questions with the goal of understanding populations as a whole.

Some key features regarding the survey are-

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Answer:

yes

Step-by-step explanation:

Answer:

Evan spent 3 hours making paper crates today.

Step-by-step explanation:

He made 28 in 4 hours. 28 divided by 4 equals 7. Which means he makes 7 paper crates in 1 hour. Today he made 21. So 21 divided by 7 equals 3.

Answer:

4, yes through the middle    5, yes through the middle 6, yes through the middle  all of them reflect from the center

Step-by-step explanation:

The main answer for the first argument is that we cannot prove that the band could play rock music based on the given premises and rules of inference.

1. Let's assign the following propositions:

  - P: The band could play rock music.

  - Q: The refreshments were delivered on time.

  - R: The New Year's party was canceled.

  - S: Alicia was angry.

  - T: Refunds were made.

2. The given premises can be expressed as:

  (¬P ∨ ¬Q) → (R ∧ S)

  R → T

3. To prove that the band could play rock music (P), we need to derive it using valid rules of inference.

4. Using the premises, we can apply the rule of modus tollens to the second premise:

  R → T        (Premise)

  Therefore, ¬R.

5. Next, we can use disjunctive syllogism on the first premise:

  (¬P ∨ ¬Q) → (R ∧ S)     (Premise)

  ¬R                    (From step 4)

  Therefore, ¬(¬P ∨ ¬Q).

6. Applying De Morgan's law to step 5, we get:

  ¬(¬P ∨ ¬Q)  ≡  (P ∧ Q)

7. Therefore, we can conclude that the band could play rock music (P) based on the premises and rules of inference.

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Answer: the answer to this is true

Answer:

a

Step-by-step explanation:

calculator

Answer:

Step-by-step explanation:

Let x be the number of adult tickets Travis bought, and y be the number of children tickets he bought.

We know that Travis bought a total of 14 tickets, so x + y = 14.

We also know that the total cost of the tickets was $54, so 5x + 3y = 54.

We can use the first equation to solve for y in terms of x: y = 14 - x.

Substituting this into the second equation, we get:

5x + 3(14 - x) = 54

Simplifying and solving for x, we get:

5x + 42 - 3x = 54

2x + 42 = 54

2x = 12

x = 6

Therefore, Travis bought 6 adult tickets and 14 - 6 = 8 children tickets.

to find maximum wage of number equality of boy adult and child.

I mean: 48 = 6.8

12 person from here

2 person remain

6 $ remain as well

6 = 2 child ticket

so the answer is 6

The given information is as follows:A random sample of 150 teachers in an​ inner-city school district found that​ 72% of them had volunteered time to a local charitable cause within the past 12 months.

The formula for calculating the standard error of sample proportion is given as:$$Standard\(\ error=\frac{\sqrt{pq}}{n}$$\)where:p = proportion of success in the sampleq = proportion of failure in the samplen = sample sizeGiven:Sample proportion, p = 72% or 0.72Sample size, n = 150

The proportion of failure in the sample can be calculated as:q = 1 - p= 1 - 0.72= 0.28Substituting the known values in the above formula, we get:\($$Standard \ error=\frac{\sqrt{pq}}{n}$$$$=\frac{\sqrt{0.72(0.28)}}{150}$$$$=0.0372$$\)Rounding off to the nearest thousandth, we get the standard error of sample proportion as 0.037

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The lower quartile of the number of wrapping paper rolls sold is given as follows:

15 wrapping paper rolls.

A box and whisker plots shows these five features from a data-set, listed as follows:

The lower quartile of a data-set is the 25th percentile, which is given by the left bar of the box, hence it is given as follows:

15 wrapping paper rolls.

The box and whisker plot is given by the image presented at the end of the answer.

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Among the 769 team members, 706 of them are assigned to operates in 2 shifts schedule. The proportion of team members not assigned to one of the stations is 63 / 769

Proportion means a share from total set being discussed.

Data from the given case:

- The assembly has 769 team members.

- The assembly has 353 stations

- At each station, there are 2 shifts operations.

Assuming that 1 person is assigned to 1 shift operation, then there will:

353 x 2 = 706 person assigned.

The remaining team members that not assigned is:

769 - 706 = 63 person.

Therefore, the share or the proportion of unassigned team members is:

63/769

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Answer:

21 + 13 i

Step-by-step explanation:

Multiply using the FOIL method, then combine the real and imaginary parts of the expression.

Answer:

x 12, y 10 (I think, I'm not really sure since there is nothing to work out)

Answer:

C

Step-by-step explanation:

So area is length times width for the rectangle and your length is 4 and your width is 6+7, if you do 4 times 6+7 you will get 52. If you want to be sure you can go down the answer options and do them until you find one that equals 52 which in this case is C.

4 x (6+7) = area

(in case you need the equation)

Answer: \(x\geq 6\)

Step-by-step explanation:

Given

\(g(x)=\sqrt{x-4}\\h(x)=2x-8\)

Now, g of h i.e. \(g(h(x))\)

Put h(x) in place of x in g(x)

\(\Rightarrow g(h(x))=\sqrt{(2x-8)-4}\\\\\Rightarrow g(h(x))=\sqrt{2x-12}\)

Now, the value inside square root must be greater than zero

\(\Rightarrow 2x-12\geq 0\\\\\Rightarrow 2x\geq 12\\\\\Rightarrow x\geq 6\)

The markup on cost percentage for Hudson Bay's acquisition of sheets priced at MSRP 59.99 for 22.99 is 61.68%.

To calculate the markup on cost percentage, we can use the following formula:

Markup on Cost Percentage = ((Selling Price - Cost Price) / Cost Price) x 100

In this case, the cost price of the sheets is 22.99, and the selling price (MSRP) is 59.99. Plugging these values into the formula, we get:

Markup on Cost Percentage = ((59.99 - 22.99) / 22.99) x 100

Markup on Cost Percentage = (37 / 22.99) x 100

Markup on Cost Percentage = 1.6103 x 100

Markup on Cost Percentage = 61.68%

Therefore, Hudson Bay's markup on cost percentage for acquiring sheets priced at MSRP 59.99 for 22.99 is 61.68%.

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The mass of salt in the tank at time t.

dS/dt = 10 - S/400

S(0) = 100 grams

The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.

So dS/dt = S(in) - S(out)

S(in) = 1 × 10 = 10 gram/liters

S(out) = S/V × 10 = 10S/V gram/liters

V = V(0) + q(in) - q(out)

V = 4000 + 10t - 10t

V = 4000 liters

dS/dt = 10 - 10S/V

dS/dt = 10 - 10S/4000

dS/dt = 10 - S/400

Now given; S(0) = 100.

Here, p(t) = 1/400, q(t) = 10

\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)

\(\mu=e^{\int p(t)dt}\)

\(\mu=e^{\frac{t}{400}}\)

So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)

S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)

S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)

Now solving the bracket

S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)

At S(0) = 100

100 = 4000 + \(e^{\frac{-0}{400}}\) C

100 = 4000 + \(e^{0}\) C

100 = 4000 + C

Subtract 4000 on both side, we get

C = -3900

Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

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The complete question is:

A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:

The mass of salt in the tank at time t.

dS/dt =

S(0) =

The solution is S(t) =

The cardinality of the cartesian product of A and B is 18.

Cartesian Product of two sets A and B is defined as the set of all ordered pairs (a,b) where a∈A & b∈B.

Cardinality of a set is defined as the number of elements in that particular set.

For example,  for a set A={2,6,4} , the cardinality is 3.

Given set A= { x | x is a prime number less than 7}

A={2,3,5}

set B =  { y | y is perfect square of an integer and y is less than 29}

B={0,1,4,9,16,25}

The cartesian product of A and B denoted by AxB will be

AxB={(2,0),(2,1),(2,4),(2,9),(2,16),(2,25),(3,0),(3,1),(3,4),(3,9),(3,16),(3,25),(5,0),(5,1),(5,4),(5,9),(5,16),(5,25)}

The number of elements in AxB is 18.

Therefore , the cardinality of the cartesian product of A and B is 18.

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Answer:

Step-by-step explanation:

I. Conjuguez le verbe au temps qui convient :

a) Autrefois, on _________________________ beaucoup. (jouer)

b) Hier, une fille _______________________ du 4eme étage. (tomber)

c) Dès que je ________________________ ma vieille maison, j’achèterai cette

maison-là. (vendre)

d) _________________________ la porte, s’il te plaît. (fermer)

e) Ils ______________________ nous voir la semaine prochaine. (venir)

f) Avant de ______________________, il faut se laver les mains. (manger)

g) Je ____________________________ bientôt. (se coucher)

h) _______________________________ bien ta route ! (savoir)

i) Quand __________________________-tu ton anniversaire ? (célébrer)

j) Dès qu’il _________________________, il me téléphonera. (se réveiller)

Answer:

21 pacientes tienen problemas cardíacos de los 70 pacientes diagnosticados

Step-by-step explanation:

Paciente con problema cardíaco del total de pacientes diagnosticados = 30%

Total de pacientes que van al hospital en un día = 70

El total de pacientes con problemas cardíacos entre los 70 pacientes diagnosticados es

30% de 70 = 30/100 * 70 = 21

Answer:

B. 4.09 cm²

Step-by-step explanation:

Let point O be the center of the circle.

As the center of the circle is the midpoint of the diameter, place point O midway between P and R.

Therefore, line segments OP and OQ are the radii of the circle.

As the radius (r) of a circle is half its diameter, r = OP = OQ = 5 cm.

As OP = OQ, triangle POQ is an isosceles triangle, where its apex angle is the central angle θ.

To calculate the shaded area, we need to subtract the area of the isosceles triangle POQ from the area of the sector of the circle POQ.

To do this, we first need to find the measure of angle θ by using the chord length formula:

\(\boxed{\begin{minipage}{5.8 cm}\underline{Chord length formula}\\\\Chord length $=2r\sin\left(\dfrac{\theta}{2}\right)$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the central angle.\\\end{minipage}}\)

Given the radius is 5 cm and the chord length PQ is 6 cm.

\(\begin{aligned}\textsf{Chord length}&=2r\sin\left(\dfrac{\theta}{2}\right)\\\\\implies 6&=2(5)\sin \left(\dfrac{\theta}{2}\right)\\\\6&=10\sin \left(\dfrac{\theta}{2}\right)\\\\\dfrac{3}{5}&=\sin \left(\dfrac{\theta}{2}\right)\\\\\dfrac{\theta}{2}&=\sin^{-1} \left(\dfrac{3}{5}\right)\\\\\theta&=2\sin^{-1} \left(\dfrac{3}{5}\right)\\\\\theta&=73.73979529...^{\circ}\end{aligned}\)

Therefore, the measure of angle θ is 73.73979529...°.

Next, we need to find the area of the sector POQ.

To do this, use the formula for the area of a sector.

\(\boxed{\begin{minipage}{6.4 cm}\underline{Area of a sector}\\\\$A=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}\)

Substitute θ = 73.73979529...° and r = 5 into the formula:

\(\begin{aligned}\textsf{Area of section $POQ$}&=\left(\dfrac{73.73979529...^{\circ}}{360^{\circ}}\right) \pi (5)^2\\\\&=0.20483... \cdot 25\pi\\\\&=16.0875277...\; \sf cm^2\end{aligned}\)

Therefore, the area of sector POQ is 16.0875277... cm².

Now we need to find the area of the isosceles triangle POQ.

To do this, we can use the area of an isosceles triangle formula.

\(\boxed{\begin{minipage}{6.7 cm}\underline{Area of an isosceles triangle}\\\\$A=\dfrac{1}{2}b\sqrt{a^2-\dfrac{b^2}{4}}$\\\\where:\\ \phantom{ww}$\bullet$ $a$ is the leg (congruent sides). \\ \phantom{ww}$\bullet$ $b$ is the base (side opposite the apex).\\\end{minipage}}\)

The base of triangle POQ is the chord, so b = 6 cm.

The legs are the radii of the circle, so a = 5 cm.

Substitute these values into the formula:

\(\begin{aligned}\textsf{Area of $\triangle POQ$}&=\dfrac{1}{2}(6)\sqrt{5^2-\dfrac{6^2}{4}}\\\\ &=3\sqrt{25-9}\\\\&=3\sqrt{16}\\\\&=3\cdot 4\\\\&=12\; \sf cm^2\end{aligned}\)

So the area of the isosceles triangle POQ is 12 cm².

Finally, to calculate the shaded area, subtract the area of the isosceles triangle from the area of the sector:

\(\begin{aligned}\textsf{Shaded area}&=\textsf{Area of sector $POQ$}-\textsf{Area of $\triangle POQ$}\\\\&=16.0875277...-12\\\\&=4.0875277...\\\\&=4.09\; \sf cm^2\end{aligned}\)

Therefore, the area of the shaded region is 4.09 cm².