Answer:
D. The liquid is a mixture because it has a gas dissolved in a liquid.
In certain metal, the stopping potential is found to be 3.70 V. When 235 nm light is incident on the metal, electrons are emitted. What is the maximum kinetic energy given to the electrons in eV and J?
Answer:
3.7 eV
5.92*10^-19 J
Explanation:
Given that.
Potential difference of the metal, V = 3.7 V
Wavelength of the light, n = 235 nm
maximum kinetic energy given to the electrons is giving them the formula
K(max) = e.V(s), where
KE(max) is the maximum kinetic energy needed
V = potential difference of the metal
KE(max) = e * 3.7
KE(max) = 3.7eV
converting our answer to Joules, we have
3.7eV = 3.7eV * 1.6*10^-19 J/eV
3.7eV = 5.92*10^-19 J
Therefore, the maximum kinetic energy in both eV and Joules is 3.7eV and 5.92*10^-19 Joules respectively
Answer:
Explanation:
d dnnd
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a stretched position. The position of the mass at any time is described by x = (8.8 cm)cos[2t/(4.18 s)]. Determine the following.
(a) period of the motion
(b) frequency of the oscillations
Hz
(c) first time the mass is at the position
x = 0
(d) first time the mass is at the site of maximum compression of the spring
A. The period of the motion is 4.18 s
B. The frequency of the oscillations
Hz is 0.2393 Hz
C. The first time the mass is at the position
x = 0 is 2.09 s
D. The first time the mass is at the site of maximum compression of the spring is 6.27s
How do we determine the values?a) The period of motion is given by the time it takes for the mass to complete one full oscillation. From the equation given, x = (8.8 cm)cos[2t/(4.18 s)], we can see that the function is in the form x = A cos(ωt + φ). The period of the motion T is given by the reciprocal of the angular frequency ω, which is T = 2π/ω.
In this case, the angular frequency is given by the coefficient of t in the argument of the cosine function, 2t/(4.18 s). So,
T = 2π/(2/(4.18 s)) = 4.18 s
b) The frequency of oscillations, f, is given by the reciprocal of the period, so
f = 1/T = 1/4.18 s^-1 = 0.2393 Hz
c) To find the first time the mass is at the position x = 0, we need to find the value of t when the cosine function is equal to 1.
x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * 1 = 8.8cm
so,
cos[2t/(4.18 s)] = 1
t = (4.18 s)/2 = 2.09 s
d) To find the first time the mass is at the site of maximum compression of the spring, we need to find the value of t when the cosine function is equal to -1.
x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * (-1) = -8.8cm
so,
cos[2t/(4.18 s)] = -1
t = (4.18 s) + (2.09 s) = 6.27s
It should be noted that the mass will be at the site of maximum compression at t = 6.27s and t = 2.09s + 4.18s = 6.27s + 4.18s = 10.45s and so on.
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if a box experiences three 400 n forces to the left and three different 410 n forces to the right which way does it go
Answer:
Explanation:
will accelerate to the right, because three different 410 N is greater than three different 400 N
As part of astronaut training, a prospective astronaut is spun around in a human centrifuge such that the candidate experiences a centripetal acceleration that is 2.8 times the acceleration due to gravity on the surface of the earth. If the candidate is 11.05 m from the center, determine the candidate's speed in meters per second.
The candidate's speed (m/s), given that the candidate experiences a centripetal acceleration that is 2.8 times the acceleration due to gravity is 17.4 m/s
How do I determine the candidate's speed?We understood that the centripetal acceleration is related to speed and radius according to the following formula:
a = v² / r
Cross multiply
v² = ar
Take the square root of both sides
v = √ar
Where
v is the speeda is the centripetal accelerationr is the radiusWithe the above formula, we can determin the speed of the candidate. Details below:
Acceleration due to gravity (g) = 9.8 m/s²Centripetal acceleration = 2.8 × g = 2.8 × 9.8 = 27.44 m/s²Radius (r) = 11.05 mSpeed of candidate (v) =?v = √ar
v = √(27.44 × 11.05)
v = 17.4 m/s
Thus, the speed of the candidate is 17.4 m/s
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A plane starting at rest at one end of a runway undergoes a uniform acceleration of
48 m/s for 13 seconds before takeoff. What is its velocity at takeoff?
What is a work out time setting? (Gym)
Answer:
It determines how long you do a certain workout.
In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?
According to the diagram the equivalent resistance of the group is
40.05 ohms
How to find the equivalent resistanceThe equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1
Resistors in parallel is solved by
Resistors in parallel = 1/25.4 + 1/70.8
Resistors in parallel = 0.0535 ohms
Equivalent resistance
Equivalent resistance = Resistors in parallel + Resistor in series
Equivalent resistance = 0.0535 + 40
Equivalent resistance = 40.0535
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If the mass of a car is 1,100 kg and its momentum is 22,000 kg
m/s, then what is its velocity?
The velocity of the car will be \(V=18.18\ \frac{m}{s}\)
What will be the velocity of the car?As velocity is the movement of the car with respect to time.
It is given that
Mass m = 1100kg
Momentum= 22000 \(\frac{kgm}{s}\)
The momentum is given as
\(P=mv\)
\(v=\dfrac{p}{m}\)
\(v=\dfrac{22000}{1100} =18.18 \ \dfrac{m}{s}\)
Thus the velocity of the car will be \(V=18.18\ \frac{m}{s}\)
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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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Pls help! What is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours?
A.
800 km/hr
B.
80 km/hr
C.
0.00125 km/hr
D.
28,800 km/hr
Answer:
800 meters per hour
Explanation:
800 meters per hour is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours.
If the distance between two masses attracted to each other is increased by a factor of 4. What is the gravitational force of attraction between the objects O 1/16 as strong O4 times stronger O 16 times stronger O force of attraction does not change
The assertion claims that the gravitational pull between the items grows four times greater.
What are example and force?The term "force" refers to a body's propensity to modify or change its state as a response of an external source. The body could change in size, shape, and movement when force is applied. A few example are kicking a soccer ball, banging on the door, and kneading bread.
Briefing:Gravitational force:
\($\quad \mathrm{F}=\frac{\mathrm{Gm}_1 \mathrm{m}_2}{\mathrm{r}^2}$\)
Case I An object's mass is twice
\($\mathrm{m}_1^{\prime}=2 \mathrm{~m}_1$\)
\($$\therefore \mathrm{F}^{\prime}=\frac{\mathrm{G}\left(2 \mathrm{~m}_1\right) \mathrm{m}_2}{\mathrm{r}^2} \Rightarrow \mathrm{F}^{\prime}=2 \mathrm{~F}$$\)
Consequently, the gravitational force doubles.
Case (ii): The items are now twice as far apart:
\($r^{\prime}=2 r$\)
\($$\therefore \mathrm{F}^{\prime}=\frac{\mathrm{Gm}_1 \mathrm{~m}_2}{(2 \mathrm{r})^2} \Rightarrow \mathrm{F}^{\prime}=\frac{\mathrm{F}}{4}$$\)
As a result, the gravitational pull is decreased by 4 times.
Distance between the objects is tripled i.e \($r^{\prime}=3 r$\)
\($$\therefore \mathrm{F}^{\prime}=\frac{\mathrm{Gm}_1 \mathrm{~m}_2}{(3 \mathrm{r})^2} \Rightarrow \mathrm{F}^{\prime}=\frac{\mathrm{F}}{9}$$\)
This results in a 9-fold reduction in gravitational force.
Case (iii): Both objects' masses are doubled:
\($\mathrm{m}_1^{\prime}=2 \mathrm{~m}_1$\) and
\($$\begin{aligned}& \mathrm{m}_2^{\prime}=2 \mathrm{~m}_2 \\& \therefore \mathrm{F}^{\prime}=\frac{\mathrm{G}\left(2 \mathrm{~m}_1\right)\left(2 \mathrm{~m}_2\right)}{\mathrm{r}^2} \Rightarrow \mathrm{F}^{\prime}=4 \mathrm{~F}\end{aligned}$$\)
Thus gravitational force becomes 4 times.
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Answer:
The gravitational force between two objects is inversely proportional to the square of the distance between them. If the distance between the Earth and the Moon is halved, the new distance becomes one-fourth (1/2)^2 of the original distance.
Since the gravitational force is inversely proportional to the square of the distance, reducing the distance by a factor of 1/4 would result in the gravitational force being increased by a factor of 4. Therefore, if the distance between the Earth and the Moon is halved, the gravitational force between them would become 4 times stronger.
Explanation:
giving brainlist What is ONE modern example OR historical example of a country that had representative government
Answer:
Canada
Explanation:
How would increasing bthe magnitude of the charges on two particles band decreasing the distance the distance between the particles affect the strength of the electric force between the strength of the electric force between particles/?
Increasing the magnitude of the charges on two particles and decreasing the distance between them will result in a significant increase in the strength of the electric force between the particles.
According to Coulomb's law, the electric force (F) between two charged particles is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance between them (r):
F ∝ (q1 * q2) / \(r^{2}\)
When the magnitude of the charges on the particles is increased, let's say doubling both charges, the force between them will also double. This is because the product of the charges in the numerator increases, leading to a proportional increase in the overall force.
Simultaneously, decreasing the distance between the particles, let's say halving the distance, will have an even more pronounced effect. Since the distance is squared in the denominator, halving it will result in the force being multiplied by a factor of four. Thus, the force between the particles will become four times stronger.
Therefore, by both increasing the magnitude of the charges on the particles and decreasing the distance between them, the strength of the electric force between the particles will be significantly amplified. The combined effect of these changes will lead to a much more powerful attraction or repulsion between the charged particles, resulting in a greater overall force of interaction.
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1. How much work does the human heart do if it uses 180 N of force to pump blood 0.3 meters to the
lungs?
Work does the human heart do if it uses 180 N of force to pump blood 0.3 meters to the lungs 39 joule.
What is work?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the direction of motion.
Work = force x distance. In units, Joules = Newtons x meters.
W = F.d
F = 180 N d=0.3 m
W = F.d
W = (180)(0.3)
W = 39 j
Work does the human heart do if it uses 180 N of force to pump blood 0.3 meters to the lungs 39 joule.
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A machine raises an object of weight 1500 N through a distance of 5m. What is its efficiency if the energy input is 15 000 J?
We have:
W = weight = 1500 N
D = distance = 5 m
Energy input = 15000 J
Apply:
Efficiency= useful output energy / input energy
Work = weight x distance = 1500 N x 5 m = 7500 J (useful output energy )
Efficiency = 7500 J / 15000 J = 0.5 or 50%
Write two artificial and two natural source of light.
Two natural sources of light: the sun and the stars
Two artificial sources of light: light bulb and torches
Answer:
Natural lights: Sunlight, Moonlight, or Lightning
Artificial: Light bulb, Candles, or a lighter/matches
Explanation:
The glowing dot represents the transmission of a nerve impulse along the nerves that make up the neural pathway. A nerve impulse is an electrical signal that travels from one nerve cell to another.
Which part of the brain processes this signal?
Answer:
The answer is "Cerebral Cortex"
Explanation:
The neurotransmitter diffuses across the short distance of the synapse and ties to a receptor protein of the objective neuron. At the point when the sub-atomic sign ties to the receptor, the cell film of the objective neuron changes its electrical state and another evaluated expected starts. On the off chance that that evaluated potential is sufficiently able to arrive at limit, the subsequent neuron produces an activity potential at its axon hillock. The objective of this neuron is another neuron in the thalamus of the mind, the piece of the CNS that goes about as a transfer for tactile data.
At another neurotransmitter, synapse is delivered and ties to its receptor. The thalamus at that point sends the sensory information to the cerebral cortex, the furthest layer of dark issue in the brain, where cognizant view of that water temperature starts.
A region of the cortex is particular for imparting signs down to the spinal cord for development. The upper engine neuron is in this area, called the precentral gyrus of the frontal cortex, which has an axon that broadens right down the spinal cord. At the degree of the spinal cord at which this axon makes a neurotransmitter, a reviewed potential happens in the cell membrane of a lower engine neuron.
A force of 585 N is exerted on a 407 kg mass a distance of 13660 km above the surface of a planet having a mass of 7.9E24 kg. Determine the average density of the planet in kg/cubic meter. Derive and express algebraic solution in terms of givens: F, m, mp, alt and G.
The average density of a planet is given by:
\(\rho=\frac{m}{V}\)where m is the mass of the planet and V is its volume. We know the mass of the planet but we don't know its volume, to find it we will need find its radius.
To find the radius of the planet we can use Newton's Law of gravitation:
\(F=G\frac{mM}{d^2}\)where G is the gravitational constant, m is the mass of the object, M is the mass of the planet and d is the distance between the planet and the object. Let r be the radius of the planet, and x be the distance from the surface of the planet to the object (x=13660 in this case); then we have:
\(\begin{gathered} F=G\frac{mM}{(r+x)^2} \\ (r+x)^2=\frac{GmM}{F} \\ r+x=\pm\sqrt[]{\frac{GmM}{F}} \\ r=-x\pm\sqrt[]{\frac{GmM}{F}} \end{gathered}\)Plugging the values given we have:
\(\begin{gathered} r=-13660\times10^3\pm\sqrt[]{\frac{(6.67\times10^{-11})(407)(7.9\times10^{24})}{585}} \\ \text{ Using the positive root we have:} \\ r=5.49\times10^6 \\ \text{ Using the negative root we have:} \\ r=-3.28\times10^7 \end{gathered}\)Since the radius of the planet has to be positive we choose the positive solution.
Now, that we know the radius of the planet we can calculate its volume; assuming the planet is spherical we have that:
\(V=\frac{4}{3}\pi r^3\)then we have:
\(\begin{gathered} V=\frac{4}{3}\pi(5.49\times10^6)^3 \\ V=6.92\times10^{20} \end{gathered}\)Finally we can calculate the density:
\(\begin{gathered} \rho=\frac{7.9\times10^{24}}{6.92\times10^{20}} \\ \rho=11398 \end{gathered}\)Therefore, the average density is 11398 kg/m^3
(6)
A 100 W heater is connected to a 240 V mains supply. Calculate the:
current drawn;
resistance of the hheater.I want to know how to go about it
Answer:
Current drawn = 0.417 A (rounded to 3 significant figures)
Resistance = 576Ω (rounded to 3 significant figures)
Explanation:
Current = Power ÷ Voltage
Current = 100W / 240V
∴ Current = 0.416666666.... = 0.417A
Resistance = Voltage ÷ Current
Resistance = 240 ÷ 0.417
∴ Resistance = 575.539 = 576Ω
a motor boat is traveling at 25 knots towards 340 degree on a river flowing at 20 knots towards 175 degrees. What is the actual speed of the boat as seen by a helicopter piolet hovering above?
Answer:
Vbx = 25 * cos 340 = 23.5 knot x-component of boats speed
Vrx = 20 cos 175 = -19.9 knot x-component of rivers speed
Vx = 3.58 knot x-component of boat and river speed
Vby = 25 sin 340 = -8.55 knot y-component of boat speed
Vry = 20 sin 175 = 1.74 knot y-component of river speed
Vy = -6.81 knot y-component of boat and river speed
V = (Vx^2 + Vb^2)^1/2 = (3.58^2 + 6.81^2)^1/2 = 7.69 knots
How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
Denise is conducting a physics experiment to measure the acceleration of a falling object when it slows down and comes to a stop. She drops a wooden block with a mass of 0.5 kilograms on a sensor on the floor. The sensor measures the force of the impact as 4.9 newtons. What’s the acceleration of the wooden block when it hits the sensor? Use F = ma.
A. 2.45 m/s2
B. 4.4 m/s2
C. 5.4 m/s2
D. 9.8 m/s2
Answer: The answer is D. (9.8 m/s2)
Explanation:
7N
6
→ 2N
Net Force:
Determine the net force acting on the object.
Answer:
When a force is applied to the body, not only is the applied force acting, there are many other forces like gravitational force Fg, frictional force Ff and the normal force that balances the other force. Therefore, the net force formula is given by, FNet = Fa + Fg + Ff + FN.
Explanation:
(b) a lake is 5.0m deep the density of the water is 1000kg/m3 (i) calculate the pressure at the bottom of the lake due to the depth of water
And the one under it I would appreciate the help thanks !
Given :
Density of the water, \(\rho = 1000\ kg/m^3\).
Depth of lake, d = 5 m.
To Find :
The pressure at the bottom of the lake due to the depth of water.
Solution :
We know, hydrostatic pressure is given by :
\(P = \rho gd\) ( Here, g is acceleration due to gravity, g = 10 m/s².
Putting all values in above equation, we get :
\(P = 1000\ kg/m^3 \times 10 \ m/s^2 \times 5\ m\\\\P = 5\times 10^4 \ Pascal\)
Hence, this is the required solution.
4 x10^4
---------------
3.63 x 10^-4
O 1.10 x 10^8
O 2.36 x 10^-8
O 2.36 x 10^-3
How we can see different colors by our eyes?
I DID A Science PROJECT ON THIS >:)))
basically light travels into the eye to the retina located on the back of the eye. the retina is covered withe millions of light sensitive cells called Rods and cones. when these cells detect light they send signals to the brain that help detect color.
the color of an object is determined by the wavelengths of light that it reflects. it's determined by the arrangement of electrons in the atoms of that substance that will absorb and re-emit photons of particular energies according to quantum laws.
find the coefficient of kinetic friction between the child and the slide if the slide is inclined at an angle of 28° below the horizontal
Given:
The acceleration of the child, a=1.26 m/s²
The angle of inclination, θ=28°
To find:
The coefficient of kinetic friction between the child and the slide.
Explanation:
The net force acting on the child when it is sliding down the slide is given by,
\(\begin{gathered} ma=mg\sin\theta-f \\ =mg\sin\theta-N\mu \\ =mg\sin\theta-mg\cos\theta\text{ }\times\mu \end{gathered}\)Where f is the frictional force, N is the normal force acting on the child, g is the acceleration due to gravity, and μ is the coefficient of kinetic friction.
On simplifying the above equation,
\(\begin{gathered} a=g\sin\theta-g\mu\cos\theta \\ \implies g\mu\cos\theta=g\sin\theta-a \\ \implies\mu=\frac{g\sin\theta-a}{g\cos\theta} \end{gathered}\)On substituting the known values,
\(\begin{gathered} \mu=\frac{9.8\sin28\degree-1.26}{g\cos28\degree} \\ =0.386 \end{gathered}\)Final answer:
The coefficient of kinetic friction between the child and the slide is 0.386
A uniform electric field is directed upward and has a magnitude of 24 N/C. A charge of -6 C is placed in this
field.
The direction of the force on the charge placed in the electric field is upward.
True or False
The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.
The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.
The force on a charged particle in an electric field can be calculated using the formula:
F = q * E
Where F is the force, q is the charge of the particle, and E is the electric field.
Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:
F = (-6 C) * (24 N/C)
F = -144 N
The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.
The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.
Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.
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Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.