Jupiter’s gravity might have kept a planet from forming. What planet?

Answers

Answer 1

Answer:

Saturn

Explanation:


Related Questions

What is the definition of science theory?

Answers

A scientific theory is a well-substantiated explanation of some aspect of the natural world that is acquired through the scientific method and repeatedly tested and confirmed through observation and experimentation.

Explain how electricity is transmitted from the main source in relation to step up and step down transformers

Answers

Answer:

The electricity produced from the main source which is an electrical generator which is usually close a remote abundant source of natural energy or at a distant location away from the residential areas where the electricity is used

The step up transformer is  the device used to raise the voltage and therefore lower the current of the of incoming generated electricity before it is transmitted through high tension cables so that the energy loss from source to destination is reduced and the electricity generated can applied where needed

However, the high voltage transmitted along power lines to reduce energy loss cannot be used as it is by the consumer, partly because it is very harmful in the event of an electric shock and can easily damage household electrical devices, therefore, the high voltage in the power lines is reversed back or lowered into voltages which can be used to power electrical devices in buildings with the use of a step-down transformer

Explanation:

What is the height at the peak of the projectiles trajectory if the magnitude vo equals 42.2 meters per second, and the angle ofΘis 41.8 degrees?

What is the height at the peak of the projectiles trajectory if the magnitude vo equals 42.2 meters per

Answers

Take into account that the vertical final velocity of the projectile is given by:

\(v^2_y=v^2_{oy}-2gy\)

Now, consider that at the peak of the trajectory, the vertical final velocity is zero. Moreover:

\(v^2_{oy}=v^2_o\sin ^2\theta\)

Then, by solving for y into the equation for vy^2, you obtain:

\(\begin{gathered} o=v^2_o\sin ^2\theta-2gy \\ y=\frac{v^2_o\sin \theta}{2g} \end{gathered}\)

where g = 9.8m/s^2 is the gravitational acceleration constant.

By using the given values for the angle and vo you obtain for the height of the peak y:

\(y=\frac{(42.2\frac{m}{s})(\sin 41.8)^2}{2(9.8\frac{m}{s^2})}\approx40.36m\)

Hence, the height of the peak of the projectil trajectory is approximately 40.36 m

why is saturn almost as large in radius as jupiter despite its smaller mass?

Answers

Answer:

Saturn is almost as big as Jupiter despite its smaller mass because Jupiter is a more dense gas giant than Saturn.

Explanation:

A 3,000 kg truck moving at +10 m/s hits a 1,000 kg parked car which moves off at +15 m/s. What is the velocity of the truck?.

Answers

The velocity of the truck is 5m/s.

Given:

m1 = 3000 (mass of truck)

m2 = 1000 (mass of car)

u1 = 10m/s( initial velocity of truck)

u2=0 (initial velocity of the car)

v1 =  ? (final velocity of the truck )

v2 = =15m/s (final velocity of the car)

The momentum of the system initially,

pi=m1u1+m2u2

\(pi = 3000 * 10 + 1000 * 0\\pi = 30000 + 0\\pi=30000\)

We know that pi = pf

m1u1+m2u2=m1v1+m2v2

\(30000=3000v1+15000\)

\(3000v1=30000-150003000v1=15000v1=15000/3000v1=5m/s\)

What is conservation of momentum?

The conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion.

What is the formula law of conservation of momentum?

As a result, the equation of the law of conservation of momentum is as follows: m 1 u 1 +m 2 u 2 represents the total momentum of particles A and B before the collision, and m 1 v 1 +m 2 v 2 represents the total momentum of particles A and B after the collision.

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A gas is compressed by an isothermal process that decreases its volume by a factor of 2. In this process, the pressurea) does not changeb) increases by a factor of more than 2c) increases by a factor less than 2d) increases by a factor of 2

Answers

If the gas is an ideal gas, then the pressure will remain constant in an isothermal process. So the correct option is a.

In general, a gas is compressed by an isothermal process that decreases its volume by a factor of 2. In this process, the pressure will either remain constant (a) .

The behavior of the pressure in an isothermal process depends on the nature of the gas. If the gas is an ideal gas, then the pressure will remain constant since the temperature is constant and the ideal gas law states that pressure is proportional to the temperature. In this case, the answer would be (a).

Finally, if the gas is an ideal gas and the process is adiabatic, then the pressure will increase by a factor less than 2 (c). This is because adiabatic processes involve a decrease in temperature, leading to a decrease in pressure.

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Assume a simply supported beam with span of 15m. It will be exposed to a dead load of 20kN/m (including self-weight) and a live load of 2kN/m along the full span. At the same time, it will be experiencing a concentrated dead load of 23kN + a live load of 1kN at midspan, as well as an additional dead load of 15kN located at 4m from the right support.
The beam has a rectangular cross-section with a width of 600mm and total height of 1000mm. The beam is reinforced with 10- 25M tensions bars at effective depth of 920 mm. The maximum aggregate size used is 20mm, and has the following material properties: f’c = 25MPa ,fy = 400 MPa.
Please perform the following task:
1) Draw the governing shear and bending moment diagram for the factored load.
2) Calculate the moment resistance of the cross section.
3) Comment if this cross section is adequately designed to resist the factored bending moment. (LRFD)

Answers

The values of all sub-parts have been obtained.

(1).  The maximum factored load the beam can withstand is 45.2 kN/m.

(2).  The moment resistance of the cross-section is 291735.65 Nm.

(3).  The factored moment demand is 27939.6 Nm

1) To draw the governing shear and bending moment diagram for the factored load, we need to first calculate the maximum factored load that the beam can withstand.

The maximum factored load on the beam is given by:

Dead Load = 20 kN/m + 15 kN

                   = 35 kN/m.

Live Load = 2 kN/m + 1 kN

                = 3 kN/m.

Total Factored Load = 1.2 x Dead Load + 1.6 x Live Load

                                  = 1.2 x 35 kN/m + 1.6 x 3 kN/m

                                  = 45.2 kN/m.

The maximum factored load the beam can withstand is 45.2 kN/m.

The shear force and bending moment diagrams for the given factored load can be obtained as shown below:

Shear Force Diagram:

Bending Moment Diagram:

2) To calculate the moment resistance of the cross-section, we can use the formula:

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

Where, σst = yield stress of tension steel [σst = fy / γst],

γst = safety factor for tension steel [γst = 1.15A']

A' = area of tension steel, [A'' = b(d - a)].

Where,

b = width of the beam [b = 600 mm],  

d = total height of the beam [d= 1000 mm],

a = effective depth of tension steel [a = 920 mm]

f'c = compressive strength of concrete [f'c = 25 MPa],

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

MR = (400 / 1.15) x 10 x (1000 - 920/2) + 0.85 x 25 x 590 x (1000 - 920/2)

MR = 291735.65 Nm

The moment resistance of the cross-section is 291735.65 Nm.

3) To check if this cross-section is adequately designed to resist the factored bending moment (LRFD), we need to calculate the factored moment demand and compare it with the moment resistance.

The factored moment demand is given by:

MF = ϕ x Mu

Where,ϕ = resistance factor = 0.9, Mu = factored bending moment

Mu = 1.2 x Dead Load x L2 / 8 + 1.6 x Live Load x L2 / 8 + 1.2 x (Dead Load + Live Load) x L2 / 2

   = 1.2 x 35 x 152 / 8 + 1.6 x 3 x 152 / 8 + 1.2 x 38 x 152 / 2

   = 31044 Nm

MF = ϕ x Mu

     = 0.9 x 31044

    = 27939.6 Nm

The factored moment demand is 27939.6 Nm, which is less than the moment resistance of the cross-section, i.e., 291735.65 Nm.

Therefore, this cross-section is adequately designed to resist the factored bending moment.

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An incidence that is caused by sleep and also occurs during sleep is known as a __________.

Answers

Answer:

parasomnia

Explanation:

Pretty sure it’s parasmonia (if I’m spelling that right

an ice hockey puck is tied by a string to a stake on rough ice and slides around in a circle until it comes to a stop. what is the sign of the work done by the tension in the rope as it slides to a stop?

Answers

The rope slides to a stop with no work being done by the tension in the rope.

Which of Newton's equations of motion best describes how a hockey puck would move if there was no external force acting on it as it slid around the ice?

first rule of Newton If not affected by a net external force, an item at rest or in motion maintains its state of motion at a constant speed.

A hockey puck striking is governed by what rule of motion?

The First Law of Motion by Newton Ice hockey is a sport that can help us understand Newton's laws of motion. Until pushed to change its condition by a net force, an object stays at rest or moves at a constant speed (speed in a constant direction).

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Sort the following planets by whether they formed within the snow line or not. Recall that the snow line is based on what phase of matter water is found in.
Within the Snow Line:
Earth
Mars
Venus
Mars
Outside the Snow Line:
Neptune
Uranus
Saturn
Jupiter

Answers

Within the snow line planets are, Mercury, Venus, Earth, and Mars were all formed.

What planets originated below the snow line?

As the solar system was forming, a line existed between the orbits of Mars and Jupiter; as a result, the rocky planets Mercury, Venus, Earth, and Mars formed within the line, while Jupiter, Saturn, Uranus, and Neptune formed outside.

Where is astronomy's snow line?

The frost line, which is sometimes referred to as the snow line or ice line, is the precise location in the solar nebula away from the central protostar where it is cold enough for vapors like water, ammonia, methane, carbon dioxide, and carbon monoxide to condense into solid ice grains.

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What is the change in velocity of a 15 kg object that experiences a 5 N force for 0.3 seconds?

Answers

Hello!

Δv = 0.1 m/s

Use the equation F = m · a to solve for the acceleration:

5 = 15 · a

a = 1/3

The equation to solve for acceleration can be rewritten to solve for the change in velocity:

Δv / t = a

Δv = at

We are given the acceleration and time, therefore:

Δv = (1/3)(0.3)

Δv = 0.1 m/s

if a neutral conducting spherical shell with radius r is placed in a uniform electric field e, the charge on the shell will redistribute itself and create a sort of dipole. (a) show that the external field due to the redistributed charge on the shell is in fact exactly equal to the field due to an idealized dipole at the center of the shell. what is the strength p of the dipole?

Answers

To determine the strength of the dipole created by the redistributed charge on the conducting spherical shell, we can consider the concept of electric dipole moment.

The electric dipole moment (p) is defined as the product of the magnitude of either charge (q) in the dipole and the separation distance (d) between them:

p = q * d

In this case, the dipole moment arises from the redistribution of charge on the conducting spherical shell. The magnitude of the charge on the shell will depend on the electric field (E) it experiences.

Now, let's analyze the scenario step by step:

1. The electric field (E) is uniform and acts on the conducting spherical shell of radius (r).

2. Due to the presence of the electric field, charges on the shell will redistribute themselves until equilibrium is reached.

3. The redistribution of charges will result in a dipole-like configuration, where positive charge accumulates on one side and negative charge on the other side.

4. To calculate the strength of the dipole moment (p), we need to determine the magnitude of the charge (q) and the separation distance (d) between them.

5. In the case of a conducting shell, the electric field inside the shell is zero, and the charges redistribute themselves to the outer surface of the shell. This means that the separation distance (d) between the positive and negative charges is equal to the diameter of the shell (2r).

6. The magnitude of the charge (q) on each side of the dipole can be determined by considering the net charge on the shell, which is zero. Therefore, the charges on each side of the dipole are equal in magnitude.

Now, we can express the dipole moment (p) as:

p = q * d = q * 2r

To find the value of q, we need to consider the electric field (E) acting on the shell. The electric field due to an idealized dipole at the center of the shell is given by:

E = (kp * cosθ) / r^2

where kp is the electric dipole moment of the idealized dipole and θ is the angle between the direction of the electric field and the axis of the dipole.

Since the electric field (E) acting on the shell is the same as the field due to the idealized dipole, we can equate these two expressions:

E = (kp * cosθ) / r^2 = (kq * 2r * cosθ) / r^2

From this equation, we can deduce that kp = 2krq.

Therefore, the strength of the dipole moment (p) is given by:

p = q * 2r = (kp * r) / (2k)

Substituting kp = 2krq, we get:

p = (2krq * r) / (2k) = rq

Hence, the strength of the dipole moment is given by p = rq, where r is the radius of the conducting spherical shell and q is the magnitude of the charge on each side of the dipole.

Note: The negative sign indicating the direction of the dipole is not considered here since we are only interested in the magnitude of the dipole moment.

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what will be the effect on the acceleration due to gravity of the earth if it is compressed to a the size the moon?​

Answers

Answer:

it gravitional pull on earth will increased becauste it is compress to a form of moon which is comperatively smaller so the gravitonal pull on per cm of earth will incrased so we can say that there will be change in acceleration due to gravity

Suppose the ski patrol towers a rescue sled and victim, having a total mass of 90.0 kg, down a 8 = 52.0degree slope at constant speed, as shown in Figure 6.22. The coefficient of frictionbetween the sled and the snow is 0.100.(a) How much work is done by friction as the sled moves 30.0 m along the hill?J(B) How much work is done by the rope on the sled in this distance?J(C) What is the work done by gravity on the sled?J(d) What is the total work done?J

Suppose the ski patrol towers a rescue sled and victim, having a total mass of 90.0 kg, down a 8 = 52.0degree

Answers

Work done by the gravity is -1662.28 Joules.

Given that:

m = 90 kg      M = 0.1

Q= 52°          S =  30m

a) work done by friction

w = fs

w = mkns

W = - Mk mg cos∅

W = - 0.1X 90 X 10 X cos 52° x30

w =  2700 X 0.61566

Wf = -1662.286 Joules

b) work done by Tention

W = -TS

W = mg sin∅ x s

W = -90x10xsin 52° x 30

W = -2700 X 0.788

W = -21276.3 Joules

c) work done by gravity

w = mg sing∅xs

wg = 21276.3Joules

d) Total work done

W= -1662-28 - 21276·3 +21276-3 -

W= -1662.28 Joules

Forces have no effect in the vertical direction. So if the force and displacement are perpendicular to each other, the work done by that force should be zero, since the force has no effect in that direction. The work done by gravity is not always zero because it depends on the displacement of the object. For example, if an object moves perpendicular to gravity, the work done will be zero. We know that the work done is defined as the magnitude of the displacement d multiplied by the component of the force acting in the direction of the displacement.

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what is the electric potential at a point in space if a charge of 7.3x 10^-17 coulombs at that point has a potential energy of 6.4

Answers

Answer:

V = 0.87 volt

Explanation:

Given that,

Charge, \(q=7.3\times 10^{-17}\ C\)

Electric potential energy, \(U=6.4\times 10^{-17}\ J\)

We need to find the value of electric potential at a point. The relation is as follows :

\(V=\dfrac{U}{q}\)

Where

V is electric potential

So,

\(V=\dfrac{6.4\times 10^{-17}}{7.3\times 10^{-17}}\\\\V=0.87\ V\)

So, the value of the electric potential at a point is equal to 0.87 Volts.

If you travel 40 m South and 100 m North, what is your displacement?

Answers

Answer:

\(displacement = ( + 100) + ( - 40) \\ = 60 \: m\)

Answer:

60m

Explanation:

Your friend just challenged you to a race through an obstacle course. You know in order to beat him, you must run 30 meters within 60 seconds in a southern direction. What does your average velocity need to be to win the race?
.5 meters per second, south
15 meters per second, south
2 meters per second, south
90 meters per second, south

Answers

Answer:

Velocity = 0.5 m/s South (A)

Explanation:

You need to determine the average rate of velocity.  

The equation you will use is velocity = displacement/time

The displacement is 30m South.

The time is 60 seconds.

Plug into the equation  Velocity = 30m South/60 s

Velocity = 0.5 m/s South

Answer: A)

Explanation:


For this object, what color will you observe?

For this object, what color will you observe?

Answers

Answer:

blue

Explanation:

blue is the only color being reflected, meaning it's the only one that will be visible

How does the force of gravity affect the rate of acceleration?

Answers

Gravity causes all objects to accelerate toward Earth at a rate of 9.8 m/s/s. Air resistance slows the acceleration of falling objects. An object falls at its terminal velocity when the upward force of air resistance equals the downward force of gravity.
Well technically because gravity is when an item falls on the ground the velocity actually increases. By which gravity causes all the objects to accelerate towards earth at a rate of 9.8m/s/s

Parallel rays of light that hit a concave mirror will come together:a. at the center of curvatureb. at the focal point.c. at a point half way to the focal point.d. at infinity.e. at the double focal distance.

Answers

Parallel rays of light that hit a concave mirror will come together b. at the focal point.

When parallel rays of light hit a concave mirror, they will converge and come together at a single point. This point is called the focal point and it is located along the principal axis of the mirror. The distance from the center of the mirror to the focal point is known as the focal length.

This phenomenon is known as converging or concave mirror. The location of the focal point is determined by the shape of the mirror, specifically its curvature. The curvature causes the light rays to reflect and converge towards the focal point. Therefore, option (b) is the correct answer: parallel rays of light that hit a concave mirror will come together at the focal point.

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When measuring the battery base voltage with a voltmeter, the vehicle engine should be _____ and all the accessories should be turned _____.
fast idling; on
running; on
off; off
running; off

Answers

When measuring the battery base voltage with a voltmeter, the vehicle engine should be running and all the accessories should be turned off and potential difference.

Thus, The term "voltmeter" refers to the instrument used to measure the electric potential difference between two locations in an electric circuit. It is connected at the same time.

Analogue voltmeters, which move a pointer around a scale in proportion to the voltage sensed, can be made using a galvanometer and a series resistor. Meters that use amplifiers can measure microvolts or less. An analog-to-digital converter is used by digital voltmeters to display voltage as a numerical value.

A wide range of designs are available for voltmeters, some of which are powered independently (by a battery, for instance) and others of which are powered directly by the source of the voltage that is being measured.

Thus, When measuring the battery base voltage with a voltmeter, the vehicle engine should be running and all the accessories should be turned off and potential difference.

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What is the relative time delay between GPS signals (L1 and L2) for a 40 TECu ionosphere when the GPS satellite is directly overhead and transmitting to a receiver on the ground?

Answers

The ionosphere refers to the uppermost layer of Earth's atmosphere, extending between 80 km and 1000 km above the surface. It earns its name due to the presence of charged particles, or ions, within this region.

These ions interact with radio waves, causing effects such as absorption, refraction, deflection, and reflection. These behaviors are particularly relevant to communication systems that rely on radio waves, including GPS.

The ionosphere plays a crucial role in GPS signal propagation.

As GPS signals pass through the ionosphere, the presence of electrons within this region causes a slowdown in the signals. The extent of this slowdown is directly related to the electron density present in the ionosphere.

Total Electron Content (TEC) is a unit of measurement used to quantify electron density, denoted as TECu (Total Electron Content Unit).

Higher TECu values indicate increased electron density, resulting in a greater delay in the GPS signals. Moreover, the delay is more pronounced for signals transmitted at the L2 frequency compared to those at the L1 frequency. L1 and L2 refer to two distinct frequencies of GPS signals.

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A 3.1 x 1023 kg object and a 7.3 x 105 kg object are orbiting each other in deep space. If these two objects are 4.3 x 1010 meters apart, what is the magnitude of their gravitational force?

Answers

The gravitational force on the object of masses 3.1×10²³ kg and  7.3×10⁵ kg respectively is 8.16×10⁻³ N.

What is gravitational force?

Gravitational force is the most prevalent force in the universe, pulling together on any two objects with mass in the universe.

To calculate the magnitude of the gravitational force, we use the formula below.

Formula:

F = GmM/r²............... Equation 1

Where:

F = Gravitational forcem = Mass of the first objectM = Mass of the second objectr = Distance between the objectsG = Universal constant.

From the question,

Given:

m = 3.1×10²³ kgM = 7.3×10⁵ kgG = 6.67×10⁻¹¹ Nm²/kg²r = 4.3×10¹⁰ m

Substitute these values into equation 1

F = (3.1×10²³× 7.3×10⁵×6.67×10⁻¹¹)/(4.3×10¹⁰ )²F = 8.16×10⁻³ N

Hence, the gravitational force is 8.16×10⁻³ N.

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we are in this device going down at constant speed. what force does not act on us? group of answer choices a torque. a reaction from the elevator floor. air drag. gravity.

Answers

There is no net force operating on us because the elevator and everything inside it, including us, are descending at a steady speed, indicating that all the forces are equal and balanced.

Because any imbalanced force is the force that is not acting on us, all of the possibilities are technically correct.

What is an elevator?A vertical transportation tool called an elevator is used to convey people or objects up and down the floors or levels of a structure. A counterweight system that aids in balancing the weight of the cab and its occupants is often part of this system, which consists of a cab or platform that is steered by rails or cables along a vertical shaft or hoistway.Elevators are frequently driven by electric motors, and they are managed by a button and sensor system that lets users choose the floor or level they want to go to. To avoid mishaps or malfunctions, safety features like brakes and emergency stop buttons are also present.

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if the air pressure at sea level is 0.1 MPa( 1MPa = 1 x 10 6 pascals = 10 bars) what is the air pressure at an elevation of 2000 meters? ( give answer in MPa)

Answers

The air pressure calculated using barometric formula at an elevation of 2000 meters is 0.068 MPa if the air pressure at sea level is 0.1 MPa.

Air pressure =  0.1 MPa

Elevation height = 2000 meters

The barometric formula is used to calculate the air pressure at an elevation of 2000 meters. Here the atmospheric pressure decreases when the elevation increases. The barometric formula is:

P = P₀ * exp(-M * g * h / (R * T))

P = pressure of altitude

P₀ = pressure at sea level

M = molar mass of Earth's atmoshpere = 0.02896 kg/mol

g =  acceleration due to gravity = 9.8 m/s²

h =  altitude height = 2000 m

R = ideal gas constant = 8.314 J/(mol·K)

T =  temperature of the air at a constant.

Substituting the values:

P = 0.1 MPa * exp(-0.02896 kg/mol * 9.8 m/s² * 2000 m / (8.314 J/(mol·K) * T))

T = 293K

P = 0.1 MPa * exp(-0.02896 kg/mol * 9.8 m/s² * 2000 m / (8.314 J/(mol·K) * 293 K))

P = 0.1 MPa * exp(0.2929808 / (8.314 J/(mol·K) * 293 K))

P =  0.1 MPa * exp(0.2929808 / 2436.002))

P  = 0.068 MPa

Therefore, we can conclude that the air pressure at an elevation of 2000 meters is 0.068 MPa.

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Which statement describes how chemical formulas, such as H20, represent compounds?

Answers

Answer:

They show the elements that make up a compound.

They show the three-dimensional shape of a molecule.

They show the types of atoms that make up a molecule.

They show the number of each type of atom in a molecule.

Explanation:

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In the middle of a thunderstorm, a lightning bolt flashes. It takes Roberto 5 seconds to
hear the thunder afterwards. How far is the source of lightning from Roberto? The temperature is 22° C.
Speed of sound at 22°C = ?
d = ?
You will be reported if you didn't answer properly​

Answers

Answer:

 v = 344.1 m / s    

 d = 1720.5 m

Explanation:

For this problem we must calculate the speed of sound in air at 22ºC

           v = 331 RA (1+ T / 273)

we calculate

           v = 331 RA (1 + 22/273)

           v = 344.1 m / s

the speed of the wave is constant,

           v = d / t

           d = v t

we calculate

           d = 344.1   5

           d = 1720.5 m

why does the velocity change when the boy hits the ball

Answers

Answer:

Freefall is a special case of motion with constant acceleration because acceleration due to gravity is always constant and downward. This is true even when an object is thrown upward or has zero velocity.

When a ball is thrown up in the air, its velocity is initially upward. Since gravity pulls the object toward the earth with a constant acceleration g, the magnitude of velocity decreases as the ball approaches maximum height. At the highest point in its route, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth.

Answer:

Acceleration from gravity is always constant and downward, but the direction and magnitude of velocity change. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth

Explanation:

Read the following dream interpretation and answer the question that follows.
"I suspect that the patient's dream of being chased originates from his unresolved feelings of guilt during childhood."
What perspective of dream interpretation is being offered?
A. Freudian
B. activation-synthesis
C. Jungian
D. motivation

Answers

Answer:

Freudian

Explanation:

Answer:

Freudian

Explanation:

Two 0.55-kg basketballs, each with a radius of 14 cm , are just touching. How much energy is required to change the separation between the centers of the basketballs to 1.1 m? (Ignore any other gravitational interactions.)

Answers

Answer:

The amount of energy required is 4.08 J.

Explanation:

Given,m1 = m2 = 0.55-kgR = 14 cm = 0.14 m The distance between the two basketballs d = 1.1 m

Energy required to change the separation between the centers of the basketballs to 1.1 m is given by the formula; E = K1 + K2 - U where K1 = kinetic energy of ball 1K2 = kinetic energy of ball 2U = potential energy

Let's calculate K1,K2, and U: K1 = 0.5 mv²where m = mass of ball v = velocity of ball Initial velocity of ball = 0 m/s Final velocity of ball v = 0.5 m/sK1 = 0.5 × 0.55 × (0.5)²= 0.069 JK2 = 0.5 mv² Initial velocity of ball = 0 m/s .

Final velocity of ball v = - 0.5 m/sK2 = 0.5 × 0.55 × (- 0.5)²= 0.069 J Let's find out the potential energy; U = (kQ1Q2) / d

where Q1 = Q2 = Q d = distance between the centers of two balls U = (kQ²) / d where k = Coulomb's constant = 8.99 × 10⁹ Nm²/C²Q = charge on a ball = 0 (because it is an uncharged object) U = 0.

Therefore, E = K1 + K2 - U= 0.069 + 0.069 - 0= 0.138 J Therefore, the amount of energy required is 4.08 J.

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